Answer:
The volume of the cone is 94.25 in³.
Step-by-step explanation:
The radius of the base is the distance between the center of the circle and the edge of the base, therefore in this case it is equal to 3 in. The volume of a cone is given by:
[tex]V = \frac{\pi*r^2*h}{3}\\V = \frac{\pi*(3)^2*10}{3}\\V = 94.25 \text{ in}^3[/tex]
The volume of the cone is 94.25 in³.
Galina had two boxes with pieces of paper in each. In the first box, each piece of paper had one possible outcome from flipping a coin 4 times (e.g. HHTH). There was one piece of paper for every possible outcome.
How many pieces of paper were in the first box?
Answer:
B
Step-by-step explanation:
U is the set of letters of the English alphabet. X is the set of letters in the word 'triangle'. Y is the set of letters in the word 'trapezoid'. Z is the set of letters in the word 'hyperbola'. What is (Y ∩ Z)’ ∩ X? *
Answer:
(Y∩Z)∩X = {r,a,e}
Step-by-step explanation:
U = {a,b,c,d,e,f,............,z)
X = { t,r,i,a,n,g,l,e}
Y = {t,r,a,p,e,z,o,i,d}
Z = {h,y,p,e,r,b,o,l,a}
Firstly,
Y∩Z = {t,r,a,p,e,z,o,i,d} ∩ {h,y,p,e,r,b,o,l,a} [Intersection : Common Elements]
=> Y∩Z = {r,a,p,e,o}
Now,
(Y∩Z)∩X = {r,a,p,e,o} ∩ { t,r,i,a,n,g,l,e}
=> (Y∩Z)∩X = {r,a,e}
A particular fruit's weights are normally distributed, with a mean of 476 grams and a standard deviation of 36 grams. The heaviest 19% of fruits weigh more than how many grams? Give your answer to the nearest gram.
Answer:
Step-by-step explanation:
Given that:
mean (μ) = 476 grams, standard deviation (σ) = 36 grams. P(z) = 19%
The z score shows by how many standard deviation the raw score is above or below the mean. It is given by the equation:
[tex]z=\frac{x-\mu}{\sigma}[/tex]
Since the 19% weigh more, therefore 81% (100% - 19%) weigh less.
From the normal distribution table, the z score that corresponds to a probability of 81%(0.81) = 0.87
We substitute z = 0.88 in the z score equation to find the raw score. Therefore:
[tex]z=\frac{x-\mu}{\sigma}\\0.87=\frac{x-476}{36}\\ x-476=31.32\\x=31.32+476\\x=507.32\\[/tex]
x ≅ 507 grams
Therefore 19% of fruits weigh more than 507 grams
Help me with this question
Answer:
60
Step-by-step explanation:
In the function, the growth factor is "a", the base of the exponent. When the exponent is increased by 1, the value is multiplied by "a".
f(7) = a·f(6) = 4·15
f(7) = 60
_____
As you know, the exponent signifies repeated multiplication. So, an increase of 1 in the exponent means the base is part of the product one more time:
a^6 = a·a·a·a·a·a
a^7 = a·a·a·a·a·a·a = a·(a^6)
A production manager at a wall clock company wants to test their new wall clocks. The designer claims they have a mean life of 1515 years with a variance of 2525. If the claim is true, in a sample of 4141 wall clocks, what is the probability that the mean clock life would differ from the population mean by more than 0.40.4 years
Answer:
The correct answer will be "0.3043".
Step-by-step explanation:
The given values are:
[tex]\mu = 15[/tex]
[tex]n=41[/tex]
[tex]\sigma^2=25[/tex]
then,
[tex]\sigma=5[/tex]
If researchers know representative sample n > 30 and default deviation those who use z-test
∴ [tex]P(x>15.4)[/tex]
⇒ [tex]1-P(x<15.4)[/tex]
⇒ [tex]1-P(\frac{x-\mu}{\frac{\sigma}{\sqrt{n} } } <\frac{15.4-15}{\frac{5}{\sqrt{41} } } )[/tex]
⇒ [tex]1-P(Z<0.51225)[/tex]
⇒ [tex]1-0.695762[/tex]
⇒ [tex]0.3043[/tex]
Susan's friends Vicki, Luis, Maddy, Todd, Ron, and Geri have volunteered to help with the preparations for a party. How many ways can Susan assign someone to buy beverages
someone to arrange for food, and someone to send the invitations? Assume that no person does two jobs.
