a battery-operated car moves forward as a result of which device?

Answers

Answer 1

Answer:

the wheels

Explanation:

Answer 2

Answer:

depends..

Explanation:

it can be Electromagnet or generator or a motor


Related Questions

In electronic circuits it is not unusual to encounter currents in the microampere range. Assume a 36 μA current, due to the flow of electrons. Part A What is the average number of electrons per second that flow past a fixed reference cross section that is perpendicular to the direction of flow?

Answers

Answer:

n = 2.25 x 10¹⁴ electrons/s

Explanation:

The amount of electric current is defined as the electric charge passing through an area per unit time. Hence:

I = q/t

where,

I = Current

q = amount of charge

t = time interval

but,

q = ne

therefore,

I = ne/t

where,

n = no. of electrons

e = charge on single electron = 1.6 x 10⁻¹⁹ C

t = 1 s (for electrons passing per second)

I = Current = 36 μA = 3.6 x 10⁻⁵ A

Therefore,

3.6 x 10⁻⁵ A = n(1.6 x 10⁻¹⁹ C)/1 s

n = (3.6 x 10⁻⁵ A)/(1.6 x 10⁻¹⁹ C)

n = 2.25 x 10¹⁴ electrons/s

- Over the weekend you go for an urban hike, traveling 3 miles north then 4 miles west before stopping to take a break. If this hike takes 1 hour, what is your average velocity during that time? - You leave your house to go for a drive to clear your head, driving 10 miles over the course of 30 minutes before arriving back home. What is your average velocity?

Answers

Answer:

A.) 5 mph

B.) 20 mph

Explanation:

Given that you are traveling 3 miles north then 4 miles west before stopping to take a break. If this hike takes 1 hour,

Let's first calculate the displacement be using pythagorean theorem

D = sqrt ( 3^2 + 4^2 )

D = sqrt ( 9 + 16 )

D = sqrt ( 25 )

D = 5

Average velocity = displacement/time

Average velocity = 5/1

Average velocity = 5 mph

Therefore, your average velocity during that time is 5 mph

- You leave your house to go for a drive to clear your head, driving 10 miles over the course of 30 minutes before arriving back home. 

Average velocity = 10/ 0.5

Average velocity = 20 mph

Which of the following is the best thermal conductor?
A. Fiberglass.
B. Stainless.
C. Steel.
D. Wood.
E. Silver

Answers

Answer:

steel because being alloy in metal it has free electrons in metals

why is evidence good for practice

Answers

Answer:

HEYO BRO! (my bad for da caps)

Explanation:

Evidence-based practice (EBP) is the idea that occupational practices ought to be based on scientific evidence. That at first sight may seem to be obviously desirable, but the proposal has been controversial.

Happy to Help From, Adam

bc U know what ur doing...?

What were the physical activities in your childhood that you still do today? Do you spend more time now in doing these activities as compared before? ​

Answers

I used to play tag or run around a lot and sometimes i do these activities but its a lot less now that i am older

what would the answer be ?

Answers

Answer:

im going between 2 of them b and c but i would have choose b

A magnetic field is created by ____.
A moving electric charges
b elctromagnetic pulses
c a strong current
d a change in the current of a wire​

Answers

Answer: a magnetic field is created by moving electric charges

An oil pump is drawing 44kW while pumping oil with a density of 860 kg/m3 at a rate of 0.1 m3/s. The inlet and outlet diameters of the pipe are 8cm and 12cm, respectively. If the pressure increases by 500kPa going through the pump and the motoreffi ciency is 90%, determine the mechanical efficiency of the pump

Answers

Answer:

The mechanical efficiency of the pump is 91.8 %

Explanation:

Given;

input power, p = 44 kw

density of oil, ρ = 860 kg/m³

motor efficiency, η = 90 %

inlet diameter, d₁ = 8 cm

outlet diameter, d₂ = 12 cm

volume flow rate, V = 0.1 m³/s

pressure rise, P = 500kPa

output power  = motor efficiency x input power

output power  = 0.9 x 44 = 39.6 kW

Thus, the mechanical input power = 39.6 kW

The mechanical output power  is given by change in mechanical energy;

[tex]E = mgh + \frac{m}{2} (v_2^2 - v_1^2) \\\\E = \rho V g h + \frac{\rho V}{2} [(\frac{V_2}{\pi r_2^2} )^2 - (\frac{V_1}{\pi r_1^2})^2]\\\\E = PV + \frac{\rho V^3}{2\pi^2} [\frac{1}{ r_2^4} - \frac{1}{ r_1^4}]\\\\E = (500 *10^3)(0.1) + \frac{(860)(0.1)^3}{2\pi^2} [\frac{1}{ 0.06^4} - \frac{1}{ 0.04^4}]\\\\E = 50000 -13653.51\\\\E = 36346.48 \ W\\\\E = 36.347 \ kW[/tex]

The mechanical efficiency is given by

η = mechanical output power /  mechanical input power

η = 36.347 / 39.6

η = 0.918

η = 91.8 %

Therefore, the mechanical efficiency of the pump is 91.8 %

3) An explorer walks 13 km due east, then 18 km north, and finally 3 km west.
a) What is the total distance walked?
b) What is the resulting displacement of the explorer from the starting point?

Answers

Answer: 34 km, 21 km  61 degrees north of east

Explanation: distance = 13 + 3 + 18 = 34

   displacement = 13 - 3 = 10

               10^2 + 18^2 = 424

              find the square root of 424 ( 20.5 rounded to 21 )

   

The total distance walked is 34 km and the resulting displacement is 20.6 km.

a) The total distance is gotten by summing up all the distance.

Total distance = Distance moved east + distance moved north + distance moved west

Total distance = 13 km + 18 km + 3 km = 34 km

b) The displacement is the distance from the beginning point to end point.

Displacement² = 18² + (13 - 3)² = 18² + 10²

Displacement² = 424

Displacement = 20.6 km

Therefore the total distance walked is 34 km and the resulting displacement is 20.6 km.

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A sprinter practicing for the 200-m dash accelerates uniformly from rest at A and reaches a top speed of 41 km/h at the 61-m mark. He then maintains this speed for the next 83 meters before uniformly slowing to a final speed of 34 km/h at the finish line. Determine the maximum horizontal acceleration which the sprinter experiences during the run. Where does this maximum acceleration value occur

Answers

Answer:

2.13 m/s^2.

Find the remaining answer in the explanation

Explanation:

Given that a sprinter practicing for the 200-m dash accelerates uniformly from rest at A and reaches a top speed of 41 km/h at the 61-m mark. He then maintains this speed for the next 83 meters before uniformly slowing to a final speed of 34 km/h at the finish line.

1.) The maximum horizontal acceleration will be when she attained her maximum speed. That is,

Speed = 41 km/h

Convert km/h to m/s

(41×1000) / 3600

Speed = 11.39 m/s

Using speed formula to calculate time

Speed = distance/time

11.39 = 61/t

t = 61/11.39

t = 5.36s

Where the distance = 61 m

Maximum acceleration = velocity /time

Maximum acceleration = 11.39/5.36

Maximum acceleration = 2.13 m/s^2

The maximum acceleration value occurs when the sprinter is starting from rest and attaining the maximum speed.

Using the equation for for Newton's Second law, m=F/a solve the following problem. You have been given an object with a force of 10N and an acceleration of 2 m/s2, what is the mass?
Group of answer choices

1. 8g

2. 3g

3. 20g

4. 5g

Answers

Answer:

4. 5g

Explanation:

F=ma so, m=Fa. All you have to do is 10/2. Don't be confused by the units. Mass will normally be in grams.

how many legs a cow has​

Answers

the cow has 4 legs :)

2. The components of vector A are given as follows:
Ax = 5.6 Ay = -4.7
What is the angle between vector A and positive direction of x-axis?​

Answers

Answer:

50 degree.

Explanation:

Given that the components of vector A are given as follows: Ax = 5.6 Ay = -4.7

The angle between vector A and B in the positive direction of x-axis will be achieved by using the formula:

Tan Ø = Ay/Ax

Substitute Ay and Ax into the formula above.

Tan Ø = -4.7 / 5.6

Tan Ø = -0.839

Ø = tan^-1(-0. 839)

Ø = - 40 degree

Therefore, the angle between vector A and B positive direction of x-axis will be

90 - 40 = 50 degree.

sam exerts a force of 65 N on a lawn mower with a mass of 25 kg. which formula can be used to calculate the acceleration of a lawn mower

Answers

Answer:

F = ma - with this you will get 2.6 m/s^2

Explanation:

Use this formula to get the acceleration...

where F is force, M is mass and A is acceleration

by using this we get...

65 = 25 * a

so, a = 65/25

Therefore, the acceleration is 2.6 m/s^2

Hope that helped :)

The acceleration of a lawn mower will be 2.6 m/s². It is the ratio of force and the mass.

What is acceleration?

The rate of change of velocity with respect to time is known as acceleration. According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.

The given data in the problem is;

The force act on a lawn mower,[tex]\rm F = 65 \ N[/tex]

Mass of  lawn mower,[tex]\rm m = 25 kg[/tex]

The acceleration of a lawn mower is,[tex]\rm a = ?[/tex]

Acceleration, is found as the ratio of force and the mass.

[tex]\rm F= ma \\\\ a = \frac{F}{m} \\\\ a= \frac{65}{25} \\\\ a = 2.6 \ m/s^2[/tex]

Hence, the acceleration of a lawn mower will be 2.6 m/s².

To learn more about acceleration, refer to the link;

https://brainly.com/question/2437624

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An unstrained horizontal spring has a length of 0.34 m and a spring constant of 180 N/m. Two small charged objects are attached to this spring, one at each end. The charges on the objects have equal magnitudes. Because of these charges, the spring stretches by 0.024 m relative to its unstrained length. Determine (a) the possible algebraic signs and (b) the magnitude of the charges. g

Answers

Answer:

a

         [tex]q_1 = -1.389 *10^{-5} \  C [/tex]   , [tex]q_2 = -1.389 *10^{-5} \  C [/tex]

OR

           [tex]q_1 = 1.389 *10^{-5} \  C [/tex]   , [tex]q_2 = 1.389 *10^{-5} \  C [/tex]    

b

[tex]q_1 = 1.389 *10^{-5} \ C [/tex] and [tex]q_2 = 1.389 *10^{-5} \ C [/tex]

Explanation:

Generally the force exerted on the string is mathematically represented as

[tex]F = k * e[/tex]

substituting values 180 N/m for k and 0.024 m for e

[tex]F = 180 * 0.024[/tex]

[tex]F = 4.32 \ N[/tex]

This force can also equivalent to the electrostatic force between the charges i.e

[tex]F = k * \frac{q^2}{ r^2}[/tex]

substituting [tex]9*10^{9}\ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.[/tex] for k and ( 0.34 + 0.024 = 0.364 m) for r we have

[tex] 4.32= 9*10^{9} * \frac{q^2}{ (0.364)^2}[/tex]

[tex]q = \sqrt{1.929 *10^{-10}}[/tex]

[tex]q = 1.389 *10^{-5} \ C [/tex]

Given the spring was stretched it means that the force between the charges is a repulsive for which tell us that both charge are of the same sign thus the possible  algebraic signs  of the charges are

         [tex]q_1 = -1.389 *10^{-5} \  C [/tex]   , [tex]q_2 = -1.389 *10^{-5} \  C [/tex]

OR

[tex]q_1 = 1.389 *10^{-5} \ C [/tex] , [tex]q_2 = 1.389 *10^{-5} \ C [/tex]

A column of soldiers, marching at 100 steps per minute, keep in step with the beat of a drummer at the head of the column. It is observed that the soldiers in the rear end of the column are striding forward with the left foot when the drummer is advancing with the right. What is the approximate length of the column? (Take the speed of sound to be 343 m/s.)

Answers

Answer:

The value is [tex]D = 205.8 \ m [/tex]

Explanation:

The time taken for the column to take a step mathematically represented as

100 steps => 1 minutes => 60 seconds

1 step => t

=> [tex]t = 0.6 \ s [/tex]

Generally the length of the column is mathematically represented as

[tex]D = v * t[/tex]

substituting 343 m/s for v we have

        [tex]D =  343 * 0.6 [/tex]

  =>    [tex]D =  205.8 \  m  [/tex]

A small block with mass 0.200 kg is released from rest at the top of a frictionless incline. The block travels a distance 0.394 m down the incline in 2.00 s. The 0.200 kg block is replaced by a 0.400 kg block. If the 0.400 kg block is released from rest at the top of the incline, how far down the incline does it travel in 2.00 s

Answers

Answer:

The distance traveled by the second block is 0.197 m

Explanation:

Given;

mass of the small block, m₁ = 0.2 kg

distance traveled by the block, d₁ =0.394 m

time of travel, t = 2 s

mass of the second block, m₂ = 0.4 kg

distance traveled by the second block, d₂ = ?

The work done per unit time on the inclined plane is given by;

[tex]\frac{f_1d_1}{t} = \frac{f_1d_1}{t}\\\\f_1d_1 = f_2d_2\\\\m_1gd_1 = m_2gd_2\\\\m_1d_1 = m_2d_2\\\\d_2 = \frac{m_1d_1}{m_2} \\\\d_2 = \frac{0.2*0.394}{0.4}\\\\d_2 = 0.197 \ m[/tex]

Therefore, the distance traveled by the second block is 0.197 m

A fisherman’s boat moves up and down periodically due to water waves. The boat travels from its highest to its lowest point, a vertical distance of 0.60 m, in 2.0 s. The horizontal distance between wave crests is 7.0 m. (a) What is the period of the wave motion? (b) What is the frequency of the wave motion? (c) W

Answers

Complete question is;

A fisherman’s boat moves up and down periodically due to water waves. The boat travels from its highest to its lowest point, a vertical distance of 0.60 m, in 2.0 s. The horizontal distance between wave crests is 7.0 m. (a) What is the period of the wave motion? (b) What is the frequency of the wave motion? (c) What is the amplitude of each wave

Answer:

A) Period = 4 s

B) Frequency = 0.25 Hz

C) Amplitude = 0.3 m

Explanation:

A) We are told that the distance it takes for the boat to travel from its highest to its lowest point is 2 s.

Thus, t = 2 s

Now, in waves, period (T) it the time between two successive waves.

This means that;

T = 2t

T = 2 × 2

T = 4 s

B) Also, the frequency(f) is given by the formula;

f = 1/T

f = 1/4

f = 0.25 Hz

C) We are given a vertical distance of 0.60 m from highest to lowest point of waves.

Now, amplitude is half of this distance.

Thus;

Amplitude(A) = 0.6/2

A = 0.3 m

What the differences between static and kinetic friction?

Answers

Answer:

Static friction prevents a stationary object from moving while kinetic or dynamic friction slows down a moving object.

Explanation:

Static Friction is the maximum force that must be overcome before a stationary object begins to  move, while kinetic or dynamic friction is the maximum force that must be overcome for an object in motion to continue moving at a uniform velocity.

Static friction keeps a stationary object at rest, once the Force of Static friction is overcome, the Force of Kinetic friction is what slows down the moving object.

What does this picture show?
A. Good accuracy, poor precision
B. Poor accuracy, good precision
C. Good accuracy, good precision
D. Poor accuracy, poor precision

Answers

B is the answer poor accuracy, good precision

Hitting a ball off a tee would be considered which of the following?

A.

A closed serial skill

B.

An open continuous skill

C.

An open discrete skill

D.

A closed discrete skill

Answers

I think the answer would be B

The rain gauge has 2 inches of precipitation.
Qualitative or Quantitative

Answers

Answer:

Quantitative is the correct term

this is quantitative.

quantitative values are ones that can be obtained by measuring something (like using a measuring cup to get 250mL of milk).
qualitative values are one that can be observed (the candle was yellow).

hope this helps :)

A pendulum built from a steel sphere with radius r cm 5 and density stl kg m S 3 7800 is attached to an aluminum bar with length l m 1 thickness t cm 0 8. and width w cm 4 and density . al kg m S 3 2820 a. Calculate the mass moment of inertia of the pendulum about its center of mass, . cm I b. Calculate the mass moment of inertia of the pendulum about its pivot point, o I .

Answers

Answer:

a)  I = 0.0198 kg m² ,  b)    I = 21.85 kg m²

Explanation:

For this exercise we will use the definition of moment of inertia

        I = ∫ r² dm

For body with high symmetry they are tabulated

sphere  I = 2/5 m r²

bar with respect to  center of mass I = 1/12 m L²

let's calculate the mass of each body

bar

        ρ = m / V

        m = ρ V

        m = ρ l w h

where we are given the density of the bar rho = 32840 kg / m³ and its dimensions 1 m, 0.8 cm and 4 cm

        m = 32820 1 0.008 0.04

        m = 10.5 kg

Sphere

       M = ρ V

       V = 4/3 pi r³

       M = rgo 4/3 π r³

give us the density 37800 kg / m³ and the radius of 5 cm

       M = 37800 4/3 π 0.05³

       M = 19.8 kg

a) asks us for the moment of inertia of the sphere with respect to its center of mass

        I = 2/5 M r²

        I = 2/5 19.8 0.05²

        I = 0.0198 kg m²

b) the moment of inertia with respect to the turning point, for this we will use the theorem of parallel axes

        I = I_cm + M d2

where d is the distance from the body to the point of interest

        I_cm = 0.0198 kg m²

the distance to the pivot point is

        l = length of the bar + radius of the sphere

        l = 1 + 0.05 = 1.005 m

        I = 0.0198 + 19.8 1.05²

        I = 21.85 kg m²

A car starts at 80 m/s but sees a cop and hits the brakes slowing down to 50 m/s in 2 sec.

Answers

Answer:

-15m/s/s

Explanation:

Acceleration = change in speed/ change in time

The change in speed is calculated by subtracting the initial speed from the final speed, so the change in speed is: 50 - 80 = -30m/s. The change in time is 2 - 0 = 2.

So the car acceleration is -30/2 = -15m/s/s

It is negative because it is decelerating.

Hope this helped!

what does Aristotle say about the good life?Does it still stand contemporary world?

Answers

Answer:

Explanation:

Aristotle was a philosopher and a scientist who believed good life for humans is ultimately about happiness and this happiness can be achieved by virtue or high moral standards.

In the contemporary world, generally, everyone's ultimate goal is still to be happy but achieving this feat by being virtuous or having a high moral standard is fading away in our contemporary world as people just want to be happy by any means possible. Some amass wealth illegally just to be happy while others do things that are considered immoral (by the society) to be happy hence people still want a good life but not a way described by Aristotle.

Aristotle stated that a good life is about happiness and this can only be achieved through high moral standards.

The statement that a good life is about happiness and this can only be achieved through high moral standards doesn't stand anymore in the contemporary world.

People now engage in immoral things as long as it brings them happiness. Even though the ultimate goal of people is to be happy, there are different ways that people go about in achieving this.

There are some people who get their wealth illegally just to ensure that they are happy. This source of happiness is gotten through vices.

In conclusion, Aristotle's statement about the good life is not applicable in the contemporary world anymore.

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Question: A) A car is driving too fast on a flat non-banked curve. The car cannot stay on the road. What path will the car take as it leaves the road? See Image. (a) (b) B) The driver wants to go faster around the same curve mentioned above and not run off the road. He adds sandbags to his car to make it weigh more so that the friction force between the tires and the road will be increased. Will this work? Explain your answer.​

Answers

Explanation:

(a) The car will leave tangentially to the road, so it will take path d.

(b) Sum of forces on the car in the vertical direction:

∑F = ma

N − mg = 0

N = mg

Sum of forces on the car in the centripetal direction:

∑F = ma

Nμ = m v²/r

mgμ = m v²/r

gμ = v²/r

v = √(grμ)

The maximum velocity is independent of mass, so adding sandbags will not work.

Calculate the length of segment RS with midpoint, M , if RM = 5x and MS = x + 12.

A. 3

B. 25

C. 30

D. 36

E. 15

Answers

Answer:

the full segment is:  30 units long

which coincides with answer C in your list

Explanation:

If M is the midpoint, then it divides the segment in two equal parts. Then, we can say that:

RM = MS (equality among the two parts of the divided segment)

replacing RM with "5 x" and MS with "x + 12", we get:

5 x = x + 12

solving for x:

5 x - x = 12

4 x = 12

then x = 3

With this info, we can calculate the length of each half of the segment and consequently its full length:

RM = 5 x = 5 (3) = 15

then the full segment is:  30 units long

What is the total electric charge of 2.5 kg of (a) electrons and (b) protons?

Answers

Answer:

a

 [tex]Q_e  =  -4.39 *10^{11}  \  C [/tex]

b

[tex]Q_p  =  + 2.395*10^{-8} \  C [/tex]

Explanation:

Generally the number of electron in the given mass is  mathematically evaluated as

        [tex]N_e =  \frac{2.5}{m_e }[/tex]

Here  m_e is the mass of electron with value [tex]m_e =  9.11 * 10^{-31} \  kg[/tex]

    =>  [tex]N_e =  \frac{2.5}{ 9.11 * 10^{-31} }[/tex]

       =>  [tex]N_e =2.74 *10^{30} \  electrons [/tex]

The total electric charge is mathematically represented as

       [tex]Q_e  =  N_e  *  e[/tex]

Here e is the charge on a single electron with value  [tex]e  =  1.60 *10^{-19}  \  C[/tex]

 So

          [tex]Q_e  =  -2.74 *10^{30}   *  1.60 *10^{-19} [/tex]

          [tex]Q_e  =  -4.39 *10^{11}  \  C [/tex]

The  negative sign is because we are considering electron

Generally the number of  protons in the given mass is  mathematically evaluated as

    [tex]N_p =  \frac{2.5}{m_p }[/tex]

Here  m_p is the mass of electron with value [tex]m_e =  1.67 * 10^{-27} \  kg[/tex]

    =>  [tex]N_p =  \frac{2.5}{ 1.67 * 10^{-27} }[/tex]

       =>  [tex]N_p =1.497 *10^{27} \  protons [/tex]

The total electric charge is mathematically represented as

       [tex]Q_p  = + N_p  *  e[/tex]

Here p is the charge on a single proton with value  [tex]p  =  1.60 *10^{-19}  \  C[/tex]

 So

          [tex]Q_p  =  +1.497 *10^{27}   *  1.60 *10^{-19} [/tex]

          [tex]Q_p  =  + 2.395*10^{-8} \  C [/tex]

what is machinery










............​

Answers


an assemblage of machines or mechanical apparatuses: the machinery of a factory. the parts of a machine, collectively: the machinery of a watch. a group of people or a system by which action is maintained or by which some result is obtained: the machinery of government.

An object is released from rest from a top of a building 90 meters high. Neglect air friction.
What is the volume of its acceleration?
Calculate the time it takes to reach the floor?
With what velocity does it reach the floor?
How fast is it moving when it is 50 meter above the floor?

Answers

Answer:

1. a = 9.8 m/s²

2. t = 4.28 s

3. Vf = 42 m/s

4. Vf = 28 m/s  

Explanation:

1.

Since, the body is under free fall motion. Therefore, the value of its acceleration shall be equal to the acceleration due to gravity.

a = 9.8 m/s²

2.

The time taken by the ball to reach the ground can be calculated by using second equation of motion:

h = Vi t + (1/2)gt²

where,

h = height = 90 m

Vi = initial velocity = 0 m/s

t = time taken = ?

Therefore,

90 m = (0 m/s)t + (1/2)(9.8 m/s²)t²

t = √(18.36 s²)

t = 4.28 s

3.

In order to find final velocity we use first equation of motion:

Vf = Vi + gt

Vf = 0 m/s + (9.8 m/s²)(4.28 s)

Vf = 42 m/s

4.

when the ball is at height of 50 m, it means it has covered:

h = 90 m - 50 m = 40 m

we use third equation of motion at this point:

2gh = Vf² - Vi²

(2)(9.8 m/s²)(40 m) = Vf² - (0 m/s)²

Vf = √(784 m²/s²)

Vf = 28 m/s

Other Questions
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