2. An electron and a proton are separated by 5 cm:
a) what is the magnitude of the force on the electron?
b) What is the net force on the system?
Answer:
a) the charge of an electron is equivalent to the magnitude of the elementary charge but barring a negative sign since the side of the elementary charge is roughly 1.602 * 10 - 19 Columbus then the charge of the electronic is-1.602 * 10 - 19
b) b=2T on the electron moving in the magnetic field
Which measures the amount of work you did?
I don’t get it
Answer:
Power is often measured in joules of work per second. The unit of measurement for power is the (W). One watt is equal to one joule of work done in one second. If an object does a large amount of work, its power is usually measured in units of 1000 watts, or kilowatts.
Explanation:
A horse pulls a sled 100 meters. The horse applies 200 newtons of force. How many joules of work did the horse do?
Please hurry and help
Explanation:
work done = force × distance
= 200N × 100m
= 20000J
= 20KJ
A small mirror is attached to a vertical wall, and it hangs a distance of 1.87 m above the floor. The mirror is facing due east, and a ray of sunlight strikes the mirror early in the morning and then again later in the morning. The incident and reflected rays lie in a plane that is perpendicular to both the wall and the floor. Early in the morning, the reflected ray strikes the floor at a distance of 3.56 m from the base of the wall. Later on in the morning, the ray is observed to strike the floor at a distance of 1.46 m from the wall. The earth rotates at a rate of 15.0o per hour. How much time (in hours) has elapsed between the two observations
Answer:
t = 1.62 h
Explanation:
A flat mirror fulfills the law of reflection where the incident angle is equal to the reflected angle.
θ_i = θ_r
If we use trigonometry to find the angles, the mirror is at a height of L = 1.87 m, and the reflected rays reach a distance x1 = 3.56 m
tan θ₁ = x₁ / L
tan θ₁ = [tex]\frac{3.56}{1.87}[/tex]
θ₁ = tan⁻¹ 1.90
θ₁ = 62.29º
for the second case x₂ = 1.46 m
tan θ₂ = x₂ / L
θ₂ = tan⁻¹ [tex]\frac{1.46}{1.87}[/tex]
θ₂ = 37.98º
the difference in degree traveled is
Δθ = θ₁- θ₂
Δθ = 62.29 - 37.98
Δθ = 24.31º
as in the exercise they indicate that every 15º there is an hour
t = 24.31º (1h / 15º)
t = 1.62 h
What type of forces is acting on an object that prevents the object from moving?
use the Group of answer choices
a Balanced forces
b Friction forces
c Gravity forces
d Unbalanced forces
Answer: Friction Forces
Explanation: (I took the same test and got the answer)
_________________________________________
I hope this helps!
pls help
How much work is done when a bucket of mass 2kg with 20kg
of water in it is pulled up from the bottom of a well 10m deep?
Answer:
2156 J
Explanation:
From the question,
Work done = Combined mass of the bucket and water×height×gravity.
W = (M+m)hg............................. Equation 1
Where M = mass of water, m = mass of the bucket, h = height, g = acceleration due to gravity.
Given: M = 20 kg, m = 2 kg, h = 10 m
Constant: g = 9.8 m/s²
Substitute these value into equation 1
W = (20+2)×10×9.8
W = 22×98
W = 2156 J
A car travels at a constant speed of 25 m/s. Find the power supplied by the engine if it can supply a maximum force of 18,000 N
Answer:
720
Explanation:
True or False: An electric circuit has to be complete for the load to
receive electricity.
