25 ml of 2.0 M silver acetate reacts with grams 35 ml of 1.0 M Calcium chloride

Answers

Answer 1

Answer:

[tex]m_{AgCl}=7.15gAgCl\\m_{Ca\ Acet}=3.15gCa\ Acet\\[/tex]

Explanation:

Hello,

In this case, with the given information, we can identify the limiting reactant and compute the theoretical yield for the undergoing chemical reaction:

[tex]2CH_3COOAg+CaCl_2\rightarrow (CH_3COO)_2Ca+2AgCl[/tex]

Thus, with the given concentrations and volumes we compute the available moles of silver acetate:

[tex]n_{Ag\ Acet}=2.0mol/L*0.025mL=0.05mol[/tex]

Then, the moles of silver acetate that are consumed by 35 mL of 1.0 M calcium chloride:

[tex]n=0.035mL*1.0molCaCl_2/L*\frac{2mol Ag\ Acet}{1molCaCl_2} =0.07mol Ag\ Acet[/tex]

Therefore, since there are less available moles, it is the limiting reactant, for that reason, the theoretical yields of both calcium acetate and silver acetate are:

[tex]m_{AgCl}=0.05mol Ag\ Acet*\frac{2molAgCl}{2mol Ag\ Acet} *\frac{143gAgCl}{1molAgCl} \\\\m_{AgCl}=7.15gAgCl\\\\m_{Ca\ Acet}=0.05mol Ag\ Acet*\frac{1molmol Ca\ Acet}{2molmol Ag\ Acet} *\frac{126gmol Ca\ Acet}{1mol Ca\ Acet} \\\\m_{Ca\ Acet}=3.15gCa\ Acet[/tex]

Best regards.


Related Questions

A sample of gas has a volume of 571 mL at a pressure of 4.04 atm. The gas is compressed and now has a pressure of 7.17 atm. Predict whether the new volume is greater or less than the initial volume, and calculate the new volume. Assume temperature is constant and no gas escaped from the container.

Answers

Answer:

The new volume is less than the initial volume.

The new volume is 322mL

Explanation:

Based on Boyle's law, the pressure of a gas is inversely proportional to its volume under constant temperature. That means if the pressure of a gas is increased, the volume decrease and vice versa. The formula is:

P₁V₁ = P₂V₂

Where P is pressure and V is volume of 1, initial state and 2, final states.

In the problem, the pressure of the gas increased from 4.04atm to 7.17atm, That means the new volume is less  than initial volume because the gas is compressed occupying less volume.

Replacing in Boyle's equation:

4.04atm*571mL = 7.17atmV₂

322mL = V₂

Beeing the new volume of the compressed gas 322mL

Summarize the feedback loop (transfer of energy) between the microbes and the mushrooms. (Video #1)

What is the Nitrogen Cycle? Discuss the 3 types of microbes required for the nitrogen cycle. What would happen to the soil if the microbes were not there?(Video #2)

Where and how does carbon move? How do plants help recycle CO2? Where do plants get their CO2 from? (Video #3)

Scientists are wondering how soil and soil microbes interact, how they will respond to global warming, specifically what will happen to the levels of CO2 and CH4 if the soil warms up.


Analyze the Results from this student’s data (Links to an external site.)

Based on these results, (1) would the warming of the climate cause an increase or a decrease in soil respiration? Use data to back up your claim. (2) How might this impact the environment?

Answers

Answer:

Cyanobacteria, Azotobactor and Azospirillum are the microbes which is required for nitrogen cycle.

Explanation:

Nitrogen Cycle is a type of cycle in which nitrogen moves from atmosphere to the earth surface and again return back to the atmosphere. Cyanobacteria, Azotobactor and Azospirillum are the microbes which is required for nitrogen cycle. If these microbes is vanished from the environment, the nitrogen cannot be converted into other forms. Carbon is present in the atmosphere in carbondioxide form. This CO2 is used by the plants from atmosphere and make food from it. When these plants are eaten by animals, this CO2 is again release in the atmosphere. Due to global warming, the microbes present in the soil die due to increase in temperature of the soil. Levels of CO2 and CH4 increases if the soil warms up.  With the increase in temperature, soil respiration increases which leads to more emission of CO2 and as a result more global warming occurs.

Consider the following reversible reaction. Upper C upper O (g) plus 2 upper H subscript 2 (g) double-headed arrow upper C upper H subscript 3 upper O upper H (g). What is the equilibrium constant expression for the given system? K e q equals StartFraction StartBracket upper C upper O EndBracket StartBracket upper H 2 EndBracket superscript 2 over StartBracket upper C upper H subscript 3 upper O upper H EndBracket EndFraction. K e q equals StartFraction StartBracket upper C upper H subscript 3 upper H upper O EndBracket over StartBracket upper C upper O EndBracket StartBracket upper H 2 EndBracket superscript 2 EndFraction. K e q equals StartFraction StartBracket upper C upper O EndBracket StartBracket upper H 2 EndBracket over StartBracket upper C upper H subscript 3 upper O upper H EndBracket EndFraction. K e q equals sart fraction StartBracket upper C upper H subscript 3 upper O StartBracket upper C upper O EndBracket StartBracket upper H 2 EndBracket EndFraction.

Answers

Answer:

[tex]Keq=\frac{[CH_3OH]}{[CO][H_2]^2}[/tex]

Explanation:

Hello,

In this case, for the described reaction at equilibrium:

[tex]CO(g)+2H_2(g)\rightleftharpoons CH_3OH(g)[/tex]

The analysis of the law of mass action allows us to write the equilibrium expression as shown below:

[tex]Keq=\frac{[CH_3OH]}{[CO][H_2]^2}[/tex]

Which is written considering that carbon monoxide, hydrogen and methanol are all in gaseous phase, for that reason all of them are included in the expression due to homogeneous equilibrium. Moreover, since hydrogen has a stoichiometric coefficient of 2, it is squared in the law of mass action.

Best regards.

Answer:

the answer is B if your looking for the letter

Explanation:

K e q equals StartFraction StartBracket upper C upper H subscript 3 upper H upper O EndBracket over StartBracket upper C upper O EndBracket StartBracket upper H 2 EndBracket superscript 2 EndFraction.

Lead forms two compounds with oxygen. One contains 2.98g of lead and 0.461g of oxygen. The other contains 9.89g of lead and 0.763g of oxygen. For a given mass of oxygen, what is the lowest whole-number mass ratio of lead in the two compounds

Answers

The given question is incomplete, the complete question is:

Lead forms two compounds with oxygen. One contains 2.98g of lead and 0.461g of oxygen. The other contains 9.89g of lead and 0.763g of oxygen. For a given mass of oxygen, what is the lowest whole-number mass ratio of lead in the two compounds that combines with a given mass of oxygen?

Answer:

The lowest whole-number mass ratio in the two compounds is 1:2.

Explanation:

There is a need to find the mole ratio between lead and oxygen atoms in order to find the whole-number mass ratio of lead in the two compounds. In the first compound, the given mass of lead is 2.98 grams, the molar mass of lead is 207.2 gram per mole.  

The no. of moles can be determined by using the formula,  

moles = mass/molecular mass

moles = 2.98 g/207.2 g/mol

= 0.0144 moles

The mass of oxygen in the compound I is 0.461 grams, the molecular mass of oxygen is 16 gram per mol.  

moles = 0.461 g /16 g/mol

= 0.0288 moles

The ratio between the lead and oxygen in the compound I is 0.0144/0.0288 = 1:2

On the other hand, in the compound II, the mass of lead given is 9.89 grams, therefore, the moles of lead in compound II is,  

moles = 9.89 g / 207.2 g/mol

= 0.0477 moles

The mass of oxygen given in compound II is 0.763 grams, the moles of oxygen present in the compound II is,  

moles = 0.763 g / 16 g

= 0.0477 moles

The ratio between the lead and oxygen in the compound II is, 0.0477 moles lead /0.0477 moles oxygen = 1:1

Hence, of the two compounds, the lowest ratio is found in the compound I, that is, 1:2.  

gas syringe
bung
chips
25 cm of dilute
hydrochloric acid
Which channes slow down the rate of reaction?
Decrease the size of pieces of marble chips
Decrease surface area of marble chips
Inercase concentration of acid
Increase temperature of acid

Answers

Answer:

Decrease surface area of marble chips.

Explanation:

Because the reaction goes on the surface  of marble chips, decreasing surface area of marble chips will decrease(slow down) the rate of the reaction.

Be sure to answer all parts. Ammonia is a principal nitrogen fertilizer. It is prepared by the reaction between hydrogen and nitrogen. 3H2(g) + N2(g) → 2NH3(g) In a particular reaction, 4.00 moles of NH3 were produced. How many moles of H2 and how many moles of N2 were reacted to produce this amount of NH3?

Answers

moles of H2

Mole ratio of H2 to NH3 is 3: 2

if 3: 2

? 4

= 4*3/2= 6

6moles of H2

moles of N2

mole ratio of N2 to NH3 is 1: 2

if 1 : 2

? 4

4*1/2 = 2

2 moles of N2

(B1-MC-12) How many of the following are oxidation-reduction reactions? NaOH (aq) + HCl (aq) → NaCl (aq) + H2O (l) Cu (s) + 2AgNO3 (aq) → 2Ag (s) + Cu(NO3)2 (aq) Mg(OH)2 (s) → MgO (s) + H2O (l) N2 (g) + 3H2 (g) → 2NH3 (g) a. 0 b. 1 c. 2 d. 3 e. 4

Answers

Answer:

C

Explanation:

They involve losing and gaining of electrons therefore there is a change of state from either solid to aqueous or vise versa

Among the given reactions only two are oxidation-reduction reactions.

Cu (s) + 2AgNO₃ (aq)  →  2 Ag (s) + Cu(NO₃)₂

N₂ (g)   +   3 H₂ (g)   →  2 NH₃

Therefore, option (c) is correct.

What are the oxidation-reduction reactions?

The reactions involve the transfer of electrons from one chemical substance to another chemical substance. These electron-transfer reactions are known as redox reactions or oxidation-reduction reactions.

These reactions involved energy changes in the form of heat, light, electricity, etc. The oxidation and reduction reaction is accompanied by the addition of oxygen or hydrogen to different substances.

The first reaction is NaOH (aq) + HCl (aq) → NaCl (aq) + H₂O. In which there is no change in the oxidation number of elements therefore, it is not a redox reaction.

In the second reaction, Cu (s) + 2AgNO₃ (aq)  →  2 Ag (s) + Cu(NO₃)₂   . There is a change in the oxidation state of copper from 0 to +2 and the oxidation number of Ag from +1 to 0. It means both oxidation and reduction are involved in this chemical reaction.

In the third reaction Mg(OH)₂ (s) → MgO (s) + H₂O (l), again there is no change in the oxidation number of Mg. The fourth reaction is the formation of ammonia in which the oxidation number of N changes from 0 to -3 and the H from 0 to +1. Therefore, it is an oxidation-reduction reaction.

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Upon the addition of water, As2O3 is converted to H3AsO3. During the titration H3AsO3 is oxidized to H3AsO4 and MnO4- is reduced to Mn2 . Write a balanced net ionic equation for the reaction

Answers

Answer:

5H3AsO3(aq) + 2MnO4-(aq) + 6H+(aq) → 5H3AsO4(aq) + 2Mn2+(aq) + 3H2O(aq)

Explanation:

Every net balanced ionic equation is composed of a union of two half equations;

The oxidation half equation (indicating electron loss) and the reduction half equation (indicating electron gain). Remember that redox reactions is a process in which electrons are lost and gained by chemical species simultaneously. One specie looses electrons in the oxidation half equation while the other specie gains electrons in the reduction half equation.

The balanced redox reaction equation shows the overall redox process and shows at a glance the total number of elect tribe lost or gained in the redox process. The overall redox reaction equation for the titration described in the question is;

5H3AsO3(aq) + 2MnO4-(aq) + 6H+(aq) → 5H3AsO4(aq) + 2Mn2+(aq) + 3H2O(aq)

DATA AND CALCULATIONS: (you must show your calculations) Part I. Determination of accuracy of a graduated cylinder Calculations: Experimental Step Measurable Mass of empty graduated cylinder 47.229 g Mass of filled graduated cylinder 71.821 g Mass of water (filled – empty) g Volume of water, calculated (calculated from mass of water, using the equation “density = mass/volume”, given the fact that the density of water is exactly 1 g/mL) mL Volume of water, measured (from the reading of the scale on the graduated cylinder) 25.0 mL Percent difference between measured and calculated volumes of water [(measured-calculated)/calculated] ×100% %

Answers

Answer:

[tex]\large \boxed{2 \, \%}[/tex]

Explanation:

1. Data

Mass of graduated cylinder              =  47.229 g

Mass of graduated cylinder + water =  71.821  g

Actual volume of water                     = 25.0     mL

2. Calculations

(a) Mass of water

Mass = 71.821 g -47.229 g  = 24.592 g

(b) Volume of water

[tex]\text{Volume} = \dfrac{\text{mass}}{\text{volume }} = \dfrac{\text{24.592 g}}{\text{ 1 g/mL}} = \text{24.592 mL}[/tex]

(c) Percent Difference

[tex]\begin{array}{rcl}\text{Percent difference}&= &\dfrac{\lvert \text{Measured - Calculated}\lvert}{ \text{Calculated}} \times 100 \,\%\\\\& = & \dfrac{\lvert 25.0 - 24.492\lvert}{24.492} \times 100 \, \% \\\\& = & \dfrac{\lvert 0.5\lvert}{24.492} \times 100 \, \%\\ \\& = & 0.02 \times 100 \, \%\\& = & \mathbf{2 \, \%}\\\end{array}\\\text{The percent difference is $\large \boxed{\mathbf{2 \, \%} }$}[/tex]

An atom or ion has 42 neutrons , 36 protons, and 36 electrons. Identify the element symbol, and determine the mass number and charge for this atom or ion.

Answers

Answer:

i hope this will help you :)

Explanation:

number of electrons=36

number of protons=36

number of neutrons=42

mass number=number of protons+number of neutrons

mass number=36+42

mass number=78

so the element will be krypton Kr

as elements are identified on their number of electrons so this atom is krypton

as the actual atomic mass of krypton is 86 here the calculated atomic mass is 78 so krypton has loss 8 electrons but this must require a great amount of energy so the charge on krypton is +8

The symbol for this element is Kr, because that element is Krypton.

It is possible to find this out by the atomic number of the element. This atomic number is equal to the number of protons in the element.

Therefore, you should look, in a periodic table, which element has the atomic number equal to 36. In this search, you will see that this element is Krypton.

To know the mass and electrical charge, follow these steps:

The element's mass is calculated as the sum of the number of protons and the number of neutrons.Thus, the mass of this element is calculated through 36+42 which results in 78u.The electric charge, refers to the amount of electrons in the valence layer of the atom.Atoms with more than 8 electrons in the valence layer have a positive electric charge and atoms with less than 8 electrons in the valence layer have a negative electric charge.Krypton has 8 electrons in the valence layer, which means this is a neutral element.

Krypton is a noble gas, and electric stability is normal among these gases. With that, we can conclude that Krypton is an atom and not an ion.

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examplesfor gas in liquid sssloution​

Answers

Answer:

Water vapor to dew

Explanation:

Water vapor turns from a gas into a liquid, such as dew on the morning grass.

Answer:

Coca cola, the beverage, is an example of gas - liquid solution, as it has carbon dioxide dissolved in water.

Which image best represents the particles in liquids

Answers

This is what I would use. Hopefully this helps:)

Answer:

The 2nd Picture represents the particles in liquids.

Explanation:

Why are covalent substances gases and liquid rather than solids?

Answers

Covalent compounds are held together with an intra molecular attraction which is weaker than metallic bond

hence covalent compounds exist as liquids, gases and soft solids

Which of the following is a correct representation of the isotope of sulfur that has 19 neutrons? sulfur-19 sulfur-35 sulfur-16 sulfur-32

Answers

Answer:

sulfur-35

Explanation:

Sulfur-35 is a radioactive isotope that contains 19 neutrons.

Isotopes are represented with mass numbers. Mass number is the addition of number of proton and number of neutrons.

The number of proton in sulfur = 16

Number of neutron = 19

So, mass number = no. of protons + no. of neutrons

                              = 16 + 19

                              = 35

Hence, the correct answer is sulfur-35.

Answer:

sulfur -35

sulfur negative thirty five

Choose the species that is incorrectly matched with its electronic geometry.
1. BeBr2 : linear
2. CF4 : tetrahedral
3. NH3 : tetrahedral
4. H2O : tetrahedral
5. PF3 : trigonal bipyramidal

Answers

Answer:

PF3 : trigonal bipyramidal

Explanation:

PF3 has 4 domains around the central phosphorus (3 shared pairs and one lone pair of electrons), thus the electron geometry that has 4 domains is tetrahedral not  trigonal bipyramidal

From the options the specie that is incorrectly matched is ( 5 ) ; PF₃ : trigonal bipyramidal

The specie PF₃ is composed of 3 shared pairs and one unshared pair of electrons ( i.e. It has 4 domains ) as seen in the  Lewis structure of  PF₃. therefore  when writing its electronic geometry, it should expressed/written as tetrahedral and not trigonal bipyramidal.

Hence we can conclude that The specie that is incorrectly matched is PF3 : trigonal bipyramidal

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Arrange the compounds in order of increasing acid strength. Consult the references section for pKa values of each acid. Suppose the strongest acid is b, the acid of intermediate strength is c and the weakest acid is a Then this leads to the following input:
a. CH 3NH3
Methylammonium ion
b. CH3 COH
Acetic acid
c. H2S
Hydrogen sulfide

Answers

C hydrogen sulfide !!!

The strongest acid is b, the acid of intermediate strength is c and the weakest acid is a Then this leads to the H2S (Hydrogen sulfide). Therefore, option C is correct.

What do you mean by an acid ?

A chemical that, when combined with certain metals, emits hydrogen ions in water and forms salts. Acids have a sour taste and cause certain dyes to turn red.

An acid is a substance that releases hydrogen ions into solution, whereas a base or alkali absorbs hydrogen ions.

In an aqueous solution or water, a weak acid is an acid that has been partially dissociated into its ions. A strong acid, on the other hand, completely dissociates into its ions in water. The pH of weak acids is higher than that of strong acids.

Thus, The strongest acid is b, the acid of intermediate strength is c and the weakest acid is a Then this leads to the H2S, option C is correct.

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Questlon 25 of 25
2 Points
Substitute 4 for xand evaluate the expression below.
3x+9x​

Answers

Answer:

48

Explanation:

hi hope this helps

3*4+9*4

12+36

48

the answer should be 48.
3(4)+9(4)
12+36
48

How are atoms arranged in a network solid, such as a diamond? A) Covalent bonds join random sets of atoms into a loose, changeable structure. B) Intermolecular forces hold diatomic molecules in an array. C) Covalent bonds join all the atoms tightly together. D) Covalent bonds join groups of 6 to 10 atoms tightly together.

Answers

Covalent bonds join all the atoms tightly together

Energy that is not utilized for work or heat transfer is converted to the chemical energy of body fat containing about 39 kJ/g. How many grams of fat will you gain if you eat 10,000 kJ (about 2390 kcal) one day and do nothing but sit relaxed for 14.3 h and sleep for the other 9.70 h

Answers

Answer:

[tex]m=107.8g[/tex]

Explanation:

Hello,

In this case, for the given information, we can compute the gained grams by firstly compute the energy consumed by 14.3 h of being sit relaxed and 9.70 h  of sleeping:

[tex]E_{sit}=120\frac{J}{s}*\frac{3600s}{1h} *14.3h*\frac{1kJ}{1000J} =6177.6kJ\\\\E_{sleep}=83\frac{J}{s}*\frac{3600s}{1h} *9.70h*\frac{1kJ}{1000J} =2898.36kJ[/tex]

Then, we compute the energy used that day:

[tex]E_T=10000kJ-2898.36kJ-6177.6kJ=4203.28kJ[/tex]

Finally, the mass by considering the consumed fat:

[tex]m=\frac{4203.28kJ}{39kJ/g} \\\\m=107.8g[/tex]

Regards.

From the given electron configurations, predict which one is for a representative element?

A) 1s22s22p63s23p64s2

B) 1s22s22p63s23p63d74s2

C) 1s22s22p63s23p63d64s2

D) 1s22s22p63s23d5

Answers

It is c hope this helped

From the given electron configurations, predict which one is for a representative element is 1s₂, 2s₂, 2p₆,3s₂, 3p₆, 3d₆, 4s₂.

What is element ?

A chemical element is a species of atoms, including the pure material made entirely of that species, that have a specific number of protons in their nuclei. Chemical elements, unlike chemical compounds, cannot be reduced by any chemical process into simpler molecules.

The most basic form of a material is an element. In general, it cannot be streamlined or divided into smaller parts. A component of an element is an atom. A certain element only has one kind of atom per atom. Protons, neutrons, and electrons, which are subatomic particles, make up atoms.

We begin by applying the aufbau principle to the prediction of the electron configuration of an atom. It instructs us to fill the lowest energy accessible orbital, one electron at a time. It operates through element 18 (argon) in a filling pattern that is simple to predict: 1s, 2s, 2p, 3s, then 3p.

Thus, option C is correct.

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A 4.215 g sample of a compound containing only carbon, hydrogen, and oxygen is burned in an excess of oxygen gas, producing 9.582 g CO2 and 3.922 g H2O. What percent by mass of oxygen is contained in the original sample?

Answers

Answer:

[tex]\% O=27.6\%[/tex]

Explanation:

Hello,

In this case, for the sample of the given compound, we can compute the moles of each atom (carbon, hydrogen and oxygen) that is present in the sample as shown below:

- Moles of carbon are contained in the 9.582 grams of carbon dioxide:

[tex]n_C=9.582gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2} =0.218molC[/tex]

- Moles of hydrogen are contained in the 3.922 grams of water:

[tex]n_H=3.922gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O} =0.436molH[/tex]

- Mass of oxygen is computed by subtracting both the mass of carbon and hydrogen in carbon dioxide and water respectively from the initial sample:

[tex]m_O=4.215g-0.218molC*\frac{12gC}{1molC} -0.436molH*\frac{1gH}{1molH} =1.163gO[/tex]

Finally, we compute the percent by mass of oxygen:

[tex]\% O=\frac{1.163g}{4.215g}*100\% \\\\\% O=27.6\%[/tex]

Regards.

A volume of 38.7 mL of H2O is initially at 28.0 oC. A chilled glass marble weighing 4.00 g with a heat capacity of 3.52 J/oC is placed in the water. If the final temperature of the system is 26.1 oC , what was the initial temperature of the marble? Water has a density of 1.00 g/mL and a specific heat of 4.18 J/goC. Enter your answer numerically, to three significant figures and in terms of oC.

Answers

Answer:

- 61.2°C = Initial T°

Explanation:

This is a calorimetry problem, where the heat from the water was gained by the marble.

Q = m . C . ΔT

where ΔT is final T° - initial T°, C is the specific heat and m, mass.

By the volume of water, we realize the mass (we apply density):

1 g/mL = mass / 38.7 mL

38.7 g = mass of water

Now, we need to find out the specific heat for the marble and we have Heat Capacity data

Heat Capacity = C . m

3.52 J/°C / 4 g = C → specific heat → 0.88 J/g °C

We make the equations for both heats:

m . C . ΔT from water = m . C . ΔT from the marble

38.7 g . 4.18 J/g°C ( 26.1°C - 28°C) = 4 g .  0.88 J/g °C . (26.1°C - Initial T°)

307.35 J = 4 g .  0.88 J/g °C . (26.1°C - Initial T°)

- 307.35 is a negative value, because the was has decreased the temperature, is a loss of heat, but we have to work with the positive number.

307.35 J / (4 . 0.88 °C/J) = 26.1°C - Initial T°

87.32°C = 26.1°C - Initial T°

- 61.2°C = Initial T°

Question
2 Points
An object in a fluid will sink if:
A. the buoyant force is larger than the weight of the object.
B. the buoyant force is larger than the mass of the object.
C. the buoyant force is smaller than the weight of the object.
D. the buoyant force is smaller than the mass of the object.
SUBM

Answers

Answer:

c

Explanation:

when the weight of the object is greater than the buoyant force sinking is occurred.

A buffered solution has a pH of 7.5. What would happen to the pH if a small
amount of acid were added?

Answers

Answer:

Dear user,

Answer to your query is provided below

When small amount of acid was added to buffered solution, pH will change very less.

Explanation:

Buffer solution resists change in ph on adding small amount of acid or base but when we calculate the value of buffer capacity we take the change in ph when we add acid or base to 1 lit solution of buffer.This contradicts the definition of buffer solution.

For some hypothetical metal, the equilibrium number of vacancies at 600°C is 1 × 1025 m-3. If the density and atomic weight of this metal are 7.40 g/cm3 and 85.5 g/mol, respectively, calculate the fraction of vacancies for this metal at 600°C. Enter your answer using scientific notation.

Answers

Answer:

fraction of vacancies for this metal FV = 1.918*10⁻⁴

Explanation:

Given:

The number of vacancies per unit volume => ( Nv = 1*10²⁵ m⁻³ )

But we know that Avogrado's constant NA = 6.022*10²³ atoms/mol

Density of the material is given in g/cm3 we need to convert it to g/m³

Density of material ( p ) in g/m³ :

To convert we know that

1 g/cm³ = 1000000 g/m³ then

7.40 * ( 1000000 ) = 7.40*10⁶ g/m³

So, Density of material ( p ) in g/m³ = 7.40*10⁶ g/m³

Given Atomic mass = 85.5 g/mol

To Calculate the number of atomic sites per unit volume , we will use the below formula by substituting those values above

N = NA * p / A

N = ( 6.022*10²³ ) * ( 7.40*10⁶ ) / 85.5

N = 4.45*10³⁰ / 85.5

N = 5.212*10²⁸ atoms/m³

We can now Calculate the fraction of vacancies using the formula below;

Fv = Nv / N

Fv = 1*10²⁵ / 5.212*10²⁸

fraction of vacancies for this metal at 600c.= 1.918*10⁻⁴

Arrange the ff substances in order of increasing tendency to donate electrons with reasons
Alpha- ketoglutarate, Oxaloacetate ,O2, NADP+, Malate​

Answers

Answer:

Alpha- ketoglutarate --> NADP+ --> Oxaloacetate --> O2.

(O2 has the HIGHEST tendency to donate electrons).

Explanation:

Okay, we are to Arrange Alpha- ketoglutarate, Oxaloacetate ,O2, NADP+ and Malate in order of increasing tendency to donate electrons, therefore, the correct order is;

Alpha- ketoglutarate --> NADP+ --> Oxaloacetate --> O2.

And this result can be gotten if we consider these compounds in their oxidative mechanism and check their potential values.

(1). When Alpha- ketoglutarate react with CO2, it gives isocitrate and standard redox potential value of -0.38.

(2). NADP+ with react with two moles of electrons and one mole of hydrogen ion to produce NADPH and standard redox potential value of -0.32.

(3). Oxaloacetate will react with two moles of hydrogen ion and electrons respectively to produce standard redox potential value of -0.18 and Malate.

(4). O2 will react with 4 moles of hydrogen ion and electrons respectively to produce 2 moles of water and standard redox potential value of +0.82.

CONCLUSION: the higher the negative values of the potential, the lesser the electron affinity and vice versa.

A solution has a hydrogen ion (or hydronium ion) concentration of 1.00×10−9 M.


What is the pH of the solution?


7.5

8.0

8.5

9.0

Answers

The ph of the solution with is 9.0

Question 1 of 10
How is each element represented in the periodic table?
A. Each element is in an order based on alphabetical order.
B. Each element is listed as an abbreviation of the first letters of its
DE ME
C. Each element is represented by a one or two-letter symbol.
D. Each element is listed in its own box based on when it was
discovered​

Answers

Answer:

C

Explanation:

A- incorrect, not in alphabetical order

B- incorrect, symbol for salt in NA not SA

C- correct

D- incorrect, not based on discovery

Each element represented in the periodic table is represented by a one or two-letter symbol.Hence , Option (C) is Correct.

What is Periodic Table ?

The periodic table, also known as the periodic table of the elements, is a tabular display of the chemical elements.

It is widely used in chemistry, physics, and other sciences, and is generally seen as an icon of chemistry.

Each element represented in the periodic table is represented by a one or two-letter symbol.Hence , Option (C) is Correct.

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Carry out the following operations as if they were calculations of experimental results and express each answer in standard notation with the correct number of significant figures and wtih the correct units. Provide both the answer and the units.
1. 5.6792 m + .6 m + 4.33 m
2. 3.70 g - 2.9133 g
3. 4.51 cm x 3.6666 cm

Answers

Answer:

1. [tex]10.6\; \rm m[/tex] (one decimal place.)

2.[tex]0.79\; \rm g[/tex] (two decimal places.)

3. [tex]16.5\;\rm cm^2[/tex] (three significant figures.)

Explanation:

1.

The first and second expressions are additions and subtractions. When adding two numbers, the accuracy of the result is given by the number of decimal places in it. The result should have as many decimal places as the input with the least number of decimal places.

For example, in the first expression:

[tex]5.6792\;\rm m[/tex] has four decimal places.[tex]0.6\; \rm m[/tex] has only one decimal place.[tex]4.33\; \rm m[/tex] has two decimal places.

Therefore, the result should be rounded to one decimal place. Note that these units are compatible for addition, since they are all the same. The result should have the same unit (that is: [tex]\rm m[/tex].)

Therefore:

[tex]\rm 5.6792\; m + 0.6\; m + 4.33\; m \approx 10.6\; \rm m[/tex]. (Rounded to one decimal place.)

2.

Similarly:

[tex]\rm 3.70\; \rm g[/tex] has two decimal places.[tex]2.9133\; \rm g[/tex] has four decimal places.

Therefore, the result should be rounded to two decimal places. Its unit should be [tex]\rm g[/tex] (same as the unit of the two inputs.)

[tex]\rm 3.70\; g - 2.9133\; g \approx 0.79\; \rm g[/tex]. (Rounded to two decimal places.)

3.

When multiplying two numbers, the accuracy of the result should be based on the number of significant figures in it. The result should have as many significant figures as the input with the least number of significant figures. In this expression:

[tex]4.51\; \rm cm[/tex] has three significant figures.[tex]3.6666\; \rm cm[/tex] has five significant figures.

Therefore, the result should have only three significant figures.

The unit of the result is supposed to be the product of the units of the input. In this expression, that unit will be [tex]\rm cm \cdot cm[/tex], which is occasionally written as [tex]\rm cm^2[/tex].

[tex]\rm 4.51 \; cm \times 3.6666 \; cm \approx 16.5\; \rm cm^2[/tex]. (Rounded to three significant figures.)

The partial pressure of CO2 gas above the liquid in a carbonated drink is 0.45 atm. Assuming that the Henry's law constant for CO2 in the drink is that same as that in water, 3.7 x 10-2 mol/L atm, calculate the solubility of carbon dioxide in this drink.

Answers

Answer:

[tex]M_{CO_2}=0.01665M[/tex]

Explanation:

Hello,

In this case, the Henry's law allows us to relate the molar concentration and partial pressure of a solute (carbon dioxide) in a solution (solvent is water) by:

[tex]M_{CO_2}=H_{CO_2}p_{CO_2}[/tex]

Whereas we introduce the Henry constant, therefore, we can easily compute the molar solubility by:

[tex]M_{CO_2}=p_{CO_2}*H_{CO_2} =0.45atm*3.7x10^{-2}\frac{M}{atm}\\\\M_{CO_2}=0.01665M[/tex]

Regards.

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