A ball is projected upward at time t = 0.0 s, from a point on a roof 70 m above the ground. The ball rises, then falls and strikes the ground. The initial velocity of the ball is What is the velocity of the ball when it is above the ground? −89 m/s − 72 m/s − 36 m/s − 107 m/s − 54 m/s

The wavelength of the wave will be 4 meters. when 5 complete waves occupy a length of 20m.

Wavelength is defined as the space between waves' crests, particularly between electromagnetic or sound wave points. A recurring event's frequency is measured by how many times it occurs in a unit of time. To underline the difference from spatial frequency, it is also occasionally referred to as temporal frequency.

There is an inverse relationship between the frequency and the wavelength of the waves as the wavelength increases the frequency decreases and if the wavelength decreases the frequency increases.

Given that a wave has 5 complete waves occupying a length of 20m. The wavelength of the wave will be calculated as below:-

λ = Distance / frequency

λ = 20 / 5

λ = 4 meters

Therefore, the wavelength of the wave will be 4 meters. when 5 complete waves occupy a length of 20m.

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Answer:

we have to measure distances and time, possibly with an automated system since the values ​​are very small

Explanation:

For this exercise we can use the relationship between momentum and momentum

        I = ∫ F dt = Δp

        F t = m [tex]v_{f}[/tex] - mv₀

In the exercise they indicate that the final speed is zero

         F t = - m v₀

         F = -m v₀ / t

With this equation we can find what measurements should be carried out.

To find the speed with which the car collides with the wall, less measure the displacement and its time during the braking process before reaching the wall and from here find the speed with which it reaches the wall.

During the impact, we must find the time that the vehicle is in contact with the wall in the first approach is equal to the time that the car takes to reach the final speed of zero.

In summary we have to measure distances and time, possibly with an automated system since the values ​​are very small

Answer:

Zero

Explanation:

The magnetic field due to the first wire on the second wire with current i₁ in the first wire at a distance d from the second wire is B₁ = μ₀i₁/2πd.

The magnetic force due to this field on the second wire of length segment, L and current i₂ is F₁ = Bi₂L = (μ₀i₁/2πd)i₂L = μ₀i₁i₂L/2πd = F

The magnetic field due to the second wire on the first wire with current i₂ in the first wire at a distance d from the second wire is B₂ = μ₀i₂/2πd.

The magnetic force due to this field on the first wire of length segment, L and current i₁ is F₂ = Bi₁L = (μ₀i₂/2πd)i₁L = μ₀i₁i₂L/2πd = F

Since their magnetic fields are in opposite directions, according to the right hand rule, their forces would also be in opposite directions.

So F₁ = F and F₂ = -F

So their vector sum F₁ + F₂ = F +(-F) = F - F = 0

Answer:

135,000 m

Explanation:

(1500 m/s) (90 s) = 135,000 m

The distance travelled by sonar pulse will be 135,000 m. Distance is a numerical representation of the distance between two objects or locations.

The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.

The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.

The length of a wave is measured in its propagation direction. The wavelength is measured in meters, centimeters, nanometers, and other units since it is a distance measurement.

The distance travelled by sonar pulse is found as;

[tex]\rm d = v \times t \\\\ \rm d = 1500\times 90 \\\\ \rm d = 135,000 \ m[/tex]

Hence, the distance travelled by sonar pulse will be 135,000 m.

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Answer:

Inductance per unit length, [tex]\frac{L}{l} = 7.02 * 10^{-7} H/m[/tex]

Explanation:

Radius of the wire, a = 2.80 mm

Currents carried by each of the wires, i = 5.00 A

Center-to-Center Separation, W = 19.0 cm

The flux in the wires is given by the equation, ∅ = Li

The Net flux of the region between the wires  is given by the equation:

[tex]\phi = \frac{l \mu_0 i}{\pi} ln(\frac{W-a}{a})[/tex]

Divide both sides by l to get the net flux per unit length

[tex]\phi/l = \frac{ \mu_0 i}{\pi} ln(\frac{W-a}{a})\\\phi/l = \frac{ 4 \pi * 10^{-7} i}{\pi} ln(\frac{0.019-0.0028}{0.0028})\\\phi/l = 7.02 * 10^{-7} i\\\frac{Li}{l} = 7.02 * 10^{-7} i\\\frac{L}{l} = 7.02 * 10^{-7} H/m[/tex]

Answer: 4.) 17.2cm

Explanation:

A flashlight is 40.0 cm from a double convex lens. The image of the flashlight is observed at a position 30.0 cm on the other side of the lens. What is the focal length?

Given the following :

Object distance(u) = 40cm

image distance (v) = 30cm

Focal length(f) =?

Using the mirror formular:

f = uv / (v+u)

f = (40 * 30) / (40 + 30)

f = 1200 / 70

f = 17.142857 cm

Answer:

The primary distinct forms that matter can exist in is solid, liquid, and gas.

Explanation:

Answer:

liquid, solid, and gas

Explanation:

Answer: when you increase or decrease your speed.

Explanation:

Moving a skate at rest, you need to apply force in order to cause acceleration.

F = ma Where

F = force applied

m = mass of the skate

a = acceleration

The initial velocity u will be equal to zero and the skate will acceleration to a certain velocity.

as you skate down your neighborhood sidewalk, you will accelerate when you increase your speed. Because

Acceleration is the rate of change of velocity. That is,

Acceleration = change in velocity/ time.

And also, you will decelerate when you reduce the speed or velocity down your neighborhood sidewalk.

Answer:

The overall charge on the wall is zero.

Explanation:

Because the atoms making the wall are neutral i.e. number of positive charges are equal to number of negative charges.

Answer:

A light year is the distance light travels in a year. ... And an astronomical unit is the average distance between the earth and the sun. So the distance to the sun is by definition one AU. A parsec is the distance at which one astronomical unit subtends an angle of one second of arc.

Answer: A light year is the distance light travels in a year. ... And an astronomical unit is the average distance between the earth and the sun. So the distance to the sun is by definition one AU. A parsec is the distance at which one astronomical unit subtends an angle of one second of arc

Explanation:

Answer:

Explanation:

work done by force exerted by canon = force x displacement

= 40 x 1.7 =  68 N

This energy would have been added to the potato .

Increase in potential energy of potato = mgh

= mg sin 35 x 1.7  = 2 x 9.8 x sin 35 x 1.7 = 19.11 J

Increase in kinetic energy = 68 - 19.11

= 48.89 J

Answer:

43,919.66 Kilotones de Co2 en 2016.

Explicación:

Ecuador produce 43,919.66 Kilotones de Co2 en 2016. Las tierras húmedas son muy importantes para la biodiversidad porque proporcionan hábitat a millones de animales. Alrededor del 35 por ciento de todas las especies amenazadas y en peligro vive en estas tierras húmedas. Estas tierras húmedas son altamente productivas y tienen la capacidad de mejorar la calidad del agua, prevenir la degradación del suelo y proporcionar alimentos a los animales que viven en estas tierras húmedas.

Answer:

The uterus plays a significant part in the pregnancy, menstruation, zygote implantation, conception, labor, and delivery of the baby along with other essential reproductive system organs.

Explanation:

The uterus is a female reproductive organ that is pare shaped and situated between the urinary bladder and the rectum ins the pelvis.  The placenta develops links with the uterine blood vessels that provide the embryo with nutrition through an umbilical cord. When this happens, the uterus delivers signals to the brain to adjust the secretion of the hormone such that releases of more eggs (i.e. ovulation) are halted and the menstrual cycle momentarily stops, thereby verifying the pregnancy. In pregnancy the uterus provides the space and an adequate atmosphere for the fetus to develop safely, it provides feedback to the brain which regulates hormones release. The uterus forms a link between the mother and the baby through the placenta and umbilical cord not only to provide the requisite nutrients and oxygen but also to extract the waste products and purify the blood of the fetus before the fetal organs take over.

Answer:

C.) vector C

Explanation:

From the graph provided:

Four vectors are present :

Vectors a, b, c and d.

The x-component of the vector is its magnitude along the x-axis.

Taking the coordinate of each vector:

Vector a = (1,4) : length of x- component = 1

Vector b = (1, 1) : length of x- component = 1

Vector c = (4, -4) : length of x- component = 4

Vector d = (-3, 4) : length of x- component = - 3

Therefore, vector c has an x-component length of 4

Answer:

V = 2.5 J/C

Explanation:

Given:

Energy = E = 20 J

Charge = Q = 8 C

Required:

Potential Difference = V = ?

Formula:

V = [tex]\frac{E}{Q}[/tex]

Solution:

V = 20/8

V = 2.5 J/C

Answer:

Given :

To Find :

Using Formula :

We know that the electric potential difference is also known as voltage (v).

