22. Fences My orchid garden abuts my house so that the house itself forms the northern boundary. The fencing for the southern boundary costs $4 per foot, and the fencing for the east and west sides costs $2 per foot. If I have a budget of $80 for the project, what is the largest area I can enclose?

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Answer 1

Given information: The fencing for the southern boundary costs $4 per foot, and the fencing for the east and west sides costs $2 per foot. The budget for the project is $80.

Therefore,The length of the northern boundary is not given. So let us assume it as "x" feet. The southern boundary also has a length of "x" feet. Let the length of the eastern and western boundary be "y" feet.Let "A" be the area enclosed. Therefore,Area (A) = xy square feetThe cost for 1 foot of southern boundary is $4. Hence, the cost for "x" feet of southern boundary is $4x.The cost for 1 foot of eastern and western boundary is $2. Hence, the cost for "y" feet of eastern and western boundary is $4y. The total cost of fencing is given to be $80. Therefore,4x + 4y = 80x + y = 20y = 20 - xSo, the area enclosed is A = xy = x(20 - x)/4 = 5x - 0.25x²So, the area enclosed is A = xy = x(20 - x)/4 = 5x - 0.25x²To maximize the area, differentiate A with respect to x and equate it to 0dA/dx = 5 - 0.5x = 0Therefore, x = 10 feetSubstitute this value in equation (2)y = 20 - x = 20 - 10 = 10 feetTherefore, the largest area that can be enclosed is A = xy = 10 x 10 = 100 square feet. Answer: 100

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A major criticism of the continental drift hypothesis was the apparent lack of a driving mechanism. This statement is true.

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