A U B={1,2,3,5,7}
A n B={3,5}
solution,
U=(1,2,3,4,5,6,7}
A={1,3,5,7}
B={2,3,5}
Now,
A U B
={1,3,5,7} U{2,3,5}
={1,2,3,5,7}
A n B
={1,3,5,7} n {2,3,5}
={3,5}
please see the attached picture..
Hope this helps..
Good luck on your assignment
the area of a sector of a circle of radius 15cm is 110cm², calculate the angle of subtended at yhe center of the circle by the arc?
Answer:
44/45 radians
Step-by-step explanation:
The area is given by the formula ...
A = (1/2)r²θ
where θ is the central angle in radians.
Filling in the given numbers, we have ...
110 cm² = (1/2)(15 cm)²θ
θ = (220 cm²)/(225 cm²) = 44/45 radians
The subtended angle is 44/45 radians, about 56.02°.
The area of circle Z is 64ft?.
What is the value of r?
r= 4 ft
r= 8 ft
D
r = 16 ft
Area
r= 32 ft
Z
Answer:
r=8
Step-by-step explanation:
Using the formula they gave us you could plug in the area (64) and divide it by pi which cancels out the pi so taking the square root of 64 gives you 8FT
Hope this helps :)
Answer:
8 ft
Step-by-step explanation:
[tex] \because \: r = \sqrt{ \frac{Area}{\pi} } \\ \\ \therefore \: r = \sqrt{ \frac{64\pi}{\pi} } \\ \\ \therefore \:r = \sqrt{64} \\ \\ \therefore r = 8 \: ft[/tex]
If Sam and Sally invested the same total amount at the end of three years, the amount Sam invested the first year is $ and the amount Sally invested the last year is $ .
Answer:
The amount Sam invested the first year = $2000
The amount Sally invested the last year = $1900
Complete question related to this was found at brainly (ID 4527784):
For three consecutive years, Sam invested some money at the start of the year. The first year, he invested x dollars. The second year, he invested $2,000 less than 5/2 times the amount he invested the first year. The third year, he invested $1,000 more than 1/5 of the amount he invested the first year.
During the same three years, Sally also invested some money at the start of every year. The first year, she invested $1,000 less than 3/2 times the amount Sam invested the first year. The second year, she invested $1,500 less than 2 times the amount Sam invested the first year. The third year, she invested $1,400 more than 1/4 of the amount Sam invested the first year.
If Sam and Sally invested the same total amount at the end of three years, the amount Sam invested the first year is $ and the amount Sally invested the last year is $ .
Step-by-step explanation:
First we would represent the information given with mathematical expressions.
Sam investment for 3 consecutive years:
Year 1 = x dollars
Year 2 = $2,000 less than 5/2 times the amount he invested the first year
Year 2 = (5/2)(x) - 2000
Year 3 = $1,000 more than 1/5 of the amount he invested the first year
Year 3 = (1/5)(x) + 1000
Sally investment for 3 consecutive years:
Year 1 = $1,000 less than 3/2 times the amount Sam invested the first year
Year 1 = (3/2)(x) - 1000
Year 2 = $1,500 less than 2 times the amount Sam invested the first year
Year 2 = 2x - 1500
Year 3 = $1,400 more than 1/4 of the amount Sam invested the first year.
Year 3 = (1/4)(x) + 1400
Since Sam and Sally invested the same total amount at the end of three years, we would equate their sum:
Sum of Sam investment for the 3years = x + (5/2)(x) - 2000 + (1/5)(x) + 1000
= x + 5x/2 -2000 + x/5 + 1000
= (10x+25x+2x)/10 - 1000
= 37x/10 - 1000
Sum of Sally investment for the 3years = (3/2)(x) - 1000 + 2x - 1500 + (1/4)(x) + 1400
= 3x/2 - 1000 + 2x -1500 + x/4 + 1400
= (6x+8x+x)/4 - 1100
= 15x/4 - 1100
37x/10 - 1000 = 15x/4 - 1100
37x/10 - 15x/4 = -100
(148x - 150x)/40 = -100
-2x = -4000
x = 2000
Therefore the amount Sam invested the first year = x = $2000
The amount Sally invested the last year (3rd year) = (1/4)(x) + 1400
(1/4)(2000) + 1400 = 500+1400 = 1900
The amount Sally invested the last year = $1900
Large samples of women and men are obtained, and the hemoglobin level is measured in each subject. Here is the 95% confidence interval for the difference between the two population means, where the measures from women correspond to population 1 and the measures from men correspond to population 2: negative 1.76 g divided by dL less than mu 1 minus mu 2 less than minus 1.62 g divided by dL. Complete parts (a) through (c) below.
