ANSWER ASAP
Which of the following is an example of non-matter?
Atom
Energy
Gas
Liquid

Answer:

the percentage yield of Cu(NO3) 2 is 40%

Answer:

A

Explanation:

I don't know how to say how I got it.

Answer:

d

Explanation:

the orbits of the planets in our circular elliptical and circular

Answer:

6.64 l is the answer.......

Answer:

question 6: winter solstice

question 7: rotation is when an object spins around its axis, revolution is when an object travels in a path around another

question 8: the rotational period is equal to the period of revolution for the moon

question 10: true

Answer:

Question 6:  winter solstice

Question 7: rotation is when an object spins around its axis,

revolution is when an object travels in a path around another

Question 8: the rotational period is equal to the period of revolution for the moon

Question 10: true

Explanation:

I took the test its right

Answer:

See explanation

Explanation:

If we look at the models, we will see that the three fluorine atoms in CF3COOH are attached to the carbon that is next to the -COOH group.

As a result of the electron withdrawing effect of the three fluorine atoms, CF3COOH  is much more acidic (104 times more acidic) than CH3COOH. This is reflected in the value of the Ka for each acid.

This electron withdrawing effect of the three fluorine atoms also stabilizes CF3COO- much more than CH3COO-.

Answer:

false

Explanation:

Answer:

Explanation:

A short circuit can cause a spark or fire.

Answer:

6 moles of CO₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

C₃H₈ + 5O₂ —> 3CO₂ + 4H₂O

From the balanced equation above,

1 mole of C₃H₈ reacted to produce 3 moles CO₂.

Finally, we shall determine the number of mole of CO₂ produced by the reaction of 2 moles of C₃H₈. This can be obtained as follow:

From the balanced equation above,

1 mole of C₃H₈ reacted to produce 3 moles CO₂.

Therefore, 2 moles of C₃H₈ will react to produce = 2 × 3 = 6 moles of CO₂.

Thus, 6 moles of CO₂ were obtained from the reaction.

what are asking commet it and I might be able to help

Answer:

B

Explanation:

Answer:

Answer:

7.81 moles

Explanation:

(4.7×10^24 )×1 moles divided by 6.02×10^23 molecules

Answer:

[C₆H₁₂O₆] = 0.139 M

Explanation:

Molarity si defined as a sort of concentration. It indicates the moles of solute that are contained in 1 L of solution.

We can also say, that molarity are the mmoles of solute contained in 1 mL of solution.

For this case, the solute is sugar (glucose). Let's determine M (mmol/mL)

(3.95 g . 1mol / 180g) . (1000 mmol / 1mol) / 158 mL

We determine moles, we convert them to mmoles, we divide by mL

M = 0.139 M

Moles = 3.95 g . 1mol / 180g → 0.0219 mol

We convert mL to L → 158 mL . 1L/1000mL = 0.158L

M = 0.0219 mol / 0.158L = 0.139 M

Answer:

It is an example of natural selection (option c)

Natural selection is demonstrated by a green rat snake living within that grass as well as a brown rat snake living throughout the desert.

The process throughout which communities of sentient creatures adapt but instead transform is known as natural selection. Persons within a demographic are inherently varied, which means they are all unique under certain manner.

This variance indicates that certain people have qualities that are more adapted to their surroundings over others.

Thus "Option C" is correct.

Find out more information about Natural selection here:

https://brainly.com/question/14485249

1.00mol is the correct answer

Answer:  175.35g

Explanation:  A 3 M solution has 3 moles of solute per litre.

The mass of one mole of NaCl equals the MW of NaCl MW =  35.45 + 23 =58.45 g/mol

The mass of 3 moles is 58.45 g/mol ×3 mol=175.35 g NaCl  or  200 g rounded to one sigfig.

Answer:

a) Concentration of salt in mg/L = 2g/100mL

b) concentration in ppm = 20000 ppm

Explanation:

Percentage composition of salt by weight in water = 2%

Density of water = 1 g/mL

100 mL of water will has a mass of 100 g

Mass of salt in 100 g of water = 2% ×100 g = 2 g

Therefore, 2 g of salt is dissolved in 100 mL of solution

Concentration of salt in 100 mL of solution = 2g/100mL

a) Concentration in mg/L

Mass of salt = 2 g = 2000 mg

Volume of solution = 100 mL = 0.1 L

Concentration in mg/L = 2000 mg/0.1 L

Concentration in mg/L = 20000 mg/L

b) Concentration in ppm

1 ppm = 1mg/L

Therefore, concentration in ppm = 20000 ppm

Answer:

Rabbit

Explanation:

I said rabbit because the snake feeds off the rabbit and that's where he gets his energy from. If the question asked you what is the primary source of energy in this food chain then the answer would be the sun. Since the question only asks you about the snake then the rabbit is the answer.

Hope this helps!

the answer for your question is whenever

That's the answer. hope you have a great day

Answer:

It is a chemical change

Explanation:

Melting of wax is temporary and wax can settle again on cooling and turns into a solid. ... Hence it is a chemical change.

Answer:

physical

Explanation:

the wax is changing it's physical state by becoming a liquid, it isn't changing it's chemical makeup

1.7960L

Explanation:

the mass of the gas is constant in both instances

pv/T=constant(according to pv=nRT)

745mmHg*2L/298K=760mmHg*v/273K

v=1.7960L

Answer:

Angiosperms

Explanation

Angiosperms have male sex organs called stamens. On the end of the stamen is the anther. This is where pollen is made. The pollen has to be taken to the pistil or the female part of the flower.

Answer:

Cone

Explanation:

Answer:

B. Free water

Answer:

a mixture of molecules - Box f

atoms of a pure elementa metal - Box D

a solid compound - Box C

a mixture of elements - Box A

Explanation:

Box a has mixture of elements which forms a solid like shape but there are different elements present in the box. The box f has mixture of molecules in which many atoms are combined together. Box c has solid compound with single element.

Answer:

True

Explanation:

The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

Hope it helps

These problems can be solved using the gas laws. The combined gas law states that PV/T = k, where P is the pressure, V is the volume, T is the temperature (in Kelvin), and k is a constant. From this relationship, you can figure out the change in pressure, volume, or temperature of a gas provided that one of those three parameters remains unchanged. This will be shown in the problems given.

1. Here, the pressure and volume of a gas change while the temperature remains constant. Since PV/T = k, if T is also constant, then the relationship becomes PV = k. In other words, the pressure and volume of a gas at a constant temperature are inversely proportional to each other. This can be expressed mathematically as [tex]P_1V_1=P_2V_2[/tex] (also called Boyle's Law), where P₁ and V₁ denote the initial pressure and volume, and P₂ and V₂ denote the final (or changed) pressure and volume, respectively.

We are given a gas with an initial pressure, P₁, of 2.03 atm and an initial volume, V₁, of 4.0 L. We are also told that the gas expands to a final volume, V₂, of 12.0 L. So, we are looking for P₂: The pressure of the gas when the volume has expanded from 4.0 to 12.0 L. From Boyle's Law,

[tex]P_2=\frac{P_1V_1}{V_2}[/tex].

Thus,

[tex]\[P_2=\frac{\left ( 2.03 \text{ atm} \right )\left ( 4.0 \text{ L} \right )}{\left ( 12.0 \text{ L} \right )}\] = 0.67 atm.[/tex]

Since the pressure and volume of a gas are inversely proportional, as one increases, the other decreases, and vice versa.

2. This is another Boyle's Law problem, but this time, we have to figure out what the final volume will be when the pressure of a gas is changed. Since the pressure is reduced, we can deduce that the volume must increase (notice the parallel with the previous question). We again turn to Boyle's Law, and this time we solve for V₂:

[tex]V_2=\frac{P_1V_1}{P_2}[/tex]

from which we obtain

[tex]\[V_2=\frac{\left ( 350.0 \text{ kPa} \right )\left ( 200 \text{ mL} \right )}{\left ( 120.0 \text{ kPa} \right )}\] = 583 mL.[/tex]

It's not clear whether 200 mL (V₁) should be assigned three significant figures or one. I gave the answer to three significant figures; the answer to one significant figure would be 600 mL.

3. We use Boyle's Law once more here, but our word problem has us working backwards (it's also not explicitly mentioned that temperature remains constant, but it should be reasonable to assume so). The current pressure of the gas inside the bike tire is 150 atm at a volume of 700 mL . But we want to know what the initial pressure of the gas was at a volume of 1000 mL. In other words, we want to solve for the P₁ in Boyle's Law:

[tex]P_1=\frac{P_2V_2}{V_1}.[/tex]

Since the volume of the gas had decreased from 1000 mL (V₁) to 700 mL (V₂), and the pressure and volume of a gas at a constant temperature are inversely proportional, we would expect the pressure of the gas to have increased; that is, our P₁ should be less than 150 atm.

[tex]\[P_1=\frac{\left ( 150 \text{ atm} \right )\left ( 700 \text{ mL} \right )}{\left ( 1000 \text{ mL} \right )}\] = 105 atm.[/tex]

Answer:

0.299 L

Explanation:

We'll begin by calculating the pressure of dry gas. This can be obtained as follow:

Measured pressure = 756 mm Hg

Water vapor pressure = 17.54 mm Hg

Pressure of dry gas =?

Pressure of dry gas = (Measured pressure) – (Water vapor pressure)

Pressure of dry gas = 738.46 mmHg

Finally, we shall determine the volume occupied at STP. This can be obtained as follow:

Initial volume (V₁) = 334 mL = 334 / 1000 = 0.334 L

Initial pressure (P₁) = 738.46 mmHg

Initial temperature (T₁) = 23 °C = 23 °C + 273 = 296 K

Final pressure (P₂) = 760 mmHg

Final temperature (T₂) = 273 K

Final volume (V₂)

P₁V₁/T₁ = P₂V₂/T₂

738.46 × 0.334 / 296 = 760 × V₂/273

Cross multiply

296 × 760 × V₂ = 738.46 × 0.334 × 273

224960 × V₂ = 67334.2597

Divide both side by 224960

V₂ = 67334.2597 / 224960

V₂ = 0.299 L

Thus, the volume of the dry gas st STP is 0.299 L.