A ball thrown straight up into the air with a speed of 10m/s. If the ball has a mass of 0.3 Kg, how high does the ball go? Acceleration due to gravity is g=9.8 m/s2

Answers

Answer 1

Answer:

5.10 m

Explanation:

Given that:

Initial velocity given to the ball, v = 10 m/s

Mass of the ball, m = 0.3 kg

Acceleration due to gravity, g = 9.8m/[tex]s^2[/tex]

To find: The height upto which the ball will go =  ?

Solution:

Initially, the ball will have kinetic energy and at top point the velocity will be zero, it will have only potential energy due to height.

Formula for kinetic energy and potential energy:

[tex]KE = \dfrac{1}{2}mv^2\\PE = mgh[/tex]

Applying conservation of energy principle:

[tex]\dfrac{1}{2}mv^2=mgh\\\Rightarrow \dfrac{1}{2}v^2=gh[/tex]

Putting the values of v and g to find h:

[tex]\Rightarrow \dfrac{1}{2}10^2=9.8\times h\\\Rightarrow h = \dfrac{50}{9.8}\\\Rightarrow h = 5.10\ m[/tex]

The ball will go 5.10 m high.


Related Questions

1.what are some of the impacts of modern communication in our socio economic life?

2.how is possible to make a call to our relatives residing in other part of country ?explain?​

Answers

Answer:

The impacts of modern communication in our socio economic life includes;

a) Staying connected

b) Carrying out business transaction

c) Exceeding boundaries

d) Overcoming weakness and disability

e) Reaching out to a wider audience

2. It is possible to make long distant call to our relatives in other part of the country by direct distance dialing (DDD)

Explanation:

The telecommunication service called direct distance dialing allows a caller to make a call to a location outside the area where they are calling without the assistance of an operator. To make a direct dialing call, a subscriber or caller will be required to include extra prefix digits to the original number than for numbers within hers or his particular local area code.

On which body would a 10 kg lamp have the most gravitational potential energy when lifted to height of 2 m? A) Earth B) Mars C) Neptune D) Uranus

Answers

Answer: C.) Neptune

Explanation:

The Gravitational Potential Energy (GPE) of a body is calculated using the formula :

GPE = mgh

Where m = mass of the body

g = acceleration due to gravity

h = distance above a surface

Mass = 10kg

h = 2m

Using the formula :

GPE of lamp on Earth: g = 9.8

GPE = 10 × 9.8 × 2 = 71.8J

GPE of lamp on Mercury: g = 3.59

GPE = 10 × 3.59 × 2 = 196J

GPE of lamp on Mars: g = 3.7

GPE = 10 × 3.7 × 2 = 74J

GPE of lamp on Neptune: g = 14.07

GPE = 10 × 14.07 × 2 = 281.4J

GPE of lamp on Uranus: g = 9

GPE = 10 × 9 × 2 = 180J

GPE of lamp on Pluto: g = 0.42

GPE = 10 × 0.42 × 2 = 8.4J

Neptune has the highest gravitational potential energy as the value of acceleration due to gravity acting on objects is highest on Neptune.

Answer:

The correct option is;

C) Neptune

Explanation:

The force of gravity is given by the equation;

[tex]F_g = G\dfrac{m_1m_2}{r^2} = m_2 \times g[/tex]

Where:

m₁ = Mass of the planet

m₂ = Mass of the body = 10 kg

r = The distance between the body and the planet = 2 m

g = Gravitational acceleration on the planet

G = Gravitational constant

Given that the potential energy, PE = m × g × h

We have that,

[tex]PE = m_2 \times g \times (r + 2) = G\dfrac{m_1m_2}{r^2} \times (r + 2) \approx G\dfrac{m_1m_2}{r^2} \times r = G\dfrac{m_1m_2}{r}[/tex]

Therefore, the gravitational potential energy is directly proportional to the acceleration of gravity, such that the body will have the most gravitational potential energy in the planet with the highest acceleration due to gravity which is Neptune with acceleration due to gravity of 14.07 m/s².

