Answer:
5(3x + 2)
Step-by-step explanation:
15x + 10
1. 5(3x + 2)
The profit, in thousands of dollars, from the sale of x thousand candles can be estimated by P(x) = 5 x - 0.7 x ln x.
1) Find the marginal profit, P'(x).
2) Find P'(10), and explain what this number represents. What does P'(10) represent?
A. The additional profit, in thousands of dollars, for selling a thousand candles once 10,000 candles have already been sold.
B. The additional profit, in thousands of dollars, when 10,000 candles are sold.
C. The additional cost, in thousands of dollars, to produce a thousand candles once 10,000 candles have already been sold.
D The additional cost, in thousands of dollars, to produce 10,000 candles.
C. How many thousands of candles should be sold to maximize profit?
1) The marginal profit is [tex]4.3 - 0.7 ln(x)[/tex].
2) The additional profit, in thousands of dollars, for selling a thousand candles once 10,000 candles have already been sold.
Thus, option (A) is correct.
C) To maximize profit 462,481 thousands of candles should be sold.
Given: [tex]P(x) = 5 x - 0.7 x[/tex] [tex]{\text}ln x.[/tex]
1) Take the derivative of the profit function P(x) with respect to x.
P(x) = 5x - 0.7x ln(x)
To find P'(x), differentiate each term separately using the power rule and the derivative of ln(x):
[tex]P'(x) = 5 - 0.7(1 + ln(x))[/tex]
= [tex]5 - 0.7 - 0.7 ln(x)[/tex]
= [tex]4.3 - 0.7 ln(x)[/tex]
2) Substitute x = 10 into the derivative:
P'(10) = 4.3 - 0.7 ln(10)
= 4.3 - 0.7(2.30259)
= 4.3 - 1.61181
= 2.68819
Therefore, the additional profit for selling a thousand candles once 10,000 candles have already been sold.
Thus, option (A) is correct.
C) Set P'(x) = 0 and solve for x:
[tex]4.3 - 0.7 ln(x) = 0[/tex]
[tex]0.7 ln(x) = 4.3[/tex]
[tex]{\text} ln(x) = 4.3 / 0.7[/tex]
[tex]{\text} ln(x) = 6.14286[/tex]
[tex]x = e^{6.14286[/tex]
[tex]x = 462.481[/tex]
Therefore, 462,481 thousands of candles should be sold.
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1) The marginal profit, P'(x), is -0.7ln(x) + 4.3.
2) The number of thousands of candles that should be sold to maximize profit is approximately 466.9.
1) To find the marginal profit, P'(x), we need to take the derivative of the profit function, P(x), with respect to x. Using the power rule and the chain rule, we can differentiate the function:
P(x) = 5x - 0.7x ln(x)
Taking the derivative with respect to x:
P'(x) = 5 - 0.7(ln(x) + 1)
Simplifying:
P'(x) = 5 - 0.7ln(x) - 0.7
P'(x) = -0.7ln(x) + 4.3
2) To find P'(10), we substitute x = 10 into the marginal profit function:
P'(10) = -0.7ln(10) + 4.3
Using a calculator, we can evaluate this expression:
P'(10) ≈ -0.7(2.3026) + 4.3 ≈ -1.6118 + 4.3 ≈ 2.6882
The value of P'(10) is approximately 2.6882.
Now, let's interpret what P'(10) represents:
The correct interpretation is A. The additional profit, in thousands of dollars, for selling a thousand candles once 10,000 candles have already been sold.
P'(10) represents the rate at which the profit is changing with respect to the number of candles sold when 10,000 candles have already been sold. In other words, it measures the additional profit (in thousands of dollars) for each additional thousand candles sold once 10,000 candles have already been sold.
Lastly, to determine the number of thousands of candles that should be sold to maximize profit, we need to find the critical points of the profit function P(x). This can be done by setting the derivative P'(x) equal to zero and solving for x.
