A circle has a diameter of 6 meters. Which statement about the circumference and area is true?

Answer:

Yes

Step-by-step explanation:

4/4 is the same thing as 4 divided by 4 which equals 1

7/8 is the same thing as 7 divided by 8 which equals 0.875

Since 1 > 0.875, 4/4 > 7/8

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer:

B) Independent

Step-by-step explanation:

Independent events:

Two events, A and B are independent, if:

[tex]P(A \cap B) = P(A) \times P(B)[/tex]

In this question:

[tex]P(A \cap B) = \frac{63}{200}[/tex]

[tex]P(A) \times P(B) = \frac{9}{20}*\frac{7}{10} = \frac{9*7}{20*10} = \frac{63}{200}[/tex]

Since [tex]P(A \cap B) = P(A) \times P(B)[/tex], these events are independent.

Answer:

(2−1)(3+2)

Step-by-step explanation:

Rewrite in product form

2x(3x+2) - 1(3x+2)

(2x-1) (3x+2)

Answer:

B?

Step-by-step explanation:

Can I have brainliest? It would help me out, if not thanks anyways! Hope this helped and have a nice day!

Answer:

The answer is 2x + -3y = 19

Step-by-step explanation:

no idea what the guy on top is saying

Answer:

True very true

Step-by-step explanation:

Answer: z=25 x=114

Step-by-step explanation:

Answer:

636

Step-by-step explanation:

SA=2LW+2LH+2WH

SA= 2(12)(10)+2(12)(9)+2(10)(9)= 636

Answer:

The answer is 636

Step-by-step explanation:

Brainliest maybe?

:)

Answer:

y = -3

Step-by-step explanation:

TO FIND :-

FACTS TO KNOW BEFORE SOLVING :-

A simple law of exponents which will be used to solve the problem :-

SOLUTION :-

[tex]3^3 \times 3^{(y-2)} = 3^{-2}[/tex]

[tex]=> 3^{3+y-2} = 3^{-2}[/tex]

[tex]=> 3^{y+1} = 3^{-2}[/tex]

Bases are same in both sides of equation. So , their powers must be equal to each other.

[tex]=> y + 1 = -2[/tex]

[tex]=> y = -2 - 1 = -3[/tex]

Answer:

y(t) =  3u₂(t) [ [tex]e^{-2t+4} - e^{-5t + 10)}[/tex] ] - 4u₅(t) [ [tex]e^{-2t+10)} - e^{-5t + 25)}[/tex] ]

Step-by-step explanation:

To find - y″+ 5y′ + 6y = 3δ(t − 2) − 4δ(t −5); y(0) = y′(0) = 0

Formula used -

L{δ(t − c)} = [tex]e^{-cs}[/tex]

L{f''(t) = s²F(s) - sf(0) - f'(0)

L{f'(t) = sF(s) - f(0)

Solution -

By Applying Laplace transform, we get

L{y″+ 5y′ + 6y} = L{3δ(t − 2) − 4δ(t −5)}

⇒L{y''} + 5L{y'} + 6L{y} = 3L{δ(t − 2)}  − 4L{δ(t −5)}

⇒s²Y(s) - sy(0) - y'(0) + 5[sY(s) - y(0)] + 6Y(s) = 3[tex]e^{-2s}[/tex] - 4[tex]e^{-5s}[/tex]

⇒s²Y(s) - 0 - 0 + 5[sY(s) - 0] + 6Y(s) = 3[tex]e^{-2s}[/tex] - 4[tex]e^{-5s}[/tex]

⇒s²Y(s) + 5sY(s) + 6Y(s) = 3[tex]e^{-2s}[/tex] - 4[tex]e^{-5s}[/tex]

⇒[s² + 5s + 6] Y(s) = 3[tex]e^{-2s}[/tex] - 4[tex]e^{-5s}[/tex]

⇒[s² + 3s + 2s + 6] Y(s) = 3[tex]e^{-2s}[/tex] - 4[tex]e^{-5s}[/tex]

⇒[s(s + 3) + 2(s + 3)] Y(s) = 3[tex]e^{-2s}[/tex] - 4[tex]e^{-5s}[/tex]

⇒[(s + 2)(s + 3)] Y(s) = 3[tex]e^{-2s}[/tex] - 4[tex]e^{-5s}[/tex]

⇒Y(s) = [tex]\frac{3e^{-2s} }{(s + 2)(s + 3)} - \frac{4e^{-5s} }{(s + 2)(s + 3)}[/tex]

Now,

Let

[tex]\frac{1}{(s+2)(s+3)} = \frac{A}{s+2} + \frac{B}{s+3} \\\frac{1}{(s+2)(s+3)} = \frac{A(s + 3) + B(s+2)}{(s+2)(s+3)}\\1 = As + 3A + Bs + 2B\\1 = (A+B)s + (3A + 2B)[/tex]

By Comparing, we get

A + B = 0 and 3A + 2B = 1

⇒A = -B

and

3(-B) + 2B = 1

⇒-B = 1

⇒B = -1

So,

A = 1

∴ we get

[tex]\frac{1}{(s+2)(s+3)} = \frac{1}{s+2} + \frac{-1}{s+3}[/tex]

So,

Y(s) = [tex]3e^{-2s}[ \frac{1}{(s + 2)} - \frac{1}{(s + 3)}] - 4e^{-5s}[ \frac{1}{(s + 2)} - \frac{1}{(s + 3)}][/tex]

⇒Y(s) = [tex]3e^{-2s} \frac{1}{(s + 2)} - 3e^{-2s} \frac{1}{(s + 3)} - 4e^{-5s}\frac{1}{(s + 2)} + 4e^{-5s}\frac{1}{(s + 3)}[/tex]

By applying inverse Laplace , we get

y(t) = 3u₂(t) [ [tex]e^{-2(t-2)} - e^{-5(t - 2)}[/tex] ] - 4u₅(t) [ [tex]e^{-2(t-5)} - e^{-5(t - 5)}[/tex] ]

⇒y(t) =  3u₂(t) [ [tex]e^{-2t+4} - e^{-5t + 10)}[/tex] ] - 4u₅(t) [ [tex]e^{-2t+10)} - e^{-5t + 25)}[/tex] ]

It is the required solution.

Answer:

(x - .20)(x - .50)

[tex]x^{2}[/tex] = (.20)(.50)

[tex]x^{2}[/tex] = 0.1

x = [tex]\sqrt{ .1[/tex]

x = .32

the product of two numbers decrease by 32%

====================================================

Explanation:

Let x be the reference angle where the question mark is located.

Opposite this angle x is 27. The adjacent side is 38.

Use the tangent ratio to tie the two sides together

tan(angle) = opposite/adjacent

tan(x) = 27/38

x = arctan(27/38)

x = 35.3947958 .... which is approximate

x = 35.4

Be sure that your calculator is in degree mode. The notation "arctan" refers to "arctangent" which is the same as inverse tangent. Your calculator should have a button labeled [tex]\tan^{-1}[/tex] to help compute this.

Step-by-step explanation:

The given angle is a 90° . Therefore the sum of both angles is 90° .

> 40 + x = 90

> x = 90 - 40

> x = 50

Solution 2 ;-

> 20 + x = 90

> x = 70

Answer:

yes

Step-by-step explanation:

yes

Answer:

Step-by-step explanation:

Farmers usually open bakery's to sell their produce or ship them to grocery stores like Walmart, Cosco, etc. I hope this answered your question since I don't quite understand...

Answer:

Perpendicular bisector

Step-by-step explanation:

Have a great day!!

Answer:

48

Step-by-step explanation:

One dozen is 12.

12 x 4 = 48

Answer:

Step-by-step explanation:

im assuming were solving for k so we wanna get it by itself

9k - 18 = -6

start by adding 18 to both sides

9k = 12

then divide both sides by 9

k = 12/9

hope this helps <3

Answer:

the answer is

k= 4/3

Step-by-step explanation:

9k-18=-6

9k=-6+18

9k=12

k= 12/9

simplify it which gives k=4/3 or in decimal form 1.333

Answer:

95/12 as an improper fraction.

Answer:

[tex]\frac{29}{12}[/tex] or 2 [tex]\frac{5}{12}[/tex]

Step-by-step explanation:

Answer:

∠TRU is supplementary with ∠PQS as SQ║TR.

Supplementary angles add up to 180°.

Consider ΔRTU

∠RUV is exterior angle and therefore is sum of ∠TRU and ∠RTU:

<TRU

Sum of 2 interiors =exterior

<RTU

Answer:

N/A

Step-by-step explanation:

Please be more specific, which is base and which is height

Answer:

Diameter of the circle = 7

Step-by-step explanation:

The exact question is as follows :

Given - The prom is in need of a floral archway, such as the one below. Segment RC is the perpendicular bisector of segment AH. If AH=6 and RC=2

To find - determine the diameter of the circle that contains AH.

Proof -

Given that,

AH = 6

RC = 2

Let us denote,

CB = x

So,

RB is the radius of the circle. It gives the value x + 2

As AH = 6

⇒AC = CH = 3

Also,

BH is the radius,

So, BH = x + 2

Now,

In triangle CBH,

BH² = CB² + HC²

⇒(x+2)² = x² + 3²

⇒x²+2² + 4x = x² + 9

⇒4 + 4x = 9

⇒4x = 9 - 4

⇒4x = 5

⇒x = 5÷4

⇒x = 1.5

So,

Radius = x + 2

           = 1.5 + 2 = 3.5

⇒Radius = 3.5

As we know,

Diameter = 2×Radius

                = 2×3.5

                = 7

⇒Diameter of the circle = 7

The Pythagoras is the sum of the square of two sides is equal to the square of the longest side. Then the diameter of the circle is 6.5 units.

It is a type of triangle in which one angle is 90 degrees and it follows the Pythagoras theorem and we can use the trigonometry function.

The prom is in need of a floral archway, such as the one below.

Segment RC is the perpendicular bisector of segment AH.

If AH = 6 and RC = 2.

Let CB be x.

Then the radius RB will be x + 2

BH = x + 2

Then by the Pythagoras theorem, we have

BH² = CB² + HC²

⇒ (x + 2)² = x² + 3²

⇒x² + 4 +4x = x² + 9

⇒ 4x = 5

⇒ x = 1.25

The radius will be

r = x + 2

r = 1.25 + 2

r = 3.25

Then the diameter will be

Diameter = 2 × r

Diameter = 2 × 3.25

Diameter = 6.5

More about the right-angle triangle link is given below.

https://brainly.com/question/3770177

Answer:

Option a. 1.2 is the correct answer

Step-by-step explanation:

Given the data in the question;

sample size n = 10

sub group = 6

The average of sample means x" = 3.2

Average range value R' = 0.6

the value of UCL for the R-chart = ?

To get the value of UCL for the R-chart, we say;

[tex]UCL_R[/tex] = D₄ × R'

from table of constants "Tabular values for x-bar and range charts

for size 6, the factor for control limits for range D₄ = 2.004

so we substitute  

[tex]UCL_R[/tex] = 2.004 × 0.6  

[tex]UCL_R[/tex] = 1.2024 ≈ 1.2  

Hence, Option a. 1.2 is the correct answer.

Answer:

144.5

Step-by-step explanation:

Area of a triangle = one half of the base length times the height

The given base length is 17 cm and the given height is 17 cm

Hence, area = [tex]\frac{17*17}{2}[/tex]

17 * 17 = 289

289 / 2 = 144.5

Area = 144.5cm²

Answer: 144.5

Step-by-step explanation:

The answer is correct because, the formula of a triangle is base times height divided by 2. Since the base and height is 17, we multiply 17 times 17. The answer for 17 times is: 289. Now we have to divide it by two. 289 divided by 2 equals: 144.5.

Hope This Helps!

Answer:

take 40 degree as reference angle

using tan rule

tan 40 =p/b

0.83=900/x

0.83x=900

x=900/0.83

x=1084.33

x=1084.3(after rounding off to the nearest tenth)

Step-by-step explanation:

Answer:

Mercantilism allowed for government regulation of trade, which interfered with natural market forces.

Answer:

416

Step-by-step explanation:

since this is a trapezoid, you would calculate the area by the formula

(a+b )h/2 where h is the height and a and b are the 2 bases

When you plug the values in you get the answer as 416

Hope this Helps!

9514 1404 393

Answer:

  3

Step-by-step explanation:

From a given vertex, two of the vertices are adjacent, so a "diagonal" to those will not form a triangle. The number of diagonals that can be drawn is 3 fewer than the number of sides. The number of triangles is 1 more than the number of diagonals.

For a 5-sided figure, 2 diagonals can be drawn from a common vertex.

  3 triangles will be formed.

Answer:

15

Step-by-step explanation:

Answer:

406

Step-by-step explanation:

hii :)

so to find the area we're going to find the area of the shapes and add them.

both 14 by 7 faces: 98*2=196

both 5 by 14 faces: 70*2=140

both little squares: they are 7 by 5 because the first shape would fold over so they would be equal. 35*2=70

adding them together: 196+140+70=406

hope this helped!