Please HELP!!! I will give brainliest to whoever gives honest help!!! A 500 kg satellite experiences a gravitational force of 3000 N, while moving in a circular orbit around the earth. Determine the radius of the circular orbit. Determine the speed of the satellite. Determine the period of the orbit.

Answers

Given that,

Mass of satellite = 500 kg

Gravitational force = 3000 N

We need to calculate the radius of the circular orbit

Using formula of gravitational force

[tex]F_{g}=\dfrac{GMm}{(R+h)^2}[/tex]

Where, G = gravitational constant

R = radius of earth

h = radius of the circular orbit

M = mass of earth

m = mass of satellite

Put the value into the formula

[tex]3000=\dfrac{6.67\times10^{-11}\times500\times6\times10^{24}}{(6.4\times10^{6})^2+h^2}[/tex]

[tex]h^2=\dfrac{6.67\times10^{-11}\times500\times6\times10^{24}-3000\times(6.4\times10^{6})^2}{3000}[/tex]

[tex]h=\sqrt{\dfrac{6.67\times10^{-11}\times500\times6\times10^{24}-3000\times(6.4\times10^{6})^2}{3000}}[/tex]

[tex]h=5073460.35\ m[/tex]

[tex]h=5.1\times10^{6}\ m[/tex]

(II). We need to calculate the speed of the satellite

Using formula of velocity

[tex]v=\sqrt{\dfrac{GM}{r}}[/tex]

Put the value into the formula

[tex]v=\sqrt{\dfrac{6.67\times10^{-11}\times6\times10^{24}}{5.1\times10^{6}}}[/tex]

[tex]v=8858.36\ m/s[/tex]

[tex]v=8.8\times10^{3}\ m/s[/tex]

[tex]v=8.8\ km/s[/tex]

(III). We need to calculate the period of the orbit

Using formula of  time period

[tex]T=2\pi\sqrt{\dfrac{r^3}{GM}}[/tex]

Put the value into the formula

[tex]T=2\pi\sqrt{\dfrac{(5.1\times10^{6})^3}{6.67\times10^{-11}\times6\times10^{24}}}[/tex]

[tex]T=3617.40\ sec[/tex]

[tex]T=1.00\ hr[/tex]

Hence, (I). The radius of the circular orbit is [tex]5.1\times10^{6}\ m[/tex]

(II). The speed of the satellite is 8.8 km/s.

(III). The period of the orbit is 1.00 hr.

In which direction of the wave motion do longitudinal waves transfer energy?
A-perpendicular
B- parallel
C- close
D-equal

Answers

Answer:

B, Parallel.

Explanation:

Mark as brainliest pls!

The wave motion does longitudinal waves transfer energy in the direction Parallel to the wave motion. Hence, option B is correct.

What is a Wave?

Waves are disturbances that move regularly and orderly from one location to another. Although sound, lighting, and the movement of elementary particles all have wave-like characteristics, surface waves that move on water are the most well-known.

The disturbance periodically oscillates with a set frequency and wavelength in the simplest waves (see periodic motion). In contrast to electromagnetic waves, which do not require a medium to travel and may move through a vacuum, mechanical waves, like sound, need a medium to go through. A medium's characteristics determine how a wave will travel across it. Seismic wave is also seen.

Therefore, option B is correct.

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A company plans to build a new mega store next to a wetland. Which of the following should it do to make sure it has scientific knowledge to inform its decision? Hire an environmental company to study the wetland and give recommendations of how to prevent flooding Ask a developer to build a new housing development next to the store site Have the city council review the architectural plans Conduct a survey to see how often people in the neighborhood shop

Answers

Answer:

The correct option is;

Hire an environmental company to study the wetland and give recommendations of how to prevent flooding

Explanation:

Due to the environmental importance of wetlands which are important plant and animal habitats and a source of filtration of reserve of water moving into other surface water bodies and underground aquifers, serving also as a buffer zone to prevent erosion and flooding during heavy rain storms, proper, detailed and well informed environmental considerations are required

As such an environmental consultant services is needed for site analysis, appraisal and recommendation will be required to fast track the process of obtaining a permit.

Answer:

A

Explanation:

Find average speed in
time interval t = 2 tot = 10s
Distance (m)
10+
8-
2
+ Time (s)
10​

Answers

Answer: 3.75 m/s

Explanation:

Average speed is distance covered per time taken.

If the time interval is from t = 2 to t = 10s

Then, the time taken will be

t = 10 - 2 = 8s

Given that the distance covered are 10 + 8 - 2 + 10

Since distance is a scalar quantity, we will only consider the magnitude and not the direction.

Total distance = 10 + 8 + 2 + 10 = 30m

Average speed = total distance/time

Substitute total distance and time into the formula

Average speed = 30/8

Average speed = 3.75 m/s

Which force best represents Fg

Answers

Answer:

The weight of barbell acting on a weight lifter is 80N.

Explanation:

Which describes reproducibility? The ability of data to be published. The ability of data to be duplicated. The ability of data to be changed. The ability of data to be invalidated.

Answers

Answer:

the ability of data to be duplicated well described reproducibility

Explanation:

Reproducibitity of a data is the ability of a data to be produced in multiple times using the same procedure. It is used to test how precise a data is and it's usually known as standard deviation

Reproducibility is the closeness of the understanding between the consequences of measurements of the equivalent measurand did with a similar procedure depicted in the relating logical proof (for example a distribution in a companion surveyed diary).

Answer:

the ability of data to be duplicated well described reproducibility

Un proyectil es lanzado horizontalmente desde una altura de 12 metro con una velocidad de 80 m/sg. a.Calcular el tiempo de vuelo b. Su alcance horizontal y velocidad de impacto contra el suelo.

Answers

Answer:

t= 1,56 s ,   x= 124,8 m , v = (80 i^ - 15,288 j ) m/s

Explanation:

Este es un ejercicio de lanzamiento proyectiles, comencemos por encontrar el tiempo que tarda en llegar al piso

        y = y₀ + [tex]v_{oy}[/tex] t – ½ g t²

en este caso la altura inicial es y₀= 12 m y llega a y=0 , como es lanzado horizontalmente la velocidad vertical es cero (v_{oy}=0)

       0 = y₀ – ½ g t²

       t= √ (2 y₀/g)

calculemos

       t= √ ( 2 12 / 9,8)

       t= 1,56 s

El alcance del proyectil es la distancia horizontal recorrida  

        x = v₀ₓ t

        x = 80 1,56

        x= 124,8 m

La velocidad de impacto cuando toca el suelo

        vx = v₀ₓ = 80 ms

        [tex]v_{y}[/tex] = v_{oy} – gt

        v_{y} = - 9,8 1,56

        v_{y} = - 15,288 m/s

la velocidad es

       v = (80 i^ - 15,288 j ) m/s

Traducttion  

This is a projectile launching exercise, let's start by finding the time it takes to reach the ground

        y = y₀ + v_{oy} t - ½ g t²

in this case the initial height is i = 12 m and it reaches y = 0, as it is thrown horizontally the vertical speed is zero ([tex]v_{oy}[/tex] = 0)

       0 =y₀I - ½ g t²

       t = √ (2y₀ / g)

let's calculate

       t = √ (2 12 / 9.8)

       t = 1.56 s

Projectile range is the horizontal distance traveled

        x = v₀ₓ t

        x = 80 1.56

        x = 124.8 m

Impact speed when it hits the ground

        vₓ = v₀ₓ = 80 ms

        v_{y} = v_{oy} - gt

        v_{y} = - 9.8 1.56

        v_{y} = - 15,288 m / s

the speed is

       v = (80 i ^ - 15,288 j) m / s

state any two physical properties for believing that aluminium is a metal.​

Answers

Answer:

amongst the properties that makes aluminium a metal is that it is malleable and ductile...and it has high melting and boiling points

I hope that helps

Explanation:

properties of metals include

1. high melting and boiling points

2 high densities

3 malleability and ductility

Average acceleration. Please help!

Answers

Answer:

8.43 m/s²

Explanation:

Average acceleration is the change in velocity over change in time.

a = Δv/Δt

First, convert km/h to m/s.

45 km/h = 12.5 m/s

500 km/h = 138.9 m/s

Now find the acceleration.

a = (138.9 m/s − 12.5 m/s) / 15.0 s

a = 8.43 m/s²

What is the net force acting on the buggy. ?The net force is pointing to the ?

Answers

Answer: 390, right

explanation: The net force is just the sum of all of these forces acting on an object. ... This equation is the sum of n forces acting on an object. The magnitude of the net force acting on an object is equal to the mass of the object multiplied by the acceleration of the object, as shown in this formula.

the net force acting on the buggy is 390 and The net force is pointing to the is right

The following information should be considered:

The net force should be the sum of all of these forces that acted an object.This equation is the sum of n forces acting on an object. The magnitude of the net force acting on an object is equivalent to the mass of the object and multiplied by the acceleration of the object

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If a locomotive uses steam at
100°C, and dumps heat into air
at 22.0°C, what is the highest
possible efficiency it could have?

Answers

Answer:

79%

Explanation:

Data obtained from the question include the following:

Input temperature = 100°C

Output temperature = 22°C

Efficiency =.?

Next, we shall convert celsius temperature to Kelvin temperature.

This is illustrated below:

T(K) = T (°C) + 273

Input temperature = 100°C

Input temperature in Kelvin = 100°C + 273 = 373K

Output temperature = 22°C

Output temperature in Kelvin = 22°C + 273 = 295K

Finally, we shall determine the efficiency of the locomotive as follow:

Efficiency = output /input x 100

Output = 295K

Input = 373K

Efficiency =?

Efficiency = output /input x 100

Efficiency = 295/373 x 100

Efficiency = 79%

Therefore, the efficiency of the locomotive is 79%.

Answer:

The answer is .209

Explanation:

I am unable to show the work for this as I did it online but I can assure you it is correct

La luz pasa del medio A al medio B formando un ángulo de 35° con la frontera horizontal entre ambos. Si el ángulo de refracción también es de 35°, ?cuál es el índice de refracción relativo entre los dos medios?

Answers

Answer:

Índice de refracción entre los dos medios = 1,43

Refractive index between the two media = 1.43

Explanation:

El índice de refracción entre dos medios se explica mejor entendiendo primero la refracción.

Cuando las olas se mueven de un medio a otro, a menudo experimentan un cambio de dirección con respecto al medio en el que viajan.

Por lo tanto, el índice de refracción se expresa como el seno del ángulo de incidencia dividido por el seno del ángulo de refracción.

El seno del ángulo de incidencia y la refracción utilizados en esta fórmula de índice de refracción se miden respectivamente con respecto a la vertical.

En esta pregunta Ángulo de incidencia = 35° a la horizontal = (90° - 35°) a la vertical = 55° a la vertical.

Ángulo de refracción = 35°

Índice de refracción entre los dos medios

= (Sin 55°) ÷ (Sin 35°)

= 0.8192 ÷ 0.5736

= 1.428 = 1.43 a 2 d.p.

¡¡¡Espero que esto ayude!!!

English Translation

The light passes from medium A to medium B at an angle of 35 ° with the horizontal border between the two. If the angle of refraction is also 35 °, what is the relative refractive index between the two media?

Solution

The refractive index between two media is best explained by first understanding refraction.

When waves move from one medium to another, they often experience a change in direction with respect to the medium in which they are travelling.

Hence, refractive index is expressed as the sine of angle of incidence dibided by the sine of angle of refraction.

The sine of angle of incidence and refraction used in this refractive index formula are both respectively measured with respect to the vertical.

In this question,

Angle of incidence = 35° to the horizontal = (90° - 35°) to the vertical = 55° to the vertical.

Angle of refraction = 35°

Refractive index between the two media

= (Sin 55°) ÷ (Sin 35°)

= 0.8192 ÷ 0.5736

= 1.428 = 1.43 to 2 d.p.

Hope this Helps!!!

the weight of a body will be zero during free fall. Why? ​

Answers

Answer:

The apparent weight of a freely falling body is zero. When a body falls freely, it is falling with an acceleration =g. Thus the entire gravitational force acting on it is utilized in accelerating it and hence its weight is not felt.

The kicker now kicks the ball with the same speed as in the number of 4,but at 60.0°from the horizontal or 30.0° from the vertical. a.What is the time the ball is in the air? b.What is the distance the balls travel before it hits the ground? c.What is the maximum height?

Answers

Answer:

Explanation:

1) The time of flight equation for projectile motion can be used here to find total time in air.

t = 2vsin∅ / g

where v is speed, Ф is launch angle

t = 2×4×sin 60 / 9.8

t = 0.71 seconds

2) Distance where it hit the ground is called as range and has the following standard equation

D = v² sin2Ф/g

D = 4²sin 2×60 / 9.8

D = 1.41m

3) Maximum elevation is maximum time reached

h = v² sin²Ф / 2g

h = 4²sin² 60 / 2*9.8

h = 0.61 m

What is the effect of the medium on the speed of the sound? In which medium sound travels more faster: air, solid, or liquid? Justify your answer?

Answers

The phase of matter has a large impact upon the elastic properties of a medium. In general, the bond strength between particles is strongest in solid materials and is weakest in the gaseous states As a result, sound waves travel faster in solids than in liquids, and faster in liquids than in gasses.

Hope this helps

Answer:

Sound travels fastest through solids. This is because molecules in a solid medium are much closer together than those in a liquid or gas, allowing sound waves to travel more quickly through it. In fact, sound waves travel over 17 times faster through steel than through air.

Does the earths magnetic field change with time?

Answers

Answer:

As per the fossil fuel records, magnetic field reversal does not impact living beings. It will take almost a century for the poles to complete the shift. Meanwhile, the earth is left with almost zero magnetic field.

HELP NEEDE ASAP!!!!!!!! How do you understand by the longitudinal wave? Describe the longitudinal nature of sound waves

Answers

Answer:

Sound as a Longitudinal Wave

For a sound wave traveling through air, the vibrations of the particles are best described as longitudinal. Longitudinal waves are waves in which the motion of the individual particles of the medium is in a direction that is parallel to the direction of energy transport.

Answer:

Hey!

Here is your answer!

Explanation:

LONGITUDINAL WAVES:

These are waves where the transferral of energy is PARALLEL to the direction it travels in...For Example...Sound Waves are Longitudinal as they move in a series of COMPRESSIONS and RAREFACTIONS (typical of all Longitudinal Waves)...

The compressions are known in diagrams to be an area of a dense collection of PARTICLES where the energy (or sound in this case) is being transferred in the same direction as the movement...

The rarefactions are shown as almost empty area of particles where the medium (the matter of which the wave travels in) is moving...

Hope this helps!

*here's a diagram*

If a star is located 100 light years from Earth, what can you conclude about the light from the star?
The light will take 100 years to reach Earth.
The light will take 100 seconds to reach Earth.
The light will take 300,000 years to reach Earth.
The light will travel a total of 300,000 kilometers to reach Earth.

Answers

Answer:

Light from star would take 100 years to reach the Earth.

Explanation:

1 light year = speed of light × 1 year

1 light year = 9.46 × 10¹⁵ m

hope i helped

-lvr

Answer:

a

Explanation:

;)

write a story that ends with poor no friend​

Answers

Answer:

Writing of a story that ends with the character becoming poor with no friends.

Explanation:

There was a young girl who believed that all things revolve around her. She had the money, the power, the family, and the beauty to ensure she was the center of attention. She would always be the main focus, everywhere she goes.

But there came a time when she had a major misfortune. Her family had come upon unfortunate times. They are going to lose their money and may even be jailed for embezzlement. It was true that she had no idea what her parents had done but she was also so familiar with the 'princess' lifestyle that she did not know how to downgrade her lifestyle. And so, when this misfortune happened, she was unsure how to react. She also assumed that her friends will be there for her. Little did she know everyone was just after her wealth and influence and had nothing to do with genuine friendship.

In a few months, their family position moved from top to bottom, which everyone found hard to accept. She had to maintain her status while at the same time try to live up with that without losing her circle. But as rumors spread fast and she wasn't able to spend the way she would normally send, she eventually experienced a dwindled friend circle. And in about a year, she had lost all of her friends, couldn't even convince someone to stay with her faithfully and worse of all, she was also poor, the very status she had degradingly taunted other people with.

A small block slides down an incline with a constant acceleration. The block is released from rest at the top of the incline. After it travels 5 m to the bottom its speed is 5 m/s. What is the speed, in m/s, of the block when it had traveled only 2.1 m from the top

Answers

Answer:

v = 3.24 m/s

Explanation:

Since we don't have time, we can use the formula;

(Final distance - initial distance)/time = (initial velocity + final velocity)/2

Thus;

(x_f - x_i)/t = ½(v_xi + v_xf)

We are given;

x_i = 0 m

x_f = 5 m

v_xi = 0 m/s

v_xf = 5 m/s

Thus, plugging in the relevant values;

(5 - 0)/t = (0 + 5)/2

5/t = 5/2

t = 2 s

Using Newton's first law of motion, we can find the acceleration.

v = u + at

Applying to this question;

5 = 0 + a(2)

5 = 2a

a = 5/2

a = 2.5 m/s²

To get the speed, in m/s, of the block when it had traveled only 2.1 m from the top, we will use the formula;

v² = u² + 2as

v² = 0² + 2(2.5 × 2.1)

v² = 10.5

v = √10.5

v = 3.24 m/s

At the equator, near the surface of the Earth, the magnetic field is approximately 50.0 μT northward, and the electric field is about 100 N/C downward in fair weather. Find the gravitational, electric, and magnetic forces on an electron in this environment, assuming that the electron has an instantaneous velocity of 8.50 ✕ 106 m/s directed to the east.

Answers

Answer:

A) F_g = 8.9278 × 10^(-30)

B) F_e = 1.6 × 10^(-17) N upwards

C) F_m = 6.8 × 10^(-17) N downwards

Explanation:

A) Formula for gravitational force is;

F_g = m_e × g

m_e is mass of electron = 9.11 x 10^(-31) kg

F_g = 9.11 x 10^(-31) × 9.8

F_g = 8.9278 × 10^(-30) N downwards

B) Formula for Electric force is;

F_e = qe

q is charge on electron = 1.6 × 10^(-19) C

E is electric field = 100 N/C

F_e = 1.6 × 10^(-19) × 100

F_e = 1.6 × 10^(-17) N upwards

C) Magnetic force is given by the formula;

F_m = qVB

q is charge on electron = 1.6 × 10^(-19) C

V is velocity given as 8.50 × 10^(6) m/s

B is magnetic field = 50.0 μT = 50 × 10^(-6) T

F_m = 1.6 × 10^(-19) × 8.50 × 10^(6) × 50 × 10^(-6)

F_m = 6.8 × 10^(-17) N downwards

An airplane starts at rest and accelerates down the runway for 25 s. At the end of the runway, its final velocity is 75 m/s east. What is its acceleration?

Answers

Answer

3m/s²

Explanation

u=o

t=25s

v=75m/s

from Newton's first law of motion,

v=u+at

75=0+a(25)

75=25a

a= 75/25

a=3m/s²

The acceleration of the airplane is 3m/s².

What is acceleration?

Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).

Given parameters:

Initial velocity of the airplane: u=o.

Time taken: t=25s.

Final velocity of the airplane: v=75m/s.

We have to find acceleration of the plane: a = ?

We know that for accelerating motion of the air plane; final velocity can be expressed as:

    v=u+at

⇒ 75=0+a(25)

⇒ 75=25a

⇒ a= 75/25

⇒ a= 3m/s².

hence, acceleration of the airplane is 3m/s².

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what causes short sightedness ?how is it corrected

Answers

Answer:

Short sight occurs when the eyeball is too long or the lens is too thick, or both. As a result, light rays from distant objects are focused in front of the retina (because the light rays are highly converged). The image formed on the retina is therefore out of focus.

Short sight can be corrected by wearing glasses with concave lenses. Light rays from distant objects are diverged by concave lenses before entering the eyes, so that light can be focused on the retina to form a sharp image.

I NEED HELP PLEASE, THANKS! :)
Three 15.0-W resistors are connected in parallel across a 30.0-V battery. Please show all work.
a) Find the current through each branch of the circuit.
b) Find the equivalent resistance of the circuit.
c) Find the current through the battery.

Answers

Answer:

Take a look at the attachment below.

Explanation:

Current for each branch of the circuit is 2A and equivalent resistance of the circuit will be 5 ohms. The current through the battery is 6A.

What is Current?

An electric current is defined as a stream of charged particles, such as electrons or ions, moving through an electrical conductor or space, which is described as the flow of electric charge through a surface or in a control volume.

Current is expressed as:

I=V/R

Where, I is the current

V is the voltage

R is the resistance

For above given information,

Since all resistors have the same resistance, it would be fine to find only 1 branch as the current would be the same for all branches.

[tex]I=V/R_1[/tex]

I= 30/15= 2 A

Equivalent resistance for parallel circuits is the sum of reciprocals of each resistor.

[tex]1/R= 1/R_1+ 1/R_2+ 1/R_3[/tex]

1/R= 1/15+ 1/15 + 1/15

1/R=3/15

R = 15/3= 5 ohms

I = V/R

Where I is current, V is voltage and R is the equivalent resistance

=> I = 30/5

=> I = 6 A

Thus, current for each branch of the circuit is 2A and equivalent resistance of the circuit will be 5 ohms. The current through the battery is 6A.

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a boy runs from his house to school at speed 5m/s on a straight road and returns with speed of 10m/s.The distance between the house and school is 100m. Find his average velocity.... with explaination please​

Answers

Explanation:

time spent to run from house to school=100/5=20s

time spent to return from school=100/10=10s

average velocity=200m/(10+20)

=6.66m/s

A 5000 kg mass rocket “breaks the engine” when it is 100 m high and climbing at a speed of 75 m / s. Calculate:
1) The maximum height it will reach
2) The speed with which it will hit the ground after the fall.

Answers

Answer:

1:281.25m

2:75m/s

Explanation:

using the equation

[tex]v^{2} = u^{2} + 2gs[/tex]

at maximum height v is zero so using that you can make s the subject of the formula

[tex]h \: max = u^{2} \div \: 2g[/tex]

so substitute the velocity 75 and the constant g-10m/s^2

as for the returning velocity we say displacement is zero since you go and come back the same distance

so

[tex]v = { + or - }u[/tex]

u is the initial speed in this case it's positive since going in the direction of gravity

Why does time slow down the closer you get to a black hole, I know that time slows down the faster you move through space and the closer you get to the speed of light, but how does being near a black hole slow time down even futher?

Answers

Answer:

Near the black hole, The gravitational pull is so strong and the black hole has a lot of stress energy. This causes the clock to tick slower than usual and due to this , Time slows down to a great extent.

answer the following question​

Answers

Answer:

A) OA, AB, BC

B) 25m/s^2

C) see explanation

D) 25

E) Rest

Explanation:

From the Velocity time graph shown:

The positive slope = OA ; This is positive because, it is the point of uniform acceleration on the graph.

Constant slope = AB, the slope here is constant because, AB on the graph is the point of constant velocity.

-ve slope = BC

B) Acceleration of body in path OA.

Acceleration = change in Velocity / time

Acceleration = (150 - 0) / 6

Acceleration = 150/6 = 25m/s^2

C) Path AB is Parallel to the because it marks the period of constant velocity (that is Velocity does not increase or decrease during the time interval).

D) Length of BC

BC corresponds to the distance moved, that velocity / time

Velocity = 150 ; time = 6

Therefore Distance (BC) = 150/6 = 25

E.) Velocity =0 ; Hence body is at rest

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