A sample of krypton gas occupies a volume of 9.87 L at 51°C and 0.565 atm. If it is desired to decrease the volume of the gas sample to 8.05 L, while increasing its pressure to 0.678 atm, the temperature of the gas sample at the new volume and pressure must be___________ °C.

Answer:

El número de átomos de una molécula depende de la "valencia" de los elementos, ya que es la capacidad de la unión de los átomos.

Explanation:

La valencia de un elemento se define como la medida de la capacidad de combinación de un elemento. Es la capacidad de combinación de un elemento con otros elementos para formar un compuesto químico o molécula.

Básicamente es el número de electrones de valencia que un elemento puede perder, ganar o compartir para formar enlaces químicos requeridos a partir de compuestos o moléculas.

¡¡¡Espero que esto ayude!!!

English Translation

The number of atoms of a molecule depends on the "valency" of the elements since it is the capacity of the union of atoms.

The valency of an element is defined as the measure of the combining ability of an element. It is the combining capacity of an element with other elements to form a chemical compound or molecule.

It is basically the number of valence electrons that an element can lose, gain or share in order to form chemical bonds required to from compounds or molecules.

Hope this Helps!!!

Answer:

i hope it will help you

Explanation:

electronic configuration 1s²,2s,²2p^6,3s²3p^6,4s^1

as it has one electron in its valence shell so it is the member of group 1A(ALKALI METALS)  and the number of shells is 4 so it is in period 4

Answer:

[tex]Y=58.15\%[/tex]

Explanation:

Hello,

For the given chemical reaction:

[tex]Al_2S_3(s) + 6 H_2O(l) \rightarrow 2 Al(OH)_3(s) + 3 H_2S(g)[/tex]

We first must identify the limiting reactant by computing the reacting moles of Al2S3:

[tex]n_{Al_2S_3}=5.00gAl_2S_3*\frac{1molAl_2S_3}{150.158 gAl_2S_3} =0.0333molAl_2S_3[/tex]

Next, we compute the moles of Al2S3 that are consumed by 2.50 of H2O via the 1:6 mole ratio between them:

[tex]n_{Al_2S_3}^{consumed}=2.50gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{1molAl_2S_3}{6molH_2O}=0.0231mol Al_2S_3[/tex]

Thus, we notice that there are more available Al2S3 than consumed, for that reason it is in excess and water is the limiting, therefore, we can compute the theoretical yield of Al(OH)3 via the 2:1 molar ratio between it and Al2S3 with the limiting amount:

[tex]m_{Al(OH)_3}=0.0231molAl_2S_3*\frac{2molAl(OH)_3}{1molAl_2S_3}*\frac{78gAl(OH)_3}{1molAl(OH)_3} =3.61gAl(OH)_3[/tex]

Finally, we compute the percent yield with the obtained 2.10 g:

[tex]Y=\frac{2.10g}{3.61g} *100\%\\\\Y=58.15\%[/tex]

Best regards.

Answer: Equilibrium constant for this reaction is [tex]2.8 \times 10^{15}[/tex].

Explanation:

Chemical reaction equation for the formation of nickel cyanide complex is as follows.

[tex]Ni(OH)_{2}(s) + 4CN^{-}(aq) \rightleftharpoons [Ni(CN)_{4}^{2-}](aq) + 2OH^{-}(aq)[/tex]

We know that,

      K = [tex]K_{f} \times K_{sp}[/tex]

We are given that, [tex]K_{f} = 1.0 \times 10^{31}[/tex]

and,    [tex]K_{sp} = 2.8 \times 10^{-16}[/tex]

Hence, we will calculate the value of K as follows.

     K = [tex]K_{f} \times K_{sp}[/tex]

     K = [tex](1.0 \times 10^{31}) \times (2.8 \times 10^{-16})[/tex]

        = [tex]2.8 \times 10^{15}[/tex]

Thus, we can conclude that equilibrium constant for this reaction is [tex]2.8 \times 10^{15}[/tex].

Answer:

109

Explanation:

Let silver-107 be isotope A

Let silver-109 be isotope B

Let silver-107 abundance be A%

Let silver-109 abundance be B%

The following data were obtained from the question:

Atomic weight of silver = 108

Mass of isotope A (silver-107) = 107

Abundance of isotope A (silver-107) = 51.8%

Abundance of isotope B (silver-109) = 48.2%

Mass of isotope B (silver-109) =?

Now, we shall determine the mass silver-109 as follow:

Atomic weight = [(Mass of A x A%)/100] + [(Mass of B x B%)/100]

108 = [(107 x 51.8)/100] + [(Mass of B x 48.2)/100]

108 = 55.426 + (Mass of B x 0.482)

Collect like terms

Mass of B x 0.482 = 108 – 55.426

Mass of B x 0.482 = 52.574

Divide both side by 0.482

Mass of B = 52.574/0.482

Mass of B = 109

Therefore, the mass of silver-109 is 109.

Answer:

certain lightbulb containing argon at 1.20 atm and 18 0 C is heated to 85 0 C at constant volume. What is the final pressure of argon in the lightbulb (in atm)? P 1 T 1 P 2 T 2 ... Ideal Gas Equation 5.4 Charles' law: V T (at constant n and P ) ... Consider a case in which two gases, A and B , are in a container of volume V.

Explanation:

Answer:

The boiling and freezing temperatures of krypton at absolute scale are 119.95 K and 116.05 K, respectively.

Explanation:

The absolute temperature on SI units corresponds to Kelvin scale, whose conversion formula in terms of the Celsius scale is:

[tex]T_{K} = T_{C} + 273.15[/tex]

Where:

[tex]T_{K}[/tex] - Absolute temperature, measured in Kelvins.

[tex]T_{C}[/tex] - Relative temperature, measured in Celsius.

Finally, freezing and boiling temperatures are converted into absolute scale:

Boiling temperature

[tex]T_{K} = (-153.2 + 273.15)\,K[/tex]

[tex]T_{K} = 119.95\,K[/tex]

Freezing temperature

[tex]T_{K} = (-157.1 + 273.15)\,K[/tex]

[tex]T_{K} = 116.05\,K[/tex]

The boiling and freezing temperatures of krypton at absolute scale are 119.95 K and 116.05 K, respectively.

Answer:

The correct option is b) SO₃(g) + NO(g) ⇌ SO₂(g) + NO₂(g)

Explanation:

The relation between Kc and Kp is given by the following equation:

[tex]Kp = Kc (RT)^{dn}[/tex]

where R is the gas constant (0,082 L.atm/K.mol), T is the temperature (in K) and dn is the change in moles.

The change in moles (dn) is calculated as:

dn = moles of products - moles reactants

If dn=0, RT= 1 ⇒ Kc=Kp

We calculate dn for each reaction from the estequiometrial coefficients of products and reactants as follows:

a) 4 NH₃(g) + 3 O₂(g) ⇌ 2 N₂(g) + 6 H₂O(g)

dn= (2+6) - (4+3) = 1 ⇒ Kc ≠ Kp

b) SO₃(g) + NO(g) ⇌ SO₂(g) + NO₂(g)

dn = (1+1) - (1+1)= 0 ⇒ Kc = Kp

c) 2 N₂(g) + O₂(g) ⇌ 2 N₂O(g)

dn= 2 - (2+1) = -1 ⇒ Kc ≠ Kp

d) 2 SO₂(g) + O₂(g) ⇌ 2 SO₃(g)

dn = 2 - (2+1) = -1 ⇒ Kc ≠ Kp

The reaction in which Kc=Kp is b), because reactants and products have the same number of moles.

