A 0.532 mol sample of SO2 gas requires 52.3 s to effuse through a tiny hole. Under the same conditions, how long will it take 0.532 mol of Ar gas to effuse?

Answer:

380g

Explanation:

Given parameters:

Number of moles of Fluorine  = 20moles

Unknown:

Mass of Fluorine  = ?

Solution:

The number of moles is the unit of quantifying the amount of particles in a substance.

 So;

      Mass of a substance  = number of moles  x molar mass

Molar mass of F = 19g/mol

 Now;

     Mass of F = 20 x 19 = 380g

Answer:

Ac

Explanation:

Answer:

The answer is a

Explanation:

Ac

Answer:

The general principle behind Slater's Rule is that the actual charge felt by an electron is equal to what you'd expect the charge to be from a certain number of protons, but minus a certain amount of charge from other electrons. Slater's rules allow you to estimate the effective nuclear charge  Zeff  from the real number of protons in the nucleus and the effective shielding of electrons in each orbital "shell" (e.g., to compare the effective nuclear charge and shielding 3d and 4s in transition metals). Slater's rules are fairly simple and produce fairly accurate predictions of things like the electron configurations and ionization energies.

Explanation:

The shielding constant of a d electron in copper is 22.15.

From Slaters's rule;

Zeff = Z - S

Where;

Z = Nuclear charge

S = Shielding constant

Now we are required to find the shielding constant for copper d - electrons;

The shielding contributed by the d electrons = (9 × 0.35) = 3.15

The shielding contributed by other electrons = (19 × 1.00) = 19

Total shielding constant =  3.15 + 19 = 22.15

Learn more: https://brainly.com/question/165414

Answer:

Given the equation of the reaction below:

3Cl₂(g) + 2Al(s) → 6Cl⁻(aq) + 2Al³⁺(aq)

The oxidized species is aluminum, Al, as its oxidation number increases from zero to +3. Al therefore, acts as the reducing agent.

Also, the reduced species is chlorine gas, Cl₂, as its oxidation number decreases from zero to -1. Therefore, Cl, is the reducing agent.

Note: the question is incomplete. a related question is given as follows; Identify the species oxidized, the species reduced, the oxidizing agent and the reducing agent in the following electron transfer reaction. 3Cl2 + 2Al → 6Cl - + 2Al3+ species oxidized:

Explanation:

An oxidation is a process in which there is a loss of electrons whereas  reduction is a process involving the gain of electrons. A redox reaction is a reaction in which oxidation and reduction processes occur concurrently and to the same extent.

In a redox reaction reaction, the substance which is oxidized serves as the reducing agent by donating electrons to the substance which is reduced. On the other hand, the substance which is reduced serves as the oxidizing agent by accepting the electrons donated by the substance which is oxidized. In oxidation, the oxidation number of the substance oxidized increases, whereas in reduction, the oxidation number of the substance decreases.

For example, given the equation of the reaction below:

3Cl₂(g) + 2Al(s) → 6Cl⁻(aq) + 2Al³⁺(aq)

The oxidized species is aluminum, Al, as its oxidation number increases from zero to +3. Al therefore, acts as the reducing agent.

Also, the reduced species is chlorine gas, Cl₂, as its oxidation number decreases from zero to -1. Therefore, Cl, is the reducing agent.

The mixture flow rate in lbm/h = 117.65 lbm/h

Given

15.0 wt% methanol

The flow rate of the methyl acetate :100 lbm/h

Required

the mixture flow rate in lbm/h

Solution

mass of methanol(CH₃OH, Mw= 32 kg/kmol) in mixture :

[tex]\tt 15\%\times 200~kg=30~kg\\\\mol=\dfrac{mass}{MW}=\dfrac{30~kg}{32~kg/kmol}=0.9375~kmol[/tex]

mass of the methyl acetate(C₃H₆O₂,MW=74 kg/kmol,85% wt) in 200 kg :

[tex]\tt 85\%\times 200=170~kg\\\\mol=\dfrac{170}{74}=2.297~kmol[/tex]

Flow rate of the methyl acetate in the mixture is to be 100 lbm/h.

1 kg mixture = 0.85 .methyl acetate

So flow rate for mixture :

[tex]\tt \dfrac{1~kg~mixture}{0.85~methyl~acetat}\times 100~lbm/h=117.65~lbm/h[/tex]