A buoy, floating in a ripple tank, is at rest when a wave reaches it. The wave has a frequency of 1.25 Hz, and an amplitude of 0.75 m. What is the magnitude of the buoy’s displacement after 2.20 seconds?

Answer:

It's A.

Explanation:

DNA is a double helix.

Model which accurately displays structure of DNA is model A as DNA is a double helical structure.

DNA  is a hereditary material which is present in human beings as well as all other living organisms.  Every cell which is present in an organism's body has DNA  which is the same. Most of the DNA is situated in the cell's nucleus  and small amount of it can be found in the cell's mitochondria as well.

Information which is stored in DNA is stored as codes made up of four chemical bases namely, adenine, thymine , cytosine and guanine.Human DNA consists of 3 billion bases .The order of the bases determines information which is required for building and maintaining an organism.

DNA bases are capable of pairing up with each other. Adenine pairs with thymine and guanine pairs up with cytosine .Each base is also attached to a sugar molecule  and a phosphate group. A base, phosphate  sugar are together called as nucleotides.

Learn more about DNA,here:

https://brainly.com/question/13552018

#SPJ2

Answer:

a)  v = 7.69 10³ m / s,  b)    T = 92.6 min

Explanation:

a) For this exercise we use the centripetal acceleration ratio, which in itself assumes a circular orbit, is equal to the acceleration of gravity

          a = v² / r

          v = [tex]\sqrt{a r}[/tex]

the distance to the ISS is

           r = R_earth + d

           r = 6400 10³ + 400 10³

           r = 6800 10³ m

we calculate

           v = [tex]\sqrt{8.69 \ 6800 \ 10^3}[/tex]Ra (8.69 6800 103)

           v = [tex]\sqrt{59.09 \ 10^6}[/tex]

           v = 7.687 10³ m / s

the result with the correct significant figures

            v = 7.69 10³ m / s

b) The speed of the ISS is constant, so we can use the uniform motion relationships

            v = d / t

if distance is the orbit distance

            d = 2π r

time is called period

            v = 2π r / T

            T = 2π r / v

let's calculate

            T = 2π 6800 10³ /7,687 10³

            T = 5.558 10³ s

let's reduce the period to minutes

            T = 5.558 10³ s (1 min / 60s)

            T = 9.26 10¹ min

            T = 92.6 min

Answer:

B

Explanation:

F= m×a

450N = 1.5kg × a

450/1.5 = a

a=300m/s²

IM NOT SURE THO

Answer:

Mechanical advantage = 4

Explanation:

Given the following data;

Distance of effort, de = 8m

Distance of ramp, dr = 2m

To find the mechanical advantage;

Mechanical advantage = de/dr

Substituting into the equation, we have;

Mechanical advantage = 8/2

Mechanical advantage = 4

This question is incomplete, the complete question is;

Determine the maximum volume in gallons​ [gal] of olive oil that can be stored in a closed cylindrical silo with a diameter of 3feet​ [ft] so the total pressure at the bottom of the container will not exceed 26 ​pound-force per square inch​ [psi]. Assume the height of the tank is sufficient to store the amount of olive oil​ required, and the surface pressure is 1 atmosphere​ [atm]. The specific gravity of olive oil is 0.86.

Answer:

A maximum of 1602.6 gallons of olive oil can be stored in the closed cylindrical silo

Explanation:

Given the data in the question;

Using SI units

Diameter = 3 ft = 3 × 0.3048 = 0.9144 m

pressure at bottom Pb = 26 psi = 26 × 6.89476 × 1000 = 179263.76 pascal

surface pressure Ps = 1 atm = 1 × 101325 = 101325 pascal

specific gravity = 0.86

we know that; density of water = 1000 kg/m³

so, density of oil P = density of water × specific gravity

= 1000 × 0.86 = 860 kg/m³

pressure at depth can be related to pressure at surface;

Pb = Ps + Pgh

acc. due gravity g = 9.81 m/s²

we substitute

179263.76 = 101325 + ( 860 × 9.81 × h)

8436.6h = 179263.76 - 101325

8436.6h = 77938.76

h = 77938.76 / 8436.6

h = 9.238 m

Now;

Volume of the cylinder = π/4 × D² × h

we substitute

Volume of the cylinder = π/4 × ( 0.9144 )² × 9.238  

Volume of the cylinder = 6.0665 m³

we know that; 1 m³ = 264.172 gal

so; Volume of the cylinder = 6.0665 × 264.172 gal

Volume of the cylinder = 1602.6 gallons

Therefore, A maximum of 1602.6 gallons of olive oil can be stored in the closed cylindrical silo

Answer:

F_total = -65.5 N

Explanation:

Coulomb's law is

           F = [tex]k \frac{q_1 q_2}{r^2}[/tex]k q1q2 / r2

In this exercise the force on the charge q3 is asked, for this we use that the force is a vector

          F_total = F₁₃ + F₂₃

let's look for every force

          F₁₃ = [tex]k \frac{q_1 q_3}{r_{13}^2}[/tex]

it is indicated that charge 1 is equal to q₁ = -11.5 nC = -11.5 10⁻⁹ C, located at x₁ = -1.675 mm = -1.675 10⁻³ m and charge q₃ = 48.0 nC = 48.0 10⁻⁹ C located at x₃ this position is not written in the exercise, suppose the position x₃ = -0.5 mm = 0.5 10⁻³ m

the distance is

          r₁₃ = [tex]\sqrt{(x_3 - x_1 )^2}[/tex]

          r₁₃ = [tex]\sqrt{(0.5-1.675)^2} \ 10^{-3}[/tex]

          r₁₃ = 1.175 10⁻³ m

we calculate

          F₁₃ = [tex]\frac{9 \ 10^{9} 11.5\ 10^{-9} 48.0\ 10^{-9} }{(1.175 10^{-3})^2 }[/tex]

          F₁₃ = 3.598 N

as the charge q₁ is negative and the charge q₃ is positive the force is attractive directed to the right

we look for F₂₃, where q₂ = 40 nC = 40.0 10⁻⁹ C located at x₂ = 0

             F₂₃ = [tex]k \frac{q_2q_3}{r_{23}^2}[/tex]

            r₂₃ = [tex]\sqrt{(x_3-x_2)^2}[/tex]

            r₂₃ = [tex]\sqrt{(0.5 -0)} \ 10^{-3}[/tex]RA (-0.5 0) 2 103

            r₂₃ = 0.5 10⁻³ m

             F₂₃ = [tex]\frac{9 \ 10^{9}\ 40\ 10^{-9} \ 48.0\ 10^{-9} x}{(0.5 \ 10^{-3})^2 }[/tex]

             F₂₃ = 6.912 10¹ N

             F₂₃ = 69.12 N

as the two charges are of the same sign, the force is repulsive, therefore it is directed to the left

the total force is

            F = total = 3.598 - 69.12

            F_total = -65.5 N

the negative sign indicates that the force is to the left

Answer:

uh finish the question please lol.

Answer:

Plane mirror.

Explanation:

Plane mirrors are a flat piece of glass coated with a metal alloy, which allows the glass to reflect a clear image, so the answer is plane mirror.

Answer:

  [tex]E_{y} (x,t)[/tex]= 10 cos (1.15 10⁻¹¹ x - 3.427 10¹⁵ t)

Explanation:

The general equation of a traveling wave on the x-axis is

        [tex]E_{y}(x,t)[/tex] = E₀ cos (kx -wt)

the amplitude of the wave is E₀ = 10 V / m

the wave number is

         k = 2π /λ

indicate the value of   λ = 550 nm = 550 10⁻⁹ m

we substitute

         k = 2π / 550 10⁻⁹

         k = 1.15 10⁻¹¹ m⁻¹

angular velocity is related to frequency

          w = 2πf

the speed of light is related to the wavelength and frequency

           c = λ f

           f = c /λ

we substitute

           w = [tex]2\pi \frac{c}\lambda }[/tex]

           w = 2π  3 10⁸/550 10⁻⁹

           w = 3.427 10¹⁵ rad / s

we substitute in the electric field equation

           [tex]E_{y} (x,t)[/tex]= 10 cos (1.15 10⁻¹¹ x - 3.427 10¹⁵ t)

Let's test the value of this wave for t = 0 at the point x = 0, the wave is worth

           Ey (0,0) = 10

which corresponds to its maximum positive value, therefore this is the expression of the traveling wave

Answer:

5 candela

Explanation:

Let the candle brightness be B

Let the distance be d

The candle brightness is inversely proportional to the distance

B α 1/d

B = k/d

If my candle has a brightness of 15 candela from a distance of 2 meter, then;

15 = k/2

k = 30

To get the brightness when the distance is 6m;

B = k/d

B = 30/6

B = 5 candela

Hence the brightness will be 5 candela

Answer:

266 m

Explanation:

Answer:

The Czochralski method, also Czochralski technique or Czochralski process, is a method of crystal growth used to obtain single crystals of semiconductors, metals, salts and synthetic gemstones

Explanation:

hope it helps:)

Answer:

agree with above answer

Answer:

[tex]625\ \text{cm}^2[/tex]

[tex]14.1\ \text{cm}[/tex]

Explanation:

[tex]F_1[/tex] = Force applied to master piston = 200 N

[tex]F_2[/tex] = Force applied to slave piston = 5000 N

[tex]A_1[/tex] = Area of master piston = [tex]25\ \text{cm}^2[/tex]

[tex]A_2[/tex] = Area of slave piston

r = Radius of slave piston

From Pascal's law we have

[tex]\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\\Rightarrow A_2=\dfrac{F_2}{F_1}A_1\\\Rightarrow A_2=\dfrac{5000}{200}\times 25\\\Rightarrow A_2=625\ \text{cm}^2[/tex]

The area of the slave piston is [tex]625\ \text{cm}^2[/tex]

Area of the slave piston is given by

[tex]A_2=\pi r^2\\\Rightarrow r=\sqrt{\dfrac{A_2}{\pi}}\\\Rightarrow r=\sqrt{\dfrac{625}{\pi}}\\\Rightarrow r=14.1\ \text{cm}[/tex]

The radius of the slave piston is [tex]14.1\ \text{cm}[/tex].

Answer:

the net charge carried by the particle is -2.35 × 10⁻⁷ C

Explanation:

Given that;

mass m = 1.41 × 10⁻⁶ kg

Magnitude E = 686 N/C

v = 5.93 m/s

A short time after being launched, the particle is 9.89 x 10-3 m below and 0.151 m east of its initial position

consider vertical;

u =0, y = 9.89 × 10⁻³ m, g = a = 9.8 m/s²

Now, from the second equation of motion;

s = ut + 1/2 × at²

so, y = ut + 1/2 × at²

we substitute

9.89 × 10⁻³ = 0×t + (1/2 × 9.8 × t²)

9.89 × 10⁻³ = 4.9t²

t² = 9.89 × 10⁻³ / 4.9

t² = 0.0201836

t = √0.00201836

t = 0.0449 s

Consider horizontal;

u = 5.93 m/s, a = (qE/m) m/s, t = 0.0449 s, x = 0.151 m

also, from the second equation of motion;

s = ut + 1/2 × at²

so

x =  ut + 1/2 ×  (qE/m) × t²

we substitute

0.151 =  (5.93 × 0.0449) + (1/2 ×  ((q×686)/1.41 × 10⁻⁶) × (0.0449 )²

0.151 = 0.266257 +  0.69149143q / 1.41 × 10⁻⁶

0.151 - 0.266257 =  0.69149143q / 1.41 × 10⁻⁶

-0.115257 = 0.69149143q / 1.41 × 10⁻⁶

-0.115257 × 1.41 × 10⁻⁶ = 0.69149143q

0.69149143q = -1.6251237 × 10⁻⁷

q = -1.6251237 × 10⁻⁷ / 0.69149143

q = -2.35 × 10⁻⁷ C

Therefore, the net charge carried by the particle is -2.35 × 10⁻⁷ C

Answer:

Intterferance

Explanation:

I took the test

If there's nothing else connected to the battery except the 3-ohm resistor, then the question is defective and the correct answer is not on the list.

With 12v connected across the resistor, the current through the resistor is

I = (E/R) = (12/3) = 4 Amperes.

The power generated inside a resistor is

P = (E x I) = (12v) x (4 A) = 48 watts

Answer:

ΔQ = 4896 KJ

Heat Flux = 57407.55 W/m²

Cost = $ 0.176

Explanation:

The amount of heat dissipated in two hours can be given as:

[tex]Heat\ Dissipation = \Delta Q = Pt\eta[/tex]

where,

P = Power of Iron = 800 W

t = time taken = 2 hrs

η = Conversion efficiency = 85% = 0.85

[tex]\Delta Q = (800\ W)(7200\ s)(0.85)\\\\[/tex]

ΔQ = 4896 KJ

Now, for heat flux:

[tex]Heat\ Flux = \frac{P}{Surface\ Area}\\\\Heat\ Flux = \frac{800\ W}{0.15\ ft^{2}}\frac{1\ ft^{2}}{0.092903\ m^{2}}[/tex]

Heat Flux = 57407.55 W/m²

Now, for total heat energy in KWhr in two hours:

[tex]Heat\ Energy = (Power)(Time)\\\\Heat\ Energy = (0.8\ KW)(2\ hr)\\\\Heat\ Energy = 1.6\ KWh[/tex]

Now, for the cost:

[tex]Cost = (Heat\ Energy)(Unit\ Cost)\\Cost = (1.6\ KWh)(\$ 0.11\ /KWh)[/tex]

Cost = $ 0.176

Answer:

go to settings and find what your looking for

Explanation:

Answer:

Explanation:

Force between charge is given by the following expression

F = k Q₁ Q₂ / R² , k = 9 x 10⁹ , Q₁ and Q₂ are charges , R is distance between charges .

Putting the given values ,

.85  = 9 x 10⁹ x 7.1 x 10⁻⁶ x Q₂ / 5.4²

Q₂ = .85 x  5.4² / (9 x 10⁹ x 7.1 x 10⁻⁶ )

= .38788  x 10⁻³ C .

= 387.88 x 10⁻⁶ C .

Answer:

2 m/s²

Explanation:

Given,

Mass of the block = 10 Kg

Acceleration = 2.5 m/s²

Let the smaller force = F

Bigger force = 4 F

Now,

F + 4F = m a

5F = 10 x 2.5

F = 5 N

If smaller mass is removed acceleration = ?

4F = m a

4 x 5 = 10 x a

[tex]a=\frac{20}{10}[/tex]

a = 2 m/s²

Acceleration of the mass is equal to 2 m/s².

Answer:

F = 36 N

Explanation:

Given that,

Charge, q₁ = +8 μC

Charge, q₂ = -5 μC

The distance between the charges, r = 10 cm = 0.1 m

We need to find the magnitude of the electrostatic force. The formula for the electrostatic force is given by :

[tex]F=\dfrac{kq_1q_2}{r^2}\\\\F=\dfrac{9\times 10^9\times8\times 10^{-6}\times 5\times 10^{-6}}{(0.1)^2}\\F=36\ N[/tex]

So, the magnitude of the electrostatic force is 36 N.

Answer:

Explanation:

Given that:

At the inlet:

Temperature [tex]T_1 = 25^0 \ C[/tex]

Pressure [tex]P_1[/tex] = 20bar = 2000 kPa

At the outlet:

[tex]P_2 = 2000 \ kPa[/tex]

a)

Q = 500 kJ/kg

Using the steam tables to determine the properties of water;

[tex]h_1 = 106.6863 \ kJ/kg \\ \\ h_2 -h_1 = 500 \\ \\ h_2 = (500 + 106.6863) \ kJ/kg \\ \\ h_2 = 606.68 \ kJ/kg[/tex]

[tex]at \ p_{sat}= 2000 \ kPa; \ h_f = 908.47 \kJ/kg; \ h_g = 2798.3 \ kJ/kg} \\ \\ h_2< h_f; \text{thus, the soil is compressed or subcooled liquid}[/tex]

b)

[tex]Q = 1500 \ kJ/kg\\ \\ Q= (h_2-h_1) \\ \\ h_2 = 1500 + 106.6863 \\ \\ h_2 = 1606.6863 \ kJ/kg \\ \\ h_f < h_2<hg \ at \ 2000 \ kPa[/tex]

Thus, the outlet steam will be a vapor-liquid mixture at 212.38° C

c)

[tex]Q = 3000 \ kJ/kg \\ \\ Q = h_2 -h_1 \\ \\ h_2 = Q + h_1 \\ \\ h_2 = 3000 + 106.6863 \\ \\ h_2 = 3106.6863 \ kJ/kg\\ \\ h_2 > hg \ at \ 2000 \ kPa[/tex]

Thus, the outlet steam will be a superheated vapor at 380° C

Answer:

180 turns

Explanation:

Given data

Vi= 240 volts

Vo= 960volts

Ns= 720 turns

Required

The amount of Primary turns Np

The expression relating voltage and turns in a transformer is given as

Np/Ns= Vi/Vo

substitute

Np/720= 240/960

cross multiply

720*240= Np*960

172800= Np*960

Np= 172800/960

Np= 180

Hence the primary turns is 180 turns

Answer:

false this is correct answer of this question

Answer:

what's the question? I don't understand

Answer:

Limestone can from form shell fragments of sea creatures

Explanation:

Answer:

mucilage can detect objects the size of millimeters, whereas humans can only detect objects larger than centimeters

Explanation:

The human ear can detect sound in the range of 20 to 20000hz, we are asked to find the mid-range wavelength of the ear at f = 10000 Hz

let's use the relationship between wave speed, wavelength and frequency

           v = λ f

           λ= v / f

           λ = 343/10000

           λ = 3.43 10⁻² m

the sound range of a bat is between 25 10³ Hz and 100 10³ Hz, they also ask for the wavelength in the middle range

          f = (100 10³ + 25 10³) / 2

          f = 62.5 10³ Hz

          λ = 343 / 62.5 10³

          λ = 5.5 10⁻³ m

Therefore the size of the object that a bat can detect is much smaller than the size that a human can detect, therefore the bat is capable of detecting insects, but humans.

The mucilage can detect objects the size of millimeters, whereas humans can only detect objects larger than centimeters

Explanation:

option A is the correct answer of this question .

plz mark my answer as brainlist if you find it useful.☺️