Answer:
-27 C converted to Kelvin is 246.15 Kelvin.
Explanation:
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Answer:
246.15K
Explanation:
Formula: (-27°)C + 273.15 = 246.15K
Identify the products in the reaction HCI + NaOH → NaCl + H20.
A. HCI, NaOH, NaCl, and H2O
B. HCl and NaOH
C. NaCl and H20
D. NaOH and H20
The products in the reaction HCI + NaOH → NaCl + H20, are C. NaCl and H20.
How are these the products ?The reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) is a neutralization reaction, which means that it produces a salt and water. In this case, the salt is sodium chloride (NaCl) and the water is H2O.
The other options are not correct because they do not include all of the products of the reaction. Option (A) includes HCl and NaOH, but it does not include H2O. Option (B) only includes HCl and NaOH. Option (D) only includes NaOH and H2O.
In conclusion, option C is correct.
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2) Which liberates the most energy?
A) F(g) + e ➡️ F-(g)
B) N(g) +e- ➡️ N-(g)
C) O(g) +e ➡️ O-(g)
D) C(g) +e ➡️ C-(g)
Answer: [tex]F(g)+e^-\rightarrow F^-(g)[/tex]
Explanation:
Electron gain enthalpy is defined as energy released on addition of electron to an isolated gaseous atom.
The amount of energy released will be maximum when the tendency to attract electrons is maximum. As flourine has atomic number of 9 and has electronic configuration of 2,7. It can readily gain 1 electron to attain stable noble gas configuration and hence liberates maximum energy.
[tex]F(g)+e^-\rightarrow F^-(g)[/tex]
An increase in the volume of a substance because of an increase in temperature is called
Answer:
Its called contraction.
Explanation:
Calculate the energy of a photon emitted when an electron in a hydrogen atom undergoes a transition from =3 to =1.
Answer:
[tex]1.936\times 10^{-18}\ \text{J}[/tex]
Explanation:
[tex]R_h[/tex] = Rydberg constant = [tex]2.178\times 10^{-18}\ \text{J}[/tex]
[tex]n_i[/tex] = Initial shell = 3
[tex]n_f[/tex] = Final shell = 1
We have the relation
[tex]\Delta E=R_h(\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2})\\\Rightarrow \Delta E=2.178\times 10^{-18}(\dfrac{1}{1^2}-\dfrac{1}{3^2})\\\Rightarrow \Delta E=1.936\times 10^{-18}\ \text{J}[/tex]
The energy of the photon emitted here is [tex]1.936\times 10^{-18}\ \text{J}[/tex].
What is the amount of diamine silver that can be formed when 10.00 g AgCl is mixed with 1.00 L of 0.100 M NH3?
The amount of diamine silver chloride = 8.87 g
Further explanationGiven
10 g AgCl
1.00 L of 0.100 M NH3
Required
the amount of diamine silver
Reaction
AgCl + 2 NH₃ → [Ag(NH₃)₂]Cl
mol AgCl :
= mass : MW
= 10 g : 143,32 g/mol
= 0.0698
mol NH₃ :
= M x V
= 0.1 x 1
= 0.1
NH₃ as a limiting reactant
mol [Ag(NH₃)₂]Cl based on NH₃ :
= 1/2 x mol NH₃
= 1/2 x 0.1
= 0.05
Mass diamine silver :
= 0.05 x 177.3822 g/mol
= 8.87 g
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Answer:
I hope I can help
Explanation:
I hope I can help you
I gave brainlest:: answer this .....
5. If all the particles in a material are made up of
several smaller particles, and every larger particle
is identical, is the material a pure substance or
not? Explain your reasoning.
Answer:
No. Because a pure substance, no matter if an element, compound, it can only contain one kind of particle .
Explanation:
Suppose you have a mixture of iron filings, sand, and sugar and you want to separate the three. Fill in the materials you expect to see at each step as you perform the actions shown to separate them. The materials you may expect to see are: iron filings, sand, sugar, and sugar water.
Answer:
Explanation:
mixture of iron filings, sand, and sugar
First Step - Iron Fillings
Use a magnet to separate the iron fillings from the mixture. Due to magnetic properties of the iron fillings, the magnets would attract the iron fillings and separate it from the mixture.
Second step - Sand
Place the sand and sugar mixture in water. The sugar would dissolve in water and the sand easily separated by filtration.
Third step - Sugar and Sugar water
Boil the sugar water to remove the water and place in the refrigerator for crystallization of the sugar.
How many grams are there in 3.4 x 10^24 atoms of He?
Group of answer choices
2.07
5.7 g
0.57 g
20.7
Given :
Number of He atoms, [tex]n = 3.4\times 10^{24}[/tex] atoms.
To Find :
How many grams are their in given number of He atoms.
Solution :
We know, molecular mass of He is 4 g. It means that their are [tex]6.022 \times 10^{23}[/tex] atoms in 4 g of He.
Let, number of gram He in [tex]3.4\times 10^{24}[/tex] atoms is x , so :
[tex]x = \dfrac{3.4\times 10^{24}}{6.022\times 10^{23}}\times 4\\\\x = $$22.58\ g[/tex]
Therefore, grams of He atoms is 22.58 g .