Answer:
68y-42
Step-by-step explanation:
Answer:
68 y-42
Step-by-step explanation:
The angle measures of triangle QRS are given:
The measure of angle Q is (5x−15)°.
The measure of angle R is 75°.
The measure of angle S is (3x)°.
What is the value of x?
Answer:
x = 15°
Step-by-step explanation:
(5x-15) + 75 + 3x = 180
8x + 60 = 180
8x = 120
x = 15°
бx + 8 = 50
I need that answer
Answer:
=
7
Step-by-step explanation:
Need help ASAP with my math
Answer: The answer is -2
Step-by-step explanation: I want points and trust me this answer is correct
Pls I need help ASAP
Answer:
the answer is 1/8
thank you
if you loved my answer then please like it and mark as brainliest
there is a box that contains a $50 bill, two $20 bills, three $10 bills and four $1 bills. If a bill is picked at random, what is the expected value?
One of the ten bills
11. Factor for
12 – 8.1 + 16
Answer:
2(6-4.05+8)
Step-by-step explanation:
2(6-48+43.05+8)
Write the following equation in the general form Ax+ By+ C:
1/2y -1/3x -1 = 0
a.) -2x +3y -6 = 0
b.) 2x -3y -6 = 0
c.) 2x 3y +6 = 0
Solve for X please :(( Will give brainliest.
5x+6+92 = 22x-4
5x+98 = 22x-4
add 5x to both sides
98 = 27x-4
add 4 to both sides
102 = 27x
divide both sides by 27
x = 3 and [tex]\frac{7}{9}[/tex]
A population has standard deviation g = 17.2.
Part 1 of 2
(a) How large a sample must be drawn so that a 99.8% confidence interval for I will have a margin of error equal to 3.8?
Round the critical value to no less than three decimal places.
Round the sample size up to the nearest integer.
A sample size of is needed to be drawn in order to obtain a 99.8% confidence interval with a margin of error equal to
3.8.
Part 2 of 2
(b) If the required confidence level were 80%, would the necessary sample size be larger or smaller?
(Choose one) because the confidence level is (Choose one)
х
Answer:
idk
Step-by-step explanation:
9. Determine whether KM and ST are parallel, perpendicular, or neither. K(-1, -8), M(1,6), S(-2,-6), T(2, 10) A Parallel B Perpendicular C Neither Hint(use slope formula)
−20=−4x−6x Find the value of x
Answer:
[tex]\huge\boxed{x=2}[/tex]
Step-by-step explanation:
[tex]-20=-4x-6x\qquad|\text{combine like terms}\\\\-20=-10x\qquad|\text{divide both sides by (-10)}\\\\\dfrac{-20}{-10}=\dfrac{-10x}{-10}\\\\2=x\to x=2[/tex]
(-8) X 2/3 i NEED the answer help me
-5.33333333333
I used a calulator can I get brainliest please
Megan had $235.17 in her bank account. She withdrew $77.98 from the account to spend
on clothing. How much money does she have left in her bank account now?
Answer: 157.19
Step-by-step explanation:
Follow the steps to find the value of x
1.Addition property of equality.
1/5(x)-2/3=4/3
1/5(x)-2/3+2/3=4/3+2/3
2.Multiplicative property if equality.
1/5(x)5/1=6/3(5/1)
The solution is x=
Answer:
its 10
Step-by-step explanation:
I got it right
x+y=k
x-y=k
The solution of the system shown is
O (OK)
O (0,0)
O (k, O)
Answer: (0,0)
Step-by-step explanation:
The only integer"s" that both add and subtract to the same value are 0 "and" 0. Properly stated, the only integer that can be added to itself and subtracted from itself with the same outcome is 0.
Of course, k will also be 0
So this system of equation works out to be
0 + 0 = 0
0 - 0 = 0
A florist sold 45 flowers in a day and 60 flowers on the next day. If p is the percent increase in the number of flowers sold, which proportion can be used to calculate p?
Answer:
c
Step-by-step explanation:
i took the test
Answer: C
Step-by-step explanation:
Only one that makes sense and I just took that test
bob is on his way home in his car. he has driven 30 miles so far, which is three-fifths of the way home. what is the total length of his drive?
The length of Bob's drive as a fraction = 5/5
Let the length of his total drive be = x
30 miles driven by Bob as a fraction =
= 3/5 of x = 30
= 3/5x = 30
= 5/x = 30 ÷ 3 ( transposing ×3 from LHS to RHS changes ×3 to ÷3 )
=5/x = 10
= x = 10 × 5 ( transposing ÷5 from LHS to RHS changes ÷5 to ×5 )
= x = 50
Now we have to see what is =
= 2/5 of 50
= 2/5 × 50
= 100/5
= 20 miles
So , total length of Bob's drive = 30 miles + 20 miles = 50 miles .
∴ The total length of Bob's drive is 50 miles .
Use a system of linear equations with two variables and two equations to solve.
175 students enrolled in a freshman-level chemistry class. By the end of the semester, 4 times the number of students passed as failed. Find the number of students who passed, and the number of students who failed.
Answer:
35 failed and 140 passed
Step-by-step explanation:
Let p = number who passed
f = number who failed
p+f = 175
4 times the number of students passed as failed, so we need to balance this to set it equal
4f = p
Substitute this into the first equation
4r+f = 175
5f = 175
5f/5 =175/5
f = 35
Now find the number who passed
p = 4f
p = 4*35
p =140
Show that each conjecture is false by finding a counterexample.
1.For any integer n, n3 > 0.
2. Each angle in a right triangle has a different measure.
3.For many years in the U.S, each bank printed its own currency. The variety of different bills led to widespread counterfeiting. By the time of the Civil War, a significant fraction of the currency in circulation was counterfeit. If one soldier had 48 bills, 16 of which were counterfeit, and another soldier had 39 bills, 13 of which were counterfeit, make a conjecture about what fraction of bills were counterfeit at the time of the Civil War.
Answer:
1. [tex]n: n^3 > 0[/tex] is not true for negative integers
2. [tex]45\ and\ 45[/tex] show that all angles do not have different measure
3. [tex]Fraction = \frac{1}{3}[/tex]
Step-by-step explanation:
Solving (1):
[tex]n: n^3 > 0[/tex]
Take
[tex]n = -1[/tex]
[tex]-1^3 = -1[/tex]
[tex]n: n^3 > 0[/tex] is not true for negative integers
Solving (2):
The angles of a right angled triangle are:
[tex]45, 45\ and\ 90[/tex]
[tex]45\ and\ 45[/tex] show that all angles do not have different measure
Solving (3):
When
[tex]Bills = 48[/tex]
[tex]Counterfeit = 16[/tex]
The fraction is calculated as thus:
[tex]Fraction = \frac{Counterfeit}{Bills}[/tex]
[tex]Fraction = \frac{16}{48}[/tex]
[tex]Fraction = \frac{1}{3}[/tex]
Similarly, when
[tex]Bills = 39[/tex]
[tex]Counterfeit = 13[/tex]
[tex]Fraction = \frac{Counterfeit}{Bills}[/tex]
[tex]Fraction = \frac{13}{39}[/tex]
[tex]Fraction = \frac{1}{3}[/tex]
Which correctly solves the equation ab+c=d solve for b.
Answer:
b=(d-c)/a
Step-by-step explanation:
Just gotta switch them around a bit
2/15 = h/125 need a step by step please
====================================
Work Shown:
2/15 = h/125
2*125 = 15*h .... cross multiply
250 = 15h
15h = 250
h = 250/15
h = (5*50)/(5*3)
h = 50/3
-----------------
Extra info:
50/3 = (48+2)/3
50/3 = (48/3)+(2/3)
50/3 = 16 + (2/3)
50/3 = 16 & 2/3
The improper fraction 50/3 converts to the mixed number 16 & 2/3
Another way to see this is to use long division to get 50/3 = 16 remainder 2.
2/3 divided by ? = 6/8 ASAP
Answer: 1/72 in decimal form 0.01389
Step-by-step explanation:
Answer:
im pretty sure it is 8/9
Step-by-step explanation:
6/8 x 8/9 =2/3
a hill rises 10 meters over horizontal distance of 8 meters
calculate the slope
Answer:
Slope = 5/4
Step-by-step explanation:
GCF of 10 and 8 is 2, divide both values by two and have the 10 as the rise and 8 as the run.