a. What does the confidence interval suggest about equality of the mean hemoglobin level in women and the mean hemoglobin level in men? Because the confidence interval does not include includes nothing, it appears that there is is not a significant difference between the mean level of hemoglobin in women and the mean level of hemoglobin in men. (Type an integer or a decimal. Do not round.)
b. Write a brief statement that interprets that confidence interval.
A. There is 95% confidence that the interval from minus 1.76 g divided by dL to minus 1.62 g divided by dL actually contains the value of the difference between the two population means left parenthesis mu 1 minus mu 2 right parenthesis .
B. There is 95% confidence that the difference between the two population means left parenthesis mu 1 minus mu 2 right parenthesis is either minus 1.76 g divided by dL or minus 1.62 g divided by dL .
C. There is 95% confidence that the difference between the two population means is not 0.
D. There is 95% confidence that the interval from minus 1.76 g divided by dL to minus 1.62 g divided by dL does not contain the value of the difference between the two population means left parenthesis mu 1 minus mu 2 right parenthesis .
c. Express the confidence interval with measures from men being population
1. and measures from women being population
2. Choose the correct answer below.
A. negative 1.62 g divided by dL less than mu 1 minus mu 2 less than 1.76 g divided by dL
B. negative 1.76 g divided by dL less than mu 1 minus mu 2 less than minus 1.62 g divided by dL
C. 1.62 g divided by dL less than mu 1 minus mu 2 less than 1.76 g divided by dL
D. negative 1.76 g divided by dL less than mu 1 minus mu 2 less than 1.62 g divided by dL.
Answer:
(a) Because the confidence interval does not include includes 0, it appears that there is not a significant difference between the mean level of hemoglobin in women and the mean level of hemoglobin in men.
(b) The correct option is (A).
(c) The correct option is (C).
Step-by-step explanation:
The 95% confidence interval for the difference between the two population mean hemoglobin level is:
CI = (-1.76 < μ₁ - μ₂ < -1.62)
(a)
The hypothesis to test the equality of the mean hemoglobin level in women and the mean hemoglobin level in men is:
H₀: The two population means are equal, i.e. μ₁ = μ₂.
Hₐ: The two population means are not equal, i.e. μ₁ ≠ μ₂.
The (1 - α)% confidence interval can be used to draw conclusion about the hypothesis test.
Decision rule:
If the (1 - α)% confidence interval does not consist of the null value then the null hypothesis will be rejected and vice-versa.
The 95% confidence interval for the difference between the two population means is:
CI = (-1.76, -1.62)
The 95% confidence interval does not consist of the null value, i.e. 0.
Thus, the null hypothesis will be rejected.
"Because the confidence interval does not include includes 0, it appears that there is not a significant difference between the mean level of hemoglobin in women and the mean level of hemoglobin in men."
(b)
The (1 - α)% confidence interval for population parameter implies that there is a (1 - α) probability that the true value of the parameter is included in the interval.
Or, the (1 - α)% confidence interval for the parameter implies that there is (1 - α)% confidence or certainty that the true parameter value is contained in the interval.
So, the 95% confidence interval (-1.76, -1.62) implies that there is a 95% confidence that the above interval actually contains the value of the difference between the two population means, (μ₁ - μ₂).
The correct option is (A).
(c)
Now it is provided that the measures from men is denoted as population 1 and measures from women is denoted as population 2.
The confidence interval for the difference between two mean is:
[tex]CI=(\bar x_{1}-\bar x_{2})\pm MOE[/tex]
According to the information:
[tex]\bar x_{1}=\bar x_{2}\\\\\bar x_{2}=\bar x_{1}[/tex]
So, the new confidence interval will be:
[tex]CI=-(\bar x_{2}-\bar x_{1})\pm MOE[/tex]
Then the confidence interval with measures from men being population
1 and measures from women being population 2 is:
[tex]CI=(1.62<\mu_{1}-\mu_{2}<1.76)[/tex]
The correct option is (C).
What is the product of the binomials below?
Answer:
A.
Step-by-step explanation:
When you multiply the two binomials using distributive property, you get the answer A. I could display the steps since it did not let me.
Hope this helps!!! PLZ MARK BRAINLIEST!!!
How do you write r2/3 t1/3 in radical form?
I hope this helps you
The probability that Paul wins a raffle is given by the expression n/n+6. Write down an expression, in the form of a combined single fraction, for the probability that Paul does not win.
Answer:
[tex]P(W') = \frac{6}{n+6}[/tex]
Step-by-step explanation:
Let P(W) represents the probability that Paul wins
Let P(W') represents the probability that Paul does not win
Given
[tex]P(W) = \frac{n}{n+6}[/tex]
Required
[tex]P(W')[/tex]
In probability, the sum of opposite probability equals 1;
This implies that
[tex]P(W) + P(W') = 1[/tex]
Substitute [tex]P(W) = \frac{n}{n+6}[/tex] in the above equation
[tex]P(W) + P(W') = 1[/tex] becomes
[tex]\frac{n}{n+6}+ P(W') = 1[/tex]
Subtract [tex]\frac{n}{n+6}[/tex] from both sides
[tex]\frac{n}{n+6} - \frac{n}{n+6} + P(W') = 1 - \frac{n}{n+6}[/tex]
[tex]P(W') = 1 - \frac{n}{n+6}[/tex]
Solve fraction (start by taking the LCM)
[tex]P(W') = \frac{n + 6 - n}{n+6}[/tex]
[tex]P(W') = \frac{n - n + 6}{n+6}[/tex]
[tex]P(W') = \frac{6}{n+6}[/tex]
Hence, the probability that Paul doesn't win is [tex]P(W') = \frac{6}{n+6}[/tex]
Sammy and Pippa's teacher gives them a homework question to solve. She tells them to plot the points A(5, -1), B(9, 4), C(15, 1) and D(11, -4) on a grid and decide whether the shape is a square or a rhombus. Sammy and Pippa do their slope calculations and Sammy insists the shape is a square whereas Pippa insists the shape is a rhombus. Who is right? Show your calculations in your reasoning
Answer:
Pippa
Step-by-step explanation:
A square has
parallel opposite sides perpendicular adjacent sides perpendicular diagonalsA rhombus has
parallel opposite sides non-perpendicular adjacent sides perpendicular diagonalsThus, we can identify the shape by comparing the slopes of the adjacent sides.
1. Draw the shape
See the graph below
2. Calculate the slope of AB
m = (y₂ - y₁)/(x₂ - x₁) = (4 - (-1))/(9 - 5) = (4 + 1)/4 = 5/4
3. Calculate the slope of BC
If BC⟂AP, its slope should be -4/5 .
m = (y₂ - y₁)/(x₂ - x₁) = (1 - 4)/(15 - 9) =-3/6 = -1/2
½ ≠ -⅘
The two lines are not perpendicular.
Pippa is right. The shape is a rhombus.
Solve for a 7a - 2b = 5a + b
Answer:
a=1.5b
Step-by-step explanation:
Add 2b on both sides to get 7a=5a+3b
Subtract 5a
2a=3b
divide by 2
a=1.5b
Towns K and L are shown on a map-
a) Work out the actual distance
between towns K and L.
b) A third town, M, is 150 km due
South of town K.
Mark M on the map with X.
c) Measure the bearing of town L
from town K.
Answer:
a) Use a ruler for the measurement.
b) convert to centimetres then use a ruler to draw the unit on the diagram.
c) measure the angle between K and L from K
See explanations below
A complete question related to this found on brainly (ID:15577387) is stated below.
Towns K and L are shown on a map.
a) Work out the actual distance
between towns K and L.
b) A third town, M, is 150 km due
South of town K.
Mark M on the map with X.
c) Measure the bearing of town L
from town K.
Scale: 1cm represent 50km
Step-by-step explanation:
Scale: 1cm represent 50km
a) To find the actual distance between towns K and L use a ruler to measure the distance between K and L.
Your answer would be in centimetres (cm).
The answer obtained would be multiplied by 50km because from the scale given 1cm represent 50km.
Therefore you'll get the actual distance in km.
b) Here we are told M is 150 km due
South of town K.
Since the length of the initial diagram is in centimeters, we have to find how many centimeters equals 150km.
