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Answer:

true

Explanation:

normally -No system has ever performed well with one object.

A system must contain more than one object is a true statement.

A system is a group of interacting or interrelated objects that act according to a set of rules to form a unified whole.

Normally, no system has ever performed well with one object.

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Answer:

diameter     of       the  wire   =  0.05  in  =0.05 /12   =4.167 *10 ^-3  ft

area   of cross  section    of the  wire  = A =  22/7 *  ( d /2 ) ^2  =0.786 *  (  4.167 *10 ^-3 ) ^2  =1.365 *10 ^-5  ft2  

E  =...

Explanation:

Answer:

Power is often measured in joules of work per second. The unit of measurement for power is the (W). One watt is equal to one joule of work done in one second. If an object does a large amount of work, its power is usually measured in units of 1000 watts, or kilowatts.

Explanation:

Answer:

B. False

A concave mirror and a converging lens will only produce a real image if the object is located beyond the focal point.

~Hoped this helped~

~Brainiliest?~

Answer:

PE = 0.73J

Explanation:

Remember that in conservative spring systems,

Total energy = potential + kinetic energy.

On the y-axis lies the kinetic energy and the question asks for the potential energy.

PE + KE must always equal the same result.

In this case, KE + PE = 1

So rearranging the equation,

PE = 1 - KE

KE = 0.27 (as we can see from the graph)

Therefore,

PE = 1 - 0.27 = 0.73J

Bonus tip: The graphs of potential and kinetic energy will look the exact opposite in this case. When the KE graph is at 0J, the PE graph is at 1J and vice versa. And they always cross over at 0.5J

Answer:

B: Amplitude

Explanation:

When a wave travels from one medium to the other from an angle, the things that change are amplitude, wavelength, intensity and velocity.

The frequency doesn't change because the frequency depends upon the source of the wave and not the medium by which the wave is propagated.

Answer:

The angle

Explanation:

Answer:

2156 J

Explanation:

From the question,

Work done = Combined mass of the bucket and water×height×gravity.

W = (M+m)hg............................. Equation 1

Where M = mass of water, m = mass of the bucket, h = height, g = acceleration due to gravity.

Given: M = 20 kg, m = 2 kg, h = 10 m

Constant: g = 9.8 m/s²

Substitute these  value into equation 1

W = (20+2)×10×9.8

W = 22×98

W = 2156 J

Answer: Friction Forces

Explanation: (I took the same test and got the answer)

_________________________________________

I hope this helps!

Answer:

720

Explanation:

Answer:

See explanation

Explanation:

Let us recall that temperature is a measure of the average kinetic energy of the molecules of a body.The higher the temperature, the higher the kinetic energy of the molecules of the body.

As temperature decreases, the kinetic energy of the molecules of a substance also decreases rapidly and the magnitude of intermolecular interaction between molecules of the substance increases.

Hence, as argon gas is cooled from 20°C to -190°C the kinetic energy of the gas molecules decreases an the magnitude of intermolecular interaction increases hence the gas changes into liquid and subsequently changes into a solid at -190°C.

Answer:

0.1014 J

Explanation:

This is the answer if the toy airplane was 120-GRAMS

if you meant KG then it's 101.4 J

Answer:

66.98 km

Explanation:

Given :

Initial time period, [tex]$T_1$[/tex] = 1 day

Radius of initial orbit, [tex]$r_1$[/tex] = 42.2 km

Final Time period, [tex]$T_2$[/tex] = 2 days

We know that,

The time period of satellite is

[tex]$T= 2 \pi \sqrt{\frac{r^3}{GM}}$[/tex]

So, for [tex]$T_2=2\pi \sqrt{\frac{r_2^3}{GM}}$[/tex]    ...........(i)

For [tex]$T_1=2\pi \sqrt{\frac{r_1^3}{GM}}$[/tex]  ...................(ii)

Therefore, dividing equation (i) by (ii), we get

[tex]$\frac{T_2}{T_1}=\sqrt{\frac{r_2^3}{r_1^3}}$[/tex]

[tex]$\left(\frac{2}{1}\right)^2=\frac{r_2^3}{(42.2)^3}$[/tex]

[tex]$r_2 = 66.98 \ km$[/tex]

Therefore, the radius is 66.98 km.

Answer:

35/2 J/s

Explanation:

Just use the 2 formulas

Work done = Force * distance moved

Power = Work done/time

WD = 7 * 50  = 350

Power = 350 / 20

= 35/2 J/s

Answer:

   ΔT = [tex]\frac{\Delta K}{(m_1+m_2) c_e }[/tex]    

Explanation:

This is an interesting problem, no data is given, so the result is a general expression.

Suppose that the disks are initially rotating with angular velocity w₁ and w₂, as well as that they have radii r₁ and r₂ and masses m₁ and m₂

we start the problem finding odl final angular velocity of the discs together, for this we define a system formed by the two discs, in this case the torques during the collision are internal and the angular momentum is conserved

initial instant. Just before the crash

           L₀ = L₁ + L₂

with

           L₁ =  I₁ w₁

the moment of inertia of a disc with an axis passing through its center is

           I₁ = ½ m₁ r₁²

we substitute

           I₀ = ½ m₁ r₁² w₁ + ½ m₂ r₂² w₂

final instant. Right after the crash

         L_f = I w

in angular momentum it is a scalar quantity, so it is additive

         I = I₁ + I₂

angular momentum is conserved

         L₀ = L_f

         I₁ w₁ + I₂ w₂ = I w

         w =  [tex]\frac{ I_1 w_1 + I_2 w_2 }{I}[/tex]            (1)

We already have the angular velocities of the system, let's find the kinetic energy of it

initial

          K₀ = K₁ + K₂ = ½ I₁ w₁² + ½ I₂ w₂²

final

          K_f = K = ½ I w²

the variation of the kinetic energy is the loss in the increase of the temperature of the system, they indicate us that we neglect the other possible losses

         ΔK = K_f -K₀

         ΔK = ½ I w² - (½ I₁ w₁² + ½ I₂ w₂²)           (2)

In this chaos we know all the values ​​for which the numerical value of ΔK can be calculated, the symbolic substitution gives expressions with complicated

Now if all this variation of energy turns into heat

         Q = ΔK

         m_{total} c_e ΔT = ΔK

where the specific heat of the bear discs must be known, suppose they are of the same material

         ΔT = [tex]\frac{\Delta K}{(m_1+m_2) c_e }[/tex]               (3)

to make a special case, we suppose some data

the discs have the same mass and radius, disc 2 is initially at rest and the discs are made of bronze that has c_e = 380 J / kg ºC

we look for the angular velocity

          I₁ = I₂ = I₀

          I = 2 I₀

we substitute in 1

           w = [tex]\frac{I_o w_1 + I_o 0 }{2I_o}[/tex] I₀ w₁ + I₀ 0 / 2Io

           w = w₁ /2

we look for the variation of the kinetic energy with 2

             ΔK = ½ (2I₀) (w₁ /2)² - (½ I₀ w₁² + ½ I₀ 0)

             ΔK = ¼ I₀ w₁² -½ I₀ w₁²

             ΔK = - ¼ I₀ w₁²

the negative sign indicates that the kinetic energy decreases

We look for the change in Temperature with the expression 3

              ΔT = [tex]\frac{ \Delta K}{(m_1 +m_2) c_e}[/tex]ΔK / (m1 + m2) ce

              ΔT = [tex]\frac{ \frac{1}{4} I_o w_1^2 }{ 2m c_e}[/tex]

              ΔT =  [tex]\frac{1}{8} \frac{ (\frac{1}{2} m r_1^2 ) w_1^2 }{ m c_e}[/tex]

              ΔT = [tex]\frac{1}{16} r_1^2 w_1^2 / c_e[/tex]

in this expression all the terms are contained

The increase in internal energy of the disks will be [tex]\rm \triangle E= mc\frac{\triangle k }{(m_1+m_2)c_e}[/tex].

The energy contained within a thermodynamic system is known as its internal energy. It's the amount of energy required to build or prepare a system in any given internal state.

The given data in the problem is;

[tex]\rm \omega_1[/tex]  is the angular velocity of  disk 1

[tex]\rm \omega_2[/tex] is the  angular velocity of disk 2

r₁ is the radius of  disk 1

r₂ is the radius of  disk 2

m₁ is the mass of disk 1

m₂ is the mass of disk 2

Momentum before the collision;

[tex]\rm L_1 = I_1 \omega_1[/tex]

The moment of inertia of disc 1

[tex]\rm i_1 = \frac{1}{2} m_1r_1^2[/tex]

The momentum gets conserved;

[tex]\rm L_0 = L_f \\\\ I_1 \omega_1 + I_2\omega_2 = I \omega \\\\ \rm \omega= \frac{I_1 \omega_1 + I_2\omega_2}{I}[/tex]

The change in the kinetic energy is;

[tex]\traingle KE= K_f - K_0 \\\\ \traingle KE= \frac{1}{2} I \omega^2-(\frac{1}{2} I_1\omega_1^2 + (\frac{1}{2} I_2\omega_2^2 )[/tex]

The change in the energy gets converted into heat;

[tex]\rm Q= \triangle k \\\\\ m_{total } c_e dt = \triangle k[/tex]

The change in the temperature is

[tex]\triangle T= \frac{\triangle k }{(m_1+m_2)c_e}[/tex]

The internal energy change is found by;

[tex]\rm \triangle E = mc_v dt[/tex]

[tex]\rm \triangle E= mc\frac{\triangle k }{(m_1+m_2)c_e}[/tex]

Hence the increase in internal energy of the disks will be [tex]\rm \triangle E= mc\frac{\triangle k }{(m_1+m_2)c_e}[/tex].

To learn more about the internal energy refer to the link;

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Answer:

The answer is letter B hope it helps

Answer:

(b) both the temperature and pressure of the gas decrease.

Explanation:

An ideal gas undergoes an adiabatic expansion, a process in which no heat flows into or out of the gas. As a result, both the temperature and pressure of the gas decrease.

Gay Lussac states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Gay Lussac's law is given by;

[tex] PT = K[/tex]

Also, according to the first law of thermodynamics which states that energy cannot be created or destroyed but can only be transformed from one form to another. Thus, the ideal gas does work on the environment with respect to the volume and temperature.

Answer:

The two correct answers are B.) reacting quickly with water, and D.) forming bonds with other atoms.

Explanation:

I took the quiz on a.pex and these were correct.

Answer:

 t = 1.62 h

Explanation:

A flat mirror fulfills the law of reflection where the incident angle is equal to the reflected angle.

          θ_i = θ_r

If we use trigonometry to find the angles, the mirror is at a height of L = 1.87 m,   and the reflected rays reach a distance x1 = 3.56 m

         tan θ₁ = x₁ / L

         tan θ₁ = [tex]\frac{3.56}{1.87}[/tex]

         θ₁ = tan⁻¹  1.90

         θ₁ = 62.29º

for the second case x₂ = 1.46 m

        tan θ₂ = x₂ / L

        θ₂ = tan⁻¹  [tex]\frac{1.46}{1.87}[/tex]

        θ₂ = 37.98º

the difference in degree traveled is

         Δθ = θ₁- θ₂

          Δθ = 62.29 - 37.98

          Δθ = 24.31º

as in the exercise they indicate that every 15º there is an hour

         t = 24.31º (1h / 15º)

         t = 1.62 h

Answer: ?

Explanation:

Answer:

A bright and sunny day not worrying about work or school no family drama just a day you can relax and be yourself surrounded by the people you love.

hope this helps

have a good day :)

Explanation:

Answer:I'll describe a perfect day as a bright sunny day without rain,having no chores or homework to do.Going outside and enjoying the sun,have a glass of lemonade.No drama and no school,nothing to worry about.Going to the pool and going for a nice swim or a lake.Going fishing,playing basketball,watching television,or visiting a relative you haven't have much time to spend with.Going for a walk in the park,hanging out with some friends.Or just staying in the house doing nothing.

Explanation:

Answer:

The mass of the rod is 16 kg.

Explanation:

Given that,

The length of a rod, L = 3 m

The moment of inertia of the rod, I = 12 kg-m²

We need to find the mass of the rod. The moment of inertia of the rod of length L is given by :

[tex]I=\dfrac{ML^2}{12}[/tex]

Where

M is mass of the rod

[tex]M=\dfrac{12I}{L^2}\\\\M=\dfrac{12\times 12}{(3)^2}\\\\M=16\ kg[/tex]

So, the mass of the rod is 16 kg.

Answer:

(A) 0.54 kg

(B) 15.5 m/s west

Explanation:

Mass is conserved.

M = m₁ + m₂

0.86 kg = 0.32 kg + m₂

m₂ = 0.54 kg

Momentum is conserved (take east to be positive).

Mv = m₁v₁ + m₂v₂

(0.86 kg)(-6 m/s) = (0.32 kg)(10 m/s) + (0.54 kg) v₂

v₂ = -15.5 m/s

Answer:

[tex]2625.156\ \text{N}[/tex]

Explanation:

Dimensions of mattress 100 cm by 194 cm by 14 cm

[tex]m_m[/tex] = Mass of mattress = 4 kg

[tex]\rho[/tex] = Density of water = [tex]1000\ \text{kg/m}^3[/tex]

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

Volume of mattress

[tex]V=100\times 194\times 14=271600\ \text{cm}^3=0.2716\ \text{m}^3[/tex]

Weight of water displaced is equal to the buoyant force

Mass of water

[tex]m=\rho V\\\Rightarrow m=1000\times 0.2716\\\Rightarrow m=271.6\ \text{kg}[/tex]

Mass of person would be

[tex]m_p=m-m_m=271.6-4\\\Rightarrow m_p=267.6\ \text{kg}[/tex]

Weight of the person would be

[tex]w=m_pg\\\Rightarrow w=267.6\times 9.81\\\Rightarrow w=2625.156\ \text{N}[/tex]

The air mattress could hold a person that weighs up to [tex]2625.156\ \text{N}[/tex].

Answer:

The air bubbles are oxygen coming out of the leaf

Explanation:

Though the leaf is in hot water, it is still using light to continue on the path of photosynthesis. Now, this path of photosynthesis involves letting oxygen out of the leaf. Thus, this oxygen is the one that we see as bubbles coming out of the water.

The reason for having more air bubbles at the lower surface than at the upper surface is because the leaf cells at the lower surface of the leaf possess faster photosynthetic rate in releasing

oxygen.

Answer:

The velocity of the center of mass of the two-ball system is 13.1 m/s.

Explanation:

Given;

mass of the first ball, m₁ = 0.5 kg

mass of the second ball, m₂ = 0.25 kg

initial velocity of the second ball, u₂ = 19.6 m/s

At the highest point the velocity of the second ball, v₂ = 0

The highest point reached by the second ball is calculated as;

v₂² = u₂² - 2gh

0 = u₂² - 2gh

2gh = u₂²

h = u₂² / 2g

h = (19.6²) / (2 x 9.8)

h = 19.6 m

The final velocity of the first ball when it had traveled 19.6 m down;

v₁² = u₁² + 2gh

v₁² = 0 + 2gh

v₁ = √2gh

v₁ = √(2 x 9.8 x 19.6)

v₁ = 19.6 m/s

The velocity of the center of mass of the two-ball system is calculated as;

[tex]v = \frac{m_1v_1 \ + \ m_2v_2}{m_1 \ + \ m_2} \\\\v = \frac{0.5\times 19.6 \ + \ 0.25\times 0}{0.5 \ + \ 0.25} \\\\v = 13.1 \ m/s[/tex]