5) Calculate the molality of 0.210 mol of KBr dissolved in 0.075kg pure
water.

Answer:

112 of O2

Explanation:

Now if simply oxygen is given so we'll consider O2

3.5 moles O2 means,

3.5 x 32 = 112 grams of O2

Considering the definition of molar mass, the mass of 3.5 moles of O₂ is 112 grams.

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

The molar mass of a compound (also called Mass or Molecular Weight) is the sum of the molar mass of the elements that form it (whose value is found in the periodic table) multiplied by the number of times they appear in the compound.

In this case, you know the molar mass of the oxygen O is 16 g/mole.

So, the molar mass of the compound O₂ is calculated as:

O₂= 2× 16 g/mole

Solving:

O₂= 32 g/mole

Next, you can apply the following rule of three: If by definition of molar mass 1 mole of the compound contains 32 grams, 3.5 moles of the compound contains how much mass?

[tex]mass= \frac{3.5 molesx32 grams}{1 mole}[/tex]

mass= 112 grams

Finally, the mass of 3.5 moles of O₂ is 112 grams.

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Answer:

relation (but not a function)

Explanation:

c on edge

Answer:

Coca-Cola (and other Colas) are dark because food colouring is added to the mixture (caramel colour) to create the traditional colour of colas.

Today we still colour our colas this way, because of tradition: That is the colour colas are supposed to be.

Explanation:

Answer:

[tex]Y=34.3\%[/tex]

Explanation:

Hello there!

In this case, according to the balanced chemical reaction:

[tex]2Al + Cr_2O_3 \rightarrow Al_2O_3 + 2Cr[/tex]

We notice there is a 1:1 mole ratio between Al2O3 and Cr2O3; thus, the following stoichiometric setup is used to compute the theoretical yield first:

[tex]m_{Al_2O_3 }=23.3gCr_2O_3*\frac{1molCr_2O_3}{151.99gCr_2O_3} *\frac{1molAl_2O_3}{1molCr_2O_3} *\frac{101.96gAl_2O_3}{1molAl_2O_3} \\\\m_{Al_2O_3}=15.6gAl_2O_3[/tex]

Thus, the percent yield turns out:

[tex]Y=\frac{5.35g}{15.6g} *100\%\\\\Y=34.3\%[/tex]

Best regards!

Answer:

[tex]m_{Hg}=829.4gHg[/tex]

Explanation:

Hello there!

In this case, considering the Avogadro's number, which helps us to realize that 1 mole of mercury atoms contains 6.022x10²³ atoms and at the same time 1 mole of mercury weights 200.59 g, we obtain:

[tex]m_{Hg}=2.49x10^{24}atoms*\frac{1mol}{6.022x10^{23}atoms} *\frac{200.59g}{1molHg}\\\\m_{Hg}=829.4gHg[/tex]

Best regards!

answer:

a mountain ridge which circles the earth

subduction zones

1. The mass of N₂ produced is 0.45 g

2. The mass of O₂ produced is 0.26 g

3. The mass of H₂O produced is 0.58 g

4NH₄NO₃(g) --> 4N₂(g) + 2O₂(g) + 8H₂O(g)

Molar mass of NH₄NO₃ = 80 g/mol

Mass of NH₄NO₃ from the balanced equation = 4 × 80 = 320 g

Molar mass of N₂ = 28 g/mol

Mass of N₂ from the balanced equation = 4 × 28 = 112 g

Molar mass of O₂ = 32 g/mol

Mass of O₂ from the balanced equation = 2 × 32 = 64 g

Molar mass of H₂O = 18 g/mol

Mass of H₂O from the balanced equation = 8 × 18 = 144 g

SUMMARY

From the balanced equation above,

320 g of NH₄NO₃ decomposed to produce 112 g of N₂, 64 g of O₂ and 144 g of H₂O

From the balanced equation above,

320 g of NH₄NO₃ decomposed to produce 112 g of N₂

Therefore,

1.29 g of NH₄NO₃ will decompose to produce = (1.29 × 112) / 320 = 0.45 g of N₂

From the balanced equation above,

320 g of NH₄NO₃ decomposed to produce 64 g of O₂

Therefore,

1.29 g of NH₄NO₃ will decompose to produce = (1.29 × 64) / 320 = 0.26 g of O₂

From the balanced equation above,

320 g of NH₄NO₃ decomposed to produce 144 g of H₂O

Therefore,

1.29 g of NH₄NO₃ will decompose to produce = (1.29 × 144) / 320 = 0.58 g of H₂O

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Answer:

