A circle is represented by the equation x2+y2=445. a) State the radius. b) Find y if point A(-9,y) is on this circle.

Answers

Answer 1

Answer:

R= sqrt 445

Y = 19

Step-by-step explanation:

Radius is the square root of 445

Find y

So, First step is to substitute what you have

-9^2 + y^2 = 445

 81 + y^2 = 445

-81               -81

y^2 =364

Y is about 19

Let me know if I'm incorrect

Hope this helps :)


Related Questions

Ms. Walker's science class is doing an egg drop experiment from the balcony of their school. Each egg is protected by a contraption that the students collectively designed. The height of the egg, in feet, after x seconds is given by the expression below. What do the zeros of the expression represent? A. the maximum height of the egg B. the time at which the egg reaches its maximum height C. the horizontal distance traveled by the egg D. the time at which the egg reaches the ground

Answers

Answer:

An object balances itself when a perpendicular line drawn through its Centre of Gravity (CG), passes through its base.

See the picture of a popular toy given below. The horse, the rider and the ball are all joined together as one single unit. This entire unit is balanced on the thin black rod shown. At which of the indicated positions, could the Centre of Gravity (CG) of the horse, rider and ball unit be?

July 10 book Science up55 down8

AA BB

CC DD

Step-by-step explanation:

The total number of hamburgers sold by a national fast-food chain is growing exponentially. If 3 billion had been sold by 2003 and 9 billion had been sold by 2010, how many will have been sold by 2013

Answers

Answer:

F(10) = 14.41 Billion

The total number of hamburgers that will have been sold by 2013 is 14.41 billion.

Step-by-step explanation:

The exponential function representing the total number of hamburgers sold by a national fast-food chain which grows exponentially can be expressed as;

f(t) = p(a)^t

In 2003, t = 0 and f(0) = 3 Billion

f(0) = p = 3 billion

The initial value p = 3 billion

In 2010, t = (2010-2003) = 7

f(7) = p(a)^7 = 9 billion

3(a)^7 = 9

a^7 = 9/3 = 3

a = 3^(1/7)

Therefore, the function f(t) is;

f(t) = 3(3)^(t/7) .......2

In 2013, t = (2013 - 2003) = 10

Substituting t = 10 into equation 2;

f(10) = 3(3)^(10/7)

F(10) = 14.41195997001 Billion

F(10) = 14.41 Billion

The total number of hamburgers that will have been sold by 2013 is 14.41 billion.

the quotient of F and the product of r,s, and T

Answers

Behold the quotient of F and the product of r,s, and T:  F / (r·s·T)

The numerical of the statement the quotient of F and the product of r,s, and T is F/(r×s×T).

What are quotient, remainder, divisor, and dividend?

The number which is being divided is the dividend.

The number with which we are dividing is the divisor.

The result when a dividend is divided by the divisor is the quotient.

A remainder is the extra portion of a number when it isn't completely divisible.

Given, Are some variables F, r, s, and t.

Now, The product of r,s, and T is,

= r×s×T and the complete statement the quotient of F and the product of r,s, and T can be written as,

F/(r×s×T).

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A person has a bag containing dimes and nickels. There are a total of 120 coins in the bag, and the total value of the coins is $9.25. Determine how many dimes and nickels are in the bag. There are _____dimes. There are _____ nickels.

Answers

Answer:

There are 65 dimes. There are 55 nickels.

Step-by-step explanation:

This question can be solved using a system of equations.

I am going to say that:

x is the number of dimes

y is the number of nickels.

There are a total of 120 coins in the bag

This means that x + y = 120.

The total value of the coins is $9.25.

The dime is worth $0.10 and the nickel is worth $0.05. So

0.1x + 0.05y = 9.25

System:

[tex]x + y = 120[/tex]

[tex]0.1x + 0.05y = 9.25[/tex]

From the first equation:

[tex]y = 120 - x[/tex]

Replacing in the second:

[tex]0.1x + 0.05y = 9.25[/tex]

[tex]0.1x + 0.05(120 - x) = 9.25[/tex]

[tex]0.1x + 6 - 0.05x = 9.25[/tex]

[tex]0.05x = 3.25[/tex]

[tex]x = \frac{3.25}{0.05}[/tex]

[tex]x = 65[/tex]

[tex]y = 120 - x = 120 - 65 = 55[/tex]

There are 65 dimes. There are 55 nickels.

