Answer:
example of adaptation in mangrove
Mangroves are salt-tolerant trees, also called halophytes, and are adapted to life in harsh coastal conditions. They contain a complex salt filtration system and complex root system to cope with salt water immersion and wave action. They are adapted to the low oxygen conditions of waterlogged mud.
adaptation of rainforest
Many animals have adapted to the unique conditions of the tropical rainforests.
hope this can help you
Which of the following statements are true (mark all that apply) primordial nucleosynthesis produced all of the elements heavier than helium chemical composition of our solar system matches the chemical composition of the Milky Way some of the stars in the Milky Way may be older than the Milky Way your body contains a lot of helium nearly all atoms of elements heavier then helium were produced through nuclear fusion in stellar interiors and through reactions that occur during explosions that massive stars undergo at the ends of their lives or during mergers of stellar remnants called neutron stars some of the oldest galaxies are about 13.2 billion years old nucleosynthesis is a process through which the atoms of various elements are produced you're mainly made of hydrogen
Answer:
The correct options are;
1) The chemical composition of our solar system matches the chemical composition of the Milky Way
2) Nearly all atoms of elements heavier than helium were produced through nuclear fusion in stellar interiors and through reactions that occur during explosions that massive stars undergo at the ends of their lives or during mergers of stellar remnants called neutron stars
3) Some of the oldest galaxies are about 13.2 billion years old
4) Nucleosynthesis is a process through which the atoms of various elements are produced
5) You re mainly made of hydrogen
Explanation:
1) There are dependencies between chemical composition of stars and planets and the same distribution of chemicals we have in our Solar system have been observed to be present in varying resemblance through out the Milky Way
2) The formation of heavier elements are believed to have been formed by astrophysical fusion processes
3) The oldest known object (and hence the galaxy where the star resides), is from a distant star known as GRB 090423 which is about 13 billion years old
4) New atomic nuclear are created by the process of protons and neutrons by the process of nucleosynthesis
5) 62%of the atoms in the body are hydrogen atoms.
1-D Kinematics
A car starts at a position of -153 m
and undergoes a displacement of
512 m. What is its final position?
(Unit = m)
Answer:
hope it helps you...........
What are some of the major differences between the ancient Olympics and modern-day Olympics? List and describe at least two differences.
Answer:
-Women are now allowed to participate in the Olympics unlike before when it was only men allowed.
-Modern Olympic Games include many more events. There are more than 20 different sports and almost 300 events in the modern games, while the first Olympics only had running.
-The Olympics are held every two years. While the ancient Olympics were originally held every four years.
-Athletes from countries around the world participate in the modern Olympics unlike in the ancient Olympics where only athletes from ancient Greece competed.
Explanation:
Edmentum Plato answer (i already reworded most of it so you don't have to) <33
An apple falls out of a tree from a height of 2.3 m What is the impact speed of the apple?
Answer:
6.72 m/s
Explanation:
recall that the equations of motion may be expressed as
v² = u² + 2as
where,
v = final velocity,
u = initial velocity = 0 m/s because it is stationary before it starts falling
a = acceleration (in this case because it is falling, it is the acceleration due to gravity = 9.81 m/s²)
s = distance traveled = 2.3m
in our case, if we neglect air resistance, then we simply substitute the known values above into the equation of motion.
v² = u² + 2as
v² = 0² + 2(9.81)(2.3)
v² = 45.126
v = √45.126
v = 6.72 m/s
If I were to fill a water bottle full of air and go up in elevation, would the water bottle expand or shrink? If I were to fill a water bottle full of air and go down in elevation, would the water bottle expand or shrink? I am at elevation 20000 I think.
Answer:
a. It would shrink
b. It would expand
Explanation:
a. Since the water bottle is filled with air at atmospheric pressure at 20000 ft, and since atmospheric pressure decreases with altitude, when we go up in elevation.
The pressure exerted by the molecules of air in the water bottle seek to balance out the atmospheric pressure as we go higher. Since the atmospheric pressure exerted by the molecules of air in the atmosphere are greater than that exerted by the molecules of air in the water bottle, this causes the volume of the water bottle to decrease and thus shrinks the water bottle until the pressure balances out
b. Since the water bottle is filled with air at atmospheric pressure at 20000 ft, and since atmospheric pressure increases with decreasing altitude, when we go down in elevation.
The pressure exerted by the molecules of air in the water bottle seek to balance out the atmospheric pressure as we go lower. The water bottle expands until the atmospheric pressure outside equals the pressure inside the water bottle.this causes the volume of the water bottle to increase and thus expands the water bottle until the pressure balances out
A toboggan with two riders has a total mass of 87.0 kg. A third person is pushing the toboggan with a force of 42.5 N at the top of a hill with an angle of 16°. The force of friction on the toboggan is 36.0 N. Which statement describes an accurate free-body diagram to represent the situation? (Choose one of the forces acting on the system with correct magnitude and direction.)
Options:
a) An arrow of magnitude 852.6 N points perpendicular to the slope of the hill.
b) An arrow of magnitude 6.50 N points down the slope of the hill.
c) An arrow of magnitude 78.5 N points down the slope of the hill.
d) An arrow of magnitude 852.6 N points straight down.
Answer:
d) An arrow of magnitude 852.6 N points straight down.
Explanation:
The total mass of the two riders, m = 87.0 kg
The free body diagrams of the situation described are drawn and contained in the files attached to this solution.
Note that the weight of the toboggan will act directly downwards.
Therefore, the weight of the toboggan, W = mg
W = 87 * 9.8
W = 852.6 N
Since the arrow representing the weight of the toboggan points straight down, the correct answer is that an arrow of magnitude 852.6 N points straight down.
what are laws of newton
Answer:
In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction
Explanation:
Answer:
Newton's Law of Motion
1- Every object persists in its state of rest or uniform motion - in a straight line unless it is compelled to change that state by forces impressed on it.
2- Force is equal to the change in momentum per change in time. For a constant mass, force equals mass times acceleration.
3- For every action, there is an equal and opposite reaction.
During the warm-up and your scheduled physical activity, what was the weather like? Did the
temperature or conditions affect how much water you drank? How?
Answer: I did these exercises outdoors. The weather was hot and humid, so I drank about two cups of water during the workout. I also drank a cup of water about an hour before I started. Yes, the weather most definitely affected how much I drank.
Explanation: Edmentum
Un cuerpo de masa m. Tiene una velocidad V. Si la masa del cuerpo se incrementa al triple de su valor original y la velocidad se mantiene constante en dirección y sentido, pero su módulo aumenta al cuádruplo de su valor original, en tal caso la razón entre el tamaño del momentum inicial P2 y el tamaño del momentum final P1 es:
Answer: El momento final es 12 veces el momento inicial.
Explanation:
El momento es definido como la cantidad de movimiento, y la ecuación es:
P1 = m*V
donde m es masa y V es velocidad
Si este es el momento inicial de nuestro objeto, y ahora la masa se triplica y la velocidad se cuadriplica (en modulo) el nuevo momento es:
P2 = (3*m)*(4*V) = 3*4*m*V = 12*m*V
Entonces la razón entre los momentos es:
P2/P1 = 12m*V/(m*V) = 12
A 500 kg satellite experiences a gravitational force of 3000 N, while moving in a circular orbit around the earth. Determine the speed of the satellite.
Answer:
Speed of the satellite V = 6.991 × 10³ m/s
Explanation:
Given:
Force F = 3,000N
Mass of satellite m = 500 kg
Mass of earth M = 5.97 × 10²⁴
Gravitational force G = 6.67 × 10⁻¹¹
Find:
Speed of the satellite.
Computation:
Radius r = √[GMm / F]
Radius r = √[(6.67 × 10⁻¹¹ )(5.97 × 10²⁴)(500) / (3,000)
Radius r = 8.146 × 10⁶ m
Speed of the satellite V = √rF / m
Speed of the satellite V = √(8.146 × 10⁶)(3,000) / 500
Speed of the satellite V = 6.991 × 10³ m/s
What is the formula for calculating the efficiency of a heat engine? Answers:
A cars start from rest . after 10 seconds its acceleration become 2 meter per second find its final velocity
Answer:
[tex] \boxed{\sf Final \ velocity = 20 \ m/s} [/tex]
Given:
Initial velocity (u) = 0 m/s
Acceleration (a) = 2 m/s²
Time taken (t) = 10 seconds
To Find:
Final velocity (v)
Explanation:
[tex]\sf From \ equation \ of \ motion: \\ \sf v = u + at \\ \\ \sf v = 0 + 2(10) \\ \\ \sf v = 2 \times 10 \\ \\ \sf v = 20 \ m/s[/tex]
A machine is 40 % efficient. The total energy supplied to the machine is 4 kJ. Calculate how much useful energy can be transferred.
Answer:
1.6 kJ
Explanation:
0.40 (4 kJ) = 1.6 kJ
Dominic made the table below to organize his notes about mixtures.
Properties of Mixtures
has no set composition
must have more than one state of matter
must have more than one substance
What mistake did Dominic make?
The title should read "Properties of Solutions" because some mixtures do not have all of the properties listed.
There is a definite recipe to make each mixture, so the composition of a mixture is set.
Although it is possible to have more than one state, it is also possible to have only one state.
A single substance can be used to make a mixture if the substance is composed of more than one element.
Answer:
Althought it us possible to have more then one state, it's also possible to have only one state of matter
Explanation:
You can make solutions of only one state if matter, for example , it two liquids can be mixed to form a solution they are called miscible.
Answer:
The correct answer is C.) Although it is possible to have more than one state, it is also possible to have only one state.
Explanation:
I just did the test on edge and got it right
Convert Gravitational constant (G) = 6.67×10^-11 Nm²kg^-2 to cm³ g ^-1 s^-2.
Answer:
6.67×10⁻⁸ cm³/g/s²
Explanation:
6.67×10⁻¹¹ Nm²/kg²
= 6.67×10⁻¹¹ (kg m/s²) m²/kg²
= 6.67×10⁻¹¹ m³/kg/s²
= 6.67×10⁻¹¹ m³/kg/s² × (100 cm/m)³ × (1 kg / 1000 g)
= 6.67×10⁻⁸ cm³/g/s²
a force of 50 n acts on abody of mass 5 kg .calculate the acceleration produced
Answer:
a = 10 m/s²
Explanation:
Given:
Force = F = 50 N
Mass = m = 5 kg
Required:
Acceleration = a = ?
Formula:
F = ma
Solution:
Rearranging the formula for a
=> a = F/m
=> a = 50/5
=> a = 10 m/s²
the value of MA in the third class lever is alaways less than one,why
Answer:
It is always less than 1 because the load arm is always longer than effort arm.
Explanation:
In the formula, MA= effort divided by load which makes it less than 1.
This helps by reducing the applied force(effort). It is a speed multiplier.
Hope it helps.
Find vertical and horizontal displacement. Please help. 10 points. Thank you.
Explanation:
horizontal velocity = 30 x Cos45 = 19.48m/s
to find horizontal displacement
horizontal displacement = horizontal velocity x timehorizontal displacement = 19.48 x 2 = 38.96mvertical velocity = 30 x Cos45 = 22.81m/s
vertical displacement = vertical velocity x time
vertical displacement = 22.81 x 2 = 45.62m
Answer:
Displacement after two seconds
= <Dx,Dy> = <42.426, 1.593> m to three decimal places
Explanation:
Given:
arrow shot at 30m/s and 45 degrees with horizontal.
Hit bull's eye after 2 seconds.
Find horizontal and vertical displacements.
Vx = 30cos(30) m/seconds constant velocity
therefore
Dx = Vx*t = 30cos(30) m/s * 2 s = 60 cos (45) = 42.426 m
Vy = 30 sin(45) m/s
Dy = Vy*t + a(t^2) /2
= 30*sin(45) -9.81(2^2)/2 (g is accelerating downwards, so negative)
= 1.593 m
The net displacement after 2 seconds is
D = <Dx,Dy> = <42.426, 1.593> m to three decimal places
differences between concave and convex meniscus
Explanation:
A concave meniscus,(normally seen) occurs when the molecules of the liquid are attracted to those of the container. This occurs with water and a glass tube. A convex meniscus occurs when the molecules have a stronger attraction to each other than to the container, as with mercury and glass.
Answer:
there are differences between concave and convex menuscus
Explanation:
A concave meniscus, which is what you normally will see, occurs when the molecules of the liquid are attracted to those of the container. This occurs with water and a glass tube. A convex meniscus occurs when the molecules have a stronger attraction to each other than to the container, as with mercury and glass.
A 150 g egg is dropped from 3.0 meters. The egg is moving at 4.4 m/s right before it hits the ground. The egg comes to a stop in 0.072 seconds.
What is the magnitude of force that the ground exerted on the egg?
0.66 N
9.2 N
13 N
180 N
Answer is 9.2 N
Answer: Magnitude of the force exerted on the egg by the ground is 9.2N
Explanation:
Given the following :
Mass of egg (m) = 150g = 0.15kg
Height(h) from which egg is dropped = 3m
velocity of egg before hitting the ground (u) = 4.4m/s
Final velocity of egg (V) = 0
Time taken (t) = 0.072s
Magnitude of the force exerted on the egg by the ground can be found by applying Newton's 2nd law:
Momentum = mass × velocity
From Newton's second law:
Force = mass × change in Velocity with time ;
That is
F = m * ΔV / t
Inputting our values
F = 0.15 * (4.4 - 0) / 0.072
F = 0.15 × (4.4 / 0.072)
F = 0.15 × 61.11
F = 9.16N
F = 9.2N
Answer:
9.2 N
Explanation:
Just took practice quiz
As a motorcycle takes a sharp turn, the type of motion that occurs is called _______________ motion.
Answer:
circular motion
Explanation:
As a motorcycle takes a sharp turn, the type of motion that occurs is called circular motion.
Circular motion is a movement of an object along a circular path. As this motorcycle makes the sharp turn, it is acted upon by a centripetal force which directs the motorcycle towards the center.
Therefore, circular motion is the correct answer to the question.
Answer:
Circular Motion
A water pipe tapers down from an initial radius of R1 = 0.2 m to a final radius of R2 = 0.09 m. The water flows at a velocity v1 = 0.87 m/s in the larger section of pipe. What is the volume flow rate of the water?
Answer:
0.109 m/s
Explanation:
The calculation of the volume flow rate of the water is shown below:-
Av = Velocity ([tex]\pi[/tex])(Radius)^2
= 0.87([tex]\pi[/tex])(0.2)^2
= 0.135258 m^3 / sec
= 0.109371429 m/s
or
= 0.109
So, for calculating the volume flow rate of the water we simply applied the above formula i.e by multiplying the velocity with pi and squaring of radius so that the volume could come
When Emma pushes a bag with a force of 27 newtons, the coefficient of kinetic friction between the bag and the floor is 0.23. What is the normal force acting on the bag by the floor? A. 0.085 newtons B. 27 newtons C. 2.7 × 102 newtons D. 1.2 × 102 newtons
Answer:
D. 1.2 × 102 newtons
Explanation:
The computation of the normal force acting on the bag is shown below:
It could find out by applying the following formula
Normal force = Force ÷ coefficient of kinetic friction
where,
Force is 27 newtons
And, the coefficient of kinetic friction is 0.23
Now placing these values to the above formula
So, the normal force is
= 27 newtons ÷ 0.23
= 117.39 N
Therefore the correct option is D.
Study the scenario. The particles in some system are moving around quickly. A few minutes later, the particles are moving, on average, more slowly. How does this change in motion affect the temperature of the system? A. The temperature of the system did not change. The speed of the particles has no effect on the temperature, only the type of atom affects the temperature. B. The temperature of the system is higher now than it was initially. Slower moving particles result in a higher temperature for the system. C. The temperature of the system did not change. The speed of the particles does not affect temperature, the number of particles affects the temperature. D. The temperature of the system is lower now than it was initially. Faster moving particles result in a higher temperature for the system.
Answer:
The correct answer is option D.
Explanation:
With an increase in temperature, the particles increase kinetic energy and move quicker. The normal speed of the particles relies upon their mass just as the temperature – heavier particles move more gradually than lighter ones at a similar temperature.
The temperature increase in this system since the average kinetic energy of the particles increases and particles move quickly. And after some time the temperature of the system is lower now than it was initially.
Thus, the correct answer is option D.
The impact of the change in motion should be option D.
Impact on the temperature:In the case when there is an increase in temperature, the particles should increase kinetic energy and move faster. The normal speed of the particles believes their mass is like the temperature. The temperature rises in this system because the average kinetic energy of the particles should rised and particles move faster.
Learn more about energy here: https://brainly.com/question/6034042
A 28-turn circular coil of radius 4.40 cm and resistance 1.00 Ω is placed in a magnetic field directed perpendicular to the plane of the coil. The magnitude of the magnetic field varies in time according to the expression B = 0.010 0t + 0.040 0t2, where B is in teslas and t is in seconds. Calculate the induced emf in the coil at t = 4.20 s.
Answer:
ε = -0.0589V = -58.9mV
Explanation:
In order to calculate the induced emf in the coil, you use the following formula:
[tex]\epsilon=-N\frac{d\Phi_B}{dt}=-N\frac{d(SBcos\alpha)}{dt}[/tex] (1)
ε: induced emf = ?
N: turns of the coil = 28
ФB: magnetic flux trough the coil
S: cross sectional area of the circular coil = π.r^2
r: radius of the cross sectional area of the coil = 4.40cm = 0.044m
B: magnetic field
α: angle between the direction of the magnetic field and the direction of the normal to the cross area of the coil = 0°
You take into account that the area is constant respect to the magnetic field that cross it. Only the magnetic field is changing with time. The magnetic field depends on time as follow:
[tex]B(t)=0.010t+0.040t^2[/tex] (2)
You replace the expression (2) into the equation (1), evaluate the derivative, and replace the values of the other parameters for t =4.20s:
[tex]\epsilon=-NS\frac{dB}{dt}=-NS\frac{d}{dt}[0.010t+0.040t^2]\\\\\epsilon(t)=-NS(0.010+0.080t)\\\\\epsilon(t)=-(28)(\pi(0.044m)^2)(0.010T/s+0.080T/s^2(4.20s))\\\\\epsilon(t)=-0.0589V=-58.9mV[/tex]
The induced emf in the coil is -58.9mV
help fast I want the correct answer please does spectral diffusion cause light to scatter
Answer: No
Explanation:
Whenever light travelling on a straight line encounters obstruction, it diffracts and scatter.
Scattering of light occurs when light passes through a rough path or a diffused surface.
But in case of spectral diffusion, which is the fluctuation in spectroscopy as a result of time dependent frequency shifts.
Spectral diffusion occurs in particular molecules initiated by excessive excitation energy.
Fluctuation in frequency does not mean diffraction of light or particles
Therefore, spectral diffusion does not cause light to scatter.
An electron moving with a velocity of 5 × 104 m s -1 enters into a uniform electric field and acquires a uniform acceleration of 104 m s -2 in the direction of its initial motion. (i) Calculate the time in which the electron would acquire a velocity double of its initial velocity. (ii) How much distance the electron would cover in this tim
Answer:
(i) t = 5s
(ii) x = 3.75*10^5 m
Explanation:
(i) To calculate the time that the electron takes to reach twice the value of its initial velocity, you use the following formula:
[tex]v=v_o+at[/tex] (1)
vo: initial velocity of the electron = 5*10^4 m/s
v: final velocity of the electron = 2vo = 1*10^5 m/s
a: acceleration of the electron = 1*10^4 m/s^2
You solve the equation (1) for t, and replace the values of the parameters:
[tex]t=\frac{v-v_o}{a}=\frac{1*10^5m/s-5*10^4m/s}{1*10^4m/s^2}=5s[/tex]
The electron takes 5s to reach twice its initial velocity.
(ii) The distance traveled by the electron in such a time is:
[tex]x=v_ot+\frac{1}{2}at^2[/tex] (2)
you replace the values of the parameters in the equation (2):
[tex]x=(5*10^4m/s)(5s)+\frac{1}{2}(1*10^4m/s^2)(5s)^2\\\\x=3.75*10^5m[/tex]
The distance traveled by the electron is 3.75*10^3m/s
a student pushed a 100 N bicycle over a distance of 15 m in 5 s. calculate the power generated.
The catch in this one is: We don't know how much force the student used to push the bike.
It wasn't necessarily the 100N. That's just the weight of the bike. But you know that you can push a car, a wagon, or a bicycle hard, you can push it not so hard, you can give it a little push, you can give it a big push, you can push it strong, you can push it weak, you can push it medium. The harder you push, the more it'll accelerate, but it's completely up to you how hard you want to push. That's what's so great about wheels ! That's why they were such a great invention ! This is where I made my biggest mistake. This guy came into my store one day and said he's got this great invention, it's definitely going to take off, it'll be a winner for sure, he called it a "wheel". I looked at it, I turned it over and I looked on all sides. I thought it was too simple. I didn't know then it was elegant. I threw him out. I was so dumb. I could have invested money in that guy, today I would have probably more than a hundred dollars.
Anyway, can we figure out how much force the student used to push with ? Stay tuned:
-- The bike covered 15 meters in 5 seconds. Its average speed during the whole push was (15m/5s) = 3 meters/sec.
-- If the bike started out with no speed, and its average speed was 3 m/s, then it must have been moving at 6 m/s at the end of the push.
-- If its speed increased from zero to 6 m/s in 5 seconds, then its acceleration was (6m/s / 5 sec) = 1.2 m/s²
-- The bike's weight is 100N.
(mass) x (gravity) = 100N
Bikemass = (100N) / (9.8 m/s²)
Bikemass = 10.2 kilograms
-- F = m A
Force = (mass) x (acceleration)
Force = (10.2 kg) x (1.2 m/s²)
Force = 12.24 N
-- Work = (force) x (distance)
Work = (12.24 N) x (15 m)
Work = 183.67 Joules
-- Power = (work done) / (time to do the work)
Power = (183.67 joules) / (5 seconds)
Power = 36.73 watts
I NEEED HELP!!!!! Upon using Thomas Young’s double-slit experiment to obtain measurements, the following data were obtained. Use these data to determine the wavelength of light being used to create the interference pattern.
Do this using three different methods.
The angle to the eighth maximum is 1.12°.
The distance from the slits to the screen is 302.0 cm.
The distance from the central maximum to the fifth minimum is 3.33cm.
The distance between the slits is 0.000250 m
Answer:
The wavelength is approximately 611 nm
Explanation:
We can use the formula for the condition of maximum of interference given by:
[tex]d\,sin(\theta)=m\,\lambda\\(0.000250\,\,m)\,\,sin(1.12^o)=8\,\lambda\\\lambda=\frac{1}{8} \,(0.000250\,\,m)\,\,sin(1.12^o)\\\lambda \approx 610.8\,\,nm[/tex]
We can also use the formula for the distance from the central maximum to the 5th minimum by first finding the tangent of the angle to that fifth minimum:
[tex]tan(\theta)=\frac{y}{D}\\ tan(\theta)=\frac{0.0333}{3.02} =0.011026[/tex]
and now using it in the general formula for minimum:
[tex]d\,sin(\theta)\approx d\,tan(\theta)=(m-\frac{1}{2} )\,\lambda\\\lambda\approx 0.00025\,(0.011026)/(4.5)\,\,m\\\lambda\approx 612.55\,\,nm[/tex]
Answer:
The correct answer is [tex]6.1\times10^{-7}\:m[/tex]
Explanation:
The distance from the central maxima to 5th minimum is:
[tex]x_{5n}-x_{0} =3.33\:cm=0.033\:m[/tex]
The distance between the slits and the screen:
[tex]L = 302\:cm = 3.02\:m[/tex]
Distance between 2 slits: [tex]d = 0.00025\:m[/tex]
[tex](n-\frac{1}{2})\lambda=\frac{d(x_n)}{L}[/tex]
For fifth minima, n = 5... so we have:
[tex]x_{5n}=\frac{9\lambda L}{2d}[/tex]
For central maxima, n = 0... so we have:
[tex]x_{0}=\frac{n\lambda L}{d}=0[/tex]
So the distance from central maxima to 5th minimum is:
[tex]\frac{9\lambda \:L}{2d}-0=0.033[/tex] (Putting the values, we get):
[tex]\Rightarrow \lambda = 6.1\times 10^{-7}\:m[/tex]
Best Regards!
how does gravitational pull affect planets with the same mass but different distance from the sun?
Answer:
it just pulls them at the same time
Explanation: