A 2,100-kg pile driver is used to drive a steel beam into the ground. The pile driver falls 5.00 m before coming into contact with the top of the beam, and it drives the beam 12.0 cm farther into the ground before coming to rest. Using energy considerations, calculate the average force the beam exerts on the pile driver while the pile driver is brought to rest.

Answer:

1120 N

Explanation:

The velocity with which he hits the water can be found with kinematics:

v² = v₀² + 2aΔy

v² = (0 m/s)² + 2 (-9.8 m/s²) (-9.00 m)

v = -13.3 m/s

Or it can be found with conservation of energy.

PE = KE

mgh = ½ mv²

v = √(2gh)

v = √(2 × -9.8 m/s² × -9.00 m)

v = -13.3 m/s

Sum of forces on the diver after he hits the water:

∑F = ma

F − mg = m Δv/Δt

F − (74.0 kg) (9.8 m/s²) = (74.0 kg) (0 m/s − (-13.3 m/s)) / (2.50 s)

F = 1120 N

Answer:

i took g = 9.8m/s

A. 1.16secs

B. 2.32secs

C. 6.57m

D. 57.91m

Explanation:

A. How long does the Missile take to reach ot peak?

Time taken (t) =( U²Sin (angle) )/g

u = initial velocity = 25m/s

angle given = 30°

g = acceleration due to gravity = 9.8m/s²

t = U² x Sin (angle) / g

t = 25² x Sin(30)/9.8

t = 1.61secs

B. How long is the missile in the air in total?

T = 2t

T = 2 x 1.61 = 2.32 secs

C. what maximum Height does the missile reach?

D. How far does the missile travel Horizontally?

Answer:

I = 2.61 A

Explanation:

It is given that,

Power of a toaster is 300 watts

It is plugged into an outlet with a voltage of 115 volts

We need to find the current in the toaster's circuit.

The electrical power is given by the formula as follows :

P = V I

I is electric current

[tex]I=\dfrac{P}{V}\\\\I=\dfrac{300}{115}\\\\I=2.61\ A[/tex]

So, 2.61 A of current is in the toaster's circuit.

Answer: D.

2.61 amps

Explanation: edmentum

Explanation:

[tex]a = \frac{change \: in \: velocity}{change \: in \: time} [/tex]

[tex]a = \frac{v - u}{t} [/tex]

[tex]v = 7 {ms}^{ - 1} [/tex]

[tex]u = 15 {ms}^{ - 1} [/tex]

[tex]t = 3 \: seconds[/tex]

[tex]a = \frac{7 - 15}{3} [/tex]

[tex]a = \frac{ - 8}{3} [/tex]

[tex]a = - 2.67 \: {ms}^{ - 2} [/tex]

Answer: The final Velocity, V, of the car is 7.9m/s

Explanation:

Given the following :

Toy car starts from rest, therefore,

Initial Velocity (u) = 0

Acceleration (a) = 1.5m/s^2 E for time, t = 5.25s

Final velocity (V) of the car =?

Using the motion equation:

v = u + at

Where v = final Velocity

u = Initial Velocity

a = acceleration

t = time

v = 0 + 1.5(5.25)

v = 0 + 7.875

v = 7.875m/s

v = 7.9m/s

Answer:

The common groundwater contaminant are fertilizers.

Explanation:

Answer:

The answer would be D( Fertilizers)

Explanation:

A fertilizers or fertilizer is any material of natural or synthetic origin that is applied to soil or to plant tissues to supply one or more plant nutrients essential to the growth of plants. Many sources of fertilizer exist, both natural and industrially produced.

This question is incomplete because the options are missing; here is the complete question:

Study the image of the Earth's layer which statement correctly compares the thicknesses of earths layers

A. Earth’s mantle is thinner than its oceanic crust.

B. Earth’s outer core is thicker than its mantle.

C. Earth’s continental crust is thicker than its lithosphere.

D. Earth’s lithosphere is thinner than its asthenosphere.

The answer to this question is D. Earth’s lithosphere is thinner than its asthenosphere.

Explanation:

The image shows the different layers that are part of Earth, as well as the thickness of each layer, in kilometers. In this, the thickest layer is the Mantle that is almost 2900 kilometers; this is followed in thickness by the outer and the inner core.

Additionally, other layers such as the continental/oceanic crust, the asthenosphere, and the lithosphere that are near the surface are thinner. About this, it can be concluded the lithosphere is thinner than the asthenosphere because the lithosphere has a thickness of 100 km, while the asthenosphere thickness is 660km. This makes option D the correct.

