A 6.5 kg rock thrown down from a 120m high cliff with initial velocity 18 m/s down. Calculate
the following using the energy/work formulae only:
1.The kinetic energy at the top of the cliff
2.The total mechanical energy at the top of the cliff
3.The kinetic energy of the Rock half way down 4.the speed of the Rock half way down
5.The speed of the Rock as it hits the ground​

Answers

Answer 1

Answer:

this is the answer......

A 6.5 Kg Rock Thrown Down From A 120m High Cliff With Initial Velocity 18 M/s Down. Calculatethe Following

Related Questions

can i eat air? im hungry

Answers

Answer:

Yes

Explanation:

50 j of work was performed in 20 seconds. How much power was used to preform this task

Answers

Answer:

Power = 2.5 [W]

Explanation:

To be able to solve this problem we must remember that power is defined as the relationship of the work done in a given time interval.

[tex]P=W/t[/tex]

where:

P = power [W] (units of watts)

W = work = 50 [J]

t = time = 20 [s]

Now replacing:

[tex]P=50/20\\P=2.5[W][/tex]

Answer:

2.5

Explanation:

The winter solstice, the shortest day of the year in the Northern hemisphere, occurs when the Earth is in which position?

Answers

Answer:

A

Explanation:

a projectile is shot horizontally from the edge of a cliff, 230m above the ground. the projectile lands 300m from base of the cliff​

Answers

Answer:

The time taken by the projectile to hit the ground is 6.85 sec.

Explanation:

Given that,

Vertical height of cliff = 230 m

Distance = 300 m

Suppose, determine the time taken by the projectile to hit the ground.

We need to calculate the time

Using second equation of motion

[tex]s=ut+\dfrac{1}{2}gt^2[/tex]

Where, s = vertical height of cliff

u = initial vertical velocity

g = acceleration due to gravity

Put the value in the equation

[tex]230=0+\dfrac{1}{2}\times9.8\times t^2[/tex]

[tex]t=\sqrt{\dfrac{230\times2}{9.8}}[/tex]

[tex]t=6.85 sec[/tex]

Hence, The time taken by the projectile to hit the ground is 6.85 sec.

All motion will eventually stop due to the "loss" of energy to___.
a) friction and thermal energy
b) gravity
c) kinetic energy
d) potential energy

Answers

Gravity (b) is the answer
I think it is c) kinetic energy

1.
In the notation, 1s2, the number 1 represents the ________ __________ where electrons are located.
energy level
outer shell
2.
The four parts, or blocks, on the periodic table are _____, _____, d, and f.
s, p
a, b
3.
The 2 in 1s2 represents the number of __________ located in that energy level.
electrons
protons

Answers

Answer:

energy level

s,p

electrons

Explanation:

I already done this trust me

In the notation 1 s² number 1 represents energy levels where electrons are located.The 4 parts on periodic table are s,p,d and f blocks.The 2 in 1 s² represents number of electrons in energy level.

What is an energy level?

Electrons present in an atom revolve in different orbits which are stationary states and are also called as energy levels. The energy levels are numbered as integers which are also called as principal quantum numbers.

Energy of the stationary state is given as E= -R

1/n² where R

is the Rydberg's constant. When an electron is excited, and it moves from lower to higher energy levels there is absorption of energy, while when it moves from higher energy level to lower energy level it radiates or gives out energy in the form of radiation.

They can also be defined as the distances between electron and nucleus of an atom . Electrons present in K energy level have least energy .Energy level diagrams are studied to understand nature of bonding , placement of electrons in orbits and and elemental behavior under certain conditions.