Evaluate 8 ÷ -2 · 4²+9. Thanks! Will give brainiest if possible
1) Suppose you buy a laptop costing $1850 at a store charging 12% add-on interest, and you make a $500 down payment.
Find the exact value using trigonometric identities.
1850 , 0.12 , − o n , 500 a
What is the value of j
Factorise fully
40-10g
Please do quick, will mark brainiest!!
Answer:
10(4-g)Step-by-step explanation:
[tex]40 - 10g[/tex]
Rewrite 40 as 4 × 10
[tex]4 \times 10 - 10g[/tex]
Factor out 10
[tex]10(4 - g)[/tex]
|3d-3n|-4 if n=2 and d=3
Answer:
-1
Step-by-step explanation:
[tex]|3d-3n|-4[/tex]
Once we have an absolute value, we know that
[tex]|3d-3n| \geq 0[/tex]
[tex]\text{For }n=2 \text{ and } d=3[/tex]
[tex]|3(3)-3(2)|-4[/tex]
[tex]|9-6|-4[/tex]
[tex]|3|-4[/tex]
[tex]3-4[/tex]
[tex]-1[/tex]
Tara's website, verdantveggies.com, specializes in the sale of rare or unusual vegetable seeds. Tara sells packets of sweet-pepper seeds for $2.85 each and packets of hot-pepper seeds for $4.29 each. She also offers a 16-packet mixed-pepper assortment combining packets of both types of seeds at $3.30 per packet. How many packets of each type of seed are in the assortment?
Answer:
Let's define the variables:
S = # of sweet pepper seeds in the mix pack.
H = # of hot pepper seeds in the mix pack.
Let's suppose that $3.30 is the mean price of the seeds in the mix pack.
Then we have two equations:
S + H = 16.
(S*$2.85 + H*$4.29)/16 = $3.30
Now let's solve this system.
The first step is isolating one variable in one of the equations, i will isolate S in the first equation.
S = 16 - H.
Now we can replace this in the second equation, and solve it for H.
( (16 - H)*$2.85 + H*$4.29)/16 = $3.30
( (16 - H)*$2.85 + H*$4.29) = $3.30*16 = $52.80
$45.60 + H*$1.44 = $52.80
H*$1.44 = $52.80 - $45.60 = $7.20
H = $7.20/$1.44 = 5
Then in the mix pack there are 5 hot-pepper seeds.
And the other 11 must be sweet-pepper seeds
Algebraic equations are equations that contain unknown variables.
The number of packets of sweet-pepper seeds is 11 and the number of packets of hot-pepper seeds is 5.
Let's represent:is
The number of packets of sweet-pepper seeds = s
The number of packets of hot-pepper seeds = h
Based on this question, our system of equations are:
$2.85 x s + $4.29 x h = $3.30(16)
2.85s + 4.29h = 52.8...........Equation 1
s + h = 16...........Equation 2
s = 16 - h
We substitute 16 - h for s in Equation 1
2.85(16 - h) + 4.29h = 52.8
45.6 -2.85h + 4.29h = 52.8
Subtract 45.6 from both sides
45.6 - 45.6 -2.85h + 4.29h = 52.8 - 45.6
1.44h = 7.2
h = 5
There are 5 hot-pepper seeds in the assortment.
Solving for the number of sweet-pepper seeds.
s = 16 - h
s = 16 - 5
s = 11
There are 11 sweet-pepper seeds in the assortment.
Therefore, the number of packets of sweet-pepper seeds is 11 and the number of packets of hot-pepper seeds is 5.
To learn more, visit the link below:
brainly.com/question/12978834
What is the sign of the product (3)(−25)(7)(−24)?
A. Positive, because the products (3)(−25) and (7)(−24) are negative, and the product of two negative numbers is positive
B. Positive, because the products (3)(−25) and (7)(−24) are positive, and the product of two positive numbers is positive
C. Negative, because the products (3)(−25) and (7)(−24) are negative, and the product of two negative numbers is negative
D. Negative, because the products (3)(−25) and (7)(−24) are positive, and the product of two positive numbers is negative