What is the standard form for 80000 + 200+ 2

Answers

Answer:

80202

Step-by-step explanation:

Simply add according to number value:

200 - 2 goes into hundreds place

2 - 2 goes into ones place

80000 - 8 goes into ten-thousands place

A data set includes 104body temperatures of healthy adult humans having a mean of 98.7degreesFand a standard deviation of 0.66degreesF.Construct a 99​%confidence interval estimate of the mean body temperature of all healthy humans. What does the sample suggest about the use of 98.6degreesFas the mean body​ temperature?

Answers

Answer:

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is between 98.53ºF and 98.87 ºF. 98.6ºF is part of the interval, so the sample suggests that the use of 98.6ºF as the mean body​ temperature is correct.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 104 - 1 = 103

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 103 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.99}{2} = 0.995[/tex]. So we have T = 2.624

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 2.624\frac{0.66}{\sqrt{104}} = 0.17[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 98.7 - 0.17 = 98.53ºF.

The upper end of the interval is the sample mean added to M. So it is 98.7 + 0.17 = 98.87 ºF.

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is between 98.53ºF and 98.87 ºF. 98.6ºF is part of the interval, so the sample suggests that the use of 98.6ºF as the mean body​ temperature is correct.

Suppose a random variable x is best described by a uniform probability distribution with range 22 to 55. Find the value of a that makes the following probability statements true.

a. P(X <= a) =0.95
b. P(X < a)= 0.49
c. P(X >= a)= 0.85
d. P(X >a )= 0.89
e. P(1.83 <= x <=a)= 0.31

Answers

Answer:

(a) The value of a is 53.35.

(b) The value of a is 38.17.

(c) The value of a is 26.95.

(d) The value of a is 25.63.

(e) The value of a is 12.06.

Step-by-step explanation:

The probability density function of X is:

[tex]f_{X}(x)=\frac{1}{55-22}=\frac{1}{33}[/tex]

Here, 22 < X < 55.

(a)

Compute the value of a as follows:

[tex]P(X\leq a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.95\times 33=[x]^{a}_{22}\\\\31.35=a-22\\\\a=31.35+22\\\\a=53.35[/tex]

Thus, the value of a is 53.35.

(b)

Compute the value of a as follows:

[tex]P(X< a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.49\times 33=[x]^{a}_{22}\\\\16.17=a-22\\\\a=16.17+22\\\\a=38.17[/tex]

Thus, the value of a is 38.17.

(c)

Compute the value of a as follows:

[tex]P(X\geq a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.85=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.85\times 33=[x]^{55}_{a}\\\\28.05=55-a\\\\a=55-28.05\\\\a=26.95[/tex]

Thus, the value of a is 26.95.

(d)

Compute the value of a as follows:

[tex]P(X\geq a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.89=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.89\times 33=[x]^{55}_{a}\\\\29.37=55-a\\\\a=55-29.37\\\\a=25.63[/tex]

Thus, the value of a is 25.63.

(e)

Compute the value of a as follows:

[tex]P(1.83\leq X\leq a)=\int\limits^{a}_{1.83} {\frac{1}{33}} \, dx \\\\0.31=\frac{1}{33}\cdot \int\limits^{a}_{1.83} {1} \, dx \\\\0.31\times 33=[x]^{a}_{1.83}\\\\10.23=a-1.83\\\\a=10.23+1.83\\\\a=12.06[/tex]

Thus, the value of a is 12.06.

A rectangular playground is to be fenced off and divided in two by another fence parallel to one side of the playground. Three hundred feet of fencing is used

dimensions of the playground that maximize the total enclosed area. What is the maximum area?

The smaller dimension is

feet

Answers

Answer:

50 ft by 75 ft3750 square feet

Step-by-step explanation:

Let x represent the length of the side not parallel to the partition. Then the length of the side parallel to the partition is ...

  y = (300 -2x)/3

And the enclosed area is ...

  A = xy = x(300 -2x)/3 = (2/3)(x)(150 -x)

This is the equation of a parabola with x-intercepts at x=0 and x=150. The line of symmetry, hence the vertex, is located halfway between these values, at x=75.

The maximum area is enclosed when the dimensions are ...

  50 ft by 75 ft

That maximum area is 3750 square feet.

_____

Comment on the solution

The generic solution to problems of this sort is that half the fence (cost) is used in each of the orthogonal directions. Here, half the fence is 150 ft, so the long side measures 150'/2 = 75', and the short side measures 150'/3 = 50'. This remains true regardless of the number of partitions, and regardless if part or all of one side is missing (e.g. bounded by a barn or river).

Legal descriptions tend to prefer neat straight lines from point to point, regardless of describing a square, rectangle, triangle or even a smooth circle. When might a property boundary end up being a squiggly line?

Answers

Answer:

When describing a property line drawn down the center of a creek bed

What is the solution to the system of linear equations below?
x+4y=22
2x+y=9

Answers

Answer:

[tex]\boxed{\sf \ \ \ x = 2 \ \ and \ \ y = 5 \ \ \ }[/tex]

Step-by-step explanation:

hello, we have two equation

(1) x + 4y = 22

(2) 2x + y = 9

let's multiply (1) by 2 and subtract (2)

2x + 8y - (2x + y) = 2*22 - 9 = 44 - 9 = 35

<=> 2x + 8y -2x -y = 35

<=> 7y = 35

<=> y = 35/7 = 5

we replace this value in (1) and it comes

x + 4*5 = 22

<=> x = 22 - 20 = 2

so the solution is

x = 2 and y = 5

hope this helps

The initial population of a town in the year 2010 was 20 000. By 2014, the population had grown exponentially to 32 500 people. Write an equation to represent the population of the town (P) over time in years (n).

Answers

Answer:

  P = 20000×1.625^(n/4)

Step-by-step explanation:

An exponential equation can be written using the given data:

  value = (initial value)×(growth factor in period)^(n/(period))

Here, the growth is by a factor of 32500/20000 = 1.625, and the period is 4 years. Then your exponential equation is ...

  P = 20000×1.625^(n/4)

answer if u love cats & dogs

Answers

Answer:

(7, 5.25) lies on the graph.

Step-by-step explanation:

We are given the following values

x = 4,   6,  8, 12 and corresponding y values are:

y = 3, 4.5, 6, 9

Let us consider two points (4, 6) and (6, 4.5) and try to find out the equation of line.

Equation of a line passing through two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is given as:

[tex]y=mx+c[/tex]

where m is the slope.

(x,y) are the coordinates from where the line passes.

c is the y intercept.

Here,

[tex]x_{1} = 4\\x_{2} = 6\\y_{1} = 3\\y_{2} = 4.5[/tex]

Formula for slope is:

[tex]m = \dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

[tex]m = \dfrac{4.5-3}{6-4}\\\Rightarrow m = \dfrac{1.5}{2}\\\Rightarrow m = \dfrac{3}{4}[/tex]

Now, the equation of line becomes:

[tex]y=\dfrac{3}{4}x+c[/tex]

Putting the point (4,3) in the above equation to find c:

[tex]3=\dfrac{3}{4}\times 4+c\\\Rightarrow 3=3+c\\\Rightarrow c =0[/tex]

So, final equation of given function is:

[tex]y=\dfrac{3}{4}x[/tex]

OR

[tex]4y=3x[/tex]

As per the given options, the point (7, 5.25) satisfies the equation.

So correct answer is [tex](7, 5.25)[/tex].

Determine whether the point (–3,–6) is in the solution set of the system of inequalities below. x ≤ –3 y < 5∕3x + 2

Answers

Answer:

The point (–3,–6) is not  in the solution set of the system of inequalities below.

x ≤ –3 y < 5∕3x + 2

Step-by-step explanation:

Given point (-3, -6)

inequality

x ≤ –3

It means that value of x should be less than or equal to -3

since in point (-3,-6) , -3 is point for representing x which is equal to -3 and hence satisfy the criteria for valid value of x,

thus, -3 lie in the solution set of inequality x ≤ –3

lets now see for y = -6

to do that we will put x = -3 in the given below inequality

y < 5∕3x + 2

y < 5∕3*-6 + 2

y < -10 + 2

y < - 8

Thus, inequality suggests that value of y should be less than -8.

but here y is -6, if we see number line -6 is greater than -8 and hence does not belong to the solution set  y < 5∕3x + 2 when x = -3

Thus, the point (–3,–6) is not  in the solution set of the system of inequalities below. x ≤ –3 y < 5∕3x + 2

A survey of 61,647 people included several questions about office relationships. Of the respondents, 26% reported that bosses scream at employees. Use a 0.05 significance level to test the claim that more than ¼ of people say that bosses scream at employees.

Answers

Step-by-step explanation:

n = 61,647, p = 0.26, q = 0.74

μ = p = 0.26

σ = √(pq/n) = 0.00177

At 0.05 significance, z = 1.96.

0.26 ± 1.96 × 0.00177

(0.257, 0.263)

0.25 is outside of the confidence interval, so we can conclude with 95% confidence that the proportion is greater than 0.25.

A tank contains 3,000 L of brine with 16 kg of dissolved salt. Pure water enters the tank at a rate of 30 L/min. The solution is kept thoroughly mixed and drains from the tank at the same rate. (a) How much salt is in the tank after t minutes

Answers

Answer:

The amount of salt in the tank after t minutes is

y= 16e^(t/100)kg

Step- by-step Explanation

The tank contain 3000L of the brine

The rate is 30L/ min

The solution is mixed thoroughly, therefore, the rate in= rate out

dy/dt= rate in to the tank= rate out of the tank

CHECK THE ATTACHMENT FOR DETAILED EXPLANATION

Two cities whose longitudes are 10E and 20W on the equator are apart

Answers

Step-by-step explanation:

to be honest I'm not sure how to do

Please need help Please

Answers

Answer: 14/11

Step-by-step explanation:

When 14/11 is multiplied by 1/4, you get a repeating decimal.  All repeating decimals are rational.

Hope it helps <3

Terry has a collection of 50 coins. There are only quarters and dimes in the collection. The total value of the coins is $8.00. How many dimes does he have?

Answers

Answer:

30 dimes and 20 quarters

30×.10=$3.00

20×.25=$5.00

30+20=50

$3+$5=$8

Suppose you were given the function F(x)=x^4-2x^3+3x^2-10x+3 and the factor (x-2). What is the value of a?

Answers

Answer:

Hope it helps..........

The given the function F(x)=x^4-2x^3+3x^2-10x+3 and the factor (x-2). Hence, the value of x is 7.5.

What is a function?

Function is a type of relation, or rule, that maps one input to specific single output.

The given the function F(x)=x^4-2x^3+3x^2-10x+3 and the factor (x-2).

here x = 2

Substitute in the function;

F(x)=x^4-2x^3+3x^2 - ax+3

F(2) = 2^4-2(2)^3+3(2)^2 - a(2) +3

F(2) = 16 - 16 + 12 - 2a +3

F(2) = 15 - 2a

15 - 2a = 0

15 = 2a

a = 7.5

Hence, the value of x is 7.5

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Want Brainliest? Get this correct Which of the following is the quotient of the rational expressions shown below?

Answers

Answer:

  [tex]\dfrac{4x^2+12x+5}{6x^2-3x}[/tex]

Step-by-step explanation:

Invert the denominator and multiply.

  [tex]\dfrac{2x+5}{3x}\div\dfrac{2x-1}{2x+1}=\dfrac{2x+5}{3x}\cdot\dfrac{2x+1}{2x-1}\\\\=\dfrac{(2x+5)(2x+1)}{(3x)(2x-1)}=\boxed{\dfrac{4x^2+12x+5}{6x^2-3x}}\qquad\text{matches choice A}[/tex]

Answer:

[tex]\frac{4x^2+12x+5}{6x^2-3x}[/tex]

Step-by-step explanation:

After using the reciprocal of the second term, the denominator will multiply out to be [tex]6x^2-3x[/tex]. There is only one option with that as the denominator so it must be the correct answer.

CAN SOMEONEHELP PLS ASAP

Answers

Answer:

a ≈ 2.2

Step-by-step explanation:

Using the Cosine rule in Δ ABC

a² = b² + c² - 2bc cos A

Here b = 3, c = 4 and A = 32° , thus

a² = 3² + 4² - (2 × 3 × 4 × cos32° )

    = 9 + 16 - 24cos32°

    = 25 - 24cos32° ( take the square root of both sides )

a = [tex]\sqrt{25-24cos32}[/tex] ≈ 2.2

A half marathon is 13.1 miles long. Leah is running a half marathon and has completed 7.75 miles. How many miles to
the finish line?

Answers

Answer:

5.35 more miles

Answer:

5.35 miles to the finish line

Step-by-step explanation:

Step one

13.1-7.75=

5.35

which of the following equations is equal to 2x^2+8 A. (2x-4i)(x-2i) B. (2x+4i)(x+2i) C. (2x-2i)(x+6i) D. (2x-4i)(x+2i)

Answers

Answer:

(2x-4i) (x+2i)

Step-by-step explanation:

2x^2+8

Factor out 2

2 ( x^2+4)

Writing as the difference of squares  a^2 -b^2 = (a-b) (a+b)

2 ( x^2 -(2i)^2)

2 ( x-2i) (x+2i)

Multiplying the 2 into the first term

(2x-4i) (x+2i)

A publisher reports that 31% of their readers own a particular make of car. A marketing executive wants to test the claim that the percentage is actually different from the reported percentage. A random sample of 100 found that 21% of the readers owned a particular make of car. Determine the P-value of the test statistic. Round your answer to four decimal places.

Answers

Answer:

[tex]z=\frac{0.21 -0.31}{\sqrt{\frac{0.31(1-0.31)}{100}}}=-2.162[/tex]  

Since is a bilateral test the p value would be:  

[tex]p_v =2*P(z<-2.162)=0.0306[/tex]  

Step-by-step explanation:

Information given

n=100 represent the random sample taken

[tex]\hat p=0.21[/tex] estimated proportion of the readers owned a particular make of car

[tex]p_o=0.31[/tex] is the value that we want to test

z would represent the statistic

[tex]p_v[/tex] represent the p value

Hypothesis to test

We need to conduct a hypothesis in order to test if the true proportion is 0.31 or no.:  

Null hypothesis:[tex]p=0.31[/tex]  

Alternative hypothesis:[tex]p \neq 0.31[/tex]  

The statistic is given by:

[tex]z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}[/tex] (1)  

And replacing we got:

[tex]z=\frac{0.21 -0.31}{\sqrt{\frac{0.31(1-0.31)}{100}}}=-2.162[/tex]  

Since is a bilateral test the p value would be:  

[tex]p_v =2*P(z<-2.162)=0.0306[/tex]  

A student writes an incorrect step while checking if the sum of the measures of the two remote interior angles of triangle ABC below is equal to the measure of the exterior angle. A triangle ABC is shown. The base of the triangle extends into a straight line. The angle formed between this straight line and the edge of the triangle is marked as p. The angle adjacent to p is marked as o, and the other two angles inside the triangle are marked as m and n. Step 1: m∠m + m∠n + m∠p = 180 degrees (sum of angles of a triangle) Step 2: m∠p + m∠o = 180 degrees (adjacent supplementary angles) Step 3: Therefore, m∠m + m∠n + m∠o = m∠o + m∠p Step 4: So, m∠m + m∠n = m∠p In which step did the student first make a mistake and how can it be corrected? Step 1; it should be m∠m + m∠n + m∠o = 180 degrees (sum of angles in a triangle) Step 1; it should be m∠m + m∠n + m∠o = 90 degrees (adjacent angles) Step 2; it should be m∠o + m∠p = 180 degrees (alternate exterior angles) Step 2; m∠p − m∠o = 90 degrees (alternate interior angles)

Answers

Answer:

(A)Step 1; it should be m∠m + m∠n + m∠o = 180 degrees (sum of angles in a triangle)

Step-by-step explanation:

In the triangle, the exterior angle = pThe adjacent interior angle =oThe two opposite angles are marked m and n

The steps followed by the student are:

Step 1: m∠m + m∠n + m∠p = 180 degrees (sum of angles of a triangle)

Step 2: m∠p + m∠o = 180 degrees (adjacent supplementary angles)

Step 3: Therefore, m∠m + m∠n + m∠o = m∠o + m∠p

Step 4: So, m∠m + m∠n = m∠p

We observe that the student made a mistake in Step 1, it should be m∠m + m∠n + m∠o = 180 degrees (sum of angles in a triangle).

p is outside the triangle, therefore it cannot form one of the angles in the triangle.

Let S be a sample space and E and F be events associated with S. Suppose that Pr (Upper E )equals 0.6​, Pr (Upper F )equals 0.2 and Pr (Upper E intersect Upper F )equals 0.1. Calculate the following probabilities. ​(a) Pr (E|F )​(b) Pr (F|E )​(c) Pr (E| Upper F prime )​(d) Pr (Upper E prime | Upper F prime )

Answers

Answer:

(a)0.5

(b)0.17

(c)0.625

(b)0.375

Step-by-step explanation:

Pr(E)=0.6​

Pr(F)=0.2

[tex]Pr(E\cap F)=0.1.[/tex]

(a)Pr (E|F )

[tex]Pr (E|F )=\dfrac{Pr(E \cap F)}{Pr(F)} \\=\dfrac{0.1}{0.2}\\\\=0.5[/tex]

(b)Pr (F|E )

[tex]Pr (F|E )=\dfrac{Pr(E \cap F)}{Pr(E)} \\=\dfrac{0.1}{0.6}\\\\=0.17[/tex]

(c)Pr (E|F')​

Pr(F')=1-P(F)

=1-0.2=0.8

[tex]Pr(E \cap F')=P(E)-P(E\cap F)\\=0.6-0.1\\=0.5[/tex]

Therefore:

[tex]Pr (E|F' )=\dfrac{Pr(E \cap F')}{Pr(F')} \\=\dfrac{0.5}{0.8}\\\\=0.625[/tex]

(d)Pr(E'|F')​

[tex]P(E'\cap F')=P(E \cup F)'\\=1-P(E \cup F)\\=1-[P(E)+P(F)-P(E\cap F)]\\=1-[0.6+0.2-0.1]\\=1-0.7\\=0.3[/tex]

Therefore:

[tex]Pr (E'|F' )=\dfrac{Pr(E' \cap F')}{Pr(F')} \\=\dfrac{0.3}{0.8}\\\\=0.375[/tex]

Can Someone help me!!! I need this ASAP! What number? Increased by 130% is 69? FYI: the answer is less than 69

Answers

Answer:

Hey there!

There are a few ways you could solve this problem, but the easiest would to be writing an equation.

You could say-

2.3x=69

Divide by 2.3

x=30

Hope this helps :)

Answer:

30

Step-by-step explanation:

the answer is 30 bc increasing something by 130% is multiplying it by 2.3 so technically you have to divide 69 by 2.3 which equals to 30

At a DBE lecture of 100 students, there are 29 women and 23 men. Out of these students, 4 are teachers and 24 are either men nor teachers. Find the number of women teachers attending the lecture

Answers

Answer:

20 teachers

Step-by-step explanation:

Because if you take 100 and minus it by 29, 23, 4 and 24 you get 20.

solve the proportion for y 11/8=y/13

Answers

Answer:

We can use the cross products property.

11/8 = y / 13

8y = 11 * 13

y = 11 * 13 / 8 = 17.875

Answer:

y=17.875

Step-by-step explanation:

[tex]\frac{11}{8} = \frac{y}{13}[/tex]

11(13)=8y

143=8y

y=17.875

Find the value of s(t(-3)):
s(x) = - 3x-2
t(x) = 5x - 4
Please helppp!

Answers

Step-by-step explanation:

(-3x-2/x) multiply by (-15x+12/x)

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