Answer:
Formula of kinetic energy:
[tex]k.e = \frac{1}{2} m {v}^{2} [/tex]
Explanation:
k.e: kinetic energy (J)
m: mass (kg)
v: velocity (m/s)
kinetic energy equals one half of the multiplication between mass and velocity
A beam of light, incident on a flat water surface, reflects from the mirror-like surface so that the angle of incidence equals the angle of reflection. The water has waves. Would individual light beams obey the law of reflection in this case?
Answer:
a protractor
Explanation:
because protractors measure angles
reason why the center of gravity must not be at 50cm
Answer:
hope this helps
hope this is what u want
Clouds
Clouds have a big influence on weather. They are a necessary precursor of precipitation, although not all of them
produce precipitation. Clouds also prevent some solar radiation from reaching the ground and absorb some of the
heat that is re-radiated from the surface. As a result, cloudy days are likely to be cooler and cloudy nights warmer
than clear days and nights.
Water vapor condenses out of the air when the temperature reaches the dew point. Air may reach its dew point
when humidity increases or air temperature decreases. The latter commonly happens when warm, moist air rises.
For clouds to form, water vapor must condense around tiny particles called nuclei (singular, nucleus). A nucleus
might be a speck of dust or smoke, or it might be a salt crystal. The condensation of many water molecules around
a nucleus forms a tiny droplet of liquid water. If billions of these water droplets come together, they make a cloud.
Clouds are classified in several ways. The most common classification used today divides clouds into groups based on altitude
• Middle clouds form at middle altitudes and consist of ice crystals, water droplets, or both. Examples of middle
clouds include altocumulus and altostratus clouds.
• Low clouds form at low altitudes and consist entirely or mainly of water droplets. Examples of low clouds
include stratus, stratocumulus, and nimbostratus clouds.
• Vertical clouds grow upward and have their bases at low altitude and their tops at middle or high altitude.
They form when strong air currents carry warm air upward. Examples of vertical clouds include cumulus and
nimbocumulus clouds.
Questions
1. How do clouds influence weather?
2. Explain how clouds form.
3. Outline how clouds are classified by altitude
Answer:
clouds from when moist, warm rising air cools and expands in the atmosphere. The water vapor in the air condenses to form tiny water droplets which are the basis of clouds.
Explanation:
on both sides.
F
10cm
2cm
(2 marks)
(a)
a
State the type of the lens in the box and explain your answer.
Answer:
please put pic of the questions
What is the density of a 36 g object with a volume of 15 cm3? (Density: D = )
0.42 g/cm3
0.54 g/cm3
2.4 g/cm3
5.4 g/cm3
Answer:
density = mass/volume
so . . .
density = (36 g)/(15 cm³) = 2.4 g/cm³
Explanation:
Use the worked example above to help you solve this problem. The amount of charge that passes through a filament of a certain lightbulb in 2.09 s is 1.56 C. (a) Find the current in the bulb. A (b) Find the number of electrons that pass through the filament in 5.24 s. electrons (c) If the current is supplied by a 12.0-V battery, what total energy is delivered to the lightbulb filament
Answer:
a) i = 0.746 A, b) # _electron = 2.44 10¹⁹ electrons, c) E = 1.87 10⁴ J
Explanation:
a) The definition of current is the charge per unit of time
i = Q / t
i = 1.56 / 2.09
i = 0.746 A
b) Let's look for the cargo in passing at this time
i = Q / t
Q = i t
Q = 0.746 5.24
Q = 3.904 C
an electron has a charge e = -1.6 10⁻¹⁹ C, let's use a direct proportions rule
# _electron = 3.904 C (1 electron / 1.6 10⁻¹⁹)
# _electron = 2.44 10¹⁹ electrons
the number of electrons has to be an integer
c) In this part you are asked to calculate the power
P = V i
P = 12 0.746
P = 8.952 W
P = E/t
E = P t
E = 8.952 2.09
E = 1.87 10⁴ J
A student carries a backpack for one mile. Another student carries the same backpack for two miles
Compared to the first student, how much work did the second student do?
Answer:
Compared to the first student, the second student did twice as much work as the first student.
Explanation:
The work done by the first student will be equal to the Force exerted by the backpack on the student carrying it multiplied by one mile (Distance). The work done by the second student will be equal to the Force exerted by the backpack on the student carrying it multiplied by two miles (Distance).
How much force will a 5 kg rock hit the Earth with if it falls
for 1 second?
