You throw a barbeque for your friends. Before you start the grill, your propane tank has a pressure of 78 psi. When you’re finished grilling, the temperature is 95°F and the propane tank reads 74 psi. Come nighttime the outside temperature drastically decreases to 20°C. What is the pressure of the propane tank at night?


Select one:

a. 16 kPa

b. 485 kPa

c. 107 kPa

d. 2300 kPa

Answer:

0.021

Explanation:

that's the answer because I just did an exam that included this question and then the miss explained to me why this was the answer, but don't worry am 100% sure the answer is 0.021 .

The mole fraction of ethanol in a solution of 47.5 g of ethanol in 850 g of water is 0.021.

Mole fraction of any substance present in solution will be calculted by dividing the moles of sample to the total moles of solution.

Moles will be calculated as:

n = W/M , where

W = given mass

M = molar mass

Moles of ethanol will be calculated as:

n = 47.5g / 46.07g/mol = 1.03 moles

Moles of water will be calculated as:
850g / 18g/mol = 47.18 moles

Total moles of solution = 1.03 + 47.18 = 48.21 moles

Mole fraction of ethanol in water will be calculated as:

mole fraction = 1.03 / 48.21 = 0.021

Hence, mole fraction is 0.021.

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Answer: [tex]49.7\ cm^3[/tex]

Explanation:

Given

At temperature [tex]T_1=289\ K[/tex]

Volume is [tex]V_1=42\ cm^3[/tex]

and the temperature changes to [tex]T_2=342\ K[/tex]

At this temperature volume is [tex]V_2[/tex]

Consider Pressure remains the constant

[tex]\therefore \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\\Rightarrow V_2=V_1\times \dfrac{T_2}{T_1}\\\\\text{Insert values}\\\\\Rightarrow V_2=42\times \dfrac{342}{289}\\\\\Rightarrow V_2=49.7\ cm^3[/tex]

The volume at this temperature is [tex]49.7\ cm^3[/tex]

Answer: 2.86 inches

Explanation: To find the radius, then, we insert 18 in for the circumference. So 18=2∏r. Solving for r gives 9/∏, or approximately 2.86 inches.

Answer:

2.86 inches

Explanation:

Answer:

1. Allele for shortness (t)

2. Allele for tallness (T)

Explanation:

Gregor Mendel performed numerous experiments using pea plants (Pisium sativum). He tested the height traits of pea plants by crossing tall pea plants (TT) and short pea plants (tt) to obtain offsprings that were all tall (Tt) in the first filial generation (F1).

This is possible because the allele for tallness is DOMINANT while the allele for shortness is RECESSIVE. This means that tallness allele (T) will mask the phenotypic expression of shortness allele (t) when in an heterozygous state (Tt) as in the F1 generation.

Answer:

In a physical change the appearance or form of the matter changes but the kind of matter in the substance does not. However in a chemical change, the kind of matter changes and at least one new substance with new properties is formed.

Explanation:

if this helped you should mark this the brainliest answer also you should join a meeting if you like it would be fun

Answer:

physical change is reversible but chemical change is irreveesable4

Answer:

2Na + 2H20--> 2NaOH+H2

............. this is the ans

Answer:

Have anyone found the answer to this? I’m on this grade result course right now

Explanation:

The concentration of a potassium manganate(VII) solution (KMnO4) is 10 g /L. What is the concentration of this solution in molarity is 0.06 M.

The ratio of number of moles of solute to the volume of the solution in litre is called molarity. it is denoted by symbol M.

Given concentration (C) of potassium manganate(VII) solution in g/L is 10 g /L

Molarity = C/molar mass of KMnO4 = 10g/L ÷ 158.02g/mol = 0.06 mol/L

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Answer: the answer is a

Explanation:

always eat fresh fruits and veggiies.

Answer:

The restoring force that prevents the furniture from tipping over when pushing the furniture towards the right, F= W × D

Where;

W = The weight of the furniture

D = The horizontal distance from the center of gravity of the furniture, CG and the to the lower right corner of the furniture

Given that A > D, for the furniture to tip over when pushing above the CG, we have;

F1 × A ≤ W × D

∴ F1 << W or for a force much smaller than W, the weight of the furniture applied above the center of gravity, the furniture will tip over

However when the force F2 is applied, where C < D, we have for no tipping over;

F2 × C ≤ W × D, therefore, given that C < D, when a force much higher than the weight, W, is applied at F2, the furniture will remain upright

Therefore, it is better push at a point lower than or equal to the center of gravity, whereby the point B is lower than the center of gravity, it is better to push at point B, Ravleen is correct and it is better to push at point B because the center of gravity is lower

If the furniture is pushed at the wrong spot it may tip over

Please see attached drawing

Explanation:

Answer:

d. Two moles of carbon dioxide were produced from this reaction

Explanation:

The given chemical reaction can be written as follows;

2C₂H₂ + 5O₂ → 4CO₂ + 2H₂O

From the above chemical reaction, we have;

Two moles of C₂H₂ reacts with five moles of O₂ to produce four moles of CO₂ and two moles of H₂O

We have;

One mole of C₂H₂ will react with two and half moles of O₂ to produce two moles of CO₂ and one mole of H₂O

Therefore, in the above reaction, when one mole of C₂H₂ is used, two moles of CO₂ will be produced.

Answer:

C5P4

Explanation:

the answer is C5P4 because penta is 5 and tetra is 4

Answer:

See Explanation

Explanation:

Volume of base used  = (31.79 - 1.6) + (32.12 - 0.98) + (42.87 -13.21)/3 = 30.34 cm3

Volume of acid used = (24.86 - 0.42) + (24.11 - 0.11) + (27.67 -3.42)/3 = 24.23 cm3

For trial 1= number of moles of HBr = 24.44/1000 * 0.3 = 0.0073 moles

For trial 2= number of moles of HBr = 24/1000 * 0.3 = 0.0072 moles

For trial 3= number of moles of HBr = 0.0089 moles

HBr(aq) + KOH(aq) -----> KBr(aq) + H2O(l)

One mole of base is required to neutralize one mole of acid.

From CAVA/CBVB =nA/nB

CAVAnB = CBVBnA

CB = CAVAnB/VBnA

CB = 0.3 * 24.23 * 1/30.34  * 1

CB = 0.24 moldm-3

number of moles of KOH = concentration * volume

number of moles = mass/molar mass

molar mass of KOH = 56 g/mol

mass/56 =  0.24 * 30.34/1000

mass = 0.24 * 30.34/1000 * 56

mass =0.408 g of KOH

Answer:

the addition to solute decreases the solvent's vapor pressure. a temperature must then be applied to overcome the change

Explanation:

Answer:

long story short: A

Explanation:

Explanation:

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The molarity (M) of a solution is 11.5 M that contains 0.75 moles of lithium fluoride, LiF in a 65 ml of solution.

Molarity (M) is defined as the number of moles of solute dissolved in 1L of solution. Molarity is also known as Molar concentration. The S.I Unit of Molarity is molar (M) or mol/L.

Molarity (M) = [tex]\frac{\text{Number of moles of solute}}{\text{Volume of solution (in liters)}}[/tex]

From the above definition it is clear that the volume of solution is in liter. In question the volume of solution is given in ml.

So, convert 65 ml into l.

65 ml = [tex]\frac{65}{1000}[/tex] = 0.065 l

Now, put the values in above formula, we get that

(M) = [tex]\frac{0.75}{0.065}[/tex] = 11.5 M

Thus, the molarity of a solution is 11.5 M that contains 0.75 moles of lithium fluoride, LiF in a 65 ml of solution.

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Answer:

Explanation:

44.5 g Al2(SO4)3

Explanation:

# moles Ba(NO3)2 = (0.543M)(0.717 L)

= 0.389 mol Ba(NO3)2

Now we use the molar ratios,

0.389 mol Ba(NO3)2 ×(1 mol Al2(SO4)3/3 mol Ba(NO3)2)

= 0.130 mol Al2(SO4)3

0.130 mol Al2(SO4)3 × (342.15 g Al2(SO4)3/(1 mol Al2(SO4)3)

= 44.5 g Al2(SO4)3

Answer:

sodium phosphide!!!!!!!!!!!!!!!

The Balanced chemical equation for above reaction will be :

[tex] \small{ \mathrm{3NaBr + H_3PO_4 \rightarrow Na_3PO_4 + 3HBr}}[/tex]

The Coefficients will be :

So, Correct option is :

A. 3, 1, 1, 3

_____________________________

[tex]\mathrm{ \#TeeNForeveR}[/tex]

Answer:

0.11 moles

Explanation:

The equation of the reaction is;

2SO2 + O2 ------>2SO3

Number of moles of O2 in 3.42 g = 3.42g/32 g/mol = 0.11 moles

Hence, 0.11 moles of O2 is consumed when 3.42 g of O2 reacts with SO2 to form SO3.

Answer:

433 m

Explanation:

Since the fall represents motion under gravity, we use the equation

s = ut - 1/2gt² where s = height of cliff or distance bowling ball falls through, u = initial velocity of bowling ball = 0 m/s(since it starts from rest), t = time = 9.4 s and g = acceleration due to gravity = -9.8 m/s².

So, substituting the values of the variables into the equation, we have

s = 0 m/s × 9.4 s - 1/2 × 9.8 m/s² × (9.4 s)²

s = 0 m - 1/2 × -9.8 m/s² × 88.36 s²

s = 1/2(865.928 m)

s = 432.964

s ≅ 433 m

Answer:

The correct answer is - Pine tree.

Explanation:

Coniferous trees or cone-bearing trees normally called conifers adapted their leaves and have needles like leaves that retain more water. Needles do not appear to be leaves but are modified leaves.

Conifer trees adapt this leaf modification to prevent water loss due to transpiration in the case of dry air or atmosphere. Important members of the conifer trees are pine trees, cedars, spruces, and Pines.

Answer:

12

my advice is split the equation into 2 and write on each side how many atoms of each element are there and it will be easier to balance.

(D)

Explanation:

On the left side two molecules, each made of 2 grays and 3 blues, which suggests that only (D) offers the right combination: 2 Al atoms and 3 O atoms that make up Al2O3.