-0.7ln(x) + 4.3 = 0
-0.7ln(x) = -4.3
ln(x) = 4.3 / 0.7
Using properties of logarithms:
x = e^(4.3 / 0.7)
Using a calculator, we can evaluate this expression:
x ≈ e^(6.1429) ≈ 466.9
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The charitable foundation for a large metropolitan hospital is conducting a study to characterize its donor base. In the past, most donations have come from relatively wealthy individuals; the average annual donor income in the most recent survey was right at $100,000. The foundation believes the average has now increased. A random sample of 200 current donors showed a mean annual income of $103,157 and a standard deviation of $27,498.a. To perform this study, we should form a null hypothesis stating that the average is ______________ 100,000. (Please fill in only one of the following: "less than", "less than or equal to", "equal to", "greater than", "greater than or equal to". Please do not use symbols.)b. At the 10% significant level, the p-value/statistics is _____________________ (Please keep three decimal points) so we should __________________ the null hypothesis (Please only fill in "reject" or "not reject".).c. Hence, we may conclude that the average _________________ increased (Please only fill in "has" or "has not") and the probability that our conclusion is correct is at least _________________ percent.
Answer:
Step-by-step explanation:
a) We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
H0: µ equal to 100000
For the alternative hypothesis,
H1: µ greater than 100000
This is a right tailed test
Since the population standard deviation is nit given, the distribution is a student's t.
Since n = 200
Degrees of freedom, df = n - 1 = 200 - 1 = 199
t = (x - µ)/(s/√n)
Where
x = sample mean = 103157
µ = population mean = 100000
s = samples standard deviation = 27498
t = (103157 - 100000)/(27498/√200) = 1.62
We would determine the p value using the t test calculator.
p = 0.053
Alpha = 10% = 0.1
Since alpha, 0.1 > than the p value, 0.053, then
b) At the 10% significant level, the p-value/statistics is 0.053, so we should not reject the null hypothesis.
c) Hence, we may conclude that the average has not increased and the probability that our conclusion is correct is at least 90 percent.
g 7. Find Re f and Im f and find their values at the given z. (Both answers should be included) f = z⁄(z + 1), z = 4 − 5
Answer:
The real and imaginary parts of the result are [tex]\frac{1441}{1601}[/tex] and [tex]\frac{4}{1601}[/tex], respectively.
Step-by-step explanation:
Let be [tex]f(z) = \frac{z}{z+1}[/tex], the following expression is expanded by algebraic means:
[tex]f(z) = \frac{z\cdot (z-1)}{(z+1)\cdot (z-1)}[/tex]
[tex]f(z) = \frac{z^{2}-z}{z^{2}-1}[/tex]
[tex]f(z) = \frac{z^{2}}{z^{2}-1}-\frac{z}{z^{2}-1}[/tex]
If [tex]z = 4 - i5[/tex], then:
[tex]z^{2} = (4-i5)\cdot (4-i5)[/tex]
[tex]z^{2} = 16-i20-i20-(-1)\cdot (25)[/tex]
[tex]z^{2} = 41 - i40[/tex]
Then, the variable is substituted in the equation and simplified:
[tex]f(z) = \frac{41-i40}{41-i39} -\frac{4-i5}{41-i39}[/tex]
[tex]f(z) = \frac{37-i35}{41-i39}[/tex]
[tex]f(z) = \frac{(37-i35)\cdot (41+i39)}{(41-i39)\cdot (41+i39)}[/tex]
[tex]f(z) = \frac{1517-i1435+i1443+1365}{3202}[/tex]
[tex]f(z) = \frac{2882+i8}{3202}[/tex]
[tex]f(z) = \frac{1441}{1601} + i\frac{4}{1601}[/tex]
The real and imaginary parts of the result are [tex]\frac{1441}{1601}[/tex] and [tex]\frac{4}{1601}[/tex], respectively.
If the density of an object is 8 g/cm³, and the mass is 200M m g. What is the volume of the object?
Answer:
Step-by-step explanation:
the mass is 2000 mg, or 2 g.
the density is 8 g/cm^3
divide 2 by 8
0.25 cm^3
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Which point is a solution to the inequality shown in this graph?
5
(3,-1)
(-3,-3)
O A. (5,-5)
O B. (1,5)
C. (-3,-3)
D. (3, -1)
Hey there!
To find the answer, we just need to see which point falls in this blue, which represents the inequality.
We see that the point (5,-5) is not on the blue.
We see that the point (1,5) is on the blue.
(-3,-3) is on the dotted line but not a solution of the inequality. The dotted line is excluded from the inequality. If it were a bold line, then it would be a solution of the inequality.
(3,-1) is also on the dotted line so it is not a solution.
Therefore, the answer is B. (1,5)
I hope that this helps!
We want to see which point is a solution for the graphed inequality.
