Explanation:
We have these reasons below as the
The reason why sales users are not able to select the new record type while they are trying to create a new account:
1. The users profile does not contain the record type yet. That is, this record type has not been added to the profile of the sales user.
2. This record type is yet to be activated.
In this exercise, you will get some practice with the __add__ method by implementing it for a class called ContactBook. This class represents a collection of names and phone numbers. ContactBook stores its information as a dictionary, where the key is a name and the value is a phone number or group of phone numbers. The keys and values in this dictionary are stored as strings. When printed, a ContactBook might look like this:
Answer:
class ContactBook():
def __init__(self):
self.contacts ={}
def __repr__(self):
return str(self.contacts)
def add_contact(self,name,number):
self.contacts[name] = number
def __add__(self, other):
new_contact = ContactBook()
other_contact = other.contacts.keys()
for name,num in self.contacts.items():
if name in other_contact:
new_contact.add_contact(name,num or other_contact[name])
else:
new_contact.add_contact(name,num)
for name,num in other.contacts.items():
if name not in self.contacts:
new_contact.add_contact(name, num)
return new_contact-
cb1 = ContactBook()
cb2 = ContactBook()
cb1.add_contact('Jonathan','444-555-6666')
cb1.add_contact('Puneet','333-555-7777')
cb2.add_contact('Jonathan','222-555-8888')
cb2.add_contact('Lisa','111-555-9999')
print(cb1)
print(cb2)
cb3 = cb1+cb2
print(cb3)
Explanation:
The ContactBook class holds the contact details of an instance of the class. The class has three magic methods the '__repr__', '__init__', and the '__add__' which is the focus of the code. The add magic method in the class adds the contact book (dictionary) of two added object instance and returns a new class with the contact details of both operand instances which is denoted as self and other.
If you have an array of 100 sorted elements, and you search for a value that does not exist in the array using a binary search, approximately how many comparisons will have to be done?
a)7
b)100
c)50
Answer:
50
Explanation:
as binary search will search the array by dividing it into two halves till it find the value.