50km = 1cm
150km = (150km × 1cm)/50km = 150cm/50
150km = 3cm
Now we can represent the distance between K and M on the diagram.
Measure 3cm from K using a ruler in the direction of south (straight line downwards). The distance of M from K would be 3cm on the south of k.
c) Draw a cross on the position of K. Also draw a cross on the position of L. Connect the distance and measure the angle from K to L. The unit would be in degrees.
From the diagram, the angle is greater than 090° but less than 180°
Find attached the diagram.
Answer:
a) 100 km
b) check the photo of my work
c) 117 degrees
Step-by-step explanation:
To get full marks take a look at the photo of my work.
Question (b) use a compass and make sure it’s 3cm aiming down {South} as u can see in the photo, then draw a line aiming {South} with a ruler. On the end of the line you put the (x) point there to get the mark.
Thank you
Adler and Erika solved the same equation using the calculations below.
Adler's Work
Erika's Work
13 - 3 - 4+* -
OCD
Which statement is true about their work?
Answer:
Both Adler and Erika solved for k correctly.
Explanation:
Either the addition property of equality or the subtraction property of equality can be used to solve for k.
Answer:
Both adler and erika are correct
Step-by-step explanation:
just took it on edg
Five times a number decreased by nine is equal to twice the number increased by 23. Which equation could be used to solve the problem? 5x – 9 = x + 23 5x – 9 = 2x + 23 5x + 23 + 2x = 23 5x + 23 = 2x + 23
Answer:
5x - 9 = 2x + 23
Step-by-step explanation:
5 times a number is represented by 5x, with x representing the unknown number.
5x decreased by 9 is (5x - 9) since 9 is being subtracted by 9.
(5x - 9) is equal to twice the number (2x), increased by 23.
So, the equation is (2x + 23).
Therefore, 5x - 9 = 2x + 23
The equation is 5x - 9 = 2x + 23.
The answer is option A.
Which equation could be used to solve the problem?5 times a number is represented by 5x, with x representing the unknown number.
5x decreased by 9 is (5x - 9) since 9 is being subtracted by 9.
(5x - 9) is equal to twice the number (2x), increased by 23.
So, the equation is (2x + 23).
Therefore, 5x - 9 = 2x + 23
What is an equation example?
An equation is a mathematical announcement this is made up of expressions related to the same signal. For instance, 3x – 5 = 16 is an equation. Fixing this equation, we get the price of the variable x as x = 7.
Learn more about the equation here: https://brainly.com/question/1214333
#SPJ2
1. Find the sum to
(a) 8 terms of 3 + 6 + 12 + .....
(b) n terms of 27/8+9/4+3/2+....
note(u can do only that was desplayed bybthe attachment
Answer:
7 1/8
57/8
Hope this helps :)
. Mr. Wayne has a 3-year contract for his cell phone service. He pays $124.65 each month to cover everyone in his family. How much will the cell phone service cost over the 3-year period? Explain your answer
Answer:
$4,523.40
Step-by-step explanation:
The cell phone cost is $124.65 per month. With 12 months in a year, we multiply $124.65 x 12 to get the answer $1,507.80. Since one year equals $1,507.80, we multiply this answer by 3 for 3 years to get $4,523.40. Thus three years of service with $124.65 a month would equal $4,523.40.
ε = {x: 2 x 30, x is an integer}, M = {even numbers}, P = {prime numbers}, T = {odd numbers} Find: I) MUP ii) M - T iii) P(MT) iv) P’U(MT’)
Answer:
Step-by-step explanation:
ε = {x: 2≤ x ≤30}
M = { even numbers} = {2,4,6,8,10,12,14,16,18,20,22,24,26,28,30}
P = { prime numbers} = {2,3,5,7,11,13,17,19,23,29}
T = {odd numbers} = {3, 5, 7, 9, 11,13,15,17,19,21,23,25,27,29}
1. M ∪ P = {2,3,4,5,6,7,8,10,11,12,13,14,16,17,18,19,20,22,23,24,26,28,29,30}
2. M - T =
n(M) - n(T)
15- 14 = 1
3. P(MT)
(MT) = M ∩ T = 0
P ∪ (M ∩ T ) = {2,3,5,7,11,13,17,19,23,29}
4. P' = not a prime number
T' = not odd number = M
P' ∪(M∩T')
P' ∪ {2,4,6,8,10,12,14,16,18,20,22,24,26,28,30}
= {2,4,6,8,9,10,12,14,15,16,18,20,21,22,24,25,26,27,28,30}
The box plots show the average speeds, in miles per hour, for the race cars in two different races. Average Speeds of Cars in Race A 2 box plots. The number line goes from 120 to 170. For Race A, the whiskers range from 120 to 170, and the box ranges from 143 to 165. A line divides the box at 153. For Race B, the whiskers range from 125 to 165, and the box ranges from 140 to 150. A line divides the box at 145. Average Speeds of Cars in Race B
Answer:
The median speed in race A is about 153 miles per hour, and the median speed in race B is about 145 miles per hour.
