A 1.8 m tallman stand in an elevator accelerating upward at 12 m/s?,

what is the blood pressure in the brain and foot.

Take the height difference between the heart and the brain to be

0.35 m?

13.3 x 103 Pa] & [Pblood = 1060 kg.m-3]

Note: [: P Heart

Answers

Answer 1

Answer:

12.483 Kpa

46.806 Kpa

Explanation:

Man's height = 1.8m

Pheart = 13.3 * 10^3

Density of blood (ρ) = 1060 kg/m³

Height difference between heart and brain (Hh - Hb) = 0.35m

g = acceleration due to gravity = 9.8 m/s²

Acceleration (a) = 12 m/s²

Blood pressure in brain :

Pbrain = Pheart - ρ(a - g) * (Hh - Hb)

Pbrain = 13.3 * 10^3 - 1060(12 - 9.8) * 0.35

Pbrain = 13300 - (2332 * 0.35)

Pbrain = 13300 - 816.2

Pbrain = 12483.8 pascal = 12.483 Kpa

Blood pressure in feet :

Pbrain = Pheart + ρ(a + g) * 1.8 - (Hh - Hb)

Pbrain = 13.3 * 10^3 + 1060(12 + 9.8)*(1.8 - 0.35)

Pbrain = 13300 + 1060(21.8 * 1.45)

Pbrain = 13300 + 33506.6

Pbrain = 46806.6 pascal = 46.806 Kpa


Related Questions

PLEASE ANSWER-Why are loose electrons needed for heat conduction?

Answers

Answer:

Why do metals conduct heat so well? The electrons in metal are delocalised electrons and are free moving electrons so when they gain energy (heat) they vibrate more quickly and can move around, this means that they can pass on the energy more quickly.

A 5kg box is sliding down a ramp with a rough surface as seen below. The height of the ramp is 20m and the distance the box travels down the ramp (from A to B) is 15m. At point A the velocity of the box is 8 m/s. If the velocity at point B is 3m/s, what was the impulse caused by friction? If the force of friction is 5N, how long did it take the box to slide the 15 m?

Answers

Answer:

A Impulse = – 25 Ns

B. Time = 5 s

Explanation:

From the question given above, the following data were obtained:

Mass (M) = 5 Kg

Initial velocity (u) = 8 m/s

Final velocity (v) = 3 m/s

Impulse (I) =?

Time (t) =?

A. Determination of the Impulse.

Mass (M) = 5 Kg

Initial velocity (u) = 8 m/s

Final velocity (v) = 3 m/s

Impulse (I) =?

I = Ft = M(v – u)

I = M(v – u)

I = 5 (3 – 8)

I = 5 × – 5

I = – 25 Ns

NOTE: the negative sign indicates that the net force is acting in the negative direction.

B. Determination of the time.

Impulse (I) = 25 Ns

Force (F) = 5 N

Time (t) =?

I = Ft

25 = 5 × t

Divide both side by 5

t = 25 / 5

t = 5 s

Thus, it will take 5 s for the box to slide through the 15 m long ramp.

100 POINTS. PLEASE EXPLAIN

Answers

Answer:

Explanation:

Note the charge balls on the top and bottom row are identical. So those charges cancel each other out. The only charges in the net electric field are the two in the middle row.

Electric field strength = k*Q/r^2

= (8.99 *10^9) * (3-(-3)) * 5*10^(-6) / (2*0.5)^2

= 269700 N/C

Answer:

Explanation:

(b) cuz the 1st n 3nd row cancel out, net electric field will go from +3Q to -3Q. the direction is right.

The Earth (geosphere) comprises several major layers, differing in chemical and mineral composition, material strength, and other physical properties. Which of the layers listed below constitutes the largest proportion of Earth's volume?
a) Lithosphere
b) Crust
c) Outer core ·
d) Inner core
e) Mantle

Answers

Answer:

Option E:

The mantle

Explanation:

The earth's mantle is the mushy, semi-solid portion of the earth that makes up most of the earth's volume. The mantle extends for a depth of about 2800km downwards into the earth, making it the largest internal portion of the earth.  It makes up about 84 percent of the earth's structure, leaving the core and the crust with 15 percent and 1 percent respectively.

Due its nature, convection currents are set up predominantly in the mantle of the earth, which leads to movements in the upper layers of the earth (the crust).

The mantle is large enough for the lighter crust to float on its surface.

If a car takes a banked curve at less than the ideal speed, friction is needed to keep it from sliding toward the inside of the curve (a real problem on icy mountain roads). (a) Calculate the ideal speed to take a 100 m radius curve banked at 15.0o. (b) What is the minimum coefficient of friction needed for a frightened dri

Answers

Answer:

a) The ideal speed = 16.21 m/s

b) Minimum co-efficient of friction = 0.216

Explanation:

From the given information:

The ideal speed can be determined by considering the centrifugal force component and the gravity component.

[tex]\dfrac{mv^2}{r}cos \theta = mg sin \theta[/tex]

[tex]v = \sqrt {gr \ tan \theta}[/tex]

[tex]= \sqrt{(9.8 \ m/s^2) (100) \ tan 15^0}[/tex]

= 16.21 m/s

(b)

Let assume that it requires 25 km/h to take the same curve.

Then, using the equilibrium conditions;

[tex]mg \ sin \theta = \dfrac{mv^2}{r} cos \theta + \mu ((\dfrac{mv^2}{r}) sin \theta + mg cos \theta)[/tex]

[tex]\mu = \dfrac{mg sin \theta - \dfrac{mv^2}{r} cos \theta }{((\dfrac{mv^2}{r}) sin \theta + mg cos \theta) }[/tex]

[tex]\mu = \dfrac{g sin \theta - \dfrac{ v^2}{r} cos \theta }{((\dfrac{v^2}{r}) sin \theta + g cos \theta) }[/tex]

[tex]\mu = \dfrac{(9.8 \ m/s^2 ) sin (15^0) - \dfrac{ \dfrac{(25 \times 10^3}{3600} \ m/s)^2 }{100 \ m } cos (15^0) }{((\dfrac{(\dfrac{25 \times 10^3}{3600} )^2}{100}) sin 15^0 + (9.8 \ m/s^2) cos 15^0 ) }[/tex]

[tex]\mathbf{\mu = 0.216}[/tex]

For which medical procedure would Doppler ultrasound be most useful?

A.
Finding a lung tumor
B.
Fixing a pulled muscle
C.
Locating a broken bone in a finger
D.
Detecting a blockage in a heart artery

Answers

The answer is d.

Thank me by clicking the ❤️. Thanks!

Doppler ultrasound would be most useful in detecting a blockage in a heart artery.

What are the clinical uses of Doppler ultrasound?

By monitoring the rate of change in pitch, a Doppler ultrasound may calculate how quickly blood flows (frequency). A sonographer with training in ultrasound imaging applies pressure to your skin with a tiny, hand-held instrument (transducer) roughly the size of a bar of soap across the area of your body being scanned, moving from one place to another as required.

As an alternative to more invasive treatments like angiography, which involves injecting dye into the blood arteries to make them visible on X-ray images, this test may be performed.

Your doctor may use a Doppler ultrasound to assess for artery damage or to keep track of specific vein and artery therapies.

Learn more about  Doppler technology here:

https://brainly.com/question/6109735

#SPJ2

A 2.0 kg block of ice with a speed of 8.0 m/s makes an elastic collision with another block of ice that is at rest. The first block of ice proceeds in the same direction as it did initially, but with a speed of 2.0 m/s. What is the mass of the second block? (Hint: Use the conservation of kinetic energy to solve for the second unknown variable.)

