Which function represents uninhibited growth?
The uninhabited growth represented by the function is [tex]N(t) = N_0e^{kt}[/tex]. The correct option is A.
What is uninhabited growth?Uninhibited Growth and Decay Models: Things that expand or deteriorate in a limitless, proportional manner are said to exhibit "uninhibited" growth or decay. Examples include population increase, bacterium growth, and radioactive decay.
Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.
The expression for the uninhabited growth is,
[tex]N(t) = N_0e^{kt}[/tex]
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i need help please help
Answer:
option 4 is correct answer of this question
6/x^3
Step-by-step explanation:
hope it helps and your day will be full of happiness
Pretty pretty please if ur good at geometry!! Help a girl out!!
Answer:
Yes, They are similar by SSS PMK similar to LMQ.
Step-by-step explanation:
Similar triangles corresponding side lengths are in a proportion.
KM corresponds with MQ
PM corresponds with LM.
Set up this proportion.
[tex] \frac{km}{pm} = \frac{lm}{mq} [/tex]
[tex] \frac{15}{28} = \frac{21}{39.2} [/tex]
Cross multiply
[tex]588 = 588[/tex]
So the triangles ARE Similar.
PM corresponds with LMKM corresponds with MQPK corresponds with LQSo PMK is similar to LMQHow does the graph of the
function g(x) = 3x + 4 differ from
the graph of f(x) = 3X?
It is moved (a). unit(s) (b)
Answer:
Math (way) is good if you wanna try that.
ee
Step-by-step explanation:
Answer:
the graph of f(x) = 7x. 3x + 4 = 7x
Poppy has one bag of beads. She is going to make three difference necklaces.
For the first necklace, she needs 3/8 of a bag of beads. For the second, she
needs 1/8 of a bag of beads. For the third, she needs 5/8 of a bag. What
fraction of a bag of beads does she need? Does she have enough? Explain.
Answer:
9/8 of a bag
she doesn't have enough beads.
Step-by-step explanation:
Bag of bead poppy has = 1
Bag of bead needed for necklace 1 = 3/8 of a bag
Bag of bead needed for necklace 2 = 1/8 of a bag
Bag of bead needed for necklace 3 = 5/8 of a bag
Total bag of beads needed = 3/8 + 1/8 + 5/8
= (3+1+5)/8
= 9/8
She needs 9/8 of a bag of bead
9/8 = 1 1/8
Therefore, she doesn't have enough beads.
The first term in a sequence is 13. The term to term rule is "take away 5" write an expression in terms of n , for the nth term of the sequence
9514 1404 393
Answer:
an = 13 -5(n -1)
Step-by-step explanation:
The "take away 5" rule means the common difference between terms is d=-5. For first term a1=13, the n-th term is ...
an = a1 +d(n -1)
an = 13 -5(n -1)
Slove the system
Linear equations
by substation
Y+11=6x
2x+3y=7
Step-by-step explanation:
y = 6x-11
substitute y into 2x+3y=7
2x+3(6x-11)=7
2x + 18x-33 = 7
20 x = 7+33
x = 2
y?
y= 6(2)-11
y = 12-11 = 1
so, x = 2 and y = 1
A bag contains 25 marbles (5 red ones, 8 ue ones and 12 yellow ones.) When a marble is picked at a random one at a time from the bag and not put back into the bag, what is the chance of picking a yellow one twice in a row?
Answer:
The chance of picking a yellow marble twice in a row without replacement is 0.22
Step-by-step explanation:
The given number of marbles in the bag = 25 marbles
The number of red marbles in the bag = 5 red marbles
The number of blue marbles in the bag = 8 blue marbles
The number of yellow marbles in the bag = 12 yellow marbles
The chance of picking a yellow marble = 12/25
The chance of picking another yellow when the first one is not replaced = 11/24
Therefore, the chance of picking a yellow marble twice in a row = 12/25 × 11/24 = 1/25 × 11/2 = 11/50
Therefore;
The chance of picking a yellow marble twice in a row without replacement = 11/50 = 0.22
ALL MY POINTS FOR THIS QUESTION!!! SHOW WORK! SHOW WORK! SHOW WORK! EXPLAIN!!!!
Answer:
2 should be added to the data
Step-by-step explanation:
Hope this helps!
If im wrong im sorry!
Answer:
18 should be added
Step-by-step explanation:
So we have one 10 and one 11 in this data set, and we need to figure out which number we need to add to get a mean of 13
let's make this unknown number x
to find the mean, we add up all the values of the numbers on the data set, and divide it by how many numbers we have.
we have 3 numbers, and our numbers are 10, 11, and x. When we add 10, 11, and x together, and then divide by 3, the value is 13
as an equation we will have:
(10+11+x)/3=13
combining like terms in the numerator, it will be:
(21+x)/3=13
We need to solve this equation, and the denominator of 3 just makes harder to do that.
Clear the fraction by multiplying both sides by 3
21+x=39
subtract 21 from both sides
x=18
so that means that 18 should be added to the data set to get a mean of 13.
Hope this helps!
in slope intercept form slope=2/7 y-intercept=0
Answer:
y=2/7x
Step-by-step explanation:
y=mx+b where m=slope and b=y-intercept
y=2/7x+0
y=2/7x
Find the slope that passes. through the two points (5-8 and (4,6)
Answer:
-14
Step-by-step explanation:
Line is passing through the points (5, -8) and (4, 6).
Therefore,
[tex]slope = \frac{ - 8 - 6}{5 - 4} \\ \\ = \frac{ - 14}{1} \\ \\ = - 14[/tex]
TSA
6. What is the total surface area of the
rectangular solid?
A. 62 m2
B. 56 m2
C. 30 m2
D. 37 m2
Answer:
C i think
Step-by-step explanation:
help!!!!? pleaseeeeee
Answer:
19.47
Step-by-step explanation:
I plugged it into a right triangle trig calculator
Answer:
HERE ARE SOME NOTES ON HOW TO DO these types of geo- problems and some more ! SORRY .
See attachment below!
Step-by-step explanation:
If your in High school Geometry, I could help with that and more!
If your someone who likes to have Notes.. I could send you some PDF's and more for Geometry!! I took Geometry and have good notes!
Please contact me for any concerns or questions!1.02 sinusoidal graph
WHAT IS THE AMPLITUDE OF THE SINUSOIDAL FUNCTION?
Enter your answer in the box.
___
Answer:
[tex]\displaystyle 5[/tex]
Step-by-step explanation:
[tex]\displaystyle \boxed{y = -5cos\:(\frac{39}{64}\pi{x} + \frac{\pi}{2}) + 1} \\ \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{32}{39}} \hookrightarrow \frac{-\frac{\pi}{2}}{\frac{39}{64}\pi} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{3\frac{11}{39}} \hookrightarrow \frac{2}{\frac{39}{64}\pi}\pi \\ Amplitude \hookrightarrow 5[/tex]
OR
[tex]\displaystyle \boxed{y = -5sin\:(\frac{39}{64}\pi{x} + \pi) + 1} \\ \\ y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-1\frac{25}{39}} \hookrightarrow \frac{-\pi}{\frac{39}{64}\pi} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{3\frac{11}{39}} \hookrightarrow \frac{2}{\frac{39}{64}\pi}\pi \\ Amplitude \hookrightarrow 5[/tex]
As you can see, the right-centred photograph displays the trigonometric graph of [tex]\displaystyle y = -5cos\:\frac{39}{64}\pi{x} + 1,[/tex]in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph farthest to the left], accourding to the horisontal shift formula above. Also keep in mind that −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so be very careful with your calculations. So, between both photographs, we can tell that the cosine graph [centre right photograph] is shifted [tex]\displaystyle \frac{32}{39}\:unit[/tex]to the right, which means that in order to match the sine graph [photograph farthest to the left], we need to shift the graph BACKWARD [tex]\displaystyle \frac{32}{39}\:unit,[/tex]which means the C-term will be negative, and by perfourming your calculations, you get [tex]\displaystyle \boxed{-\frac{32}{39}} = \frac{-\frac{\pi}{2}}{\frac{39}{64}\pi}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = -5cos\:(\frac{39}{64}\pi{x} + \frac{\pi}{2}) + 1.[/tex]Intermediate, we have two sine graphs [centre left photograph and the photograph farthest to the left]. The left-centred photograph displays the trigonometric graph of [tex]\displaystyle y = -5sin\:\frac{39}{64}\pi{x} + 1.[/tex]So, just like before, we need to figure out the appropriate C-term that will horisontally shift the graph back into position ["position", meaning shifting this sine graph back in plase (matching the sine graph in the photograph on the left)]. So, between the two photographs, we can tell that the left-centred sine graph is shifted [tex]\displaystyle 1\frac{25}{39}\:unit[/tex]to the right, which means that in order to match the leftward sine graph, we need to shift the graph BACKWARD [tex]\displaystyle 1\frac{25}{39}\:unit,[/tex]which means the C-term will be negative, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-1\frac{25}{39}} = \frac{-\pi}{\frac{39}{64}\pi}.[/tex]So, when shifted back into original position, the sine graph is [tex]\displaystyle y = -5sin\:(\frac{39}{64}\pi{x} + \pi) + 1.[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [-6\frac{22}{39}, 1],[/tex]from there to [tex]\displaystyle [-3\frac{11}{39}, 1],[/tex]they are obviously [tex]\displaystyle 3\frac{11}{39}\:units[/tex]apart, telling you that the period of the graph is [tex]\displaystyle 3\frac{11}{39}.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, and in case you want to be certain, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 1,[/tex]in which each crest is extended five units beyond the midline, hence, your amplitude. Now... the sine graph in the photograph farthest to the right is the OPPOCITE of the sine graph in the photograph farthest to the left, and the reason for this is because of the negative inserted in front of the amplitude value. Whenever you insert a negative in front of the amplitude value of any trigonometric equation, the whole graph reflects over the midline. Keep this in mind moving forward. So, overall, no matter how far the graph shifts vertically, the midline will ALWAYS follow.
I am delighted to assist you at any time.
Can someone solve only this it’s shorttt, pleaseeeee I only have 5 minutes
Express 90 as the product of its prime factors.
Write the prime factors in ascending order.
|
I
Answer:
fafafasda
Step-by-step explanation:
wdwasdsa wr 1+11123121
Pleaseeeeee helpppppp fasttttttt 11 pointssss
Answer:
x = 9
m∠1 = m∠2 = 54°
Step-by-step explanation:
Two lines r and s are the parallel lines and a transversal line is intersecting these lines at two distinct points.
a). ∠1 ≅ ∠2 [Corresponding angles]
Therefore, m∠1 = m∠2
(63 - x)° = (72 - 2x)°
2x - x = 72 - 63
x = 9
b). m∠1 = (63 - x)°
= 63 - 9
= 54°
m∠2 = (72 - 2x)°
= 72 - 18
= 54°
Write a polynomial with 5 terms in standard form.
Identify the leading coefficient and the degree of the polynomial and name the polynomial.?
Answer:
Step-by-step explanation:
5x⁴ - 2x³ + 12x² + 24x - 26
Degree = 4
Leading term = 5x⁴
Leading coefficient = 5
Evaluate the expression 1/4y + 10 + y2
Answer:
9/4y+10
Step-by-step explanation:
1/4y+10+2y
9/4y+10
unless u meant y^2 then the answer would be
0.25(y+40+4y^2)
Help me with this please
Answer:
Slope is equal to the change in y over the change in x , or rise over run.
m=change in y/ change in x
The change in x is equal to the difference in x-coordinates (also called run), and the change in y is equal to the difference in y-coordinates (also called rise).
m=y2−y1/x2−x1
Substitute in the values of x and y into the equation to find the slope.
m=0−(2)/9−(5)
Simplify.
m=−12
Step-by-step explanation:
Answer: (7, 1)
Midpoint formula = ([tex]\frac{x1 , x2}{2}[/tex] , [tex]\frac{y1, y2}{2}[/tex])
5 + 9 / 2 = 7
2 + 0 / 2 = 1
4x2-24x+34=0 answer rounded to the nearest hundredth ASAP PLEASEEE ILL GIVE 20 POINTS AND A BRAINLIEST
Answer:
x=[tex]-3+\frac{1}{2}\sqrt{2}[/tex]
x=[tex]-3+\frac{-1}{2} \sqrt{2}[/tex]
Step-by-step explanation:
a. Calculate the average yearly rate of change in home runs hit from 1990
to 1992.
Answer:
Step-by-step explanation:
Use the rise over run formula
y2-y1/x2-x1
1992-1990/3317-3038
2/-279
-139.5
1. A coin is tossed and a single die is rolled. What is the theoretical
probability that the coin shows tails and the die shows an even number?
1/4
1/2
3/6
1/3
Answer:
A
Step-by-step explanation:
The chance the coin will show 'tails' is 1/2, since there are only 2 sides to a coin. The chance that the die will show an even number is also 1/2, since half of the numbers on a die are even, and half are odd. But, since both of these events depend on each other, or in other words, are dependent, we have to multiply both numbers. 1/2 x 1/2 = 1/4, therefore your answer is A.
Can someone pls give me the answer?
Answer:
2/5
Step-by-step explanation:
It's 2/5 because it goes up 2 and over 5
Answer:
A hope this helps
Step-by-step explanation:
PLZ PLZ HELP!! BRAINLIEST IF RIGHT!!
Describe the error in the work below.
Problem 3. Jurainy and Rayhana love to bake cookies. Jurainy can bake 60 cookies in an hour, while
Rayhana can bake 80 cookies within an hour. They started to bake at 6:30 a.m. and agreed to make
the same number of cookies
8. How many cookies can each of them bake?
a 120 cookies b. 180 cookies
c. 240 cookies
d. 400 cookies
Answer:
C
Step-by-step explanation:
I need help!
The foot of a ladder is placed 77 meters from a wall. If the top of the ladder rests 99 meters up on the wall, how long is the ladder?
Pls help me I'm stuck!
Answer:
∠S = 151°
Step-by-step explanation:
Hello there!
This is an irregular pentagon
If you didn't know the sum of the interior angles add up to equal 540
We must solve for x to be able to find the measure of angle S
we can use this equation to solve for x
540 = 5x + 2 + 10x - 3 + 7x - 11 + 13x - 31 + 8x - 19
step 1 combine like terms
2 - 3 - 11 - 31 - 19 =-62
5x + 10x +7x + 13x + 8x = 43x
so now we have
540 = 43x - 62
step 2 add 62 to each side
-62 + 62 cancels out
540 + 62 = 602
now we have
602 = 43x
step 3 divide each side by 43
43x/43 = x
602/43=14
we're left with x = 14
Now we want to plug in x for angle S
13(14) - 31
13*14=182
182-31=151
So we can conclude that the measure of angle S is 151 degrees
A line passes through (2,4) and (-2,2)
a)Find the value of y if (6,y) lies on the
plane
b)Does this line pass through the point of
origin?
c)Does this tine intersect with the line
V=-X+32
d)lf your answer was yes in b, in which
quadrant did they intersect?
Answer:
a) The value of [tex]y[/tex] is 6.
b) This line does not pass through the point of origin.
c) [tex]y = \frac{1}{2}\cdot x + 3[/tex] intersects with [tex]y = -x+32[/tex].
d) Both [tex]y = \frac{1}{2}\cdot x + 3[/tex] and [tex]y = -x+32[/tex] intersect in the first quadrant.
Step-by-step explanation:
a) By Analytical Geometry, we know that an equation of the line can be found by knowing the coordinates of two distinct points on the plane. The equation of the line is defined by this formula:
[tex]y = m\cdot x + b[/tex] (1)
Where:
[tex]x[/tex] - Independient variable.
[tex]y[/tex] - Dependent variable.
[tex]m[/tex] - Slope.
[tex]b[/tex] - x-Intercept.
To determine the slope and x-intercept of the equation of the line, we have to solve the following system of linear equations:
[tex]m\cdot x_{1}+b = y_{1}[/tex] (2)
[tex]m\cdot x_{2}+b = y_{2}[/tex] (3)
If we know that [tex](x_{1}, y_{1} ) = (2,4)[/tex] and [tex](x_{2}, y_{2}) = (-2, 2)[/tex], then the solution of the system is:
[tex]m = \frac{1}{2}[/tex], [tex]b = 3[/tex]
Then, the equation of the line is [tex]y = \frac{1}{2}\cdot x + 3[/tex]. If we know that [tex]x = 6[/tex], then the value of [tex]y[/tex] is:
[tex]y = 6[/tex]
The value of [tex]y[/tex] is 6.
b) If this line passes through the point of origin, then the value of [tex]y[/tex] must be zero for [tex]x = 0[/tex]. If we know that [tex]y = \frac{1}{2}\cdot x + 3[/tex] and [tex]x = 0[/tex], then the value of [tex]y[/tex] is:
[tex]y = 3[/tex]
The line does not pass through the point of origin since x-intercept is not zero.
c) A system of two linear equations always has an unique solution if and only if slopes and x-intercepts are different to each other. This condition is satisfied by [tex]y = -x+32[/tex], so we conclude that both lines intersect each other.
d) (Note: Question was incorrectly written. Correct form is: If your answer was yes in c, in which quadrant did they intersect?)
First, we solve the following system of linear equations:
[tex]\frac{1}{2}\cdot x -y = -3[/tex] (4)
[tex]-x-y = -32[/tex] (5)
The solution of this system is [tex](x,y) = (19.333, 12,667)[/tex], which means that both lines intersects each other in the first quadrant.