A bird flies 3.7 meters in 46 seconds, what is its speed?

Meter #2 is more precise.

There's no information here that tells us which meter is more accurate.

Answer:

8.6602 tons

Explanation:

We first draw the known vector forces.

2fcos30⁰

We have f to be equal to 5tons

Inserting into formula

Σfx = 2(5)cos30⁰

= 8.6602 tons

Σfy is equal to 0, this is because in the y direction, the forces cancel themselves out.

Therefore the resultant force on the ship is equal to 8.6602 tons

I hope this helps!

Please check attachment for diagram.

Answer:

Force is the push or pull exerted on an object to make it move.

Without force , an object will remain in it's position

Newton's first law of motion proves this. And it states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force.

Explanation:

Newton's second law of motion describes how force is related to mass and acceleration, and this relationship is used to calculate force. In general, the greater the mass of the object, the greater the force needed to move that object.

Answer:

Please add the multiple choice awensers too then I'll get back to you when I can

Answer:

Answer is D

Explanation:

Explanation:

distance = rate*time

time = distance divided by rate

now just substitute

time = distance (60 m) divided by rate (34.8 m/sec)

Answer:

Change in Q = 2.1x 10^-3 C

Explanation:

We are given that

The Initialcapacitance C1 = 6.0μF

Initial charge oncapacitor

Q1 = C1 V

= 6.00 x 10^-6 x 100

= 6.00 x 10^-4 C

So the Final capacitance C2 will be

= K x C1 = 4.5 x 6.00 x 10^-6

= 2.7 x 10^ -5 F

So to get Finalcharge

We use Q2 = C2 x V

= 2.7 x 10^ - 5 x 100

= 27 x 10^ -4 C

So Charge flown in thecapacitor is change in Q

Which is = Q2 - Q1

= 27 x 10^-4 - 6.0 x 10^ -4

Change in Q = 2.1x 10^-3 C

Answer:

The value is [tex]d = 31.45 \ m [/tex]

Explanation:

Generally the relative speed at which you are moving with respect to the person ahead of you is mathematically represented as

[tex]v_r = v_s - v_c[/tex]

substituting 1.05 m/s for [tex] v_c [/tex] and 2.75 m/s for [tex]v_s[/tex]

So

[tex]v_r = 2.75 - 1.05[/tex]

=> [tex]v_r = 1.7 \ m/s [/tex]

Generally the distance by which the person is ahead of you is mathematically represented as

[tex]d = v_r * t[/tex]

substituting 18.5 s for [tex] t [/tex]

       [tex]d =  1.7  * 18.5[/tex]

=>      [tex]d  =  31.45 \  m [/tex]

The direction of movement of the body or item is defined by velocity. Your total displacement will be 684 meters.

The direction of movement of the body or item is defined by velocity. Speed is fundamentally a scalar number. Velocity is, in essence, a vector quantity. It is the pace at which distance changes. It is the displacement rate of change.

Given that It takes you 9.5 min to walk with an average velocity of 1.2 m/s to the north from the bus stop to the museum entrance.

Time = 9.5 minutes = 9.5 × 60 seconds = 570 seconds

Average Velocity = 1.2 m/s

Now, the displacement made by you can be written as,

Velocity = Displacement / Time

1.2 m/sec = Displacement / 570 seconds

Displacement = 1.2 m/sec × 570 seconds

Displacement = 684 meter

Hence, your total displacement will be 684 meters.

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Answer:

The flag will appear to be black.

Explanation:

This is because red is the only brighter color in the American flag, so when a blue light is shined, the red turns dark and then the flag looks just blank and black.

Answer:

As red light falls on a blue surface, it absorbs the red light and no light will be reflected back. Thus, the object appears to be black. When the flag is illuminated by red light, the red and white stripes of the flag will appear solid red, the stars will appear red, and the blue portion will appear black.