Answers

Answer:

6kg

Explanation:

According to conservation of kinetic energy

m1u1+m2u2 = (m1+m2)v

m1 and m2 are the masses of the bodies

u1 and u2 are the initial velocities

v is the final velocity

Given

m1 =2kg

u1 = 8.0m/s

m2 = ?

u2 = 0m/s (second ice at rest)

v = 2.0m/s

Substitute into the formula

2(8)+m2(0) = (2+m2)(2)

16+0 = 4+2m2

16-4= 2m2

12 = 2m2

m2 =12/2

m2 = 6kg

Hence the mass of the second block is 6kg

A 5kg box is sliding down a ramp with a rough surface as seen below. The height of the ramp is 20m and the distance the box travels down the ramp (from A to B) is 15m. At point A the velocity of the box is 8 m/s. If the velocity at point B is 3m/s, what was the impulse caused by friction? If the force of friction is 5N, how long did it take the box to slide the 15 m?

Answers

Answer:

the answer is b luv .

Explanation:

Help can’t find the answer no where

Answers

i'm stuck on that question also

A car was moving at 14 m/s After 30 s, its speed increased to 20 m/s. What was the acceleration during this time ( need help fast!!!)

Answers

Answer:let initial velocity u=14m/s

Final velocity v=20m/s

Time taken t=30

Acceleration =a

V=u +at

a= (20-14)/30

a=0.2m/s^2

Explanation:

Acceleration is the change in velocity with respect to time.

Determine the gravitational field of Earth at a height 2.88 x 10^8 m above its surface (the height of the moon above Earth). Earth's mass is 6.0 x 10^24 kg and its radius is 6.4 x 10^6 m.

Answers

Answer:

12

Explanation:

A car with mass 1141 kg, moving at 16 m/s, strikes a(n) 2916 kg car at rest. If the two cars stick together, with what speed do they move

Answers

Answer:

V = 4.49 m/s

Explanation:

Given that,

Mass of the car 1, m₁ = 1141 kg

Initial speed of car 1, u₁ = 16 m/s

Mass of car 2, m₂ = 2916 kg

Initial speed of car 2, u₂ = 0

We need to find the speed of the cars if they stick together. Let the speed be V. The momentum will remain conserved in the process. Using the conservation of momentum to find it.

m₁u₁ + m₂u₂ = (m₁+m₂)V

[tex]V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}\\\\=\dfrac{1141\times 16+2916 \times 0}{(1141 +2916 )}\\\\=4.49\ m/s[/tex]

So, the required speed of the two cars is 4.49 m/s.

Suppose the posted designated speed for a highway ramp is to be 30 mph and the radius of the curve is 700 ft. At what angle must the curve be banked? No Friction

Answers

Answer:

4.92°

Explanation:

The banking angle θ = tan⁻¹(v²/rg) where v = designated speed of ramp = 30 mph = 30 × 1609 m/3600 s = 13.41 m/s, r = radius of curve = 700 ft = 700 × 0.3048 m = 213.36 m and g = acceleration due to gravity = 9.8 m/s²

Substituting the variables into the equation, we have

θ = tan⁻¹(v²/rg)

= tan⁻¹((13.41 m/s)²/[213.36 m × 9.8 m/s²])

= tan⁻¹((179.8281 m²/s)²/[2090.928 m²/s²])

= tan⁻¹(0.086)

= 4.92°

A Discuss the possibility of fracture of two leg bones that have a length of about 70cm and an average area of

about 4cm

2 when a 80kg person jump from a height of 300cm.

Noting: The breaking stress of the bone ϬB =1.5×108 N/m2 , and

Young’s modulus for the bone is Y=1.5×1010 N/m2

Answers

Answer: The bones won't fracture.

Explanation: Stress, in Physics, is a quantity describing forces that can cause deformation. Strain is the measure of how muc an object can be stretched or deformed. The ratio between stress and strain is called Young's modulus or elastic modulus

Breaking Stress of Bone is the maximum stress a bone can take before a rupture occur.

To determine if a person will break his/her bones by jumping from a height, we determine the energy necessary for that jump and compare it with the energy necessary to break a bone.

The energy for breaking a bone is calculated as

[tex]E=\frac{Al_{0}\sigma_{B}^{2}}{2Y}[/tex]

A is the area in m²

l₀ is length in m

[tex]\sigma_{B}[/tex] is breaking stress in N/m²

Y is Young's modulus in N/m²

Calculating energy to break a bone:

[tex]E=\frac{4.10^{-4}.7.10^{-1}.(1.5.10^{8})^{2}}{2.(1.5.10^{10})}[/tex]

[tex]E=210[/tex] J

This is the energy necessary to break one leg bone, so as there are 2, energy will be 420 Joules.

Potential energy gained by jumping is calculated as

E = m.g.h

m is mass in kg

g is acceleration due to gravity in m/s²

h is height in m

Calculating

E = 80.(9.8)(0.3)

E = 235.2 J

Comparing the two energies, potential energy for jumping is less than maximum energy a bone can absorve without breaking, so the leg bones won't suffer a fracture.

A Shaolin monk of mass 60 kg is able to do a ‘finger stand’: he supports his whole weight on his two index fingers, giving him a total contact area of 4 cm 2 with the ground. Calculate the pressure he exerts on the ground (include units), and write your answer to two significant figures.

Answers

Answer:

P = 1471500 [Pa]

Explanation:

We must remember that pressure is defined as the relationship between Force over the area.

[tex]P=F/A[/tex]

where:

P = pressure [Pa] (units of pascals)

F = force [N] (units of Newtons)

A = area of contact = 4 [cm²]

But first we must convert from cm² to m²

[tex]A = 4[cm^{2}]*\frac{1^{2} m^{2} }{100^{2} cm^{2} }[/tex]

A = 0.0004 [m²]

Also, the weight should be calculated as follows:

[tex]w = m*g[/tex]

where:

m = mass = 60 [kg]

g = gravity acceleration = 9.81 [m/s²]

Now replacing:

[tex]w = 60*9.81\\w = 588.6[N][/tex]

And the pressure:

[tex]P=588.6/0.0004\\P=1471500 [Pa][/tex]

Because 1 [Pa] = 1 [N/m²]

What is the wavelength of a wave that has a speed of 350 meters second and a frequency of 140 hert??

Answers

Wavelength is the distance between identical points (adjacent crests) in the adjacent cycles of a waveform signal propagated in space or along a wire. In wireless systems, this length is usually specified in meters (m), centimeters (cm) or millimeters (mm).

Hope this helped

Which statements correctly describe the formula or name of a compound? Select all that apply.
OA. The formula of nitrogen trifluoride is NF 3
B. The formula of ammonia is NH3.
C. The name of AlF, is trialuminum fluoride.
D. The formula of calcium chloride is CaCl2
E. The name of Li, Se is lithium selenate.
OF. The formula of dinitrogen monoxide is NO
2
Results
G. The formula of sulfur trioxide is 30.
Cho
Аа
H. The formula of magnesium hydroxide is Mg(OH)2
G.

Answers

Answer:

A, B, D, and H

Explanation:

Statements A, B, D and H are all correct except the following:

Statement C is incorrect. The name of [tex] AlF_3 [/tex] is aluminium fluoride NOT "trialuminium fluoride".

Statement E is incorrect. The name of [tex] Li_2Se [/tex] is lithium selenide NOT "lithium selenate".

Statement F is incorrect. Dinitrigen monoxide, also known as nitrous oxide has a formula of [tex] N_2O [/tex] NOT [tex] NO_2 [/tex].

Statement G is incorrect. Sulfur trioxide formula is [tex] SO_3 [/tex].

A physics grad student has a machine that measures how
many electrons are whizzing through a ring. If she measures 2
Coulombs of charge flowing through the ring every second,
what is the current passing through the ring?
1 = _A

Answers

Answer:

2A

Explanation:

Given parameter:

Quantity of charge  = 2C

Time taken = 1s

Unknown:

The current passing through the ring = ?

Solution:

Current can also be defined as the quantity of charge that passes  through a conductor per unit of time:

         I  = [tex]\frac{q}{t}[/tex]  

 So;

          I  = [tex]\frac{2}{1}[/tex]   = 2A

A toy car, mass of 0.025 kg, is traveling on a horizontal track with a velocity of 5 m/s. If
the track then starts to climb upwards, how high up the track can the car reach?

Answers

Answer:

1.25 m

Explanation:

This is the vertical height not the distance along the slope.

[tex]K=U\\\frac{1}{2}mv^{2} = mgh\\h = \frac{v^{2}}{2g}=\frac{25}{20}=1.25 m[/tex]

The height the car can reach if the the track starts to climb upwards is 1.2742 meters up.

What is kinetic and potential energy?

Kinetic energy is energy possessed by a body by virtue of its movement. Potential energy is the energy possessed by a body by virtue of its position or its relation with its surrounding systems.

P.E. = mass × g × height

K.E. = 0.5 × mass × (velocity)²

Given that the toy car has a mass of 0.025 kg and is traveling on a horizontal track with a velocity of 5 m/s. Now, the car starts to climb up vertically, therefore, the kinetic energy will be converted to potential energy.

Kinetic Energy = Potential Energy

0.5 × mass × (velocity)² = mass × g × height

Cancel mass from both the sides,

0.5 × (velocity)² = g × height

0.5 × (5 m/s)² = 9.81 m/sec² × height

height = 1.2742 meters

Hence, the car will travel 1.2742 meters up.

Learn more about Kinetic and Potential Energy here:

https://brainly.com/question/15764612

#SPJ5

which hand has a negatively charged?

Answers

Answer:

The dryer sheet is negatively charged and your hand is positively charged

Explanation:

A car accelerates uniformly from rest and reaches a speed of 9.9 m/s in 11.4 s. The diameter of a tire is 86.9 cm. Find the number of revolutions the tire makes during this motion, assuming no slipping. Answer in units of rev.

Answers

Answer:

Number of revolutions = 20.71 rev.

Explanation:

Given the following data;

Initial speed, u = 0m/s

Final speed, v = 9.9m/s

Time, t = 11.4secs

Diameter = 86.9cm to meters = 86.9/100 = 0.869m

To find the acceleration;

Acceleration, a = (v - u)/t

Acceleration, a = (9.9 - 0)/11.4

Acceleration, a = 9.9/11.4

Acceleration, a = 0.87m/s²

Now we would find the distance covered by the tire using the second equation of motion.

S = ut + ½at²

S = 0(11.4) + ½*0.87*11.4²

S = 0 + 0.435*129.96

S = 56.53m

The circumference of the tire is calculated using the formula;

Circumference = 3.142 * diameter

Circumference = 3.142 * 0.869

Circumference = 2.73m

Number of revolutions = distance/circumference

Number of revolutions = 56.53/2.73

Number of revolutions = 20.71 rev.

Therefore, the number of revolutions the tire makes during this motion is 20.71 revolutions.

g A box of mass 10 kg attached to a spring is pulled to a maximum of 44 cm. The box is released. What is the speed when the box reaches a point 10 cm from the equilibrium position

Answers

Answer:

The speed when the box reaches a point 10 cm from the equilibrium position is 2.02 m/s.

Explanation:

Mass attached to the spring, m = 10 kg

maximum displacement of the spring, A = 0.44 m

The spring constant is calculated from Hook's law;

F = kx

mg = kx

k = (mg) / x

k = (10 x 9.8) / 0.44

k = 222.73 N/m

The angular speed of the spring is calculated as;

[tex]\omega = \sqrt{\frac{k}{m} } \\\\\omega =\sqrt{\frac{222.73}{10} } \\\\\omega = 4.72 \ rad/s[/tex]

The speed when the box reaches a point 10 cm from the equilibrium position is calculated as;

[tex]v = \omega \sqrt{A^2-x^2} \\\\v = 4.72\sqrt{0.44^2-0.1^2}\\\\v = 2.02 \ m/s[/tex]

Therefore, the speed when the box reaches a point 10 cm from the equilibrium position is 2.02 m/s.

An athlete runs on track at a constant speed of 75 meters/min for 15 s. What is the total distance he covered during that time?

Answers

Answer:

45

Explanation:

Two force vectors are oriented such that the angle between their directions is 46 degrees and they have the same magnitude. If their magnitudes are 2.81 newtons, then what is the magnitude of their sum

Answers

Answer:

F = 5.17 N

Explanation:

If we know the magnitudes of both vectors, and the angle between them, we can find the magnitude of their sum, applying the cosine theorem, as follows:

       [tex]F =\sqrt{F_{1} ^{2} +F_{2} ^{2} + 2*F_{1} * F_{2} * cos \theta} (1)[/tex]

Replacing by the givens, F₁ = F₂ = 2.81 N, θ = 46º, we get:

       [tex]F =\sqrt{2.81 N ^{2} +2.81 N ^{2} + 2*2.81N* 2.81N* cos 46} = 5.17 N (2)[/tex]

While driving his sports car at 20.00 m/s down a four lane highway, a
man comes up behind a very slow school bus. The man is in a hurry so he
decides to pass the bus. If the man's car can accelerate at 6.00 m/s^2,
how long will it take for him to reach a speed of 35.00 m/s in order to pass
the bus? Round to the nearest hundredth. (2 decimal places) Type the
number only.

Answers

Answer:

2.50 s

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 20 m/s

Acceleration (a) = 6 m/s²

Final velocity (v) = 35 m/s

Time (t) =?

Thus, we can obtain the time taken for the man to reach a speed of 35 m/s as follow:

v = u + at

35 = 20 + 6t

Collect like terms

35 – 20 = 6t

15 = 6t

Divide both side by 6

t = 15/6

t = 2.50 s

Thus, it will take the man 2.50 s to reach a speed of 35 m/s.

3.
A person drives north 6 blocks, then drives west 6 blocks.
The displacement is a straight line from the starting point to the finish in a
direction
O A northwesterly
O B southwesterly
O c northeasterly
OD southeasterly

Answers

The answer is c northeasterly because it goes through the middle of those two

A jumbo egg (80 grams) is dropped from a height of 15 meters onto a 1 inch of foam. Using kinematics, determine the velocity of the egg the instant before impact.

Answers

Answer:

the velocity of the egg the instant before impact is 17.15 m/s.

Explanation:

Given;

mass of the egg, m = 80 g = 0.08 kg

height through which the egg was dropped, h = 15 m

The velocity of the egg before impact will be maximum, and the final velocity is given by the following kinematic equation;

v² = u² + 2gh

where;

u is the initial velocity of the egg = 0

v is the final velocity of the egg before impact

v² = 0 + 2 x 9.8 x 15

v² = 294

v = √294

v = 17.15 m/s

Therefore, the velocity of the egg the instant before impact is 17.15 m/s.

1. Amy uses 30N of force to push a lawn mower 10 meters. How much work does she do?

Answers

Work=300J (basically multiplying)

An inventor claims to have developed a resistance heater that supplies 1.2 kWh of energy to a room for each kWh of electricity it consumes. Is this a reasonable claim, or is it true that the inventor has developed a perpetual-motion machine

Answers

Answer:

if we are to go by the first law of thermodynamics, the Inventors claims are not reasonable.

The inventor has developed a perpetual-motion machine { any device that violates the first law of thermodynamics}

Explanation:

Given that;

energy supplied to a room Qh= 1.2 kWh

for each for each kWh of electricity it consumes, i.e work input W = 1 kWh

W know that; the first law of thermodynamics says energy can neither be created nor destroyed but can flow from one body to another;

which means ∑Q should or must be equal to ∑W;  ∑Q = ∑W

but in the given system; Qh⇒1.2 kWh is NOT equal to W⇒1 kWh

i.e Qh⇒1.2 kWh W⇒1 kWh

which simply means his device create energy and that violate the first law of thermodynamics.

Therefore, if we are to go by the first law of thermodynamics, the Inventors claims are not reasonable.

The inventor has developed a perpetual-motion machine { any device that violates the first law of thermodynamics}

Two charges q1 and q2 are separated by a distance r and apply a force F to each other. If both charges are doubled, and the distance between them is halved, the new force between them is

Answers

Answer:

The new force between them is increased by a factor of 16.

Explanation:

According to Coulombs law, the force of attraction between two (2) charges is given by the formula;

F = Kq1q2/r²

Given the following data;

q1 = 2q1

q2 = 2q2

r = r/2

Substituting into the equation, we have;

F = 2q1*2q2/(r/2)²

F = 4q1q2/r²/4

F = 4q1q2 * 4/r²

F = 16q1q2/r²

Therefore, the new force between them is increased by a factor of 16.

Other Questions
6 of 9Question 6Item 6Read the following passage carefully before you choose your answers.This passage is excerpted from a novel first published in 2006.I sat watching my mum wash our clothes in a hill stream. She beat the dirt out against a smooth rock, then soaked the bruised cloth in the water, shook it out, and let it float.I had been keeping my distance. It was my way of punishing her for having been rude to Mr. Watts. Now I thought of another way of getting at her. I took aim at the back of her head and asked her if she missed my dad. No angry look flashed over her shoulder, which is what I had expected. No. What happened was her hands became busier. So did her shoulders.Why do you ask, girl?I shrugged, but of course she didnt see that. A new silence was about to open up between us.Sometimes, she added. Sometimes I will look up and see the jungle part, and there is your father, Matilda. And he is walking towards me.And me?She dropped the washing and turned to me.And you. Yes. Your father is walking towards us both. And then I have memories.Which are?No blimmin use, she said. Thats what they are. But since you ask, I do remember back when the mine was open and your father was in court on a disorderly charge.I didnt know any of this, and yet her tone of voice suggested my fathers misdemeanor was no worse, say, than his forgetting to bring her something home from Arawa. His court appearance was no more calamitous than an instant of forgetfulness. This is what she wished me to believe. But I didnt. I wished she hadnt told me. There was more.I remember how soft and red his face looked, she said. How very sorry in a pray-to-God-I-am-sorry sort of way. Well, I remember looking out the window of the courthouse. I saw an airplane draw a white line in the sky, and at the same time a coconut fell past the window. For a moment, I did not know which one to look at, ehat that thing that was rising or the thing that was falling.She pushed off her knees and stood up so she could look at me.If you really must know, Matilda, I didnt know if I was looking at a bad man or a man who loved me.I was hearing more than I wanted. This was adult talk. And because she was watching me carefully I knew she had caught up with that thought.I miss sea horses too, she said more brightly. You will never find a more wise eye anywhere than in a sea horse. This is true. I made that discovery when I was younger than you. And I discovered something about parrot fish. They stare at you in their hundreds and actually remember you from the day before and the day before that one.Thats a lie. I laughed.No, she said. Its true. She held her breath, and so did I, and she was the first to burst out laughing.Now that I had met Miss Havisham, and knew more about her unhappy past, I had changed my mind about my mum being like Pips sister.1 She had more in common with Miss HavishamMiss Havisham who cannot move on from the day of her greatest disappointment. On the clock, the exact hour and minute that the bridegroom failed to show. The wedding feast untouched, left for the cobwebs to mark time.Miss Havisham remains in her wedding gown for an event that has been and gone. I had an idea my mum was stuck in a similar moment. Only it had to do with an argument with my dad. Her frown gave her away. A frown that could be traced back to the original moment. I had an idea that whatever my dad had said still rang in her ears.In the context of the passage as a whole, the narrator is best described as a reader whoA fantasizes about escaping her boring day-to-day existenceB is passionate about sharing the stories she reads with othersC feels superior to others who have not been exposed to literatureD uses the stories she reads to help contextualize her own experienceE struggles to understand the complicated plots in difficult texts Carriers have to be whatgenotype? The Third Platform is a new operating system that combines mobile computing, cloud services, and social networking.TrueFalse Suppose your bathroom sink is clogged and you have decided to try and unclog it by pushing a wire into the drain. You have several types of wire available around the house, some insulated and some not. Which of the following wire characteristics would you need to consider in selecting a wire for the job?The wire characteristics are listed as follows:a. Immunity to electrical noiseb. Color of the insulationc. Resistance of the insulation to salt waterd. Resistance of the insulation to firee. Costf. Stiffnessg. Ease of stripping the insulation -h. Weight i. Availabilityj. Strengthk. Resistance to high temperaturesl. Resistance to stretching 1) Oliver had collected 3/4 of the baseball cards he needs for a full set. What percent ofcards has he collected? Which is a section of a Cabinet department?a commissionan authoritya corporationa bureau What were womans Christian temperance goal and accomplishments? Can someone please help me with 1 and 2 :) Which of the following is either a median or an altitude? Solve the equation.5/6b = 1 7/8 A box contains the numbers 9, 2, 2, 11, 1, 8, 8, 2, 6, 1, 7, 3. Journalists try to use shorter or simpler words in their news stories whenever possible. The box below shows the number of letters in each word taken from one sentence in a news article. What are the mean and median number of letters per word? What is the outlier? The mean number of letters per word = The median number of letters per word = The outlier = Houston-based Advanced Electronics manufactures audio speakers for desktop computers. The following data relate to the period just ended when the company produced and sold 41,000 speaker sets:Sales $3,362,000 Variable costs 840,500 Fixed costs 2,310,000 Management is considering relocating its manufacturing facilities to northern Mexico to reduce costs. Variable costs are expected to average $20.00 per set; annual fixed costs are anticipated to be $1,986,000. Required:1. Calculate the companys current income and determine the level of dollar sales needed to double that figure, assuming that manufacturing operations remain in the United States.2. Determine the break-even point in speaker sets if operations are shifted to Mexico.3. Assume that management desires to achieve the Mexican break-even point; however, operations will remain in the United States.4. If variable costs remain constant, by how much must fixed costs change?5. If fixed costs remain constant, by how much must unit variable cost change?6. Determine the impact (increase, decrease, or no effect) of the following operating changes.A) Effect of an increase in direct material costs on the break-even point.B) Effect of an increase in fixed administration costs on the unit contribution margin.C) Effect of an increase in the unit contribution margin on net income.D) Effect of a decrease in the number of units sold on the breakeven point. Find the indicated probability. In one town, 71% of adults have health insurance. What is the probability that 4 adults selected at random from the town all have health insurance I NEED HEEELPPP!!!!!!!!!!!!! CORRECT ANSWER GETS BRAINLIEST 9 - 12x + 6y[tex]9 - 12x + 6y[/tex] what was mr van.daan's reaction to getting caught stealing the bread. The ratio of Rogers age to his sons is 7:3. If the sum of their ages are 60 how old is Rogers son Hi, can you please help me? 1 Over a period of 3 hours, 190 leaves fell from a tree. At this rate, about how many leaves fell every hour? (Round your answer to the nearest whole number.)A. 60 leaves per hourB. 72 leaves per hourC. 75 leaves per hourD. 63 leaves per hour question 2:Mrs. Hill drove a total of 252 miles and used 12 gallons of gasoline. What is the unit rate?A. 16 miles per gallonB. 12 miles per gallonC. 21 miles per gallonD. 32 miles per gallon 1. Ais a letter with hanging feet. * Evaluate the following.7 + 2 x 5 + 20:5please help ASAP!!