(a). 46,666.7 g/mol; 78,571.4 g/mol

(b). 86950g/mol; 46,666.7 g/mol.

(c). 86950g/mol; 43,333.33 g/mol

Explanation:

So, we are given the molar masses for the three samples as: 10,000, 30,000 and 100,000 g mol−1.

Thus, the equal number of molecule in each sample = ( 10,000 + 30,000 + 100,000 ) / 3 = 46,666.7 g/mol.

The average molar mass = [ ( 10,000)^2 + (30,000)^2 + 100,000)^2] ÷ 10,000 + 30,000 + 100,000 = 78,571. 4 g/mol.

(b). The equal masses of each sample = 3/[ ( 1/ 10,000) + (1/30,000 ) + (1/100,000) ] = 20930.23 g/mol.

Average molar mass = ( 10,000 + 30,000 + 100,000 ) / 3 = 46,666.7 g/mol.

(c). Equal masses of the two samples = (0.145 × 10,000) + (0.855 × 100,000)/ 0.145 + 0.855 = 86950g/mol.

The weight average molar mass = 1.7 + 10,000 + 100,000/ 1.7 + 1 = 43,333.33 g/mol.

Answer:

64.7

Explanation:

Answer:

64.7 is the answer

hope this helps

have a good day :)

Explanation:

Answer: A

Explanation: I'm not exactly sure if it is, but I've done similar work to this so

Answer:

22 g

Explanation:

Step 1: Write the balanced equation

N₂(g) + 3 H₂(g) ⇒ 2 NH₃(g)

Step 2: Calculate the moles of NH₃ produced from 2.0 moles of H₂

The molar ratio of H₂ to NH₃ is 3:2.

2.0 mol H₂ × 2 mol NH₃/3 mol H₂ = 1.3 mol NH₃

Step 3: Calculate the mass corresponding to 1.3 moles of NH₃

The molar mass of NH₃ is 17.03 g/mol.

1.3 mol × 17.03 g/mol = 22 g

Answer:

69.8%

Explanation:

k = 0.00813 sec-1

t = 44.1 s

What percentage of the compound has decomposed?

We can obtain this using the formular;

[A] = [A]o e^(-kt)

where;

Final Concentration = [A]

Initial concentration = [A]o

[A] / [A]o = e^(-kt)

[A] / [A]o  =  e^(-0.00813*44.1)

[A] / [A]o = e^(-0.359)

[A] / [A]o = 0.698

Percentage decomposed = Final Concentration / Initial concentration * 100

Percentage decomposed = [A] / [A]o   * 100%

Percentage decomposed = 0.698 * 100 = 69.8%

Based  on the data given,  the percentage decomposed in the first order reaction is 69.8%

From the data provided;

rate constant, k = 0.00813 sec-1

time, t = 44.1 s

Since the reaction is first order, we calculate using the formula below:

where;

Finding the ratio of final and initial concentration

[A]/[A]₀ = e^(-kt)

Substituting the values:

[A]/[A]₀ =  e^(-0.00813 * 44.1)

[A]/[A]₀ = e^(-0.359)

[A]/[A]₀ = 0.698

Percentage decomposed = [A]/[A]₀ * 100%

Percentage decomposed = 0.698 * 100%

Percentage decomposed = 69.8%

Therefore, the percentage decomposed in the first order reaction is 69.8%.

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Answer:

If two tectonic plates collide, they form a convergent plate boundary. Usually, one of the converging plates will move beneath the other, a process known as subduction. ... Most divergent plate boundaries are underwater and form submarine mountain ranges called oceanic spreading ridges

Explanation:

Hope this helps

Answer: c plus sign

Explanation:

The symbol that is used in the reaction is an equal sign, it is put between reactant and product. The correct option is A, an equal sign.

The representation of a reaction in the equation form is known as a chemical equation.

In the given reaction, the hydrochloric acid and potassium hydroxide undergoes a reaction and produce potassium chloride and water.

The reactants and the products are always divided with an arrow or equal sign.

HCI + KOH = KCI + H2O

Thus, the correct option is A, an equal sign.

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Answer:

Calcium is more reactive than magnesium because calcium atom is larger than magnesium atom and it has one more energy level. ... Thus Ca is more reactive than Mg.

Answer:

Germanium monoxide

hope this helps :)

Answer:

because the brian is like a computer because that both use electrical signals to send messages the brain uses chemicals to transmit information and the computer uses electricity.

Hope that was helpful

Answer:one mole of stuff (atoms, molecules, eggses), there are NA individual items of that stuff. So, there are 4.5 × NA BCl3 molecules; i.e. 4.5 × 6.022×1023 ≅ 27×1023 individual molecules of BCl3

Explanation:

Answer:

[tex]\boxed {\boxed {\sf About \ 2.7 *10^{24}\ atoms\ N }}[/tex]

Explanation:

To convert from moles to atoms, Avogadro's Number: 6.022*10²³ must be used. This number tells us the amount of particles (atoms, molecules, etc) in 1 mole of a substance. In this case, the particles are atoms of nitrogen.

[tex]\frac {6.022 *10^{23} \ atoms \ N}{1 \ mol \ N}[/tex]

Multiply by the given number of moles: 4.5

[tex]4.5 \ mol \ N *\frac {6.022 *10^{23} \ atoms \ N}{1 \ mol \ N}[/tex]

The moles of nitrogen will cancel.

[tex]4.5 \ *\frac {6.022 *10^{23} \ atoms \ N}{1 }[/tex]

The denominator of 1 can be ignored.

[tex]4.5 \ *{6.022 *10^{23} \ atoms \ N}[/tex]

[tex]2.7099*10^{24} \ atoms \ N[/tex]

The original measurement of moles had 2 significant figures, so our answer must have the same. For the number we calculated, that is the tenth place. The 0 in the hundredth place tells us to leave the 7.

[tex]2.7 *10^{24}\ atoms\ N[/tex]

There are about 2.7*10²⁴ atoms of nitrogen in 4.5 moles.

Answer:

The splash cause the volume of the block to be too high

Explanation:

This is because, from the previous measurement made by the student, the volume of the block is 5.7ml higher.

Answer:

2.0 × 10⁴ mg

Explanation:

Step 1: Given data

Mass (m): 0.020 kg

Step 2: Convert the mass from kilograms to grams

We will use the conversion factor 1 kg = 1,000 g.

0.020 kg × (1,000 g/1 kg) = 20 g

0.020 kg is equal to 20 g.

Step 3: Convert the mass from grams to milligrams

We will use the conversion factor 1 g = 1,000 mg.

20 g × (1,000 mg/1 g) = 2.0 × 10⁴ mg

20 g is equal to 2.0 × 10⁴ mg. Then, 0.020 kg is equal to 2.0 × 10⁴ mg.

Answer:

C.NH3(ammonia) is Answer.

Explanation:

I hope it's helpful!

Answer:

NH3 (Ammonia)

Explanation:

Answer:

Most manure consists of animal feces; other sources include compost and green manure. Manures contribute to the fertility of soil by adding organic matter and nutrients, such as nitrogen, that are utilised by bacteria, fungi and other organisms in the soil.

Explanation:

Hope it is helpful....

Answer:

Animal manure, such as chicken manure and cow dung, has been used for centuries as a fertilizer for farming. It can improve the soil structure (aggregation) so that the soil holds more nutrients and water, and therefore becomes more fertile. ... Manure is also commercially composted and bagged and sold as a soil amendment.

Explanation:

Answer:

O + O ---Δ----> O2

Explanation:

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Answer:

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