Answer: B. Carbon dioxide and water

Explanation: Combustion simply refers to burning. A combustion reaction may thus be explained as a chemical process which involves the reaction between a substance and an oxidizer usually oxygen gas. The combustion reaction in most cases involves the reaction between hydrocarbons which are combustible compounds and oxygen gas. The reaction between the combustible compound and oxygen gas is then followed by the release of energy, with the product being carbondioxid and water. Below is an example of combustion reaction.

Combustion the Methane CH4.

Here, CH4 reacts with oxygen gas(O2) to produce carbondioxide and water.

CH4 + 2O2 ------> CO2 + 2H2O

Answer:

Correct answer B

Explanation:

Just took quiz

Answer:

28.39 g

Explanation:

D= m ÷ v

So, M= D × V

0.835 × 34= 28.39

Answer:

C. 28.39 g

Explanation:

took the test<3

Answer:

4.489 m/s

Explanation:

We are given;

Length of rod;L = 51.4 cm = 0.514 m

When the ball is at the top end, it's velocity will be zero and it's kinetic energy will be transformed to potential energy.

Thus; ½mv² = mgh

m will cancel out to give;

v² = 2gh

Where:

g is acceleration due to gravity = 9.8 m/s²

h is the maximum height of the ball which is equal to twice the length of the rod.

Thus, h = 2(0.514) = 1.028 m

v² = 2 × 9.8 × 1.028

v = √20.1488

v = 4.489 m/s

Copper is a reddish orange, soft metal with a bright metallic luster. It is an excellent conductor of heat and electricity. Copper surfaces when exposed to air gradually turns to a dull, brownish color.

Given that,

Weight = 0.75 N

Acceleration due to gravity = 9.81 m/s²

Density of water = 1 g/ml

We need to calculate the volume of water

Using formula of weight

[tex]W=mg[/tex]

[tex]W=\rho Vg[/tex]

[tex]mg=\rho\times V\times g[/tex]

Where, V = volume

g = acceleration

m = mass

Put the value into the formula

[tex]0.076\times 9.8\times10^3=1\times V\times9.8[/tex]

[tex]V= \dfrac{0.076\times 9.8\times10^3}{1\times9.8}[/tex]

[tex]V=76\ ml[/tex]

Hence, The volume of water is 76 mL.

Answer:

76.5mL

Explanation:

w = mg

0.75N = m * 9.81

m = 0.75 / 9.81 = 0.0765 kg

The mass in grams is 0.0765 * 1000 = 76.5g

At a density of 1 g/mL,

76.5g ÷ 1g/ml = 76.5mL

Answer:

The temperature at the top is -39.5 degree

Explanation:

The height of Mt Everest = 8850 m

The base is at the elevation of = 5400 m

The drop in temperature = 1 degree per 100 m

At the base, the temperature = -5

Since every 100 meter rise in height results in the one degree drop of temperature. Therefore, first find the difference between the base and height. Multiply with negative one.

Difference in heights = 8850 – 5400 = 3450

The temperature at the top = (3450 / 100) + 5 = -39.5 degree

Since there is fall in temperature so we use negative sign.

Answer:

n = 3.1x10¹²

Explanation:

To find the number of electrons we need to find first the charge (q):

[tex] I = \frac{q}{\Delta t} \rightarrow q = I*\Delta t [/tex]    (1)

Where:

I: is the electric current = 0.59 A

t: is the time

The time t is equal to:

[tex]v = \frac{\Delta x}{\Delta t} \rightarrow \Delta t = \frac{\Delta x}{v}[/tex]   (2)

Where:

x: is the displacement

v: is the average speed = 2.998x10⁸ m/s

The displacement is equal to the perimeter of the circumference:

[tex] \Delta x = 2\pi*r = \pi*d [/tex]     (3)

Where d is the diameter = 80.0 m

By entering equations (2) and (3) into (1) we have:

[tex]q = I*\Delta t = I*\frac{\Delta x}{v} = \frac{I\pi d}{v} = \frac{0.59 A*\pi*80.0 m}{2.99 \cdot 10^{8} m/s} = 4.96 \cdot 10^{-7} C[/tex]      

Now, the number of electrons (n) is given by:

[tex] n = \frac{q}{e} [/tex]

Where e is the electron's charge = 1.6x10⁻¹⁹ C  

[tex] n = \frac{q}{e} = \frac{4.96 \cdot 10^{-7} C}{1.6 \cdot 10^{-19} C} = 3.1 \cdot 10^{12} [/tex]

Therefore, the number of electrons in the beam is 3.1x10¹².

I hope it helps you!

Answer:

decrease

Explanation:

as the mass of the cart increase the acceleration of the cart decrease

Answer:

86.17m/s

Explanation:

Since the motion is of constant acceleration, we can use one of the equations of motion as follows;

v² = u² + 2as

Where;

v = final velocity of the airplane

u = initial velocity of the airplane

s = distance covered by the plane

a = acceleration

From the question,

u = 15m/s

s = 600m

a = 6m/s²

Substitute these values into the equation above as follows;

v² = 15² + 2(6)(600)

v² = 225 + 7200

v² = 7425

v = √7425

v  = 86.17m/s

Therefore, the final velocity of the airplane is 86.17m/s

Explanation:

If Team A is on the left, B is on the right

if the force is constant, it means that the effort applied is equal.

So Team B is pulling 5000N to the right.

Answer:

Explanation:

Kinetic energy is 1/2mv²

where m is the mass of the object

v is the velocity

From the question

m = 200kg

v = 2.7m/s

Kinetic energy is

1/2 × 200 × 2.7²

= 729 Joules

Hope this helps you

Answer: 1.44m/s West

Explanation:

Given the following :

Mass of skater = 60kg

Average force = 240N east

Time of = 0.360 seconds

The Velocity after 0.360seconds

Recall the relation:.

Force(f) * time(t) = mass (m) * (final Velocity(V) - initial velocity(u))

Where ; final Velocity(v) - initial velocity(u) = Magnitude of velocity(V)

Ft = mV

240 × 0.360 = 60 × V

60 × V = 86.4

V = 86.4 / 60

V = 1.44m/s

According to Newton's third law, to every action, there is an equal and opposite reaction.

The action force acts in the eastern direction hitting the wall with a force of 240N, therefore direction after hitting the wall will be in the opposite (western direction) direction, which is the direction of the reaction force

Therefore, velocity is 1.44ms West

Answer:

Joule

Explanation:

As any unit of energy (kinetic, potential, etc.), the gravitational potential energy has SI units of Joule. This s the work done by a force of 1 Newton to displace an object 1 meter in the direction of application of the force.

Answer:

  D. 3.0 × 10^-6 m

Explanation:

Wavelength is found by dividing the speed of light by the frequency:

  λ = c/f = (3·10^8 m/s)/(1.0·10^14 Hz) = 3.0·10^-6 m

Answer:

1.01 W/m

Explanation:

diameter of the pipe d = 30 mm = 0.03 m

radius of the pipe r = d/2 = 0.015 m

external air temperature Ta = 20 °C

temperature of pipe wall Tw = 150 °C

convection coefficient at outer tube surface h = 11 W/m^2-K

From the above, we assumed that the pipe wall and the oil are in thermal equilibrium.

area of the pipe per unit length A = [tex]\pi r ^{2}[/tex] = [tex]7.069*10^{-4}[/tex] m^2/m

convectional heat loss Q = Ah(Tw - Ta)

Q = 7.069 x 10^-4 x 11 x (150 - 20)

Q = 7.069 x 10^-4 x 11 x 130 = 1.01 W/m

The heat loss per unit length of tube should be considered as the 1.01 W/m.

Since

diameter of the pipe d = 30 mm = 0.03 m

radius of the pipe r = d/2 = 0.015 m

external air temperature Ta = 20 °C

temperature of pipe wall Tw = 150 °C

convection coefficient at outer tube surface h = 11 W/m^2-K

Now

area of the pipe per unit length A should be

= πr^2

 = 7.069*10^-4 m^2/m

Now

convectional heat loss Q = Ah(Tw - Ta)

Q = 7.069 x 10^-4 x 11 x (150 - 20)

Q = 7.069 x 10^-4 x 11 x 130

= 1.01 W/m

hence, The heat loss per unit length of tube should be considered as the 1.01 W/m.

Learn more about heat here: https://brainly.com/question/15170783

Answer:

Displacement

Explanation:

Displacement is a vector quantity i.e it has both magnitude and direction. The direction is indicated with compass bearing i.e North, South, East or West or you could have North East, North West, South West, South East.

Light bends away from the normal, because it's moving from higher to lower refractive index.

Same bend-direction as when it goes from water into air.

Answer and Explanation:

Given that

v_f = 5 km/s = 5,000 m/s

d = 4 m

v_i = 0 m/s

The computation is shown below:

1. The acceleration in m/s is

Here we use the motio third equation which is

[tex]v_f^2 = v_i^2 + 2ad[/tex]

5000^2 = 0^2 + 2 (a) (4)

So

[tex]a = 3.125 \times 10^{6} m/s^2[/tex]

2. Now acceleration in g is

[tex]= \frac{3.125 \times 10^{6} m/s^2}{9.81}[/tex]

[tex]= 3.18 \times 10^{5}g[/tex]

3. The long of acceleration last is

[tex]t = \frac{v-u}{a}[/tex]

[tex]= \frac{5000 - 0}{3.125 \times 10^{6}}[/tex]

[tex]= 1.6 \times 10^{-3}s[/tex]

4.As we can see that

[tex]3.18 \times 10^{5}[/tex] is smaller than the [tex]4.5 \times 10^{5}g[/tex]

So, it should not be ruled out

Answer:

By nuclear fission

Explanation:

The sun generates enormous energy through the process of nuclear fusion.

The core or the innermost part of the sun is characterized by high temperature and pressure. These two factors cause the separation of nuclei from electrons and the fusion of hydrogen nuclei to form a  helium atom.

During the fusion process, energy is released.

Answer: The image is at a distance of 24 cm on the right of the lens, it will be an inverted, real image and has a height of 7 cm.

Explanation: To determine the position of the image of the object, use the Lens Equation, which is described by:

[tex]\frac{1}{f} = \frac{1}{u} +\frac{1}{v}[/tex]

where

f is focal length;

u is distance of the object from the lens;

v is distance of the image of the pbject from the lens;

Calculating the position of the image will be:

[tex]\frac{1}{v} =\frac{1}{f} - \frac{1}{u}[/tex]

[tex]\frac{1}{v} = \frac{1}{8} - \frac{1}{12}[/tex]

[tex]\frac{1}{v} = \frac{1}{24}[/tex]

v = 24 cm

Note that the distance of the image from the lens is positive. This means that the formed image is positioned at the right of the lens and is inverted.

For the height of the image, it can be used the Magnification (M) of an image:

M = [tex]\frac{h_{i}}{h_{o}} = \frac{v}{u}[/tex]

where:

[tex]h_{i}[/tex] is the height of the image

[tex]h_{o}[/tex] is the height of the object

For this image:

[tex]\frac{h_{i}}{3.5} = \frac{24}{12}[/tex]

[tex]h_{i} =[/tex] 2 * 3.5

[tex]h_{i}[/tex] = 7 cm

The image formed for this lens is 24 cm on the right of the lens, inverted related to the object and has height of 7 cm.

Answer:

La fuerza promedio que ejerce la resistencia del aire sobre el planeador cuando ingresa con un ángulo de planeo constante de 12 ° con respecto a la Tierra es 9613.8 N

Explanation:

Los parámetros dados son;

Masa del planeador = 980 kg.

Velocidad de lanzamiento horizontal = 480 km / h

Altitud de lanzamiento = 3500 m.

Velocidad de aterrizaje final = 210 km / h

Ángulo de deslizamiento, θ = 12 °

La ecuación para el equilibrio de fuerzas.

L · cos (θ) + D · sin (θ) = W

L · sin (θ) + D · cos (θ)

Dónde:

L = fuerza de elevación

D = fuerza de arrastre

W = Peso del "planeador"

W = Masa del "planeador" × Aceleración debido a la gravedad = 980 kg × 9.81 m / s²

W = 9613.8 N

Por lo tanto, tenemos;

L · cos (12) + D · sin (12) = 9613.8 ,,,,,,,,,,,,, (1)

L · sin (12) = D · cos (12) ,,,,,,,,,,,,, (2)

De la ecuación (2), tenemos;

L = D · (cos (12)/sin (12))

Sustituyendo el valor de L = D · (cos (12) / sin (12)) en la ecuación (1), se obtiene;

D · (cos (12)/sin (12)) · cos (12) + D · sin (12) = 9613.8

D = 9613.8/((cos (12)/sin (12)) · cos (12) + sin (12)) = 1998.82 N

L = D · (cos (12)/sin (12)) = 1998.82 · (cos (12)/sin (12)) = 9403.72 N

Por lo tanto, la fuerza da la fuerza promedio que la resistencia del aire ejerce sobre el planeador cuando ingresa con un ángulo de planeo constante de 12 ° con respecto a la Tierra;

F = √ (L² + D²) = √ (9403.72² + 1998.82²) = 9613.8 N.

Answer:

In this case, the horizontal velocity of the rocket starts from the acceleration, so if its velocity drops to zero,

Explanation:

When a satellite is in orbit the most important force is the docking of gravity with the Earth

             F = m a

where the acceleration is centripetal and F is the force of universal attraction

centripetal acceleration is

             a = v² / r

             F = m v² / r

In this case, the horizontal velocity of the rocket starts from the acceleration, so if its velocity drops to zero, the force also drops to serious and the satellite steels to Earth.

The speed of the satellite is provides the speed, by local for smaller speeds in satellite, it descends in its orbits and when the speed is amate you have the energy to stop an orb to go to a higher orbit.