A twin-sized air mattress used for camping has dimensions of 100 cm by 194 cm by 14 cm when blown up. The weight of the mattress is 4 kg. How heavy a person (in N) could the air mattress hold if it is placed in freshwater
Answer:
[tex]2625.156\ \text{N}[/tex]
Explanation:
Dimensions of mattress 100 cm by 194 cm by 14 cm
[tex]m_m[/tex] = Mass of mattress = 4 kg
[tex]\rho[/tex] = Density of water = [tex]1000\ \text{kg/m}^3[/tex]
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
Volume of mattress
[tex]V=100\times 194\times 14=271600\ \text{cm}^3=0.2716\ \text{m}^3[/tex]
Weight of water displaced is equal to the buoyant force
Mass of water
[tex]m=\rho V\\\Rightarrow m=1000\times 0.2716\\\Rightarrow m=271.6\ \text{kg}[/tex]
Mass of person would be
[tex]m_p=m-m_m=271.6-4\\\Rightarrow m_p=267.6\ \text{kg}[/tex]
Weight of the person would be
[tex]w=m_pg\\\Rightarrow w=267.6\times 9.81\\\Rightarrow w=2625.156\ \text{N}[/tex]
The air mattress could hold a person that weighs up to [tex]2625.156\ \text{N}[/tex].
2.4 What is the radiation error of a temperature measurement?
I
Answer:
diameter of the wire = 0.05 in =0.05 /12 =4.167 *10 ^-3 ft
area of cross section of the wire = A = 22/7 * ( d /2 ) ^2 =0.786 * ( 4.167 *10 ^-3 ) ^2 =1.365 *10 ^-5 ft2
E =...
Explanation:
How much work is done in pushing an object 7.0 m across a floor with a force of 50 N and then
pushing it back to its original position? How much power is used if this work is done in 20 sec?
Answer:
35/2 J/s
Explanation:
Just use the 2 formulas
Work done = Force * distance moved
Power = Work done/time
WD = 7 * 50 = 350
Power = 350 / 20
= 35/2 J/s
At the same instant that a 0.50-kg ball is dropped from 25 m above Earth, a second ball, with a mass of 0.25 kg, is thrown straight upward from Earth's surface with an initial velocity of 19.6 m/s. They move along nearby lines and pass each other without colliding. When the second ball is at its highest point, what is the velocity of the center of mass of the two-ball system
Answer:
The velocity of the center of mass of the two-ball system is 13.1 m/s.
Explanation:
Given;
mass of the first ball, m₁ = 0.5 kg
mass of the second ball, m₂ = 0.25 kg
initial velocity of the second ball, u₂ = 19.6 m/s
At the highest point the velocity of the second ball, v₂ = 0
The highest point reached by the second ball is calculated as;
v₂² = u₂² - 2gh
0 = u₂² - 2gh
2gh = u₂²
h = u₂² / 2g
h = (19.6²) / (2 x 9.8)
h = 19.6 m
The final velocity of the first ball when it had traveled 19.6 m down;
v₁² = u₁² + 2gh
v₁² = 0 + 2gh
v₁ = √2gh
v₁ = √(2 x 9.8 x 19.6)
v₁ = 19.6 m/s
The velocity of the center of mass of the two-ball system is calculated as;
[tex]v = \frac{m_1v_1 \ + \ m_2v_2}{m_1 \ + \ m_2} \\\\v = \frac{0.5\times 19.6 \ + \ 0.25\times 0}{0.5 \ + \ 0.25} \\\\v = 13.1 \ m/s[/tex]
P.E
1. Tukuyin ang mga galaw sa kahon kung ito ay pag-galaw sa low level, middle level o high
level. Isulat ang iyong sagot sa teybol sa ibaba.
pag-upo
paglakad
pagtakbo
pagdapa sa sahig
pagtalon
Answer:
pagtalon?
Explanation:
because that had to be the answer
A concave lens cannot produce a real image.
A. True
B. False
Answer:
B. False
A concave mirror and a converging lens will only produce a real image if the object is located beyond the focal point.
~Hoped this helped~
~Brainiliest?~
1 poin 4. If the same strength force is exerted on two objects but the objects have different masses, the object with mass will have a greater change in velocity. O more O less O greater O the same
Answer:
hellli
Explanation:
Sir
can u help me in my physics exams
A sound wave was determined to have a frequency of 0.3 Hz, speed of 150 cm/s, and amplitude of 2 cm. Find its wavelength.