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Suppose that a single guitar player makes noise at 70 dB. If two guitar players play at the same time, the noise level will be approximately 73 dB. How many guitar players will it take for the sound intensity level to be 100 dB

Answers

Answer: it will take 1000 guitar players for sound intensity level to be 100 dB

Explanation:

Given that;

noise level of a single player = 70 dB

Intensity of one guitar will be;

SL= 10 × log(I/I₀)

where I₀ is hum threshold intensity = 10⁻¹² W/m²

I is intensity of sound produced by 1 guitar

SL is intensity level of one guitar

so we substitute

70 = 10 × log(I/10⁻¹²)

70/10 = log (I/10⁻¹²)

I = 10⁻¹² × 10⁷

I = 10⁻⁵ W/m²  

now Suppose n guitars produce sound intensity of 100 dB, then intensity of n guitars (In) will be;

100 = 10 × log(In/10⁻¹²)

log(In/10⁻¹²)  = 100/10

In = 10⁻¹² × 10¹⁰ =  10⁻² Wm²

we know that Now intensity of 1 guitar I = 10⁻⁵ W/m²

so Intensity of n guitars will be;

n × I = In

n = In / I

we substitute

n = 10⁻² Wm² /  10⁻⁵ W/m²

n = 1000

Therefore, it will take 1000 guitar players for sound intensity level to be 100 dB

 

a car accelerate at 9 m/s squared. Assuming the car starts from rest how far will it travel in 10 seconds

Answers

Answer:

450m

Explanation:

[tex]s = ut + \frac{1}{2} a {t}^{2} \\ s = 0 + t + \frac{1}{2} a {t}^{2} \\ \frac{1}{2 } \times 9 \times {10}^{2} = 450m[/tex]

What are similarities between homogeneous mixture and
heterogeneous mixture

Answers

Answer:

they both are the mixture of substance

Answer:

a homogeneous mixture is a uniform mixture whose components appear to be in a single state while a heterogeneous mixture is non uniform mixture whose components remain separate

Explanation:

example of homogeneous_ water and ethanol

heterogeneous_ water and chalk

A 2.00 kg block on a horizontal floor is attached to a horizontal spring that is initially compressed 0.0300 m . The spring has force constant 815 N/m . The coefficient of kinetic friction between the floor and the block is μk=0.40. The block and spring are released from rest and the block slides along the floor.

Required:
What is the speed of the block when it has moved a distance of 0.0200 m from its initial position? (At this point the spring is compressed 0.0100 m.)

Answers

Answer:

v = 0.41 m/s

Explanation:

In this case, the change in the mechanical energy, is equal to the work done by the fricition force on the block.At any point, the total mechanical energy is the sum of the kinetic energy plus the elastic potential energy.So, we can write the following general equation, taking the initial and final values of the energies:

       [tex]\Delta K + \Delta U = W_{ffr} (1)[/tex]

Since the block and spring start at rest, the change in the kinetic energy is just the final kinetic energy value, Kf.⇒ Kf = 1/2*m*vf²  (2)The change in the potential energy, can be written as follows:

       [tex]\Delta U = U_{f} - U_{o} = \frac{1}{2} * k * (x_{f} ^{2} - x_{0} ^{2} ) (3)[/tex]

       where k = force constant = 815 N/m

       xf = final displacement of the block = 0.01 m (taking as x=0 the position

      for the spring at equilibrium)

      x₀ = initial displacement of  the block = 0.03 m

Regarding the work done by the force of friction, it can be written as follows:

       [tex]W_{ffr} = - \mu_{k}* F_{n} * \Delta x (4)[/tex]

       where μk = coefficient of kinettic friction, Fn = normal force, and Δx =

       horizontal displacement.

Since the surface is horizontal, and no acceleration is present in the vertical direction, the normal force must be equal and opposite to the force due to gravity, Fg:Fn = Fg= m*g (5)Replacing (5) in (4), and (3) and (4) in (1), and rearranging, we get:

        [tex]\frac{1}{2} * m* v^{2} = W_{ffr} - \Delta U = W_{ffr} - (U_{f} -U_{o}) (6)[/tex]

        [tex]\frac{1}{2} * m* v^{2} = (- \mu_{k}* m*g* \Delta x) -\frac{1}{2} * k * (x_{f} ^{2} - x_{0} ^{2} ) (7)[/tex]

Replacing by the values of m, k, g, xf and x₀, in (7) and solving for v, we finally get:

    [tex]\frac{1}{2} * 2.00 kg* v^{2} = (-0.4*2.00 kg*9.8m/s2*0.02m) +( (\frac{1}{2} *815 N/m)* (0.03m)^{2} - (0.01m)^{2}) = -0.1568 J + 0.326 J (8)[/tex]

[tex]v =\sqrt{(0.326-0.1568} = 0.41 m/s (9)[/tex]

Why is it important that an astronomer studies physics?

