Answer:
8.44 * 10^-3 %
Explanation:
The solubility of CO2 gas in water is 0.15g/100 ml at a CO2 pressure of 760 mmHg.
Determine the percentage of the CO2 that dissolved originally in the solution that remains
Amount remaining ( Sg = kpg )
Sg = solubility of gas = 0.15 / 100 g/ml
pg. = partial pressure of gas = 760 mmHg = 1 atm
therefore ; K = 1.5 * 10^-3 gm^-1 atm^-1
solubility of gas inside container
Sg = 0.675 * 10^-2 g/ml
solubility of gas during/after dissolution ( amount that remains )
sg = 1.5 * 10^-3 * 0.00038
= 5.7 * 10^-7 g/ml
therefore the percentage remaining
= (5.7 * 10^-7 / 0.675 * 10^-2 ) * 100
= 8.44 * 10^-3 %
The percentage of CO2 remaining in the solution after the soft drink reaches equilibrium is 8.4 × 10⁻³ %
There exists some missing information in the question.
Let us assume that:
the solubility of CO2 gas in the water = 0.15 g/100 mL = 1.5 × 10⁻³ the partial pressure of CO2 = 760 mmHg = 1 atmThen, by applying Henry's law:
[tex]\mathbf{S_g = k P_g}[/tex]
[tex]\mathbf{k = \dfrac{S_g}{P_g}}[/tex]
[tex]\mathbf{k =\dfrac{1.5 \times 10^{-3} g/mL}{1\ atm}}}[/tex]
k = 1.5 × 10⁻³ g/m* atm
The percentage of CO2 that was originally dissolved in the solution is:
[tex]\mathbf{S_g = k P_g}[/tex]
Assuming the partial pressure of CO2 = 4.5 atmThen;
[tex]\mathbf{S_g = 1.5 \times 10^{-3} g/mL* atm \times 4.5 \ atm}[/tex]
[tex]\mathbf{S_g =0.00675 \ g/mL}[/tex]
The partial pressure in the can when the soft drink is being opened is 0.00038 atm.
The solubility of the gas [tex]\mathbf{S_g = 1.5 \times 10^{-3} g/mL* atm \times 0.00038 \ atm}[/tex]
[tex]\mathbf{S_g =5.7 \times 10^7 \ g/mL}[/tex]
Thus, the percentage of CO2 remaining in the solution after the soft drink reaches equilibrium is:
[tex]\mathbf{=\dfrac{5.7\times 10^{-7}}{0.00675} \times 100 \%}[/tex]
[tex]\mathbf{=0.0084 \%}[/tex]
= 8.4 × 10⁻³ %
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identify two conjugate base for each compound HCN and HBr
The conjugate base of HCN is CN^-
The conjugate base of HBr is Br^-
how many cats are in the word
Answer: more than 70,00 and most of that population is living on the streets
HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Which of the following statements is true?
Some plants cannot reproduce.
Pollen contains male sperm cells.
Mitosis results in two non-identical cells.
Flowering plants reproduce using spores.
Answer:
errccvbnnbb
Explanation:
jjuxxxsyy
Answer:
i think it the third one
Explanation:
sorry if im wrong are u in biology?
For the reaction 2Na + Cl2 2NaCl, calculate the percent yield if
155.0 g of chlorine (Cl2) should be produced and your experiment
produced 143 g (C12).
Answer:
[tex]Y=92.25\%[/tex]
Explanation:
Hello there!
In this case, according to the given chemical reaction, it is possible for us to calculate the percent yield by dividing the actual yield of 143 grams of gaseous chlorine by the theoretical yield of 155 g of this gas. In such a way, we proceed as follows:
[tex]Y=\frac{143g}{155g} *100\%[/tex]
Which has a result of:
[tex]Y=92.25\%[/tex]
Regards!
How to do 3 and 4 questions
Answer:
3) Q = -836.8 J.
4) Q = 950J.
Explanation:
Hello there!
In this case, for those calorimetry problems, we use the general equation:
[tex]Q=mC\Delta T[/tex]
Thus, we proceed as follows:
3) Here, the temperature difference is from 80 °C to 40 °C, the mass is 5.0 g and the specific heat 4.184 in SI units; thus, the heat is calculated as follows:
[tex]Q=(5g)(4.184\frac{J}{g\°C} )(40\°C-80\°C)\\\\Q=-836.8J[/tex]
4) Here, the temperature difference is from 100 °C to 200 °C, the mass is 5.0 g and the specific heat about 1.90 in SI units; thus, the heat is calculated as follows:
[tex]Q=(5g)(1.90\frac{J}{g\°C} )(200\°C-100\°C)\\\\Q=950J[/tex]
Regards!
What happens when an electron moves to a higher energy level?
A. It releases energy of a specific frequency
B. It gains energy in a quantized amount.
C. It loses energy in the form of light.
D. It absorbs photons of many energies
ANSWER: B. It gains energy in a quantized amount.
Answer:
B. It gains energy in a quantized amount.
please help me with Chem I ONLY HAVE 5 MINUTES if methane gas (CH4) flows at a rate of 0.25L/s, how many grams of methane gas will there be in a room after 1 hour of time has passed?
Answer:
643g of methane will there be in the room
Explanation:
To solve this question we must, as first, find the volume of methane after 1h = 3600s. With the volume we can find the moles of methane using PV = nRT -Assuming STP-. With the moles and the molar mass of methane (16g/mol) we can find the mass of methane gas after 1 hour as follows:
Volume Methane:
3600s * (0.25L / s) = 900L Methane
Moles methane:
PV = nRT; PV / RT = n
Where P = 1atm at STP, V is volume = 900L; R is gas constant = 0.082atmL/molK; T is absolute temperature = 273.15K at sTP
Replacing:
PV / RT = n
1atm*900L / 0.082atmL/molK*273.15 = n
n = 40.18mol methane
Mass methane:
40.18 moles * (16g/mol) =
643g of methane will there be in the roomCarbon dioxide had how many nonbonding electron pairs in its electron arrangement?
A. 2
B. 4
C. 8
D. 6
E. 3
Answer: A.) 2 is the answer.
Explanation:
What piece of apparatus could be used to measure the volume of gas produced in a reaction
1)beaker
2)gas syringe
3) top pan balance
Answer: 2)gas syringe
Explanation:
the volume of a gas is usually measured with a gas syringe (or sometimes with an upside-down measuring cylinder)
Answer:
top pan balance
Explanation:
The compound AlP (aluminum phosphide) is a compound semiconductor having mixed ionic and covalent bonding. Calculate the fraction of bonding that is ionic.
Answer:
0.086
Explanation:
The formula for calculating the fraction of a covalent bond can be expressed as:
= exp (-0.25ΔE²)
[tex]= exp[-0.25(E_{Al}-E_{p})^2]---(1)[/tex]
from the equation above;
[tex]E_{Al}[/tex] = the electronegativity of aluminum
[tex]E_P[/tex] = electronegativity of phosphorus
Using the data from periodic table figures;
[tex]E_{Al}[/tex] = 1.5
[tex]E_P[/tex] = 2.1
∴
fraction of the covalent = exp[-0.25(1.5 - 2.1)²]
fraction of the covalent = exp(-0.09)
fraction of the covalent = 0.914
Now, the fraction of ionic bond will be = 1 - the fraction of covalent bond
= 1 - 0.914
∴
the fraction of bond that is ionic = 0.086
A substance in a specific state of matter with volume of 6 liters was transferred to a 12 liter container. The substance took up the
A. It is highly compressible.
B. It also has a definite shape.
C.Its particles slide past one another
D. Its intermolecular forces are of high strength.
[tex]\huge\color{yellow}\boxed{Answer:}[/tex]
My answer is C.Its particles slide past one another
[tex]\huge\color{yellow}\boxed{toshiro hitsugaya}[/tex]
When the 6 liters volume of the substance takes up 12 liter container, we conclude that the substace is highly compressible.
What is compressibility?
Compressibility is the measure of the relative volume change of a solid or a fluid with respect to pressure change.
Gases are the most compressible susbtance because most of the volume of a gas is composed of the large amounts of empty space between the gas particles.
Therefore, when the 6 liters volume of the substance takes up the entire volume of 12 liter container, we can conclude that the substace is highly compressible.
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When a lead acid car battery is recharged by the alternator, it acts essentially as an electrolytic cell in which solid lead(II) sulfate PbSO4 is reduced to lead at the cathode and oxidized to solid lead(II) oxide PbO at the anode.Suppose a current of 62.0 is fed into a car battery for 23.0 seconds. Calculate the mass of lead deposited on the cathode of the battery. Round your answer to 3 significant digits. Also, be sure your answer contains a unit symbol.
Answer: The mass of lead deposited on the cathode of the battery is 1.523 g.
Explanation:
Given: Current = 62.0 A
Time = 23.0 sec
Formula used to calculate charge is as follows.
[tex]Q = I \times t[/tex]
where,
Q = charge
I = current
t = time
Substitute the values into above formula as follows.
[tex]Q = I \times t\\= 62.0 A \times 23.0 sec\\= 1426 C[/tex]
It is known that 1 mole of a substance tends to deposit a charge of 96500 C. Therefore, number of moles obtained by 1426 C of charge is as follows.
[tex]Moles = \frac{1426 C}{96500 C/mol}\\= 0.0147 mol[/tex]
The oxidation state of Pb in [tex]PbSO_{4}[/tex] is 2. So, moles deposited by Pb is as follows.
[tex]Moles of Pb = \frac{0.0147}{2}\\= 0.00735 mol[/tex]
It is known that molar mass of lead (Pb) is 207.2 g/mol. Now, mass of lead is calculated as follows.
[tex]No. of moles = \frac{mass}{molar mass}\\ 0.00735 = \frac{mass}{207.2 g/mol}\\mass = 1.523 g[/tex]
Thus, we can conclude that the mass of lead deposited on the cathode of the battery is 1.523 g.
NEED HELP ASAP
Question 7 (5 points)
(05.05 MC)
A synthesis reaction takes place when carbon monoxide (CO) and hydrogen gas (H2) react to form methanol (CH3OH). How many grams of
methanol are produced when 7.0 grams of carbon monoxide reacts with excess hydrogen gas? (5 points)
20 grams
7.0 grams
8.0 grams
6.1 grams
Explanation:
Write the balance equation for the reaction taking place:
CO(g) + 2H2(g) ==> CH3OH ... balanced equation
Find the limiting reactant:
moles CO present = 14 g x 1 mol CO / 28 g = 0.5 moles COmoles H2 present = 1.5 g x 2 mol H2 / 2 g = 0.75 moles H2OBecause according to the balanced equation it takes 2 moles H2 for every 1 mole CO, there isn't enough H2, so it is limiting and will dictate how much CH3OH can be made.
Mass of CH3OH produced = 0.75 moles H2 x 1 mol CH3OH / 2 mol H2 x 32 g CH3OH / mol = 12 g CH3OH
12 points
Methyl methacrylate has a molar mass of 100 g/mole When a sample of methyl methacrylate weighing 3.14 g was completely combusted, the only products formed
were 6.91 g of CO2 and 2.26 g of water. What is methyl methacrylate's molecular formula?
O A C5H8O2
OBC6H120
OCC7H16
OD. None of the above
O E C4H403
Answer:
C₅H₈O₂
Explanation:
methyl methacrylate = 100 amu
6.91g CO₂ = 0.157 moles
2.26g H₂O = 0.125 moles
0.157 ÷ 0.125 = 1.256
{(CO₂)₁.₂₅₆ + (H₂O)₁} × 4 = (CO₂)₅ + (H₂O)₄
C₅H₈O?
C₅ = 60.05 amu H₈ = 8.064 amu
60.05 + 8.064 = 68.114 amu
100 amu - 68.114 amu = 31.886 amu
O = 16 amu
O = 2
The molecular formula of methyl methacrylate is C₅H₈O₂. The correct option is A, C₅H₈O₂.
What is methyl methacrylate?
Methyl methacrylate (MMA) is a colorless liquid monomer with a distinctive fruity odor. It is an organic compound that belongs to the family of acrylic esters.
We have to determine the empirical formula of methyl methacrylate first and then multiply it by the integer n to determine the molecular formula. Empirical formula:
CO₂ and H₂O are the combustion products of methyl methacrylate.
C₅H₈O₂ + (9n / 2)
O₂ → 5CO₂ + (n)H₂O
There are 5 C atoms and (8 + 2n), H atoms in the left and 5 C atoms, and n H atoms in the right.
5C = 5C, and 8 + 2n = nH.
n = 6
Molecular formula calculation is dividing the molecular weight by the empirical formula weight to determine the multiplication factor.
C₅HₙO₂ (empirical formula) has a weight of:
(5 x 12.011) + (8 x 1.008) + (2 x 15.999) = 100.12 g/mol
The actual molecular weight of methyl methacrylate is 100 g/mol.
Therefore, the molecular formula is (C₅H₈O₂) x 1, which is C₅H₈O₂, option A.
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Questions
Determine the primary and secondary valencies of the following complexes and calculate their spin only magnetic
moment.
iii. [Cu(OH2)6]504
i. K[TI(CN).]
ii. [V(NH3)4Br2]
iv. K3 [Cr(CN)6]
Answer:
yes
Explanation:
yes
Astronauts must be protected from extreme heat while
reentering the Earth's atmosphere. Scientists can use the
engineering design process to help make reentry safer.
You have defined the problem as a need for heat shields to be stronger. What
should be your next step in using the engineering design process to solve the
problem?
O A. Communicate your solution to your team members.
O B. Update your initial design for the heat shield.
O C. Identify the criteria and constraints of the project.
O D. Build a prototype of a possible new type of heat shield.
The next engineering step to be taken is to update your initial design for the heat shield.
What is a heat sheild?The term heat sheild refers to a device that can be used to shield an from astronaut extreme heat especially as they re-enter the earth's atmosphere.
After you have identified the problem, the next engineering step to be taken is to update your initial design for the heat shield.
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Name the following alkene:
CH3CH = CHCH2CH3
A. 3-pentane
B. 2-pentene
C. 2-pentane
D. 3-pentene
Answer:
2-pentene
Explanation:
The name of the alkene is 2 pentene. The correct option is B, 2-pentene.
What is 2-pentene?Alkenes with the chemical formula [tex]C_5H_10[/tex] are known as pentene. Within its molecular structure, each has one double bond.
The given alkene [tex]CH_3CH = CHCH_2CH_3[/tex] is 2-pentene because the double bond is present in the second carbon and it's pentene because there are five carbons present.
Thus, the correct option is B. 2-pentene.
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Hey duckers
Pp poopoo everyday
Answer:
So when a cat puts up its middle finger its usually trying to scare you off.
Explanation:
it's gonna kill you.
A 2.5 M solution of a weak acid is prepared. Using a pH meter, the pH is measured to be 5.1. Calculate the acid ionization constant, [tex]K_{a}[/tex] , of this weak acid.
Show your work
Molarity of acid=2.5M
pH=5.1.
ka=?
Now
We need to write an eqn to show the dissociation of the acid
HA + H2O === H3O+ + A-
Writing The Equilibrium(Or Acid dissociation constant) of this reaction
Ka =[H3O+] {A-]/ {HA].
The concept behind this is
concentration of Products divided by those of reactants. Water is not written because its a pure liquid and does not affect the Equilibrium constant.
Now If you have any Idea on ICE tables..
You'd know that the concentration of acid will decrease by 2.5-x
Whilst the products...will increase by x each
Note: This is when the ratio of their Moles are in 1:1
ka= x.x/2.5-x
Since the Moles of A- and H3O+ are in 1:1... Their concentrations at equilibrium will be the same
so
Ka= x²/2.5-x
Now what is x??
x is the Hydrozonium ion concentration.
we can get it from the pH formula
pH= -log (H3O+)
Making H3O+ subject by applying Logarithm Rules
H3O+ = 10^-ph
x=10^-5.1
=7.94x10^-6.
Now back to Ka
Ka= x²/2.5-x
Ka= (7.94x10^-6)²/2.5-(7.94x10^-6)
Ka= (7.94x10^-6)²/2.4999
Ka= 2.52x10^-11.
Was a Fun One
The ionization constant of this weak acid is [tex]2.52*10^{-11}[/tex]. The values can be substituted in dissociation formula.
What information do we have?
Molarity of acid=2.5M
pH=5.1
To find:
ka=?
Calculation of ionization constant:[tex]HA + H_2O < === > H_3O^+ + A^-[/tex]
The value of dissociation constant will be:
[tex]Ka =[H_3O^+] [A^-]/ {HA][/tex]
The Moles of A- and H3O+ are in 1:1.Their concentrations at equilibrium will be the same.
[tex]Ka= x.x/2.5-x\\\\Ka= x^2/2.5-x\\\\pH= -log (H_3O^+)\\\\H_3O^+ = 10^{-pH}\\\\x=10^{-5.1}\\\\x=7.94*10^{-6}[/tex]
[tex]Ka= x^2/2.5-x\\\\Ka= (7.94*10^{-6})^2/2.5-(7.94*10^{-6})\\\\Ka= (7.94*10^{-6})^2/2.4999\\\\Ka= 2.52*10^{-11}\\\\[/tex]
Thus, ionization constant of this weak acid is [tex]2.52*10^{-11}[/tex].
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Pbo.....
= 2Pb +......
Answer:
It's
Explanation:
Pbo + c
= pb + co2
While balancing it becomes
2pbo + c = 2pb + co2
(I was also doing same qn)
What happens in radioactive decay?
O A. An electron is lost to form a negatively charged particle.
O B. An unstable nucleus breaks down into smaller parts.
O C. Two smaller nuclei are joined to form one larger nucleus.
O D. A large nucleus breaks apart to form smaller nuclei.
SHIRME
A radioactive atom will spontaneously release radiation in the shape of energy rather than particles in order to transition into a more steady state.
Why is something radioactive?Radioactivity, as its name suggests, seems to be the act of generating radiation without any external cause. This is carried out by an unstable atomic nucleus that "wants" to abandon certain power in order to change to a more stable form.
Are people radioactive at all?Absolutely, since humans consume radioactive materials from the environment through food, drink, and air, our bodies are inherently radioactive. Our bodies take these substances in and store them in our bones, tissues, and organs. We also breathe them in and consume them.
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How many ions are in 1
mole of potassium sulfate?
Answer:
We will need two potassium ions to balance the charge on the sulfate ion, so the proper chemical formula is K 2SO 4.
Explanation:
hope this helps
Calculate the molar mass of Ca3(PO4)2
934.32 g Ca3(PO4)2 =______
moles Ca3(PO4)2
Answer:
Molar mass of Ca₃(PO₄)₂ = 310.18 g/mol934.32 g Ca₃(PO₄)₂ = 3.01 moles Ca₃(PO₄)₂Explanation:
The molar mass (MM) of Ca₃(PO₄)₂ can be calculated as follows:
MM of Ca₃(PO₄)₂ = (MM of Ca)*3 + [(MM of P) +(MM of O)*4]*2MM of Ca₃(PO₄)₂ = 310.18 g/molNow we can convert 934.32 g of Ca₃(PO₄)₂ into moles:
934.32 g ÷ 310.18 g/mol = 3.01 molesA chemistry student needs 30.0 g of acetic acid for an experiment. He has available 1.2 kg of a 7.58% w/w solution of acetic acid in acetone.
Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button.
Round your answer to 3 significant digits.
Answer:
The mass of solution will be "395.78 g".
Explanation:
Given:
Mass of acetic acid,
= 30 g
Percentage,
= 7.58% w/w
Now,
⇒ % [tex]=\frac{Mass \ of \ acetic \ acid}{Mass \ of \ solution}\times 100[/tex]
By putting the values, we get
⇒ [tex]7.58=\frac{30}{Mass \ of \ solution}\times 100[/tex]
⇒ [tex]Mass \ of \ solution=\frac{30\times 100}{7.58}[/tex]
⇒ [tex]=\frac{3000}{7.58}[/tex]
⇒ [tex]=395.78 \ g[/tex]
Considering the side chain of each of the amino acids at pH 7.4, is that amino acid classified at neutral, basic, or acidic? You are currently in a sorting module. Turn off browse mode or quick nav, Tab to items, Space or Enter to pick up, Tab to move, Space or Enter to drop. Neutral Basic Acidic
Answer:
Considering the side chain of each of the amino acids at pH 7.4, is that amino acid classified at neutral, basic, or acidic? You are currently in a sorting module. Turn off browse mode or quick nav, Tab to items, Space or Enter to pick up, Tab to move, Space or Enter to drop. Neutral Basic Acidic
The answer is in the the images. I have placed all the structures in the specific boxes. I hope this helps.
which best describes the type of titration for the graph below? O strong acid titrated with a strong base
O strong base titrated with a strong acid
O weak acid titrated with a strong base
O weak base titrated with a strong acid
Answer:
B. strong base titration with a strong acid
sodium is an inactive metal why
Answer:
Inactive metals are inert metals that doesn’t react with most of the chemicals.They are highly resistant to oxidation and corrosion when exposed to moisture.
Explanation:
What is the the heat of reaction, delta, in kJ/mol?
a) -26kJ/mol
b) -25kJ/mol
c) -10kJ/mol
d)-35kJ/mol
Answer:
b) -25 kJ/mol.
Explanation:
Hello there!
In this case, since the general definition of the enthalpy of reaction involves the subtraction of the energy of the products and the energy of the reactants:
[tex]\Delta H=H_{prod}-H_{react}[/tex]
Thus, since the graph shows that the energy of the products is 20 kJ/mol and that of reactants 45 kJ/mol, we will obtain:
[tex]\Delta H=20kJ/mol-45kJ/mol\\\\\Delta H=-25kJ/mol[/tex]
Which means it is exothermic.
Regards!
is a glow stick Endothermic or exothermic ?
Answer:
exothermic
Explanation:
How many neutrons are in an atom of argon–40?
Answer:
22 neutrons
Explanation:
If so please sorry