Answer:

If it loses 2 electrons, the net charge on the atom will be 2+

If the atom instead gains 4 electrons, the net charge will be 4-

Explanation:

It is based on adding and subtracting charges. Protons are +1 and electrons are -1

If the atom has 9 protons and 9 electrons, the net charge is +9 + (-9) = 0. The +9 is the 9 protons and the -9 is from the 9 electrons.

If two electrons are taken away, there would be 9-2 or 7 electrons with 9 protons. The net charge would then be +9 + (-7) = +2. +9 comes from the 9 electrons and -7 is from the 7 electrons.

So, if two electrons are taken away, the net charge is +2.

Similarly, if the atom gains 4 electrons, there will be 9+4 or 12 electrons and 9 protons. The net charge would then be +9 + (-12) = -4. +9 comes from the 9 protons and -12 comes from the 12 electrons.

So, if 4 electrons are added, the net charge is -4.

Answer:

It was because the vaccine generated actively acquired immunity, that is, inoculation of a portion of the measles virus so that the body forms the antibodies for a second contact and thus can destroy it without triggering the pathology.

Explanation:

Vaccines are methods of active acquired immunity since the antibody is not passively inoculated, it is manufactured by the body with a physiological process once part of the virus is inoculated.

The measles virus most of all affected the lives of infants or newborn children with severe rashes and high fevers that led to death.

Answer:

128 gram of CaC2O4 contains 40 gram of Calcium

40.3 gram of CaC2O4 cotnains = 40*40.3/128 = 12.59 gram of Calcium

out of 15 gram 12.59 gram is Calcaim that means around 50% of orginal sample has Calcium

Answer:

Ba>Sn>Pb>As>S

Explanation:

Hello,

In this case, we can write the atomic radius for the given elements:

[tex]r_{Ba}=268pm\\r_{Sn}=225pm\\r_{S}=100pm\\r_{Pb}=202pm\\r_{As}=185pm[/tex]

In such a way, the required order is:

Ba>Sn>Pb>As>S

This is also in agreement as a periodic trend which states that the higher the period, the higher the radius.

Regards.

Answer:

5) 1.147 moles Cl2

6) 12.57 grams ClF3

7)  339.10 grams ClF3

8) 5.63 grams F2

Explanation:

Step 1: Data given

Number of moles F2 = 3.44 moles

Molar mass F2 = 38.00 g/mol

Step 2: The balanced equation

Cl2 + 3F2 → 2ClF3

Step 3: Calculate moles F2

For 1 mol Cl2 we need 3 moles F2 to produce 2 moles ClF3

For 3.44 moles F2 we'll need 3.44/3 = 1.147 moles Cl2

Step 1: Data given

Number of moles F2 = 0.204 moles

Molar mass F2 = 38.00 g/mol

Molar mass ClF3 = 92.448 g/mol

Step 2: The balanced equation

Cl2 + 3F2 → 2ClF3

Step 3: Calculate moles ClF3

For 1 mol Cl2 we need 3 moles F2 to produce 2 moles ClF3

For 0.204 moles F2 we'll have 2/3 * 0.204 = 0.136 moles

Step 4: Calculate mass ClF3

Mass ClF3 = Moles ClF3 * molar mass ClF3

Mass ClF3 = 0.136 moles * 92.448 g/mol

Mass ClF3 = 12.57 grams ClF3

Step 1: Data given

Mass of Cl2 = 130.0 grams

Molar mass F2 = 38.00 g/mol

Molar mass ClF3 = 92.448 g/mol

Step 2: The balanced equation

Cl2 + 3F2 → 2ClF3

Step 3: Calculate moles Cl2

Moles Cl2 = mass Cl2 / molar mass Cl2

Moles Cl2 = 130.0 grams / 70.9 g/mol

Moles Cl2 = 1.834 moles

Step 4: Calculate moles

For 1 mol Cl2 we need 3 moles F2 to produce 2 moles ClF3

For 1.834 moles Cl2 e'll have 2*1.834 = 3.668 moles ClF3

Step 5: Calculate mass ClF3

Mass ClF3 = Moles ClF3 * molar mass ClF3

Mass ClF3 = 3.668 moles * 92.448 g/mol

Mass ClF3 = 339.10 grams ClF3

Step 1: Data given

Mass of Cl2 = 3.50 grams

Molar mass F2 = 38.00 g/mol

Molar mass ClF3 = 92.448 g/mol

Step 2: The balanced equation

Cl2 + 3F2 → 2ClF3

Step 3: Calculate moles Cl2

Moles Cl2 = Mass Cl2 / molar mass Cl2

Moles Cl2 = 3.50 grams / 70.9 g/mol

Moles Cl2 = 0.0494  moles

Step 4: Calculate moles F2

For 1 mol Cl2 we need 3 moles F2

For 0.0494 moles we need 3*0.0494 = 0.1482 moles

Step 5: Calculate mass F2

Mass F2 = moles F2 * molar mass F2

Mass F2 = 0.1482 moles * 38.00 g/mol

Mass F2 = 5.63 grams F2

Answer:

An ion is an atom that has lost or gained one or more electrons.

Explanation:

Ions are positively or negatively charged atoms of elements. This is because they can give, take, or share electrons with other elements to encourage the formation of chemical bonds.

Protons are what decide the chemical identity of the element. So, for example, if an atom has 11 protons, we know that will be a Sodium (Na) atom. A loss or gain of protons completely changes the chemical identity of the element and it will then become another element.

Electrons are what give an atom a neutral electrical charge (if that atom has the number of protons and neutrons normally described for the element - otherwise, a discrepancy or gain in neutrons is referred to as an isotope and declares that ions have nothing to do with the mass of an element).

With this information, you can realize that neutrons and protons have nothing to do with ions and you can confirm that ions are atoms that have lost or gained one or more electrons.

Answer:

Question 1.

1. [OH−] = 6×10−12 M  is less than 1 * 10⁻⁷, therefore is acidic.

2. [OH−] = 9×10−9 M  is less than 1 * 10⁻⁷, therefore is acidic.

3. [OH−] = 8×10−10 M  is less than 1 * 10⁻⁷, therefore is acidic.

4. [OH−] = 7×10−13 M  is less than 1 * 10⁻⁷, therefore is acidic.

5. [OH−] = 2×10−2 M  is greater than 1 * 10⁻⁷, therefore is basic.

6. [OH−] = 9×10−4 M  is greater than 1 * 10⁻⁷, therefore is basic.

7. [OH−] = 5×10−5 M  is greater than 1 * 10⁻⁷, therefore is basic.

8. [OH−] = 1×10−7 M  is equal to 1 * 10⁻⁷, therefore is neutral

Question 2:

[OH⁻] = 1.92 * 10⁻⁸ M

Question 3:

[H₃O⁺] = 3.70 * 10⁻¹¹ M

Explanation:

The ion product constant of water  Kw = [H₃O⁺][OH⁻] = 1 * 10⁻¹⁴ M² is a constant which gives the product of the concentrations of hydronium and hydroxide ions of dissociated pure water. The concentrations of the two ions are both equal to 1 * 10⁻⁷ in pure water.

A solution that has [OH⁻] greater than 1 * 10⁻⁷ is basic while one with [OH⁻] less than 1 * 10⁻⁷ is acidic.

1. [OH−] = 6×10−12 M  is less than 1 * 10⁻⁷, therefore is acidic.

2. [OH−] = 9×10−9 M  is less than 1 * 10⁻⁷, therefore is acidic.

3. [OH−] = 8×10−10 M  is less than 1 * 10⁻⁷, therefore is acidic.

4. [OH−] = 7×10−13 M  is less than 1 * 10⁻⁷, therefore is acidic.

5. [OH−] = 2×10−2 M  is greater than 1 * 10⁻⁷, therefore is basic.

6. [OH−] = 9×10−4 M  is greater than 1 * 10⁻⁷, therefore is basic.