Answer:
5 m
Explanation:
From the question,
v = λf....................... Equation 1
Where v = speed of the sound wave, λ = wavelength of the sound wave, f = frequency of the sound wave.
make λ the subject of the equation
λ = v/f..................... Equation 2
Given: v = 150 cm/s = 1.5 m/s, f = 0.3 hz.
Substitute these values into equation 2
λ = 1.5/0.3
λ = 5 m.
When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees upon landing to reduce the force of the impact. A 63.5-kg man just before contact with the ground has a speed of 7.89 m/s. (a) In a stiff-legged landing he comes to a halt in 3.99 ms. Find the magnitude of the average net force that acts on him during this time. (b) When he bends his knees, he comes to a halt in 0.205 s. Find the magnitude of the average net force now. (c) During the landing, the force of the ground on the man points upward, while the force due to gravity points downward. The average net force acting on the man includes both of these forces. Taking into account the directions of the forces, find the magnitude of the force applied by the ground on the man in part (b).
Answer:
a) F = 1.26 10⁵ N, b) F = 2.44 10³ N, c) F_net = 1.82 10³ N directed vertically upwards
Explanation:
For this exercise we must use the relationship between momentum and momentum
I = Δp
F t = p_f -p₀
a) It asks to find the force
as the man stops the final velocity is zero
F = 0 - p₀ / t
the speed is directed downwards which is why it is negative, therefore the result is positive
F = m v₀ / t
F = 63.5 7.89 / 3.99 10⁻³
F = 1.26 10⁵ N
b) in this case flex the knees giving a time of t = 0.205 s
F = 63.5 7.89 / 0.205
F = 2.44 10³ N
c) The net force is
F_net = Sum F
F_net = F - W
F_net = F - mg
let's calculate
F_net = 2.44 10³ - 63.5 9.8
F_net = 1.82 10³ N
since it is positive it is directed vertically upwards
True or false? A system must contain more than one object.
Answer:
true
Explanation:
normally -No system has ever performed well with one object.
A system must contain more than one object is a true statement.
What is system?A system is a group of interacting or interrelated objects that act according to a set of rules to form a unified whole.
Normally, no system has ever performed well with one object.
To learn more about System here
https://brainly.com/question/24893867
#SPJ2
Describe a perfect day
Answer:
A bright and sunny day not worrying about work or school no family drama just a day you can relax and be yourself surrounded by the people you love.
hope this helps
have a good day :)
Explanation:
Answer:I'll describe a perfect day as a bright sunny day without rain,having no chores or homework to do.Going outside and enjoying the sun,have a glass of lemonade.No drama and no school,nothing to worry about.Going to the pool and going for a nice swim or a lake.Going fishing,playing basketball,watching television,or visiting a relative you haven't have much time to spend with.Going for a walk in the park,hanging out with some friends.Or just staying in the house doing nothing.
Explanation:
A 4768-kg roller coaster train full of riders approaches
Answer: ?
Explanation:
A geosynchronous Earth satellite is one that has an orbital period of precisely 1 day and has a radius of 42.2 km of its orbit about the Earth. For certain application, it is desirable to have a satellite that orbits the Earth with a period of precisely 2days. What should be the radius of such a (every-two-days) satellite
Answer:
66.98 km
Explanation:
Given :
Initial time period, [tex]$T_1$[/tex] = 1 day
Radius of initial orbit, [tex]$r_1$[/tex] = 42.2 km
Final Time period, [tex]$T_2$[/tex] = 2 days
We know that,
The time period of satellite is
[tex]$T= 2 \pi \sqrt{\frac{r^3}{GM}}$[/tex]
So, for [tex]$T_2=2\pi \sqrt{\frac{r_2^3}{GM}}$[/tex] ...........(i)
For [tex]$T_1=2\pi \sqrt{\frac{r_1^3}{GM}}$[/tex] ...................(ii)
Therefore, dividing equation (i) by (ii), we get
[tex]$\frac{T_2}{T_1}=\sqrt{\frac{r_2^3}{r_1^3}}$[/tex]
[tex]$\left(\frac{2}{1}\right)^2=\frac{r_2^3}{(42.2)^3}$[/tex]
[tex]$r_2 = 66.98 \ km$[/tex]
Therefore, the radius is 66.98 km.
