а)
In figure below, assume that a 20-mm-diameter rivet joins the plates that are each 110 mm
wide. The allowable stresses are 120 MPa for bearing in the plate material and 60 MPa for
shearing of rivet. Find the followings. Express your final answer in N/mm².
110 mm
20-mm
P
(1) Determine the minimum thickness of each plate and largest average tensile stress in the
plates.
(6 marks)

Answers

Answer 1

Image of the plate is missing, so i have attached it.

Answer:

A) t = 7.854 mm

B) σ = 26.67 MPa

Explanation:

A) From shearing of rivet, formula for pressure is;

P = τ•A_rivets

Where;

τ is allowable stress

A_rivets is Area of rivet

We are given:

τ = 60 MPa

Diameter; d = 20 mm

A_rivets = πd²/4 = π × 20²/4 = 100π

Thus;

P = 60 × 100π

P = 6000π N

From bearing of plate material, we can calculate pressure as;

P = σ_b•A_b

We are given;

σ_b = 120 MPa

A_b is area of plate = 20t

Where t is the thickness

Thus;

6000π = 120 × 20t

t = 6000π/(120 × 20)

t = 7.854 mm

B) Largest average tensile stress is given by the formula;

σ = P/A

Where A = 110t - 20t

A = 90t

A = 90 × 7.854

Thus;

σ = 6000π/(90 × 7.854)

σ = 26.67 MPa


Related Questions

Drag each label to the correct location on the image. Not all labels will be used, Classify the sides of the mountain range based on the direction of the prevailing winds leeward side windward side Jake-effect side
WILL MARK BRAINLIEST!​

Answers

Answer:

The picture didn't go thruuuuuuu

Answer:

hi

Explanation:

hi

What does the potential energy diagram of a chemical reaction tell you?
O A. Whether atoms are being created or destroyed
O B. Whether the reaction is endothermic or exothermic
C. Whether there are more reactants or products
D. Whether the law of conservation of matter is being obeyed

Answers

Answer:

B

Explanation:

I'm learning about this now actually and it can be a little confusing but it would be endothermic or exothermic. if endothermic the products have less energy than the reactants and if exothermic products have more energy than reactants

which of the following changes will increase the frequency of an oscillating pendulum?
a. an increase in the mass of the pendulum.
b. an increase in the initial height of release.
c. an increase in the length of the rope.
d. more than one of the above
e. none of the above
explain your answer in your own words.
NO LINKS.​

Answers

Answer:

b (i think)

Explanation:

Explain the mode of operation of x-ray​

Answers

Answer:

If x-rays get in touch with our body tissues, they create a picture of a metal film. The high energizing rays are unable to penetrate soft tissue, such as skin and organs and travel through the laser. The places where the x-rays pass soft tissues are Black areas of an X-ray.

Answer:

Explanation:

Mode of Operation: In the X-ray tube a Low voltage high p.d is applied between the hot cathode and the anode. Electrons are emitted from the cathode and are accelerated to an extremely high speed. ... They are produced by increasing the p.d. between the cathode and anode.

If a body of mass 2 kg is moving with a velocity of 30 m/s, then on doubling its velocity the momentum becomes______.
a-60kgm/s
b-120kgm/s
c-90kgm/s
D-30kgm/s​

Answers

I think it’s B. So 120kgm/s

Which quantity does not change when there is an increase in temperature?​

Answers

Answer:

But Mass of solids does not depend upon the temperature because it is matter contained in the solids.

Explanation:

The mass is the quantity which does not change when there is an increase in temperature.

What is mass?

A tangible body's mass is the amount of matter it possesses. It's also a metric of inertial, or the resistance to velocity when a net force is exerted.

The quantity does not change when there is an increase in temperature is mass because it is matter that makes up solids, their mass is unaffected by temperature.

Thus, the mass is the quantity which does not change when there is an increase in temperature.

Learn more about the mass here:

https://brainly.com/question/15959704

#SPJ2

A system is in liquid-vapor mixture of 0.5 kg of saturated water vapor and 0.5 kg
of saturated liquid. Calculate the quality.​

Answers

Answer:

x = 0.5 = 50%

Explanation:

The quality of a water liquid-vapor mixture can be defined as the fraction of water vapor present in the water liquid-vapor mixture. Therefore, it can be calculated by the use of the following formula:

[tex]x = \frac{m_{vap}}{m}[/tex]

where,

x = quality = ?

m_vap = mass of saturated water vapor = 0.5 kg

m = total mass = mass of saturated vapor + mass of saturated liquid

m = 0.5 kg + 0.5 kg = 1 kg

Therefore,

[tex]x = \frac{0.5\ kg}{1\ kg}[/tex]

x = 0.5 = 50%


What are 3 facts you learned about the periodic table:

Answers

Answer: the rarest element is Francium. J is not on the periodic table. also Dmitri Mendeleev proposed the periodic table.

Explanation: Kinda looked the last one up.

Un corredor hace los 400 metros lisos en 50 seg. Calcula la velocidad en la carrera.

Answers

Answer:

8 meters/second

Explanation:

Rate x Time = Distance

R x T = D

R x 50sec = 400meters

R x 50sec/50sec = 400meters/50sec

R = 8meters/sec

Future space stations could create an artificial gravity by rotating. Consider a cylindrical space station that rotates with a period of 28 seconds about its axis. Astronauts walk on the inside surface of the space station, and they experience an Earth-like gravitational acceleration of 9.8 m/s2. What is the diameter of the space station?
510m
145m
660m
390m​

Answers

Answer:

P = 2 pi R / v    period of space station

F / m = v^2 / R    centripetal force per unit of mass

So F / m = 4 pi^2 R^2 / (P^2 * R) = 4 pi^2 R / P^2

Also, F / m = 9.8 m/s^2   earth's gravitational attraction

So 9.8 = 4 pi^2 R / P^2    or    R = 9.8 P^2 / 4 * pi^2) = 195 m

Or D = 2 R = 390 m the diameter required

What is the term for the force that holds protons and neutrons together in the nucleus of
an atom?
a electromagnetism
b. gravity
c. the strong force
d the weak force

Answers

Protons and neutrons are held together in a nucleus of an atom by the strong force. C hope this helped!
C is the answer I took the test

what determines the strength of a base?

Answers

The higher the dissociation constant the stronger the acid or base. Since electrolytes are created as ions are freed into solution there is a relationship between the strength of an acid, a base, and the electrolyte it produces. Acids and bases are measured using the pH scale.

The higher the dissociation constant the stronger the acid or base. Since electrolytes are created as ions are freed into solution there is a relationship between the strength of an acid, a base, and the electrolyte it produces. Acids and bases are measured using the pH scale.

What is the frequency of microwaves of wavelength 3 cm?
Give your answer to the
nearest GHz and without units.

Answers

Answer:

10 GHz

Explanation:

Applying,

v = λf.................... Equation 1

Where v = speed of microwave, λ = wavelength, f = frequency.

make f the subject of the equation

f = v/λ................ Equation 2

Note: Microwave is an electromagnetic wave, and all electromagnetic wave have the same speed, which is 3×10⁸ m/s

From the question,

Given: λ = 3 cm = 0.03 m

Constant; v = 3×10⁸ m/s

Substitute these values into equation 2

f = 3×10⁸/(0.03)

f = 10¹⁰ Hz

f = (10¹⁰/10⁹) GHz

f = 10 GHz

A 6.00 kg object at rest is suddenly broken apart into two fragments by an explosion. The fragment with mass 3.50 kg is moving 24.0m/s to the left. The other fragment is moving _______m/s to the right. Group of answer choices

Answers

Answer: 33.6 m/s

Explanation:

Given

The initial mass of the object is [tex]6\ kg[/tex]

It breaks into two fragments of 3.5 and 2.5 kg

3.5 kg part moves at 24 m/s towards left

Suppose 2.5 kg part moves with a speed of v towards the right

As the center of mass is at rest before the collision, it continues to remain at rest after the collision.