Answer:

The area is [tex]A = 0.015 \ m^2 [/tex]

The resistance is  [tex]R =  1.0 *10^{5} \ \Omega [/tex]

Explanation:

From the question we are told that

The relativity of dry skin is [tex]\rho = 1 * 10^6\ \Omega\cdot m[/tex]

The thickness of the skin is [tex]d = 1.5 \ mm = 1.5 *10^{-3} \ m[/tex]

Generally the area of a flat palm with length = 0.10 m and breath b = 0.15 m is mathematically represented as

[tex]A = d * L[/tex]

[tex]A = 0.10 * 0.15 [/tex]

[tex]A = 0.015 \ m^2 [/tex]

Generally the resistance is mathematically represented as

[tex]R = \frac{\rho * d}{ A }[/tex]

=>    [tex]R =  \frac{ 1.0 *10^{6} *   1.5*10^{-3}}{ 0.015  }[/tex]

=> [tex]R = 1.0 *10^{5} \ \Omega [/tex]

Answer:

A)   θ = 13.1º  , B)  E

Explanation:

A) For this exercise, let's use Newton's second law, let's set a reference frame where the axis ax is in the radial direction and is horizontal, the axis y is vertical.

In this reference system the only force that we must decompose is the Normal one, let's use trigonometry

        sin θ = Nₓ / N

        cos θ = [tex]N_{y}[/tex] / N

        Nₓ = N sin θ

       Ny = N cos θ

x-axis (radial)

        Nₓ = m a

where the acceleration is centripetal

         a = v² / R

we substitute

        -N sin θ = -m v² / R                   (1)

the negative sign indicates that the force and acceleration towards the center of the circle

y-axis (Vertical)

          Ny - W = 0

           N cos θ = mg

           N = mg / cos θ

we substitute in 1

          mg / cos θ  sin θ = m v² / R

          g tan θ = v² / R

          θ = tan⁻¹ (v² / gR)

we calculate

        θ = tan⁻¹ (25² / 9.8 274)

        θ = 13.1º

B) when comparing the equations the correct one is E

Answer:

80

Explanation:

because of the denstiy formula

Answer:

c

Explanation:

Answer:

the answer is c i just did it

Explanation:

Answer:

2 seconds

Explanation:

The time taken for the movement is 2.81 seconds.

To find the time, the given values are,

Distance = 45 meters

speed = 16 m/s.

Formula of distance,

              Distance = Speed × Time.

As we have to find the time, Formula can be rearranged as,

              Time = Distance / Speed

Substituting the given datas in the formula,

Time = 45 / 16

        = 2.81 seconds.

So, the time taken for the movement is 2.81 seconds.

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Responder:

Explicación:

Usaremos la ecuación de movimiento para determinar la altura de la bola medida desde la parte superior del edificio.

Usando la ecuación para obtener la altura de caída

S = ut + 1 / 2gt²

u es la velocidad inicial = 25 m / s

g es la aceleración debida a la gravedad = 9,81 m / s²

t es el tiempo = 7 segundos

S es la altura de la caída

S = 25 (7) +1/2 (9,81) × 7²

S = 175 + 4,905 (49)

S = 175 + 240,345

S = 415,35 m

Esto significa que la pelota se elevó a 415,35 m de altura

La altura vertical máxima alcanzada es de 31,88 m.

Tenemos la siguiente información de la pregunta;

Velocidad inicial = 25 m/s

Velocidad final = 0 m/s (a la altura máxima)

tiempo empleado = 3,5 minutos (el tiempo empleado para subir y bajar es igual).

Usando la ecuación;

v^2 = u^2 - 2gh

Dado que v = 0

u^2 = 2gh

h = tu^2/2g

h = (25)^2/2 *9.8

h = 31,88 m

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Answer:

The range of initial speeds allowed to make the basket is: [tex]9.954\,\frac{m}{s}\leq v \leq 10.185\,\frac{m}{s}[/tex].

Explanation:

We must notice that basketball depicts a parabolic motion, which consists of combining a constant speed motion in x-direction and free fall motion in the y-direction. The motion is described by the following kinematic formulas:

x-Direction

[tex]x = x_{o} + v_{o}\cdot t \cdot \cos \alpha[/tex]

y-Direction

[tex]y = y_{o} + v_{o}\cdot t\cdot \sin \alpha +\frac{1}{2}\cdot g\cdot t^{2}[/tex]

Where:

[tex]x_{o}[/tex], [tex]y_{o}[/tex] - Initial position of the basketball, measured in meters.

[tex]x[/tex], [tex]y[/tex] - Final position of the basketball, measured in meters.

[tex]v_{o}[/tex] - Initial speed of the basketball, measured in meters per second.

[tex]t[/tex] - Time, measured in seconds.

[tex]\alpha[/tex] - Tilt angle, measured in sexagesimal degrees.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

If we know that [tex]x_{o} = 0\,m[/tex], [tex]y_{o} = 2.20\,m[/tex], [tex]\alpha = 36^{\circ}[/tex], [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], [tex]x = (9.10\pm0.23)\,m[/tex] and [tex]y = 2.70\,m[/tex], the system of equation is reduce to this:

[tex](9.10\pm 0.23)\,m = 0\,m + v_{o}\cdot t \cdot \cos 36^{\circ}[/tex]

[tex]9.10\pm 0.23 = 0.809\cdot v_{o}\cdot t[/tex] (Ec. 1)

[tex]2.70\,m = 2.20\,m + v_{o}\cdot t \cdot \sin 36^{\circ} + \frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right) \cdot t^{2}[/tex]

[tex]0.50 = 0.588\cdot v_{o}\cdot t-4.904\cdot t^{2}[/tex] (Ec. 2)

At first we clear [tex]v_{o}\cdot t[/tex] in (Ec. 1):

[tex]v_{o}\cdot t = \frac{9.10\pm 0.23}{0.809}[/tex]

[tex]v_{o}\cdot t = 11.248\pm 0.284[/tex]

(Ec. 1) in (Ec. 2):

[tex]0.5 = 0.588\cdot (11.248\pm 0.284)-4.904\cdot t^{2}[/tex]

Now we clear the time in the resulting expression:

[tex]4.904\cdot t^{2} = 0.588\cdot (11.248\pm 0.284)-0.5[/tex]

[tex]t = \sqrt{\frac{0.588\cdot (11.248\pm 0.284)-0.5}{4.904} }[/tex]

There are two solutions:

[tex]t_{1} = \sqrt{\frac{0.588\cdot (11.248- 0.284)-0.5}{4.904} }[/tex]

[tex]t_{1} \approx 1.101\,s[/tex]

[tex]t_{2} = \sqrt{\frac{0.588\cdot (11.248+ 0.284)-0.5}{4.904} }[/tex]

[tex]t_{2}\approx 1.131\,s[/tex]

The initial velocity is cleared within (Ec. 2):

[tex]v_{o}=\frac{0.50+4.904\cdot t^{2}}{0.588\cdot t}[/tex]

The bounds of the range of initial speed is determined hereafter:

[tex]t_{1} \approx 1.101\,s[/tex]

[tex]v_{o} = \frac{0.50+4.904\cdot (1.101)^{2}}{0.588\cdot (1.101)}[/tex]

[tex]v_{o} = 9.954\,\frac{m}{s}[/tex]

[tex]t_{2}\approx 1.131\,s[/tex]

[tex]v_{o} = \frac{0.50+4.904\cdot (1.131)^{2}}{0.588\cdot (1.131)}[/tex]

[tex]v_{o} = 10.185\,\frac{m}{s}[/tex]

The range of initial speeds allowed to make the basket is: [tex]9.954\,\frac{m}{s}\leq v \leq 10.185\,\frac{m}{s}[/tex].

Answer:

true

Explanation:

Because if u have seen many velocity videos or got taught it then u should know

Answer:

The average velocity is 0.15 m/s

Explanation:

Use the definition of average velocity as the distance traveled divided the time it took.

Since the movement was on the plane from the origin (0, 0) to the point (-30, 20) corresponding to 30 m west and 20 m north, we calculate the distance using the distance between two points on the plane:

[tex]distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} = \sqrt{(-30)^2+20^2} =\sqrt{1300} \approx 36.06\,\,m[/tex]

Then the magnitude of the average velocity can be estimated via the quotient between distance divided time, but since the units required are meters per second, we first convert the four minute time into seconds: 4 * 60 = 240 seconds.

Then the average velocity becomes:

[tex]v_{ave}=\frac{distance}{time} =\frac{36.06}{240} =0.15\,\,m/s[/tex]

Answer:

Heat, potential energy, and sound.

Explanation:

Edgenuity says so

The characteristics of the inelastic shocks allow to find the correct answers of in which the kinetic energy can be transformed are:

In a collision the total momentum of the system is conserved, this is an important principle of physics, we have two types of collisions:

In inelastic collision, part of the energy of the movement is transformed into potential energy of configuration of the system.

Let's analyze the different answers:

a) Heat.

True. Heat is a form of energy that, due to the change in the relative friction motion of bodies, is one of the greatest sources of transformation of energy into configuration power energy.

b) Impulse.

False. The impulse is the change of the momentum of the system and this is conserved, therefore the momentum is also conserved.

c) Momentum

False. Momentum is preserved in all crashes.

d) Potential energy.

True. Power energy is a configuration energy, therefore kinetic energy can be transformed into potential energy.

e) The sound.

True. Sound is a wave that carries energy, therefore kinetic energy can be transformed into traveling sound waves.

In conclusion, using the characteristics of inelastic shocks, we can find the correct answers that the kinetic energy can be transformed into are:

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Answer:

I know

Explanation:

Physics= hard

Answer:

181.87 N

Explanation:

Given that a  mountain climber lies flat on the surface of a glacier (assumed frictionless), which is inclined at 30 degrees to the horizontal. he remains stationary because he is holding on to a rope that is attached to a spoke in the ice further up the slope.

Since the he slope is parallel to the surface of the ice.

if the force of the ice on the climber is 210N, the tension T in the rope will be

T = 210 cos 30

T = 181.86 N

Therefore, the tension in the rope is 181.86 N

Answer:

F=200N

a=500m/s2​

Mass=?

Explanation:

F=ma

200=m*500

200/500=m

Mass=0.4kg

Answer:

10 miles per minute.

Answer:

The value is [tex]U = 0.06 \ J [/tex]

Explanation:

From the question we are told that

The value of charge on each three point charge is

[tex]q_1 = q_2 = q_3 =q= 1.05 \mu C = 1.05 *10^{-6} \ C[/tex]

The length of the sides of the equilateral triangle is [tex]r = 0.500 \ [/tex]

Generally the total potential energy is mathematically represented as

[tex]U = k * [ \frac{q_1 * q_2}{r} + \frac{q_2 * q_3}{r} + \frac{q_3 * q_1}{r} ][/tex]

=> [tex]U = k * 3 * \frac{q^2}{r} [/tex]

Here k is coulomb constant with value [tex]k = 9*10^{9}\ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.[/tex]

=>    [tex]U  = 9*10^9 * 3 * \frac{(1.05 *10^{-6})^2}{0.5 }  [/tex]

[tex]U  = 0.06 \  J  [/tex]

The statement "thermal energy can increase even if the average kinetic energy is constant" is definitely true.

Kinetic energy may be characterized as a type of energy that an object possesses due to its motion. It is defined as the work that is required to accelerate a body of a given mass from rest to its stated velocity. It measures the work an object can do by the virtue of its motion.

The thermal energy will still enhance even if the average kinetic energy remains constant. This is because it is based on the relationship between kinetic energy and thermal energy. Kinetic energy is defined as the energy possessed by an object or body as a result of its motion.

Therefore, the statement "thermal energy can increase even if the average kinetic energy is constant" is definitely true.

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Answer:

Newton's first law of motion is that an object at rest will stay at rest, unless acted upon by an external force.

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The "external force" can be anything, from a gust of wind, to a person moving the object. His first law also corresponds with the definition of inertia.

Hope this helps!

Answer: the only force acting upon your body is the force of gravity

Explanation: a non-contact force. ... The force of gravity is the only force acting upon your body. There are no external objects touching your body and exerting a force. As such, you would experience a weightless sensation.

Explanation:

When in free fall, the only force acting upon your body is the force of gravity - a non-contact force. Since the force of gravity cannot be felt without any other opposing forces, you would have no sensation of it. You would feel weightless when in a state of free fall

Answer:

water displacement.

the bigger the item means more water displacement meaning bouyance