A woman is standing on a steep hillside in the rain and is not moving. A
sudden gust of wind blows down the hillside, which makes her start sliding
down the hill. When the wind stops blowing, the woman continues to slide.
Which of the following statements explains why she continues to slide down
the hillside?
A. The component of the woman's weight along the hillside is larger
than the kinetic friction between the woman and the ground.
B. The component of the woman's weight along the hillside is less
than the kinetic friction between the woman and the ground.
C. The component of the woman's weight along the hillside is larger
than the static friction between the woman and the ground.
D. The component of the woman's weight along the hillside is less
than the static friction between the woman and the ground.
SUBMIT

Answer:

4.489 m/s

Explanation:

We are given;

Length of rod;L = 51.4 cm = 0.514 m

When the ball is at the top end, it's velocity will be zero and it's kinetic energy will be transformed to potential energy.

Thus; ½mv² = mgh

m will cancel out to give;

v² = 2gh

Where:

g is acceleration due to gravity = 9.8 m/s²

h is the maximum height of the ball which is equal to twice the length of the rod.

Thus, h = 2(0.514) = 1.028 m

v² = 2 × 9.8 × 1.028

v = √20.1488

v = 4.489 m/s

Copper is a reddish orange, soft metal with a bright metallic luster. It is an excellent conductor of heat and electricity. Copper surfaces when exposed to air gradually turns to a dull, brownish color.

Answer:

The temperature at the top is -39.5 degree

Explanation:

The height of Mt Everest = 8850 m

The base is at the elevation of = 5400 m

The drop in temperature = 1 degree per 100 m

At the base, the temperature = -5

Since every 100 meter rise in height results in the one degree drop of temperature. Therefore, first find the difference between the base and height. Multiply with negative one.

Difference in heights = 8850 – 5400 = 3450

The temperature at the top = (3450 / 100) + 5 = -39.5 degree

Since there is fall in temperature so we use negative sign.

Answer:

Medium B is denser than medium C

When light travels from B to C light bends away from the normal .

Refractive index of C with respect to B is 8/9

Ratio of speed of light in medium B to the speed of light in medium A = 4/3

Explanation:

Refractive index of medium A /  Refractive index of medium B =  4/3

Refractive index of medium A /  Refractive index of medium C = 3/2  

Dividing ,

Refractive index of medium B /  Refractive index of medium C

= 3/2  x  3/4

= 9 / 8

Refractive index of medium B  >   Refractive index of medium C

Refractive index of C with respect to B is 8/9

 speed of light in medium B /  the speed of light in medium A

= refractive index of A / refractive index of B = 4 / 3

Answer:

I take the thread and wrap it round the cylinder until it goes round the circumference of the cylinder.

Explanation:

I take the thread and wrap it round the cylinder until it goes round the circumference of the cylinder.

I then cut the thread at this length and extend it out on a table or floor.

I then place the length of the thread along the meter rule and mark of the position of its tip and bottom along the meter rule.

The difference between the bottom and top points is the circumference of the cylinder.

If the thread is longer than the meter rule, i mark off where the the length of the meter rule stops along the thread and then place the meter rule at that point and then mark off where the length of the thread stops.

The circumference of the cylinder is then 1 meter plus the extra measurement along the meter rule.

Answer:

Remember the equation:

F = m*a

where F is force, m is mass and a is acceleration.

If we have F constant. and we want that increases, then we can have the case where m decreases.

The mass can decrease in cases like a rocket, where as the fuel of the rocket consumes, the mass of the rocket decreases and the acceleration increases.

b) The cases where a constant force results in a constant acceleration of zero, is when the force is canceled, an example of this is the constant force of the gravity in all the objects. The objects that are in the ground are being affected by this force, but the gravitational force is canceled with the normal force of the ground. Then we have a constant force that does not cause any acceleration.

Answer:

d = 57.87 m

Explanation:

It is given that,

Acceleration of car due to applied brake is [tex]-5.4\ m/s^2[/tex]

Its initial speed was 25 m/s

Its final speed was 0 as its comes to rest.

Leat d is the distance covered by the car. It can be calculated using third equation of kinematics as :

[tex]v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{0^2-(25)^2}{2\times (-5.4)}\\\\d=57.87\ m[/tex]

So, the distance covered by the car is 57.87 m.

Answer:

d = 57.87 m

Explanation:  have a nice day :)

Answer:

86.17m/s

Explanation:

Since the motion is of constant acceleration, we can use one of the equations of motion as follows;

v² = u² + 2as

Where;

v = final velocity of the airplane

u = initial velocity of the airplane

s = distance covered by the plane

a = acceleration

From the question,

u = 15m/s

s = 600m

a = 6m/s²

Substitute these values into the equation above as follows;

v² = 15² + 2(6)(600)

v² = 225 + 7200

v² = 7425

v = √7425

v  = 86.17m/s

Therefore, the final velocity of the airplane is 86.17m/s

Explanation:

If Team A is on the left, B is on the right

if the force is constant, it means that the effort applied is equal.

So Team B is pulling 5000N to the right.

Light bends away from the normal, because it's moving from higher to lower refractive index.

Same bend-direction as when it goes from water into air.

Answer:

A police car with its siren on is driving towards you, and you perceive the pitch of the siren to increase.

Explanation:

In Physics, Doppler effect can be defined as the change in frequency of a wave with respect to an observer in motion and moving relative to the source of the wave.

Simply stated, Doppler effect is the change in wave frequency as a result of the relative motion existing between a wave source and its observer.

The term "Doppler effect" was named after an Austrian mathematician and physicist known as Christian Johann Doppler while studying the starlight in relation to the movement of stars.

The phenomenon of Doppler effects is generally applicable to both sound and light.

An example of the Doppler effect is a police car with its siren on is driving towards you, and you perceive the pitch of the siren to increase. This is so because when a sound object moves towards you, its sound waves frequency increases, thereby causing a higher pitch. However, if the sound object is moving away from the observer, it's sound waves frequency decreases and thus resulting in a lower pitch.

Other fields were the Doppler effects are applied are; astronomy, flow management, vibration measurement, radars, satellite communications etc.

Answer:

A police car with its siren on is driving towards you, and you perceive the pitch of the siren to increase.

Explanation:

This should be the correct answer.

Answer:

In this case, the horizontal velocity of the rocket starts from the acceleration, so if its velocity drops to zero,

Explanation:

When a satellite is in orbit the most important force is the docking of gravity with the Earth

             F = m a

where the acceleration is centripetal and F is the force of universal attraction

centripetal acceleration is

             a = v² / r

             F = m v² / r

In this case, the horizontal velocity of the rocket starts from the acceleration, so if its velocity drops to zero, the force also drops to serious and the satellite steels to Earth.

The speed of the satellite is provides the speed, by local for smaller speeds in satellite, it descends in its orbits and when the speed is amate you have the energy to stop an orb to go to a higher orbit.

Answer:

1.01 W/m

Explanation:

diameter of the pipe d = 30 mm = 0.03 m

radius of the pipe r = d/2 = 0.015 m

external air temperature Ta = 20 °C

temperature of pipe wall Tw = 150 °C

convection coefficient at outer tube surface h = 11 W/m^2-K

From the above, we assumed that the pipe wall and the oil are in thermal equilibrium.

area of the pipe per unit length A = [tex]\pi r ^{2}[/tex] = [tex]7.069*10^{-4}[/tex] m^2/m

convectional heat loss Q = Ah(Tw - Ta)

Q = 7.069 x 10^-4 x 11 x (150 - 20)

Q = 7.069 x 10^-4 x 11 x 130 = 1.01 W/m

The heat loss per unit length of tube should be considered as the 1.01 W/m.

Since

diameter of the pipe d = 30 mm = 0.03 m

radius of the pipe r = d/2 = 0.015 m

external air temperature Ta = 20 °C

temperature of pipe wall Tw = 150 °C

convection coefficient at outer tube surface h = 11 W/m^2-K

Now

area of the pipe per unit length A should be

= πr^2

 = 7.069*10^-4 m^2/m

Now

convectional heat loss Q = Ah(Tw - Ta)

Q = 7.069 x 10^-4 x 11 x (150 - 20)

Q = 7.069 x 10^-4 x 11 x 130

= 1.01 W/m

hence, The heat loss per unit length of tube should be considered as the 1.01 W/m.

Learn more about heat here: https://brainly.com/question/15170783

Answer:

The average force has a magnitude 6524 N due north.

Explanation:

The average net force F = ma where m = mass of car = 1400 kg and a = acceleration.

a = (v - u)/t where u = initial velocity of car = 0 m/s (since it starts from rest)

v = final velocity of car = 27 m/s due north and t = time of motion = 5.8 s

a = (27 m/s - 0 m/s)/5.8 s = 27 m/s ÷ 5.8 s = 4.66 m/s

Since the direction of the velocity change is the direction of the acceleration, the acceleration is 4.66 m/s due north.

The average force, F = ma = 1400 kg × 4.66 m/s = 6524 N

Since the acceleration is due north, the average force takes the direction of the acceleration.

So the direction of the average force is due north

The average force has a magnitude 6524 N due north.

Answer and Explanation:

Given that

v_f = 5 km/s = 5,000 m/s

d = 4 m

v_i = 0 m/s

The computation is shown below:

1. The acceleration in m/s is

Here we use the motio third equation which is

[tex]v_f^2 = v_i^2 + 2ad[/tex]

5000^2 = 0^2 + 2 (a) (4)

So

[tex]a = 3.125 \times 10^{6} m/s^2[/tex]

2. Now acceleration in g is

[tex]= \frac{3.125 \times 10^{6} m/s^2}{9.81}[/tex]

[tex]= 3.18 \times 10^{5}g[/tex]

3. The long of acceleration last is

[tex]t = \frac{v-u}{a}[/tex]

[tex]= \frac{5000 - 0}{3.125 \times 10^{6}}[/tex]

[tex]= 1.6 \times 10^{-3}s[/tex]

4.As we can see that

[tex]3.18 \times 10^{5}[/tex] is smaller than the [tex]4.5 \times 10^{5}g[/tex]

So, it should not be ruled out

Answer:

By nuclear fission

Explanation:

The sun generates enormous energy through the process of nuclear fusion.

The core or the innermost part of the sun is characterized by high temperature and pressure. These two factors cause the separation of nuclei from electrons and the fusion of hydrogen nuclei to form a  helium atom.

During the fusion process, energy is released.

Given that,

Weight = 0.75 N

Acceleration due to gravity = 9.81 m/s²

Density of water = 1 g/ml

We need to calculate the volume of water

Using formula of weight

[tex]W=mg[/tex]

[tex]W=\rho Vg[/tex]

[tex]mg=\rho\times V\times g[/tex]

Where, V = volume

g = acceleration

m = mass

Put the value into the formula

[tex]0.076\times 9.8\times10^3=1\times V\times9.8[/tex]

[tex]V= \dfrac{0.076\times 9.8\times10^3}{1\times9.8}[/tex]

[tex]V=76\ ml[/tex]

Hence, The volume of water is 76 mL.

Answer:

76.5mL

Explanation:

w = mg

0.75N = m * 9.81

m = 0.75 / 9.81 = 0.0765 kg

The mass in grams is 0.0765 * 1000 = 76.5g

At a density of 1 g/mL,

76.5g ÷ 1g/ml = 76.5mL

Answer:

Joule

Explanation:

As any unit of energy (kinetic, potential, etc.), the gravitational potential energy has SI units of Joule. This s the work done by a force of 1 Newton to displace an object 1 meter in the direction of application of the force.

Answer:

i took g = 9.8m/s

A. 1.16secs

B. 2.32secs

C. 6.57m

D. 57.91m

Explanation:

A. How long does the Missile take to reach ot peak?

Time taken (t) =( U²Sin (angle) )/g

u = initial velocity = 25m/s

angle given = 30°

g = acceleration due to gravity = 9.8m/s²

t = U² x Sin (angle) / g

t = 25² x Sin(30)/9.8

t = 1.61secs

B. How long is the missile in the air in total?

T = 2t

T = 2 x 1.61 = 2.32 secs

C. what maximum Height does the missile reach?

D. How far does the missile travel Horizontally?

Resultant force is basically the force left after everything is added.

if a ball is being pushed one one side with 180N, and being pushed on teh opposite side with 84N (I added friction and air resistance since they're acting on the same side), then the resultant force would be:

180N - 84N = 96N   (you can determine whether it's positive or negative based on the direction of the vector)

Answer:

Height of the first projectile = 49.98 m

Height of the second projectile = 72.52 m

Explanation:

From the given information;

Two projectiles are thrown from the same point with the velocity of49m/s

First is  projected making an angle  θ with the horizontal

and the second at an angle of 90 - θ.

Thus; for the first height to the horizontal; we have;

[tex]H_1 = \dfrac{v^2 sin^2 \theta}{2g}[/tex]  ----- (1)

the second height in the vertical direction is :

[tex]H_2 = \dfrac{v^2 cos^2 \theta}{2g}[/tex]    -----(2)

However; the second is found to rise 22.5 m higher than the first; so , we have :

[tex]\dfrac{v^2 cos^2 \theta}{2g}= 22.5 + \dfrac{v^2 sin^2 \theta}{2g}[/tex]

Let's recall that :

Cos²θ = 1 - Sin²θ

Replacing it into above equation; we have:

[tex]\dfrac{v^2}{2g} - \dfrac{v^2 sin^2 \theta}{2g}= 22.5 + \dfrac{v^2 sin^2 \theta}{2g}[/tex]

[tex]\dfrac{v^2}{2g} - 22.5 = \dfrac{v^2 sin^2 \theta}{g}[/tex]

[tex]\dfrac{1}{2 } \dfrac{v^2}{g} - 22.5 = \dfrac{v^2 sin^2 \theta}{g}[/tex]

[tex]\dfrac{1}{2 } - \dfrac {9.8 \times 22.5}{(49)^2} = sin^2 \theta[/tex]

[tex]\dfrac{1}{2 } - \dfrac {220.5}{2401} = sin^2 \theta[/tex]

[tex]sin^2 \theta= 0.408[/tex]

From (1);

[tex]H_1 = \dfrac{v^2 sin^2 \theta}{2g}[/tex]

[tex]H_1 = \dfrac{49^2 \times 0.408}{2*9.8}[/tex]

[tex]H_1 = \dfrac{979.608}{19.6}[/tex]

[tex]\mathbf{H_1 =49.98 \ m }[/tex]

Height of the first projectile = 49.98 m

Similarly;

From(2)

[tex]H_2 = \dfrac{v^2 cos^2 \theta}{2g}[/tex]    

[tex]H_2 = \dfrac{v^2 (1-sin^2 \theta)}{2g}[/tex]

[tex]H_2 = \dfrac{49^2 (1-0.408 )}{2 \times 9.8}[/tex]

[tex]H_2 = \dfrac{2401 (0.592 )}{19.6}[/tex]

[tex]H_2 = \dfrac{1421.392}{19.6}[/tex]

[tex]\mathbf{H_2 = 72.52 \ m}[/tex]

Height of the second projectile = 72.52 m

Explanation:

1) This is a synthesis reaction (two or more reactants combine to form a single product).

2) The coefficients are added to balance the reaction.

3) Adding the states of matter (solid, liquid, gas) will make the reaction more precise.

Answer:

El avión recorrió 45 km en los 180 s.

Explanation:

La relación entre velocidad, distancia y tiempo se da de la siguiente manera;

[tex]Velocidad= \dfrac{Distancia}{Hora}[/tex]

Por lo cual los parámetros dados son los siguientes;

Velocidad = 900 km/h = 250 m / s

Tiempo = 180 s

Estamos obligados a calcular la distancia recorrida

De la ecuación para la velocidad dada arriba, tenemos;

Distancia recorrida = Velocidad pf viaje × Tiempo de viaje

Distancia recorrida = 900 km/h × 180 s = 900

Distancia recorrida = 900 km/h × 1 h/60 min × 1 min/60 s × 180 s = 45 km

Por lo tanto, el avión viajó 45 km en 180 s.

Answer: 1.44m/s West

Explanation:

Given the following :

Mass of skater = 60kg

Average force = 240N east

Time of = 0.360 seconds

The Velocity after 0.360seconds

Recall the relation:.

Force(f) * time(t) = mass (m) * (final Velocity(V) - initial velocity(u))

Where ; final Velocity(v) - initial velocity(u) = Magnitude of velocity(V)

Ft = mV

240 × 0.360 = 60 × V

60 × V = 86.4

V = 86.4 / 60

V = 1.44m/s

According to Newton's third law, to every action, there is an equal and opposite reaction.

The action force acts in the eastern direction hitting the wall with a force of 240N, therefore direction after hitting the wall will be in the opposite (western direction) direction, which is the direction of the reaction force

Therefore, velocity is 1.44ms West

Answer:

decrease

Explanation:

as the mass of the cart increase the acceleration of the cart decrease

Explanation:

[tex]a = \frac{change \: in \: velocity}{change \: in \: time} [/tex]

[tex]a = \frac{v - u}{t} [/tex]

[tex]v = 7 {ms}^{ - 1} [/tex]

[tex]u = 15 {ms}^{ - 1} [/tex]

[tex]t = 3 \: seconds[/tex]

[tex]a = \frac{7 - 15}{3} [/tex]

[tex]a = \frac{ - 8}{3} [/tex]

[tex]a = - 2.67 \: {ms}^{ - 2} [/tex]

Answer:

I = 2.61 A

Explanation:

It is given that,

Power of a toaster is 300 watts

It is plugged into an outlet with a voltage of 115 volts

We need to find the current in the toaster's circuit.

The electrical power is given by the formula as follows :

P = V I

I is electric current

[tex]I=\dfrac{P}{V}\\\\I=\dfrac{300}{115}\\\\I=2.61\ A[/tex]

So, 2.61 A of current is in the toaster's circuit.

Answer: D.

2.61 amps

Explanation: edmentum

Answer:

(1) The orbits are ellipses, with focal points ƒ1 and ƒ2 for the first planet and ƒ1 and ƒ3 for the second planet. The Sun is placed in focal point ƒ1.

(2) The two shaded sectors A1 and A2 have the same surface area and the time for planet 1 to cover segment A1 is equal to the time to cover segment A2.

(3) The total orbit times for planet 1 and planet 2 have a ratio a13/2 : a23/2

Answer:

g the day off and I will be there at work and I will be there at work and I will

Explanation:

you are not going to be able to make it to the meeting tonight but I can tomorrow

Answer:

C

Explanation:

It is directly propotional to the amount of charge and inversly propotional to distance.

Answer:

C. Distance and amount of charge

Explanation:

The magnitude of the electric potential depends on which factors?

Distance and amount of charge