[tex]\therefore 6\times 0=3.5\times 24-2.5\times v\\\Rightarrow 3.5\times 24=2.5\times v\\\\\Rightarrow v=33.6\ m/s[/tex]

Therefore, the velocity of 2.5 kg mass is 33.6 m/s towards right.



Descriptions of the sky at various locations on Earth

Answers

what are we suppose to do with this ?
Cloudy, Clear, Gloomy, Rainy, Dark, ect.

If the height is 10m, what is the potential energy? Asuming that the mass is 10

Answers

[tex]\huge{\textit{\sf{{\color{m}{Answer}}{\color{b}{࿐}}}}}[/tex]

we know,

[tex] \boxed{potential \: energy = mgh}[/tex]

So,

[tex]\longmapsto10 \times 9.8 \times 10[/tex]

[tex]\longmapsto980 \: joules[/tex]

A sample contains radioactive atoms of two types, A and B. Initially there are five times as many A atoms as there are B atoms. Two hours later, the numbers of the two atoms are equal. The half-life of A is 0.77 hours. What is the half-life of B in hours?

Answers

Answer:

Explanation:

Initially no of atoms of A = N₀(A)

Initially no of atoms of B = N₀(B)

5 X N₀(A)  = N₀(B)

N = N₀ [tex]e^{-\lambda t}[/tex]

N is no of atoms after time t , λ is decay constant and t is time .

For A

N(A) = N(A)₀ [tex]e^{-\lambda_1 t}[/tex]

For B

N(B) = N(B)₀ [tex]e^{-\lambda_2 t}[/tex]

N(A) = N(B) , for t = 2 h

N(A)₀ [tex]e^{-\lambda_1 t}[/tex] = N(B)₀ [tex]e^{-\lambda_2 t}[/tex]

N(A)₀ [tex]e^{-\lambda_1 t}[/tex] = 5 x N₀(A)  [tex]e^{-\lambda_2 t}[/tex]

[tex]e^{-\lambda_1 t}[/tex] = 5  [tex]e^{-\lambda_2 t}[/tex]

[tex]e^{\lambda_2 t}[/tex] = 5  [tex]e^{\lambda_1 t}[/tex]

half life = .693 / λ

For A

.77 =  .693 / λ₁

λ₁ = .9 h⁻¹

[tex]e^{\lambda_2 t}[/tex] = 5  [tex]e^{\lambda_1 t}[/tex]

Putting t = 2 h , λ₁ = .9 h⁻¹

[tex]e^{\lambda_2\times 2}[/tex] = 5  [tex]e^{.9\times 2}[/tex]

[tex]e^{\lambda_2\times 2}[/tex] = 30.25

2 x λ₂ = 3.41

λ₂ = 1.7047

Half life of B = .693 / 1.7047

= .4065 hours .

= .41 hours .

Which of the following statements correctly describe the various applications listed above?
a. None of these technologies use radio waves.
b. None of these technologies use lower-frequency microwaves.
c. None of these technologies use higher-frequency microwaves.
d. None of these technologies use infrared waves.
e. The radiation emitted by some wireless local area networks has the shortest wavelength of all the technologies listed above.
f. All these technologies emit waves with a wavelength in the range 0.10 to 10.0 cm.
g. All the technologies emit waves with a wavelength in the range 0.01 to 10.0 km.

Answers

Answer:

The answer is "c,d,e, and g".

Explanation:

The correct choices can be defined as follows:

Higher-frequency microwaves aren't used in any of these systems.Infrared waves aren't seen in each of these technologies.Its shortest wavelength of all of the technologies listed is the above radiation generated by certain wireless networks.These devices all produce waves of wavelengths ranging from 0.10 to 10.0 cm.

A solid, uniform sphere of mass 2.0 kg and radius 1.8 m rolls from rest without slipping down an inclined plane of height 7.5 m. What is the angular velocity of the sphere at the bottom of the inclined plane

Answers

Answer:

[tex]w^2=5.5rads/s[/tex]

Explanation:

From the question we are told that:

Mass [tex]m=2.0kg[/tex]

Radius [tex]r=1.8m[/tex]

Height [tex]h=7.5m[/tex]

Generally the equation for Potential energy is mathematically given by

Potential energy=Kinetic energy+Rotational energy

 [tex]mgh=\frac{1}{2}mv^2+\frac{1}{2}Iw^2[/tex]

Since there is no slipping

 [tex]v=rw[/tex]

Therefore

 [tex]mgh=\frac{1}{2}mr^2w^2+\frac{1}{2}Iw^2[/tex]

Where

      [tex]I=\frac{1}{2}mr^2[/tex]

      [tex]l=3.24m[/tex]

 [tex]2*9.81*7.5=\frac{1}{2}(2)(1.8)^2w^2+\frac{1}{2}(3.24)w^2\\\\[/tex]

 [tex]147.15=3.24w^2+1.62w^2[/tex]

 [tex]w^2=\frac{147.15}{4.86}[/tex]

 [tex]w^2=\sqrt{\frac{147.15}{4.86}}[/tex]

 [tex]w^2=5.5rads/s[/tex]

If I have a sphere rolling on a table with an initial velocity and then it falls off the edge of the table, from this point on it is taken as if my initial velocity were zero, or it starts from the initial velocity that I had before in the table?

Answers

Answer:

The initial velocity after leaving the table is the same as it was before leaving the table (nothing is present to produce discontinuties in the velocity).

Before leaving the table the vertical velocity was zero and is zero when it leaves the table.

The horizontal velocity is constant with no forces present to change the velocity.

A horizontal wire supports it weight in a 0.001T magnetic field, oriented orthogonally to the wire. This is due to current running from left to right in the wire. Calculate the current through this wire that will just support the weight of the wire (over the length of the wire). The length of the wire is 0.5 m, and the mass of the 0.5 m section is 50 g. [give your answer in units of Amps]

Answers

Answer:

Explanation:

Force on a current carrying wire in a magnetic field

= B i L where B is magnetic field , i is current and L is length of the wire .

Putting in the given values in the question

force on a current carrying wire in a magnetic field  = .001 T x i x .5 m

5 x 10⁻⁴ i  N .

weight of the wire = .050 kg x 9.8 m/s²

= .49 N .

For equilibrium

5 x 10⁻⁴ i  = .49

i = 980 A .

The instrument measuring the temperature change between inspired cool air and expired warm air is called?​

Answers

Answer:

It's called a Spirometer

a 4 kg block is moving at 12 m/s on a horizontal frictionless surface. a constant force is applied such that the block slows with an acceleration of 3 m/s^2. how much work must this force do to stop the block?
a. -576 J
b. -360 J
c. -288 J
d. 360 J
e. 576 J
walk me through this please. NO LINKS. ​

Answers

Answer:

Is there a picture?

Explanation:

a particle covers 10m distance in 2sec. if final velocity is 8m/s, find initial velocity​

Answers

Answer:

vi =2

Explanation:

Δx = 1/2 (vi + vf) t

10 = 1/2 ( vi + 8 ) 2

10 = vi + 8

10-8 = vi

vi = 2 m/s

vi= initial velocity

vf= final velocity

Δx= distance

t= time

An object has one force acting on it. It is a 33- Newton force pointing downward. To create a net force of zero on the object, which force must be applied to it?

Answers

As soon as I see "Which...", I know that the last part of the question is the list of answer choices, but you decided not to let us see them.

The answer is: A 33-Newton force pointing upward.

