You are the lead crime scene investigator for a home robbery case. The robber cut their finger on a piece of glass that was left at the crime scene. The blood from the glass was sent to your lab. You also have cheek swabs from 3 suspects. a. What DNA test would you perform to analyze these samples? b. List the steps in order that you would complete to finish the forensic science part of the investigation.

Answers

Answer 1

DNA test you would perform to analyze these samples: STR analysis Short Tandem Repeats (STR) analysis is a DNA test that you would perform to analyze these samples.

This is because this test analyzes the variations in the DNA sequence and specifically identifies repeating patterns that are unique to individuals you would take to complete the forensic science part of the investigation To complete the forensic science part of the investigation, the following are the steps you would take in order Collect samples from the crime scene.

The first step you would take is to collect the samples from the crime scene. This would include the glass with the blood on it Collect DNA samples from suspects You would then collect DNA samples from the three suspects. This could be done by taking cheek swabs. Extract DNA from the samples You would then extract the DNA from the samples. This is done by breaking down the cells to release the DNA Amplify the DNA After extracting the DNA, the next step is to amplify it.

This is done by using the Polymerase Chain Reaction (PCR) technique. This process makes many copies of the DNA so that there is enough to analyze. The final step is to compare the DNA samples. This would involve looking for matches between the DNA from the crime scene and those of the suspects. This would help to identify the perpetrator of the crime.

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Related Questions

A virus that has entered the lysogenic cycle: Cannot replicate its genome Can only replicate its genome when environmental conditions are favorable Replicates its genome when its host cell replicates Can only replicate its genome when it exits the lysogenic cycle and enters the lytic cycle

Answers

A virus that has entered the lysogenic cycle: Cannot replicate its genome Can only replicate its genome when environmental conditions are favorable Replicates its genome when its host cell replicates Can only replicate its genome when it exits A virus that has entered the lysogenic cycle replicates its genome when its host cell replicates.

In the lysogenic cycle, a virus integrates its genetic material into the host cell's genome and remains dormant. During this phase, the virus does not immediately replicate its genome but instead relies on the host cell's replication machinery to replicate its genetic material along with the host's DNA. When the host cell undergoes replication, the viral genome is also replicated, allowing it to be passed on to daughter cells. Therefore, a virus in the lysogenic cycle replicates its genome when its host cell replicates.

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Briefly describe multiple sclerosis. Include information about
the location of lesions, aetiology and clinical manifestations of
the disease.

Answers

Multiple sclerosis (MS) is an autoimmune, inflammatory, and demyelinating disease of the central nervous system (CNS) that involves the destruction of myelin in axons, followed by axonal loss and gliosis. MS is a chronic and unpredictable disease that has a variety of symptoms and affects approximately 2.5 million people worldwide. It is a disease that typically affects people in their prime of life, ranging from 20 to 40 years old. The etiology of MS is still unknown; however, it is hypothesized that it is a combination of environmental factors and genetic susceptibility.  Lesions are usually located in the brain and spinal cord, which leads to a variety of clinical manifestations.

Lesions are typically scattered throughout the CNS, resulting in clinical symptoms that are dependent on their location and size. MS symptoms can be divided into motor, sensory, cerebellar, and visual symptoms. In addition, urinary and bowel problems, as well as cognitive and psychological symptoms, can occur. Treatment for MS can range from symptomatic and supportive to disease-modifying therapy, and the prognosis varies depending on the type of MS and the severity of the disease.

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1. Discuss how carbon sources will affect the microbes that grow in the Winogradskycolumn.
2. If samples were extracted from the various layers of all the columns, where would you find photosynthetic organisms such as cyanobacteria and algae? Explain why

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Additionally, these organisms require oxygen for photosynthesis, which is also available in the upper layers of the column. Therefore, the presence of these photosynthetic organisms in the upper layer of the Winogradsky column indicates a well-oxygenated environment with sufficient light for photosynthesis to occur.

1. Carbon sources will affect the microbes that grow in the Winogradsky columnCarbon sources are key to the survival and growth of microbes in the Winogradsky column. In this column, the presence of various carbon sources will affect the types of microbes that grow in different areas. Some carbon sources include carbohydrates, fatty acids, amino acids, and organic acids such as citric acid, malic acid, and succinic acid. The availability of these different carbon sources will determine which microbes can grow, as different microbes have different metabolic pathways and are capable of using different carbon sources.2. Cyanobacteria and algae in the Winogradsky columnPhotosynthetic organisms such as cyanobacteria and algae will be found in the upper layer of the Winogradsky column. This is because they require sunlight to carry out photosynthesis, which is only available in the uppermost layers of the column. Additionally, these organisms require oxygen for photosynthesis, which is also available in the upper layers of the column. Therefore, the presence of these photosynthetic organisms in the upper layer of the Winogradsky column indicates a well-oxygenated environment with sufficient light for photosynthesis to occur.

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Muscle cells need ATP to function. Briefly explain why muscle cells use different metabolic fuels for different levels of activity (10 marks)

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Muscle cells utilize various metabolic fuels for different levels of activity due to the varying demands of energy production.

Muscle cells require a constant supply of ATP (adenosine triphosphate) to carry out their functions. ATP serves as the energy currency for cellular processes, including muscle contraction. However, the amount of ATP required by muscle cells can vary depending on the level of activity.

During low-intensity activities such as resting or light exercise, muscle cells primarily rely on oxidative metabolism. This process involves the breakdown of glucose or fatty acids through aerobic respiration, resulting in the production of ATP. This fuel choice is efficient and allows for sustained energy production.

On the other hand, during high-intensity activities such as intense exercise or rapid movements, muscle cells require a rapid and substantial energy supply. To meet this demand, muscle cells switch to anaerobic metabolism.

This metabolic pathway involves the breakdown of glucose in the absence of oxygen, leading to the production of ATP through glycolysis. While anaerobic metabolism generates ATP quickly, it is less efficient and can only sustain energy production for short durations.

The utilization of different metabolic fuels by muscle cells ensures that they can adapt to varying energy requirements. By employing oxidative metabolism during low-intensity activities, muscle cells can efficiently produce ATP and maintain sustained energy production.

In contrast, the shift to anaerobic metabolism during high-intensity activities allows for rapid ATP production, although it is less efficient and suitable for short bursts of energy. This metabolic flexibility enables muscle cells to meet the demands of different levels of activity.

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Listen In an organism that reproduces asexually, offspring are genetically identical to the parent reflect combinations of genes from both par are unlikely to ever reproduce themselves will always reproduce sexually

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In an organism that reproduces asexually is option 1. Offspring are genetically identical to the parent.

1. Offspring are genetically identical to the parent: This statement is correct. Asexual reproduction is a method of reproduction that does not involve the fusion of gametes. It results in the production of offspring that are genetically identical or clones of the parent, as they inherit an identical set of genes.

2. Reflect combinations of genes from both parents: This statement is incorrect. Asexual reproduction does not involve the contribution of genetic material from two parents. Unlike sexual reproduction, there is no recombination of genes, and the offspring do not reflect combinations of genes from both parents.

3. Are unlikely to ever reproduce themselves:   This statement is incorrect. Many asexual organisms are capable of reproducing asexually and can generate offspring of their own without the need for sexual reproduction. Asexual reproduction can be a successful and prevalent reproductive strategy in certain organisms.

4. Will always reproduce sexually: This statement is incorrect. Asexual reproduction can occur independently of sexual reproduction and does not involve the fusion of gametes from different individuals.

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The complete question is:

In an organism that reproduces asexually,

1. offspring are genetically identical to the parent

2. reflect combinations of genes from both parents

3. are unlikely to ever reproduce themselves

4. will always reproduce sexually

Hi there. I'm having some difficulty wrapping my head around this question and some help would be great!
a) How is it possible that an mRNA in a cell can be found throughout the cytoplasm but the protein it encodes for is only found in a few specific regions? What type of regulation would this be?

Answers

There are various ways that the location of a protein can be regulated. One such way is post-transcriptional regulation which allows for the regulation of protein levels by regulating mRNA stability, translation initiation and mRNA localization throughout the cytoplasm.

The mRNA molecules are not the only molecules to be regulated post-transcriptionally. Small non-coding RNAs and microRNAs may also regulate gene expression by binding to specific mRNA targets. This mechanism provides another level of regulation, which may be exploited to develop novel therapies for genetic diseases.

Once an mRNA molecule is produced, it can be regulated through various mechanisms, such as alternative splicing, which is the process of making different transcripts from the same gene.

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Which cancers can potentially be treated with T-cell
mediated Immunotherapy?

Answers

It is important to note that the efficacy of T-cell mediated immunotherapy can vary depending on individual patient characteristics and cancer subtypes. Ongoing research and clinical trials are continuously exploring the potential of immunotherapy in treating a wider range of cancers, and the field is evolving rapidly with new advancements and discoveries.

T-cell mediated immunotherapy has shown potential for treating various types of cancers. The specific cancers that can potentially be treated with this approach include:

1. Melanoma: Immunotherapy has demonstrated remarkable success in treating advanced melanoma, a type of skin cancer. T-cell-based therapies, such as immune checkpoint inhibitors and adoptive cell transfer, have shown promising results in improving patient outcomes.

2. Non-small cell lung cancer (NSCLC): Immunotherapy has emerged as a valuable treatment option for NSCLC. Immune checkpoint inhibitors that target programmed cell death protein 1 (PD-1) or its ligand (PD-L1) have been approved for advanced NSCLC and have shown significant clinical benefits.

3. Leukemia and lymphoma: Immunotherapy approaches, including chimeric antigen receptor (CAR) T-cell therapy, have shown promising results in the treatment of certain types of leukemia and lymphoma. CAR-T cell therapy involves modifying a patient's own T cells to express receptors that can recognize specific cancer cells, leading to their targeted elimination.

4. Bladder cancer: Immunotherapy, particularly immune checkpoint inhibitors targeting PD-1/PD-L1, has shown efficacy in treating advanced bladder cancer. These treatments have demonstrated durable responses and improved survival rates in some patients.

5. Renal cell carcinoma: Immunotherapies, such as immune checkpoint inhibitors, have shown promise in treating renal cell carcinoma, a type of kidney cancer. These therapies can enhance the immune response against cancer cells and improve patient outcomes.

6. Head and neck cancers: Immunotherapy has emerged as a valuable treatment option for certain head and neck cancers, including squamous cell carcinoma. Immune checkpoint inhibitors have shown efficacy in improving survival rates and quality of life in these patients.

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Which of the following cancer chemotherapeutic agents is
produced by a fungus? Group of answer choices
a. psilocybe
b. taxol
c. iturine
d. penicillin

Answers

Taxol is the cancer chemotherapeutic agent that is produced by a fungus. It is also known as paclitaxel.

Taxol is an anti-cancer chemotherapy drug used in the treatment of breast, ovarian, lung, bladder, prostate, and pancreatic cancers. It was originally derived from the bark of the Pacific yew tree.

Later on, the fungus Taxomyces andreanae, which grows on the Pacific yew tree, was discovered to be the actual source of taxol.Fungal metabolites have played a major role in developing drugs used in chemotherapy.

Other chemotherapeutic agents produced by fungi include iturine and griseofulvin. Penicillin is an antibiotic produced by the fungus Penicillium.

Psilocybe is a genus of fungi that contains species known for their hallucinogenic properties. However, it does not produce cancer chemotherapeutic agents.

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Select the true statements about enhancer sequences enhancers are common in both prokaryotes and eukaryotes one gene may have multiple enhancers enhancers encode proteins enhancer are located next to the transcription start sit enhancers are cis-regulatory elements

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The true statements about enhancer sequences are: Enhancers are common in both prokaryotes and eukaryotes. One gene may have multiple enhancers. Enhancers are located next to the transcription start site. Enhancers are cis-regulatory elements.

Enhancers are DNA sequences that play a crucial role in regulating gene expression. They are found in both prokaryotes and eukaryotes, although their complexity and organization differ between the two. Enhancers can be located upstream, downstream, or even within the gene they regulate. They are cis-regulatory elements, meaning they act on the same DNA molecule they are located on.

One gene can have multiple enhancers, and each enhancer can function independently, binding specific transcription factors and modulating gene expression. Enhancers do not encode proteins themselves but rather serve as binding sites for transcription factors and other regulatory proteins. These proteins, when bound to enhancer sequences, can enhance or activate gene transcription.

Enhancers are positioned near the transcription start site, allowing them to interact with the gene's promoter region and initiate transcriptional activity. They communicate with the transcriptional machinery, leading to the recruitment of RNA polymerase and the initiation of transcription.

In summary, enhancers are common in both prokaryotes and eukaryotes and are cis-regulatory elements located near the transcription start site. They do not encode proteins themselves but function as binding sites for transcription factors. One gene can have multiple enhancers, and they play a vital role in modulating gene expression.

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Which of the following would not promote the development of a cancer cell: o a, constitutive activation of a proto-oncogene b.overexpression of a proto-oncogene c. Inactivation of a tumor suppressor gene d.overexpression of a tumor suppressor gene

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The option d. overexpression of a tumour suppressor gene would not aid in the growth of a cancer cell.Genetic changes that affect how cell growth and division are normally regulated contribute to the development of cancer.

Normal genes called proto-oncogenes have the potential to turn into oncogenes and aid in the progression of cancer. When a proto-oncogene is constitutively activated, as in option a, it remains activated continuously, promoting unchecked cell development and perhaps resulting in cancer.When a proto-oncogene is overexpressed, as in option b, more of it is produced, which causes aberrant stimulation of cell growth and division and may aid in the formation of cancer.a tumour suppressor gene is inactivated, as in option c, the growth-inhibitory regulation is removed, allowing aberrant cells to multiply and perhaps lead to development.

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b. Calculate p for the North American population. Record your answer as a frequency with two decimal places. c. Calculate the frequency of heterozygotes for the North American population. Record your answer as a frequency with two decimal places. 2. For a recent biology class 16 of the 24 students could not taste PTC. ( 1 point each) a. What is the frequency of non-tasters in this population? Record your answer as a frequency with two decimal places.

Answers

1a. q, the frequency of non-tasters = 0.45

1b. p, the frequency of the dominant allele (taster allele) = 0.55

1c. The frequency of heterozygotes in the North American population is approximately 0.495.

2. The frequency of non-tasters in the population is approximately 0.67.

What is the frequency of the non-tasters?

To calculate the frequencies of the alleles in the North American population:

a. Calculate q for the North American population:

q represents the frequency of the recessive allele (non-taster allele).

q = frequency of non-tasters = 0.45

b. Calculate p for the North American population:

p represents the frequency of the dominant allele (taster allele).

p = 1 - q = 1 - 0.45 = 0.55

c. Calculate the frequency of heterozygotes for the North American population:

Heterozygotes have one copy of the dominant allele (T) and one copy of the recessive allele (t).

Frequency of heterozygotes (2pq) = 2 * p * q

Frequency of heterozygotes = 2 * 0.55 * 0.45 = 0.495

2. To calculate the frequency of non-tasters (homozygous recessive) in the given population:

Total students in the population = 24

Number of non-tasters = 16

Frequency of non-tasters = Number of non-tasters / Total students

Frequency of non-tasters = 16 / 24

Frequency of non-tasters ≈ 0.67

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Complete question:

1. Recall that the ability to taste PTC (T) is dominant to the inability to taste. We will treat it as completely dominant. For the North American population, the frequency of tasters is 0.55 and the frequency of non-tasters is 0.45. (1 point each) Record your answer as a

a. Calculate q for the North American population. frequency with two decimal places.

b. Calculate p for the North American population. Record your answer as a frequency with two decimal places.

c. Calculate the frequency of heterozygotes for the North American population. Record your answer as a frequency with two decimal

Can you please help me answer the following questions in your own words and in much details as possible. I really need them and I will rate.
1. Describe how the immune system is able to produce receptors against a wide variety of antigens when the immune system has not yet encountered foreign antigens?
2. Explain how an individual’s first and subsequent exposures to an allergen differ by describing how the immune system responds to exposure.
3. Describe osponization and its role in immunity.
4. Describe the steps that hospitals take to ensure that people do not have incompatible blood transfusions.

Answers

1. The immune system is capable of producing receptors against a wide variety of antigens even in the absence of prior exposure to foreign antigens through mechanisms such as genetic recombination, somatic hypermutation, and repertoire diversity.

2. During the first exposure, the immune system recognizes the allergen as foreign and mounts an immune response, which can result in the production of allergen-specific antibodies.

Subsequent exposures lead to an exaggerated immune response, with the allergen binding to pre-existing antibodies and triggering the release of inflammatory mediators.

3. Opsonization is a process in which antibodies or other molecules coat pathogens, facilitating their recognition and engulfment by immune cells. It enhances phagocytosis and clearance of pathogens by immune cells, playing a crucial role in immunity.

4. Hospitals take several steps to ensure compatibility in blood transfusions, including ABO and Rh typing, cross-matching, and following strict protocols to prevent errors and mismatched transfusions.

1. The immune system has a remarkable ability to produce receptors against a wide variety of antigens, even when it has not encountered foreign antigens before. This diversity is achieved through mechanisms such as genetic recombination and somatic hypermutation.

Genetic recombination occurs during the development of immune cells, where gene segments encoding antigen receptor proteins are rearranged randomly, leading to a vast repertoire of potential receptor specificities.

Somatic hypermutation introduces point mutations in the genes encoding the receptor proteins, further increasing diversity. These mechanisms generate a diverse pool of immune cells with the potential to recognize and respond to a wide range of antigens.

2. During an individual's first exposure to an allergen, the immune system recognizes the allergen as foreign. Antigen-presenting cells capture and process the allergen, presenting it to specific immune cells called T cells.

This triggers the production of allergen-specific antibodies, such as immunoglobulin E (IgE). These IgE antibodies bind to mast cells and basophils, priming them for subsequent exposures.

On subsequent exposures, the allergen binds to the pre-existing IgE antibodies on mast cells and basophils, leading to the release of inflammatory mediators, such as histamine. This results in an exaggerated immune response, causing allergy symptoms.

3. Opsonization is a process by which antibodies or other molecules coat pathogens, making them more recognizable to immune cells. Antibodies, particularly immunoglobulin G (IgG), can bind to pathogens, marking them for recognition by phagocytic cells, such as macrophages and neutrophils.

The binding of antibodies to pathogens enhances phagocytosis, making it easier for immune cells to engulf and destroy the pathogens. Opsonization also activates complement proteins, which further facilitate pathogen recognition and clearance.

By promoting phagocytosis and activating the immune response, opsonization plays a crucial role in the immune system's ability to eliminate pathogens and provide protection against infections.

4. Hospitals take several precautions to ensure compatibility in blood transfusions. Before a transfusion, the blood type of the donor and recipient is determined through ABO and Rh typing. ABO typing identifies the presence of A, B, AB, or O antigens on red blood cells, while Rh typing determines the presence or absence of the Rh antigen.

Cross-matching is then performed, where the recipient's plasma is mixed with the donor's red blood cells to check for compatibility and potential adverse reactions.

Hospitals follow strict protocols, including multiple checks and verification processes, to prevent errors and mismatched transfusions. These measures are crucial to ensure patient safety and minimize the risk of transfusion reactions or other complications.

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1) What are the three stages/processes of a typical cell cycle (including all the events within each stage)? From beginning (prep), to completion (splitting into new identical cells) Answer: 2) What are the three stages of interphase? What happens in each stage? Answer: 3) What happens with DNA (chromatid) during S phase? Answer: 4) During prophase how many replicated chromosomes are in the cell? Answer: 5) During anaphase how many chromosomes are in the cell? Answer: 6) What is a chromatid? Answer: 7) In cell division, you start with one parent cell, what is produced at the end of cytokinesis? Answer: 8) What are the major differences between animal and plant mitosis? Answer:

Answers

1) The three stages/processes of a typical cell cycle (including all the events within each stage) are as follows:i. Interphase- During this stage, the cell prepares for the division. The interphase is further divided into G1, S, and G2 phases.ii. Mitosis - In this stage, the cell divides into two identical daughter cells. Mitosis is also divided into different sub-stages such as prophase, metaphase, anaphase, and telophase.iii. Cytokinesis - In this stage, the cell divides into two identical daughter cells completely.2) The three stages of interphase are as follows:G1 Phase - This phase is responsible for cell growth and metabolic activitiesS Phase - In this phase, DNA replication occursG2 Phase - This phase ensures the cell is ready for mitosis3) During S-phase, the DNA or chromatid replicates, resulting in the formation of identical chromatids or sister chromatids.

4) During prophase, there are replicated chromosomes in the cell.5) During anaphase, the cell has twice as many chromosomes as there are in G1 phase, and the chromosomes move towards opposite poles.6) A chromatid is one-half of the replicated chromosome that is joined to another chromatid at the centromere.7) At the end of cytokinesis, two identical daughter cells are produced.8) The major differences between animal and plant mitosis are as follows:Animal mitosis - In animal mitosis, the cell membrane constricts inwards, forming a cleavage furrow that separates the two daughter cells.Plant mitosis - In plant mitosis, the cell plate forms at the center of the cell and divides the cell into two equal halves.

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What is the source of the reducing power used to fix carbon dioxide in the Calvin cycle? a) The light reactions. b) NADP. c) Hexoses like glucose. d) Mitochondria

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The source of reducing power used to fix carbon dioxide in the Calvin cycle is NADPH (nicotinamide adenine dinucleotide phosphate).

NADPH is synthesized during the light-dependent reactions of photosynthesis and used in the Calvin cycle to reduce CO2 to sugar. The light-dependent reactions occur in the thylakoid membranes of the chloroplast and they produce ATP and NADPH from light energy.NADPH is the primary reducing agent used in the Calvin cycle, which occurs in the stroma of the chloroplast. The Calvin cycle uses ATP and NADPH, which are produced by the light-dependent reactions, to synthesize sugars from CO2. The first step of the cycle is the fixation of CO2 by the enzyme Rubisco (ribulose-1,5-bisphosphate carboxylase/oxygenase).This reaction produces an unstable 6-carbon molecule that immediately breaks down into two 3-carbon molecules of 3-phosphoglycerate. ATP and NADPH are then used to convert 3-phosphoglycerate into glyceraldehyde 3-phosphate (G3P), which can be used to synthesize glucose and other sugars.The main answer to the question is that the source of the reducing power used to fix carbon dioxide in the Calvin cycle is NADPH, which is produced during the light-dependent reactions of photosynthesis in the thylakoid membranes of the chloroplast. In the Calvin cycle, ATP and NADPH are used to synthesize sugars from CO2, which are used as a source of energy by the plant. Therefore, NADPH is an important molecule in photosynthesis, as it provides the reducing power needed for the Calvin cycle to synthesize sugars from CO2.

NADPH is the reducing agent used in the Calvin cycle to fix carbon dioxide.

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Which statement IS CORRECT regarding the release factor during translation? It is a protein which helps the release of tRNA from the ribosome O All of the answers O It is a protein which binds to A-site bearing the stop codon on mRNA It is an empty tRNA which binds to A-site bearing the stop codon on mRNA M

Answers

The correct statement regarding the release factor during translation is: It is a protein which binds to A-site bearing the stop codon on mRNA. So the option (c) is correct statement

The release factor is an essential protein which helps in the termination of protein synthesis. In order to stop protein synthesis, release factors bind to A-site bearing the stop codon on mRNA. The stop codons UAA, UAG, and UGA (amino acid codons) do not match any tRNA molecule.

Because of this, instead of a tRNA molecule, a release factor binds to the A site of the ribosome, causing the formation of a peptide bond between the polypeptide chain and a molecule of water. As a result, the polypeptide chain is released from the ribosome. Read more on protein synthesis. So the option (c) is correct statement

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The full question is given below

Which statement IS CORRECT regarding the release factor during translation?

(a)It is a protein which helps the release of tRNA from the ribosome

(b) All of the answers

(c) It is a protein which binds to A-site bearing the stop codon on mRNA

(d)It is an empty tRNA which binds to A-site bearing the stop codon on mRNA M

The correct option regarding the release factor during translation is "It is a protein which binds to A-site bearing the stop codon on mRNA". Therefore, option C is correct.

The genetic code is a sequence of nucleotides that instructs the ribosome to synthesize proteins. Translation is the process of reading the genetic code to produce a protein. The genetic code is read in a three-nucleotide segment known as a codon.The release factor is a protein that is important in terminating protein synthesis. When a stop codon appears on the mRNA, it binds to the A site of the ribosome, the release factor binds to the site, triggering the ribosome to release the newly synthesized protein from the ribosome. The polypeptide chain is separated from the tRNA molecule in the P-site by the hydrolysis of the bond between the polypeptide and the tRNA molecule.

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Females are expected to be larger or more brightly colored than the males in a population when Females have lower average reproductive success than males. Females have higher average reproductive success than males. Females have lower variance in reproductive success than males. Females and males have equal variance in reproductive succcess. Females have higher variance in reproductive success than males.

Answers

Females are larger or more brightly colored than males when they have **higher variance** in reproductive success.

In species where females have higher variance in reproductive success, some females are able to have many offspring, while others have few or no offspring. This creates a strong selection pressure for females to be able to compete for mates and resources. Larger or more brightly colored females are often more successful at attracting mates and raising offspring, so these traits are more likely to be passed on to the next generation.

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Arrange these parts of a neuron in an order that would receive, integrate, and transmit a signal to another cell. Dendrite Cell Body Synapse Axon Collateral

Answers

Neurons are the building blocks of the nervous system, and the parts of a neuron are responsible for carrying out various functions. The dendrite, cell body, axon, collateral, and synapse are the five main components of a neuron. The dendrites are responsible for receiving signals from other neurons and transmitting them to the cell body.

The cell body, also known as the soma, integrates incoming signals and generates an output signal that travels along the axon. The axon is responsible for transmitting the signal to other cells, either neurons or muscle cells. The collateral is a branch of the axon that can transmit signals to multiple cells, allowing for the coordination of complex movements or behaviors. Finally, the synapse is the point at which the axon terminal of one neuron communicates with another neuron or muscle cell.

The order in which these parts of a neuron are arranged to receive, integrate, and transmit a signal to another cell is: dendrite, cell body, axon, collateral, synapse.

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For bacterial species that have a large difference between core genome size and pan-genome size, what is a leading explanation for how this was influenced by the ecological niche of the species.
A. Species living in niches with more species diversity are less likely to undergo horizontal gene transfer in comparison to niches with little or no species diversity.
B. Species living in niches with more species diversity are likely to evolve defense mechanisms that prevent horizontal gene transfer.
C. Species living in niches with more species diversity are more likely to undergo horizontal gene transfer in comparison to niches with little or no species diversity.
D. Species with larger core genomes relative pan genomes are better adapted to evolve inside eukaryotic cells as obligate intracellular organisms.
RNA velocity measurements are useful for analyzing what type of sequencing data?
A. single cell RNA-seq
B. RNA-seq of polyA purified mRNA
C. SNP genotyping of transcribed genes
D. allele-specific transcript expression

Answers

1. For bacterial species with a large difference between core genome size and pan-genome size, the leading explanation for how this is influenced by the ecological niche of the species is that species living in niches with more species diversity are more likely to undergo horizontal gene transfer, leading to a larger pan-genome size .

2. RNA velocity measurements are useful for analyzing single-cell RNA-seq data.

Therefore, the correct answer is option C for the first question and option A for the second question.

1. Bacterial species have a core genome, which consists of genes shared by all members of the species, and a pan-genome, which includes the core genome plus the accessory genome composed of genes present in only a subset of strains. The size of the pan-genome can vary greatly among bacterial species, and this variation can be influenced by the ecological niche in which the species resides.

Horizontal gene transfer is the transfer of genetic material between different organisms, and it can contribute to the expansion of the pan-genome. In niches with more species diversity, there is a higher likelihood of encountering and interacting with diverse bacterial species, increasing the opportunities for horizontal gene transfer events. This can lead to the acquisition of new genetic material, resulting in a larger pan-genome size for the bacterial species.

2. RNA velocity measurements, as mentioned in option A, are indeed useful for analyzing single-cell RNA-seq data. RNA velocity is a computational method that leverages the splicing dynamics of RNA molecules to infer the rate at which genes are being transcribed and the direction of their expression changes over time. It provides insights into the developmental trajectories and cell state transitions within a population of cells, allowing researchers to study gene expression dynamics and infer the directionality of cellular processes.

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What are the different types of streaking techniques in
microbiology?

Answers

There are three main types of streaking techniques commonly used in microbiology: the quadrant streak method, the T-streak method, and the zigzag streak method.

Quadrant Streak Method:

This technique involves dividing the agar plate into four quadrants. A sterile loop or a streaking tool is used to inoculate a small amount of the sample onto the first quadrant. Then, without re-inoculating, the loop is dragged across the surface of the first quadrant into the second, and then into the third quadrant. Finally, the loop is dragged from the third quadrant into the fourth, resulting in the gradual dilution of the sample. This technique is useful for obtaining isolated colonies for further analysis or identification.

T-Streak Method:

In this method, a single streak is made down the center of the agar plate, resembling the letter "T." The loop is then dragged across the surface of the initial streak, back and forth, without crossing over into the previously streaked area. The T-streak technique is commonly used to obtain pure cultures by isolating individual colonies at the terminal end of the streak.

Zigzag Streak Method:

This technique involves creating a series of zigzag streaks across the surface of the agar plate. The loop is moved back and forth across the plate, overlapping the previous streaks slightly. This method is useful for obtaining a mixed culture or for spreading the sample evenly across the plate.

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One of Gregor Mendel's key findings was a. that inheritance involved the blending of parental characteristics.
b. that purple is always dominant to any other flower color. c. that there are usually more than two alleles for each trait.
d. that inheritance was of a particulate nature.
e. that crossing over occurs in meiosis.

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The main answer is d. that inheritance was of a particulate nature.  Gregor Mendel's key finding was that inheritance was of a particulate nature.

He conducted extensive experiments with pea plants and observed that traits were inherited as discrete units, which he called "factors" (later termed "genes"). He proposed that these factors were passed down from parents to offspring unchanged, without blending or mixing. This idea contradicted the prevailing notion of blending inheritance, which suggested that parental traits would blend together in offspring. Mendel's discovery laid the foundation for the field of genetics and provided crucial insights into the mechanisms of inheritance, including the principles of dominance, segregation, and independent assortment. His work is now considered the basis of classical genetics.

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1. Multiple answer: Select the three options that are correct. There are three important metabolites that allow incorporation of nitrogen from the ammonium ion in humans. These metabolites are: a. Aspartate b. Carbamate c. Carbamoyl-phosphate d. Glutamate e. Glutamine

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The three correct metabolites that allow the incorporation of nitrogen from the ammonium ion in humans are aspartate, glutamate, and glutamine. The correct options are A, D & E.

These metabolites play essential roles in nitrogen metabolism and amino acid synthesis. Glutamine acts as a carrier of amino groups, allowing for the transport and delivery of nitrogen to various tissues.

Glutamate serves as a precursor for the synthesis of other amino acids through a process called transamination. Aspartate is involved in the urea cycle, where it combines with citrulline to form argininosuccinate, a key intermediate in the removal of ammonia from the body.

These metabolites facilitate the efficient utilization and elimination of nitrogen, contributing to overall nitrogen balance and the synthesis of important biomolecules in human metabolism.

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describe lysogenic conversion and its significance
[10]

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Lysogenic conversion is a phenomenon in which a bacteriophage integrates its genetic material into the genome of its bacterial host, resulting in the transfer of new genes and traits to the bacterium.

Lysogenic conversion occurs when a temperate bacteriophage infects a bacterial cell and integrates its genetic material, called a prophage, into the bacterial genome. Unlike the lytic cycle, where the bacteriophage immediately lyses the host cell to release new viral particles, the prophage remains dormant within the bacterial chromosome. During this latent phase, the prophage is replicated along with the bacterial DNA during cell division.

Lysogenic conversion is significant because it allows for the transfer of new genetic material to the bacterial host. The integrated prophage can carry genes that encode for specific virulence factors or other advantageous traits. These genes can alter the behavior, metabolism, or pathogenicity of the bacterial host, enabling it to adapt to new environments, evade the host immune system, or enhance its ability to cause disease. Lysogenic conversion has been observed in various pathogenic bacteria, such as Vibrio cholerae, which acquires genes encoding cholera toxin through lysogeny, contributing to the severity of cholera infections.

Overall, lysogenic conversion plays a crucial role in bacterial evolution and the acquisition of virulence factors, providing a mechanism for bacteria to acquire new traits that can enhance their survival and pathogenic potential.

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Why can gene duplication lead to so much important variation in gene families such as the globin genes? A.because any time a duplication occurs "good things" happen
B. because the duplicated copy is now free to evolve a new function
C. it can't.gene duplication is always bad D.this can only happen in genes that are not very important to the survival of the organism

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Gene duplication can lead to significant variation in gene families, such as globin genes, as the duplicated copy is free to evolve new functions, increasing genetic diversity and  providing new adaptive advantages.

Gene duplication is a crucial mechanism in the evolution of gene families and the generation of genetic diversity. When a gene is duplicated, an extra copy of the gene is created in the genome. This duplicated copy is not subjected to the same selective pressures as the original gene and is therefore free to accumulate mutations and evolve new functions.

The duplicated gene copy can undergo various evolutionary processes, such as neofunctionalization or subfunctionalization. Neofunctionalization occurs when the duplicated copy acquires a completely new function that was not present in the original gene. This can result in the evolution of novel traits or biochemical activities.

On the other hand, subfunctionalization occurs when the duplicated copies divide the functions of the original gene between them. Each copy retains only a subset of the original functions, and this division of labor allows for functional specialization and potentially increased efficiency.

In the case of gene families like the globin genes, which play crucial roles in oxygen transport and storage, gene duplication has led to the evolution of multiple globin genes with specialized functions. Different globin genes have diversified to adapt to specific physiological conditions, such as oxygenation at different levels, in different tissues or developmental stages, or under different environmental conditions.

In summary, gene duplication provides opportunities for genetic variation and innovation by allowing duplicated gene copies to acquire new functions or divide existing functions. This process is crucial in the evolution of gene families like the globin genes, leading to the diversification and specialization of genes within the family, ultimately contributing to the adaptability and evolutionary success of organisms.

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2. What is meant by sensory transduction and how are ions and membrane potentials involved? 3. How can the brain interpret action potentials from different stimuli into meaningful integration? In other words how does the brain distinguish between different touch signals (gentle vs greater pressure)? 4. If all stimuli reach the brain by action potentials, how then can we distinguish one stimulus to another? In other words, how can we distinguish between sight, sounds and smell? 5. What are the two ways a transduction can be modified? Give a specific example of both. 6. Describe how action potentials are initiated by mechanoreceptors and chemoreceptors. Give an example for both.

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2. Sensory transduction refers to the process by which sensory stimuli (such as light, sound, or touch) are converted into electrical signals or action potentials that can be understood and processed by the nervous system. In this process, sensory receptors in our body detect the stimuli and convert them into electrical signals that can be transmitted to the brain for interpretation.

Ions and membrane potentials play a crucial role in sensory transduction. Sensory receptors are often specialized cells that have ion channels embedded in their membranes. When a sensory stimulus is detected, it triggers changes in the permeability of these ion channels, allowing specific ions (such as sodium, potassium, or calcium) to enter or exit the cell. This movement of ions alters the membrane potential, creating an electrical signal or action potential that can be transmitted to the brain via neurons.

3. The brain interprets action potentials from different stimuli into meaningful integration through a process called sensory integration. Sensory integration occurs in various regions of the brain, where incoming sensory signals are processed and combined to form a coherent perception of the external world.

To distinguish between different touch signals, the brain relies on several mechanisms. One mechanism is the recruitment of different types of sensory receptors that are sensitive to specific touch stimuli, such as receptors for light touch or receptors for deep pressure. Additionally, the brain can interpret the intensity and duration of action potentials generated by the receptors to differentiate between gentle and greater pressure.

4. Although all stimuli reach the brain as action potentials, we can distinguish one stimulus from another through a process called labeled lines. Labeled lines refer to the specific pathways in the nervous system that transmit sensory information from different modalities (such as sight, sound, and smell) to distinct regions of the brain. Each sensory modality has dedicated pathways that carry information related to that specific modality. Therefore, the brain can distinguish between different stimuli based on the specific labeled lines activated by each modality.

5. Transduction can be modified through two main mechanisms: sensory adaptation and sensitization. Sensory adaptation refers to a decrease in the responsiveness of sensory receptors to a constant or repetitive stimulus over time. For example, when we first enter a room with a strong odor, we may initially perceive it strongly, but over time, our olfactory receptors adapt, and the perception of the odor diminishes.

On the other hand, sensitization refers to an increase in the responsiveness of sensory receptors to a stimulus. This can occur in response to certain conditions or prior stimulation. An example of sensitization is when our skin becomes more sensitive to touch after an injury or inflammation, leading to heightened perception of touch stimuli.

6. Action potentials initiated by mechanoreceptors occur when these specialized sensory receptors are physically deformed or stimulated. For example, when pressure is applied to the skin, mechanoreceptors called Pacinian corpuscles in the skin are mechanically deformed, which triggers the opening of ion channels and the generation of action potentials.

Action potentials initiated by chemoreceptors occur when these receptors detect specific chemical molecules or substances. For instance, olfactory chemoreceptors in the nose can detect different odor molecules present in the air. When these molecules bind to specific receptors on the chemoreceptor cells, it triggers a cascade of events that leads to the generation of action potentials, which are then transmitted to the brain for odor perception.

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Question 5 1 pts What is the effect of tryptophan and allolactose binding on the function of the trpR protein and the lacl protein respectively? The trpR protein binds the DNA when it is bound to tryptophan, but the lack protein binds the DNA when it is NOT bound to allolactose. The trpR protein binds the DNA when it is NOT bound to tryptophan, and the lacl protein binds the DNA when it is NOT bound to allolactose. The trpR protein does NOT bind the DNA when it is bound to tryptophan, but the lacl protein binds the DNA when it is bound to allolactose. The trpR protein binds the DNA when it is bound to tryptophan, and the lacl protein binds the DNA when it is bound to allolactose.

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The effects of tryptophan and allolactose binding on the function of the trpR protein and the lacI protein are that they both undergo structural changes that enable them to carry out their regulatory functions.

Tryptophan and allolactose are effector molecules that bind to the regulatory proteins trpR and lacI, respectively. These effector molecules cause conformational changes in their regulatory proteins which allow them to bind to DNA. The trpR protein undergoes an allosteric change when it binds to tryptophan, allowing it to bind to the operator site on the trp operon and thereby repressing transcription.

This process is called repression. The lacI protein undergoes an allosteric change when it binds to allolactose, which prevents it from binding to the operator site on the lac operon. As a result, the transcription of genes that are involved in lactose metabolism is induced. This process is called induction.

Therefore, the correct option is "The trpR protein binds the DNA when it is bound to tryptophan, and the lacl protein binds the DNA when it is bound to allolactose."

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Which organisms would be the most closely related? OTwo that share the same Family Two that share the same Class Two that share the same Kingdom OTwo that share the same genus

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The organisms that would be the most closely related are two that share the same genus. Genus is the second last level of classification. This is why it is more specific than the previous classifications which are Kingdom, Phylum, Class, and Order.

These levels group organisms based on their similarities in the general sense, and the categories get more and more specific as the classifications continue. Each genus consists of a group of species that are closely related and share a common ancestor. The organisms that share the same genus have the same fundamental characteristics such as morphology and genetics. For instance, lions and tigers belong to the same genus which is Panthera.

The organisms that share the same family, class, and kingdom, but not the same genus, will still share common features and traits, but their differences will be more pronounced compared to those organisms that share the same genus. For instance, humans and apes belong to the same family (Hominidae), class (Mammalia), and kingdom (Animalia), but they are in different genera, and therefore are different species.

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The official sequencing of the human genome began in 1990 and took 13 years to finish. The composition of the genome was a big surprise regarding the percentage of the human genome containing coding genes. What was the surprise and provide three different types of non-coding DNA that were found in the human genome?

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The surprise was that coding genes constitute only a small fraction of the human genome. It was found that only around 2% of the human genome encodes proteins.

The rest of the genome is composed of non-coding DNA. Some examples of non-coding DNA found in the human genome are as follows:1. Introns: These are the segments of DNA that lie between coding regions in a gene and are transcribed into RNA but are ultimately spliced out during RNA processing.2. Regulatory DNA: These sequences control when and how genes are expressed.

They include promoter regions, enhancers, and silencers.3. Transposable Elements: These are DNA sequences that can move around the genome.

They were once thought to be "junk DNA" but are now known to have important functions in gene regulation and evolution.

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Which is FALSE about the structure of DNA? DNA is a double helix structure. A and U pair together, C and G pair together. DNA consists of a sugar backbone and nucleotide bases. Strands run in an anti-parallel direction.

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The statement which is FALSE about the structure of DNA is: A and U pair together. DNA is composed of two strands that intertwine to form a double helix structure.

It consists of nucleotides which are made up of a sugar molecule (deoxyribose), a phosphate group, and a nitrogenous base (adenine, guanine, cytosine, or thymine).The nitrogenous bases always pair together in a specific way, with adenine always bonding with thymine and guanine always bonding with cytosine. This is known as complementary base pairing and is responsible for maintaining the stability and accuracy of DNA replication.In RNA, the nitrogenous base uracil replaces thymine and binds with adenine instead. Therefore, the statement "A and U pair together" is false about the structure of DNA. A and U pair together only in RNA instead of DNA. Hence, this is the false statement regarding the structure of DNA.

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Saved Modern, aquatic, toothed whales evolved from a terrestrial ancestor, Pakicetus attocki. Present day whales are linked to their terrestrial ancestors by embryological evidence biogeography anatomical evidence the fossil record

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You are designing a hydraulic power takeoff for a garden tractor. The hydraulic pump will be directly connected to the motor and supply hydraulic fluid at 250 p... The modern aquatic and toothed whales evolved from a terrestrial ancestor . The connection between the terrestrial and aquatic whales is shown through the fossil record of more than 100 million years ago.

Embryological evidence refers to the study of the development of an organism from the fertilization of an egg to its birth. Biogeography is the study of the geographical distribution of organisms. Anatomical evidence refers to the similarities and differences in the physical structures of organisms.

The fossil record is a historical document that reveals the origins and development of life on earth, which makes it an excellent piece of evidence in understanding how the whales evolved. The fossils record of more than 100 million years ago connects modern-day whales to their terrestrial ancestors. Therefore, the answer is the fossil record.

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For each embryonic tissue type, write one organ or differentiated cell type that is derived from that tissue. (8)
Neural Ectoderm ________________________
Epidermis ________________________
Neural Crest ________________________
Somite _____ ___________________

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producir elmelanina, que determina el color de la piel y protege contra los rayos UV. En resumen, la epidermis del ectodermo protege el cuerpo y el sistema nervioso central procesa y transmite información en el cuerpo.

Neural Ectoderm: El cerebro y la columna vertebral son las estructuras del sistema nervioso central (CNS) responsables de procesar y transmitir información en el cuerpo. Los neuronas, que son los componentes esenciales del sistema nervioso, y las células gliales, que brindan apoyo e insulación a los neuronas, son algunos de los diversos tipos de células especializadas que componen estos órganos.La capa exterior de la piel es la epidermis, que proviene del ectodermo. It functions as a barrier that protects against external factors like pathogens, UV radiation, and dehydration. El dermis está formado por varios tipos de células, incluidos los keratinocitos que producen el keratino proteico, que da a la piel su fuerza y propiedades impermeables. Los melanócitos son otras células presentes en la epidermis y son responsables de

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The neural ectoderm gives rise to the central and peripheral nervous system, the epidermis gives rise to the skin and associated structures, the neural crest gives rise to several cell types, and the somite gives rise to muscle and bone.

For each embryonic tissue type, write one organ or differentiated cell type that is derived from that tissue. (8)The eight embryonic tissues and the organs or differentiated cell types derived from them are as follows:1. Neural Ectoderm: The neural ectoderm is a group of cells that differentiate into the central and peripheral nervous systems.2. Epidermis: The epidermis is the outermost layer of skin that protects the body from the environment and helps regulate body temperature.3. Neural Crest: The neural crest gives rise to several cell types including sensory and autonomic ganglia, Schwann cells, and adrenal medulla cells.4. Somite: The somite is a group of cells that differentiate into muscle and bone.

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