A regular octagon has what type of symmetry?

A.

line symmetry only

B.

point symmetry only

C.

both point and line symmetry

OD.

neither point nor line symmetry

Answer:

The 1st graph

Step-by-step explanation:

The quickest and easiest way is to just graph y < x² + 4x + 5. When you do so you should be able to see your answer.

Answer:

he domain of the composition is all real x values except for x = -1

In other words: [tex]\left \{ x \, |\, x \neq -1} \right \}[/tex]

Step-by-step explanation:

Let's find the composition [tex]f(g(x))[/tex] in order to answer about its domain (where on the Real number set the function is defined), give the two functions:

[tex]f(x)= \frac{1}{x+4}[/tex]    and    [tex]g(x)=\frac{8}{x-1}[/tex]  :

[tex]f(g(x))=\frac{1}{g(x)+4} \\f(g(x))=\frac{1}{\frac{8}{x-1} +4} \\f(g(x))=\frac{1}{\frac{8+4(x-1)}{x-1} }\\f(g(x))=\frac{x-1}{8+4x-4} \\f(g(x))=\frac{x-1}{4+4x} \\[/tex]

This rational function is defined for every real number except when the denominator adopts the value zero. Such happens when:

[tex]4+4x=0\\4x=-4\\x=-1[/tex]

So the domain of the composition is all real x values except for x = -1

Answer:

csc 270° is the answer.

Answer:

Haha proofs are an interesting thing. Usually, nothing is to scale, which is why you can't measure anything. They are pretty annoying, but it helps to know why certain things are the way that they are and develop justification skills for higher level math.

Sorry to discourage you, but you're going to see "Justify" quite a lot in calculus and beyond which is basically a more informal version of a proof

you can never escape it tbh lol

We can't just measure the two figures to see if they are congruent as congruence is about shape and size.

It should be noted that congruence simply means that the shapes have identical length, angles, and size.

Therefore, we can't just measure the two figures to see if they are congruent as congruence is about shape and size.

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Answer:

Initial Value Problem: [tex]\frac{d^2 x}{dt^2} = -32, x(0) = 200, \frac{dx}{dt}(0) = 40[/tex]

[tex]x(t) = -16t^2 + 40t +200[/tex]

Step-by-step explanation:

The ball is thrown vertically downward, this means that acceleration due to gravity, [tex]g = \frac{dx^{2} }{dt^{2} } = - 32 ft/s^2[/tex]

The height of the ball at time, t = 0 at the top of the building will be: [tex]x(0) = 200 ft[/tex]

The velocity at which the ball is thrown from the top of the building, [tex]\frac{dx}{dt} (0)= 40 ft/s[/tex]

Therefore the initial value problem is written below:

[tex]\frac{d^2 x}{dt^2} = -32, x(0) = 200, \frac{dx}{dt}(0) = 40[/tex]

Let us solve for x(t)

[tex]\frac{d^2 x}{dt^2} = -32\\d(\frac{dx}{dt} )= -32 dt\\[/tex]

Integrate both sides

[tex]\frac{dx}{dt} = -32t + k_1\\\frac{dx}{dt} (0) = 40\\40 = -32(0) + k_1\\k_1 = 0\\\frac{dx}{dt} = -32t + 40[/tex]

Integrate both sides

[tex]x(t) = -16t^2 + 40t + k_2\\x(0) = 200\\200 = -16(0) + 40(0) + k_2\\k_2 = 200\\x(t) = -16t^2 + 40t +200[/tex]

Answer:

It's D: No, there is not enough information given.

Step-by-step explanation:

just took the quiz

The correct answer option D which is No, there is not enough information given.

A parallelogram is a quadrilateral having four sides with two opposite sides parallel to each other. The sum of the angles suspended by all the four sides of the parallelogram is 360.

Using VX = WZ and m∠ZVX = m∠XWZ, we have a side and an angle. In order to prove the triangles congruent by SAS, we must have two sides and the angle between them. With the information we have now, we would have to have VZ = WX. However, we are not given that information.

We do have that ZX = ZX by the reflexive property, but this is not SAS, as the angle we have is not between the two sides.

Therefore correct answer option D which is No, there is not enough information given.

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Answer:

543

Step-by-step explanation:

let x= total salary

0.25x=135.75

x=543

Answer:

[tex]\$ \: 543.00[/tex]

Step-by-step explanation:

[tex]25\% \times x =135.75[/tex]

[tex]1/4 \times x =135.75[/tex]

[tex]0.25 \times x =135.75[/tex]

[tex]x=135.75 \times 4[/tex]

[tex]x=543[/tex]

Answer:

[tex]\cos (\theta)[/tex]

Step-by-step explanation:

[tex]\dfrac{\tan (\theta) \cot (\theta)}{\sec (\theta)}= \\\\\\\dfrac{\dfrac{\sin (\theta)}{\cos (\theta)}\cdot \dfrac{\cos (\theta)}{\sin (\theta)}}{\dfrac{1}{\cos (\theta)}}= \\\\\\1\cdot \cos (\theta)=\\\\\\\boxed{\cos (\theta)}[/tex]

Hope this helps!

Answer:

a = 30

b = 6/7

Step-by-step explanation:

The number of yeast cells after t hours is modeled by the following equation:

[tex]f(t) = a(1 + be^{-0.7t})[/tex]

In which a is the initial number of cells.

At time t = 0 the population is 30 cells

This means that [tex]a = 30[/tex]

So

[tex]f(t) = 30(1 + be^{-0.7t})[/tex]

And increasing at a rate of 18 cells/hour.

This means that f'(0) = 18.

We use this to find b.

[tex]f(t) = 30(1 + be^{-0.7t})[/tex]

So

[tex]f(t) = 30 + 30be^{-0.7t}[/tex]

Then, it's derivative is:

[tex]f'(t) = -30*0.7be^{-0.7t}[/tex]

We have that:

f'(0) = 18

So

[tex]f'(0) = -30*0.7be^{-0.7*0} = -21b[/tex]

Then

[tex]-21b = 18[/tex]

[tex]21b = -18[/tex]

[tex]b = -\frac{18}{21}[/tex]

[tex]b = \frac{6}{7}[/tex]

Answer:

[tex]\frac{1}{12}[/tex]

Step-by-step explanation:

The number with the smallest denominator is the larger number and [tex]\frac{1}{12}[/tex] is the number with the smallest denominator out of [tex]\frac{1}{12} , \frac{1}{32} , \frac{1}{48} , \frac{1}{18}[/tex].

Answer:

1/12

Step-by-step explanation:

Start with a number, for example 100.

Now divide 100 by several numbers which are greater and greater:

100/1 = 100

100/2 = 50

100/4 = 25

100/10 = 10

100/100 = 1

As you divide the same number, 100, by a greater number, the result becomes smaller.

As we divide 100 by 1, then by 2, then by 4, etc., we are always dividing 100 by a greater and greater number. The result is smaller and smaller, 100, 50, 25, etc. If you always divide the same number by other numbers, the larger the number you divide by, the smaller the result.

Numbers in order from greatest to smallest:

1/12, 1/18, 1/32, 1/48

Answer: The greatest number is 1/12

Answer: The mean difference is between 799586.3 and 803257.9.

Step-by-step explanation: To estimate the mean difference for confidence interval:

Find the statistic sample:

For the traffic count, mean = 1835.8 and s = 1382607.3

The confidence interval is 90%, so:

α = [tex]\frac{1-0.9}{2}[/tex]

α = 0.05

The degrees of dreedom are:

df = n - 1

df = 10 - 1

df = 9

Using a t-ditribution table, the t-score for α = 0.05 and df = 9 is: t = 1.833.

Error will be:

E = [tex]t.\frac{s}{\sqrt{n} }[/tex]

E = 1.833.([tex]\frac{1382607.3}{\sqrt{10} }[/tex])

E = 801422.1

The interval is: mean - E < μ < E + mean

1835.8 - 801422.1 < μ < 1835.8+801422.1

-799586.3 < μ < 803257.9

The estimate mean difference in trafic count between 6th and 13th using 90% level of confidence is between 799586.3 and 803257.9.

The graph of the compound inequality can be seen at the end.

Here we have two inequalities that depend on p, these are:

4p + 1 > -15

6p + 3 < 45

First, we need to isolate p on both inequalities.

4p + 1 > -15

4p > -15 - 1

p > -16/4

p > - 4

6p + 3 < 45

6p < 45 - 3 = 42

p < 42/6 = 7

So we have the compound inequality:

p > -4

p < 7

or:

-4 < p < 7

Then this represents the set (-4, 7) where the values -4 and 7 are not included, so we should graph them with open circles.

The graph of the inequality is something like the one below.

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Answer:

the answer is 157

Step-by-step explanation:

7 +10= 17

17+20=37

37+40=77

77+80=157

157+160=317

At the beginning you add +10. Every sequence, you need to multiply that number x2. For example: 10 x 2=20...

Answer:

The relative change from Ohio to Indiana is 49.04

Step-by-step explanation:

Answer:

-2x² + 15

Step-by-step explanation:

Step 1: Add like terms

4x² - 6x² = -2x²

-10x + 10x = 0

12 + 3 = 15

Step 2: Rewrite

-2x² + 15

[tex](8 - 10x + 3) + ( - 12 + 10x + 12)[/tex]

[tex](11 - 10x) + (10x)[/tex]

[tex] 11 - 10x + 10x[/tex]

[tex] = 11[/tex]

Answer:

b. Skewed-left

Step-by-step explanation:

The histogram will be expressed with the x-axis representing the salaries, in growing amount to the right. The y-axis will represent the relative or absolute frequency.

We know that most of the players earn the minimum league wage. Then, we will have a high frequency in the low salaries classes, at the left of the histogram. A few players earn very high salaries, so we will have a right tail with high values for the salaries a little frequency.

There is no symmetry in this histogram and it is not uniform, as there is no representative mean salary.

As most of the data will be close to the left side, we can conclude that the histogram will be skewed-left.

The Histogram of salary data, with most having less salary is RIGHT Skewed

Given : Data of players' salary is concentrated towards towards most players having less ( minimum ) salary.

Right Skewness denotes a distribution where Tail is on the right side. This implies data is highly concentrated toward left side, ie lower independent variable (x - here 'salary') values.

Left Skewness denotes a distribution where Tail is on the left side. This implies data is highly concentrated towards right side, ie higher independent variable (x - here 'salary') values.

In this case : As more players have lower values of independent variable ie salary, so the data will be concentrated at left - having tail at right.

Hence, it will be Skewed Right

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Answer:

g(x) is greater

Step-by-step explanation:

Step-by-step explanation:

a) 2x = 8 x 3

2x = 24

x = 12

b) 3x = 12

x = 4

Answer:

The explanation is:

All interior angles in an equilateral triangle are congruent, making them all 60° by the sum of angles in a triangle. Because alternate interior angles of parallel lines are congruent, x = 60°.

Answer:

[tex]\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2[/tex]

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

[tex] \bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0[/tex]

And we can solve for [tex]\sum_{i=1}^n w_f *X_f [/tex] and solving we got:

[tex] 3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f [/tex]

And from the previous result we got:

[tex] 3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f[/tex]

And solving we got:

[tex] \sum_{i=1}^n w_f *X_f =120 -67.2= 52.8[/tex]

And then we can find the mean with this formula:

[tex] \bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3[/tex]

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Step-by-step explanation:

For this case we know that the currently mean is 2.8 and is given by:

[tex] \bar X = \frac{\sum_{i=1}^n w_i *X_i }{24} = 2.8[/tex]

Where [tex] w_i[/tex] represent the number of credits and [tex]X_i[/tex] the grade for each subject. From this case we can find the following sum:

[tex]\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2[/tex]

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

[tex] \bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0[/tex]

And we can solve for [tex]\sum_{i=1}^n w_f *X_f [/tex] and solving we got:

[tex] 3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f [/tex]

And from the previous result we got:

[tex] 3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f[/tex]

And solving we got:

[tex] \sum_{i=1}^n w_f *X_f =120 -67.2= 52.8[/tex]

And then we can find the mean with this formula:

[tex] \bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3[/tex]

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Answer:

D.

Step-by-step explanation:

Deus ex machina is the plot device of using something very improbable to resolve a situation.

Answer:

40.5 ft

162 ft

16 in

7.2 in

13.9 ft

Step-by-step explanation:

1) V=√32d

d= ?

V=36 ⇒ 36²= 32d  ⇒ d= 1296/32=40.5 feet

2) S= 5.5√d

S= 70 mph, d=?

70²= 5.5²d ⇒ d= 4900/ 30.25≈ 162 feet

3) d= 0.25√h

d= 1 mile, h=?

1²= 0.25²h ⇒ h= 1/0.0625= 16 in

4) a= 4, b= 6, c=?

c²= a²+b² ⇒ c= √a²+b²= √4²+6² = √52≈ 7.2 in

5) c= 16 foot, b= 8 feet, a=?

c²= a²+b² ⇒ a= √c² - b²= √16²-8²= √256- 64= √192≈13.9 feet

Answer:

y = -3x + 3

[tex]y=\frac{1}{3}x-7[/tex]

Step-by-step explanation:

Slope of a line passing through two points ([tex]x_1, y_1[/tex]) and [tex](x_2, y_2)[/tex] is determined by the formula,

Slope = [tex]\frac{(y_2-y_1)}{(x_2-x_1)}[/tex]

If these points are (0, 3) and (3, -6),

Slope of the line passing through these lines = [tex]\frac{3+6}{0-3}[/tex] = (-3)

Equation of the line which passes through (0, 3) and slope = (-3),

y - y' = m(x - x')

y - 3 = (-3)(x- 0)

y - 3 = -3x

y = -3x + 3

Now slope of another line that passes through (3, -6) and (0, -7),

m' = [tex]\frac{(-6+7)}{(3-0)}[/tex]

m' = [tex]\frac{1}{3}[/tex]

Equation of the line that passes through (0, -7) and slope = [tex]\frac{1}{3}[/tex]

y - (-7) = [tex]\frac{1}{3}(x-0)[/tex]

y + 7 = [tex]\frac{1}{3}x[/tex]

y = [tex]\frac{1}{3}x-7[/tex]

Therefore, system of linear equations are,

y = -3x + 3

[tex]y=\frac{1}{3}x-7[/tex]

Answer:

36

Step-by-step explanation:

Answer:

15 is the answer to the question

Answer:

15, which for some reason does not seem to be an option.

Step-by-step explanation:

Product means to multiply to numbers, items etc.

5 times 3, as you should know, is 15.

Hope this helps.

Answer:

[tex] P(X>1)= 1-P(X \leq 1)= 1- [P(X=0) +P(X=1)][/tex]

And if we use the probability mass function we got:

[tex]P(X=0)=(4C0)(0.6)^0 (1-0.6)^{4-0}=0.0256[/tex]  

[tex]P(X=1)=(4C1)(0.6)^1 (1-0.6)^{4-1}=0.1536[/tex]  

And replacing we got:

[tex] P(X>1) =1- [0.0256 +0.1536]= 0.8208[/tex]

Step-by-step explanation:

Let X the random variable of interest, on this case we now that:  

[tex]X \sim Binom(n=4, p=0.6)[/tex]  

The probability mass function for the Binomial distribution is given as:  

[tex]P(X)=(nCx)(p)^x (1-p)^{n-x}[/tex]  

Where (nCx) means combinatory and it's given by this formula:  

[tex]nCx=\frac{n!}{(n-x)! x!}[/tex]  

We want to find the following probability:

[tex] P(X >1)[/tex]

And for this case we can use the complement rule and we got:

[tex] P(X>1)= 1-P(X \leq 1)= 1- [P(X=0) +P(X=1)][/tex]

And if we use the probability mass function we got:

[tex]P(X=0)=(4C0)(0.6)^0 (1-0.6)^{4-0}=0.0256[/tex]  

[tex]P(X=1)=(4C1)(0.6)^1 (1-0.6)^{4-1}=0.1536[/tex]  

And replacing we got:

[tex] P(X>1) =1- [0.0256 +0.1536]= 0.8208[/tex]

Answer:

1  3/10

Step-by-step explanation:

9/8  +7/40

Get a common denominator of 40

9/8 *5/5 + 7/40

45/40 + 7/40

52/40

Rewriting as

40/40 +12/40

1 + 3/10

1  3/10

Answer:

1 3/10

Step-by-step explanation:

First, you need to get a common denominator:

8x5=40 <-- common denominator

45/40+7/40= 52/40

yes you can simplify it.

your final answer will be: 1 3/10

Answer:

-17.32

Step-by-step explanation:

(1319- 19*797)/798 = -17.3233

Answer:

(a)650 ways

(b)650 ways

(c)676 ways

Step-by-step explanation:

There are 26 red and 26 black cards.

If a card is dealt to each of 2 players, we want to find out how many different ways this can be done.

(a)Both cards are red

If both cards are red:

The first red card can be dealt in 26 ways.

The second red card can be dealt in 25 ways.

Therefore: Both Red cards can be dealt in: 26 X 25 = 650 ways

(b)Both cards are black

If both cards are black:

The first black card can be dealt in 26 ways.

The second black card can be dealt in 25 ways.

Therefore: Both black cards can be dealt in: 26 X 25 = 650 ways

(c)One card is black and the other is red.

The red card can be dealt in 26 ways.

The black card can be dealt in 26 ways.

Therefore: Both cards can be dealt in: 26 X 26 = 676 ways

Answer:

None

Step-by-step explanation:

The answers are:

1. g(10) -31

2. x= -17/3

3. f(3)= 2

4.x= √30

5. h(-2)= 1

6. x= 0

7. h(a)= 1

In mathematics, a function is represented as a rule that produces a distinct result for each input x. In mathematics, a function is indicated by a mapping or transformation. Typically, these functions are identified by letters like f, g, and h. The collection of all the values that the function may input while it is defined is known as the domain. The entire set of values that the function's output can produce is referred to as the range. The set of values that could be a function's outputs is known as the co-domain.

Given:

f(x) = x² – 7

g(x) = -3x - 1

j(x)= 2x-9

h(x) = 1

1. g(10)= -3(10) -1 = -30 - 1= -31

2. g(x) = 16

-3x- 1= 16

-3x = 17

x= -17/3

3. f(3)= (3)² – 7 = 9- 7= 2

4. f(x)= 23

x² – 7=  23

x² = 30

x= √30

5. h(-2)= 1

6. x= 0

7. h(a)= 1

8. S(-1) = 3

The value of function s(a) at a=-1 is 3.

10. g(4) = -1

The value of function g(a) at a=4 is -1.

11. h(2) = 8

The value of function h(a) at a=2 is 8.

12. k(2) = 9​

The value of function k(a) at a= 2 is 9.

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