Answer:
C.
Explanation:
Internet of things
The Basic premise of the Internet of Things is that objects can be tagged, tracked, and monitored through a local network, or across the Internet option (c) is correct.
What is IoT?The term "Internet of things" refers to actual physical items that have sensors, computing power, software, and other innovations and can link to those other systems and gadgets via the Internet or other communication networks and share files with them.
As we know,
Using a local network or the Internet, things may be identified, tracked, and monitored is the fundamental tenet of the Internet of Things.
Thus, the Basic premise of the Internet of Things is that objects can be tagged, tracked, and monitored through a local network, or across the Internet option (c) is correct.
Learn more about the IoT here:
https://brainly.com/question/25703804
#SPJ2
Two character strings may have many common substrings. Substrings are required to be contiguous in the original string. For example, photograph and tomography have several common substrings of length one (i.e., single letters), and common substrings ph, to, and ograph as well as all the substrings of ograph. The maximum common substring length is 6. Let X = X122 . Im and Y = yıy2 - - • Yn be two character strings. Using dynamic programming, design an algorithm to find the maximum common substring length for X and Y using dynamic programming. Please follow the general steps for designing a dynamic programming solution as in Q1 (other than the actual programming part).
Answer:
Explanation:
The following function is written in Java. It takes two strings as parameters and calculates the longest substring between both of them and returns that substring length.
import java.util.*;
class Test
{
public static void main(String[] args)
{
String X = "photograph";
String Y = "tomography";
System.out.println(X + '\n' + Y);
System.out.println("Longest common substring length: " + longestSub(X, Y));
}
static int longestSub(String X, String Y)
{
char[] word1 = X.toCharArray();
char[] word2 = Y.toCharArray();
int length1 = X.length();
int length2 = Y.length();
int substringArray[][] = new int[length1 + 1][length2 + 1];
int longestSubstringLength = 0;
for (int i = 0; i <= length1; i++)
{
for (int j = 0; j <= length2; j++)
{
if (i == 0 || j == 0)
substringArray[i][j] = 0;
else if (word1[i - 1] == word2[j - 1])
{
substringArray[i][j]
= substringArray[i - 1][j - 1] + 1;
longestSubstringLength = Integer.max(longestSubstringLength,
substringArray[i][j]);
}
else
substringArray[i][j] = 0;
}
}
return longestSubstringLength;
}
}
Taran is concerned with the security of his macros in a database. Which security option could he use to provide protection?
digital signatures
hide database objects
start-up options
secure VBA code
Answer:security VBA code
Explanation:
Write an algorithm (pseudo-code) that takes an unsorted list of n integers and outputs a sorted list of all duplicate integers. There must be no duplicates in the output list, also the output list should be a sorted list. The algorithm must run in O(n) time. Show your analysis of the running time. Note: Assume that inputs are integer values from 0 to 255. (Hint: use the concept that being used in the separate chaining)
Answer:
brainliest if it did help you
Explanation:
Given array : A[0...n-1]Now, create a count array Cnt[0...n-1]then, initialize Cnt to zero
for(i=0...n-1)
Cnt[i]=0 ---------O(n) time
Linearly traverse the list and increment the count of respected number in count array.
for(i=0...n-1)
Cnt[A[i]]++; ---------O(n) time
Check in the count array if duplicates exist.
for(i=0...n-1){
if(C[i]>1)
output (i); -----------O(n) time
}
analysis of the above algorithm:
Algorithm takes = O(1 + n + n + n)
= O(n)
//java code
public class SortIntegers {
public static void sort(int[] arr) {
int min = arr[0];
int max = arr[0];
for (int i = 0; i < arr.length; ++i) {
if (arr[i] > max) {
max = arr[i];
}
if (arr[i] < min) {
min = arr[i];
}
}
int counts[] = new int[max - min + 1];
for (int i = 0; i < arr.length; ++i) {
counts[arr[i] - min]++;
}
for (int i = 0; i < counts.length; ++i) {
if (counts[i] > 1) {
System.out.print((i + min) + " ");
}
}
System.out.println();
}
public static void main(String[] args) {
sort(new int[] { 5, 4, 10, 2, 4, 10, 5, 3, 1 });
}
}
Which tab can be used to change the theme and background style of a presentation?
O Design
O Home
O Insert
O View
Answer:
Design
Explanation:
seems the most correct one..
The variable strFirst's scope is _____.
Answer:
- the usernameMaker function
Explanation:
When you look at the code, you can see it's located alongside the usernameMaker. It it only utilized then, therefore being it's scope. For reassurance, it's also correct on Edge.
I hope this helped!
Good luck <3