How many ways can Susan assign her volunteers?
ways
Answer:
120 ways
Step-by-step explanation:
She has 6 friends and needs 3 people to do jobs. This means that for the first job, she has 6 options for someone to buy beverages, but for the second job, she will now only have 5 options, as somebody is already buying beverages. After she assigns someone to the second job, she now has 4 people to pick from for the third job, as 2 are already doing a job. This means she has 6*5*4 ways to assign her volunteers, or 120 ways.
The table shows claims and their probabilities for an insurance company.
O A. (a)
O B. (a)
Amount of Claim
$0
$50,000
$100,000
$150,000
$200,000
$250,000
Probability
0.60
0.25
0.09
0.04
0.01
0.01
O c. (a) $
OD. (a) $
(a) Calculate the expected value.
(b) How much should the company charge as an average premium so that it breaks even on its claim
costs?
(c) How much should the company charge to make a profit of $60 per policy?
Answer:
a) Expected Value of Claims = $32,000
b) Average premium per claim, in order to break-even on claim costs
= $5,333.33
c) To make a profit of $60 per policy (i.e. a total profit of $360 ($60 x 6), it must charge:
= $5,393.33 per policy
Step-by-step explanation:
a) Data and Calculations:
Amount of Claim Probability Expected Value
$0 0.60 $0
$50,000 0.25 $12,500
$100,000 0.09 9,000
$150,000 0.04 6,000
$200,000 0.01 2,000
$250,000 0.01 2,500
Expected Cost of claims = $32,000
b) Average premium per claim, in order to break-even on claim costs
= Total Claim cost divided by number of policies
= $32,000/6 = $5,333.33
c) To make a profit of $60 per policy (i.e. a total profit of $360 ($60 x 6), it must charge:
Total Claim cost + Total profit / 6 or Average Premium plus Profit per policy =
= ($32,000 + $360)/6 or $5,333.33 + $60
= $32,360/6 or $5,393.33
= $5,393.33
The total expected value is $32000, the average premium so that it breaks even on its claim costs are $5333.33 and the company charge to make a profit of $60 per policy is $5393.33.
Given :
The table shows claims and their probabilities for an insurance company.
Amount of Claim Probability Expected Value
$0 0.60 0
$50000 0.25 $12500
$100000 0.09 $9000
$150000 0.04 $6000
$200000 0.01 $2000
$250000 0.01 $2500
A) So, the total expected value is = 12500 + 9000 + 6000 + 2000 + 2500
= $32000
B) The average premium is given by:
[tex]=\dfrac{32000}{6}[/tex]
= $5333.33
C) The company charge to make a profit of $60 per policy is:
[tex]= \dfrac{32000+360}{6}[/tex]
[tex]=\dfrac{32360}{6}[/tex]
= $5393.33
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find the area of the shaded region. 27.8 in and 150 degrees
Answer: 57769.8 in²
Let A be the area of the shaded region
We have a relation that can help us calculate its area
A= 0.5*(θ-sin(θ))*r² where r is the radius and θ the angle
A= 0.5*(150-sin(150°))* 27.8² =57769.79≈57769.8 in²
Answer:
818.4
Step-by-step explanation:
Which are the roots of the quadratic function f(b) = 62 – 75? Select two options.