ASAP 20 POINTS!!
The air also contained a small amount of argon
As the temperature of the air decreased from 20C to -190 C the argon changed
Explain the changes in arrangement and movement of the particles of the argon as the temperature of the air decreased
Answer:
See explanation
Explanation:
Let us recall that temperature is a measure of the average kinetic energy of the molecules of a body.The higher the temperature, the higher the kinetic energy of the molecules of the body.
As temperature decreases, the kinetic energy of the molecules of a substance also decreases rapidly and the magnitude of intermolecular interaction between molecules of the substance increases.
Hence, as argon gas is cooled from 20°C to -190°C the kinetic energy of the gas molecules decreases an the magnitude of intermolecular interaction increases hence the gas changes into liquid and subsequently changes into a solid at -190°C.
Un basquetbolista efectúa lo siguientes desplazamientos 6 metros al este 4 metros en dirección noroeste y finalmente 2 metros norte°Cual es la distancia total que recorre?
°Encuentra en forma gráfica el desplazamiento resultante en que dirección actúa y cual es el valor del angulo medido respecto al este
Answer:
R = 10.06 m, θ = 28.7º
Explanation:
o find the total displacement the best way is to find the displacement in the x (East) and y (North) axes
let's decompose the displacements
d₂ = 4 m
θ₂ = 45
let's use trigonometry
cos 45 = x₂ / d₂
sin 45 = y₂ / d₂
x₂ = d₂ cos 45
y₂ = d₂ sin 45
x₂ = 4 cos 45 = 2,828 m
y₂ = 4 sin 45 = 2,828 m
The shredding the x axis is
x_total = x₁ + x₂
x_total = 6 + 2,828
x_total = 8,828 m
The displacement in the y-axis
y_total = y₂ + y₃
y_total = 2,828 + 2
y_total = 4.828 m
Let's use Pythagoras' theorem for total displacement
R = [tex]\sqrt{x_{total}^2 + y_{total}^2 }[/tex]
R = [tex]\sqrt{8.828^2 + 4.828^2 }[/tex]
R = 10.06 m
for the direction let's use trigonometry
tan θ = [tex]\frac{x_{total} }{y_{total} }[/tex]
θ = tan⁻¹ \frac{x_{total} }{y_{total} }
θ = tan⁻¹ [tex]\frac{ 4.828}{ 8.828}[/tex]
θ = 28.7º
this angle is measured counterclockwise from the positive side of the x axis (Eat)
When conducting objects (such as metals) are connected for a brief time, charge can be made to flow quite easily from one to the other, even if the objects are in contact for an extremely brief amount of time. To that end, consider two identical metallic ball bearings (i.e., two very tiny metallic solid spheres) having unknown charges 41 and 42. It is found that when they are placed 1 m apart, they experience a 25-N attractive force.
(a) What can you conclude about the charges on these metal marbles from the information given?
(b) The ball bearings are made to touch very briefly and then are separated by 1 m again. What can you conclude about the charges now? Explain.
(c) Suppose that when the charges are 1 m apart, after briefly touching, they again feel a force of 25 N Determine the charges 41 and 42.
Answer:
a) charges of the opposite, b) Δq = q₄₂-q₄₁, force is repulsive
c) q = 5.27 10⁻⁵ C
Explanation:
a) In electrostatic studies it is found that charges of the same sign repel and charges of the opposite sign attract.
On the other hand, as the force between the spheres is attractive, the charges on them are of different sign
b) When the balls touch, the charges are quickly distributed between the two spheres, therefore there are two possibilities:
* if the charges were equal and as they are of the opposite sign, they are neutralized, therefore the spheres remain uncharged
The force between them is zero
* if the charges are different, a residual charge remains
Δq = q₄₂-q₄₁
that is distributed between the two spheres and the force between them is repulsive
c) For this case the charges on the two spheres is equal
q₄₁ = q₄₂ = q
the force is repulsive so the charges are of the same sign.
