Find a polynomial with real coefficients that has the given zeros. 5+2i, 5-2i, -1 One such polynomial P(x) can be defined as P(x) = x³ - 9x² + x + 29.​

Answers

Answer 1

The polynomial with real coefficients from the zeros is P(x) = 2x³ - 18x² + 2x + 58

Find a polynomial with real coefficients from the zeros.

From the question, we have the following parameters that can be used in our computation:

zeros =  5+2i, 5-2i, -1

One such polynomial P(x) can be defined as

P(x) = x³ - 9x² + x + 29.

When this polynomial is multiplied by a costant, the roots and zeros remain the same

Let the constant be 2

So, we have

New P(x) = 2(x³ - 9x² + x + 29)

Evaluate

New P(x) = 2x³ - 18x² + 2x + 58

Hence, the function is P(x) = 2x³ - 18x² + 2x + 58

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