The planets and the asteroid belt orbit the Sun in __________. Multiple Choice a spherical distribution, whereas the Oort cloud of comets orbits in a plane planes, whereas the Oort cloud of comets has a spherical distribution orbits nearly identical to the Oort cloud of comets planes tilted at an angle to the plane of the Oort cloud of comets a spherical distribution similar to that of the Oort cloud of comets

Answers

Answer:

planes, whereas the Oort cloud of comets has a spherical distribution.

Explanation:

A planet can be defined as a large celestial body having sufficient mass to allow for self-gravity and make it assume a nearly circular shape (hydrostatic equilibrium), revolves in an orbit around the Sun in the solar system and has a cleared neighborhood.

Basically, the planets are divided into two (2) main categories and these includes;

I. Outer planets: these planets are beyond the asteroid belt and comprises of jupiter, saturn, uranus and neptune, from left to right of the solar system.

II. Inner planets: these planets are the closest to the sun and comprises of mercury, venus, earth and mars.

These outer planets are made mostly of gases (hydrogen and helium) causing them to be less dense than the solid inner planets. These gases are generally known to be less dense in terms of physical properties.

Oort cloud is also referred to as Opik and it typically comprises of icy pieces of planetesimals (space debris) that spherically surrounds the sun at distances ranging from about 3000 to 100,000 AU.

Hence, the planets and the asteroid belt orbit the Sun in planes, whereas the Oort cloud of comets has a spherical distribution.

A uniform rod of length 80cm rotated in the xy plane about a frictionless pin passing through one end (as shown in figure). If the angular
velocity of the rod is 4rad/s, find the linear velocity (in m/s) of its mid-point C
Rod
Pin
С
Select one:
O a. 0.5
O b. 1.6
O c. 1.3
O d. 0.8​

Answers

Answer:

Linear velocity (in m/s) = 1.6 m/s

Explanation:

Given:

Length of rotational plane = 80 cm

Angular  velocity of the rod = 4rad/s

Find:

Linear velocity (in m/s)

Computation:

Radius from mid point C = Length of rotational plane / 2

Radius from mid point C = 80 / 2

Radius from mid point C = 40 cm

Radius from mid point C = 0.4 m

Linear velocity (in m/s) = Angular  velocity of the rod x Radius from mid point C

Linear velocity (in m/s) = 0.4 x 4

Linear velocity (in m/s) = 1.6 m/s

You throw a ball straight up. Compare the sign of the work done by gravity while the ball goes up with the sign of the work done by gravity while it goes down.

a. Work is + on the way up and + on the way down
b. Work is + on the way up and - on the way down
c. Work is - on the way up and + on the way down
d. Work is - on the way up and - on the way down

Answers

Answer:

c. Work is - on the way up and + on the way down

Explanation:

Work done is given as the product of the applied force and the displacement of the object.

Work done = F x d

Work done = mg x d

where;

g is acceleration due to gravity = 9.8 m/s²

When the ball goes up, it moves against the force of gravity which tends to pull every object downwards. Since the ball moves against gravity, the work done is negative.

Also, when the ball goes down, it moves in the direction of gravity which acts downwards. Since the ball moves in the same direction as gravity, the work done is positive.

The correct option is "C. Work is negative (-) on the way up and positive (+) on the way down"

If you cut a permanent magnet into four pieces,
you will have what?

A) four temporary magnets
B) four smaller permanent magnets
C) two north poles and two south poles
D)four objects that are no longer magnets

Answers

you would have C) two north poles and two south poles

DESCRIBE THE REQUIREMENTS OF AN INTERNET CONNECTION?
please tell me the answer​

Answers

Answer: The basic requirements for connecting to the Internet are a computer device, a working Internet line, and the right modem for that Internet line. In addition, software programs such as Internet browsers, email clients, Usenet clients, and other special applications are needed in order to access the Internet.

Explanation: brainleist pls :)

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