Write a program that declares and initializes a variable representing the weight in milligrams from the keyboard. The program displays the equivalent weight in kilograms, grams, and milligrams. For example, 1050042 milligrams are equivalent to 1 kilogram, 50 grams, and 42 milligrams.

Answer:

weight = int(input("Enter weight in milligrams: "))

kilograms = int(weight / 1000000)

grams = int((weight - (kilograms * 1000000)) / 1000)

milligrams = weight - ((kilograms * 1000000) + (grams * 1000))

print("{} milligrams are equivalent to {} kilogram(s), {} gram(s), and {} milligram(s)".format(weight, kilograms, grams, milligrams))

Explanation:

*The code is in Python.

Ask the user to enter the weight and set it to the variable weight

Calculate the kilograms, divide the weight by 1000000 and cast the result to the int (If the weight is 1050042, kilograms would be 1050042/1000000 = 1)

Calculate the grams, subtract the kilograms from the weight, divide it by 1000 and cast the result to the int (If the weight is 1050042, grams would be int((1050042 - (1 * 1000000)) / 1000) = 50)

Calculate the milligrams, subtract the kilograms and grams from the weight (If the weight is 1050042, milligrams would be 1050042 - ((1 * 1000000) + (50 * 1000)) = 42)

Print the weight, kilograms, grams, and milligrams in the required format

In this exercise we have to use the knowledge of the python language to write the code, so we have to:

The code is in the attached photo.

Some important information informed in the statement that we have to use in the code is:

So to make it easier the code can be found at:

weight = int(input("Enter weight in milligrams: "))

kilograms = int(weight / 1000000)

grams = int((weight - (kilograms * 1000000)) / 1000)

milligrams = weight - ((kilograms * 1000000) + (grams * 1000))

print("{} milligrams are equivalent to {} kilogram(s), {} gram(s), and {} milligram(s)".format(weight, kilograms, grams, milligrams))

See more about python at brainly.com/question/26104476

#include
main()
{
int i, n=10, rem, inc=0;
scanf("%d",&n);
for(i=1; i =3)
inc++;
else;
inc--;
}
printf("Final Value=\n",inc);
}
SOLVE THIS PROGRAM...

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