An uncharged capacitor and a resistor are connected in series with a switch and a 12 V battery. At the instant the switch is closed, the voltage across the resistor is

spray him in the eyes and you have until he washes it put

Answer:

No kinetic energy-because there is no movement

Explanation:

It states that the monk is at complete rest so there is no movement.

Answer:

Is fire matter? Matter is anything that has mass and occupies space. The flame itself is a mixture of gases (vaporized fuel, oxygen, carbon dioxide, carbon monoxide, water vapor, and many other things) and so is matter. The light produced by the flame is energy, not matter.

Answer:

The magnitude of the force exerted on the pipe by the air is 4830 N and it acts horizontally

Explanation:

Given the data in the question;

from the Newton's second law of motion;

F = ma

where m is the mass, a is acceleration and F is the force exerted on the pipe due to the airflow in it

now in terns of mass flow;

F = [tex]m^{"}[/tex]V

where [tex]m^{"}[/tex] is the mass flow rate, V is the velocity(

so

[tex]m^{"}[/tex] = pAV

[tex]m^{"}[/tex] = p × ([tex]\frac{\pi }{4}[/tex] d² ) × V

where d is the diameter of the pipe( 0.5 m)

p is the density( 1.23 kg/m³ )

velocity v is 100 m/s

so we substitute

[tex]m^{"}[/tex] = 1.23 × ([tex]\frac{\pi }{4}[/tex] (0.5)² ) × 100

[tex]m^{"}[/tex] = 30.75 × [tex]\frac{\pi }{4}[/tex]

[tex]m^{"}[/tex] = 24.15 kg/s

Now lets write the equation for the force exerted on the pipe by the airflow

F = [tex]m^{"}[/tex]( V₁ - V₂)

where V₁ is velocity at inlet ( 100 m/s )

V₂ is velocity at exit ( - 100 m/s )

so we substitute

F = 24.15 ( 100 - (-100))

F = 24.15 × 200

F = 4830 N

The pipe is symmetric about horizontal axis so the force should also b acting only in the horizontal direction since any force component in the vertical direction is nullified due to this symmetry

Therefore, The magnitude of the force exerted on the pipe by the air is 4830 N and it acts horizontally

Answer:

Eliza’s suggestion is the most promising

Explanation:

Newton’s law of universal gravitation is [tex]F = G\frac{m_1m_2}{r^2}[/tex] where G is a constant and both masses are constant in this experiment as well. So it only depends on r, the distance between the center of mass of both objects.

Bringing it high in the sky, as Flo suggests, is definitely not a good idea because it only increases the distance from the center of the Earth mass.

A mountain contains significant mass, so the center of the Earth mass is somewhat shifted to regions with the largest mountains. However, standing on top of a mountain, as Lorenzo suggests, doesn’t help since the shift of the center of mass, if any, is far smaller than the height of the mountain.

Standing near sea level, as Eliza suggests, is a good way to minimize the distance to the center of the Earth mass.

Answer:

a)   E = 1.69 10⁶6 N / C,  b)  F = 3.38 10⁶ N

Explanation:

a)  In this exercise using Gauss's law we can consider the charge of the generator sphere as if it were at its center, therefore the electric field is

          E = k [tex]\frac{q}{r^2}[/tex]

let's calculate

         E = 9 10⁹ 3.00 10⁻³ / 4²2

         E = 1.6875 10⁶ N / C

          E = 1.69 10⁶6 N / C

b) let's calculate the electric force

          F = q E

          F = 2.00 1.69 10⁶

          F = 3.38 10⁶ N

Answer:

a. 104.5 C b. 7.94 × 10⁶ A/m² c. 5.83 × 10⁻⁴ m/s

Explanation:

a. How much electric charge passes through the starter motor?

Using Q = It where Q = electric charge passing through the starter motor, I = current = 110 A and t = time = 0.95 s

So, Q = It = 110 A × 0.95 s = 104.5 C

b. What is the current density in the wire?

The current density, J = I/A where I = current = 110 A and A = cross-sectional area = πd²/4 where d = diameter of copper wire = 4.20 mm = 4.20 × 10⁻³ m

So, J = I/A

= I/πd²/4

= 4I/πd²

= 4 × 110 A/π(4.20 × 10⁻³ m)²

= 440 A/55.42 × 10⁻⁶ m²

= 7.94 × 10⁶ A/m²

c. How far does an electron travel along the wire while the starter motor is on? (The density of conduction electrons in copper is n = 8.50×1028 1/m3.)

To find how far the electron travels, we need to find the electron drift velocity from

J = nev where J = current density = 7.94 × 10⁶ A/m², n = electron density = 8.50 × 10²⁸ m⁻³, e = electron charge = 1.602 × 10⁻¹⁹ C, v = drift velocity of electrons and A = cross-sectional area of wire = πd²/4 where d = diameter of copper wire = 4.20 mm = 4.20 × 10⁻³ m

So, v = J/ne

Substituting the values of the variables into the equation, we have

v = 7.94 × 10⁶ A/m² ÷ (8.50 × 10²⁸ m⁻³ × 1.602 × 10⁻¹⁹ C)

v = 7.94 × 10⁶ A/m² ÷ (13.617 × 10⁹ Cm⁻³)

v = 0.583 × 10⁻³ m/s

v = 5.83 × 10⁻⁴ m/s

see the picture and here is the name of it

A = Pulmonary artery

B = inferior vena cava

C = aorta

D = left ventricle

E = right ventricle

F = pulmonary system in kidney

G = Pulmonary system

H = Pulmonary vein

#Moderators please don't be mean, dont delete my answers just to get approval from your senior or just to get the biggest moderation daily rank.

Answer:

I don't understand the question

Explanation:

sorry I cant help because I am just a first former

Complete question:

Consider the hypothetical reaction 4A + 2B → C + 3D

Over an interval of 4.0 s the average rate of change of the concentration of B was measured to be -0.0760 M/s. What is the final concentration of A at the end of this same interval if its concentration was initially 1.600 M?

Answer:

the final concentration of A is 0.992 M.

Explanation:

Given;

time of reaction, t = 4.0 s

rate of change of the concentration of B =  -0.0760 M/s

initial concentration of A = 1.600 M

⇒Determine the rate of change of the concentration of A.

From the given reaction: 4A + 2B → C + 3D

2 moles of B ---------------> 4 moles of A

-0.0760 M/s of B -----------> x

[tex]x = \frac{4(-0.076)}{2} \\\\x = -0.152 \ M/s[/tex]

⇒Determine the change in concentration of A after 4s;

ΔA = -0.152 M/s  x 4s

ΔA = -0.608 M

⇒ Determine the final concentration of A  after 4s

A = A₀ + ΔA

A = 1.6 M + (-0.608 M)

A = 1.6 M - 0.608 M

A = 0.992 M

Therefore, the final concentration of A is 0.992 M.

Answer:

Answer 11

Explanation:

. Newton's law of gravitation, statement that any particle of matter in the universe attracts any other with a force varying directly as the product of the masses and inversely as the square of the distance between them

Answer:

The frequency of a sound wave is what your ear understands as pitch. A higher frequency sound has a higher pitch and the lower the period

Answer:

High-frequency sound waves produce high-pitched sounds, and low-frequency sound waves produce low-pitched sounds.

Answer:

The following seems to be the summary including its given phrase.

Explanation:

Answer:

Yes.

Explanation:

Answer:

I do believe it is. (more characters for character limit)