We can apply Coulomb's law
F = [tex]k \frac{q_1q_2}{r^2}[/tex]
in this case
F = [tex]k \frac{q^2}{r^2}[/tex]
q = [tex]\sqrt{ \frac{F \ r^2}{k} }[/tex]
let's calculate
q = [tex]\sqrt{ \frac{25 \ 1^2}{9 \ 10^{9}} }[/tex] = [tex]\sqrt{27.7778 \ 10^{-10}}[/tex]
q = 5.27 10⁻⁵ C
pls helpone phyics question lots of points!
Answer:
PE = 0.73J
Explanation:
Remember that in conservative spring systems,
Total energy = potential + kinetic energy.
On the y-axis lies the kinetic energy and the question asks for the potential energy.
PE + KE must always equal the same result.
In this case, KE + PE = 1
So rearranging the equation,
PE = 1 - KE
KE = 0.27 (as we can see from the graph)
Therefore,
PE = 1 - 0.27 = 0.73J
Bonus tip: The graphs of potential and kinetic energy will look the exact opposite in this case. When the KE graph is at 0J, the PE graph is at 1J and vice versa. And they always cross over at 0.5J
which two options describes behaviors of particles that are related to the chemical properties of the materials
a- forming hydrogen bonds between them
b- reacting quickly with water
c- having a high mass
d- forming bonds with other atoms
Answer:
The two correct answers are B.) reacting quickly with water, and D.) forming bonds with other atoms.
Explanation:
I took the quiz on a.pex and these were correct.
One thing that animals have not demonstrated the ability to do with language (that humans can) is use language to describe itself. This use is called
a. reflexiveness.
b. specialization.
C. prevarication.
d. duality of patterning sounds, which is used to produce an infinite number of unique utterances.
Answer:
The answer is letter B hope it helps
Help me, 100 points to answer right, answer without context will be reported
1. In the situation below, a tractor pulls a 850 sledge along a ramp of height ℎ = 1 and large = 30 °. If the tractor applies a constant force to the sledge = 6750 , at an angle = 36.9 °, determine the total work performed by all forces on the sledge to move it along the ramp. The coefficient of kinetic friction between the sledge and the plane is = 0.3. Tip: for the calculation, remember that only the components of the windows that are parallel to the direction of travel contribute to the work. Disregard the dimensions of the sled.
2) When firing a 2 projectile at a 1.4 bloco block, initially at rest, it is observed that the projectile is stuck in the block and the system moves together for a distance = 0.1 before stop. If the coefficient of kinetic friction between the block and the surface is = 0.25, determine what was the velocity of the projectile in the instant before impact. Tip: here you must use the conservation of linear momentum and also energy, considering the work done by the frictional force
A 120-gram toy airplane flies in a straight line at a speed of 1.3 m/s. How much kinetic energy does the airplane have?
Answer:
0.1014 J
Explanation:
This is the answer if the toy airplane was 120-GRAMS
if you meant KG then it's 101.4 J
An ideal gas undergoes an adiabatic expansion, a process in which no heat flows into or out of the gas. As a result, (a) the temperature of the gas remains constant and the pressure decreases. (b) both the temperature and pressure of the gas decrease. (c) the temperature of the gas decreases and the pressure increases. (d) both the temperature and volume of the gas increase. (e) both the temperature and pressure of the gas increase. Group of answer choices a b c d e
Answer:
(b) both the temperature and pressure of the gas decrease.
Explanation:
An ideal gas undergoes an adiabatic expansion, a process in which no heat flows into or out of the gas. As a result, both the temperature and pressure of the gas decrease.
Gay Lussac states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.
Mathematically, Gay Lussac's law is given by;
[tex] PT = K[/tex]
Also, according to the first law of thermodynamics which states that energy cannot be created or destroyed but can only be transformed from one form to another. Thus, the ideal gas does work on the environment with respect to the volume and temperature.