Step-by-step explanation:
For comparison, we need to analyze and compare both races data which are as follows
For Race A
Maximum range = 170 miles per hour
Minimum range = 120 miles per hour
First quartile ≈ 142 miles per hour
Median quartile ≈ 153 miles per hour
It comes from
[tex]= \frac{142\ miles + 165\ miles}{2}[/tex]
= 153 miles
The Third quartile = 165 miles per hour
For Race B
Maximum range = 165 miles per hour
Minimum range = 125 miles per hour
First quartile ≈ 139 miles per hour
Median quartile = 145 miles per hour
It comes from
[tex]= \frac{139\ miles + 150\ miles}{2}[/tex]
= 145 miles
The third quartile = 150 miles per hour
Hence, the last option is correct
Type the missing number in this sequence
Answer:
50
Step-by-step explanation:
the missing number is 50
Answer:
50
Step-by-step explanation:
Every number is being multiplied by 10
Hope this helps you out! :)
the picture is the qestion
Answer:
the first option
Step-by-step explanation:
3/3 is equal to one so when you multiply 5/6 by one it stays the same but in this case it equals 15/18
The first law of thermodynamics states that ΔE= Q− W. Is this also a statement of the principle of conservation of energy? No, the heat that is added to the system is only used to do work. No, the change in internal energy is the energy lost in the system. Yes, the heat added and the change in internal energy of the gas equal the work done by the piston. Yes, the heat that flows into the system is used to change the internal energy of the gas and becomes work done by the piston.
Answer:
yes
Step-by-step explanation:
as we see in the picture the variation of the internal energy of a system is W-Q by analogie we get the second relation in the 2nd picture wich is the first law of thermodynamics
Answer:
Yes, the heat that flows into the system is used to change the internal energy of the gas and becomes work done by the piston.
Step-by-step explanation:
I took the K12 test :)
Al saves pennies. He agreed to give six thirteenths of his pennies to Bev if she would give six thirteenths of what she got from Al to Carl and if Carl in turn would give six thirteenths of what he got from Bev to Dani. Bev, Carl, and Dani agreed and Dani received 2376 pennies. How many pennies did Al have initially?
Answer:
Step-by-step explanation:
Let x represent the number of pennies that Al had initially.
He agreed to give six thirteenths of his pennies to Bev. It means that the number of pennies that he gave to Bev is 6/13 × x = 6x/13
if she would give six thirteenths of what she got from Al to Carl, it means that the number of pennies that Carl received is 6/13 × 6x/13 = 36x/169
if Carl in turn would give six thirteenths of what he got from Bev to Dani and Dani received 2376 pennies, it means that
6/13 × 36x/169 = 2376
216x/2179 = 2376
216x = 2376 × 2179
216x = 5220072
x = 5220072/216
x = 24167
AI had 24167 pennies initially
Work out the mean for the data set below:
3, 5, 4, 3, 5, 6
Give your answer as a fraction
Answer:
13/3
Step-by-step explanation:
To find the mean of a data set, you must add all the given numbers and then divide the numbers by how many numbers there are.
3+5+4+3+5+6=26/6=4.3333...
When we convert the answer from a decimal to a fraction, we get 13/3.
Hope this helps!!! PLZ MARK BRAINLIEST!!!
In a coin jar, there are 45 nickels. The number of pennies and nickels together equal the number of dimes. There are 2 quarters for every 3 nickels and 2 dimes for every quarter. Complete the table: Pennies Nickels Dimes Quarters 45
Answer:
15 45 60 30
Step-by-step explanation:
Answer:
15 45 60 30
Step-by-step explanation:
the person above me is right and so am I I promise it's correct just did it on Time 4 Learning
QT and PM
trianglePQR. If QR = 8 cm, PR 7 cm and
QT = 4 cm, what is PM?