b=573
Ob= -573
b=35
b= -35
Ob= 253
Answer:
[tex]b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}[/tex]
Step-by-step explanation:
Given
[tex]f(b) = b^2 - 75[/tex]
Required
Determine the roots
To get the root of the function, then f(b) must be 0;
i.e. f(b) = 0
So, the expression becomes
[tex]0 = b^2 - 75[/tex]
Add 75 to both sides
[tex]75 + 0 = b^2 - 75 + 75[/tex]
[tex]75 = b^2[/tex]
Take square roots of both sides
[tex]\sqrt{75} = \sqrt{b^2}[/tex]
[tex]\sqrt{75} = b[/tex]
Reorder
[tex]b = \sqrt{75}[/tex]
Expand 75 as a product of 25 and 3
[tex]b = \sqrt{25*3}[/tex]
Split the expression
[tex]b = \sqrt{25} *\sqrt{3}[/tex]
[tex]b = \±5 *\sqrt{3}[/tex]
[tex]b = \±5 \sqrt{3}[/tex]
[tex]b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}[/tex]
The options are not clear enough; however the roots of the equation are [tex]b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}[/tex]
adam had used 84 wihite squares 20 more white than yellow and 15 more red than yellow. what is the number of red squares adam used.
Answer:
Number of red squares used are 79.
Step-by-step explanation:
Given that Adam had used 84 white squares.
White squares used are 20 more than that of yellow.
Let yellow squares used = [tex]x[/tex]
([tex]x[/tex] + 20) is the number of white squares used.
Also given that 15 more red than yellow
So, Number of red squares used = [tex]x+15[/tex]
To find:
Number of red squares that Adam used.
Solution:
As per given statement:
White squares used =
[tex]x+20=84\\\Rightarrow x=64[/tex]
[tex]\therefore[/tex] Number of yellow squares used, [tex]x[/tex] = 64
Number of red squares = [tex]x + 15 = 64+15 =79[/tex]
So, Number of red squares used are 79.
This is not an incomplete question, it has come from a very reliable source, please dont delete. If 60% of the students in Mr. Bobby's class are bio majors, which of the following could be the total number of students in his class? 28 32 35 39 PLZHELPTHANKS
Answer:
35 students
Step-by-step explanation:
Take the number of students in the class and multiply by 60% and see if you get an integer number
28 * .60 =16.8 not an integer
32 * .6 =19.2
35 * .6 =21 yes
39*.6 =23.4
perform the indicated operations a. 3/10+6/10. b. 1/3+2/4+1/6. c. 5/6-3/6 d. 2/3-6/10 e. 4/10×3/7 f. 1/6x6/15 g. 1/8÷4/9 h. 1/5÷3/4
Answer:
A. [tex]\frac{9}{10}[/tex]
B. 1
C. [tex]\frac{2}{6}[/tex] or [tex]\frac{1}{3}[/tex]
D. [tex]\frac{2}{30}[/tex] or [tex]\frac{1}{15}[/tex]
E. [tex]\frac{12}{70}[/tex] or [tex]\frac{6}{35}[/tex]
F. [tex]\frac{6}{90}[/tex] or [tex]\frac{1}{15}[/tex]
G. [tex]\frac{9}{32}[/tex]
H. [tex]\frac{4}{15}[/tex]
Answer:
Step-by-step explanation:
Reducing the given expressions to the lowest terms:
A. 3/10 + 6/10:
B. 1/3 + 1/4 + 1/6:
C. 5/6-3/6:
D. 2/3-6/10:
E. 4/10*3/7:
F. 1/6*6/15:
G. 1/8 divided by 4/9:
H. 1/5 divided by 3/4:
Find the length of KC
Answer:
54
give me brainliest please please please and follow my page
Step-by-step explanation:
To find length of KC...we need to find the length of HM and MU first ...
so....HM= 96- 78 = 14
JU = 96 + HM = 96 + 14 = 110
....
KU = 110 - JK = 110 - 82 = 28
....
UN = 105+ 82 -( 96 + 14 )
187 - 110
= 77
UC = 77 - 51 = 26
KC = UC + KU = 26 + 28 = 54
The length of [tex]\overline{KC}[/tex] along line [tex]\overline{JN}[/tex] is given as 54 (Option A) See the computation below.
How do you compute the length of [tex]\overline{KC}[/tex]?To determine the length of [tex]\overline{KC}[/tex], the length of [tex]\overline{HM}[/tex] and [tex]\overline{MU}[/tex]must first be derived.