[tex]{\star{\small{\underline{\boxed{\sf{\red{ V =\dfrac{E}{Q}}}}}}}}[/tex]

Solution :

Substituting the given values in the formula to find potential difference :

[tex]{\dashrightarrow{\small{\pmb{\sf{ V =\dfrac{E}{Q}}}}}}[/tex]

[tex]{\dashrightarrow{\small{\sf{ V =\dfrac{20}{8}}}}}[/tex]

[tex]{\dashrightarrow{\small{\sf{ V = \cancel{\dfrac{20}{8}}}}}}[/tex]

[tex]{\dashrightarrow{\small{\sf{ V = {\dfrac{10}{4}}}}}}[/tex]

[tex]{\dashrightarrow{\small{\sf{ V = \cancel{\dfrac{10}{4}}}}}}[/tex]

[tex]{\dashrightarrow{\small{\sf{\underline{\underline{\purple{V = 2.25}}}}}}}[/tex]

Hence, the potential difference is 2.25V.

[tex]\underline{\rule{220pt}{3pt}}[/tex]

Answer:

Transverse wave  and Longitudinal wave  and Electromagnetic wave

Explanation:

Answer:

Transverse wave  and Longitudinal wave  and Electromagnetic wave

Explanation:

Answer:

Explanation:

The resistance of a material is expressed as R = ρL/A

Volume of the original material V = Area * Length = A*L

ρ is the resistivity of the material

R is the resistance

A is the cross sectional area

L is the length of the wire.

If the wire is stretched o twice its original length then new length of the wire L₂ = 2L. Note that an increase in the length of wire will affect its area but its volume and density will not change.

This means V = V₂

A*L = = A₂*L₂

A*L = A₂*(2 L)

A = 2 A₂

A₂ = A/2

The new resistance of the material Rf = ρL₂/A₂

R₂ = ρ(2 L)/(A/2)

Rf =  2ρL * 2/A

Rf = 4(ρL/A)

Since R = ρL/A

R₂ = 4R

Hence, the resistance of the stretched wire will be four times that of the original wire.

If the wire is stretched to twice its original length, the new resistance would be quadrupled.

The resistance (R) of a wire is given by:

[tex]R=\rho\frac{L}{A} \\\\where\ L\ is\ length\ of\ wire, A\ is\ the\ cross\ sectional\ area\ and\ \rho\ \\is\ the\ resistivity[/tex]

Since the wire is stretched, the new length (L₁) is twice its original length, hence:

L₁ = 2L

An increase in length affects the area, the new area (A₁) is:

initial volume = volume after stretch

AL = A₁L₁

AL = A₁(2L)

A₁ = A/2

The resistance of the stretched wire (R₁) is:

[tex]R_1=\rho\frac{L_1}{A_1} \\\\R_1=\rho\frac{2L}{A/2} \\\\R_1=4\rho\frac{L}{A}=4R[/tex]

Therefore if the wire is stretched to twice its original length, the new resistance would be quadrupled.

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The net force acting on the sled is zero. The sled is in a state of dynamic equilibrium.

Explanation:

The two vertical forces, Fg and Fn, cancel each other out, but I choose to "ignore" them in my explenation, although they remain present at all times.

Since the net force acting on the sled is zero, the sled is in some state of equilibrium...

Whether the sled or a stationary equilibrium or in a dynamic equilibrium, depends on the the motion of the object. If the object is moving then it is a dynamic equilibrium and if the object is not moving, then there is a stationary equilibrium.

Look closely at the picture of the sled and the dogs, and try to find out if the sled is standing still or if the sled is moving with a constant speed.

From the movement of snow around the dogs, you can tell, the sled is moving. It clearly is not stationary or left standing still.

So in this case it must be a dynamic equilibrium. The combined pull of all dogs is shown by Ft = 225 N.

Apparently, the friction is displayed as an opposite force shown as Ff = - 225 N. These two horizontal forces cancel each other out.

Strangely enough, this can be compared with a situation like a "tug of war", in which both sides pull with equal force. Although there can be an enormous tension in the cord, nothing moves.... The same is true here although the sled is moving with a constant speed...

EXTRA

Given is that the sled is moving with a constant speed.

No imagine two situations and try to predict what will happen.... Here we go...

Situation 1 The friction force remains Ff = - 225 N but the dogs suddenly start to pull harder, say with a force of 275 N.

Now the net Force will be greater then zero. In that case it will be 275 - 225 = 50 N in favour of the dogs, which would result in an exeleration of the sled, and thus an increase of the speed...

Situation 2 The friction force becomes greater Ff = - 300 N, but the dogs pull with the same force of 225 N.

Now the net Force will be less then zero. In that case it will be 225 - 300 = -75 N in favour of the friction Force, which would result in slowing down the sled. Perhaps the sled operator applied the brake on the sled, which caused a deceleration of the sled, and thus the speed decreases.

Answer:

yes

Explanation:

edg 2020

Answer:

A.) H = 58.6 m

B.) T = 6.92 s

C.) 345.12 m

D.) V = 22.13 m/s

E.) Ø = 32.1 degree

Explanation:

Given that the

initial speed U = 60.3 m/s

Angle Ø = 34.2 degree

A.) At maximum height, final velocity V is equal to zero.

Using the third equation of motion under gravity.

V^2 = U sin Ø^2 - 2gH

Substitute for U and g. Where g = 9.8 m/s^2

0 = (60.3 sin 34.2)^2 - 2 × 9.8 × H

1148.78 = 19.6 H

H = 1148.78/19.6

H = 58.6 m

B.) To Determine the total time in the air, let us use the formula

V = UsinØ - gt

At maximum height, V = 0

t = UsinØ/g

Total time T = 2t

Therefore, T = 2UsinØ/g

T = (2 × 60.3 × sin 34.2)/9.8

T = 67.79/9.8

T = 6.92 s

C.) To determine the total horizontal distance covered which is the range, we will use second equation of motion.

S = UcosØT - 1/2gt^2

Where S = range R

g = 0, since the range is not a vertical distance

T = total time

Substitute all the parameters into the formula

R = 60.3 cos 34.2 × 6.92

R = 345.12 m

D.) After 1.2 s firing,

V = UsinØ - gt

Where t = 1.2 s

Substitute into the formula

V = 60.3 × sin34.2 - 9.8 × 1.2

V = 33.89 - 11.76

V = 22.13 m/s

Therefore the speed of the projectile 1.20 s after firing is 22.13 m/s

E.) The direction will be determined by using the formula

t = VsinØ/ g

Cross multiply

VsinØ = gt

Make SinØ the subject of formula

SinØ = gt/V

SinØ = (9.8×1.2)/22.13

Sin Ø = 11.76/22.13

Sin Ø = 0.53

Ø = sin^-1( 0.53 )

Ø = 32.1 degree

Answer:

Magnitude of the acceleration(g) = 9.7 meters/second²

Explanation:

Given:

Height of tower = 56 meter

Time taken = 3.4 second

Final velocity (v) = 33 meters/second

Initial velocity (u) = 0 meters/second

Find:

Magnitude of the acceleration(g)

Computation:

Using first equation of motion:

v = u + at

Magnitude of the acceleration(g)

v = u + gt

33 = 0 + g(3.4)

g = 33 / 3.4

g = 9.7 meters/second²

Magnitude of the acceleration(g) = 9.7 meters/second²

Answer: 6700m/s^2 E

Explanation:

Given the following :

Velocity of ball before being hit by a racquet = initial velocity(u) = 55m/s W

Velocity of the ball after being hit = final Velocity (v) = 45m/s E

Time of contact between ball and racquet (t) = 1.5 × 10^-2

The acceleration of a body is the change in Velocity of a body with time. It given by:

Acceleration (a) = [final Velocity(v) - initial velocity(u)] / time(t)

The westward direction is towards the left and thus Velocity takes a negative value, similarly, if it's towards the right, Velocity takes a positive value.

Therefore,

a = [45 - (-55)] / 1.5×10^-2

a = [45 + 55] / 0.015

a = 100 / 0.015

a = 6666.6666 m/s^2

a = 6700m/s^2 E

Since the value of acceleration is positive, the direction is towards the East (acceleration is in the direction of the ball's final Velocity).

Answer:

[tex]d_{2}[/tex] = 169 cm

Explanation:

Mass 1 = 45 kg   => Force = 450 N

Mass 2 = 29 kg   => Force = 290 N

According to principle of moments:

=> [tex]F_{1}d_{1} = F_{2}d_{2}[/tex]

Where [tex]F_{1}[/tex] = 450 N, [tex]d_{1}[/tex] = 109 cm and [tex]F_{2}[/tex] = 290 N

=> (450)(109) = 290[tex]d_{2}[/tex]

=> 49050 =  290[tex]d_{2}[/tex]

Dividing both sides by 290

=> [tex]d_{2}[/tex] = 169 cm

Answer:

85.0 please I don't understand

Given that,

Eccentricity = 0.0086

Suppose, The length of half of the major axis is [tex]1\times10^{9}\ km[/tex]

We need to calculate the distance from the center to the foci

Using formula of eccentricity

[tex]e=\dfrac{c}{a}[/tex]

[tex]c=e\times a[/tex]

Where, e = eccentricity

a = major axis

c = the distance from the center to the foci

Put the value in to the formula

[tex]c=0.0086\times1\times10^{9}[/tex]

[tex]c=8600000[/tex]

We need to calculate the perihelion distance of Neptune from the sun

Using formula of distance

[tex]d=a-c[/tex]

Put the value into the formula

[tex]d=1\times10^{9}-0.0086\times10^{9}[/tex]

[tex]d=991400000\ km[/tex]

Hence, The perihelion distance of Neptune from the sun is 991400000 km.

Answer:

A. can never be efficient due to friction

HEY!!

Answer:

A. friction

Explanation:

Now if we obtain output work same as input energy then it is 100% efficient.

but this is only possible when we have no energy loss while it is not possible due to many reasons:

one of the main cause of energy loss is friction

A machine can never be 100% efficient because some work is always lost due to the lack of materials or equipment that would convert work by 100%. but so far, no machine has got 100% efficiency.

So when the machine are working there must be a friction between its working parts due to which the out-input energy is lost in different parts and hence we can never be 100% efficient machine.

HOPE IT HELPS!!

Answer:

Please INCLUDE a picture.

Explanation:

You did not include a picture, so there is no way to tell how the charges will interact with each other.

Please INCLUDE a picture.

The net force acting on q1 is 3.2 N to the right.

The force on q₁ due to q₂ is:

F1 = k * q₁ * q₂ / r²

where:

k is Coulomb's constant, which is 8.98755 × 10⁹ N m² C⁻²

q₁ is the charge of q₁, which is +2.0 × 10⁻⁵ C

q₂ is the charge of q₂, which is -4.0 × 10⁻⁵ C

r is the distance between q₁ and q₂, which is 0.1 m

Plugging in the values, we get:

F₁ = 8.98755 × 10⁹ N m² C⁻² * 2.0 × 10⁻⁵ C * -4.0 × 10⁻⁵ C / (0.1 m)²

= 6.4 N

The force on q₁ due to q₃ is:

F₂ = k * q₁ * q₃ / r²

where:

k is Coulomb's constant, which is 8.98755 × 10⁹ N m² C²

q₁ is the charge of q₁, which is +2.0 × 10⁻⁵ C

q₃ is the charge of q₃, which is -4.0 × 10⁻⁵ C

r is the distance between q₁ and q₃, which is 0.2 m

Plugging in the values, we get:

F₂ = 8.98755 × 10⁹ N m² C⁻² * 2.0 × 10⁻⁵ C * -4.0 × 10⁻⁵ C / (0.2 m)²

= 16 N

The net force on q₁ is the sum of F₁ and F₂:

Fnet = F₁ + F₂

= 6.4 N + 16 N

= 22 N

The net force on q1 is to the right because both F₁ and F₂ are to the right.

Net electric field

The net electric field acting on q1 is 3.2 N/C to the right.

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Answer:

Relative density is proportional to the frequency of a material's density to its water density. Because both have had the same proportions, their proportion is also dimensionless.

Explanation:

The dimension of relative density:-

Relative Density of a Substance (R.D.) = Substance Density / Water Density.

Therefore, R.D. Is just a ratio or a number. There are no units or dimensions to it.

For example:- The density of iron is 8.5 GM's/cm^3 & the density of water is 1 gm/cm^3 (in cgs units).

Tension:-   Surface tension is the propensity of the new worlds and infographics to reduce to the particle size which is least appropriate. Atmospheric pressure helps insects (e.g. water striders) can travel or move and on a water surface, typically object is sensed rather than water.

Answer:

[tex]m=35.58 kg[/tex]

Explanation:

Using the first Newton's equation

[tex]\Sum F_{T}=F-mgsin(25)-\mu mgcos(25)=0[/tex]

We just need to solve it for m:

[tex]m=\frac{F}{g(sin(25)+\mu cos(25))}[/tex]

[tex]m=\frac{350}{9.81(sin(25)+0.64cos(25))}[/tex]

[tex]m=35.58 kg[/tex]

I hope it helps you!

Answer:

total number of modes is 8

Explanation:

attached here is the calculations