Answer:
Blue car
Explanation:
first let's find the speed:
1) S=D/T
so 120/1= 120km per hr
2) 130/1=130km per hr
so as we can see 130km per hr is faster than 120 km per hr by 10 km per hr
Why does eating less meat conserve more water than just eating plants?
Answer:
Studies show that eating fewer animal-based products could reduce water use since animal production uses more water than crops do. In addition, reducing the amount of food that's lost or wasted at various points in the food supply chain could feed about 1 billion extra people while simultaneously reducing water use.
Find out about organisms that has been bred by humans. It could be a pet such as a dog. A farm animal such as chicken or a crop, such as corn.
Two speakers that are 15.0 mproduce in-phase sound waves of frequency 250.Hz in a roomwhere the speed of sound is 340. m/s. A woman starts out at the midpoint between the two speakers.a.What does she hear at the midpoint, constructive or destructive interference?b.She now walks slowly towards one of the speakers. How far from the center must she walk before she first hears the sound reach a minimum intensity?c.How far from the center must she walk before she first hears the sound at a maximum intensity?d.How far from the center must she walk before the second time she hears the sound at the minimum intensity?
Answer:
a. Constructive interference.
b. [tex]0.34\; \rm m[/tex].
c. [tex]0.68\; \rm m[/tex].
d. [tex]1.02\; \rm m[/tex].
Explanation:
Frequency of this sound wave: [tex]f = 250\; \rm Hz = 250\; \rm s^{-1}[/tex].
Speed of this sound wave: [tex]v = 340\; \rm m \cdot s^{-1}[/tex].
Calculate the wavelength of this sound wave:
[tex]\begin{aligned} \lambda &= \frac{v}{f} \\ &= \fraac{340\; \rm m \cdot s^{-1}}{250\; \rms^{-1}} \approx 1.36\; \rm m\end{aligned}[/tex].
Path difference refers to the absolute value of the difference between:
the distance between the first source (the first speaker) and the observer, andthe distance between the second source (the second speaker) and the observer.When the observer in this question is on the line between the two speakers at [tex]d[/tex] meters from the midpoint, the corresponding path difference would be [tex]2\; d[/tex] meters. (Add [tex]d\![/tex] to the distance from the closer source, and subtract [tex]d\!\![/tex] from the distance from the other source.)
The question states that sound from the two speakers are in-phase. In other words, at every instant, the sound wave from the two speakers are at the same phase at the position of each speaker.
Because wave from the two sources are in-phase at the source:
Constructive interference happens when the path difference is an integer multiple of wavelength ([tex]k\, \lambda[/tex], where [tex]k[/tex] is an integer.) That includes: [tex]0[/tex], [tex]\lambda[/tex], [tex]2\, \lambda[/tex], etc.Destructive interference happens when the path difference is an one-half plus some integer multiple of wavelength ([tex](k + 1/2) \, \lambda[/tex], where [tex]k[/tex] is an integer.) That includes: [tex]\lambda / 2[/tex], [tex]3\, \lambda / 2[/tex], [tex]5\, \lambda / 2[/tex], etc.Path difference is [tex]0[/tex] when the observer is at the midpoint. That would correspond to constructive interference.
The first destructive interference (minimum intensity) corresponds to a path difference of [tex]\lambda / 2[/tex]. Along the line, that would be observed at [tex](1/2) \cdot (\lambda / 2) = 0.34\; \rm m[/tex] from the midpoint.
The next constructive interference (maximum intensity) would be observed when path difference is [tex]\lambda[/tex]. Along the line, that would be observed at [tex](1/2)\cdot \lambda = 0.68\; \rm m[/tex] from the midpoint.
The second destructive interference (minimum intensity) would be observed when path difference is [tex](1 + (1/2))\, \lambda[/tex]. Along the line, that would be observed at [tex](1/2) \cdot ((3/2)\cdot \lambda) = 1.02\; \rm m[/tex] from the midpoint.
HELP PLZZZ
Which optical devices can form images that are larger than the original
object?
Answer: B- A and C
Explanation:
A P E X
The optical devices uses light. The correct option for the optical devices can form images that are larger than the original object is B i.e A and C.
What is optical device?The device which uses light for the meaningful purpose is called optical devices.
The device which form the images larger than the object are the converging type of lens or mirror.
The lens which is converging is the convex lens denoted by C in diagram and the converging mirror is the concave mirror denoted by A.
Therefore, the correct option for the optical devices can form images that are larger than the original object is B i.e A and C.
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Think of a technology or appliance that you use regularly. Identify the transfers and transformations of energy necessary to operate the technology. Explain your answer
PLZZ
Answer:
Energy conversion
Explanation:
We regularly use automobile which runs on the chemical energy of the fuels such as diesel and petrol, the chemical energy from the fuel would convert into the thermal energy which is used to drive the engine of the vehicle,further the thermal energy converted into the mechanical energy which is used to drive the prime mover of the automobile.
What is thermal energy?It can be defined as the form of the energy in which heat is transferred from one body to another body due to their molecular movements, thermal energy is also known as heat energy.
We frequently utilize vehicles that operate on chemical energy from fuels like diesel and gasoline.
This chemical energy is transformed into thermal energy, which drives the engine of the vehicle, and then mechanical energy, which drives the prime mover of the vehicle.
Thus, we can say that the transfers and transformations of energy are necessary to operate the technology.
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How would we find bond length?
Which image shows an example of the strong nuclear force in action?
i think this is the incomplete page that you are showing but the answer is
:-
BCharges of +5C and −9C are at a distance of 1m from each other. Which diagram represents the force between the two charges?
Answer: Well the charges in 9c are positive so 5c is th force between the two making the ansewr
Explanation:
Answer:
C (3RD OPTION)
Explanation:
E2020
Carlos uses a rope to pull his car 30 m to a parking lot because it ran out of gas. If Carlos exerts 2,000 N of force to pull the rope, and the rope is at an angle of 15° to the road, how much work did he do? Round your answer to two significant figures.
1.6 × 104 J
3.5 × 104 J
5.8 × 104 J
9.0 × 104 J
Answer:
Explanation:
Remark
The only thing that might trip you up is what to do with the angle. The vertical component of the 15 degrees does no work against anything. So the 15 degrees limits the horizontal force.
The formula is
Work = F * d * cos(15)
The givens are
F = 2000 N
d = 30 m
Cos(15) = 0.9659
Solution
Work = 2000 * 30 * cos(15)
Work = 57,955
Rounded to two places would be 5.8 * 10^4
C
what are three assumptions of the kinetic molecular theory
How did the solar system begin? Please use complete sentences (will mark B !!!)
Please hurry I have a math test tmr :(
Answer:
about 4.5 billion years ago from a dense cloud of interstellar gas and dust. The cloud collapsed, possibly due to the shockwave of a nearby exploding star, called a supernova. When this dust cloud collapsed, it formed a solar nebula a spinning, swirling disk of material.
Explanation:
HELP DUE IN 3 MINUTESSSSS
Answer:
roots
Explanation:
What is the definition of input force?
Answer:
The input force (effort) is the amount of effort used to push down on a rod, or pull on a rope in order to move the weight. In this example, the force the little guy is using to pull the elephant is the input force.
Explanation:
Three charges lie along the x-axis. One positive charge, q1 = 4.80*10^-18 C, is at x = 3.72 m, and another positive charge, q2 = 1.60*10^-19 C, is at the origin.
At what point on the x-axis must a negative charge, q3, be placed so that the resultant force on it is zero?
Answer:
The third charge needs to be placed at [tex]x \approx 0.57\; \rm m[/tex].
Explanation:
Both [tex]q_1[/tex] and [tex]q_2[/tex] would attract [tex]q_3[/tex].
These two electrostatic attractions need to balance one another. Hence, they need to be opposite to one another. Therefore, [tex]q_1[/tex] and [tex]q_2[/tex] need to be on opposite sides of [tex]q_3[/tex]. That is possible only if [tex]q_3 \![/tex] is on the line segment between [tex]q_1 \![/tex] and [tex]q_2 \![/tex].
Assume that [tex]q_3[/tex] is at [tex]x\; \rm m[/tex], where [tex]0 < x < 3.72[/tex] (in other words, [tex]q_3 \![/tex] is on the line segment between [tex]q_1[/tex] and [tex]q_2[/tex], and is [tex]x\; \rm m \![/tex] away from [tex]q_2 \![/tex].)
Let [tex]k[/tex] denote Coulomb's constant.
The magnitude of the electrostatic attraction between [tex]q_1[/tex] and [tex]q_3[/tex] would be:
[tex]\displaystyle \frac{k\cdot q_1 \cdot q_3}{(3.72 - x)^{2}}[/tex].
Similarly, the magnitude of the electrostatic attraction between [tex]q_2[/tex] and [tex]q_3[/tex] would be:
[tex]\displaystyle \frac{k\cdot q_2 \cdot q_3}{x^{2}}[/tex].
The magnitudes of these two electrostatic attractions need to be equal to one another for the resultant electrostatic force on [tex]q_3[/tex] to be [tex]0[/tex]. Equate these two expressions and solve for [tex]x[/tex]:
[tex]\displaystyle \frac{k\cdot q_1 \cdot q_3}{(3.72 - x)^{2}} = \frac{k\cdot q_2 \cdot q_3}{x^{2}}[/tex].
[tex]\displaystyle \frac{q_1}{(3.72 - x)^{2}} = \frac{q_2}{x^{2}}[/tex].
[tex]\displaystyle \frac{x^2}{(3.72 - x)^{2}} = \frac{q_2}{q_1}[/tex].
[tex]\displaystyle \frac{x^2}{(3.72 - x)^{2}} = \frac{q_2}{q_1} = \frac{1}{30}[/tex].
By the assumption that [tex](0 < x < 3.72)[/tex], it should be true that [tex](x > 0)[/tex] and [tex](3.72 - x > 0)[/tex]. Therefore, [tex]\displaystyle \frac{x}{(3.72 - x)} > 0[/tex].
Take the square root of both sides of the equation [tex]\displaystyle \frac{x^2}{(3.72 - x)^{2}} = \frac{1}{30}[/tex].
[tex]\displaystyle \sqrt{\frac{x^2}{(3.72 - x)^{2}}} = \sqrt{\frac{1}{30}}[/tex].
[tex]\displaystyle \frac{x}{3.72 - x} = \frac{1}{\sqrt{30}}[/tex].
[tex]\sqrt{30}\, x = 3.72 - x[/tex].
Therefore:
[tex]\left(1 + \sqrt{30}\right)\, x = 3.72[/tex].
[tex]\displaystyle x = \frac{3.72}{1 + \sqrt{30}} \approx 0.57[/tex].
Hence, [tex]q_3[/tex] should be placed at [tex]x \approx 0.57\; \rm m[/tex].
A medication given to treat ventricular
tachycardia and ventricular fibrillation
Answer:
Amiodarone
Explanation:
Which of the following is an example of an electromagnetic wave ?
Answer:
Its a wave
Explanation:
THis is one
Answer: a light wave
Explanation: a pex
When a wool cloth is rubbed on the surface of a balloon, it tends to give away electrons causing the surface of the balloon to become :
positively charged
negativity charged
neutrally charged
Answer:
It is negativity charged
Answer:
positively charged
Explanation:
a wool has neutral charges hence when rubbed against a balloon it will generate positive charges
30 PTS NEED THIS FAST
Answer:
the one made from aluminum
Explanation:
What exactly occurs at the alveoli? Explain using blood vessels, diffusion, oxygen, and carbon dioxide in your answer (2-3 sentences)
Answer:
Gas exchange takes place in the millions of alveoli in the lungs and the capillaries that envelop them. Inhaled oxygen moves from the alveoli to the blood in the capillaries, and carbon dioxide moves from the blood in the capillaries to the air in the alveoli.
Explanation:
Hope this helps :)
A hanging 7.5 kg object stretches a spring 1.1 m. What is the spring constant?
A hanging 7.5 kg object stretches a spring 1.1 m, the spring constant of the spring is approximately 66.82 N/m.
Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position, can be used to compute the spring constant.
F = -k * x
Here, we have:
mass (m) = 7.5 kg,
displacement (x) = 1.1 m,
acceleration due to gravity (g) = 9.8 m/[tex]s^2[/tex].
We know that:
weight (W) = mass * acceleration due to gravity
So,
W = m * g
W = 7.5 kg * 9.8 m/[tex]s^2[/tex]
W = 73.5 N
F = W = 73.5 N
F = -k * x
73.5 N = -k * 1.1 m
Solving for k:
k = -73.5 N / 1.1 m
k ≈ 66.82 N/m
Thus, the spring constant of the spring is approximately 66.82 N/m.
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A body of mass m1 = 1.5 kg moving along a directed axis in the positive sense with a velocity
of 11 ms-1 collides head-on with a body of mass m2 = 14 kg moving in the negative sense
with a velocity of 5 ms-1. If the velocity of m1 after the collision is 1 m s-1 in the negative
sense, Apply your scientific knowledge and understanding of collisions to solve the problem
and find the final velocity of m2.
Answer:
3.71 m/s in the negative direction
Explanation:
From collisions in momentum, we can establish the formula required here which is;
m1•u1 + m2•v2 = m1•v1 + m2•v2
Now, we are given;
m1 = 1.5 kg
m2 = 14 kg
u1 = 11 m/s
v1 = -1 m/s (negative due to the negative direction it is approaching)
u2 = -5 m/s (negative due to the negative direction it is moving)
Thus;
(1.5 × 11) + (14 × -5) = (1.5 × -1) + (14 × v2)
This gives;
16.5 - 70 = -1.5 + 14v2
Rearranging, we have;
16.5 + 1.5 - 70 = 14v2
-52 = 14v2
v2 = - 52/14
v2 = 3.71 m/s in the negative direction
The final velocity of the body 2 is 3.71 m/s in the negative sense.
The given parameters:
Mass of the body 1, m1 = 1.5 kgMass of the body 2, m2 = 14 kgInitial velocity of body 1, u1 = 11 m/sInitial velocity of the body 2, u2 = - 5m/sFinal velocity of body 1, v1 = -1 m/sThe final velocity of the body 2 is calculated by applying the principle of conservation of linear momentum;
[tex]m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2\\\\1.5(11) + 14(-5) = 1.5(-1) + 14(v_2)\\\\-53.5 = -1.5+ 14v_2\\\\-52 = 14v_2\\\\v_2 = \frac{-52}{14} \\\\v_2 = -3.71 \ m/s[/tex]
Thus, the final velocity of the body 2 is 3.71 m/s in the negative sense.
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An object with a velocity of
1 m s-l accelerates with an
acceleration of 1 m s2.
What is its velocity after
moving 1 m?
A 1.4 ms s-1
B 1.7 m s -1
C) 2.0 m s-
D 3.0 m s-1
-1
Answer:
v = 1.7 m/s
Explanation:
Given that,
Initial velocity of the object, u = 1 m/s
Acceleration of the object, a = 1 m/s²
We need to find the velocity of the object after moving 1 m. Let v be the velocity. Using third equation of kinematics to find it i.e.
[tex]v^2-u^2=2ad\\\\v^2=2ad+u^2\\\\v^2=2(1)(1)+1^2\\\\v=\sqrt3\\\\v=1.7\ m/s[/tex]
So, the final velocity of the object is 1.7 m/s.
A guitar string vibrates 600 times in 2 seconds.
Find its frequency and time period.
Steps Required.
frequency is equal to number of oscillations or vibrations upon time
therefore,
check picture
You come out of a shopping mall one night and look at your car. Your car is painted blue, and the light illuminating the car is yellow. What color does your car appear to you in the yellow light?
A rolling ball has 18 J of kinetic energy and is rolling 3 m/s. Find its mass.
If you did 3x18 this would equal 54
Helppp please I’m have no time quick please
Answer:
I = 1.09 A
Explanation:
Here, 5 ohm and 12 ohm resistor are connected in parallel. Using the parallel combination of resistors as follows :
[tex]\dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}\\\\\dfrac{1}{R}=\dfrac{1}{5}+\dfrac{1}{12}\\\\ R=3.52\ \Omega[/tex]
Now R and 2 ohm resistors are in series. Let the equivalent be [tex]R_{eq}[/tex]. So,
[tex]R_{eq}=3.52+2\\\\=5.52\ \Omega[/tex]
Let I be the current. Using Ohm's law,
V = IR
[tex]I=\dfrac{V}{R_{eq}}\\\\I=\dfrac{6}{5.52}\\\\I=1.086\ A[/tex]
or
I = 1.09 A
So, the correct option is (c).
a dogs tail hit a 1.3kg flower vase, knocking it over. the net force on the flower vase over time is shown below
what is the bases speed at t=20 ms?
round answer to two significant figures
note that time is in ms.
Answer: 0.15 m/s
Explanation:
How does the mass of an object affect the outcome when an unbalanced force acts on it?
if you can, can you also simplify it into simple terms that are easier to understand?
Answer:
By Newton's second law, it reduces the magnitude of the acceleration, without changing its direction.
F = unbalanced force
m = mass
a = acceleration
a = F/m
what does "no reference to direction of motion mean"?
Explanation:
its means the quantity in question is a scalar quantity, has only magnitude but no direction, for example. speed,has no reference to direction of motion, since the speed of a body say 5 m/s( the direction of the body has not been stated) but the velocity of a body say 5m/s to the east has a reference to direction of the motion.
That's why velocity is different from speed
I need to know on the second one.
A. Negative
B.positive
C. Neither
IT WOULD MEAN A LOT IF U COULD HELP ME