A=6
B=8
The measure of c is

Answer:

[tex]\displaystyle dy = 25e^{5x}dx\\dy = 3.27 \cdot 10^7[/tex]

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Calculus

Derivatives

Derivative Notation

Differentials

Basic Power Rule:

eˣ Derivative: [tex]\displaystyle \frac{dy}{dx}[e^u] = u'e^u[/tex]

Step-by-step explanation:

Part A

Step 1: Define

[tex]\displaystyle y = 5e^{5x}[/tex]

Step 2: Differentiate

Part B

Step 1: Define

[Differential] [tex]\displaystyle dy = 25e^{5x}dx[/tex]

[Given] x = 3, dx = 0.4

Step 2: Evaluate

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Differentials

Book: College Calculus 10e

Answer:

b.5 hours

520-195=325

325/65=5

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

........................ .....

Answer:

120.4ft

Step-by-step explanation:

Find the diagram in the attachment.

The triangle shown is a right angled triangle with the side DE as the hypotenuse, EF is adjacent side while DF is the opposite side.

To get DE, we will use the SOH CAH TOA trigonometry identity

Using CAH which is defined as:

Cos(theta) = Adjacent/Hypotenuse

Cos 79°= 23/Hypotenuse

Hypotenuse = 23/cos79°

Hypotenuse = 23/0.191

Hypotenuse = 120.4feet

DE = 120.4feet (to nearest tenth)

Answer:

18x - 30

Step-by-step explanation:

in order to expand the expression, you need to use the distributive property to simplify 6(3x - 5).

first, distribute 6 to 3x, which is just 6 • 3x.

now distribute 6 to -5, which is just 6 • -5.

therefore, 6(3x - 5) expanded is 18x - 30 :) i hope this helps!! have a lovely rest of your day <3

Answer:

hi

Step-by-step explanation:

Find an answer to your question The volume of the box is 448 ft'. Find its length and width. 4 ft X-6 X The box has a length of ft and a width of ft.

hope this helps

Answer:

4 1/12

Step-by-step explanation:

Answer: 4 1/2

cause it is

Answer:

1) Between 12.5 miles and 21.7 miles.

2) b) 75%

3) c) 95%

4) Between 13.7 miles and 20.5 miles.

Step-by-step explanation:

Empirical Rule:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

Chebyshev Theorem:

The Chebyshev Theorem can also be applied to non-normal distribution. It states that:

At least 75% of the measures are within 2 standard deviations of the mean.

At least 89% of the measures are within 3 standard deviations of the mean.

An in general terms, the percentage of measures within k standard deviations of the mean is given by [tex]P = 100(1 - \frac{1}{k^{2}})[/tex].

1) According to Chebyshev's theorem, at least 36% of the commute distances lie between miles and miles.

Within k standard deviations of the mean, and k is found when [tex]P = 36[/tex]. So

[tex]P = 100(1 - \frac{1}{k^{2}})[/tex]

[tex]36 = 100 - \frac{100}{k^2}[/tex]

[tex]\frac{100}{k^2} = 64[/tex]

[tex]64k^2 = 100[/tex]

[tex]k^2 = \frac{100}{64}[/tex]

[tex]k = \sqrt{\frac{100}{64}}[/tex]

[tex]k = \frac{10}{8}[/tex]

[tex]k = 1.25[/tex]

Within 1.25 standard deviations of the mean.

1.25*3.7 = 4.6 miles

17.1 - 4.6 = 12.5 miles

17.1 + 4.6 = 21.7 miles

Between 12.5 miles and 21.7 miles.

2) According to Chebyshev's theorem, at least of the commute distances lie between 9.7 miles and 24.5 miles.

17.1 - 9.7 = 24.5 - 17.1 = 7.4 miles, so within 2 standard deviations of the mean, which is 75%, option B.

3) Suppose that the distribution is bell-shaped. According to the empirical rule, approximately of the commute distances lie between 9.7 miles and 24.5 miles.

Within 2 standard deviations of the mean, by the Empirical Rule, which is 95%, option c.

4) Suppose that the distribution is bell-shaped. According to the empirical rule, approximately 68% of the commute distances lie between miles and miles.

Within 1 standard deviation of the mean.

17.1 - 3.4 = 13.7

17.1 + 3.4 = 20.5

Between 13.7 miles and 20.5 miles.

Answer:

29

Step-by-step explanation:

32 can be created from 4 x 8, so it is not.

42 can be created from 6 x 7, so it is not.

15 can be created from 5 x 3, so it is not.

29 cannot be created from any numbers multiplied.

Answer:

5.5n -2 -0.5p

Step-by-step explanation:

Make Everything to either decimals or fractions.

then simplify as shown

Answer: n=

−z2−5

z

Step-by-step explanation:

Let's solve for n.

(−n)(z)−z2−2=3

Step 1: Add z^2 to both sides.

−nz−z2−2+z2=3+z2

−nz−2=z2+3

Step 2: Add 2 to both sides.

−nz−2+2=z2+3+2

−nz=z2+5

Step 3: Divide both sides by -z.

−nz

−z

=

z2+5

−z

Answer:

-z^2-5z

Step-by-step explanation:

To evaluate a polynomial at a given value, we substitute the given value for the variable and then simplify using order of operations. We are given n=3, so we substitute 3 for n in the polynomial −nz−z2−2z and simplify as follows.

−nz−z2−2z

−(3)z−z2−2z

−3z−z2−2z

−z2−5z

Answer:

83.4

Step-by-step explanation:

16.2 x 2

=

32.4 +

1/2 x 8.5 x 12  

=

51 + 32.4 = 83.4

Hope this helps!

Answer:

An inequality sign is like an equal sign with a line through it

so, like, if you put = and / together

Answer:

<, >, =>, =<

Step-by-step explanation:

Given:

The two ratios are 13:15 and 30:26.

To find:

Whether the given ratios are equivalent or not.

Solution:

Two ratios are equivalent if the values of the ratio are equal after simplification.

[tex]13:15=\dfrac{13}{15}[/tex]

And,

[tex]30:26=\dfrac{30}{26}[/tex]

[tex]30:26=\dfrac{15}{13}[/tex]

[tex]30:26=15:13[/tex]

The first ratio is 13:15 and the value of second ratio after simplification is 15:13 both ratios are different, so,

[tex]\dfrac{13}{15}\neq \dfrac{30}{26}[/tex]

Therefore, the required answer is "No", the given ratios are not a pair of equivalent ratios.

Answer:

ella tiene que pagar 10 por mes. lo siento si no es así, esa no es la respuesta correcta.

Step-by-step explanation:

Answer:

Step-by-step explanation:

I thought those lines mean that they are equal meaning that the number is 68.

Answer:

B

Step-by-step explanation:

Answer:

[tex]t = 4b + 10c[/tex]

Step-by-step explanation:

Given

1 bag = 4 doughnuts

1 carton = 10 doughnuts

Required

Determine the amount of doughnuts in b bags and c cartons

If 1 bag contains 4 doughnuts, then b bags contain 4b doughnuts

If 1 carton contains 10 doughnuts, then c cartons contain 10b doughnuts

So, the total (t) is calculated by adding up the amount of doughnuts in the cartons and the bags:

i.e.

[tex]t = 4b + 10c[/tex]

Answer:

can confirm guy or girl above me

Step-by-step explanation:

The solution to the equation is y=14/15.

The given equation is -3y+2/3=2y-4.

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

Now, transpose -3y to RHS and simplify.

That is, 2/3=5y-4

Transpose -4 to LHS and simplify.

That is, 14/3=5y

Multiply by 1/5 on both sides of the equation.

So, 14/3×1/5=5y×1/5

⇒y=14/15

Therefore, the solution to the equation is y=14/15.

To learn more about the equation visit:

https://brainly.com/question/10413253.

SPJ5

Answer:11.39

Step-by-step explanation:

multiplication of the gradients of the two diagonals is equals to -1 if they are perpendicular

Answer:

$12,000.

Step-by-step explanation:

Given that in the year 2001, a person bought a new car for $ 15500, and for each consecutive year after that, the value of the car depreciated by 5%, to determine how much would the car be worth in the year 2005, to the nearest hundred dollars, the following calculation must be performed:

100-5 = 95

15,500 x 0.95 x 0.95 x 0.95 x 0.95 x 0.95 = X

14.725 x 0.95 x 0.95 x 0.95 x 0.95 = X

13,988.75 x 0.95 x 0.95 x 0.95 = X

13,289.3125 x 0.95 x 0.95 = X

12,624.846875 x 0.95 = X

11.993.60453125 = X

Thus, to the nearest hundred dollars, the cost of the car after 5 years will be $ 12,000.

Answer:

I would have to say A

Step-by-step explanation:

B has 2 of the same variables while A has to different variables and C&D have no variables there for the answer is A

Answer:

The distance is less than 216 inches.

Step-by-step explanation:

Each feet has 12 inches.

The large shelves in the storage area are 17 feet 8 inches apart

So, in inches, this distance is of:

17*12 + 8 = 212

This distance is less than 216 inches.

Answer:

Step-by-step explanation:

25

Answer:

B

Step-by-step explanation:

Answer:

Answer:48 cubes

You could fit 48 cubes with side lengths of 1/3 cm inside a rectangular prism with dimensions of 1 cm X 2 2/3 cm X 2/3 cm.

I hope it's helpful!

Answer:

a. [tex]dA(t)/dt = 50 - \frac{7A(t)}{400} where A(0) = 400[/tex]

b. [tex]A(t) = \frac{20000}{7} + \frac{17200}{7}e^{-7t/400}[/tex]

c. 3.717 kg

Step-by-step explanation:

a) Write the differential equation that represents the problem.

Let A(t) be the amount of dissolved oxygen in the tank at any time, t.

The net flow rate dA(t)/dt = mass flow in - mass flow out

Since 10 g/l of oxygen flows in at a rate of 5 l/min, the mass flow in is 10 g/l × 5 l/min = 50 g/min

Since A(t) is the amount of oxygen present in the tank at time, t, and the volume of the tank is 400 liters. The concentration of oxygen in the tank is thus A(t)/400 g/l.

Also, water is being pumped out at a rate of 7 l/min. So, the mass flow out is thus concentration × flow rate out = A(t)/400 g/l × 7 l/min = 7A(t)/400 g/min

So, dA(t)/dt = mass flow in - mass flow out

dA(t)/dt = 50 - 7A(t)/400 with A(0) = 400 l × 1 g/l = 400 g since the tank initially contains 1 g/l of dissolved oxygen and has a volume of 400 l

So, the differential equation is

dA(t)/dt = 50 - 7A(t)/400  where A(0) = 400 g

[tex]dA(t)/dt = 50 - \frac{7A(t)}{400} where A(0) = 400[/tex]

b) Solve the differential equation

To solve the equation, we use separation of variables, so

dA(t)/dt = 50 - 7A(t)/400  where A(0) = 400 g

dA(t)/(50 - 7A(t)/400) = dt

Integrating both sides, we have

∫dA(t)/(50 - 7A(t)/400) = ∫dt

-7/400 ÷ -7/400∫dA(t)/(50 - 7A(t)/400) = ∫dt

1/ (-7/400)∫-7/400dA(t)/(50 - 7A(t)/400) = ∫dt

(-400/7)㏑(50 - 7A(t)/400) = t + C

㏑(50 - 7A(t)/400) = -7t/400 + (-7/400)C

㏑(50 - 7A(t)/400) = -7t/400 + C'     (C' = (-7/400)C)

taking exponents of both sides, we have

50 - 7A(t)/400 = exp[(-7t/400) + C']

50 - 7A(t)/400 = exp(-7t/400)expC'

[tex]50 - \frac{7A(t)}{400} = e^{-7t/400}e^{C'} \\50 - \frac{7A(t)}{400} = Ae^{-7t/400} A = e^{C'}\\ \frac{7A(t)}{400} = 50 - Ae^{-7t/400} \\A(t) = \frac{400}{7} X 50 - \frac{400}{7} Ae^{-7t/400} \\A(t) = \frac{20000}{7} - \frac{400}{7} Ae^{-7t/400}[/tex]

when t = 0 , A(0) = 400. So,

[tex]A(t) = \frac{20000}{7} - \frac{400}{7} Ae^{-7t/400} \\A(0) = \frac{20000}{7} - \frac{400}{7} Ae^{-7(0)/400}\\A(0) = \frac{20000}{7} - \frac{400}{7} Ae^{0/400}\\A(0) = \frac{20000}{7} - \frac{400}{7} Ae^{0}\\A(0) = \frac{20000}{7} - \frac{400}{7} A\\400 = \frac{20000}{7} - \frac{400}{7} A\\\frac{400}{7} A = 400 - \frac{20000}{7}\\\frac{400}{7} A = \frac{2800}{7} - \frac{20000}{7}\\\frac{400}{7} A = -\frac{17200}{7}\\\\A = -\frac{17200}{7} X \frac{7}{400} \\A = -43[/tex]

So,

[tex]A(t) = \frac{20000}{7} - \frac{400}{7} X -43e^{-7t/400} \\A(t) = \frac{20000}{7} + \frac{17200}{7}e^{-7t/400}[/tex]

c) At 1 p.m., what is the amount of dissolve oxygen in the fish tank.

At 1 p.m, t = 60 min

So, the amount of dissolved oxygen in the fish tank is A(60)

So,

[tex]A(t) = \frac{20000}{7} + \frac{17200}{7}e^{-7t/400}\\A(60) = \frac{20000}{7} + \frac{17200}{7}e^{-7X60/400}\\A(60) = \frac{20000}{7} + \frac{17200}{7}e^{-420/400}\\A(60) = \frac{20000}{7} + \frac{17200}{7}e^{-1.05}\\A(60) = \frac{20000}{7} + \frac{17200}{7} X 0.3499\\A(60) = \frac{20000}{7} + \frac{6018.93}{7} \\A(60) = \frac{26018.93}{7} \\A(60) = 3716.99 g[/tex]

A(60) ≅ 3717 g

A(60) ≅ 3.717 kg

Answer:

[tex]\displaystyle d = 4\sqrt{5}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Algebra II

Step-by-step explanation:

Step 1: Define

Point (-5, 6) → x₁ = -5, y₁ = 6

Point (3, 2) → x₂ = 3, y₂ = 2

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d