Answer:
The volume increases because the temperature increases and is 2.98L
Explanation:
Charles's law states that the volume of a gas is directely proportional to its temperature. That means if a gas is heated, its volume will increase and vice versa. The equation is:
V₁/T₁ = V₂/T₂
Where V is volume and T is absolute temperature of 1, initial state, and 2, final state of the gas.
In the problem, the gas is heated, from 53.00°C (53.00 + 273.15 = 326.15K) to 139.00°C (139.00 + 273.15 = 412.15K).
Replacing in the Charles's law equation:
2.36L / 326.15K= V₂/412.15K
2.98L = V₂
Write chemical equation and balance for copper(II)nitrate and barium sulfide
Answer:
Cu(NO3)2 + BaS ==> Ba(NO3)2 + CuS
Explanation:
Ba(NO3)2 + CuSO4 = BaSO4 + Cu(NO3)2 (Barium nitrate + Copper (II) sulfate)
How many grams of Boron can be obtained from 234 grams of B2O3?
Answer:
72.67g of B
Explanation:
The reaction of B₂O₃ to produce boron (B), is:
B₂O₃ → 3/2O₂ + 2B
That means B₂O₃ produce 2 moles of boron
Molar mass of B₂O₃ is 69.62g/mol. 234g of B₂O₃ contains:
234g B₂O₃ ₓ (1mol / 69.62g) = 3.361 moles of B₂O₃.
As 1 mole of B₂O₃ produce 2 moles of B, Moles of B that can be produced from B₂O₃ is:
3.361mol B₂O₃ ₓ 2 = 6.722 moles of B.
As molar mass of B is 10.811g/mol. Thus mass of B that can be produced is:
6.722mol B ₓ (10.811g / mol) = 72.67g of B
Write a balanced molecular equation for hydrochloride acid solution combined with a potassium hydroxide solution, an acid base reaction occurs
Answer:
HCl (aq) + KOH (aq) --------> KCl (aq) + H2O (l) [balanced molecular equation]
Explanation:
Balanced molecular equation has all the components of reaction written as "molecules" thus the name molecular (the other equations break appropriate components into ions, those are total ionic or net ionic equation)
We know hydrochloride acid solution is written as HCl (aq) and potassium hydroxide solution is written as KOH (aq). We know from our knowledge that when acids react with bases they make salt and water, so now we react!
HCl (aq) + KOH (aq) --------> KCl (aq) + H2O (l) [balanced molecular equation]
What is the percent composition of muscovite mica if its chemical formula is (KF)2 (Al2O3 )3 (SiO2 )6 (H2O)
Answer:
Explanation:
Hello,
To find the percentage composition of muscovite mica, we'll have to first find the molecular mass of the compound.
Chemical formula = (KF)₂(Al₂O₃)₃(SiO₂)₆(H₂O)
(KF)₂ = 58.097 × 2 = 116.194g/mol
(Al₂O₃)₃ = 3 × 101.96 = 305.88g/mol
(SiO₂)₆ = 6 × 60.08 = 360.48g/mol
H₂O = 18g/mol
(KF)₂(Al₂O₃)₃(SiO₂)₆(H₂O) = 116.194 + 305.88 + 360.48 + 18 = 800.554g/mol
Potassium = (78.18 / 800.554) × 100 = 9.765%
Fluorine = (38 / 800.554) × 100 = 4.75%
Aluminium = (162 / 800.554) × 100 = 20.23%
Silicon = (168.48/800.554) × 100 = 21.04%
Oxygen = (352/800.554) × 100 = 43.97%
Hydrogen = (2 / 800.554) × 100 = 0.24%
Muscovite mica is an aluminosilicate compound or a polysillicate compound found in rocks
1. Determine whether the following hydroxide ion concentrations ([OH−]) correspond to acidic, basic, or neutral solutions by estimating their corresponding hydronium ion concentrations ([H3O+] using the ion product constant of water (Kw).
Kw = [H3O+][OH−] = [1×10−7 M][1×10−7 M] = 1×10−14 M
Hydronium ion concentration [H3O+] Solution condition
Greater than 1×10−7 M Acidic
Equal to 1×10−7 M Neutral
Less than 1×10−7 M Basic
Drag the appropriate items to their respective bins.
1. [OH−] = 6×10−12 M
2. [OH−] = 9×10−9 M
3. [OH−] = 8×10−10 M
4. [OH−] = 7×10−13 M
5. [OH−] = 2×10−2 M
6. [OH−] = 9×10−4 M
7. [OH−] = 5×10−5 M
8. [OH−] = 1×10−7 M
A. Acidic
B. Neutral
C. Basic
2. A solution has [H3O+] = 5.2×10−5M . Use the ion product constant of water
Kw=[H3O+][OH−]
to find the [OH−] of the solution.
3. A solution has [OH−] = 2.7×10−2M . Use the ion product constant of water
Kw=[H3O+][OH−]
to find the [H3O+] of the solution.
Answer:
Question 1.
1. [OH−] = 6×10−12 M is less than 1 * 10⁻⁷, therefore is acidic.
2. [OH−] = 9×10−9 M is less than 1 * 10⁻⁷, therefore is acidic.
3. [OH−] = 8×10−10 M is less than 1 * 10⁻⁷, therefore is acidic.
4. [OH−] = 7×10−13 M is less than 1 * 10⁻⁷, therefore is acidic.
5. [OH−] = 2×10−2 M is greater than 1 * 10⁻⁷, therefore is basic.
6. [OH−] = 9×10−4 M is greater than 1 * 10⁻⁷, therefore is basic.
7. [OH−] = 5×10−5 M is greater than 1 * 10⁻⁷, therefore is basic.
8. [OH−] = 1×10−7 M is equal to 1 * 10⁻⁷, therefore is neutral
Question 2:
[OH⁻] = 1.92 * 10⁻⁸ M
Question 3:
[H₃O⁺] = 3.70 * 10⁻¹¹ M
Explanation:
The ion product constant of water Kw = [H₃O⁺][OH⁻] = 1 * 10⁻¹⁴ M² is a constant which gives the product of the concentrations of hydronium and hydroxide ions of dissociated pure water. The concentrations of the two ions are both equal to 1 * 10⁻⁷ in pure water.
A solution that has [OH⁻] greater than 1 * 10⁻⁷ is basic while one with [OH⁻] less than 1 * 10⁻⁷ is acidic.
1. [OH−] = 6×10−12 M is less than 1 * 10⁻⁷, therefore is acidic.
2. [OH−] = 9×10−9 M is less than 1 * 10⁻⁷, therefore is acidic.
3. [OH−] = 8×10−10 M is less than 1 * 10⁻⁷, therefore is acidic.
4. [OH−] = 7×10−13 M is less than 1 * 10⁻⁷, therefore is acidic.
5. [OH−] = 2×10−2 M is greater than 1 * 10⁻⁷, therefore is basic.
6. [OH−] = 9×10−4 M is greater than 1 * 10⁻⁷, therefore is basic.
7. [OH−] = 5×10−5 M is greater than 1 * 10⁻⁷, therefore is basic.
8. [OH−] = 1×10−7 M is equal to 1 * 10⁻⁷, therefore is neutral
Question 2:
Kw = [H₃O⁺][OH⁻] = 1 * 10⁻¹⁴ M²
[H₃O⁺][OH⁻] = 1 * 10⁻¹⁴ M²
[OH⁻] = 1 * 10⁻¹⁴ M²/ [H₃O⁺]
[OH⁻] = 1 * 10⁻¹⁴ M²/5.2*10⁻⁵ M
[OH⁻] = 1.92 * 10⁻⁸ M
Question 3:
Kw = [H₃O⁺][OH⁻] = 1 * 10⁻¹⁴ M²
[H₃O⁺][OH⁻] = 1 * 10⁻¹⁴
[H₃O⁺] = 1 * 10⁻¹⁴ M²/ [OH⁻]
[H₃O⁺] = 1 * 10⁻¹⁴ M²/ 2.7 * 10⁻² M
[H₃O⁺] = 3.70 * 10⁻¹¹ M
Which 3 laws combine to make the Combined Gas Law?
Answer:
Boyle's Law, Charles' Law, and Gay-Lussac's Law
Explanation:
Answer:
Boyle's Law, Charles's Law, and Gay-Lussac's Law
Explanation:
For each of the following pairs of elements
(1C and N2) (1Ar and Br2)
pick the atom with
a. more favorable (exothermic) electron affinity.
b. higher ionization energy.
c. larger size.
How do you even go about do this?
Explanation:
Electron affinity is defined as the energy released by the addition of an electron to any gaseous atom. Electron affinity of an atom depends on the electronic configuration.
a).The carbon has vacant p-orbital and nitrogen has half-filled configuration which is more stable. Therefore, one electron can be easily added to carbon whereas nitrogen having more stable configuration releases more amount of energy on adding one electron. Therefore, nitrogen has more electron affinity than carbon.
The bromine has vacant p-orbital whereas argon has filled orbital which is most stable. Therefore, one electron can be easily added to bromine whereas argon having more stable configuration releases more amount of energy on adding one electron.Therefore, argon has more electron affinity than bromine.
