A rabbit moves n times as fast as a squirrel . A fox moves m times as fast as a rabbit . The fox moves how many times as fast as the squirrel?

Answer:

no idea

Step-by-step explanation:

Jk the answers square

Answer:

C

Step-by-step explanation:

Okay so im going to gudie you thru So what it is asking you is to Count all the cubic squares looking things so what i can see is that You circled 169 aka C that would be correct because it cant be 11 cause it dosent look like 11 square units  lol you get what im saying so the answer is C hope this HELPSS!!

By the way follow my insta. exotic. jaliyah if you need anymore help

Answer:

1/3 cup of ice icream

Step-by-step explanation:

This is a proportions question. Since we know that we need 1/4 cup of ice cream for every 3/4 cup of root beer, we need to find how many cups of ice cream we need for 1 cup of root bear.

We need to find out what times 3/4 makes 1. This can be done with:

(3/4)x = 1

x = 4/3

Now multiply that with 1/4 to get the amount of ice cream.

4/3 times 1/4 = 1/3

Answer:

165

Step-by-step explanation:

you need to x it

Hope this helps! Have a nice day!

are you looking for the perimeter or area or what

Answer:

16+13+12=41

Step-by-step explanation:

it is acute

Answer:

a) [tex]\frac{dA}{dt} = 48 \pi\frac{in^{2}}{min}[/tex]

b) [tex] \frac{dh}{dt} = - \frac{13}{3} \frac{in}{min}[/tex]

c) [tex]\frac{dh}{dt} = - 2\frac{h}{r} \frac {dr}{dt}[/tex]

Step-by-step explanation:

In order to solve this problem, we must first picture a cylinder of height h and radius r (see attached picture).

a) So, in order to find the rate at which the area of the circular surface of the dough is increasing with respect to time, we need to start by using the are formula for a circle:

[tex]A=\pi r^{2}[/tex]

So, to find the rate of change of the area, we can now take the derivative of this formula with respect to the radius r:

[tex]dA = \pi(2) r dr[/tex]

and divide both sides into dt so we get:

[tex]\frac{dA}{dr} = 2\pi r \frac{dr}{dt}[/tex]

and now we can substitute:

[tex]\frac{dA}{dr} = 2\pi(12in)(2\frac{in}{min})[/tex]

[tex]\frac{dA}{dt} = 48\pi\frac{in^{2}}{min}[/tex]

b) In order to solve part b, we can start with the formula for the volume:

[tex]V=\pi r^{2} h[/tex]

and solve the equation for h, so we get:

[tex]h=\frac{V}{\pi r^{2}}[/tex]

So now we can rewrite the equation so we get:

[tex]h=\frac{V}{\pi}r^{-2}[/tex]

and now we can take its derivative so we get:

[tex]dh=\frac{V}{\pi} (-2) r^{-3} dr[/tex]

we can rewrite the derivative so we get:

[tex]\frac{dh}{dt}=-2\frac{V}{\pi r^{3}}\frac{dr}{dt}[/tex]

we can take the original volume formula and substitute it into our current derivative, so we get:

[tex]\frac{dh}{dt}= -2\frac{\pi r^{2} h}{\pi r^{3}} \frac{dr}{dt}[/tex]

and simplify:

[tex]\frac{dh}{dt} =-2\frac{h}{r} \frac{dr}{dt}[/tex]

so now we can go ahead and substitute the values  provided by the problem:

[tex]\frac{dh}{dt} =-2\frac{13in}{12in} (2\frac{in}{min})[/tex]

Which simplifies to:

[tex] \frac{dh}{dt} = - \frac{13}{3} \frac{in}{min}[/tex]

c)

Part c was explained as part of part b where we got the expression for the rate of change of the height of the dough with respect to the radius of the dough in terms of the height h and the radius r:

[tex]\frac{dh}{dt} =-2\frac{h}{r} \frac{dr}{dt}[/tex]

The rate of change of the height of the pizza with respect to (w.r.t.) time

can be found given that the volume of the pizza is constant.

Reasons:

The height of the dough when t = k is 13 inches

Radius of the dough = 12 inches

Rate at which the radius of the dough is increasing, [tex]\dfrac{dr}{dt}[/tex] = 2 in.²/min

(a) Required: The rate of increase of the surface area with time

Solution:

The circular surface area, A = π·r²

By chain rule of differentiation, we have;

[tex]\dfrac{dA}{dt} = \mathbf{\dfrac{dA}{dr} \times \dfrac{dr}{dt}}[/tex]

[tex]\dfrac{dA}{dt} = \dfrac{d ( \pi \cdot r^2)}{dr} \times \dfrac{dr}{dt} = 2 \cdot \pi \times 2 = 4 \cdot \pi[/tex]

The rate of increase of the surface area with time, [tex]\mathbf{\dfrac{dA}{dt}}[/tex] = 4·π in.²/min.

(b) Required: The rate of decrease of the height with respect to time

The volume of the pizza is constant, given by; V = π·r² ·h

Therefore;

[tex]h = \mathbf{ \dfrac{V}{\pi \cdot r^2}}[/tex]

[tex]\dfrac{dh}{dt} = \dfrac{d \left( \dfrac{V}{\pi \cdot r^2} \right)}{dr} \times \dfrac{dr}{dt} = \dfrac{-2 \cdot V}{\pi \cdot r^3} = \dfrac{-2 \cdot \pi \cdot r^2 \cdot h}{\pi \cdot r^3} \times \dfrac{dr}{dt} = \mathbf{-2 \cdot \dfrac{h}{r} \times \dfrac{dr}{dt}}[/tex]

[tex]\dfrac{dh}{dt} = -2 \cdot \dfrac{h}{r} \times \dfrac{dr}{dt} = -2 \times \dfrac{13}{12} \times 2 = \dfrac{13}{3} = 4. \overline 3[/tex]

The rate at which the height of the dough is decreasing, [tex]\mathbf{\dfrac{dh}{dt}}[/tex]= [tex]\underline{4.\overline 3 \ in./min}[/tex]

(c) Required:]The expression for the rate of change the height of the dough with respect to the radius of the cone.

Solution:

[tex]\dfrac{dh}{dr} = \dfrac{d \left( \dfrac{V}{\pi \cdot r^2} \right)}{dr} = \dfrac{-2 \cdot V}{\pi \cdot r^3} = \dfrac{-2 \cdot \pi \cdot r^2 \cdot h}{\pi \cdot r^3} = -2 \cdot \dfrac{h}{r}[/tex]

[tex]\dfrac{dh}{dr} = \mathbf{ -2 \cdot \dfrac{h}{r}}[/tex]

The rate of change the height of the dough w.r.t. the radius is [tex]\underline{\dfrac{dh}{dr} = -2 \cdot \dfrac{h}{r}}[/tex]

Learn more here:

https://brainly.com/question/20489729

Answer:

Slope (m) = 5

Y-intercept (b) = 3

Step-by-step explanation:

The equation of a line is y = mx + b, where (m) is the slope and(b) is the y-int.

Knowing this, we see that the slope is 5 and the y-int is 3.

hope this helps!

Answer:

No idea

Step-by-step explanation:

No idea for that either

Hope this helps, have a good day

Step-by-step explanation:

1. The bag contains fewer than 10 carrots

2.catherin3 biked farther than 10 miles

3.the chair is shorter than 20 in

4.carlos scored over 20 points

Answer:

i think is the A and D

i hope this hepl you

Answer:

callum bought 78.6 stamps

Answer:

log(c). log(8) - log(2)

Step-by-step explanation:

Answer:

Formed will be i think 9, but im not sure.

Answer:

8b + 7m + 4n = -10

Step-by-step explanation:

(8b + 8) + (7m – 2) + (4n + 4)

First thing to do is to try to open the brackets, so we have

8b + 8 + 7m - 2 + 4n + 4 =

Next, we collect like terms, so that we have

8b + 7m + 4n + 8 - 2 + 4 =

8b + 7m + 4n + 10 =

And rearranging, we have that

8b + 7m + 4n = -10

Answer:

99 degrees F

Step-by-step explanation:

subtract 5 from 104

Answer:

average 104 degrees F

Step-by-step explanation:

Answer:

4:3 8:6 12:9 so on

Step-by-step explanation:

Answer:

4 to 3 or 3 to 4

Step-by-step explanation:

depending on how the question is worded if its red the green then 4 to 3 but if it green to red then its 3 to 4.

Answer:

c. (6, 3)

Step-by-step explanation:

subtract

3x + 6y = 36

3x - 6y =  0

12y = 36, y = 3

3x + 6(3) = 36

3x + 18 = 36

3x = 18, x = 6

x = 6, y = 3

Answer:

the answer is b good luck

Answer:   If a team uses 75 water bottles when the temperature is 60 degrees, ( 75 - 15 = 60 )

I guess if they have 120 bottles, you'd have to take away 15 again, which = 105

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Sorry if i'm wrong

Answer: $9.04

Step-by-step explanation:

one box is $2.65 and $2.65x4=$10.09 and if there is a $20.00 then $20.00-$10.09=$9.04. :P

Answer:

Step-by-step explanation:

Apples- 2

Oranges-4

Bananas- 3

In each basket

Answer:

[tex]1\frac{1}{4} c[/tex]

Step-by-step explanation:

[tex]c+\frac{1}{4}c[/tex]

Rewrite the expression

[tex]= 1c+\frac{1}{4} c[/tex]

Add

[tex]= 1\frac{1}{4} c[/tex]

Therefore, [tex]c+\frac{1}{4}c[/tex] is equal to [tex]1\frac{1}{4} c[/tex].

I hope this helps!

Answer: 8° per day.

Step-by-step explanation:

Based on the information above, since we are informed that in three days, the temperature dropped by 24 degrees, the number of degrees per day that the temperature dropped will be go by dividing 24° by 3 days. This will be:

= 24° / 3 days

= 8° per day

Answer: 140?

I am not really sure but I think 140......

Answer:

10/2

Step-by-step explanation:

first 10/2=5

you divide 10 into 2 until you get 5 of such groups

Answer:

Mode =Li+[f1-f0/2f1-f0-f2] *h

Li=lower limit.

F1= first frequency

F0= upper frequency of first frequency.

F2= second frequency.

H= difference between class intervals.

Hope it is helpful

Answer: The third one

Step-by-step explanation: open circle, with crocodile sign pointing to right which means u have to go left! Have a nice day!!

Answer:

C) a number line going from negative 6.5 to negative 5.8. An open circle is at negative 6.1. Everything to the left of the circle is shaded.

Step-by-step explanation:

Open circle means < or >

Closed circle means < or >

So has to be an open circle since the sign is <. it also says w < -6.1

so w has to be less than -6.1. So less than -6.1 would be -6.2, -6.3, -6.4etc.

The point is a solution to this system of inequalities y ≤1/2x-3 and y+2x greater than 6 are B) (2,- 3) and D) (4,1).

To track down the answer for the arrangement of imbalances y ≤ 1/2x - 3 and y + 2x > 6, we want to test each answer decision to check whether it fulfills the two disparities.

A) (7,- 8):

y ≤ 1/2(7) - 3 = 0.5

y + 2(7) > 6

This point doesn't fulfill the primary imbalance, so it's anything but an answer.

B) (2,- 3):

y ≤ 1/2(2) - 3 = - 2

y + 2(2) > 6

This point fulfills the two imbalances, so it is an answer.

C) (5,- 2):

y ≤ 1/2(5) - 3 = - 0.5

y + 2(5) > 6

This point doesn't fulfill the main imbalance, so it's anything but an answer.

D) (4,1):

y ≤ 1/2(4) - 3 = - 1

y + 2(4) > 6

This point fulfills the two imbalances, so it is an answer.

Accordingly, the answers for the arrangement of imbalances are B) (2,- 3) and D) (4,1).

To track down the answer for the arrangement of disparities y ≤ 1/2x - 3 and y + 2x > 6, we really want to test each answer decision to check whether it fulfills the two imbalances. Just response decisions B) (2,- 3) and D) (4,1) fulfill the two imbalances, making them the arrangements.

To learn more about inequalities, refer:

https://brainly.com/question/28895822

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