P=7 cm
M=8 cm
Answer:
The length of the altitude PM is 3.5 cm.
Step-by-step explanation:
We are given that QT and PM are the altitudes of the triangle PQR. Also, QR = 8 cm, PR = 7 cm and QT = 4 cm.
We have to find the length of the altitude PM.
As we know that the area of the triangle is given by;
Area of triangle = [tex]\dfrac{1}{2} \times \text{Base} \times \text{Height(Altitude)}[/tex]
Here, in [tex]\triangle[/tex]PQR; Base = PR = 7 cm
Height(Altitude) = QT = 4 cm
So, the area of the triangle PQR = [tex]\frac{1}{2} \times 7 \times 4[/tex]
= 14 sq cm.
Similarly, the area of the triangle can also be;
Area = [tex]\frac{1}{2} \times \text{QR} \times \text{PM}[/tex]
Here, QR = Base of triangle PQR = 8 cm
PM = the required altitude
So, Area of triangle = [tex]\frac{1}{2} \times 8\times \text{PM}[/tex]
[tex]14 =4 \times \text{PM}[/tex]
PM = [tex]\frac{14}{4}[/tex] = 3.5 cm
Hence, the length of the altitude PM is 3.5 cm.
The graph shows the function f(x) = 2*
What is the value of xwhen f(x) = 8?
Answer:
x=3
Step-by-step explanation:
f(x) = 2^x
Let f(x) =8
8 = 2^x
Rewriting 8 as 2^3
2^3 = 2^x
The bases are the same so the exponents are the same
3=x
Answer:
A. 3
Step-by-step explanation:
y = 2^x
y = 8
Plug y as 8 in the first equation.
8 = 2^x
Make the left side of the equation with a base of 2.
2^3 = 2^x
Cancel bases.
3 = x
What is the measure for the following<
M
m= if i get the Diagram i will answer
Select all that are true.
Answer:
1
2
6
Step-by-step explanation:
1/2 +1/2 =1
length 1/2 ×4=2
wide 1/2 ×3 =1 1/2
height 1/2×3= 1 1/2
There are 4 grams of fiber in 1 over 2 cup of oats. How many grams of fiber are in 3 and 1 over 2 cups of oats?
Answer:
28 grams
Step-by-step explanation:
each cup contains 8 grams 8*3 =24 plus the last half cup which contains 4 grams which brings the total to 28
Which is the graph of f(x) = (2)-x
Answer:
Use a graphing calc.
Step-by-step explanation:
Answer:
b
Step-by-step explanation:
Find the roots of the function f(x) = (2^x − 1) - (x2 + 2x − 3) with x ∈ R.
Answer: There are no real roots.
Step-by-step explanation:
To find the roots of the function
f(x) = (2^x − 1) - (x2 + 2x − 3) with x ∈ R.
First open the bracket
2^x - 1 - x^2 - 2x + 3 = 0
Rearrange and collect the like terms
2x^2 - x^2 - 2x + 3 - 1= 0
X^2 - 2x + 2 = 0
Factorizing the above equation will be impossible, we can therefore find the root by using completing the square method or the quadratic formula.
X^2 - 2x = - 2
Half of coefficient of x is 1
X^2 - 2x + 1^2 = -2 + 1^2
( x - 1 )^2 = - 1
( x - 1 ) = +/- sqrt(-1)
X = -1 + sqrt (-1) or -1 - sqrt (-1)
The root of the function is therefore
X = -1 + sqrt (-1) or -1 - sqrt (-1)
Since b^2 - 4ac of the function is less than zero, we can therefore conclude that there is no real roots
Find X. Do not round your Answer
Answer:
83/5, 16.6, 16 3/5
Step-by-step explanation:
When two secant segments are drawn to a circle from an external point, the product of one secant segment and its external segment equals the product of the other secant segment and its external segment.
6 times 18 = 5(5+x)
The total secant segment is 6+12=18
so one side = 6 times 8.
The line from the circle (but not inside) is 5.
You don't know the entire segment, but you do know that 5 is part of it. Hence 5 times (5+x).
Sorry for the trashy explanation.
Answer:
16.6Step-by-step explanation: