write the equation of a circle with the center (6,4) that passes through the coordinate (2,1) in your final answer include all of your calculations
Answers
Step-by-step explanation:
define define equation we need the value of the radius and
Related Questions
Yvette exercises 14 days out of 30 in one month. What is the ratio of the number of days she exercises to the number of days in the month? Simplify the ratio.
Answers
Answer:
7 to 15, 7:15, 7/15
Step-by-step explanation:
Ratios can be written as:
a to b
a:b
a/b
We want to find the ratio of exercise days to days in the month. She exercises 14 days out of 30 days in the month. Therefore,
a= 14
b= 30
14 to 30
14:30
14/30
The ratios can be simplified. Both numbers can be evenly divided by 2.
(14/2) to (30/2)
7 to 15
(14/2) : (30/2)
7:15
(14/2) / (30/2)
7/15
Answer:
divide both numbers by 14.. the ans is 1: 2
According to the Vivino website, suppose the mean price for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is $32.48. A New England-based lifestyle magazine wants to determine if red wines of the same quality are less expensive in Providence, and it has collected prices for 65 randomly selected red wines of similar quality from wine stores throughout Providence. The mean and standard deviation for this sample are $30.15 and $12, respectively.
(a) Develop appropriate hypotheses for a test to determine whether the sample data support the conclusion that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48. (Enter != for ≠ as needed.)
H0:
Ha:
(b) Using the sample from the 60 bottles, what is the test statistic? (Round your answer to three decimal places.)
Using the sample from the 60 bottles, what is the p-value? (Round your answer to four decimal places.)
p-value =
(c) At α = 0.05, what is your conclusion?
Do not reject H0. We can conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.
Reject H0. We can conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.
Do not reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.
Reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.
(d) Repeat the preceding hypothesis test using the critical value approach.
State the null and alternative hypotheses. (Enter != for ≠ as needed.)
H0:
Ha:
Find the value of the test statistic. (Round your answer to three decimal places.)
State the critical values for the rejection rule. Use
α = 0.05.
(Round your answers to three decimal places. If the test is one-tailed, enter NONE for the unused tail.)
test statistic ≤
test statistic ≥
State your conclusion.
Do not reject H0. We can conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.
Reject H0. We can conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.
Do not reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.
Reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.
Answers
Answer:
a) Null and alternative hypothesis
[tex]H_0: \mu=32.48\\\\H_a:\mu< 32.48[/tex]
b) Test statistic t=-1.565
P-value = 0.0612
NOTE: the sample size is n=65.
c) Do not reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.
d) Null and alternative hypothesis
[tex]H_0: \mu=32.48\\\\H_a:\mu< 32.48[/tex]
Test statistic t=-1.565
Critical value tc=-1.669
t>tc --> Do not reject H0
Do not reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.
Step-by-step explanation:
This is a hypothesis test for the population mean.
The claim is that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.
Then, the null and alternative hypothesis are:
[tex]H_0: \mu=32.48\\\\H_a:\mu< 32.48[/tex]
The significance level is 0.05.
The sample has a size n=65.
The sample mean is M=30.15.
As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=12.
The estimated standard error of the mean is computed using the formula:
[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{12}{\sqrt{65}}=1.4884[/tex]
Then, we can calculate the t-statistic as:
[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{30.15-32.48}{1.4884}=\dfrac{-2.33}{1.4884}=-1.565[/tex]
The degrees of freedom for this sample size are:
[tex]df=n-1=65-1=64[/tex]
This test is a left-tailed test, with 64 degrees of freedom and t=-1.565, so the P-value for this test is calculated as (using a t-table):
[tex]\text{P-value}=P(t<-1.565)=0.0612[/tex]
As the P-value (0.0612) is bigger than the significance level (0.05), the effect is not significant.
The null hypothesis failed to be rejected.
At a significance level of 0.05, there is not enough evidence to support the claim that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.
Critical value approach
At a significance level of 0.05, for a left-tailed test, with 64 degrees of freedom, the critical value is t=-1.669.
As the test statistic is greater than the critical value, it falls in the acceptance region.
The null hypothesis failed to be rejected.
Sameer chose 12 different toppings for his frozen yogurt sundae, which was Three-fourths of the total number of different toppings available at the make-your-own sundae shop. To determine the number of different toppings available at the shop, Sameer set up and solved the equation as shown below.
Three-fourths = StartFraction x over 12 EndFraction. Three-fourths (12) = StartFraction x over 12 EndFraction (12). 9 = x.
Which best describes the error that Sameer made?
Sameer did not use the correct equation to model the given information.
Sameer should have multiplied both sides of the equation by Four-thirds instead of by 12.
The product of Three-fourths(12) is not equal to 9.
The product of Four-thirds and StartFraction 1 over 12 EndFraction should have been the value of x.
Answers
Answer: B. Sameer did not use the correct equation
Step-by-step explanation:
12 IS three-fourths OF x
IS: equals
OF: multiplication
[tex]12=\dfrac{3}{4}x[/tex]
48 = 3x
16 = x
Answer:
it's b in Edg
Step-by-step explanation:
Let x=−1−5i and y=5−i. Find x⋅y.
Answers
Answer:
-10 -24i
Step-by-step explanation:
Note : i=√-1 (imaginary number)
i² = -1
xy
= (−1−5i)(5−i)
= -5 +i -25i +5i²
=-5 +i -25i + 5(-1)
= -5 +i -25i -5
= -5 -5 +i -25i
= -10 -24i
A complex number is a number system that extends the real numbers with a particular element labelled "i" known as the imaginary unit. The value of x·y is (−10 −24i).
What is a complex number?A complex number is a number system that extends the real numbers with a particular element labelled "i" known as the imaginary unit, and satisfies the equation i² = -1; every complex number may be represented as a + bi, where a and b are real numbers.
Given that x=−1−5i and y=5−i. Therefore, the value of x·y is,
x·y = (−1 −5i)(5-i)
= −5 + i −25i +5i²
= −5 −24i − 5
= −10 −24i
Hence, the value of x·y is (−10 −24i).
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if jonny has 3 × 6 amounts of dish soap, how much dish soap does he have?!
a(I dont know)
b(18)
c(12)
d(6)
look up a skit called what's 6×3 before answering.
Answers
Answer: 18 (b)
Step-by-step explanation:
3x6=18
Answer:
18
Step-by-step explanation:
you can use a visual for a short answer or organize 3 dots in six groups, count in total
Which angles are pairs of alternate exterior angles
Answers
Answer:
when a straight line cuts two or more parallel lines then the angles forming on the side of transversal line exteriorly opposite to eachother is called exterior alternative angle.
for eg if AB //CD and EF is a transversal line meeting the parallel lines at G abd H then the exterior alternative angle are angle EGB = angle CHF and angle AGE=angle DHF are two pairs of exterior alternative angle .
hope its helpful to uh !!!!!!
The amount of pollutants that are found in waterways near large cities is normally distributed with mean 8.6 ppm and standard deviation 1.3 ppm. 38 randomly selected large cities are studied. Round all answers to 4 decimal places where possible
a. What is the distribution of X?
b. What is the distribution of a?
c. What is the probability that one randomly selected city's waterway will have more than 8.5 ppm pollutants?
d. For the 38 cities, find the probability that the average amount of pollutants is more than 8.5 ppm.
e. For part d), is the assumption that the distribution is normal necessary?
f. Find the IQR for the average of 38 cities.
Q1=__________ ppm
Q3 =_________ ppm
IQR=_________ ppm
Answers
We assume that question b is asking for the distribution of [tex] \\ \overline{x}[/tex], that is, the distribution for the average amount of pollutants.
Answer:
a. The distribution of X is a normal distribution [tex] \\ X \sim N(8.6, 1.3)[/tex].
b. The distribution for the average amount of pollutants is [tex] \\ \overline{X} \sim N(8.6, \frac{1.3}{\sqrt{38}})[/tex].
c. [tex] \\ P(z>-0.08) = 0.5319[/tex].
d. [tex] \\ P(z>-0.47) = 0.6808[/tex].
e. We do not need to assume that the distribution from we take the sample is normal. We already know that the distribution for X is normally distributed. Moreover, the distribution for [tex] \\ \overline{X}[/tex] is also normal because the sample was taken from a normal distribution.
f. [tex] \\ IQR = 0.2868[/tex] ppm. [tex] \\ Q1 = 8.4566[/tex] ppm and [tex] \\ Q3 = 8.7434[/tex] ppm.
Step-by-step explanation:
First, we have all this information from the question:
The random variable here, X, is the number of pollutants that are found in waterways near large cities.This variable is normally distributed, with parameters:[tex] \\ \mu = 8.6[/tex] ppm.[tex] \\ \sigma = 1.3[/tex] ppm.There is a sample of size, [tex] \\ n = 38[/tex] taken from this normal distribution.a. What is the distribution of X?
The distribution of X is the normal (or Gaussian) distribution. X (uppercase) is the random variable, and follows a normal distribution with [tex] \\ \mu = 8.6[/tex] ppm and [tex] \\ \sigma =1.3[/tex] ppm or [tex] \\ X \sim N(8.6, 1.3)[/tex].
b. What is the distribution of [tex] \\ \overline{x}[/tex]?
The distribution for [tex] \\ \overline{x}[/tex] is [tex] \\ N(\mu, \frac{\sigma}{\sqrt{n}})[/tex], i.e., the distribution for the sampling distribution of the means follows a normal distribution:
[tex] \\ \overline{X} \sim N(8.6, \frac{1.3}{\sqrt{38}})[/tex].
c. What is the probability that one randomly selected city's waterway will have more than 8.5 ppm pollutants?
Notice that the question is asking for the random variable X (and not [tex] \\ \overline{x}[/tex]). Then, we can use a standardized value or z-score so that we can consult the standard normal table.
[tex] \\ z = \frac{x - \mu}{\sigma}[/tex] [1]
x = 8.5 ppm and the question is about [tex] \\ P(x>8.5)[/tex]=?
Using [1]
[tex] \\ z = \frac{8.5 - 8.6}{1.3}[/tex]
[tex] \\ z = \frac{-0.1}{1.3}[/tex]
[tex] \\ z = -0.07692 \approx -0.08[/tex] (standard normal table has entries for two decimals places for z).
For [tex] \\ z = -0.08[/tex], is [tex] \\ P(z<-0.08) = 0.46812 \approx 0.4681[/tex].
But, we are asked for [tex] \\ P(z>-0.08) \approx P(x>8.5)[/tex].
[tex] \\ P(z<-0.08) + P(z>-0.08) = 1[/tex]
[tex] \\ P(z>-0.08) = 1 - P(z<-0.08)[/tex]
[tex] \\ P(z>-0.08) = 0.5319[/tex]
Thus, "the probability that one randomly selected city's waterway will have more than 8.5 ppm pollutants" is [tex] \\ P(z>-0.08) = 0.5319[/tex].
d. For the 38 cities, find the probability that the average amount of pollutants is more than 8.5 ppm.
Or [tex] \\ P(\overline{x} > 8.5)[/tex]ppm?
This random variable follows a standardized random variable normally distributed, i.e. [tex] \\ Z \sim N(0, 1)[/tex]:
[tex] \\ Z = \frac{\overline{X} - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex] [2]
[tex] \\ z = \frac{\overline{8.5} - 8.6}{\frac{1.3}{\sqrt{38}}}[/tex]
[tex] \\ z = \frac{-0.1}{0.21088}[/tex]
[tex] \\ z = \frac{-0.1}{0.21088} \approx -0.47420 \approx -0.47[/tex]
[tex] \\ P(z<-0.47) = 0.31918 \approx 0.3192[/tex]
Again, we are asked for [tex] \\ P(z>-0.47)[/tex], then
[tex] \\ P(z>-0.47) = 1 - P(z<-0.47)[/tex]
[tex] \\ P(z>-0.47) = 1 - 0.3192[/tex]
[tex] \\ P(z>-0.47) = 0.6808[/tex]
Then, the probability that the average amount of pollutants is more than 8.5 ppm for the 38 cities is [tex] \\ P(z>-0.47) = 0.6808[/tex].
e. For part d), is the assumption that the distribution is normal necessary?
For this question, we do not need to assume that the distribution from we take the sample is normal. We already know that the distribution for X is normally distributed. Moreover, the distribution for [tex] \\ \overline{X}[/tex] is also normal because the sample was taken from a normal distribution. Additionally, the sample size is large enough to show a bell-shaped distribution.
f. Find the IQR for the average of 38 cities.
We must find the first quartile (25th percentile), and the third quartile (75th percentile). For [tex]\\ P(z<0.25)[/tex], [tex] \\ z \approx -0.68[/tex], then, using [2]:
[tex] \\ -0.68 = \frac{\overline{X} - 8.6}{\frac{1.3}{\sqrt{38}}}[/tex]
[tex] \\ (-0.68 *0.21088) + 8.6 = \overline{X}[/tex]
[tex] \\ \overline{x} =8.4566[/tex]
[tex] \\ Q1 = 8.4566[/tex] ppm.
For Q3
[tex] \\ 0.68 = \frac{\overline{X} - 8.6}{\frac{1.3}{\sqrt{38}}}[/tex]
[tex] \\ (0.68 *0.21088) + 8.6 = \overline{X}[/tex]
[tex] \\ \overline{x} =8.7434[/tex]
[tex] \\ Q3 = 8.7434[/tex] ppm.
[tex] \\ IQR = Q3-Q1 = 8.7434 - 8.4566 = 0.2868[/tex] ppm
Therefore, the IQR for the average of 38 cities is [tex] \\ IQR = 0.2868[/tex] ppm. [tex] \\ Q1 = 8.4566[/tex] ppm and [tex] \\ Q3 = 8.7434[/tex] ppm.
which point is a solution to the inequality shown in the graph? (3,2) (-3,-6)
Answers
The point that is a solution to the inequality shown in the graph is:
A. (0,5).
Which points are solutions to the inequality?The points that are on the region shaded in blue are solutions to the inequality.
(3,2) and (-3,-6) are on the dashed line, hence they are not solutions. Point (5,0) is to the right of the line, hence it is not a solution, and point (0,5) is a solution, meaning that option A is correct.
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A superintendent of a school district conducted a survey to find out the level of job satisfaction among teachers. Out of 53 teachers who replied to the survey, 13 claim they are satisfied with their job.
z equals fraction numerator p with hat on top minus p over denominator square root of begin display style fraction numerator p q over denominator n end fraction end style end root end fraction
The superintendent wishes to construct a significance test for her data. She find that the proportion of satisfied teachers nationally is 18.4%.
What is the z-statistic for this data? Answer choices are rounded to the hundredths place.
a. 2.90
b. 1.15
c. 1.24
d. 0.61
Answers
Answer:
b. 1.15
Step-by-step explanation:
The z statistics is given by:
[tex]Z = \frac{X - p}{s}[/tex]
In which X is the found proportion, p is the expected proportion, and s, which is the standard error is [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
Out of 53 teachers who replied to the survey, 13 claim they are satisfied with their job.
This means that [tex]X = \frac{13}{53} = 0.2453[/tex]
She find that the proportion of satisfied teachers nationally is 18.4%.
This means that [tex]p = 0.184[/tex]
Standard error:
p = 0.184, n = 53.
So
[tex]s = \sqrt{\frac{0.184*0.816}{53}} = 0.0532[/tex]
Z-statistic:
[tex]Z = \frac{X - p}{s}[/tex]
[tex]Z = \frac{0.2453 - 0.184}{0.0532}[/tex]
[tex]Z = 1.15[/tex]
The correct answer is:
b. 1.15
Evaluate the expression.........
Answers
Answer:
9
Step-by-step explanation:
p^2 -4p +4
Let p = -1
(-1)^1 -4(-1) +4
1 +4+4
9
If a baseball player has a batting average of 0.375, what is the probability that the player will get the following number of hits in the next four times at bat?
A. Exactly 2 hits(Round to 3 decimal places as needed)
B. At least 2 hits (Round to 3 decimal places as needed)
Answers
Answer:
a) [tex]P(X=2)=(4C2)(0.375)^2 (1-0.375)^{4-2}=0.330[/tex]
b) [tex]P(X\geq 2)=1-P(X< 2)=1-[P(X=0)+P(X=1)][/tex]
[tex]P(X=0)=(4C0)(0.375)^0 (1-0.375)^{4-0}=0.153[/tex]
[tex]P(X=1)=(4C1)(0.375)^1 (1-0.375)^{4-1}=0.366[/tex]
And replacing we got:
[tex]P(X\geq 2)=1-P(X< 2)=1-[0.153+0.366]=0.481[/tex]
Step-by-step explanation:
Let X the random variable of interest, on this case we now that:
[tex]X \sim Binom(n=4, p=0.375)[/tex]
The probability mass function for the Binomial distribution is given as:
[tex]P(X)=(nCx)(p)^x (1-p)^{n-x}[/tex]
Where (nCx) means combinatory and it's given by this formula:
[tex]nCx=\frac{n!}{(n-x)! x!}[/tex]
Part a
[tex]P(X=2)=(4C2)(0.375)^2 (1-0.375)^{4-2}=0.330[/tex]
Part b
[tex]P(X\geq 2)=1-P(X< 2)=1-[P(X=0)+P(X=1)][/tex]
[tex]P(X=0)=(4C0)(0.375)^0 (1-0.375)^{4-0}=0.153[/tex]
[tex]P(X=1)=(4C1)(0.375)^1 (1-0.375)^{4-1}=0.366[/tex]
And replacing we got:
[tex]P(X\geq 2)=1-P(X< 2)=1-[0.153+0.366]=0.481[/tex]
What is the solution to the system of equations x+y=10 and x+2y=4 using the linear combination method?
Answers
Answer:
The solution:
X = 16 and Y = -6
Step-by-step explanation:
The equations to be solved are:
x+y = 10 ------- equation 1
x+2y = 4 ----------- equation 2
we can multiply equation 1 by -1 to make the value of x and y negative.
This will give us
-x- y = - 10 ------- equation 3
x+2y = 4 ----------- equation 2
We will now add equations 3 and 2 together so that x will cancel itself out.
this will give us
y = -10 +4 = -6
hence, we have the value of y as -6.
To get the value of x, we can put this value of y into any of the equations above. (I will use equation 1)
x - 6 = 10
from this, we have that x = 4
Therefore, we have our answer as
X = 16 and Y = -6
A small regional carrier accepted 19 reservations for a particular flight with 17 seats. 14 reservations went to regular customers who will arrive for the flight. Each of the remaining passengers will arrive for the flight with a 52% chance, independently of each other. (Report answers accurate to 4 decimal places.)
1. Find the probability that overbooking occurs.
2. Find the probability that the flight has empty seats.
Answers
Answer:
(a) The probability of overbooking is 0.2135.
(b) The probability that the flight has empty seats is 0.4625.
Step-by-step explanation:
Let the random variable X represent the number of passengers showing up for the flight.
It is provided that a small regional carrier accepted 19 reservations for a particular flight with 17 seats.
Of the 17 seats, 14 reservations went to regular customers who will arrive for the flight.
Number of reservations = 19
Regular customers = 14
Seats available = 17 - 14 = 3
Remaining reservations, n = 19 - 14 = 5
P (A remaining passenger will arrive), p = 0.52
The random variable X thus follows a Binomial distribution with parameters n = 5 and p = 0.52.
(1)
Compute the probability of overbooking as follows:
P (Overbooking occurs) = P(More than 3 shows up for the flight)
[tex]=P(X>3)\\\\={5\choose 4}(0.52)^{4}(1-0.52)^{5-4}+{5\choose 5}(0.52)^{5}(1-0.52)^{5-5}\\\\=0.175478784+0.0380204032\\\\=0.2134991872\\\\\approx 0.2135[/tex]
Thus, the probability of overbooking is 0.2135.
(2)
Compute the probability that the flight has empty seats as follows:
P (The flight has empty seats) = P (Less than 3 shows up for the flight)
[tex]=P(X<3)\\\\1-P(X\geq 3)\\\\=1-[{5\choose 3}(0.52)^{3}(1-0.52)^{5-3}+{5\choose 4}(0.52)^{4}(1-0.52)^{5-4}+{5\choose 5}(0.52)^{5}(1-0.52)^{5-5}]\\\\=1-[0.323960832+0.175478784+0.0380204032]\\\\=0.4625399808\\\\\approx 0.4625[/tex]
Thus, the probability that the flight has empty seats is 0.4625.
Which of the following represents a coefficient from the expression given?
9x – 20 + x2
Answers
Answer:
1 or 9.
Step-by-step explanation:
A coefficient is "a numerical or constant quantity placed before and multiplying the variable in an algebraic expression (e.g. 4 in 4xy)".
So, in this case, the coefficient of 9x would be 9.
The coefficient of x^2 would be 1.
Hope this helps!
In the given quadratic expression 9x - 20 + x, 1, 9, and -20 are the coefficients.
What are coefficients in a quadratic expression?In a quadratic expression of the standard form ax² + bx + c, x is the variable and a, b, and c are the numeric coefficients.
How to solve the given question?In the question, we are asked to identify the coefficients from the given quadratic expression 9x - 20 + x².
First, we try to express the given quadratic expression, 9x - 20 + x², in the standard form of a quadratic expression, ax² + bx + c.
Therefore, 9x - 20 + x² = x² + 9x - 20.
Comparing the expression x² + 9x - 20 with the standard form of a quadratic expression ax² + bx + c, we get a = 1, b = 9, c = -20.
We know that in a quadratic expression ax² + bx + c, x is the variable and a, b, and c are the numeric coefficients.
Thus, we can say that in the given quadratic expression 9x - 20 + x², 1, 9, and -20 are the coefficients.
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The two triangles are similar. What is the value of x? Enter your answer in the box. x =
Answers
Answer:
the value of x=12
Step-by-step explanation:
d) the answer is d on edg.
if p+4/p-4, what is the value of p
Answers
Answer:
p = 2
Step-by-step explanation:
p + 4/p - 4
multiplying through by p,
p×p + 4/p ×p - 4×p
p² + 4 - 4p = 0
p² - 4p + 4 = 0
factorizing,
p(p - 2) -2(p - 2) =0
(p -2)(p -2) =0
p-2 =0
p=2
HELP PLEASE!!What method can you use to find the area of the composite figure. Check ALL that apply.
Answers
Answer:
C
Step-by-step explanation:
The reason we can use this method is because we are given a composite figure with a house shape with one triangle on top. We can use the guidance of the dotted lines to make out that a rectangle can be used to find the figure. We can see that apart from the figure, there are two congruent triangles. To find the area we would do -
First find the missing height of the smaller triangles. We would use the pythagorean theorem to find that the missing height is√5
We could do 8(4) = 32 to find the area of the rectangle.
Then, we could do 2√5/2 to find one missing triangle. We could then add the triangles to find the measures of the combined triangles as 2√5. Then, we could do 32 - 2√5 to find the area as 27.5.
Hope this helps :)
Answer:
it is A,B,D
Step-by-step explanation:
i got it right on edge
F =9/5 C + 32 A) constants B) units C) variables D) numbers
Answers
Answer:
a) 32
b) none?
c) C & F
D) 9/5, 32?
Step-by-step explanation:
ANSWER ASAP! PLEASE HELP!
Answers
Find the domain of the graphed function.
10
-10
10
10
O A. -45x39
B. -43x8
C. X2-4
0
D. x is all real numbers.
Answers
Solve the inequality and enter your solution as an inequality in the box below,
using "<=" for sor">=" for 2 if necessary.
-2(5x + 1) > 48
Answer here
Answers
Answer:
x < -5
Step-by-step explanation:
-2(5x + 1) > 48
Divide by -2, remembering to flip the inequality
-2/ -2(5x + 1) < 48/-2
5x +1 < -24
Subtract 1 from each side
5x+1-1 < -24-1
5x < -25
Divide by 5
5x/5 < -25/5
x < -5
Suppose IQ scores were obtained for 20 randomly selected sets of siblings . The 20 pairs of measurements yield x overbar equals98.26, y overbar equals99, requals 0.911, P-valueequals 0.000, and ModifyingAbove y with caret equals negative 5.9 plus 1.07 x , where x represents the IQ score of the older child . Find the best predicted value of ModifyingAbove y with caret given that the older child has an IQ of 102 ? Use a significance level of 0.05 g
Answers
Answer:
The answer to the best prediction is 115.04
Step-by-step explanation:
We have to:
x = 102
They also tell us that:
y = 5.9 + 1.07 * x
If we replace we have:
y = 5.9 + 1.07 * (102)
y = 115.04
Therefore, the best predicted value of ModifyingAbove and with caret given that the older child has an IQ of 102 is 115.04
PLEASE HELP ITS DUE SOON ALL HELP NEEDED!!
Answers
Answer:
12345678901234567890
Answer:
[tex]95ft^2[/tex]
Step-by-step explanation:
First, note the surfaces we have. We have four triangles and one square base. Thus, we can find the surface area of each of them and them add them all up.
First, recall the area of a triangle is [tex]\frac{1}{2} bh[/tex]. We have four of them so:
[tex]4(\frac{1}{2} bh)=2bh[/tex]
The base is 5 while the height is 7. Thus, the total surface area of the four triangles are:
[tex]2(7)(5)=70 ft^2[/tex]
We have one more square base. The area of a square is [tex]b^2[/tex]. The base is 5 so the area is [tex]25ft^2[/tex].
The total surface area is 70+25=95.
What is the complete factorization of x^2+4x-45?
Answers
Answer:(x-5)(x+9)
Step-by-step explanation:
You want two numbers that can give you -45 in multiplication and two numbers that can add to 4 and that is -5 and 9.
Answer: (x - 5)(x + 9)
If you have to solve, x=5 or x= -9
Step-by-step explanation: You need two numbers that multiply to be 45.
(could be 3 × 15 or 5 × 9) . The difference between the two factors needs to be 4, the coefficient of the middle term.
9 - 5 =4, so use those. -45 has a negative sign, so one of the factors must be + and the other - Since the 4 has the + sign, the larger factor has to be + so the difference will be positive.
So (x -5)(x + 9) are your factors. You can FOIL to be sure
x × x += x² . x × 9 = 9x . -5 × x = -5x . -5 × 9 = -45 .
Combine the x terms: 9x -5x = +4x
I got the answer but I really don’t know if it’s correct or not, please help this is due today
Answers
Explanation: 180-52 = 128
So we have an equation:
2^3x+1=128 ( cuz they are in the same position)
Now we need to find what number that 2 raise to the power of that number is 128
And the answer is 2^7=128
Let’s go back to our equation:
2^3x+1=128
And we know that 2^7=128
Now we just have to make 3x+1=7:
3x+1=7
x=(7-1)/3
x=2
And there you have it x=2
A committee has ten members. There are two members that currently serve as the board's chairman and vice chairman. Each member is equally likely to serve in any of the positions. Two members are randomly selected and assigned to be the new chairman and vice chairman. What is the probability of randomly selecting the two members who currently hold the positions of chairman and vice chairman and reassigning them to their current positions?
Answers
Answer:
1/90 = 1.11%
Step-by-step explanation:
We have that the number of ways of total selections and assignments possible is a permutation.
We know that permutations are defined like this:
nPr = n! / (n-r)!
In our case n = 10 and r = 2, replacing:
10P2 = 10! / (10 - 2)! = 10! / 8!
10P2 = 90
In addition to this, there will only be one way to randomly select the two members currently holding the positions of President and Vice President and reassign them to their current positions. Thus,
Probability would come being the following:
P = 1/90 = 1.11%
What is the volume of a cubed shaped box with edges 6 cm. in length?
Answers
Answer:
216 cm³
Step-by-step explanation:
The volume of a cube is denoted by V = s³, where s is the side length.
Here, the side length is 6 centimetres, so plug this into the formula to find V:
V = s³
V = 6³ = 6 * 6 * 6 = 216
The answer is thus 216 cm³.
~ an aesthetics lover
Answer:
216
Step-by-step explanation:
6³ = 216
simpifly (-5x2 - 3x - 7) + (-2x3 + 6x2 - 8)
Answers
Answer:
-2x³ + x² - 3x - 15
Step-by-step explanation:
Simply combine like terms together:
-5x² - 3x - 7 - 2x³ + 6x² - 8
-2x³ + (-5x² + 6x²) - 3x + (-7 - 8)
-2x³ + x² - 3x + (-7 - 8)
-2x³ + x² - 3x - 15
Answer: -2x^3+x^2-3x-15
Step-by-step explanation:
As there is only addition and subtraction here, and the two groups of parenthesis are added, you can ignore the parenthesis.
Thus, simply combine like terms to get.
-2x^3+x^2-3x-15
Hope it helps <3
PLEASE HELP. FINAL TEST QUESTION!!!!
Devon is having difficulty determining if the relation given in an input-output table is a function. Explain why he is correct or incorrect.
Answers
Step-by-step explanation:
input x , output y
if x= x1 then y=y1 and y1 is the only value then it is a function
if we get multiple values of y then it is not a function
A 30% cranberry juice drink is mixed with a 100% cranberry juice drink. The function f(x)=(6)(1.0)+x(0.3)6+x models the concentration of cranberry juice in the drink after x gallons of the 30% drink are added to 6 gallons of pure juice. What will be the concentration of cranberry juice in the drink if 2 gallons of 30% drink are added? Give the answer as a percent.
Answers
Answer:
82.5%
Step-by-step explanation:
It helps to start with the correct formula:
f(x) = ((6)(1.0) +x(0.3))/(6 +x) . . . . parentheses are required
Then f(2) is ...
f(2) = (6 +.3(2))/(6+2) = 6.6/8
f(2) = 82.5%