Answer:
f
Explanation:
f
If electrical current is moving through a horizontal wire toward your face, what direction is the induced magnetic field?
a. clockwise
b. straight left
c. straight right
d. counter clockwise
Answer:(b)
Explanation:
Given
Electric current flowing through the horizontal wire towards the observer's face.
The direction of the magnetic field is given by the right-hand thumb rule, i.e. place the thumb in the direction of current and the wrapping of fingers will give the direction of the magnetic field
the direction of the magnetic field will be counterclockwise as observed by an observer.
Two loudspeakers, A and B are driven by the same amplifier and emit sinusoidal waves in phase. Speaker B is 2.00 m to the right of speaker A. The frequency of the sound waves produced by the loudspeakers is 206 Hz. Consider a point P between the speakers and along the line connecting them, a distance x to the right of A. Both speakers emit sound waves that travel directly from the speaker to point P. For what values of x will:
a. destructive interference occur at P
b. constructive interference occur at P
Answer:
a) 0, ±1.65 b) ± 0.825m
Explanation:
This is a sound interference exercise, it can be described by the path difference between the two waves
for the case of constructive interference
Δr = 2n λ/ 2 n = 0, 1, 2 ...
for the case of destructive interference
Δr = (2n + 1) λ/ 2
the speed of sound is related to the wavelength
v = λ f
λ = v / f
λ= 340/206
λ = 1.65 m
let's set a reference system in the center between the two speakers
a) let's find the distances for constructive interference
Δr = 2n 1.65 / 2
Δr = 1.65 n
* the first interference occurs at n = 0
Δr = 0
therefore the interference in the center is maximum
* n = 1
Dr = 1.65 m
the second inference occurs at 1.65 m from the center, therefore there is a right wing and a left wing,
We do not have any more interference between the speakers because
n = 2 Δr = 3.3m this distance can be from the speaker
b) let's look for the destructive interference points
Δr = (2n + 1) 1.65 / 2
Δr = (2n + 1) 0.825
m = 0 Δr = 0.825m
m = 1 Δr = 2,475m
We can see that we only have the first destructive interference, one on each side.
Pls help me I’m failing
Answer:
A is the answer okkkkkkkkkkkkkkkk
Assuming the speed of sound is 340 m/s, what is the most likely speed of the jet shown below?
Well we know it has to be greater than 300,000 km/s since we can't see it.
We can't calculate it any closer than that using the given information.
How much work must be done to raise a 1100kg car 2m above the ground?
Answer:
21560 J
Explanation:
Work = mg*h = 1100*9.8*2 = 21560 J
21560 J work must be done to raise an 1100 kg car 2m above the ground.
Work = mass * gravity * height
= 1100 * 9.8 * 2
= 21560 J
What is work done?In precis, work is carried out whilst pressure acts upon an item to purpose a displacement. 3 portions must be regarded in the way to calculate the quantity of work. The ones 3 portions are force, displacement, and the perspective between the pressure and the displacement.
Paints carried out are elaborated in this type of manner that includes both forces exerted on the body and the whole displacement of the body. This block is preceded by a steady force F. The purpose of this pressure is to move the body a certain distance d in an immediate route in the route of the pressure.
Learn more about work here: https://brainly.com/question/1382377
#SPJ2
Assume all of the resistors in the following circuits have a value of 5 ohms. Which ammeter will have the highest
reading?
Answer:
Circuit B
Explanation:
To know the correct answer to the question, we shall determine the reading of the ammeter i.e the current in each circuit. This can be obtained as follow:
For circuit A:
Resistance (R) = 5 ohms
Voltage (V) = 1.5 V
Current (I) =?
V = IR
1.5 = I × 5
Divide both side by 5
I = 1.5 / 5
I = 0.3 A
For circuit B:
We'll begin by calculating the total resistance in the circuit. This can be obtained as follow:
Resistance 1 (R₁) = 5 ohms
Resistance 2 (R₂) = 5 ohms
Total resistance (Rₜ) =?
Since they are in parallel connections, the total resistance can be obtained as illustrated below:
Rₜ = R₁ × R₂ / R₁ + R₂
Rₜ = 5 × 5 / 5 + 5
Rₜ = 25 / 10
Rₜ = 2.5 ohms
Finally, we shall determine the current in the circuit.
Resistance (R) = 2.5 ohms
Voltage (V) = 1.5 V
Current =?
V = IR
1.5 = I × 2.5
Divide both side by 2.5
I = 1.5 / 2.5
I = 0.6 A
For circuit C:
We'll begin by calculating the total resistance in the circuit. This can be obtained as follow:
Resistance 1 (R₁) = 5 ohms
Resistance 2 (R₂) = 5 ohms
Total resistance (Rₜ) =?
Since they are in series connections, the total resistance can be obtained as illustrated below:
Rₜ = R₁ + R₂
Rₜ = 5 + 5
Rₜ = 10 ohms
Finally, we shall determine the current in the circuit.
Resistance (R) = 10 ohms
Voltage (V) = 1.5 V
Current =?
V = IR
1.5 = I × 10
Divide both side by 10
I = 1.5 / 10
I = 0.15 A
SUMMARY:
Circuit >>>>>>> Current
A >>>>>>>>>>>> 0.3 A
B >>>>>>>>>>>> 0.6 A
C >>>>>>>>>>>> 0.15 A
from the above calculations, circuit B has the highest ammeter reading.
The Willis Tower in Chicago has an observation deck 412 m above ground.
How far can you see out over Lake Michigan from the observation deck?
Answer:
Check Newton's Rings:
d = height of air film
s = distance from center to ring being considered
R = radius of circle considered
The approximate formula is:
d = s^2 / (2 R) or s = (2 R d)^1/2
If we just use 4000 mi for R and 1/4 mi for d the height
we get s = (2 * 4000 * 1/4)^1/2 = 2000^1/2 mi = 45 mi
An object is dropped from a bridge. A second object is thrown downwards 1.0 s later. They both reach the water 20 m below at the same instant. What was the initial speed of the second object? Neglect air resistance.
Answer:
15m/s
Explanation:
[tex]20m = \frac{1}{2} g {t}^{2} \\ t = 2s \\ t0 = 2s - 1s = 1s \\ vt + \frac{1}{2} g {t}^{2} = 20m \\ v \times 1s + \frac{1}{2} \times 10 \times 1 = 20 \\ v = 15[/tex]
What two air masses creates hurricanes?
Answer:
The warm seas create a large humid air mass. The warm air rises and forms a low pressure cell, known as a tropical depression.
Explanation:
Hurricanes arise in the tropical latitudes (between 10 degrees and 25 degrees N) in summer and autumn when sea surface temperature are 28 degrees C (82 degrees F) or higher.
Answer:
air
Explanation:
A 40.0-kg packing case is initially at rest on the floor of a 1500-kg pickup truck. The coefficient of static friction between the case and the truck floor is 0.30, and the coefficient of kinetic friction is 0.20. Before each acceleration given below, the truck is traveling due north at constant speed. Find the magnitude and direction of the friction force acting on the case
(a) when the truck accelerates at 2.20m/s22.20m/s 2 northward and
(b) when it accelerates at 3.40m/s23.40m/s 2 southward.
Answer:
Before providing an answer to the question, the values for acceleration given in questions A and B were written twice. So correction would go like this: For (a) when the truck accelerates at 2.20m/s2 northward, and for (b) when it accelerates at 3.40m/s2 southward.
The answer:
(a) 88N, northward.
(b) 78.4, southward.
Explanation:
(a) Maximum frictional force acting on the packing case= (coefficient of static friction) X (Normal force)
Normal force = mass X acceleration due to gravity
Maximum static frictional force acting on the packing case = (coefficient of static friction) X (mass of packing case X acceleration due to gravity)
Maximum static frictional force = (0.30) X (40.0-kg) X (9.8m/s 2) = 117.6N
While Reaction force acting on the packing case = (mass of packing case) x (acceleration generated by the pickup truck)
Reaction force acting on the case = (40.0-kg) X (2.20m/s2) = 88N
With these values, one can conclude that the packing case is at rest since the reaction force of the case acting in the opposite direction is lesser than the frictional force. Making the magnitude and direction of the friction force acting on the case still move northward, and the static frictional force acting on equals the reaction force.
The answer is 88N, northward.
(b) Here too, we need to still compare the reaction force with the value of the already determined Maximum static frictional force (117.6N) above. This is necessary to know the frictional force between the pickup truck"s floor and the packing case.
Reaction force acting on the case when acceleration is 3.40m/s2 = (40.0-kg) X (3.40m/s2) = 136 N
We can conclude that the reaction force (136 N) is greater than the maximum static frictional force (117.6N), suggesting that the packing case is in motion and the frictional force is no longer static.
This means a kinetic force is now acting on the pickup truck"s floor causing the packing case to also move. This kinetic force can be calculated as:
kinetic force = (coefficient of kinetic friction) X (mass of packing case X acceleration due to gravity)
= (0,20) X (40.0-kg) X (9.8m/s 2) = 78.4N
Two bodies, A and B, have equal kinetic energies. The mass of A is nine times that of B. The ratio of the momentum of A to that of B is:_______.A. 1:9B. 1:3C. 1:1D.3:1E. 9:1
Answer:
D. 3 : 1
Explanation:
Let suppose that A and B are particles. From statement we know that [tex]K_{A} = K_{B }[/tex] (same kinetic energy) and [tex]m_{A} = 9\cdot m_{B}[/tex]. Then,
[tex]K_{A} = K_{B}[/tex]
[tex]\frac{1}{2}\cdot m_{A}\cdot v_{A}^{2} = \frac{1}{2}\cdot m_{B}\cdot v_{B}^{2}[/tex]
[tex]m_{A} \cdot v_{A}^{2} = m_{B}\cdot v_{B}^{2}[/tex]
[tex]\frac{v_{B}}{v_{A}} = \sqrt{\frac{m_{A}}{m_{B}} }[/tex]
[tex]\frac{v_{B}}{v_{A}} = 3[/tex]
And the ratio of the momentum of A to the momentum of B is:
[tex]r = \frac{m_{A}\cdot v_{A}}{m_{B}\cdot v_{B}}[/tex]
[tex]r = 9\times \frac{1}{3}[/tex]
[tex]r = 3[/tex]
Hence, the correct answer is D.
what is a resultant vector
Answer:
A resultant vector is a combination or, in simpler words, can be defined as the sum of two or more vectors which has its own magnitude and direction.
How could being mindful in conversation be helpful?
You can see if the person your talking to and being mindfull they will see respect towards you or they see you as a mindful person.It shows a person that you care.
Explanation:
Can any wan help pls
Answer:
b
Explanation:
because of bonds and the bowl is used for heating purpose
Answer:
I think b not sure but I hope its right and is that the nwea test??
The mass of a ship before launch is 55,000 metric tons. The ship is launched down a ramp and drops a total of 10 vertical meters before coming to rest in a lock containing 75,000 cubic meters of fresh water. The specific heat of water is 4200 joules per kilogram degree Celsius. Assume all energy is transferred from the ship to the water. Determine the change in temperature of the water in degrees Celsius .
Answer:
ΔT = 17.11 °C
Explanation:
In this case, we have a ship standing on a place with a given mass and it's about to be launched to a lock containing water.
At first, before launch, the ship has a potential energy, and when the ship hits the water after being launched, this potential energy is transformed into kinetic energy.
So, let's calculate first the potential energy of the ship:
E = mgh (1)
We have the mass, gravity and height, so we need to replace the given data here. Before we do that, let's remember to use the correct units. A ton is 1000 kg, so replacing and converting we have:
E = (55000 ton * 1000 kg/ton) * (9.8 m/s²) * 10 m
E = 5.39x10⁹ J
Now this energy will be the same when the ship hits the water, only that is kinetic energy that will result in the rise of temperature. To get this rise we use the following expression:
E = m * C * ΔT (2)
We have the energy, the mass of water (assuming density of water as 1 kg/m³) and the specific heat, so, replacing in (2) and solving for ΔT we have:
ΔT = E / m * C (3)
ΔT = 5.39x10⁹ / 4200 * 75000
ΔT = 17.11 °CHope this helps
Please help! THIS IS A EASY ONE, HOPEFULLY.
Answer:
megaliter > kiloliter > liter >centiliter >mililiter > deciliter > nanoliter
Explanation:
plz mark brainlest
A substance of mass 200g measures 50cm*4cm*8cm. Calculate it density giving your answer in SI unit
Answer:
0.2kg/0.0016m^3
Explanation:
200g is 0.2 kg
50*4*8 is equivalent to 1600 cubic centimeters which is also equivalent to 0.0016 cubic meters.
The SI unit for density is kg per cubic meter
So now we have 0.2kg/0.0016m^3
I hoped this helped, and if it did please give me brainliest
is it possible for an atom to lose a proton and have a negative charge?
explain
Answer:
Sometimes atoms gain or lose electrons. The atom then loses or gains a "negative" charge. These atoms are then called ions. Positive Ion - Occurs when an atom loses an electron negative charge it has more protons than electrons.
Explanation:
:)
what is diffrence between damping and undamping?
Answer:
Oscillation whose amplitude reduce with time are called damped oscillation. This happen because of the friction. In oscillation if its amplitude doesn't change with time then they are called Undamped oscillation
Damped and undamped vibration refer to two different types of vibrations. The main difference between damped and undamped vibration is that undamped vibration refer to vibrations where energy of the vibrating object does not get dissipated to surroundings over time, whereas damped vibration refers to vibrations where the vibrating object loses its energy to the surroundings.
A garbage truck and a minivan are moving at the same velocity.
Which automobile will have greater momentum and why? Explain your response using Newton’s second law of motion specifically.
If the garbage truck and minivan in Part A get into an accident with each other, how can safety restraints in a car can save a life? Explain your response using one of Newton’s laws.
Which of Newton’s laws of motion act upon the vehicles at the point of impact? Explain your answer.
Answer:
Part A
Newton's second law of motion states that the force applied to an object is directly proportional to the rate of change of momentum that is produced
Mathematically, we have;
F = m·v - m·u/Δt
Where;
m = The mass of the object
v = The final velocity of the object
u = The initial velocity of the object
Δt = The duration of motion of the object during change in velocity
Therefore, given that the mass, 'M', of the truck is larger than the mass, 'm', of the minivan, where the time of change in velocity Δt, and the initial and final velocities of both automobiles are the same such as in a sudden stop, the garbage ruck will exert more force than the minivan, and therefore, the garbage truck has a greater initial momentum before the automobiles are brought to a stop
Part B;
According to Newton's first law of motion, we have;
The use of a seat belt (and airbag for front seated passengers) will prevent dashboard or windscreen for the front passengers or the front seat for the passengers in the back, from being the item that stops the continued forward motion of the passengers in the car, which can lead to injury
Part C; The Newton's law of motion that act on a body at the point of impact is Newton's third law of motion, which states that the action and reaction are equal and opposite
Therefore, the action of the garbage truck on the minivan upon impact is equal to the reaction of the minivan to the force the garbage truck exerts on the minivan
Explanation:
Describe effective communication strategies for gathering information, educating patients
Explanation:
Effective communication with patients will enable one to know the needs of the patient better as well as reducing the barriers to understanding each other for both parties.
To be an effective communicator while educating patients, the person must:
It is important to establish good rapport with the patient. By so doing they can trust you and let you in. Show empathy. Do not make them feel like you are judging themUse proper body language. Make eye contacts and try to be on the same level as the patient so you can be face to face with them.make the interaction easier for them. You have to keep questions as well as your sentences short and moderate. Stay on topic and always make sure that concepts are clear to them.show respect. try not to speak with commands. Give the patient opportunity to make choices.be patient with them. Due to age or the nature of their illnesses, the patient may be slow in speech or movement. help them to move at their own pace by not rushing them.give them time to respond and ask questions. this will make communication more effective.you cause graphics where necessary or written instructions for the patient.Show two data points from your simulation that demonstrate this behavior.
I1 V1 I2= 2I1 V2=2V1 V1/ I1 =V2/I2
For the light bulb, why is it better to take more measurements in the range 20mA < I < 40mA, instead of just taking equally spaced measurements in the entire range of 0 mA < I< 55mA
Answer:
hello your question is incomplete attached below is the complete and the required circuit diagrams
answer :
Ai) This proves that when the current across the resistor is doubled the value of the voltage across the resistor doubles as well
B) It is better to take more measurements in the range 20mA < I < 40mA because of the amount of temperature reached by the bulb and the change in resistance is affected by the temperature
hence At 0 mA current, there won't be any noticeable change
Explanation:
Ai) The voltage across the resistor will double when you double the current through the resistor
Given that : V = I*R.
lets assume : I = 2 amperes , R = 3 ohms
V = 2*3 = 6 v
secondly lets assume double the value of (I) i.e. I = 4 amperes
hence : V = 4*3 = 12 volts
This proves that when the current across the resistor is doubled the value of the voltage across the resistor doubles as well
Aii) Showing the two data points from simulation
I1 V1 I2= 2I1 V2=2V1 V1/ I1 =V2/I2
0.9*10^3 9 * 10^3 1.8*10^3 18*10^3 10 ohms
1.6 * 10^3 16 * 10^3 3.2*10^3 32*10^3 10 ohms
B) It is better to take more measurements in the range 20mA < I < 40mA because of the amount of temperature reached by the bulb and the change in resistance is affected by the temperature
hence At 0 mA current, there won't be any noticeable change