Answer:
72 W
Explanation:
60% is wasted, or:
0.60 (120 W) = 72 W
What is electronic configuration?
Answer:
Electronic Configuration is the distribution of electrons in sub shells (s,p,d,f).
For Example,
The electronic configuration of Carbon (6 electrons) is [tex]1s^22s^22p^2[/tex]
Is Einstein's equation E=mc^2 is applicable on our earth if it is not why?is it applicable in space can a body moves through speed of light
◦•●◉✿hello friend ur answer✿◉●•◦
◦•●◉✿What does E mc2 actually mean?
E = mc2. It's the world's most famous equation, but what does it really mean? "Energy equals mass times the speed of light squared." On the most basic level, the equation says that energy and mass (matter) are interchangeable; they are different forms of the same thing.✿◉●•◦
Ratio of acceleration due to grabity and universal gravitational constant
Answer:
acceleration due to gravity = 9.8m/s^2
universal gravitational constant= 6.67×10 ^_11 nm^2 kg_2
now, ratio=9.8/6.67×10^_11.
Why are fuel cells used on space shuttles instead of batteries?
Answer:
Fuel cells are used in the space shuttle as one component of the electrical power system. ... The fuel cell power plants generate heat and water as by-products of electrical power generation. The excess heat is directed to fuel cell heat exchangers, where the excess heat is rejected to Freon coolant loops
1. Two blocks (5.0 kg and 6.0 kg) are connected through a frictionless system. The angle of
the ramp is 45°
A. Find the tension in the string.
B. Determine the normal force on the 5.0 kg block.
Answer: A) 45.5N b) 34.6N
Explanation:
Given the following :
Mass of block A(m1) = 5kg
Mass of block B (m2) = 6kg
Angle of incline (Θ) = 45°
Force pulling the down the incline = m1×a×sinΘ
Tension (T) = (m2×a) - (m2)×g
Where g = acceleration due to gravity
a = acceleration
Net force = (5×9.8×sin45°) - (6×9.8)
Net force = 34.648232 - 58.8
The net force acting on the body = 24.4N
Therefore,
Acceleration, a = Net force/ total mass
a = 24.4 / (6+5)
a = 2.22ms^-2
T = (m2 ×g) - (m2×a)
T = (6 × 9.8) - (6 × 2.22)
T = 58.8 - 13.32
T = 45.48
T = 45.5N
B) Normal reaction:
Horizontal component:
m1gCosΘ = 5 × 9.8 × cos45°
= 5 × 9.8 × 0.7071067
= 34.648232
= 34.6N
The tension on the string is 45.62N and the normal force is 34.65N
Data;
m1 = 5.0kgm2 = 6.0kgangle = 45°Tension in The StringTaking the two mass into consideration
for the 6kg mass
[tex]6g - 6a[/tex]
for the 5kg mass
[tex]5gsin45 + 5a\\[/tex]
Equating the tension in both equations
[tex]6g - 6a = 5gsin45 + 5a[/tex]
Let's solve for a
[tex]6a + 5a = 6g - 5gsin45\\11a = 6g - 5gsin45\\a = \frac{6g - 5gsin45}{11}\\ a = \frac{6* 9.8 - 5*9.8*sin45}{11}\\ a = 2.1956 m/s^2\\T = 6g - 6a\\T = 6*9.8 - 6*2.1956\\T = 45.62N[/tex]
b)
The normal force on the 5kg block.
The normal force on the 5kg block can be calculated as
[tex]N = 5 * 9.8 cos 45 = 34.65N[/tex]
The tension on the string is 45.62N and the normal force is 34.65N
Learn more on tension and normal force here;
https://brainly.com/question/24994188
when is the acceleration of a body is positive, negative and zero?
Answer:
In vector form , if angle between velocity vector and acceleration vector is less than 90° and greater than 0° then it is positive acceleration and if it is less than 180° and greater than 90° then it is negative acceleration. If there is no acceleration vector then it is called zero acceleration
Explanation:
Answer:
The acceleration is positive when it's in the same direction as that of velocity. It keeps on increasing the velocity. In this case, velocity is not constant.
The acceleration is negative when it is in the direction opposite to that of velocity. It keeps on decreasing the speed of body.
The acceleration is zero when the body moves with a constant velocity in any particular direction.
a shot putter shoots a 7.3kg shot from rest to 14m/s in 1.5s. what was the average power?
Answer: 477W
Explanation:
Given the following :
Mass (m) = 7.3kg
Initial Velocity (u) = 0
Final velocity (v) = 14m/s
time (t) = 1.5s
Power = workdone (W) / time (t)
The workdone can be calculated as the change in kinetic energy (KE) :
Recall ;
KE = 0.5mv^2
Therefore, change in KE is given by:
0.5mv^2 - 0.5mu^2
Change in KE = 0.5(7.3)(14^2) - 0.5(7.3)(0^2)
Change in KE = 715.4J
Therefore ;
Average power = Workdone / time
Workdone = change in KE = 715.4N
Average power = 715.4 / 1.5
Average power = 476.93333 W
= 477W
What is the meaning of refraction
Answer:
A change of direction that light undergoes when it enters a medium with a different density from the one through which it has been traveling.
Answer:
the fact or phenomenon of light radio waves etc being deflected in passing obliquely through the interface between one ,medium and another or through a medium of varying density
Explanation:
Samuel applies a horizontal force of 35.0 N to a sleigh over a distance of 1.50 m along a level surface. Calculate the work done on the sleigh by samuel. show your work.
Answer:
52.5 J
Explanation:
Work done (W) is the product of the force (F) applied on a body and the distance (s) moved in the direction of the force.
i.e W = F × s
It is a scalar quantity and measured in Joules (J).
Given that: F = 35.0 N and s = 1.50 m, then;
W = F × s
W = 35.0 × 1.5
= 52.5 J
Therefore, the work done on the sleigh by Samuel is 52.5 J.
A body is acted upon by a force of 4N.
As a result, the velocity of the body has
changed from 0.3 m/s to 0.1 m/s passing
through a certain distance. If the mass
of the body is 1 kg, find the distance travelled.
[tex]\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}[/tex]
Actually Welcome to the Concept of the Kinematics.
so here we get as,
V^2 = U^2 + 2as
so here, a = -0.2 m/s^2
(0.1)^2 = (0.3)^2 + (-0.2)(s)
=> 0.01 = 0.09 - 0.2s
=> 0.2s = 0.08
=> s = 0.08/0.2
=> s = 0.4 m
a disc starts from rest with an angular acceleration completes 10 revolutions in 2 seconds. the time taken by it to complete 10 more revolution from that instant is
Starting from rest, the disc completes [tex]\theta[/tex] revolutions after [tex]t[/tex] seconds according to
[tex]\theta=\dfrac\alpha2t^2[/tex]
with angular acceleration [tex]\alpha[/tex]. It completes 10 rev in 2 s, which means
[tex]10\,\mathrm{rev}=\dfrac\alpha2(2\,\mathrm s)^2\implies\alpha=5\dfrac{\rm rev}{\mathrm s^2}[/tex]
Find the time it takes to complete 20 rev with this acceleration:
[tex]20\,\mathrm{rev}=\dfrac12\left(5\dfrac{\rm rev}{\mathrm s^2}\right)t^2\implies t=\sqrt8\,\mathrm s\approx2.83\,\mathrm s[/tex]
so it takes approximately 0.83 s to complete 10 more rev.
What will happen if the value of g that is 9.8m/s^2 becomes zero???
Answer:
everything will fly about endlessly
Explanation:
the gravitational mass or whatever is now zero, this implies that object that are attracted to each other would no longer gain that attraction due to the absence of the force of attraction putting everything in place
Answer:
The earth will become an unhabitable planet.
Explanation:
I think the earth starts losing the atmosphere and of course you know what will happen next.
A gas is held at atmospheric pressure, approximately 100kPa, and room temperature, 298K,
in a container closed with a piston. The piston is initially in a fixed position so the container has a volume of 2.0dm3.
The gas is heated to a temperature of 100∘C
What is the pressure in the container?
Answer:
125 KPa
Explanation:
Data obtained from the question include:
Initial pressure (P1) = 100 KPa
Initial temperature (T1) = 298 K
Final temperature (T2) = 100°C = 100°C + 273 = 373 K
Final pressure (P2) =..?
Since the volume of the container is fixed, the final pressure in the container can be obtained as follow:
P1/T1 = P2/T2
100/298 = P2/373
Cross multiply
298 x P2 = 100 x 373
Divide both side by 298
P2 = (100 x 373) / 298
P2 = 125.2 ≈ 125 KPa
Therefore, the final pressure in the container is approximately 125 KPa.
A box of mass 4.5 kg is pushed across a rough surface (μK = 0.18) for a distance of 2.0 m by a constant force of 10 N. If the object reaches a speed of 2.0 m/s by the end of the push, what was its speed at the beginning of the push?
Answer:
Explanation:
Work done by force applied = force x displacement
= 10 x 2 = 20 J
Negative work done by frictional force
= μ mg x d where μ is coefficient of kinetic friction , m is mass and d is displacement
= - .18 x 4.5 x 9.8 x 2
= - 15.87 J
Net positive work done on the mass = 4.13 J
If v was the initial velocity
increase in kinetic energy = positive work done on mass
= 1 / 2 m v² - 1/2 m u² = 4.13 where v is final and u is initial velocity
1 /2 x 4.5 x 2 ² - 1/2 x 4.5 u² = 4.13
9 - 2.25 u² = 4.13
2.25 u² = 4.87
u² = 2.16
u = 1.47 m /s .
Which describes refraction? *
10 points
O
Refracted rays travel through a boundary into a new medium.
O
The angle of incidence is the same for angle of refraction
Refracted rays change direction and go back to the original medium
Answer:
Refracted rays travel through a boundary into a new medium.
Explanation:
Refracted rays travel through a boundary into a new medium. is only true for refraction.
The angle of incidence is the same for angle of refraction, is not true for refraction. Refraction follows Snell's law, states that ratio of the sine of the angle of refraction and the sine of the angle of incidence is always constant and equivalent to the ratio of phase velocities of the two mediums it is passing through.
Refracted rays change direction and go back to the original medium is false for refraction however, it is true for reflection.
0.0000302 in scientific notation
Answer:
3.02x10^-5
Explanation:
A scientific notation consists of
c x 10^n
the c must be a number between 1-9, while n must be an integer.
it indicates the c being multiplied by the nth power of 10.
From 0.0000302, we need to move the decimal to after 3 so that 3.02 can be a number between 1-9. When moving the decimal point to the right side, each digit moved counts as -1 power of 10.
So, to give 3.02, we need to move the decimal by 5 digits. hence, we can conclude n = -5.
0.0000302 = 3.02x10^-5
5. A bus starting from rest accelerates in a straight line at a constant rate of 3m/s2 for 8s. Calculate the distance travelled by the bus during this time interval.
Answer:
d = 96 meters
Explanation:
a = acceleration
t = time
d = distance
[tex]d = \frac{1}{2} \times a \times {t}^{2} [/tex]
[tex]d = \frac{1}{2} \times 3 \times {8}^{2} [/tex]
[tex]d = 96[/tex]
a device has a least count of 0.01m if it measures a length less than 100m the minimum and maximum number of significant figure are
a)1 and 2
B)2 and 3
C)1 and 4
D) 0 and 2
Answer:
C) 1 and 4
Explanation:
Least count is .01 m . If one measures any number between 100 and 99 , it will be like 99.25 or 99.37 m . So number of significant figure will be 4 ( maximum )
The least one can measure is .01 so least number of significant figure possible is 1 .
A force of 6 N is used to open a door, wherein the distance of the force to the axis of rotation is 80 cm. If the angular acceleration it acquires is 0.5 rad/s 2, determine the moment of inertia of the door.
Explanation:
∑τ = Iα
(6 N) (0.80 m) = I (0.5 rad/s²)
I = 9.6 kg m²
A car speeds over a hill past point A, as shown in the figure. What is the maximum speed the car can have at point A such that its tires will not leave the track? Round to one decimal place and include units. Image:
Answer:
see explanations below
Explanation:
At the point when the car leaves the track, the reaction on the road is zero, meaning that the centrifugal force equals the gravitation force, namely
mv^2/r = mg
Solve for v in SI units
v^2 = gr = 9.81 m/s^2 * 14.2 m = 139.302 m^2/s^2
v = sqrt(139.302) = 11.8 m/s
Answer: at 11.8 m/s (26.4 mph) car will leave the track.
Define like and unlike forces
Answer:
Like forces are the forces that are parallel to each other and have the same direction. Unlike forces are the forces that parallel yet have directions inverse to each other.
hope this helps :)
Answer:
Like Parallel forces are the forces that are parallel to each other and have the same direction. Unlike parallel forces are the forces that parallel yet have directions inverse to each other
Explanation:
Where is the energy in a glucose molecule stored?
Answer:
Energy is stored in the bonds between atoms
Answer:
Energy is stored in the bonds between atoms
Explanation:
Ape-x
Sb-40 a boat operating in a narrow channel is required to keep as close as is safe to what side?
Answer:
The not alligator side.
Obviously the middle, both sides will be shallow, so the middle will most likely be the deepest part.
Explanation:
how does an electric iron work when the power is on
Answer:
The basic principle on which the electric iron works is that when a current is passed through a piece of wire, the wire heats up. This heat is distributed to the sole (base) plate of the electric iron through conduction.
Will Mark Brainliest if Correct PLZ!!!!! A bullet is shot at some angle above the horizontal at an initial velocity of 87m/s on a level surface. It travels in the air for 13.6 seconds before it strikes the ground 760 m from the shooter. At what angle above the horizontal was the bullet fired? Round to the nearest whole number and include units in your answer Use g= -9.8 m/s2 for the acceleration of gravity.
Answer:
≅50°
Explanation:
We have a bullet flying through the air with only gravity pulling it down, so let's use one of our kinematic equations:
Δx=V₀t+at²/2
And since we're using Δx, V₀ should really be the initial velocity in the x-direction. So:
Δx=(V₀cosθ)t+at²/2
Now luckily we are given everything we need to solve (or you found the info before posting here):
Δx=760 mV₀=87 m/st=13.6 sa=g=-9.8 m/s²; however, at 760 m, the acceleration of the bullet is 0 because it has already hit the ground at this point!With that we can plug the values in to get:
[tex]760=(87)(cos\theta )(13.6)+\frac{(0)(13.6^{2}) }{2}[/tex]
[tex]760=(1183.2)(cos\theta)[/tex]
[tex]cos\theta=\frac{760}{1183.2}[/tex]
[tex]\theta=cos^{-1}(\frac{760}{1183.2})\approx50^{o}[/tex]
You are helping your friend move a new refrigerator into his kitchen. You apply a horizontal force of 272 N in the negative x direction to try and move the 61 kg refrigerator. The coefficient of static friction is 0.62. (a) How much static frictional force does the floor exert on the refrigerator? Give both magnitude (in N) and direction.
Answer:
F_f = 370.636 N
Explanation:
We are given;
co-effficient of static friction;μ = 0.62
mass of the object;m = 61 kg
acceleration due to gravity;g = 9.8 m/s²
The maximum force of static friction is given by the formula:
F_f = μmg
Plugging in the relevant values, we have;
F_f = 0.62 × 61 × 9.8
F_f = 370.636 N
Now, we are told that a horizontal force of 272 N in the negative x direction to try and move.
Since the Frictional force exceeds this horizontal force, it means the Fridge is not going to move and would require a greater force
Derive the following equations for uniformly accelerated motion by graphical method. a) Velocity -time relation b) Position - time relation 3) Position – velocity relation.
Answer:
a) velocity - time realation
that graph's gradient gives the uniform acceleration
A 28-turn circular coil of radius 4.40 cm and resistance 1.00 Ω is placed in a magnetic field directed perpendicular to the plane of the coil. The magnitude of the magnetic field varies in time according to the expression B = 0.010 0t + 0.040 0t2, where B is in teslas and t is in seconds. Calculate the induced emf in the coil at t = 4.20 s.
Answer:
ε = -0.0589V = -58.9mV
Explanation:
In order to calculate the induced emf in the coil, you use the following formula:
[tex]\epsilon=-N\frac{d\Phi_B}{dt}=-N\frac{d(SBcos\alpha)}{dt}[/tex] (1)
ε: induced emf = ?
N: turns of the coil = 28
ФB: magnetic flux trough the coil
S: cross sectional area of the circular coil = π.r^2
r: radius of the cross sectional area of the coil = 4.40cm = 0.044m
B: magnetic field
α: angle between the direction of the magnetic field and the direction of the normal to the cross area of the coil = 0°
You take into account that the area is constant respect to the magnetic field that cross it. Only the magnetic field is changing with time. The magnetic field depends on time as follow:
[tex]B(t)=0.010t+0.040t^2[/tex] (2)
You replace the expression (2) into the equation (1), evaluate the derivative, and replace the values of the other parameters for t =4.20s:
[tex]\epsilon=-NS\frac{dB}{dt}=-NS\frac{d}{dt}[0.010t+0.040t^2]\\\\\epsilon(t)=-NS(0.010+0.080t)\\\\\epsilon(t)=-(28)(\pi(0.044m)^2)(0.010T/s+0.080T/s^2(4.20s))\\\\\epsilon(t)=-0.0589V=-58.9mV[/tex]
The induced emf in the coil is -58.9mV
Suppose that an object is moving with a constant velocity. Make a statement concerning its acceleration
When an object is moving at a constant velocity, the acceleration of the object is zero because the change in the velocity of the object is zero.
Acceleration is defined as the change in velocity per change in time of motion.
The acceleration of an object is calculated as;
[tex]a = \frac{\Delta v}{\Delta t } = \frac{v_2 - v_1}{t_2 - t_1}[/tex]
When an object is moving at a constant velocity, the change in the velocity of the object is zero.
[tex]v_2 = v_1\\\\a = \frac{v_2 - v_1}{t_2 -t_1} = \frac{v_2 - v_2}{t_2 -t_1} = 0[/tex]
Thus, we can conclude that when an object is moving at a constant velocity, the acceleration of the object is zero because the change in the velocity of the object is zero.
Learn more here:https://brainly.com/question/19004094
Un automovil circula a 126km/h por una autopista. Su conductor observa que a 150 m delante de el, se encuentra un árbol caído que ocupa toda la calzada. Inmediatamente presiona los frenos con una aceleración de -3,5 m/s². Determinar si logra evitar el choque.
Answer:
El conductor no puede evitar el choque.
Explanation:
Primero, convierta la velocidad del conductor a m / s:
1 km/h = 0.277778 m/s
126 km/h = 126 * 0.277778 = 35 m/s
La velocidad del automóvil es de 35 m / s.
El conductor presiona los frenos con una aceleración de -3.5 m / s² para evitar un choque a 150 m por delante.
Veamos qué distancia se moverá el automóvil después de que comience a desacelerar.
Utilizaremos una de las ecuaciones de movimiento lineal de Newton:
[tex]v^2 = u^2 + 2as[/tex]
donde v = velocidad final = 0 m / s (el automóvil debe detenerse)
u = velocidad inicial = 35 m / s
a = aceleración = -3.5 m / s².
s = distancia recorrida
Por lo tanto:
[tex]0 = 35^2 + (2 * -3.5 * s)\\\\=> 1225 = 7.0s\\\\s = 1225 / 7 = 175 m[/tex]
Esto significa que el automóvil se detendrá a 175 m.
Por lo tanto, a esa velocidad y aceleración, el conductor chocará contra el árbol caído porque el automóvil no podrá detenerse antes de alcanzar la posición del árbol.