14 cm
10 cm
3.cn
22 cm
SO THIS IS A COMPLEX SHAPE, WHATS THE THE AREA PLEASE I NEED ASAP

Answer:

12/40, 15/40, 18/40

Step-by-step explanation:

1/4, 1/2 = 1/4, 2/4

Since, Three rational numbers cannot come in between 1/4 and 2/4, we multiply them with 10.

∴ 1/4 × 10 = 10/40

∴ 2/4 × 10 = 20/40

∴ Three rational numbers between 10/40 and 20/40 = 12/40, 15/40, 18/40

(You can add more numbers from between 10/40 and 20/40 if you need)

Answer:

R = - 0.9453

T = - 5.019

Pvalue = 0.212

Step-by-step explanation:

Given the data:

Lemon_Imports_(x)

230

264

359

482

531

Crash_Fatality_Rate_(y):

15.8

15.6

15.5

15.3

14.9

The Correlation Coefficient, R using a correlation Coefficient calculator is - 0.9453 ; this depicts a strong negative correlation between the dependent and independent variable.

The test statistic, T :

T = r / √(1 - r²) / (n - 2)

T = -0.9453/ √(1 - (-0.9453)²) / (5 - 2)

T = - 0.9453 / 0.1883329

T = - 5.019

The Pvalue using a Pearson Pvalue calculator ;

df = n - 1 = 5 - 2 = 3 ; r = - 0.9453

Pvalue = 0.212

Answer:

a) 2

b)

0.1353 = 13.53% probability that exactly 0 customers will arrive during a five-minute period.

0.2707 = 27.07% probability that exactly 1 customer will arrive during a five-minute period.

0.2707 = 27.07% probability that exactly 2 customers will arrive during a five-minute period.

0.1805 = 18.05% probability that exactly 3 customers will arrive during a five-minute period.

c) 0.1428 = 14.28% probability that delays will occur

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\mu[/tex] is the mean in the given interval.

a. What is the mean or expected number of customers that will arrive in a five-minute period?

0.4 customers per minute, so for five minutes, this is [tex]\mu = 5*0.4 = 2[/tex]

b. Assume that the Poisson probability distribution can be used to describe the arrival process. Use the arrival rate in part (a) and compute the probabilities that exactly 0, 1, 2, and 3 customers will arrive during a five-minute period.

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-2}*2^{0}}{(0)!} = 0.1353[/tex]

0.1353 = 13.53% probability that exactly 0 customers will arrive during a five-minute period.

[tex]P(X = 1) = \frac{e^{-2}*2^{1}}{(1)!} = 0.2707[/tex]

0.2707 = 27.07% probability that exactly 1 customer will arrive during a five-minute period.

[tex]P(X = 2) = \frac{e^{-2}*2^{2}}{(2)!} = 0.2707[/tex]

0.2707 = 27.07% probability that exactly 2 customers will arrive during a five-minute period.

[tex]P(X =3) = \frac{e^{-2}*2^{3}}{(3)!} = 0.1805[/tex]

0.1805 = 18.05% probability that exactly 3 customers will arrive during a five-minute period.

c. Delays are expected if more than three customers arrive during any five-minute period. What is the probability that delays will occur?

This is:

[tex]P(X > 3) = 1 - P(X \leq 3)[/tex]

In which:

[tex]P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.1353 + 0.2707 + 0.2707 + 0.1805 = 0.8572[/tex]

[tex]P(X > 3) = 1 - P(X \leq 3) = 1 - 0.8572 = 0.1428[/tex]

0.1428 = 14.28% probability that delays will occur

Answer: 5/2

Explanation:

According to 30-60-90 triangle rule:

The side opposite of 30 degree is equal to half of the hypotenuse and the hypotenuse here is 5 so therefore x = 5/2

Answer:

Option A

Step-by-step explanation:

We have y=X-7

sub 1st value 10 then we get y=10-7=3

In the same way y=11-7=4

Y=12-7=5

Y=13-7=6

Y=14-7=7

Answer:

on the pic

Step-by-step explanation:

substitute the x with 1

Answer:

f(1)=44

Step-by-step explanation:

Wherever you see x, you will replace it with 1

so, 5(8)1+4

(40)1+4

40+4

=44

Answer:

123,458,023 is the answer

Step-by-step explanation:

Answer:

152,345,677,626

Step-by-step explanation:

Temporary Help Answer

The answer is limited due to the lack of questions, so I'll give you some answers related.

State appropriate Hypothesis for performing a significance test. Be sure to define the parameter of interest. (u = mu)

[tex]H_{null}:u=17 \\H_{a}:u<17[/tex]        Where mu = the true mean of almonds in each bar of candy.

Calculate the test statistic and the P-Value.

mu = 17

x-bar = 14

[tex]S_{x} = 8[/tex]

[tex]n = 30[/tex]

Use the T-Test (STAT) if you have a Graphing Calculator.

Interpret the P-Value in context.

Assuming the mean number of almonds in each candy bar is 17, there is a [P-Value] probability of getting a sample mean of 14 by chance alone.

What is the decision at the given significance level?

P-val of [P-Value] is (> or <?) to the alpha level [[tex]a[/tex]], so you must (fail to reject or reject?) the Null Hypothesis.

What do you conclude? (If P-val is smaller than the alpha level, reject the null hypothesis, meaning there is significant evidence.)

Because the P-Value of [P-Value] is (less/greater) than [tex]a = (?)[/tex], the observed result (is or is not?) statistically significant. There (is or is not?) significant evidence to conclude that the chocolate almond bars contain fewer almonds than they've previously contained.

9514 1404 393

Answer:

  $32,528.58

Step-by-step explanation:

For simplicity, we'll assume each year has 365 days.

The future value A of principal amount P at rate r compounded daily for t years is ...

  A = P(1 +r/365)^(365t))

We want P when A = 80,000, r = 0.075, and t = 12.

  P = A/(1 +r/365)^(365t)

  P = $80000/(1+0.075/365)^(365·12) ≈ $32,528.58

You will have to deposit about $32,528.58.

Answer:

The expected cost is $8.75

Step-by-step explanation:

Given

[tex]Time = \{1pm, 2pm, 3pm, 4pm\}[/tex]

[tex]C_1 = \$5[/tex] --- If Bob and Anna meet

[tex]C_2 = \$10[/tex] --- If Bob and Anna do not meet

Required

The expected cost of  Bob's meal

First, we list out all possible time both Bob and Anna can select

We have:

[tex](Bob,Anna) = \{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3)[/tex][tex],(3,4),(4,1),(4,2),(4,3),(4,4)\}[/tex]

[tex]n(Bob, Anna) = 16[/tex]

The outcome of them meeting at the same time is:

[tex]Same\ Time = \{(1,1),(2,2),(3,3),(4,4)\}[/tex]

[tex]n(Same\ Time) = 4[/tex]

The probability of them meeting at the same time is:

[tex]Pr(Same\ Time) = \frac{n(Same\ Time)}{n(Bob,Anna)}[/tex]

[tex]Pr(Same\ Time) = \frac{4}{16}[/tex]

[tex]Pr(Same\ Time) = \frac{1}{4}[/tex]

The outcome of them not meeting:

[tex]Different = \(Bob,Anna) = \{(1,2),(1,3),(1,4),(2,1),(2,3),(2,4),(3,1),(3,2)[/tex]

[tex],(3,4),(4,1),(4,2),(4,3)\}[/tex]

[tex]n(Different) = 12[/tex]

The probability of them meeting at the same time is:

[tex]Pr(Different) = \frac{n(Different)}{n(Bob,Anna)}[/tex]

[tex]Pr(Different) = \frac{12}{16}[/tex]

[tex]Pr(Different) = \frac{3}{4}[/tex]

The expected cost is then calculated as:

[tex]Expected = C_1 * P(Same) + C_2 * P(Different)[/tex]

[tex]Expected = \$5 * \frac{1}{4} + \$10 * \frac{3}{4}[/tex]

[tex]Expected = \frac{\$5}{4} + \frac{\$30}{4}[/tex]

Take LCM

[tex]Expected = \frac{\$5+\$30}{4}[/tex]

[tex]Expected = \frac{\$35}{4}[/tex]

[tex]Expected = \$8.75[/tex]

The expected cost is $8.75

6. 24

7. 40

8. 16

9. 10

10. 18

11. 36

12. 24

13. 22

I haven't done these kinds of problems in a while so sorry if any of them are wrong :(

Have a good day :)

Answer:

QUESTION:

Jamal discovers that the sum of point B and point C is zero which sentence is a correct statement about points B and C.A. point B is twice the distance to the left of zero as C is to the right of zero. .B. Point B is the opposite of point C..C. Point B has the value of zero and point C has a value less than zero. .D. Point B is positive while point C is negative

[tex] \huge\fbox\red{ᴀ}\huge\fbox\orange{ⁿ} \huge\fbox\pink{s}\huge\fbox\green{ʷ} \huge\fbox\blue{ᴇ}\huge\fbox\purple{ʳ}\ [/tex]

Step-by-step explanation:

Let B (x1, y1) and C (x2, y2) be two points.

if sum of B and C is 0:

([x1 + x2]/2, [y1 +y2]/2) = (0, 0)

then

[x1 + x2]/2=0 then x1+x2=0 then x1 = -x2 similarly, [y1+y2]/2=0 then y1+y2 = 0 then y1=-y2

Therefore,

B= (-x2, -y2) while C (x2, y2)

Point B and C are additive inverses of each other I e they are Opposite

Because then

Answer:

11 + 24x

Step-by-step explanation:

8 - 4(x - 7x) + 3

8 - 4x + 28x + 3

11 - 4x + 28x

11 + 24x

Answer:

8-4x+28x+3 = 24x+11

Step-by-step explanation:

brainliest?

Answer:

go to school, do your work, you are only cheating yourself, not the school, or end up homeless

Step-by-step explanation:

Answer:

162 cans

Step-by-step explanation:

100 - 82 = 18

18% of 900 =

0.18 * 900 =

162

Answer:

There seems to be m linear relation between te data.

Negative relationships between variables.

Step-by-step explanation:

Speed(X)

60

60

60

60

80

80

80

80

100

100

100

100

120

120

120

120

140

140

140

140

Lifetime (Y) :

4.6

3.8

4.9

4.5

4.7

5.8

5.5

5.4

5

4.5

3.2

4.8

4.1

4.5

4

3.8

3.6

3

3.5

3.4

The linear regression equation obtained by fitting the data using a regression model is :

ŷ = -0.017X + 6.03

From the regression plot, the relationship between the two variables, speed and lifetime is negative, that is an increase in one variable will lead to a corresponding decrease in the other.

Answer:

[tex]\sigma_x = 0.57[/tex]

Step-by-step explanation:

Given

[tex]\mu_x = 6[/tex]

See attachment

Required

Calculate [tex]\sigma_x[/tex]

This is calculated as:

[tex]\sigma_x = \sqrt{Var(x)}[/tex]

Where

[tex]Var(x) =\sum (x - \mu_x)^2 * P(x)[/tex]

So, we have:

[tex]Var(x) =(0 - 0.4)^2 * 0.64 + (1 - 0.4)^2 * 0.32 + (2 - 0.4)^2 * 0.04[/tex]

Using a calculator

[tex]Var(x) =0.32[/tex]

[tex]\sigma_x = \sqrt{Var(x)[/tex]

[tex]\sigma_x = \sqrt{0.32[/tex]

[tex]\sigma_x = 0.57[/tex] --- approximated

Answer:

Jenelle put $13,000 in Fund A mutual fund and $ 4,000 in Fund B mutual fund.

Step-by-step explanation:

As soon as Jenelle invested $ 17000 in two mutual funds: Fund A, which earned a 4% profit during the first year; and Fund B, which suffered a 1.5% loss, if she received a total of $ 460 profit, to know how much had she invested in each mutual fund, the following calculation must be done:

17000 x 0.04 - 0 x 0.015 = 680

15000 x 0.04 - 2000 x 0.015 = 570

13000 x 0.04 - 4000 x 0.015 = 460

Therefore, Jenelle put $ 13,000 in Fund A mutual fund and $ 4,000 in Fund B mutual fund.

Answer:

see below

Step-by-step explanation:   5 19 16 09

cos Θ  =  Adj side / hypotenuse

first we need to calculate the hypotenuse

a² + b² = c²        leg1² + leg2² = hypotenuse²

                           6²     + √7²  = hypotenuse²

                           36     +   7   = hypotenuse²

                               √43    = hypotenuse

cos K  =  Adj side / hypotenuse

cos K =     6 / √43

cos K =     (6 √43) / ((√43)(√43))

cos K =     6√43 / 43

------------------------------------------------------------

check

or tan Θ =    opp /adj

     K  = inv tan (√7/6)

     Θ  = 23.795°

cos (23.795°) = 0.91499          6√43 / 43 = 0.91499

Answer:

Theoretical probability is what we expect to happen, where experimental probability is what actually happens when we try it out. The probability is still calculated the same way, using the number of possible ways an outcome can occur divided by the total number of outcomes.

Step-by-step explanation:

The probability is still calculated the same way, using the number of possible ways an outcome can occur divided by the total number of outcomes. As more trials are conducted, the experimental probability generally gets closer to the theoretical probability

Answer:

12n-10=14, n=2

Step-by-step explanation:

( Twelve times of a number decreased by 10 is equal to 14 ) This sentence can be written mathematically to be: 12n-10=14

The answer: Add 10 to both sides: 12n-10=14 > 12n-10+10=14+10 > 12n=24

Divide both sides by 12: 12n=24 > [tex]\frac{12n}{12} =\frac{24}{12}[/tex] > n=2

Answer:

-1 , 5 for the original figure and 7, 2 for the final figure

Step-by-step explanation:

Self Explanatory

If you want explanation, comment on this answer and I will tell you

Refer to the diagram below. We have the following points

The shadow extends from point B to point C. If we let x be the the horizontal distance from the lamp to the person, then dx/dt represents the speed at which the person is walking away from the lamp. In this case, dx/dt = 4 feet per second.

Let y be the length of the shadow. We can use similar triangles and proportions to help find what y is equal to in terms of x

AD/BE = AC/BC

15/6 = (x+y)/y

15y = 6(x+y)

15y = 6x+6y

15y-6y = 6x

9y = 6x

y = 6x/9

y = 2x/3

y = (2/3)*x

The length of the shadow is 2/3 that of the distance from the person to the lamp.

Now apply the derivative to both sides to compute dy/dt, which represents how fast the shadow is changing.

y = (2/3)x

dy/dt = d/dt[ (2/3)x ]

dy/dt = (2/3)*d/dt[ x ]

dy/dt = (2/3)*dx/dt

dy/dt = (2/3)*4

dy/dt = 2.667

The rate in which the shadow is lengthening is approximately 2.667 ft per second.

Answer:

47.7 ft

Step-by-step explanation:

tan= o/a

tan(23)= x/100

x=100/tan(23)

x= 42.4

42.4 + 5.3 = 47.7

Answer:

m∠B = 15°

and

h ≈ 31.28 ft

Step-by-step explanation:

only if it's on edge 2021. this showed up when I put in the question, so imma just assume there are others here like me.

Answer:

20

Step-by-step explanation:

We plug m and n into the expression because we know that it is. Therefore, the expression is 4+ (7-5)^4. Simplify this to get 4+(2)^4. 2^4 is equal to 2x2x2x2 which is equal to 4x4 which is equal to 16. Therefore, 2^4 is 16. 4+16 is equal to 20. Therefore, the answer is 20.

If this has helped please mark as brainliest

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\textsf{Equation:}[/tex]

[tex]\mathsf{4 + (m - n )^4}[/tex]

[tex]\large\textsf{Solving:}[/tex]

[tex]\mathsf{4 + (m - n )^4}[/tex]

[tex]\mathsf{\mathsf{= 4 + (7 - 5)^4}}[/tex]

[tex]\mathsf{= 4 + (2)^4}[/tex]

[tex]\mathsf{= 4 + (2\times2\times2\times2)}[/tex]

[tex]\mathsf{= 4 + 2\times2\times2\times2}[/tex]

[tex]\mathsf{= 4 + 4\times 4}[/tex]

[tex]\mathsf{= 4 + 16}[/tex]

[tex]\mathsf{= 20}[/tex]

[tex]\large\textsf{Therefore, your answer should be:}[/tex]

[tex]\large\boxed{\frak{20}}\large\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

20 patients

Step-by-step explanation:

4/5 of 25 is 20

Answer:

z(s) is in the acceptance region we accept H₀. We don´t have enough evidence to support the breeder´s claim

Step-by-step explanation:

We will test the breeder´s claim at 95% ( CI) or significance level

α = 5 %   α = 0,05    α /2 = 0,025

Sample Information:

sample size   n  = 45

sample mean   x  = 72,5 pounds

Sample standard deviation  s = 16,1

1.-Hypothesis Test:

Null Hypothesis                              H₀        x  =  70

Alternative Hypothesis                  Hₐ        x  ≠  70

Alternative hypothesis contains the information about what kind of test has  to be developed ( in this case it will be a two-tail tets)

2.-z (c) is from z-table     z(c) = 1,96

3.- z(s)  =  ( x - 70 ) / 16,1 / √45

z(s)  =  (72,5 -70 ) *√45 / 16,1

z(s)  = 2,5 * 6,71 / 16,1

z(s)  = 1,04

4.-Comparing  z(s) and z(c)

z(s)  <  z(c)

Then z(s) is in the acceptance region we accept H₀. We don´t have enough evidence to support the breeder´s claim

Complete Question:

It is assumed that the mean weight of a Labrador retriever is 70 pounds. A breeder claims that the average weight of an adult male Labrador retriever is not equal to 70 pounds. A random sample of 45 male Labradors weigh an average of 72.5 pounds with a standard deviation of 16.1 pounds. Test the breeder's claim at \alpha=0.04

a)State null and alt hypothesis

b)determine t statistics

c)compute the P value

d) decision about the test

Answer:

a)Null Hypothesis            [tex]H_0:\mu=70[/tex]

  Alternative Hypothesis[tex]H_1=\mu \neq70[/tex]

b)   [tex]t=1.042[/tex]

c)  [tex]TDIST(1.042)=0.30310338[/tex]

d)We reject the alternative hypothesis

Step-by-step explanation:

From the question we are told that:

Population mean [tex]\mu=70[/tex]

Sample size [tex]n=45[/tex]

Sample mean [tex]\=x=72.5[/tex]

Standard deviation [tex]\sigma=16.1 pounds.[/tex]

Significance level [tex]\alpha=0.04[/tex]

a

Generally the Hypothesis is mathematically given by

Null Hypothesis            [tex]H_0:\mu=70[/tex]

Alternative Hypothesis[tex]H_1=\mu \neq70[/tex]

b) Generally the Equation for test statistics is mathematically given by

  [tex]t=\frac{\=x-\mu}{\frac{s}{\sqrt{n} } }[/tex]

  [tex]t=\frac{72.5-70}{\frac{16.1}{\sqrt{45}}}[/tex]

  [tex]t=1.042[/tex]

c)

Generally From T distribution table P value is mathematically given by

  [tex]TDIST(1.042)=0.30310338[/tex]

d)

Therefore as p value is greater tab significance level

[tex]0.30310338>0.04[/tex]

The Test statistics does nt fall in the rejection rejoin

Therefore

We reject the alternative hypothesis

Answer:

The 99% confidence interval for the proportion of drug-related deaths that were caused by legally prescribed drugs is (0.841, 0.943).

As a percentage, the confidence interval is (84.1%, 94.3%).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

223 out of 250 deaths were caused by legally prescribed drugs.

This means that:

[tex]n = 250, \pi = \frac{223}{250} = 0.892[/tex]

99% confidence level

So [tex]\alpha = 0.01[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.01}{2} = 0.995[/tex], so [tex]Z = 2.575[/tex].

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.892 - 2.575\sqrt{\frac{0.892*0.108}{250}} = 0.841[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.892 + 2.575\sqrt{\frac{0.892*0.108}{250}} = 0.943[/tex]

The 99% confidence interval for the proportion of drug-related deaths that were caused by legally prescribed drugs is (0.841, 0.943).

As a percent:

Multiply the proportions by 100%.

0.841*100% = 84.1%

0.943*100%=  94.3%

As a percentage, the confidence interval is (84.1%, 94.3%).