**Explanation:**

Work done by a force is given by :

[tex]W=Fd\cos\theta[/tex]

Where

F is force, d is displacement and [tex]\theta[/tex] is the angle between F and d.

In this problem, a crane is moving in downward direction, the force gravity is in downward direction and the tension is in upward direction.

We know that if force and displacement is in same direction, work is positive while if force and displacement is in oposite direction, work is negative.

**I would mean that, **[tex]W_g[/tex]** is positive, because gravity is parallel to the displacement and **[tex]W_t[/tex]** is negative, because the tension is opposite to the displacement.**

Help me Please!!!!!!!

The speed is equal to the area under the line up to the point where t .=15 s.

Do find the area of the triangle and that if the rectangle and add them together.

The area of the triangle is 25 and the rectangle is also 25 so the speed is 50 m/s

Do find the area of the triangle and that if the rectangle and add them together.

The area of the triangle is 25 and the rectangle is also 25 so the speed is 50 m/s

Define reflection of sound?

The reflection of sound is the movement of sound waves bouncing off of a surface and back into another direction, hope this helped :)

A

6. All other changeable factors that must

be kept the same to ensure a fair test

(what you keep the same).

**Answer:**

a constant variable?

**Explanation:**

A constant variable is any aspect of an experiment that a researcher intentionally keeps unchanged throughout an experiment.

Experiments are always testing for measurable change, which is the dependent variable. You can also think of a dependent variable as the result obtained from an experiment. It is dependent on the change that occurs

What is the key for a successful relationship? and Why?

**Answer:**

communication, if you don't talk you'll never know what's going on.

**Explanation:**

-. What is the acceleration of 4 kg trolling bag pulled by a girl with a

force of 3 N?

**Answer:**

Acceleration(a) = 0.75 m/s²

**Explanation:**

**Given:**

Force(F) = 3 N

Mass of thing(m) = 4 kg

**Find:**

Acceleration(a)

**Computation:**

Force(F) = ma

3 = (4)(a)

Acceleration(a) = 3/4

**Acceleration(a) = 0.75 m/s²**

Your TV has a resistance of 10 ohms and a wall voltage of 120 V. How much current and power does it use

Answer:

Current used is 12 ampere.

Power is 1440 watts.

Explanation:

To find the current used by the TV.

Current (I) = voltage/resistance

Current= 120/10

Current is 12Ampere.

To get power used by the TV,

Power = voltage × current.

= 120× 12

Power = 1440 watts.

HELP PLEASE!!!

If we have a sample of silicon (Si) atoms that has 14 protons, 14 electrons, and 18 neutrons

What is the name of this specific silicon isotope?

si-14

si-32

si-46

si-153

**Answer:**

It is si-32

**Explanation:**

**Answer:**

silicon-32

**Explanation:**

just took the quiz and got it right

Which of the filling is a fossil fuel?

I need a picture to see what exactly this question is asking

The boys are finally old enough to compete in the box car derby race at the local fair. They have been working on their cars since the conclusion of the race last year. One boy's car raced down the track and placed 2nd in his race. However, the other boy's car started well but half-way through the race a wheel came off and his car came to a complete stop. The boy was very disappointed and the other boy felt horrible for his friend. Which of the following graphs best represents the motion of boy's car that stopped?

i think it’s b because they both stumbled up a hole

A 75 Kg skateboarder is riding downhill, exerting 25 N. What is their acceleration?

**Answer:**

[tex]a=0.33\frac{m}{s^2}[/tex]

**Explanation:**

Hello.

In this case, since the force is defined in terms of the mass and acceleration as follows:

[tex]F=ma[/tex]

Given the force and the mass, we can compute the acceleration as shown below:

[tex]a=\frac{F}{m}=\frac{25N}{75kg}=\frac{25kg\frac{m}{s^2} }{75kg}\\ \\a=0.33\frac{m}{s^2}[/tex]

Best regards.

A student uses a microwave oven to heat a meal. The wavelength of the radiation is 8.97 cm. What is the energy of one photon of this microwave radiation? Multiply the answer you get by 1025 to be able to input a number more easily into canvas. Enter to 2 decimal places.

**Answer:**

The energy of one photon is 2.21x10⁻²⁴ J. Multiplied by 10²⁵ is 22.10 J.

**Explanation: **

The energy (E) of a photon is:

[tex] E = h\frac{c}{\lambda} [/tex]

Where:

h: is the Planck's constant = 6.62x10⁻³⁴ J.s

λ: is the wavelength of the radiation = 8.97 cm

c: is the speed of light = 3.00x10⁸ m/s

[tex] E = h\frac{c}{\lambda} = 6.62 \cdot 10^{-34} J.s\frac{3.00\cdot 10^{8} m/s}{8.97 \cdot 10^{-2} m} = 2.21 \cdot 10^{-24} J [/tex]

Hence, the energy of one photon is 2.21x10⁻²⁴ J.

Now, if we multiply the answer by 10²⁵ we have:

[tex] E = 2.21 \cdot 10^{-24} J \cdot 10^{25} = 22.10 J [/tex]

I hope it helps you!

The **energy** of one **photon** is** 2.21x10⁻²⁴ J. Multiplied** by 10²⁵ is** 22.10 J.**

We know that

[tex]E = h\frac{c}{\lambda}[/tex]

Here

h be the **Planck's constant **= 6.62x10⁻³⁴ J.s

λ be the **wavelength** of the **radiation** = 8.97 cm

c be the **speed** of **light** = 3.00x10⁸ m/s

Now

Here we need to **multiply** the answer 10^25 so that the **correct** answer could come.

[tex]E = 6.62.10^{-34} \frac{3.00.10^{8}}{8.97.10^{-2}}[/tex]

= 2.21x10⁻²⁴ J.

= 22.10 J.

Hence, the** energy** of one **photon** is** 2.21x10⁻²⁴ J. Multiplied** by 10²⁵ is** 22.10 J.**

learn more about **energy** here; https://brainly.com/question/24719731

Question 4

Which of the following is unique for any given element?

O the mass of a neutron

o the number of neutrons

o the charge on the electons

O the number of protons

the number of protons

it's unique for any element because it's determined by the atomic number and no two elements have the same atomic number

it's unique for any element because it's determined by the atomic number and no two elements have the same atomic number

Compare and contrast the CONFLICT (choose one) in the short story you read with the elements appearing in The Watsons Go to Birmingham—1963. Explain how they are similar or different in a few sentences.

**Answer:**

they were in two places in flint and Birmingham and in Birmingham it is hot but flint of cold the Simi is they both have Sunday school for Joetta

**Explanation:**

use in your own words teachers know when your not trust me.

The Earth's magnetic field is modeled as that of a bar magnet with the geographic poles being Magnetic poles of the bar magnet, Based on our definitions of Magnetic Poles, if you were to go to the Earth's Geographic North Pole, you would be at a Magnetic _______________ of the bar magnet.

**Answer:**

**South pole**

**Explanation:**

In a bar magnet, field lines go from the North Pole to the South Pole (outside the magnet).

As the earth magnetic field lines go from South Pole (geographic) to the North one, this means that the North pole (geographic) really behaves as a South Pole (magnetic).

A car which is traveling at a velocity of 15 m/s undergoes an acceleration of 6.5 m/s2 over a distance of 340 m. How fast is it going after that acceleration?

**Answer:68.15m/s**

**Explanation:**

**Given: **

v₁=15m/s

a=6.5m/s²

v₁=?

x=340m

**Formula:**

v₁²=v₁²+2a (x)

**Set up:**

=[tex]\sqrt{15m/s} ^{2} +2(6.5m/s^2)(340m)[/tex]

Consider a particle of mass m which can move freely along the x axis from -a/2 to a/2, but which is strictly prohibited from being found outside this region. The wave function of the particle within the allowed region is

**Answer:**

φ = B sin (2π n/a x)

**Explanation:**

In quantum mechanics when a particle moves freely it implies that the potential is zero (V = 0), so its wave function is

φ = A cos kx + B sin kx

we must place the boundary conditions to determine the value of the constants A and B.

In our case we are told that the particle cannot be outside the boundary given by x = ± a / 2

therefore we must make the cosine part zero, for this the constant A = 0, the wave function remains

φ = B sin kx

the wave vector is

k = 2π /λ

now let's adjust the period, in the border fi = 0 therefore the sine function must be zero

φ (a /2) = 0

0 = A sin (2π/λ a/2)

therefore the sine argument is

2π /λ a/2 = n π

λ= a / n

we substitute

φ = B sin (2π n/a x)

How long would it take you to walk 3,962 km from New York to Los

Angeles?

**Answer:**

913 hours ur welcome :)

A boat initially moving at 10 m/s accelerates at 2 m/s for 10 s. What is the velocity of the boat after 10 seconds?

**Answer:**

30 m/s

**Explanation:**

v = u + at

given that,

u = 10 m/s (initial speed)a = 2 m/s^2 t = 10sv =?(final speed)v = 10 + ( 2 × 10)

v = 10 + 20

v = 30 m/s

describe the energy conversion that occurs in a diesel engine

A diesel engine is a type of heat engine that uses the internal combustion process to convert the energy stored in the chemical bonds of the fuel into useful mechanical energy. ... First, the fuel reacts chemically (burns) and releases energy in the form of heat.

Write a function to accept a vector of masses (m) from the user and gives the corresponding energy to them. Energy vector is the output of the program. Constant c is the speed of light which is 2.9979 x 108 m/s inside the function.

**Answer:**

Written in Python

def energyvector(mass):

c = 2.9979 * 10**8

energy = mass * c ** 2

print(round(energy,2))

**Explanation:**

**This line defines the function**

def energyvector(mass):

**This line initializes the speed of light**

c = 2.9979 * 10**8

**This line calculates the corresponding energy**

energy = mass * c ** 2

**This line prints the calculated energy**

print(round(energy,2))

Help me out on this?

I can’t see the problem

what phase changes take place when you are adding energy to the substance

**Answer:**

**During a phase change, a substance undergoes transition to a higher energy state when heat is added, or to a lower energy state when heat is removed. Heat is added to a substance during melting and vaporization. Latent heat is released by a substance during condensation and freezing. Explanation:**

A sleigh is being pulled horizontally by a train of horses at a constant speed of 6.38 m/s. The magnitude of the normal force exerted by the snow-covered ground on the sleigh is 7.50 ✕ 103 N.

(a) If the coefficient of kinetic friction between the sleigh and the ground is 0.26, what is the magnitude of the kinetic friction force experienced by the sleigh?

N

(b) If the only other horizontal force exerted on the sleigh is due to the horses pulling the sleigh, what must be the magnitude of this force?

N

**Answer:**

(a). The kinetic friction force is 1950 N.

(b).** **The magnitude of force will be equal of friction force

**Explanation:**

**Given that,**

Constant speed = 6.38 m/s

Force [tex]F=7.50\times10^{3}\ N[/tex]

Kinetic friction = 0.26

**(a). We need to calculate the friction force**

**Using formula of friction force**

[tex]f_{k}=\mu F_{N}[/tex]

Put the value into the formula

[tex]f_{k}=0.26\times7.50\times10^{3}[/tex]

[tex]f_{k}=1950\ N[/tex]

**(b).** If the only other horizontal force exerted on the sleigh is due to the horses pulling the sleigh,

**We need to calculate the magnitude of this force**

**According to given data,**

The same force will be applied to keep constant velocity.

**Hence, (a). The kinetic friction force is 1950 N.**

**(b). The magnitude of force will be equal of friction force. **

(a). The **kinetic** **friction force** is **1950 N.**

(b). The **magnitude** of force will be **equal** of friction force

a. The magnitude of the kinetic friction force **experienced** by the **sleigh** is

[tex]= 0.76 \times 7.50 \times 10^3[/tex]

= 1950 N

b. It should be equivalent to the** friction force. **

Learn more: https://brainly.com/question/24908711?referrer=searchResults

What's the difference between an open cluster and a globular cluster

**An open cluster is a group of up to a few thousand stars that were formed from the same giant molecular cloud, and are still loosely gravitationally bound to each other. In contrast, globular clusters are very tightly bound by gravity. ... Open clusters are very important objects in the study of stellar evolution.**

In a mattress test, you drop a 7.0 kg bowling ball from a height of 1.5 m above a mattress, which as a result compresses 15 cm as the ball comes to a stop. (a) What is the kinetic energy of the ball just bef

**Answer:**

**(a)** The kinetic energy of the bowling ball just before it hits the matress is 102.974 joules.

**(b)** The work done by the gravitational force of Earth on bowling ball during the first part of the fall is 102.974 joules.

**(c)** Work done by gravitational force on bowling ball when mattress is compressed is 10.298 joules.

**(d)** The work done by the mattress on the bowling ball is 113.272 joules.

**Explanation:**

The statement is incomplete. The complete question is:

*In a mattress test, you drop a 7.0 kg bowling ball from a height of 1.5 m above a mattress, which as a result compresses 15 cm as the ball comes to a stop.
*

*(a) **What is the kinetic energy of the ball just before it hits the mattress? *

*(b)** How much work does the gravitational force of the earth do on the ball as it falls, for the first part of the fall (from the moment you drop it to just before it hits the mattress)? *

*(c)** How much work does the gravitational force do on the ball while it is compressing the mattress?
*

*(d)** How much work does the mattress do on the ball? (You’ll need to use the results of parts **(a)** and **(c)**）*

**(a)** Based on the Principle of Energy Conservation, we know that ball-earth system is conservative, so that kinetic energy is increased at the expense of gravitational potential energy as ball falls:

[tex]K_{1}+U_{g,1} = K_{2}+U_{g,2}[/tex] **(Eq. 1)**

Where:

[tex]K_{1}[/tex], [tex]K_{2}[/tex] - Kinetic energies at top and bottom, measured in joules.

[tex]U_{g,1}[/tex], [tex]U_{g,2}[/tex] - Gravitational potential energies at top and bottom, measured in joules.

Now we expand the expression by definition of gravitational potential energy:

[tex]U_{g,1}-U_{g,2} = K_{2}-K_{1}[/tex]

[tex]K_{2}= m\cdot g \cdot (z_{1}-z_{2})+K_{1}[/tex] **(Eq. 1b)**

Where:

[tex]m[/tex] - Mass of the bowling ball, measured in kilograms.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]z_{1}[/tex], [tex]z_{2}[/tex] - Initial and final heights of the bowling ball, measured in meters.

If we know that [tex]m = 7\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]z_{1}= 1.5\,m[/tex], [tex]z_{2} = 0\,m[/tex] and [tex]K_{1} = 0\,J[/tex], the kinetic energy of the ball just before it hits the matress:

[tex]K_{2} = (7\,kg)\cdot \left(9.807\,\frac{m}{s^{2}}\right)\cdot (1.5\,m-0\,m)+0\,m[/tex]

[tex]K_{2} = 102.974\,J[/tex]

The kinetic energy of the bowling ball just before it hits the matress is 102.974 joules.

**(b)** The gravitational work done by the gravitational force of Earth ([tex]\Delta W[/tex]), measured in joules, is obtained by Work-Energy Theorem and definition of gravitational potential energy:

[tex]\Delta W = U_{g,1}-U_{g,2}[/tex]

[tex]\Delta W = m\cdot g\cdot (z_{1}-z_{2})[/tex] **(Eq. 2)**

If we know that [tex]m = 7\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]z_{1}= 1.5\,m[/tex] and [tex]z_{2} = 0\,m[/tex], then the gravitational work done is:

[tex]\Delta W = (7\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (1.5\,m-0\,m)[/tex]

[tex]\Delta W = 102.974\,J[/tex]

The work done by the gravitational force of Earth on bowling ball during the first part of the fall is 102.974 joules.

**(c)** The work done by the gravitational force of Earth while the bowling when mattress is compressed is determined by Work-Energy Theorem and definition of gravitational potential energy:

[tex]\Delta W = U_{g,2}-U_{g,3}[/tex]

Where [tex]U_{g,3}[/tex] is the gravitational potential energy of the bowling ball when mattress in compressed, measured in joules.

[tex]\Delta W = m\cdot g \cdot (z_{2}-z_{3})[/tex]

Where [tex]z_{3}[/tex] is the height of the ball when mattress is compressed, measured in meters.

If we know that [tex]m = 7\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]z_{2}= 0\,m[/tex] and [tex]z_{3} = -0.15\,m[/tex], the work done is:

[tex]\Delta W = (7\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot [0\,m-(-0.15\,m)][/tex]

[tex]\Delta W = 10.298\,J[/tex]

Work done by gravitational force on bowling ball when mattress is compressed is 10.298 joules.

**(d)** The work done by the mattress on the ball equals the sum of kinetic energy just before mattress compression and the work done by the gravitational force when mattress is compressed:

[tex]\Delta W' = K_{2}+\Delta W[/tex]

([tex]K_{2} = 102.974\,J[/tex], [tex]\Delta W = 10.298\,W[/tex])

[tex]\Delta W' = 113.272\,J[/tex]

The work done by the mattress on the bowling ball is 113.272 joules.

What do mammoths and tigers need energy for

Muscles

.............

.............

Weight of a person's muscles, bones, tendons, and ligaments.

A. flexibility

B. lean mass

C. aerobic

I’m pretty sure it’s lean mass but let another guy answer you before you use mine

the radius of the earth social

6,371km is the radius of the earth

3. A wye-connected load has a voltage of 480 V applied to it. What is the voltage dropped across each phase?

**Answer:**

[tex]E_s = 277.13V[/tex]

**Explanation:**

**Given**

[tex]Load\ Voltage = 480V[/tex]

**Required**

Determine the voltage dropped in each stage.

**The relation between the load voltage and the voltage dropped in each stage is **

[tex]E_l = E_s * \sqrt3[/tex]

**Where**

[tex]E_l = 480[/tex]

**So, we have:**

[tex]480 = E_s * \sqrt3[/tex]

**Solve for **[tex]E_s[/tex]

[tex]E_s = \frac{480}{\sqrt3}[/tex]

[tex]E_s = \frac{480}{1.73205080757}[/tex]

[tex]E_s = 277.128129211[/tex]

[tex]E_s = 277.13V[/tex]

**Hence;**

**The voltage dropped at each phase is approximately 277.13V**

Work Done by a Varying Force 06 Work and Energy

w of Energy

100%

2.) The force required to stretch a spring by 1 m from its unstretched length is

150 N. What is the force required to stretch the spring by 3 m?

A. 600 N

B. 450 N

C. 300 N

D. 200 N

**Answer:**

B. 450 N

**Explanation:**

Use Hooke's law:

F = kx

150 N = k (1 m)

k = 150 N/m

F = kx

F = (150 N/m) (3 m)

F = 450 N

PLS ANSWER WILL GIVE BRAINLIEST!! PLSS!In the play, the _____________of events is changed. But many of the characters are the same. Nonsense,________________, and distortion of time and space are themes in the novels as well as the play. This is on Alice in Wonderland and Through The Looking Glass. Please make sure you understand the text before answering.
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