We will find that the correct option is B, (1, 5)
Notice that the line that defines the inequality contains the points (-3, -3) and (3, -1)
Then the slope of that line is:
[tex]a = \frac{-1 -(-3)}{3 - (1)} = 1/2[/tex]
Then the line is something like:
y = (1/2)*x + b
To find the value of b, we use the fact that this line passes through the point (3, -1), then we have:
-1 = (1/2)*3 + b
-1 - 3/2 + b
-5/2 = b
So the line is:
y = (1/2)*x - 5/2
And we can see that the line is slashed, and the shaded area is above the line, then we have:
y > (1/2)*x - 5/2
Now that we have the inequality, we can just input the values of the points in the inequality and see if this is true.
First, options C and D can be discarded because these points are on the line, and the points on the line are not solutions.
So we only try with A and B.
A) x = 5
y = -5
then we have:
-5 > (1/2)*5 - 5/2
-5 > 0
Which clearly is false.
B) x = 1
y = 5
Then we have:
5 > (1/2)*1 - 5/2 = -4/2
5 > -4/2
This is true, then the point (1, 5) is a solution.
Thus the correct option is B.
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Gravel is being dumped from a conveyor belt at a rate of 35 ft3/min, and its coarseness is such that it forms a pile in the shape of a cone whose base diameter and height are always equal. How fast is the height of the pile increasing when the pile is 10 ft high? (Round your answer to two decimal places.)
Answer:
0.45 ft/min
Step-by-step explanation:
Given:-
- The flow rate of the gravel, [tex]\frac{dV}{dt} = 35 \frac{ft^3}{min}[/tex]
- The base diameter ( d ) of cone = x
- The height ( h ) of cone = x
Find:-
How fast is the height of the pile increasing when the pile is 10 ft high?
Solution:-
- The constant flow rate of gravel dumped onto the conveyor belt is given to be 35 ft^3 / min.
- The gravel pile up into a heap of a conical shape such that base diameter ( d ) and the height ( h ) always remain the same. That is these parameter increase at the same rate.
- We develop a function of volume ( V ) of the heap piled up on conveyor belt in a conical shape as follows:
[tex]V = \frac{\pi }{12}*d^2*h\\\\V = \frac{\pi }{12}*x^3[/tex]
- Now we know that the volume ( V ) is a function of its base diameter and height ( x ). Where x is an implicit function of time ( t ). We will develop a rate of change expression of the volume of gravel piled as follows Use the chain rule of ordinary derivatives:
[tex]\frac{dV}{dt} = \frac{dV}{dx} * \frac{dx}{dt}\\\\\frac{dV}{dt} = \frac{\pi }{4} x^2 * \frac{dx}{dt}\\\\\frac{dx}{dt} = \frac{\frac{dV}{dt}}{\frac{\pi }{4} x^2}[/tex]
- Determine the rate of change of height ( h ) using the relation developed above when height is 10 ft:
[tex]h = x\\\\\frac{dh}{dt} = \frac{dx}{dt} = \frac{35 \frac{ft^3}{min} }{\frac{\pi }{4}*10^2 ft^2 } \\\\\frac{dh}{dt} = \frac{dx}{dt} = 0.45 \frac{ft}{min}[/tex]
Solve the system by the method of elimination.
Answer:
x=47/3 y=-11
Step-by-step explanation:
A bit messy, but I hope you can understand from this.
If you have any questions, please feel free to ask any time!
Answer:
work is shown and pictured
PLEASE HELP ASAP DUE IN 10 MINUTES PLEASE!!!!!!!!!!!!!The president of the United States produces a new national plan to reduce water pollution which of these would most likely provide the revenue to pay for this new public service
Answer
i think its federal income tax increase. 2nd one i believe
Step-by-step explanation:
The President of the United States proposes a new national plan to reduce water pollution.
Which of these would most likely provide the revenue to pay for this new public service?
Step-by-step explanation:
answer is :
the united states senate passes a bill that increases the federal income tax rate , which then pays for the service read it b4 yhu answer your question.have a good day!!and DM meh if yhu need a question answer here for 24/7pls if yhu want to mark meh as brainlist.....Write an equation that expresses the following relationship. w varies directly with u and inversely with d In your equation, use k as the constant of proportionality.
Step-by-step explanation:
solution.
if variable d increases then w reduces
w=k.u ×1/d
=ku/d
therefore w=k.u/d
Triangler prisms help
Answer:
1. 60 in cubed.
2. 36 m cubed.
3. 96 m cubed.
4. 60 yds cubed.
5. 120 in cubed.
Step-by-step explanation:
Alright, we need to know what the formula is for the volume of a triangular prism. Before that, here is the formula to find the volume of all shapes. Some formulas may be different for cones, spheres, and pyramids, but this is the general formula.
The formula is V=Bh.
V is your volume
B is the area of the base
h is the height of the prism..
The formula for calculating the volume for a triangular prism is 1/2bh times h. 1/2bh is the formula for finding the area of your triangle which is the base shape for a triangular prism. The other h is the height of your prism.
For number 1, they already calculated the area of the base for you, so just multiply that number with the height. 20 times 3 is 60.
That is 60 meters cubed.
Number 2, they haven't calculated the area of the base, so you have to do that. The length of the triangle is 4 and the height of the triangle is 3. Lets find the area of the triangle or the base, Do 4 times 3 which is 12 and divide it by 2 or multiply it by half. it is the same thing. You get 6, and that is the area of your base. Multiply that area by the height of the prism. You get 36 meters cubed. The reason why it is cubed is because meter times meter times meter is meter cubed.
Hope this helps!
Please help fast!!!! What are the center and radius of the circle defined by the equation x2 + y2 - 6x+By+21=0 ?
Answer:
Option A
Step-by-step explanation:
The first thing we want to do here is to rewrite the equation given to us, in standard circle equation -
[tex]x^2+y^2-6x+8y+21=0,\\\left(x-3\right)^2+\left(y-\left(-4\right)\right)^2=2^2[/tex]
The " standard form " of a circle is given to be in the following form,[tex](x-a)^{2} + (y-b)^{2} = r^2[/tex] where r = radius, centered at ( a, b )
Now as you can see, the center ( given by ( a, b ) ) should be ( 3, - 4 ). Respectively the radius is 2, and therefore the circle properties are -
Center [tex]( 3, - 4 )[/tex]; radius [tex]2[/tex]
Hope that helps!
Write an equation to model the total charge y (in dollars) in terms of x (the number of miles), A car rental
agency charges a flat fee of 25 dollars plus 4 dollars a mile
Answer: the answer is C: y=4x+25
Step-by-step explanation:
25= B which is the initial charge and being that no other answer has a matching response, I connected the clues.
Hunter is 9 years older than 3 times the age of his nephew. Hunter is 33 years old. How old is his nephew?
Answer:
8 years old.
(3x+9)
(3(8)+9)=33
Select the correct answer from each drop-down menu. Gino is buying wood screws at the corner hardware store. The table shows different numbers of bags of screws and their corresponding prices. Bags of Screws Price ($) 2 10 4 20 7 35 According to the table, the relationship between the number of bags and the price is proportional or not proportional
Find the greatest common factor of the
following monomials:
15r25
48353
Answer:
475r35
Step-by-step explanation:
If nine of every 11 trick-or-treaters that came to your house last Halloween were dressed as pirates what proportion of trick-or-treaters were not dressed as pirates
Answer:
11 - 9 = 2 trick-or-treaters out of 11 were not dressed as pirates so the proportion is 2/11.
Answer: Ratio is 2:11
Step-by-step explanation:
So your ratio of pirates to non-pirates would be 9:11
So you subtract number of pirates from total trick-or-treaters and get 2.
So the proportion of non-pirates would be 2:11.
"A researcher wants to test if the mean G.P.A. of CC students transferring to Sac State is above 3.3. She randomly samples 25 CC students and finds that their average G.P.A. is 3.45. Assuming that the standard deviation of G.P.A.’s is 0.5, what can the researcher conclude at the 5% significance level
Answer:
We failed to reject H₀
t < 2.06
1.5 < 2.06
We do not have significant evidence at significance level α=0.05 to show that the mean G.P.A. of CC students transferring to Sac State is above 3.3
Step-by-step explanation:
Set up hypotheses:
Null hypotheses = H₀: μ = 3.3
Alternate hypotheses = H₁: μ > 3.3
Determine type of test:
Since the alternate hypothesis states that mean G.P.A. of CC students transferring to Sac State is above 3.3, therefore we will use a upper-tailed test.
Select the test statistic:
Since the sample size is very small (n < 30) therefore, we will use t-distribution.
Determine level of significance and critical value:
Given level of significance = 5% = 0.05
Since it is a upper tailed test,
At α = 0.05 and DF = n – 1 = 25 - 1 = 24
t-score = 2.06
Set up decision rule:
Since it is a upper tailed test, using a t statistic at a significance level of 5%
We Reject H₀ if t > 2.06
Compute the test statistic:
[tex]$ t = \frac{\bar{x}-\mu}{\frac{s}{\sqrt{n} } } $[/tex]
[tex]$ t = \frac{ 3.45- 3.3 }{\frac{0.5}{\sqrt{25} } } $[/tex]
[tex]t = 1.5[/tex]
Conclusion:
We failed to reject H₀
t < 2.06
1.5 < 2.06
We do not have significant evidence at significance level α=0.05 to show that the mean G.P.A. of CC students transferring to Sac State is above 3.3
Quadrilateral JKLM has vertices J(8, 4), K(4, 10), L(12, 12), and M(14, 10). Match each quadrilateral, described by its vertices, to the sequence of transformations that will show it is congruent to quadrilateral JKLM. W(5,1), X(1,7), Y(9,9), and Z(11,7) O(10,1), P(6,7), Q(14,9), and R(16,7) S(4, 16), T(10, 20), U(12, 12), and V(10, 10) A(-8, -4), B(-4, -10), C(-12, -12), and D(-14, -10) E(5,6), F(1,12), G(9,14), and H(11,12) a translation 2 units right and 3 units down arrowRight a translation 3 units left and 2 units up arrowRight a translation 3 units down and 3 units left arrowRight a sequence of reflections across the x- and y-axes, in any order arrowRight
Answer:
See Explanation
Step-by-step explanation:
Given:
Quadrilateral JKLM has vertices J(8, 4), K(4, 10), L(12, 12), and M(14, 10).
(a)If we translate quadrilateral JKLM 3 units down and 3 units left:
(x-3,y-3), we obtain: W(5,1), X(1,7), Y(9,9), and Z(11,7)
Therefore, we match it with: A translation 3 units down and 3 units left
(b)If we translate quadrilateral JKLM 2 units right and 3 units down:
(x+2,y-3), we obtain: O(10,1), P(6,7), Q(14,9), and R(16,7)
Therefore, we match it with:A translation 2 units right and 3 units down
S(4, 16), T(10, 20), U(12, 12), and V(10, 10)
(c) If we transform quadrilateral JKLM by a sequence of reflections across the x- and y-axes, in any order, we obtain:
A(-8, -4), B(-4, -10), C(-12, -12), and D(-14, -10)
(d)If we translate quadrilateral JKLM 3 units left and 2 units up:
(x-3,y+2), we obtain:E(5,6), F(1,12), G(9,14), and H(11,12)
Therefore, we match it with: A translation 3 units left and 2 units up
(e)S(4, 16), T(10, 20), U(12, 12), and V(10, 10)
No suitable transformation is found from JKLM to STUV.
Answer:
a translation 3 units down and 3 units left
W(5,1), X(1,7), Y(9,9), and Z(11,7)
a translation 2 units right and 3 units down
O(10,1), P(6,7), Q(14,9), and R(16,7)
a sequence of reflections across the
x- and y-axes, in any order
S(4, 16), T(10, 20), U(12, 12), and V(10, 10)
a translation 3 units left and 2 units up
E(5,6), F(1,12), G(9,14), and H(11,12)
The length of a rectangle is four times its width.
If the perimeter of the rectangle is 70 ft, find its area.
Answer:
196 ft^2
Step-by-step explanation:
4(w) = L
2w + 2L = 70
2w + 2(4w) = 70
10w = 70
w = 7
4(7) = 28
Area = 28*7
Area = 196
Answer:
The area of the rectangle is 196 ft^2.
Step-by-step explanation:
Looking for: Area
The length of a rectangle is four times its width can be translated into
l = 4w
Perimeter = 2w + 2l
2w + 2(4w) = 70
2w + 8w = 70
10w = 70
w = 7
l = 4w
l= 4(7)
l=28
Area = l times w
28 times 7 = 196
The area of the rectangle is 196 ft^2.
Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) g(y) = y − 5 y2 − 3y + 15
Answer:
0, 10
Step-by-step explanation:
The given function is:
[tex]g(y) = \frac{y-5}{y^2-3y+15}[/tex]
According to the quotient rule:
[tex]d(\frac{f(y)}{h(y)}) = \frac{f(y)*h'(y)-h(y)*f'(y)}{h^2(y)}[/tex]
Applying the quotient rule:
[tex]g(y) = \frac{y-5}{y^2-3y+15}\\g'(y)=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}[/tex]
The values for which g'(y) are zero are the critical points:
[tex]g'(y)=0=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}\\(y-5)*(2y-3)-(y^2-3y+15)=0\\2y^2-3y-10y+15-y^2+3y-15\\y^2-10y=0\\y=\frac{10\pm \sqrt 100}{2}\\y_1=\frac{10-10}{2}= 0\\y_2=\frac{10+10}{2}=10[/tex]
The critical values are y = 0 and y = 10.
3.
A passenger jet can fly 1,290 mil
in 3 hours with a tailwind bi
1,230 miles in 3 hours
headwind. Find the speed
the Jet in Still air and the
of the wind.
Answer:
Jet= 420 mph Wind = 10mph
Step-by-step explanation:
The speed of the plane in a tailwind can be modeled by x+y where x is the speed of the plane and y is the speed of the wind. Dividing 1290 by 3 gets you the average speed of the jet in a tailwind, which is 430.
The speed of the plane in a headwind can be modeled by x-y where x is the speed of the plane and y is the speed of the wind. Dividing 1230 by 3 gets you the average speed of the jet in a tailwind, which is 410.
This can be modeled by a system of equations, where x+y=430 and x-y=410. Solving the equation you get x=420 and y=10.
So, the speed of the jet is 420 mph and the speed of the wind is 10 mph.
What is the domain of the function y = 3 l n x graphed below?
On a coordinate plane, a curve starts in quadrant 4 and then increases up into quadrant 1. It crosses the x-axis at (1, 0).
x greater-than 0
x less-than 0
x less-than 3
x greater-than 3
Answer:
x>0
Step-by-step explanation:
The domain are the possible values of x you can use.
For ln functions, x must be positive (the ln of a negative number does not exist).
So, x must be larger than 0. No part of the graph will be left of the y axis.
Answer:
The answer is option A.
x > 0Hope this helps you
I NEED HELP PLEASE, THANKS! :)
While doing bicep curls, Tamara applies 155 Newtons of force to lift the dumbbell. Her forearm is 0.366 meters long and she begins the bicep curl with her elbow bent at a 15° angle below the horizontal, in the direction of the positive x-axis. Determine the magnitude of the torque about her elbow. (Show work)
Answer:
54.8 N·m
Step-by-step explanation:
The horizontal distance from the dumbbell to the elbow is ...
(0.366 m)cos(15°) ≈ 0.3535 m
Then the torque due to the vertical force is ...
(155 N)(0.3535 m) = 54.8 N·m
What is invariant under a dilation?
Answer:
pls look at photo attached
What is the simplified value of this expression pls help
Answer:
7
Step-by-step explanation:
Remove parentheses.
[tex]\frac{-8+4(4.5)}{6.25-8.25} \\[/tex]
Add −8 and 4.5.
[tex]\frac{4(-3.5)}{6.25 - 8.25} \\\\[/tex]
Subtract 8.25 from 6.25.
[tex]\frac{4*-3.5}{-2}[/tex]
Multiply 4 by −3.5.
[tex]\frac{-14}{-2}[/tex]
Divide −14 by −2.
= 7
Suppose f(x)=x^2 and g(x) =7x^2 which statement best compares the graph of g(x) with the graph f(x)
Answer:
The graph g(x) is the graph f(x) vertically stretched by a factor of 7.
Step-by-step explanation:
Quadratic Equation: f(x) = a(bx - h)² + k
Since we are modifying the variable a, we are dealing with vertical stretch (a > 1) or vertical shrink (a < 1). Since a > 1 (7 > 1), we are dealing with a vertical stretch by a factor of 7.
Answer:
The graph g(x) is the graph f(x) vertically stretched by a factor of 7.
Step-by-step explanation:
Quadratic Equation: f(x) = a(bx - h)² + k
Since we are modifying the variable a, we are dealing with vertical stretch (a > 1) or vertical shrink (a < 1). Since a > 1 (7 > 1), we are dealing with a vertical stretch by a factor of 7.
Me ayudan con esto 63÷X=1.06
Answer:
[tex]x = \dfrac{3150}{53}[/tex]
[tex] x \approx 59.43 [/tex]
Step-by-step explanation:
[tex] 63 \div x = 1.06 [/tex]
[tex] 63 \div x \times x = 1.06 \times x [/tex]
[tex] \dfrac{1.06x}{1.06} = \dfrac{63}{1.06} [/tex]
[tex] x = \dfrac{6300}{106} [/tex]
[tex]x = \dfrac{3150}{53}[/tex]
[tex] x \approx 59.43 [/tex]
A man starts at a point A and walks 18 feet north. He then turns and walks due east at 18 feet per second. If a searchlight placed at A follows him, at what rate is the light turning 3 seconds after he started walking east
Answer:
1/10 per sec
Step-by-step explanation:
When he's walked x feet in the eastward direction, the angle Θ that the search light makes has tangent
tanΘ = x/18
Taking the derivative with respect to time
sec²Θ dΘ/dt = 1/18 dx/dt.
He's walking at a rate of 18 ft/sec, so dx/dt = 18.
After 3seconds,
Speed = distance/time
18ft/sec =distance/3secs
x = 18 ft/sec (3 sec)
= 54ft. At this moment
tanΘ = 54/18
= 3
sec²Θ = 1 + tan²Θ
1 + 3² = 1+9
= 10
So at this moment
10 dΘ/dt = (1/18ft) 18 ft/sec = 1
10dΘ/dt = 1
dΘ/dt = 1/10 per sec
At 1/10 per second is the rate when the light turns 3 seconds after he started walking east.
It is given that a man starts at point A and walks 18 feet north. He then turns and walks due east at 18 feet per second.
It is required to find at what rate is the light turning 3 seconds after he started walking east.
What is the trigonometric ratio?The trigonometric ratio is defined as the ratio of the pair of a right-angled triangle.
The [tex]\rm tan\theta[/tex] is the ratio of the perpendicular to the base.
When he started walking eastward direction, the searchlight makes an angle [tex]\theta[/tex]
Let the distance is x
And the [tex]\rm tan\theta = \frac{x}{18}[/tex]
After performing the derivate with respect to time, we get:
[tex]\rm sec^2\theta\frac{d\theta}{dt} = \frac{1}{18} \frac{dx}{dt}[/tex] ...(1) ( the differentiation of [tex]\rm tan\theta \ is \ sec^2\theta\\[/tex])
He walking at the rate of 18 ft per second ie.
[tex]\rm \frac{dx}{dt} = 18[/tex]
After 3 seconds [tex]\rm Speed=\frac{Distance}{Time}[/tex]
By using speed- time formula we can calculate the distance:
Distance x = 18×3 ⇒ 54 ft.
[tex]\rm tan\theta = \frac{54}{18}[/tex] ⇒3
We know that:
[tex]\rm sec^2\theta = 1+tan^2\theta[/tex]
[tex]\rm sec^2\theta = 1+3^2\\\\\rm sec^2\theta = 10\\[/tex]
Put this value in the (1) equation, we get:
[tex]\rm 10\frac{d\theta}{dt} = \frac{1}{18} \times18[/tex] ∵ [tex]\rm (\frac{dx}{dt} =18)[/tex]
[tex]\rm 10\frac{d\theta}{dt} = 1\\\\\rm \frac{d\theta}{dt} = \frac{1}{10} \\\\[/tex]per second.
Thus, at 1/10 per second what rate is the light turning 3 seconds after he started walking east.
Know more about trigonometry here:
brainly.com/question/26719838
Calculate the slope of a line passing through point A at (2, 1) and point B at (4, 2). Calculate to one decimal place.
Answer: 0.5
Step-by-step explanation:
To find the slope of a line with two given points, you use the formula [tex]m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex].
[tex]m=\frac{2-1}{4-2}=\frac{1}{2}=0.5[/tex]
The slope is 0.5.
A cellular phone company monitors monthly phone usage. The following data represent the monthly phone use in minutes of one particular
customer for the past 20 months. Use the given data to answer parts (a) and (b).
325 517 424 395 494
396 351 379 408 426
523 421 434 373 456
535 394 437 403 513
(a) Determine the standard deviation and interquartile range of the data.
s=(Round to two decimal places as needed.)
Answer:
The answer is: 325 517 424 395 494
Step-by-step explanation: