Assuming the second plus sign is a typo and was meant to be a reaction arrow, this would be the balanced equation:
C3H8 + 5O2 —> 3CO2 + 4H2O
What is the concentration of a 500 mL solution with 25 mol of HF? Write your answer with TWO decimal places and round accordingly.
Answer:
oop I'm thinking hmmmmm
Which of the following is the best hypothesis?
A. If paper is burned, the products will be carbon dioxide and water.
B. At what temperature does a piece of notebook paper start to burn?
C. Some people use burning paper to help get a campfire started.
D. You should recycle paper instead of burning it.
Answer:
THE CORRECT ANSWER IS A
sorry for caps
A separatory funnel contains the two immiscible liquids water and toluene. Use the given densities to determine which layer is on top and which is on the bottom in the binary mixture.
Solvent Density (g/mL)
toluene 0.87
water 0.998
Drag and drop each label into the box to indicate the position of the liquid in the mixture.
Top layer
Bottom layer
Answer:
Top layer TolueneBottom layer WaterExplanation:
When two non-miscible liquids are put together, the one with the higher density will be on the bottom, while the one with the lower density will be on top.
Meaning that in this problem's case toluene would be on the top layer and water in the bottom layer.
Rank the following compounds in order of increasing solubility in water. Items (4 items) (Drag and drop into the appropriate area) No more items Items in order most soluble CaO BaO KCI KI
I have tried CaO> BaO > KCl > KI, this is incorrect.
Answer:
CaO < BaO < KCl <KI
Explanation:
Let us remember that the solubility of an ionic substance in water depends on the magnitude of the lattice energy and the hydration energy. If the hydration energy is equal to or is greater than the lattice energy, the substance dissolves in water.
However, the lattice energy depends on the size of the ions. The smaller the ions in the ionic compound, the higher the lattice energy and the lesser the solubility of the ionic compound.
KI has the least lattice energy and the highest solubility in water while CaO has the highest lattice energy and the least solubility in water.
5. A grouping of organisms based on shared characteristics is called
A. binomial nomenclature
B. scientific name
C. classification
D. genus
Answer:
peace of vassals
Explanation:
I think i spelled it worng
What is the percent composition of hydrogen in glucose
Answer:
67%Explanation:
Thus the % composition of glucose by mass is carbon 40.0 % oxygen 53.3 % hydrogen 6.7 % in this way, the % composition by mass of any compound can be calculated provided that is formed is known.__C+_SO2—_CS2 + __CO
Answer:
_c+_so2-_cs2+_co= Toxic
How many fluorine atoms are there in 39.4 moles of CF4?
Answer:
here
Explanation:
Answer: 4
A molecule of carbon tetrafluoride, CF4 , is made up of 1 carbon atom bonded to 4 fluorine atoms. Each carbon atom weighs 12.0 amu and each fluorine atom weighs 19.0 amu so 1 CF4 molecule weighs 1×12.0 amu + 4×19.0 amu = 88.0 amu. This number, 88.0, is called the molecular weight (or molecular mass) of CF4.
Calculate the [H+] for
(a) black coffee with a pH of 3.59
Which of the following is a homogeneous mixture ?A.pizza B.oxygen
C.tea
D .pure water
I think it would be d bc water is everywhere
anyone help with the percent yield questions?
Answer:
oof this is way to hard sry man
Explanation:
5.07 x 10^24 atoms of antimony is how many moles?
8.98 mol
7.99 mol
4.82 mol
8.42 mol
Answer:
8.42 moles (3 sig. figs.)
Explanation:
Given 5.07 x 10²⁴ atoms of antimony (Sb) => ? moles Sb
1 mole of any substance contains 6.02 x 10²³ particles ( atoms or molecules)
∴ Think in terms of 'how many 6.02 x 10²³'s are in 5.07 x 10²⁴ atoms Sb?
That is => moles Sb = 5.07 x 10²⁴ atoms Sb / 6.02 x 10²³ atoms Sb/mole Sb
= 8.42192691 moles Sb (calculator answer) ≅ 8.42 moles (3 sig. figs.)
How many electrons and protons does the sodium ion have 11 protons and 11 electrons
Answer:
A sodium ion Na+ contains 10 electrons, 11 protons, and 12 neutrons.
Explanation:
Match the function to the part of the cell.
1.lysosome
A.serves as a temporary storage area for nutrients and waste materials
2.vacuole
B.breaks down waste materials
3.chloroplast
C.converts energy from the sun to food energy
Answer: Chloroplast: Converts energy from the sun to food energy
Answer: Vacuole: Servers as a temporary storage area for nutrients and waster materials.
Answer: Lysosome: Breaks down waste materials
Explanation: Dude above me is wrong
If 43.1 g of O2 and 6.8 g of CO2 are placed in a 13.7 L container at 34 degrees C, what is the mixture of gasses?
answer must be in atm
Answer:
The total pressure of the gas mixture = 2.76 atm
Note: The question is not complete. The complete question is as follow:
If 43.1 g of O2 and 6.8 g of CO2 are placed in a 13.7 L container at 34 degree Celsius , what is the pressure of the mixture of gases?
Explanation:
Mass of O₂ gas = 43.1 g, molar mass of O₂ gas = 32.0 g/mol
Number of moles of O₂ gas = 43.1/32.0 = 1.347 moles
Mass of CO₂ gas = 6.8 g, molar mass of CO₂ gas = 44.0 g
Number of moles of CO₂ gas = 6.8/44 = 0.155 moles
Total number of moles of gas mixture, n = (1.347 + 0.155) = 1.502 moles
Volume of gas mixture, V = 13.7 L
Temperature of gas mixture, T = 34 °C = (273.15 + 34) K = 307.15 K
Pressure of gas mixture = ?
Molar gas constant, R = 0.0821 liter·atm/mol·K.
Using the ideal gas equation: PV =nRT
P = nRT/V
P = (1.502 × 0.0821 × 307.15) / 13.7
P = 2.76 atm
Therefore, the total pressure of the gas mixture = 2.76 atm
The second law of thermodynamics can be worded in different ways, such as a.) heat can flow spontaneously from a hot object to a cold object, or b.) the total entropy of any system plus that of the environment increases as a result of natural processes. Why are these statements equivalent
Answer:
Explanation:
The principal reason why these statements are equivalent and identical is that there can be a progressional flow of heat from a hot object item to a cold object because of this entropy is increasing and expanding Δg < 0 but stream flow from cold to hot is nonspontaneous as Δg > 0.
e.g [tex]dS = \dfrac{\delta Q}{T}[/tex]
As found in heat engines and refrigerators.
Identify the techniques used in the work-up and characterization of benzoic acid. The analytical method used to confirm the structure and functional groups of the product NMR spectroscopy The technique used to separate the pure product from any excess reagent, impurities, and byproducts Recrystallization The quick, numeric analysis used to characterize the product and assess the purity Melting point.
Answer:
Explanation:
[tex]\text{From the list of the options given; we are to identify the suitable techniques} \\ \\ \text{for the characterization of benzoic acid.}[/tex]
[tex]\text{The analytical method used to confirm the structure and functional groups}\\ \\ \text{present in the product is} \ \ \mathbf{IR \ spectroscopy.}[/tex]
[tex]\text{The technique used to separate pure products from any excess reagents,} \\ \\ \text{impurities, and byproducts is}\ \ \mathbf{Recrystallization.}[/tex]
[tex]\text{The quick, numeric analysis done to characterize the product and assess the purity is}[/tex][tex]\mathbf{melting \ point.}[/tex]
Which of the following wavelengths has the lowest frequency?
10mm
10nm
10km
10cm
10m
Answer:
10m es su respuesta
Explanation:
espero te sirva
What is the formula for Dicarbon trioxide
Answer:
diboron trioxide Formula: B 2 O 3 Molecular weight: 69.620 CAS Registry Number: 1303-86-2
Explanation:
hope that helps you╰(*°▽°*)╯How Ever Gets This RITE IS REWARDED BRAINLIEST and 25 points get it rite
can you show the options? i'm pretty sure it's "before"
Answer:
the answer is According to fossil records scallops live before dinosaurs
Explanation:
before
Is the Swedish timber industry more likely a result of good resource availability or a lack of trees elsewhere on Earth?
Answer:
The forest products industry plays a major role in the Swedish economy, and accounts for between nine and 12 percent of Swedish industry's total employment, exports, sales and added value. It includes companies within the pulp and paper industry, as well as the wood-mechanical industry.
Consider the following equilibrium
N204(9) - 2NO2(9) Keq = 5.85 x 10-3
Which statement about this system is true?
If the equilibrium concentration of NO2 is 1.78 x 10-2 M, the equilibrium concentration of N2O4 is
The equilibrium concentration of N₂O₄, given that the concentration of NO₂ is 1.78×10⁻² is 5.42×10⁻²
Data obtained from the question N₂O₄ <=> 2NO₂Equilibrium constant (Keq) = 5.85×10⁻³ Equilibrium concentration of NO₂ = 1.78×10⁻²Equilibrium concentration of N₂O₄ =?How to determine the equilibrium concentration of N₂O₄Keq = [Product] / [Reactant]
Keq = [NO₂]² / [N₂O₄]
5.85×10⁻³ = [1.78×10⁻²]² / [N₂O₄]
Cross multiply
5.85×10⁻³ × [N₂O₄] = [1.78×10⁻²]²
Divide both sides by 5.85×10⁻³
[N₂O₄] = [1.78×10⁻²]² / 5.85×10⁻³
[N₂O₄] = 5.42×10⁻²
Learn more about equilibrium constant:
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Answer:
First answer is "The equilibrium lies to the left", and the second one is 5.42 x 10^-2 M.
Explanation:
Hope i helped yall :D
You heat water and olive oil in two separate pans for a delicious new pasta recipe. The pans are the same temperature, but only the water is boiling! Why?
A
Olive oil has weaker intermolecular forces than water. This makes the intermolecular forces in oil easier to break, and keeps the molecules stuck together in a liquid state.
B
Water has weaker intermolecular forces than olive oil. This makes the intermolecular forces easier to break, allowing the individual water molecules to separate and change to a gas.
C
Water is losing electrons more quickly than olive oil is. The electrons float to the surface of the water, and their movement allows the phase change to happen.
Answer:
I think A is the correct answer
Answer: the answer is B 100%
How many moles of LiOH are in a 4.5 M solution containing 1.5 L of water?
Answer:
d
Explanation:
An FCC iron-carbon alloy initially containing 0.20 wt% C is carburized at an elevated temperature and in an atmosphere wherein the surface carbon concentration is maintained at 1.0 wt%. If after 51 h the concentration of carbon is 0.35 wt% at a position 3.9 mm below the surface, determine the temperature at which the treatment was carried out. You will need to use data in the two tables below to solve this problem.
Answer:
Explanation:
[tex]\text{From the information given:}[/tex]
[tex]C_o = 0.20 \ wt\% \\ \\ C_s = 1 \ wt\% \\ \\ t = 51 \ h \\ \\ x = 3.9 \ mm \\ \\ C_x = 0.35 \ wt\%[/tex]
[tex]\text{Using Fick's 2{nd} \ law \ of \ diffusion;} \\ \\ \dfrac{C_x- C_o}{C_s-C_o}= 1 - erf ( \dfrac{x}{2\sqrt{Dt}})[/tex]
[tex]\dfrac{0.35-0.20}{1-0.20}= 1 - erf ( \dfrac{x}{2\sqrt{Dt}})[/tex]
[tex]0.1875 = 1 - erf ( \dfrac{x}{2\sqrt{DT}}) \\ \\ erf ( \dfrac{x}{2\sqrt{DT}}) = 1 - 0.1875 \\ \\ erf ( \dfrac{x}{2\sqrt{DT}}) = 0.8125[/tex]
[tex]\text{To find the value of Z by Obtaining Data from Tabulation of Error Function}[/tex] [tex]\text{Table Values:}[/tex]
Z erf(z)
0.90 → 0.7970
0.95 → 0.8209
? → 0.8225
∴
[tex]\dfrac{z-0.90}{0.95-0.90}= \dfrac{0.8125-0.7970}{0.8209-0.7970}[/tex]
[tex]\dfrac{z-0.90}{0.05}= \dfrac{0.0155}{0.0239}[/tex]
[tex]z = 0.9324[/tex]
[tex]\text{To determine the diffusion coefficient;}[/tex]
[tex]erf (0.9324) = 0.8125 = erf (\dfrac{x}{2\sqrt{Dt}}) \\ \\[/tex]
[tex]\dfrac{x}{2 \sqrt{Dt}}= 0.9324 \\ \\ \dfrac{3.9 \times 10^{-3}}{2 \times \sqrt{D\times 51 \times 3600}} = 0.92324 \\ \\ \sqrt{D} = 4.88 \times 10^{-6} \\ \\ D = \sqrt{4.88 \times 10^{-6}} \\ \\ D = 2.38 \times 10^{-11} \ m^2 /s[/tex]
Plssss help ASAP I really need help with this y’all I’m bad at science
A chemistry student is given 4.00 L of a clear aqueous solution at 22°C. He is told an unknown amount of a certain compound X is dissolved in the solution. The student allows the solution to cool to 22 C. The solution remains clear. He then evaporates all of the water under vacuum. A precipitate remains. The student washes, dries and weighs the precipitate. It weighs 0.56 kg.
Required:
Using only the information above, Calculate the solubility of X in water at 22° C. If you said yes, calculate it Be sure your answer has a unit symbol and 2 no .0 it. significant digits.
Answer:
The responses to the given points can be defined as follows:
Explanation:
In point 1:
The answer is "No".
In point 2:
The mass of solute = The mass of precipitate [tex]= 0.56\ kg =0.56\ \times 1000 = 560 \ g[/tex]
Calculating the solubility:
[tex]= \frac{\text{mass of solute in g}}{\text{volume of solution in ml}}\\\\ = \frac{560}{ 4000} \\\\ = 0.14 \ \frac{g}{ml}[/tex]
Calculate the wavelength for the transition from n = 4 to n = 2, and state the name given to the spectroscopic series to which this transition belongs?
Answer:
The wavelength for the transition from n = 4 to n = 2 is 486nm and the name name given to the spectroscopic series belongs to The Balmer series.
Explanation
lets calculate -
Rydberg equation- [tex]\frac{1}{\pi } =R(\frac{1}{n_1^2} -\frac{1}{n_2^2})[/tex]
where ,[tex]\pi[/tex] is wavelength , R is Rydberg constant ( [tex]1.097\times10^7[/tex]), [tex]n_1[/tex] and [tex]n_2[/tex]are the quantum numbers of the energy levels. (where [tex]n_1=2 , n_2=4[/tex])
Now putting the given values in the equation,
[tex]\frac{1}{\pi }=1.097\times10^7\times(\frac{1}{2^2} -\frac{1}{4^2} )[/tex][tex]=2056875m^-^1[/tex]
Wavelength [tex]\pi =\frac{1}{2056875}[/tex]
=[tex]4.86\times10^-^7[/tex] = 486nm
Therefore , the wavelength is 486nm and it belongs to The Balmer series.
What is thePercent composition of dichlorine heptoxide?
Answer:
The percent composition of dichlorine heptoxide is 38.76% CI and 61.24% O
Answer:
38.76%cl and 61.24%o
Explanation:
the percent composition of dichlorine heptoxide is 38.76%Cl and 61.24%O
What is the molality of a 10.0 % by mass solution of NaCl?
(molar mass of NaCl = 58.44 g/mol)
mol/kg
On CK-12 all of these answers are correct
1.9
1.888
1.89
1.88
The molality of a 10.0 % by mass solution of sodium chloride (NaCl) is 1.7M.
How do we calculate molarity?Molarity of any solution will be calculated as number of moles of solutes present in per litre of the solution.
Moles of the substance will be calculated as:
n = W/M, where
W = given mass
M = molar mass
Given that percent mass of NaCl = 10% i.e. 10g of NaCl is present in 100 g of solution.
We know that 1 g = 0.001 L
100 g = 0.1 L
Moles of NaCl = 10g / 58.44g/mol = 0.17 mol
Molarity of NaCl = 0.17 / 0.1 = 1.7M
Hence required molarity is 1.7 M.
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