7. [OH−] = 5×10−5 M  is greater than 1 * 10⁻⁷, therefore is basic.

8. [OH−] = 1×10−7 M  is equal to 1 * 10⁻⁷, therefore is neutral

Question 2:

Kw = [H₃O⁺][OH⁻] = 1 * 10⁻¹⁴ M²

[H₃O⁺][OH⁻] = 1 * 10⁻¹⁴ M²

[OH⁻] = 1 * 10⁻¹⁴ M²/ [H₃O⁺]

[OH⁻] = 1 * 10⁻¹⁴ M²/5.2*10⁻⁵ M

[OH⁻] = 1.92 * 10⁻⁸ M

Question 3:

Kw = [H₃O⁺][OH⁻] = 1 * 10⁻¹⁴ M²

[H₃O⁺][OH⁻] = 1 * 10⁻¹⁴

[H₃O⁺] = 1 * 10⁻¹⁴ M²/ [OH⁻]

[H₃O⁺] = 1 * 10⁻¹⁴ M²/ 2.7 * 10⁻² M

[H₃O⁺] = 3.70 * 10⁻¹¹ M

Answer:

Mass H2SO4 = 3.42 grams

Mass of lead acetate = 0 grams

Mass PbSO4 = 4.58 grams

Mass of CH3COOH = 1.81 grams

Explanation:

Step 1: Data given

Mass of sulfuric acid = 4.90 grams

Molar mass of sulfuric acid = 98.08 g/mol

Mass of lead acetate = 4.90 grams

Molar mass of lead acetate = 325.29 g/mol

Step 2: The balanced equation

H2SO4 + Pb(C2H3O2)2 → PbSO4 + 2CH3COOH

Step 3: Calculate moles

Moles = mass / molar mass

Moles H2SO4 = 4.90 grams / 98.08 g/mol

Moles H2SO4 = 0.0500 moles

Moles lead acetate = 4.9 grams / 325.29 g/mol

Moles lead acetate = 0.0151 moles

Step 4: Calculate the limiting reactant

For 1 mol H2SO4 we need 1 mol lead acetate to produce 1 mol PbSO4 and 2 moles CH3COOH

The limiting reactant is lead acetate. It will completzly be consumed (0.0151 moles). H2SO4 is in excess. There will react 0.0151 moles. There will remain 0.0500 - 0.0151 = 0.0349 moles

Step 5: Calculate moles of products

For 1 mol H2SO4 we need 1 mol lead acetate to produce 1 mol PbSO4 and 2 moles CH3COOH

For 0.0151 moles lead acetate we'll have 0.0151 moles PbSO4 and 2*0.0151 = 0.0302 moles CH3COOH

Step 6: Calculate mass

Mass = moles * molar mass

Mass H2SO4 = 0.0349 moles * 98.08 g/mol

Mass H2SO4 = 3.42 grams

Mass PbSO4 = 0.0151 moles * 303.26 g/mol

Mass PbSO4 = 4.58 grams

Mass of CH3COOH = 0.0302 moles * 60.05 g/mol

Mass of CH3COOH = 1.81 grams

Answer:

Explanation:

Hello,

To find the percentage composition of muscovite mica, we'll have to first find the molecular mass of the compound.

Chemical formula = (KF)₂(Al₂O₃)₃(SiO₂)₆(H₂O)

(KF)₂ = 58.097 × 2 = 116.194g/mol

(Al₂O₃)₃ = 3 × 101.96 = 305.88g/mol

(SiO₂)₆ = 6 × 60.08 = 360.48g/mol

H₂O = 18g/mol

(KF)₂(Al₂O₃)₃(SiO₂)₆(H₂O) = 116.194 + 305.88 + 360.48 + 18 = 800.554g/mol

Potassium = (78.18 / 800.554) × 100 = 9.765%

Fluorine = (38 / 800.554) × 100 = 4.75%

Aluminium = (162 / 800.554) × 100 = 20.23%

Silicon = (168.48/800.554) × 100 = 21.04%

Oxygen = (352/800.554) × 100 = 43.97%

Hydrogen = (2 / 800.554) × 100 = 0.24%

Muscovite mica is an aluminosilicate compound or a polysillicate compound found in rocks

Answer:

8

Explanation:

When you balance the entire equation, you should get:

C5H12 + 8O2 ---> 5CO2 + 6H2O

Answer:

H = 4,034,250 J

Explanation:

Mass, m = 165kg = 165,000g (Converting to grams)

Initial temperature = 15.7°C

Final temperature = 95.7°C

Temperature change, ΔT = 95.7 - 15.7 = 50°C

Specific heat capacity, c = 0.489 J/g·°C

Heat = ?

All the parameters are related with the equation below;

H = m * c * ΔT

H = 165000 * 0.489  * 50

H = 4,034,250 J

Answer:

The initial volume of the chlorine gas [tex]V1=733.28mL[/tex]

Explanation:

Given:

P1= 686mmHg

P2= 991mmHg

V2= 5076mL

V1=?

According to Boyle's law which states that at a constant temperature, the pressure on a gas increases as it's volume decreases.

It can be expressed as : P1V1 = P2V2

Where P1 is the initial pressure

P2= final pressure

V1= initial volume

V2 = final volume

[tex]V1= (P2V2)/P1[/tex]

V1= (991mmHg*507.6mL)/686mmHg

V1=503031.6/686

[tex]V1=733.28mL[/tex]

Therefore, The initial volume of the chlorine gas [tex]V1=733.28mL[/tex]

Answer: a weak acid

Explanation:

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance increases. Oxidizing agent is the substance which itself gets reduced by gaining electrons and thus oxidize others.

Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced. Reducing agent is the substance which itself gets oxidized by losing electrons and thus reduces others.

Weak acids are those substances which dissociate partially to give [tex]H^+[/tex] ions when dissolved in water.

[tex]C_6H_5OH\rightleftharpoons C_6H_5O^-+H^+[/tex]

Weak bases are those substances which dissociate partially to give [tex]OH^-[/tex] ions when dissolved in water.

[tex]NH_4OH\rightleftharpoons NH_4^++OH^-[/tex]

Answer:

1.73g of H2O

Explanation:

The following data were obtained from the question:

Volume (V) of O2 = 1.3L

Temperature (T) = 325 K

Pressure (P) = 0.991 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Next, we shall determine the number of mole (n) of O2 produced from the reaction. This can be obtained by using the ideal gas equation as shown below:

PV = nRT

0.991 x 1.3 = n x 0.0821 x 325

Divide both side by 0.0821 x 325

n = (0.991 x 1.3) /(0.0821 x 325)

n = 0.048 mole

Therefore, 0.048 mole of O2 was produced from the reaction.

Next, we shall determine the number of mole H2O that produce 0.048 mole of O2. This is illustrated below:

2H2O(l) → 2H2(g) + O2(g)

From the balanced equation above,

2 moles of H2O produced 1 mole of O2.

Therefore, Xmol of H2O will produce 0.048 mole of O2 i.e

Xmol of H2O = (2 x 0.048)/1

Xmol of H2O = 0.096 mole

Therefore, 0.096 mole of H2O was used in the reaction.

Finally, we shall convert 0.096 mole of H2O to grams. This is illustrated below:

Molar mass of H2O = (2x1) + 16 = 18g/mol

Number of mole H2O = 0.096 mole

Mass of H2O =..?

Mole = mass /molar mass

0.096 = mass /18

Cross multiply

Mass = 0.096 x 18

Mass of H2O = 1.73g

Therefore, 1.73g of H2O is required for the reaction.

Answer:

The correct option is "Triscsuit"

Explanation:

In my opinion the correct option is tricsuit, because it has 0% saturated fat and TRANS fat, which is healthy fats since these fats are the worst for our body.

They also contain sodium but their levels are not high enough to trigger hypertension.

Answer:

K = 150, C = - 123.15°

Explanation:

Kelvin = Celcius + 273.15 / 0 Kelvin = - 273.14 C

_____________________________________

Thus,

150 K = Celcius + 273.15,

150 - 273.15 = C,

C = -123.15 degrees

Solution, C = - 123.15°

Answer:

C=-123.15

Explanation:

This is easy

Answer:

The lock-and-key model:

c. Enzyme active site has a rigid structure complementary

The induced-fit model:

a. Enzyme conformation changes when it binds the substrate so the active site fits the substrate.

Common to both The lock-and-key model and The induced-fit model:

b. Substrate binds to the enzyme at the active site, forming an enzyme-substrate complex.

d. Substrate binds to the enzyme through non-covalent interactions

Explanation:

Generally, the catalytic power of enzymes are due to transient covalent bonds formed between an enzyme's catalytic functional group and a substrate as well as non-covalent interactions between substrate and enzyme which lowers the activation energy of the reaction. This applies to both the lock-and-key model as well as induced-fit mode of enzyme catalysis.

The lock and key model of enzyme catalysis and specificity proposes that enzymes are structurally complementary to their substrates such that they fit like a lock and key. This complementary nature of the enzyme and its substrates ensures that only a substrate that is complementary to the enzyme's active site can bind to it for catalysis to proceed. this is known as the specificity of an enzyme to a particular substrate.

The induced-fit mode proposes that binding of substrate to the active site of an enzyme induces conformational changes in the enzyme which better positions various functional groups on the enzyme into the proper position to catalyse the reaction.

Answer:

861 kJ = 861000 J,

3495 kcal = 14623.08 kJ

Explanation:

As I mentioned before, the last bit " 7.84 × 106 " just threw me off track, so I am simply going to assume that that does not appear in your question.

_______________________________________________________

Now we have 861 kilojoules, and have to convert it into joules for this first bit. Kilo being equal to 1000, to convert to joules you would have to multiply 861 by 1000, = 861000 Joules.

This second bit here asks us to convert 3495 kilocalorie to kilojoules. The difference between the two is that one is about 4.18 times greater than the other, so 3495 kilocalorie = 3495 * 4.18 = 14623.08 kilojoules.

Hope that helps!

Answer:

[tex]6.68~g~NO_2[/tex]

Explanation:

We have to start with the combustion reaction:

[tex]NO~+~O_2~->~NO_2[/tex]

Then we can balance the reaction:

[tex]2NO~+~O_2~->~2NO_2[/tex]

If we want to find the theoretical yield, we have to calculate the amount of [tex]NO_2[/tex]. To do this, we have to first convert the 4.36 g of [tex]NO[/tex] to moles [tex]NO[/tex] (using the molar mass 30 g/mol), then we have to convert from moles of [tex]NO[/tex] to moles of [tex]NO_2[/tex] (using the molar ratio) finally, we have to convert from moles of [tex]NO_2[/tex] to grams of [tex]NO_2[/tex] (using the molas mass 46 g/mol), so:

[tex]4.36~g~NO\frac{1~mol~NO}{4.36~g~NO}\frac{2~mol~NO_2}{2~mol~NO}\frac{46~g~NO_2}{1~mol~NO_2}=6.68~g~NO_2[/tex]

I hope it helps!

Answer:

D. rate = k [(CH3)3CCl]

Explanation:

(CH3)3CCl + OH- → (CH3)3COH + Cl-

The mechanisms are;

Step 1)

(CH3)3CCl → (CH3)3C+ + Cl- (slow)

Step 2)

(CH3)3C+ + OH- → (CH3)3COH (fast)

In kinetics, the slowest step is the ratee determining step.

For a given reaction;

A → B + C, the rate law expression is given as;

rate = k [A]

In this problem, from step 1. The rate expression is;

rate = k [(CH3)3CCl]