Answer:
1. a. C; b. N; c. C; 2. a. Br; b. Ar; c. Br
Explanation:
Use your Periodic Table and follow the trends in atomic properties (Fig. 1).
Electron affinity increases from left to right and from bottom to top.
The elements with the most exothermic EA are at the upper right corner
Exceptions are the noble gases (group 18) and the pnictogens (group 18).
The elements of Group 18 have a complete octet and have no tendency to accept electrons.
The elements of Group 15 have half-filled p subshells. They are more stable than the elements immediately preceding them, so they are less exothermic when adding an electron.
Ionization energy increases from left to right and from bottom to top.
The atoms with the highest IE are at the upper right corner.
Atomic size increases from right to left and from bottom to top.
The largest atoms are on the lower-left corner.
1. C vs N
(a) EA: C. N is a Group 15 element
(b) IE: N. N is further to the right.
(c) Size: C. C is further to the left.
2. Ar vs Br
(a) EA: Br. Ar is a noble gas.
(b) IE: Ar. Ar is further to the right.
(c) Size: Br. Br is nearer to the bottom.
AMMONIUM CARBONATE
5. How many grams of nitrogen (N) are in a mass of ammonium carbonate that contains
1.23x10^23 carbon atoms?
Answer:
Zero
Explanation:
Hello,
The question require us to calculate the mass of nitrogen present in aluminium carbonate.
This can easily be calculated using Avogadro's number as a constant with some minor calculations but however in this case, we can't because there's no single atom of nitrogen present in aluminium carbonate hence we can't calculate the mass of nitrogen present in it.
Chemical formula of aluminium carbonate = Al₂(CO₃)₃.
From the above chemical formula, we can see that there's no single atom of nitrogen present in the formula hence the mass of nitrogen present in aluminium carbonate that contains 1.23×10²³ carbon atoms is zero.
Calculate ΔG (in kJ) for the following reaction at 1.0 atm for C2H6, 0.5 atm for O2, and 2.0 atm for CO2, and 25 oC: C2H6 (g) + O2 (g) ---> CO2 (g) + H2O (l) (unbalanced) ΔGfo C2H6 (g) = - 32.89 kJ/mol; ΔGfo CO2 (g) = - 394.4 kJ/mol; ΔGfo H2O (l) = - 237.13 kJ/mol
Answer:
Explanation:
Calculate ΔG (in kJ) for the following reaction at 1.0 atm for C2H6,
0.5 atm for O2, and
2.0 atm for CO2, and
25 oC:
C2H6 (g) + O2 (g) ---> CO2 (g) + H2O (l) (unbalanced)
ΔGfo C2H6 (g) = - 32.89 kJ/mol;
ΔGfo CO2 (g) = - 394.4 kJ/mol;
ΔGfo H2O (l) = - 237.13 kJ/mol
The balance equation of this reaction is
[tex]2C_2H_6 (g) + 7O_2 (g) ---> 4CO_2 (g) + 6H_2O (l)[/tex]
[tex]\Delta G_{rxn}=\sum G^o_f(product)-\sum G^o_f(reactant)[/tex]
[tex]=4G^o_f(CO_2)+6G^o_f(H_2O)-7G^o_f(O_2)-2G^o_f(C_2H_6)\\\\[/tex]
[tex][4(-394.4)+6(-237.13)-7(0)-2(-32.89)]kJ/mol\\\\=-1577.6-1422.78+65.78\\\\=-3000.38+65.78\\\\=-2934.6kJ/mol[/tex]
3. In the above molecules, generally the octet rule can not be followed for every atom. When there are too many electrons or two few electrons and the atoms cannot or will not form multiple bonds, which atom in the structure does not receive a complete or has an expanded octet? Explain why only one atom in the structure is affected in these situations.
Answer:
The octet rule is possible in those atoms which has high number of electrons in their shells.
Explanation:
The octet rule is a type of rule in which the atom has 8 electrons in its outermost shell or valance shell. This rule is not possible for hydrogen and helium because there are very less number of electrons and we know that octet rule needed more number of electrons. Only one atom may be hydrogen or helium is affected in the structure is affected in these situations due to presence of less number of electrons in shells.
The combustion of 1.685 g of propanol (C3H7OH) increases the temperature of a bomb calorimeter from 298.00 K to 302.16 K. The heat capacity of the bomb calorimeter is 13.60 kJ/K . Determine ΔH for the combustion of propanol to carbon dioxide gas and liquid water. g
Answer:
ΔH = - 2020.57 kJ/mol
Explanation:
Given that :
mass of propanol = 1.685 g
the molar molar mass = 60 g/mol
Thus; the number of moles = mass/molar mass
= 1.685 g/60 g/mol
= 0.028 g/mol
However ;
ΔH = heat capacity C × Δ T
Given that:
The temperature increases from 298.00 K to 302.16 K.
Then ;
Δ T = 302.16 K - 298.00 K
Δ T = 4.16 K
heat capacity C = 13.60 kJ/K
∴
ΔH = 13.60 kJ/K × 4.16 K
ΔH = 56.576 kJ
The equation of the given reaction can be represented as :
[tex]C_3H_7OH_{(l)}+\dfrac{3}{2}O_{2(g)} \to 3CO_{2(g)} +4H_2O_{(l)}[/tex]
Thus for 0.028 mol of heat liberated; ΔH = 56.576 kJ
For 1 mole of heat liberated now:
ΔH = 56.576 kJ/0.028 mol
ΔH = 2020.57 kJ/mol
SInce , Heat is liberated, the reaction undergoes an exothermic reaction thus;
ΔH = - 2020.57 kJ/mol
Predict which of the following pairs of solutions, when mixed together, will cause a precipitate to form. (Select all that apply.) Ksp values are: CoS 4.0 × 10–21 Hg2Cl2 3.5 × 10–18 PbCl2 2.4 × 10–4 Ag2SO4 1.5 × 10–5 Group of answer choices 1.5 L of 0.025 M BaCl2 and 1.25 L of 0.014 M Pb(NO3)2 25 mL of 1 × 10–5 M Co(NO3)2 and 75 mL of 5 × 10–4 M Na2S 500 mL of 7.5 × 10–4 M AlCl3 and 100 mL of 1.7 × 10–5 M Hg2(NO3)2. 650 mL of 0.0080 M K2SO4 and 175 mL of 0.15 M AgNO3
Answer:
25 mL of 1 × 10–5 M Co(NO₃)₂ and 75 mL of 5 × 10–4 M Na₂S
500 mL of 7.5 × 10–4 M AlCl₃ and 100 mL of 1.7 × 10–5 M Hg₂(NO₃)₂.
650 mL of 0.0080 M K₂SO₄ and 175 mL of 0.15 M AgNO₃
Explanation:
When 2 compounds that produce an insoluble substance are mixed together, A precipitate will be formed if Q of reaction > Ksp
For the solutions:
1.5 L of 0.025 M BaCl₂ and 1.25L of 0.014 M Pb(NO₃)₂.
Ksp is:
PbCl₂(s) ⇄ Pb²⁺(aq) + 2Cl⁻(aq)
Ksp = 2.4x10⁻⁴ = [Pb²⁺][Cl⁻]²
Molar concentration of each ion is:
[Pb²⁺] = 1.25L ₓ (0.014mol / L) = 0.0175mol / 2.75L = 6.36x10⁻³M
[Cl⁻] = 2 ₓ 1.5L ₓ (0.025mol / L) = 0.075mol / 2.75L = 0.0273M
Replacing in Ksp expression to find Q:
Q = [6.36x10⁻³M][0.0273M]² = 4.73x10⁻⁶
As Q < Ksp, the mixture will not produce a precipitate.
25 mL of 1 × 10–5 M Co(NO₃)₂ and 75 mL of 5 × 10–4 M Na₂S
Ksp is:
CoS(s) ⇄ Co²⁺(aq) + S²⁻(aq)
Ksp = 4.0x10⁻²¹ = [Co²⁺][S²⁻]
Molar concentration of each ion is:
[Co²⁺] = 0.025L ₓ (1x10⁻⁵mol / L) = 2.5x10⁻⁷mol / 0.1L = 2.5x10⁻⁶M
[S²⁻] = 0.075L ₓ (5x10⁻⁴mol / L) = 3.75x10⁻⁵mol / 0.1L = 3.75x10⁻⁴M
Replacing in Ksp expression to find Q:
Q = [2.5x10⁻⁶M][3.75x10⁻⁴M] = 9.38x10⁻⁶
As Q > Ksp, the mixture will produce a precipitate.
500 mL of 7.5 × 10–4 M AlCl₃ and 100 mL of 1.7 × 10–5 M Hg₂(NO₃)₂.
Ksp is:
Hg₂Cl₂(s) ⇄ 2Hg⁺(aq) + 2Cl⁻(aq)
Ksp = 3.5x10⁻¹⁸ = [Hg⁺]²[Cl⁻]²
Molar concentration of each ion is:
[Hg⁺] = 2ₓ0.100L ₓ (1.7x10⁻⁵mol / L) = 3.4x10⁻⁶mol / 0.6L = 5.67x10⁻⁶M
[Cl⁻] = 3 ₓ 0.500L ₓ (7.5x10⁻⁴mol / L) = 1.125x10⁻³mol / 0.6L = 1.88x10⁻³M
Replacing in Ksp expression to find Q:
Q = [5.67x10⁻⁶M]²[1.88x10⁻³M]² = 1.14x10⁻⁶
As Q > Ksp, the reaction will produce a precipitate.
650 mL of 0.0080 M K₂SO₄ and 175 mL of 0.15 M AgNO₃
Ksp is:
Ag₂SO₄(s) ⇄ 2Ag⁺(aq) + SO₄²⁻(aq)
Ksp = 1.5x10⁻⁵ = [Ag⁺]²[SO₄²⁻]
Molar concentration of each ion is:
[Ag⁺] = 0.175L ₓ (0.15mol / L) = 0.02625mol / 0.825L = 0.0318M
[SO₄²⁻] = 0.650L ₓ (0.080mol / L) = 0.052mol / 0.825L = 0.0630M
Replacing in Ksp expression to find Q:
Q = [0.0318M]²[0.0630M] = 6.37x10⁻⁵
As Q > Ksp, the reaction will produce a precipitate.
How are electrons arranged in molecules of compounds
Answer:
The electrons in an atom move around the nucleus in specific regions called electron shells. Every electron shell can just contain a specific number of electrons. The manner in which the electrons are arranged in an iota is known as the atom's electronic structure or electronic configuration of the specific atom.
Atoms or molecules are arranged in molecular compounds in set proportions by forming bonds, where outer shell valence electrons from each atom are shared between two same or different atoms of the compound.
Use the Heisenberg uncertainty principle to calculate the uncertainty (in meters) in the position of a honeybee weighing 0.67 g and traveling at a velocity of 0.80 m/s . Assume that the uncertainty in the velocity is 0.1 m/s.
Answer:9.84x 10^-31m
Explanation: 9.84x 10^-31m
Heisenberg uncertainty principle states that says that the position and momentum of a particle cannot be known at the same time and accurately. and that the values of position and momentum all times must be greater than h/4π.
Using the formula for Heisenberg Uncertainty principle
Δx. Δp ≥ h / 4π
=Δx. m ΔV ≥ h / 4π
where h = Planck’s constant = 6.62607004 × 10-34 m2 kg / s
Δx is the uncertainty in position
Δp is the uncertainty in momentum
m = mass
Δv=is the uncertainty in velocity
Given,
v = 0.80m/s,
m = 0.67 g = 0.67 g / 1000
= 0.00067 kg
h = 6.62607004 × 10-34 m2 kg / s
uncertainty in the velocity is 0.1 m/s.
Δv = 0.80×0.1 = 0.080m/s
Δx. m ΔV ≥ h / 4π
Δx ≥ h / 4πm ΔV
6.62607004 × 10-34 / 4 π x 0.08 x 0.00067
=6.62607004 × 10-34 / 4 x3.14 5.3 x 10^-5 = 9.84x 10^-31m
What force is needed to accelerate a truck with mass 2,000 kg at a rate of 5.0
m/s22
O A. 1,000 N
B. 20,000 N
C. 2,000 N
O D, 10,000 14
Answer:
D
Explanation:
[tex]F=ma \\\\F=2000\cdot 5=10,000N[/tex]
Hope this helps!
will give BRAINLIEST!!! Will give BRAINLIEST
A student makes a standard solution of potassium hydroxide by adding 14.555 g to 500.0 mL of water.
Answer the following questions, being sure to include units and remember sig figs. Show your work.
What possible issues may result from air bubbles in the burette for this experiment? Be specific about
how this may affect the final calculated concentration of acid (Will it be lower or higher than actual?
Why?)
Answer:
The calculated concentration of acid will be higher than the actual concentration of acid
Explanation:
We have information that all enable us to calculate the concentration of KOH in the solution. From the question, we have;
Mass of KOH= 14.555g
Molar mass of KOH= 56.1056 g/mol
Volume of solution= 500 ml
Number of moles of KOH= ???
From;
m/M= CV
m= mass of KOH
M= molar mass of KOH
C= concentration of KOH solution
V= volume of solution
Substituting values;
14.555g/56.1056 g/mol = C× 500/1000
0.259 moles = 0.5C
C= 0.259/0.5
C= 0.518 M
If the acid is HA, the reaction equation is;
KOH(aq) + HA(aq) ----> KA(aq) + H2O(l)
The concentration of the acid is usually determined via titration. This involves delivering a particular volume of acid in a burette into the base and watching out for the volume of acid used at end point. If there are air bubbles in the burette, then more volume of acid is recorded than that actually used and this will make the calculated concentration of the acid to be higher than the actual concentration of acid present.
Describe how you would prepare 150ml of 0.02N NaOH in the laboratory.
Answer:
Explanation:
molar mass of any subtance in 1 litre water gives 1N solution
for NaOH molar mass =40 g
40g --- 1000ml ---1N
Xg---- 150 ----0.02
X= 40*150*0.02/1000*1 =0.12 g
Which molecule will have a double bond?
Answer:
Covalent Molecule
Explanation:
A 2.950×10−2 M solution of glycerol (C3H8O3) in water is at 20.0∘C. The sample was created by dissolving a sample of C3H8O3 in water and then bringing the volume up to 1.000 L. It was determined that the volume of water needed to do this was 998.7 mL . The density of water at 20.0∘C is 0.9982 g/mL.Calculate:
a. molality
b. mole fraction of glycerol in this solution
c. the concentration of the glycerol solution in percent by mass
d. the concentration of the glycerol solution in parts per million
Answer:
a. 2.959x10⁻²m
b. 5.327x10⁻⁴
c. 0.272%
d. 2718 PPM
Explanation:
A solution of 2.950x10⁻²M contains 2.950x10⁻² moles of Glycerol per Liter of solution. As the volume of the solution made was 1.000L, moles of glycerol are 2.950x10⁻².
a. molality: Molality is defined as the ratio between moles of solute (2.950x10⁻²) in kg of solvent. As there are 998.7mL of solvent and density is 0.9982g/mL, kg are:
998.7mL ₓ (0.9982g/mL) ₓ (1kg / 1000g) = 0.9969kg of solvent.
Molality: 2.950x10⁻² moles / 0.9969kg of solvent = 2.959x10⁻²m
b. Mole fraction is the ratio between moles of solute and total moles. Moles of water are:
998.7mL ₓ (0.9982g/mL) ₓ (1mol / 18.01g) = 55.35 moles of water.
Mole fraction glycerol:
2.950x10⁻² moles / (2.950x10⁻²moles + 55.35) = 5.327x10⁻⁴
c. Percent by mass Is the ratio by mass of solute and solution multiplied 100 times.
Mass of glycerol (Molar mass: 92.09g/mol):
2.950x10⁻² moles × (92.09g / mol) = 2.717g of glycerol
Mass of water:
998.7mL ₓ (0.9982g/mL) = 996.9g of water.
Percent by mass:
2.717g of glycerol / (996.9g of water + 2.717g) × 100 = 0.272%
d. Parts per million are defined as the ratio between mg of solute and kg of solution.
mg of 2.717g of glycerol are 2717mg
kg of solution are (996.9g + 2.717g) / 1000 = 0.9996kg
Parts per million:
2717mg / 0.9996kg = 2718 PPM
A reaction occurs between sodium carbonate and hydrochloric acid, producing sodium chloride, carbon dioxide, and water. Which is the correct set of coefficients, respectively, for the balanced reaction?
a. 5 10 10 5 5
b. 1 2 2 1 1
c. 8 6 5 10 5
d. none of these
Answer:b
Explanation:
The correct set of coefficients of the balanced chemical equation of sodium carbonate and hydrochloric acid is 1, 2, 2, 1, 1. Therefore, option (b) is correct.
What is the balanced chemical equation?The chemical equation in which the number of atoms of each element of substances is equal on either side of the chemical equation is known as a balanced chemical equation.
The law of conservation of mass must be followed by every balanced chemical equation. By obeying this law, the total mass of reactants should be equal to the total mass of the products in a balanced chemical equation.
Given the chemical equation of the reaction between sodium carbonate and hydrochloric acid,
Na₂CO₃ + HCl → NaCl + H₂O + CO₂
The balanced chemical equation will be the one in which the number of Na, C, O, H, and Cl will be equal on both sides of the equation.
Na₂CO₃ + 2 HCl → 2 NaCl + CO₂ + H₂O
Therefore, the set of coefficients for the balanced reaction is 1, 2, 2, 1, 1.
Learn more about the balanced chemical equation, here:
brainly.com/question/15052184
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Spell out the full name of the compound.
Explanation:
Step one look for the longest chain of carbon atoms
Longest chain is 7 C atoms
Step 2 look for double bonds or others functional groups
it is present in 3rd carbon
Therefore IUPAC name is 3-heptene
From point of stereochemistry it can also be written as trans-3-heptene as the hydrogens are placed in opposite side of the C=C bond.
Hope this helps...
The compound name is: trans 3-heptene
What is molecular compound?Molecular compounds are inorganic compounds that take the form of discrete molecules.
Looking at the given compound:
1. We need to look for the highest carbon chain, So in this compound the highest carbon chain is of 7 carbon atoms.
2. This compound also has a double bond in between that is present at the third carbon which can be detected by numbering the carbon in a order where the lowest number will come over a double bond.
3. Lastly, we can derive the name for this compound as hept-3-ene or 3-heptene.
4. Also, there is one more thing to notice here which is the position of two hydrogen that are present as substituents since they are placed opposite to each other thus we can name it as trans 3-heptene.
Thus, the compound name is: trans 3-heptene.
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Nitrogen monoxide is produced by combustion in an automobile engine. For the following reaction, 4.36 grams of nitrogen monoxide are mixed with excess oxygen gas . The reaction yields 5.46 grams of nitrogen dioxide . nitrogen monoxide ( g ) oxygen ( g ) nitrogen dioxide ( g ) What is the theoretical yield of nitrogen dioxide
Answer:
[tex]6.68~g~NO_2[/tex]
Explanation:
We have to start with the combustion reaction:
[tex]NO~+~O_2~->~NO_2[/tex]
Then we can balance the reaction:
[tex]2NO~+~O_2~->~2NO_2[/tex]
If we want to find the theoretical yield, we have to calculate the amount of [tex]NO_2[/tex]. To do this, we have to first convert the 4.36 g of [tex]NO[/tex] to moles [tex]NO[/tex] (using the molar mass 30 g/mol), then we have to convert from moles of [tex]NO[/tex] to moles of [tex]NO_2[/tex] (using the molar ratio) finally, we have to convert from moles of [tex]NO_2[/tex] to grams of [tex]NO_2[/tex] (using the molas mass 46 g/mol), so:
[tex]4.36~g~NO\frac{1~mol~NO}{4.36~g~NO}\frac{2~mol~NO_2}{2~mol~NO}\frac{46~g~NO_2}{1~mol~NO_2}=6.68~g~NO_2[/tex]
I hope it helps!
Because cylinder with a volume of 3.00dm^3 contains 8.00 moles of oxygen gas at a temperature of 50.0 K. What is the pressure inside the cylinder? ( R=8.31)
Answer:
Option A. 1110 KPa.
Explanation:
The following data were obtained from the question:
Volume (V) = 3 dm³
Number of mole (n) = 8 moles
Temperature (T) = 50K
Gas constant (R) = 8.31 KPa.dm³/Kmol
Pressure (P) =..?
Pressure inside the cylinder can be obtained by using the ideal gas equation as follow:
PV =nRT
P x 3 = 8 x 8.31 x 50
Divide both side by 3
P= (8 x 8.31 x 50) /3
P = 1108 ≈ 1110 KPa
Therefore, the pressure inside the cylinder is 1110 KPa
How many elements make up most of the ocean?
Answer:
Hydrogen and oxygen
Explanation:
Answer:
eight
Explanation:
the elements of course are the following
hydrogen
oxygen
calcium
sodium
sulfur
magnesium
chlorine
potassium
i hope this helps you
Combustion analysis of 2.400 g of an unknown compound containing carbon, hydrogen, and oxygen produced 4.171 g of CO2and 2.268 g of H2O. What is the empirical formula of the compound
Answer:
[tex]C_3H_8O_2[/tex]
Explanation:
Hello,
In this case, for the given combustion process, we can compute the present moles of carbon atoms by considering that the only product containing carbon is CO2, thus, we have:
[tex]n_C=4.171gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2} =0.095molC[/tex]
Next, we compute the moles of hydrogen that is present at the water only as a product:
[tex]n_H=2.268gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{2molH}{1molH_2O} =0.252molH[/tex]
Then, we compute the moles of oxygen by considering the oxygen present in both the CO2 and H2O and the initial sample:
[tex]m_O=2.400g-0.095molC*\frac{12gC}{1molC} -0.252molH*\frac{1gH}{1molH} \\\\m_O=1.008gO\\\\n_O=1.008gO*\frac{1molO}{16gO} =0.063molO[/tex]
Now, we divide the moles of C, H and O by the moles of O since they are lower amount, in order to compute the subscript in the empirical formula:
[tex]C=\frac{0.095}{0.063}=1.5\\ \\H=\frac{0.252}{0.063}=4\\ \\O=\frac{0.063}{0.063}=1[/tex]
But the smallest whole number is:
[tex]C_3H_8O_2[/tex]
Regards.
What is the law of conservation and what happens when two substances at different temperatures come into contact.
Answer:
- Both energy and matter cannot be neither created nor destroyed.
- An equilibrium temperature will be reached.
Explanation:
Hello,
In this case, the law of conservation is applied to both matter and energy, and it states that both energy and matter cannot be neither created nor destroyed. Specifically, in chemical reactions, it states that in closed systems, the mass of the reactants equals the mass of the products even when the number of moles change. Moreover, for energy, if two substances at different temperatures come into contact, the hot one will cool down and the cold one will heat up until an equilibrium temperature so the energy lost by the hot one is gained by the cold one, which accounts for the transformation of energy.
Best regards.
HELP PLEASE!
When phenol dissolves in water, a few (no all) of the molecules ionize H+ from the -OH group. This makes it
O a reducing agent
O an oxidizing agent
O a weak acid
a weak base
Answer: a weak acid
Explanation:
Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance increases. Oxidizing agent is the substance which itself gets reduced by gaining electrons and thus oxidize others.
Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced. Reducing agent is the substance which itself gets oxidized by losing electrons and thus reduces others.
Weak acids are those substances which dissociate partially to give [tex]H^+[/tex] ions when dissolved in water.
[tex]C_6H_5OH\rightleftharpoons C_6H_5O^-+H^+[/tex]
Weak bases are those substances which dissociate partially to give [tex]OH^-[/tex] ions when dissolved in water.
[tex]NH_4OH\rightleftharpoons NH_4^++OH^-[/tex]
Among three bases, X−, Y−, and Z−, the strongest one is Y−, and the weakest one is Z−. Rank their conjugate acids, HX, HY, and HZ, in order of decreasing strength. Rank the acids from strongest to weakest. To rank items as equivalent, overlap them.
Answer: HZ > HX > HY in order of decreasing strengths.
Explanation: Generally, the rule is that the stronger the acid, the weaker its conjugate base and vice versa; same rule applies for bases and their conjugate acids.
So the weakest base Z- would have the strongest conjugate acid. Consequently, the strongest base Y- would have the weakest conjugate acid.
I hope this was MORE helpful as this is the correct answer.
The ranking of the conjugate acids in order of decreasing strength (i.e from strongest to weakest) is; HZ < HX < HY
First we must know that the stronger a base is, the weaker is it's conjugate acid and the weaker a base is, the stronger is it's conjugate acid.
Therefore, the order of decreasing strength of the conjugate acid is; HZ < HX < HY
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Perform the conversions between energy units.
861 kJ=
J
3495 kcal=
kJ
7.84×106
Answer:
861 kJ = 861000 J,
3495 kcal = 14623.08 kJ
Explanation:
As I mentioned before, the last bit " 7.84 × 106 " just threw me off track, so I am simply going to assume that that does not appear in your question.
_______________________________________________________
Now we have 861 kilojoules, and have to convert it into joules for this first bit. Kilo being equal to 1000, to convert to joules you would have to multiply 861 by 1000, = 861000 Joules.
This second bit here asks us to convert 3495 kilocalorie to kilojoules. The difference between the two is that one is about 4.18 times greater than the other, so 3495 kilocalorie = 3495 * 4.18 = 14623.08 kilojoules.
Hope that helps!
Two aqueous solutions are both at room temperature and are then mixed in a coffee cup calorimeter. The reaction causes the temperature of the resulting solution to fall below room temperature. Which of the following statements is true?
A. The products have a lower potential energy than the reactants.
B. This type of experiment will provide data to calculate AErxn.
C. The reaction is exothermic.
D. Energy is leaving the system during reaction.
E. None of these statements are true.
Answer:
the correct option is that C. The reaction is exothermic.
Explanation:
When the temperature decreases, and that the final temperature is lower than the initial, it indicates that less calories were perceived in the calorimeter, therefore said reaction releases heat to the external environment, thus being an exothermic reaction.
The reaction of given two liquids that have been resulted in the lowering of the temperature of the solution has been an exothermic reaction. Thus option C is correct.
There has been a decrease in the temperature of the solution after the mixing of the two solutions.
This can be described as the reaction between the two molecules that will result in the release of the energy from the system to the surroundings. The release of energy will result in the lowering of the temperature of the system.
The reaction in which the release of energy has been there is termed an exothermic reaction. Thus the reaction of given two liquids that have been resulted in the lowering of the temperature of the solution has been an exothermic reaction. Thus option C is correct.
For more information about the reaction temperature, refer to the link:
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