PSYW - Please Show Your Work
A radiator made out of iron of specific heat capacity 450 J/kgk has a mass of 45.0 kg
and is filled with 23.0 kg of water of specific heat capacity 4200 J/kgK.
Determine the energy required to raise the temperature of the radiator-water system by
1°K
Answer:
9.66E4 J
Explanation:
We have that the energy required to raise the temperature of the radiator-water system by
1°K
E=116.85KJ
From the question we are told
A radiator made out of iron of specific heat capacity 450 J/kgk has a mass of 45.0 kg and is filled with 23.0 kg of water of specific heat capacity 4200 J/kgK.
Determine the energy required to raise the temperature of the radiator-water system by 1°K
Generally the equation for the Energy is mathematically given as
[tex]E=((mc)_i+mc_w)dt\\\\Therefore\\\\E=(45* 450 +4200*23)1\\\\E=116850J\\\\E=116.85KJ\\\\[/tex]
Therefore
the energy required to raise the temperature of the radiator-water system by
1°K
E=116.85KJ
For more information on this visit
https://brainly.com/question/23379286
what is photons as in physics
Answer:
The photon,s a type of elementary particle. It is the quantum of the electromagnetic field including electromagnetic radiation such as light and radio waves, and the force carrier for the electromagnetic force.
Explanation:
Examine the diagram of a cell.
Which organelle is marked with an X?
cell membrane
mitochondrion
nucleus
ribosome
Answer:
It is the Nucleus
Answer:
Nuclease
Explanation:
This graph shows the path length based on the number of speciation events in a evolution path.
Speciation Events vs. Path Length gradual evolution Path Length punctuational evolution Number of Speciation Events
What does the graph suggest about the evolution path length
a. The punctuational evolution path is the same as the gradual evolution path
b. The gradual evolution path is longer that the punctuational evolution path
c. Gradual evolution does not effect the evolution path length
d. Punctuational evolution does not effect the evolution path length
Answer:
Nbhb
Explanation:
All of the following are possible transition points that occur during adulthood except __________.
A.
marriage
B.
rapid physical growth
C.
parenthood
D.
divorce
Answer:
B
Explanation:
.....................
Answer:
B. Rapid Physical Growths
Speed versus Time
The graph below suggests
A. a constant speed of 3 m/s followed by speed of 1 m/s
B. a constant velocity of 2 m/s followed by speed of zero
C. a constant speed of 4 m/s followed by speed of zero
D. a constant acceleration of 2 m/s followed by speed of zero
F. a constant speed of 2 m/s followed by speed of zero
Answer:
a constant speed of 2 m/s followed by speed of zero
Explanation:
I got it right on the test.
Find the magnitude of the sum
of these two vectors:
5.00 mA,
30.0°
B4
6.00 m
magnitude (m)
Answer:
Approximately [tex]3.01\; \rm m[/tex].
Explanation:
Decompose each vector into the sum of two vectors: a horizontal one (parallel to the arrow that points to the right) and a vertical one (parallel the arrow that points upwards.)
Vector [tex]\sf A[/tex] is horizontal and is at an angle of [tex]0^\circ[/tex] with the horizon.
Horizontal component of vector [tex]\sf A[/tex]: to the right, with a length of [tex]5.00\; \rm m \cdot \cos\left(0^\circ \right) = 5.00\; \rm m[/tex].Vertical component of vector [tex]\sf A[/tex]: [tex]5.00\; \rm m \cdot \sin\left(0^\circ \right) = 0\; \rm m[/tex].Vector [tex]\sf B[/tex] is at an angle of [tex]30^\circ[/tex] below the horizon.
Horizontal component of vector [tex]\sf B[/tex]: to the right, with a length of [tex]\displaystyle 6.00\; \rm m \cdot \cos\left(30^\circ \right) = (6.00\; \rm m) \times \frac{\sqrt{3}}{2}\approx 5.19615\; \rm m[/tex].Vertical component of vector [tex]\sf B[/tex]: downwards, with a length of[tex]\displaystyle 6.00\; \rm m \cdot \sin\left(30^\circ \right) = 6.00\; \rm m \times \frac{1}{2} = 3.00\; \rm m[/tex].Calculate the sum of vector [tex]\sf A[/tex] and vector [tex]\sf B[/tex].
The horizontal component of vector [tex]\sf A[/tex] and vector [tex]\sf B[/tex] are opposite to one another. Therefore, the length of the horizontal component of [tex]\sf (A + B)[/tex] would be the difference between the length of the horizontal components of vector [tex]\sf A\![/tex] and of vector [tex]\sf B\![/tex]:
[tex]\displaystyle (6.00\; \rm m) \times \frac{\sqrt{3}}{2} - 5.00\; \rm m \approx 0.196152\; \rm m[/tex].
The length of the vertical component of vector [tex]\sf A[/tex] is [tex]0\; \rm m[/tex]. Therefore, the length of the vertical component of [tex]\sf (A + B)[/tex] would be equal to the length of the vertical component of vector [tex]\sf B[/tex], [tex]\displaystyle 6.00\; \rm m \times \frac{1}{2} = 3.00\; \rm m[/tex].
Therefore, the length of the horizontal and vertical component of [tex]\sf (A + B)[/tex] are approximately [tex]0.196152\; \rm m[/tex] and [tex]3.00\; \rm m[/tex], respectively. The length of vector [tex]\sf (A + B)\![/tex] would be approximately:
[tex]\displaystyle \sqrt{(0.196152\; \rm m)^{2} + (3.00\; \rm m)^{2}} \approx 3.01\; \rm m[/tex].
The law of universal gravitation states that any two objects in the universe, without exception,
a
repel each other
b
attract each other
c
create friction
Answer:
attract each other
Explanation:
..........
2. Which one of the following liquids is more suitable for making a simple barometer?
Answer:
Emm I don't see the liquid options but usually mercury is used for making barometers...
Explanation:
The description of the structure of the atom is called the??
I think for this it is atomic model
How many meters across is a road sign that has an angular size of 120 arcseconds and is 1 km away?
PLEASE HELP!!!!! WILL GIVE BRAINLIEST!!!
Fossil fuels (oil, coal, and natural gas) provide us with much of the energy that allows us to drive a car, heat and cool our houses, cook food, watch television, and more. Despite many people’s concerns about the use of fossil fuels, other energy sources are not used very much.
Which energy source do you think is the best alternative and why?
A lever with a mechanical advantage of .4 is more advantageous than just picking up the object with your hands and lifting it up.
True
False
Answer:
true
Explanation:
One mole of iron (6 x 10^23 atoms) has a mass of 56 grams, and its density is 7.87 grams per cubic centimeter, so the center-to-center distance between atoms is 2.28 x 10^-10 m. You have a long thin bar of iron, 2.3 m long, with a square cross section, 0.12 cm on a side. You hang the rod vertically and attach a 149 kg mass to the bottom, and you observe that the bar becomes 1.17 cm longer. From these measurements, it is possible to determine the stiffness of one interatomic bond in iron.
ks = 20014.1 N/m
Number of side-by-side long chains of atoms = 4.81e^12
Number of bonds in total length = 1.096e^10
What is the stiffness of a single interatomic "spring"?
Answer:
Explanation:
Given that:
length l = 2.3 m
a = 0.12 cm = [tex]0.12 \times 10^{-2} \ m[/tex]
[tex]x = 1.17 \ cm = 1.17 \times 10^{-2}\ m[/tex]
m = 149 kg
[tex]\delta = 7.87 \ g/cm^3[/tex]
[tex]da = 2.28 \times 10^{-10}\ m[/tex]
[tex]F_{net} = F-mg\\ \\0 = F - mg \\ \\ F = mg \\ \\ k_sx = mg \\ \\[/tex]
∴
[tex]k_s = \dfrac{149(9.8)}{1.17 \times 10^{-2}} \\ \\ k_s = 124803.42 \ N /m[/tex]
[tex]N_{chain} = \dfrac{A_{wire}}{A_{atom}} = \dfrac{A_w}{da^2}[/tex]
[tex]N_{chain} = \dfrac{(a)^2}{(da)^2} = (\dfrac{a}{da})^2[/tex]
[tex]N_{chain} = (\dfrac{0.12 \times 10^{-2} }{2.28 \times 10^{-10}})^2[/tex]
[tex]N_{chain} = 2.77 \times 10^{13}[/tex]
[tex]N_{bond} = \dfrac{L}{da} \\ \\ = \dfrac{2.3}{2.28 \times 10^{-10}} \\ \\ N_{bond} = 1.009 \times 10^{10}[/tex]
[tex]\text{Finally; the stiffness of a single interatomic spring is:}[/tex]
[tex]k_{si} =\dfrac{N_{bond}}{N_{chain}}\times k_s[/tex]
[tex]k_{si} =\dfrac{(1.009 \times 10^{10})}{2.77*10^{13}}}\times (124803.42)[/tex]
[tex]\mathbf{k_{si} =45.46 \ N/m}[/tex]
4. You are walking at a leisurely pace of .75 m/s when you hear the train coming and start running to catch it. Over the next 10 seconds, you speed up to 3.5 m/s and catch your train! What was your acceleration over that time?
Answer:
0.275 m/s²
Explanation:
The acceleration of an object is defined as the change in velocity over the change in time.
a = Δv/Δt a = (v - v₀)/tWe are given the initial velocity, 0.75 m/s. The final velocity of the user in question is 3.5 m/s.
The time it takes for us to catch the train is 10 seconds. Using these variables, let's substitute into our equation.
a = (3.5 - 0.75)/10 a = 2.75/10 a = 0.275 m/s²Our acceleration over that time was 0.275 m/s² in order to catch the train.
A 2.50 kg ball moving at 7.50 m/s is caught by a 70.0 kg man while the man is standing on ice. How
fast will the man / ball combination be moving after the ball is caught by the man?
Explanation:(2.5kg) (7.5) m/s +70 kg(0) =(2.5kg +70 kg (v3) 18. 75 =72.5 =v3
v3=.26m/s 2.5+70
The specific heat of water in its solid phase (ice) is 2090 J/(kg K), while in the liquid phase (water) its specific heat is 4190 J/(kg K). Water's latent heat of fusion is 333,000 J/kg. If you have a 2kg block of ice at -90°C and you add 1,000,000 J of heat, what is its new temperature?
a. 0°C
b. 14°C
c. 49°C
d. 149°C
Answer:
d. 149 ⁰C.
Explanation:
Given;
mass of the block of ice, m = 2 kg
specific heat capacity of the ice, C = 2090 J/(kgK)
initial temperature of the ice, t₁ = -90 ⁰C
heat added to the ice, H = 1,000,000 J
let the final temperature of the ice = t₂
The final temperature of the ice after adding the heat is calculated as follows;
[tex]H = mC_{ice} \Delta t\\\\H = mC_{ice} (t_2 - t_1)\\\\1,000,000 = 2 \times 2090 \times (t_2 - (-90))\\\\1,000,000 = 4,180(t_2 +90)\\\\1,000,000 = 4,180t_2 + 376,200\\\\1,000,000 - 376,200 = 4,180t_2\\\\623,800 = 4,180 t_2\\\\t_2 = \frac{623,800}{4,180} \\\\t_2 = 149 \ ^0C[/tex]
Therefore, the new temperature of the water is 149 ⁰C.
what instrument will be used to measure the volume of a box
Answer:
A ruler.
Explanation:
Just measure height, length and width and multiply each.
In any vector space au=bu implies a=b ? Trou or False
Answer:
False
Explanation:
(I guess if it were written "properly" it would be ax=bx implies a=b).
Given the axioms we were given, it would seem that the statement should be true, no?
A related statement -- also listed as false -- is that "in any vector space, ax=ay implies that x=y." Again, given the axioms we have.
Answer:
False
Explanation:
Simply use the counterexample u = 0
For zero vector:
au=bu=0
holds for a=3, b=4
False
Timed plz hurry
Enlarged brain ventricles are presumed to signify
A. an excess of dopamine activity
B. frontal lobe abnormalities
C. development of brain tissue
D. a deterioration of brain tissue
Answer:
D. a deterioration of brain tissue
A deterioration of brain tissue cause enlargement of brain ventricles
When an injury or illness alters the circulation of CSF, one or more of the ventricles becomes enlarged as CSF accumulates. In an adult, the skull is rigid and cannot expand, so the pressure in the brain may increase profoundly. Hydrocephalus is a chronic condition in which is the buildup of fluid in the cavities (ventricles) deep within the brain. It can be controlled, but usually not cured.What is CSF?Cerebrospinal fluid (CSF) is a clear, colorless liquid found in your brain and spinal cord. They combinedly form central nervous system.Central nervous system controls and coordinates everything you do including muscle movement, organ function, and even complex thinking and planningHence, D) is the correct option.
To know more about CSF here
https://brainly.com/question/15682090
#SPJ2
What is the fastest bird
Answer:
Peregrine Falcon/hawk
Explanation:
i really dunno if you are talking about brids that can't fly or not.
Infer Which of the following is NOT true of gravitational force?
Answer:
I think it's a repulsive force
Can u help me please
Answer:
Find answer below.
Explanation:
a. Group 2: alkaline earth metals. Some examples of alkaline earth metals are magnesium, calcium, barium, etc.
b. Transition metals: metals with unpredictable properties.
c. Chlorine: halogen.
d. Metalloid: make good semiconductors.
e. Group 1: alkali metals. These includes the soft, light and reactive chemical elements found in group 1 of the periodic table. Some examples are hydrogen, potassium, lithium, sodium, etc.
f. Noble gases: has a full outer energy level (shell). These are chemical elements with eight valence electrons and as such have a full octet. Some examples are argon, neon, etc.
h. Metal: loses electron in bonding. They usually lose electrons in order to attain a full outer energy level or noble gas electronic configuration.
Which experimental result led to the inference that atoms have a dense,
positive center?
A. A few alpha particles bounced off a thin sheet of gold foil.
B. Most alpha particles passed straight through a thin sheet of gold
foil.
C. The beam in a cathode ray tube was moved by a magnetic force.
D. The beam in a cathode ray tube was moved by an electric force.
A few alpha particles bounced off a thin sheet of gold foil.
The correct option for the given question about Rutherford Gold Foil Experiment is Option A) "A few alpha particles bounced off a thin sheet of gold foil".
What caused Rutherford's gold-foil experiment's alpha particles to bounce off?Rutherford predicted that the particles will pierce the foil without any resistance. But he discovered that as the particle bounced off through the foil, its course would change or be deflected. Like charges repel one another, which is the reason behind this.
Thus we can conclude that Rutherford Gold Foil Experiment (A few alpha particles bounced off a thin sheet of gold foil) results led to the inference that atoms have a dense positive centre.
Learn more about Rutherford Gold Foil Experiment here:
https://brainly.com/question/1130007
#SPJ2
6) If a mass of an object is decreased to half and acting force is reduced by quarter the acceleration of its motion
b) Increases to its doute
d) Remains constant
a) Remains constant,
c) Increases to its four times
Answer:
Decreases to half.
Explanation:
From the question given above, the following data were obtained:
Initial mass (m₁) = m
Initial force (F₁) = F
Initial acceleration (a₁) =?
Final mass (m₂) = ½m
Final force (F₂) = ¼F
Final acceleration (a₂) =?
Next, we shall determine a₁. This can be obtained as follow:
F₁ = m₁a₁
F = ma₁
Divide both side by m
a₁ = F / m
Next, we shall determine a₂.
F₂ = m₂a₂
¼F = ½ma₂
2F = 4ma₂
Divide both side by 4m
a₂ = 2F / 4m
a₂ = F / 2m
Finally, we shall determine the ratio of a₂ to a₁. This can be obtained as follow:
a₁ = F / m
a₂ = F / 2m
a₂ : a₁ = a₂ / a₁
a₂ / a₁ = F/2m ÷ F/m
a₂ / a₁ = F/2m × m/F
a₂ / a₁ = ½
Cross multiply
a₂ = ½a₁
From the illustrations made above, the acceleration of the car will decrease to half the original acceleration
A ball has a mass of 140 g what is the force needed to accelerate the mall at 25 m/s squared
Answer:
[tex]\boxed {\boxed {\sf 3.5 \ Newtons}}[/tex]
Explanation:
Force is the product of mass (in kilograms) and acceleration (in meters per square second).
[tex]F=ma[/tex]
The mass of the ball is 140 grams and the acceleration is 25 m/s². Convert grams to kilograms.
1 kg=1000 g[tex]140 \ g *\frac{1 \ kg}{1000 \ g}=\frac{140}{1000} \ kg =0.14 \ kg[/tex]Substitute the values into the formula.
[tex]F= 0.14 \ kg * 25 \ m/s^2[/tex]
Multiply.
[tex]F= 3.5 \ kg*m/s^2[/tex]
1 kilogram meter per square second is equal to 1 NewtonOur answer equals 3.5 Newtons[tex]F= 3.5 \ N[/tex]
3.5 Newtons of force are required.
A 7.0kg object rests on a horizontal frictionless surface. What is the magnitude of the horizontal
force that is required to accelerate it at the rate of 2.3m/s2
?if you can show work it would be perfect
Answer:
16.1 N
Explanation:
From the question,
F = ma.............................. Equation 1
Where F = horizontal force, m = mass of the object, a = acceleration .
Given: m = 7.0 kg, a = 2.3 m/s²
Substitute this values into equation 1
F = (7.0×2.3)
F = 16.1 N.
Hence the magnitude of the horizontal force is 16.1 N
Which of the following features make Earth and Venus similar to each other?
Answer:
A. size and mass
Explanation:
A rain drop of radius 0.3mm has terminal velocity 1m/s in air. The viscosity of air is 18X10-5 poise, then viscous force is
Answer:
F = 1.0178 × 10^(-2) dyne
Explanation:
From stokes law, the viscous force also known as drag force on rain drop is given by the formula;
F = 6πηrv
Where;
η is viscosity
r is radius
v is velocity
We are given;
η = 18 × 10^(-5) poise
r = 0.3 mm = 0.03 cm
v = 1 m/s = 100 cm/s
Thus;
F = 6π × 18 × 10^(-5) × 0.03 × 100
F = 1.0178 × 10^(-2) dyne
why an inclined is considered as simple machine