[tex]\overline{HM}[/tex] = 96 - 78
[tex]\overline{HM}[/tex] = 14
[tex]\overline{JU}[/tex] = 96 + [tex]\overline{HM}[/tex]
= 96 + 14
[tex]\overline{JU}[/tex]= 110
[tex]\overline{KU}[/tex] = 110 - [tex]\overline{JK}[/tex]
= 110 - 82
[tex]\overline{KU}[/tex]= 28
[tex]\overline{UN}[/tex] = 105+ 82 -( 96 + 14 )
=187 - 110
[tex]\overline{UN}[/tex]= 77
[tex]\overline{UC}[/tex] = 77 - 51
[tex]\overline{UC}[/tex]= 26
Thus,
[tex]\overline{KC}[/tex] = [tex]\overline{UC}[/tex] + [tex]\overline{KU}[/tex]
[tex]\overline{KC}[/tex]= 26 + 28
[tex]\overline{KC}[/tex]= 54
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A random variable X follows the uniform distribution with a lower limit of 720 and an upper limit of 920. a. Calculate the mean and the standard deviation of this distribution. (Round intermediate calculation for standard deviation to 4 decimal places and final answer to 2 decimal places.) Mean Standard deviation b. What is the probability that X is less than 870? (Do not round intermediate calculations. Round your answer to 2 decimal places.) Probability
(a) The support has length 920 - 720 = 200, so X has probability density
[tex]f_X(x)=\begin{cases}\frac1{200}&\text{for }720\le x\le920\\0&\text{otherwise}\end{cases}[/tex]
X has mean
[tex]E[X]=\displaystyle\int_{-\infty}^\infty xf_X(x)\,\mathrm dx=\frac1{200}\int_{720}^{920}x\,\mathrm dx=\boxed{820}[/tex]
and variance
[tex]V[X]=E[(X-E[X])^2]=E[X^2]-E[X]^2[/tex]
The second moment is
[tex]E[X^2]=\displaystyle\int_{-\infty}^\infty x^2f_X(x)\,\mathrm dx=\frac1{200}\int_{720}^{920}x^2\,\mathrm dx=\frac{2,027,200}3[/tex]
and so
[tex]V[X]=\dfrac{2,027,200}3-820^2=\dfrac{10,000}3[/tex]
The standard deviation is the square root of the variance, so
[tex]SD[X]=\sqrt{V[X]}=\sqrt{\dfrac{10,000}3}\approx\boxed{57.73}[/tex]
(b)
[tex]P(X<870)=\displaystyle\int_{-\infty}^{870}f_X(x)\,\mathrm dx=\frac1{200}\int_{720}^{870}\mathrm dx=\frac{870-720}{200}=\boxed{0.75}[/tex]
find an angle between 0 and 2π that is coterminal with -3π /10
Answer:
17π/10
Step-by-step explanation:
To find a co-terminal angle in a specific range, add or subtract multiples of 2π until you have an angle in the desired range. Here, you can add 2π.
-3π/10 +20π/10 = 17π/10 . . . . angle co-terminal with -3π/10
is -17 a natural number
━━━━━━━☆☆━━━━━━━
▹ Answer
-17 isn't a natural number
▹ Step-by-Step Explanation
Positive integers are only natural numbers, meaning negative numbers aren't natural numbers.
Hope this helps!
- CloutAnswers ❁
Brainliest is greatly appreciated!
━━━━━━━☆☆━━━━━━━
The sum of 9 distinct positive integers is 2009. Find the maximum possible value of the greatest common divisor of these 9 numbers.
Answer:
49
Step-by-step explanation:
The greatest common divisor of the addends must also be a divisor of 2009. That number can be factored as ...
2009 = 1×2009 = 7×287 = 41×49
The largest possible factor such that the other factor can be a sum of 9 positive integers is 49.
The maximum value of the GCD is 49.
Do the table and the equation represent the
same function?
y = 390 + 11(x)
Answer:
NO
Step-by-step explanation:
Try to replace x by -50 y= 390 + 11*(-50) = -160 in the table we have -210 so the table doesn't represent the equationa patient is taking 65 grams of medicine if it is increased by 20% how many grams are they taking
Answer:
78 grams
Step-by-step explanation:
20% is 1/5
1/5 of 65 is 13
65 + 13 = 78
brainliest?
Not sure how to graph this
Answer:
y=2x+6
Step-by-step explanation:
The slope is 2x and the y-intercept is 6. It is shown how to graph it in the attachment.
A taxi company charges $2.25 per ride plus $0.30 per mile. Enter a linear model represents the cost, C, as a function of d, the number of miles of the ride.
Answer:
C(d) = d(2.25) + m(0.3)
Step-by-step explanation:
A taxi company charges $2.25 per ride plus $0.30 per mile.
Let d represent number of rides..
Let m represent number of Miles...
Then let C represent the total cost for each ride at a specific number of Miles.
The linear model representing the cost as a function of d the total ride
C(d) = d(2.25) + m(0.3)
The values stand independently because the customer can choose a different right and a different mile.
need help asap! what is the value of x given that figure MNOP is a trapezoid with median QR
Answer:
x = 8
Step-by-step explanation:
To find the possible value of x in the given trapezoid MNOP with median QR, recall that one of the properties of a trapezoid is that the median length = ½ of the sum of the length of the parallel bases
Thus, ½ of [x + (3x + 8)] = 20
Let's find x
½*[x + (3x + 8)] = 20
½*[x + 3x + 8)] = 20
½*[4x +8] = 20
Multiply both sides by 2
4x + 8 = 20*2
4x + 8 = 40
Subtract 8 from both sides
4x = 40 - 8
4x = 32
Divide both sides by 4
x = 32/4
x = 8
Answer:
I think its 8 ♂️
Step-by-step explanation:
Charlotte is running at a rate of 9 (km)/(h) what is charlotte speed in (m)/(s)
Answer:
2.5 meters per second
Step-by-step explanation:
9x1000=9000m/h
9000/60/60=2.5m/s
Answer:
2.5 m/s
Step-by-step explanation:
convert kilometers to meters and then use a conversion calc to do the rest
Translate the English phrase into an algebraic expression: nine times the sum of n and one.
Travis bought $9.45 worth of 49-cent stamps and 21-cent stamps. The number of 21-cent stamps was 5 fewer than the number of 49-cent stamps. Solve the equation 0.49s+0.21(s−5)=9.45 for s to find the number of 49-cent stamps Travis bought.
Answer:
15 49-cent stamps
Step-by-step explanation:
We can solve this problem with the equations 0.49(x) + 0.21(y) = 9.45 and x - 5 = y. Well, 0.49(15) + 0.21(10) = 9.45, so we know that there are 15 49-cent stamps and 10 21-cent stamps. The question is asking for the number of 49-cent stamps, so we can tell Travis bought 15 49-cent stamps.
Hope this helps! Plz give me brainliest, it will help me achieve my next rank.
The number of 49-cent stamps that Travis bought given the equation is 15.
What he number of 49-cent stamps Travis bought?Given this equation: 0.49s+0.21(s−5)=9.45 take the following steps to determine the value of s
Expand the bracket: 0.49s + 0.21s - 1.05 = 9.45Combine similar terms : 0.49s + 0.21s = 9.45 + 1.05Add similar terms: 10.50 = 0.70sDivide both sides of the equation by 0.70: s = 15To learn more about mathematical equations, please check: https://brainly.com/question/26427570
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Adam tabulated the values for the average speeds on each day of his road trip as 60.5, 63.2, 54.7, 51.6, 72.3, 70.7, 67.2, and 65.4 mph. The sample standard deviation is 7.309. Adam reads that the average speed that cars drive on the highway is 65 mph. The t-test statistic for a two-sided test would be __________. Answer choices are rounded to the hundredths place.
Answer:
We accept null hypothesis
Step-by-step explanation:
We assume a normal distribution
The population mean μ₀ = 65 mph
Sample mean μ = 63,2 mph ( calculated from data )
Sample standard deviation σ = 7,309
Sample size n = 8
Degree of freedom is n - 1 8 - 1 = 7
As n < 30 we have to use the t-student test
We will do our test with a confidence interval of 95 % that means α = 5 %
or α = 0,05 and as we are going through a two-tail test α/2 = 0,025
Test Hypothesis:
Null Hypothesis: H₀ μ = μ₀
Alternate Hypothesis Hₐ μ ≠ μ₀
From t-student table for the degree of freedom 7, α/2 = 0,025 two-tail test we find tc
tc = 2,365
And calculate ts as
ts = ( μ - μ₀ ) / σ /√n
ts = ( 63,2 - 65 ) / 7,309/ √8
ts = - 1,8 *2,828/ 7,309
ts = - 5,091 /7,309
ts = - 06965
Now we compare ts and tc
tc = 2,365 or tc = - 2,365 ( by simmetry) tc = -2,37
and ts = -0,06965 ts = - 0,07
As |ts| < |tc|
ts is in the acceptance zone so we accept null hypothesis
Answer:
-0.70
Step-by-step explanation:
For the tabulated value the mean is calculated as:
Mean = (60.5 + 63.2 + 54.7 + 51.6 + 72.3 + 70.7 + 67.2 + 65.4)/8
= 505.6/8
Mean \bar{x}= 63.2
and population mean as assumption u= 65
and given that the sample standard deviation is: s= 7.309
The test statistic is calculated as:
Ζ = Τ –μ 63.2 - 65 = -0.696 -0.70 S
Hence the T statistic would be -0.70
which one doesn't belong? anything helps thx!!
Answer:
in 1,2 options they r in exponential form
in 4,option also, we can write it as xpower1/2 so this also in exponential form
but in third option y=x there is no exponential form
ABC trucking company realized that on an annual basis that distance traveled is normally distrubuted with a mean of 50,000 miles and a standard deviation of 12,000 HOw many miles will be traveled by at least 80% of the trucks
Answer:
39896 miles will be traveled by at least 80% of the trucks
Step-by-step explanation:
Given that :
the mean [tex]\mu[/tex] = 50000
standard deviation [tex]\sigma[/tex] = 12000
we are to calculate how many miles will be traveled by at least 80% of the trucks.
This implies that :
[tex]P(X > x_o) = 0.8[/tex]
Likewise;
[tex]P(X < x_o) = 1- P(X > x_o)[/tex]
[tex]P(X < x_o) = 1-0.8[/tex]
[tex]P(X < x_o) = 0.2[/tex]
We all know that
[tex]z = \dfrac{X- \mu}{\sigma}[/tex]
[tex]P(\dfrac{X- \mu}{\sigma}< \dfrac{x_o - \mu }{\sigma}) = 0.2[/tex]
[tex]P({z < \dfrac{x_o - \mu }{\sigma}) = 0.2[/tex]
Using the z table to determine the value for (invNorm (0.2)); we have ;
[tex]\dfrac{x_o - \mu }{\sigma} = invNorm (0.2)[/tex]
[tex]{x_o - \mu } = {\sigma} \times invNorm (0.2)[/tex]
[tex]{x_o } = \mu + {\sigma} \times invNorm (0.2)[/tex]
From z tables; [tex]invNorm (0.2)= -0.842[/tex]
[tex]{x_o } = 50000 + 12000 \times(-0.842)[/tex]
[tex]{x_o } = 50000 -10104[/tex]
[tex]\mathbf{{x_o } =39896}[/tex]
Thus; 39896 miles will be traveled by at least 80% of the trucks
Scott has eight CDs, and he picks two to take to work each day. How many different ways can Scott choose two CDs?
Answer:
The total number of ways to select 2 CDs from 8 CDs is 28.
in QRS, m Q = 70°, m R = 44", and m S = 66º. Which side of QRS is the shortest?
Answer:
QS
Step-by-step explanation:
The side opposite to the smallest angle must be the shortest side. The smallest angle is ∠R so the opposite side is QS.
Answer:
Hey there!
Smaller angles are opposite smaller sides, so the side opposite to angle R would be the shortest. (Or side SQ)
Hope this helps :)