Answers

Physicists and astronomers conduct research to understand the nature of the universe and everything in it. These scientists observe, measure, interpret, and develop theories to explain celestial and physical phenomena using mathematics. From the vastness of space to the infinitesimal scale of subatomic particles, they study the fundamental properties of the natural world and apply the knowledge gained to design new technologies.

Answer:

Astrophysicists study the physics of the universe. “Astrophysics” is a term that is often used interchangeably with “astronomy.” Atomic, molecular, and optical physicists study atoms, simple molecules, electrons, and light, as well as the interactions among them

Explanation:

Which is an example of current electricity?

Answers

Examples are, starting a car, turning on a light, cooking on an electric stove, watching tv, shaving with an electric razor, playing video games, using a phone, and charging a cell phone, i found this information on www.electricityforum.com

The period of a pendulum is directly proportional to the mass of the bob.

true or false.

Answers

Answer:

false

Explanation:

i just took the test <3

The period of a pendulum is not directly proportional to the mass of the bob. The period of pendulum is independent of the mass of the bob. Thus, the given statement is false.

What is the period of pendulum?

A simple pendulum is the one which consists of a small metal ball called as the bob or a mass which is suspended from a fixed point by a long piece of thread such that the bob is free to swing back and forth from its mean position under the influence of the gravity.

The time period of a simple pendulum is the time taken by it to complete one oscillation. The formula for the time period or period (T) of a simple pendulum is T = 2π (√L/g), where L is the length of the pendulum thread and g is the acceleration due to gravity.

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PLEASE ANSWER ASAP BEFORE MY TEACHER AND MY MOM KILLES ME PLEASE ASAP

The first person with the right answer gets to be a brainlest

In the attachment there is a density column where there is colour

Question: tell me why is the red at the bottom of the density column if it is the least dense

Answers

Answer:

the red at the bottom should not count, but the red at the top is the least dense because it floats upon the other liquids

Explanation:

hope this helps

The kinetic energy of an object of mass 3.5 kg is 112 J. Its speed is?
64 m/s
8.0 m/s
5.67 m/s
6.8 m/s

Answers

5.67 is the correct answer




That’s the correct answer on edg

2. A 60 kg diver jumps off a diving board with a height of 10
meters and accelerates toward the ground. At the point shown
in the diagram, she has 1,764 Joules of gravitational energy
and 4,116 Joules of kinetic energy. What is the diver's total
mechanical energy at that point?

Answers

Answer:5,880

Explanation:Lol if I get this wrong sorry I’m trying to do this also but if you add the 1,764 joules and 4,116 joules in total if you add them all up it’ll give you 5,880 hope that helps.

For each of the situations described below, the object considered is undergoing some changes. Among the possible changes you should consider are:

(Q) The object is absorbing or giving off heat.
(T) The object's temperature is changing.
(E) The object's thermal energy is changing.
(W) The object is doing mechanical work or having work done on it.
(C) The objects chemical energy is changing.

For each of the two situations, identify which of the five changes is taking place, indicating the applicable letters Q T U W C (or none) as appropriate while providing your reasoning.

a. An ice cube sits in the open air and is melting.
b. A cylinder with a piston on top contains a compressed gas and is sitting on a thermal reservoir (a large iron block that can provide or take thermal energy as the system needs). After everything has come to thermal equilibrium, the piston is moved upward somewhat (very slowly). The object to be considered is the gas in the cylinder.

Answers

Answer: a. (Q), (T), (E)

              b. (Q), (T), (E), (W)

Explanation: Thermal Energy and Temperature are closely related: when the temperature rises causing atoms or molecules to move, thermal energy is produced. Thermal energy is the energy within the system.

Mechanical Work is the amount of energy transferred due to an applied force.

Chemical Energy is the energy contained in the bonds of chemical structures of the molecules released when a chemical reaction happens.

Given the explanations, let's analyse the situations:

a. For an ice cube to be melting, it has to be absorbing heat, which means its thermal energy is changing and, consequently, so does its temperature;

b. First, the gas inside the cylinder reaches a thermal equilibrium, which means its thermal energy and temperature changed. Since there were  exchange of heat to reach the equilibrium, the gas absorbed or gave off heat. After the equilibrium, when the piston starts to be moved, the energy of the pressure is transferred to the gas, so mechanical work had been done.

Chirag, a champion weightlifter, raises 259 kg of weights a distance of 2.40 m. How much work is done by Brutus lifting the weights?

622 J
6090 J
2540 J
0 J

How much work is done by Chirag holding the weights above his head?
622 J
6090 J
2540 J
0 J

Answers

1.

6090 J

2.

622 J

I bet so~

The answers are
1.6090j
2.622j

Which heat related illness requires immediate medical attention

Answers

Answer:

Heat stroke

Explanation:

Heat Stroke is the most serious heat-related illness and requires immediate medical attention.

Answer:

Heat Stroke is the most serious heat-related illness and requires immediate medical attention. Symptoms include: confusion, fainting, seizures, very high body temperature and hot, dry skin or profuse sweating. CALL 911 if a coworker shows signs of heat stroke.

Explanation:

I HOPE THIS HELPS * pls mark me brainliest }

A helium-neon laser (λ = 633 nm) illuminates a single slit and is observed on a screen 1.50 m behind the slit. The distance between the first and second minima in the diffraction pattern is 3.75 mm .

Required:
What is the width (in mm) of the slit?

Answers

Answer:

d = 0.25 mm

Explanation:

The position that the Minimal fall in single silt diffraction pattern can be written as

y=λmD/d ..........eqn(1)

(y2 - y1 )= difference of y that exist between first and second minima

D= distance of slit from the screen=1.50m

d= width of the slit

λ= 633 nm = 633×10^-9m

y= position of pth minimal

eqn(1) can be written as

(y2 - y1)= λmD/d .........eqn(2)

If we substitute the given values we have

(y2 - y1 )= [ (2×633×10^-9 × 1.50) /d] -[ (1×633×10^-9 × 1.50) /d]

Simplyfying

(y2 - y1)=(9.495×10^-7)/d

But The distance between the first and second minima in the diffraction pattern = 3.75, which implies that (y2 - y1) = 3.75mm=

✓ we can substitute (y2 - y1)= 3.75mm=3.75 ×10^-3 into expression above

3.75 ×10^-3 =(9.495×10^-7)/d

The we can make "d" subject of the formula

d=(9.495×10^-7)/ (3.75 ×10^-3)

d=0.00025m

d=0.25×10^-3 m

d=0.25 mm

Hence, the width (in mm) of the slit is 0.25mm

Define specific charge of an electron. Write its value.​

Answers

Answer:

The specific charge is defined as a charge by mass ratio i.e e/m. The charge on an electron (e) = 1.602 X 10-19C. The mass of the electron (m) = 9.1×10−31Kg.

Various radial points on a rotating Ferris wheel have: I. different linear velocities II. different angular velocities III. equal linear velocities IV. equal angular velocities

Answers

Answer:

I) True,  II) False,  III) False,  IV) True    

Explanation:

In this exercise, it is asked to answer different statements, for this we will use the relationship between angular and linear velocity

           v = w r

let's review the claims

I) True. From the initial equation we see that the linear velocity depends on the radius

II) False. All points rotate with the same angular velocity

III) False. Linear velocity changes with radius

IV) True. The angular velocity of all points is the same

At various radial points on a rotating Ferris wheel have, different linear velocity (True), different angular velocity (false), equal linear velocity (false) and equal angular velocity (True).

The angular velocity of a rotating Ferris is calculated as follows;

[tex]\omega = \frac{v}{r} = 2\pi N[/tex]

The linear velocity of a rotating Ferris is calculated as follows;

v = ωr

where;

v is the linear velocityr is the radius of the Ferrisω is the angular velocity

The linear velocity increases with increase in radius.

Thus, we can conclude that, at various radial points on a rotating Ferris wheel have;

different linear velocitiesconstant angular velocity

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A 0.500-kg object connected to a light spring with a spring constant of 20.0 N/m oscillates on a frictionless horizontal surface. (a) Calculate the total energy of the system and b) the maximum speed of the object if the amplitude of the motion is 3.00 cm. (c) Compute the kinetic and potential energies of the system when the displacement is 2.00 cm

Answers

Answer:

a = 0.009 J

b = 0.19 m/s

c = 0.005 J and 0.004 J

Explanation:

Given that

Mass of the object, m = 0.5 kg

Spring constant of the spring, k = 20 N/m

Amplitude of the motion, A = 3 cm = 0.03 m

Displacement of the system, x = 2 cm = 0.02 m

a

Total energy of the system, E =

E = 1/2 * k * A²

E = 1/2 * 20 * 0.03²

E = 10 * 0.0009

E = 0.009 J

b

E = 1/2 * k * A² = 1/2 * m * v(max)²

1/2 * m * v(max)² = 0.009

1/2 * 0.5 * v(max)² = 0.009

v(max)² = 0.009 * 2/0.5

v(max)² = 0.018 / 0.5

v(max)² = 0.036

v(max) = √0.036

v(max) = 0.19 m/s

c

V = ±√[(k/m) * (A² - x²)]

V = ±√[(20/0.5) * (0.03² - 0.02²)]

V = ±√(40 * 0.0005)

V = ±√0.02

V = ±0.141 m/s

Kinetic Energy, K = 1/2 * m * v²

K = 1/2 * 0.5 * 0.141²

K = 1/4 * 0.02

K = 0.005 J

Potential Energy, P = 1/2 * k * x²

P = 1/2 * 20 * 0.02²

P = 10 * 0.0004

P = 0.004 J

The total energy of the system is 0.009 J

The maximum speed of the object is 0.19 m/s

The kinetic and potential energies of the system when the displacement is 2.00 cm are 0.005 J and 0.004 J respectively

The object is under simple harmonic motion.

Given that the mass of the object m =0.5 kg , spring constant k = 20N/m

(a) The total energy of the system in SMH,

[tex]E=\frac{1}{2}kA^2[/tex]

If the amplitude of motion A = 3cm = 0.03m, then total energy

[tex]E=\frac{1}{2}*20*0.03*0.03 J\\\\E = 0.009J[/tex]

E = 0.009J is the total energy of the system.

(b) maximum speed of the object

the maximum kinetic energy of the object = total energy of the object

[tex]\frac{1}{2} m(v_{max})^{2} =E\\\\v_{max}=\sqrt{2E/m}\\\\v_{max}=\sqrt{2*0.009/0.5}\\\\v_{max}=0.19m/s[/tex]

0.19 m/s is the maximum speed

(c) KE and PE when x = 2cm = 0.02m

potential energy at x = 0.02

[tex]PE=\frac{1}{2}kx^2\\\\PE=\frac{1}{2}*20*0.02*0.02\\\\PE= 0.004J[/tex]

Now, Kinetic energy + potential energy = total energy

KE + PE = E

KE = E - PE

KE = 0.009J - ).004J

KE = 0.005J

The kinetic and potential energies are 0.005 J and 0.004 J respectively.

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A car is traveling due north at 23.6 m>s. Find the velocity of the car after 7.10 s if its acceleration is (a) 1.30 m>s2 due north, or (b) 1.15 m>s2 due south.

Answers

Answer:

a) v = 32.8 m/s

b) v= 15.4 m/s

Explanation:

a)

Applying the definition of acceleration (assumed to be constant), we can write the following expression for the velocity v:

        [tex]v = v_{o} + a*t (1)[/tex]

        where v₀ is the initial velocity and a is the acceleration, being t the

       time elapsed.

In the case a) the acceleration and the velocity vectors have both the same direction (due north), so both have the same sign, which means that the car is speeding up.Replacing by the givens v₀ and t in (1), we get:

       [tex]v = 23.6 m/s + (1.30 m/s2 * 7.10 s) = 32. 8 m/s (2)[/tex]

b)  

In this case, the acceleration vector and the velocity vector have opposite directions, so the car slows down, due to both vectors have opposite signs.Replacing by the givens in (1) and taking into account the signs, we get:

       [tex]v = 23.6 m/s + ((-1.15 m/s2) * 7.10 s)) = 15. 4 m/s (3)[/tex]

A rock moving in the +x-direction with speed 16.0 m/s has a net force applied to it at time t = 0, and this produces a constant acceleration in the −x-direction that has magnitude 4.00 m/s2. For what three times t after the force is applied is the rock a distance of 24.0 m from its position at t = 0?

Answers

Answer: The rock is (24m) away from the origin at t = 2 s, t = 6 s, and t = 9.29 s

You are assigned the design of a cylindrical, pressurized water tank for a future colony on Mars, where the acceleration due to gravity is 3.71 meters per second per second. The pressure at the surface of the water will be 150 KPa , and the depth of the water will be 14.4 m . The pressure of the air in the building outside the tank will be 88.0 KPa .
Find the net downward force on the tank's flat bottom, of area 2.15 m2 , exerted by the water and air inside the tank and the air outside the tank.

Answers

Answer: F = 6262.2 kN

Explanation: Pressure is defined as force per area. But pressure varies according to the depth of a fluid: in air, it decreases the higher the altitude, while in water, it increases the deeper you go.

So, at the bottom of the tank, besides the pressure of air inside the tank and air outside the tank, there is pressure of water due to its depth.

Pressure due to the depth is calculated as

                                    [tex]P=h.\rho.g[/tex]

h is the depth in m

ρ is density of the fluid, in this case is water, so ρ = 997 kg/m³

g is acceleration due to gravity, which, in this case, is 3.71 m/s²

Then, pressure at the bottom of the tank due to variation in depth is

[tex]P=14.4(997)(3.71)[/tex]

P = 53263.73 Pa or 53.26 kPa

Assuming positive referential is downward, all pressures at the bottom point down, so total or resultant pressure is:

[tex]P_{r}=P_{1}+P_{2}+P_{3}[/tex]

[tex]P_{r}=150+88+53.26[/tex]

[tex]P_{r}=[/tex] 291.26 kPa

At last, pressure is force per area:

[tex]P=\frac{F}{A}[/tex]

[tex]F=P.A[/tex]

[tex]F_{r}=P_{r}.A[/tex]

[tex]F_{r}=291.26.10^{3}(2.15)[/tex]

[tex]F_{r}=[/tex] 626209 N or 626.2 kN

At the cylindrical tank's flat bottom, net force has magnitude 626.2 kN.

Two resistors, A and B, are connected in parallel across of a 6V battery. The current through B is found to be 2.0 A. When the two resistors are connected in series to the 6V battery, a voltmeter connected across the resistor A measures a voltage of 4V. Find the resistances of A and B.

Answers

Answer:

Resistance of A is [tex]6\ \Omega[/tex] and B is [tex]3\ \Omega[/tex]

Explanation:

The voltage across both the resistances will be the same as they are connected in parallel.

V = Voltage = 6 V

[tex]I_B=2\ \text{A}[/tex]

Resistance is given by

[tex]R_B=\dfrac{V}{I_B}\\\Rightarrow R_B=\dfrac{6}{2}\\\Rightarrow R_B=3\ \Omega[/tex]

[tex]V_B=V_b-V_A\\\Rightarrow V_B=6-4\\\Rightarrow V_B=2\ \text{V}[/tex]

Series connection

[tex]V_A=4\ \text{V}[/tex]

The current is constant in series connection

[tex]I=\dfrac{V_B}{R_B}\\\Rightarrow I=\dfrac{2}{3}\ \text{A}[/tex]

[tex]R_A=\dfrac{V_A}{I}\\\Rightarrow R_A=\dfrac{4}{\dfrac{2}{3}}\\\Rightarrow R_A=6\ \Omega[/tex]

The resistance of A is [tex]6\ \Omega[/tex] and B is [tex]3\ \Omega[/tex].

Can someone please help?

Answers

Answer:

1: E

2: A

3: C

4: B

5: D

Explanation:

Which property of a solid measures how resistant the material is to deformation?

A. Elasticity

B. Hardness

C. Plasticity

D. resilience

Answers

Answer: the answer is a

Explanation:

What happens to the molecules of a substance when it changes phase?

Answers

Energy is required to change the phase of a substance, such as the energy to break the bonds between molecules in a block of ice so it may melt. During a phase change energy my be added or subtracted from a system, but the temperature will not change.

When it comes to phase shifts or phase change the greater the intermolecular interactions are the closer the molecules are to one another.

What is phase change?A phase change occurs when matter transitions from one state to another (solid, liquid, gas, plasma). When enough energy is provided to the system (or when a significant quantity is removed), as well as when the pressure on the system is adjusted, these changes occur.Any two phases of matter can undergo phase transitions.All phase shifts are accompanied by an energy shift.Isothermal phase shifts occur in all cases.Temperature changes can cause substances to change phase often. Most substances are solid at low temperatures; as the temperature rises, they become liquid; and at even higher temperatures, they become gaseous.

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4. Chrissy had 4 gallons of gas in her tank when she arrived at thegas station. She pumped gas into her car at a rate of 0.3 gallon persecond. How many gallons of gas were in the tank after s seconds? If the setting of a story is a deserted soccer field, which character most closely connects with this setting? A protagonist who is trying to find a way to help his sick neighbor A protagonist who is fighting against robots that are taking over a city A protagonist who has no real friends to count on A protagonist who time travels to the middle of a futuristic city Lin and Elena have discovered they have so much in common. They each have a fish tank holding 20 units of water. Whose tank holds 20 gallons, and whose holds 20 cups? help please! i just need the activity on the bottom I need help on this question. if you are the first one to git it right you will be brainly Rahul drives his car and travels 10Km in 12mins. What is the distance covered by him in 1 hour?Pls answer quick I have an exam tomm I need answer for this questionFirst helpful answer will be marked as brainliest Regards,Me Most people in cities get their water ___ Helppp I will make you a brainlist The modernist literary period in America is characterized byDisillusionmentPrideHopeOptimism Hello! Please answer this question with all of the info it is asked for. Please be sure to include all of your work and share any of your thoughts you had when solving. Please do not answer unless you know the answer. Thanks! Good Luck!A football is kicked straight up into the air from 3 feet above the ground with an initial velocity of 208 ft/s. The function that models the ball's height is: h(t) = -16t^2 + 208t + 3.a) Find how long it takes for the football to reach its maximum height.b) Determine how long the football was in the air (approximately). Why might this not quite be accurate?c) Determine the maximum height of the football. Match the instrument with the correct family.Shakera. BrassTromboneb. PercussionSaxophonec. WoodwindCellod. StringRespond to the following based on your reading.Kenney plays a melody on his bagpipe. One pipe on the bagpipe plays a single continuous note. Whats that note called?The first electronic instrument was invented by a German physicist in which century?Some percussion instruments have definite pitch, which means they produce notes that could be used to play melodies. Others are said to have _________.The grand piano is a member of what instrument family?How many players are in a string quartet? Please help!!Each pair of polygons is similar. Find the value of x. On January 1, 2024, Bear Cove Co. issued its 11% bonds in the face amount of $3,000, which mature on January 1, 2034. The bonds were issued for $3,385 to yield 9%. Bear Cove uses the effective-interest method of amortizing the bond premium. Interest is payable annually on December 31. The 12/31/24 bond carrying value is approximately: what is one possible combination that can be found in the gamete formed by an individual with the genotype AaBB? what was on of the main effects of the black death in europe In the coordinate plane, which of the following functions dilates by a factor of 3about the point (9, 6)?A. (, ) = (3 + 9, 3 +6)B. (, ) = (3( + 9), 3( + 6))C. (, ) = (9+ 3( 9), 6 + 3( 6))D. (, ) = (9+ 3(9 ), 6+ 3(6 )) What is the equation of the line that contains the points(-5,0) and (0,6) ? #5) What is the slope of the line that passes through the points (6, -8) and (4,10)?A)1/3B)-1/9C) - 9D) -1 PLEASE HELP I'M BEING TIMES!! (UNIT RATE!!!!!)Find the unit rate if 6 chocolate chip cookies have 426 calories. Show the answer in fraction and word form.a.There are 71 calories per cookie.b.There is 1 calorie per 71 cookies.c.There are 61 calories per cookie.d.There are 426 calories per 6 cookies. Coffee costs $1.75 a pound. How much would 3.2 pounds of coffee cost?