Answer:
5.702 mol K₂SO₄
General Formulas and Concepts:
Atomic Structure
Reading a Periodic TableCompoundsMolesStoichiometry
Using Dimensional AnalysisExplanation:
Step 1: Define
[Given] 993.6 g K₂SO₄
[Solve] moles K₂SO₄
Step 2: Identify Conversions
[PT] Molar Mass of K: 39.10 g/mol
[PT] Molar Mass of S: 32.07 g/mol
[PT] Molar mass of O: 16.00 g/mol
Molar Mass of K₂SO₄: 2(39.10) + 32.07 + 4(16.00) = 174.27 g/mol
Step 3: Convert
[DA] Set up: [tex]\displaystyle 993.6 \ g \ K_2SO_4(\frac{1 \ mol \ K_2SO_4}{174.27 \ g \ K_2SO_4})[/tex][DA] Divide [Cancel out units]: [tex]\displaystyle 5.7015 \ mol \ K_2SO_4[/tex]Step 4: Check
Follow sig fig rules and round. We are given 4 sig figs.
5.7015 mol K₂SO₄ ≈ 5.702 mol K₂SO₄
Using the balanced equation for the next few questions: 4 Fe(s) + 30 (9) - 2Fe2O3(s)
How many moles of Iron (11) Oxide would be produced by complete reaction of 0.15
moles of iron? (Be sure to show your work including the mole ratio you used)
Answer:
0.075 moles of iron oxide would be produced by complete reaction of 0.15 moles of iron.
Explanation:
The balanced reaction is:
4 Fe + 3 O₂ → 2 Fe₂O₃
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Fe: 4 molesO₂: 3 molesFe₂O₃: 2 molesYou can apply the following rule of three: if by stoichiometry 4 moles of Fe produce 2 moles of Fe₂O₃, 0.15 moles of Fe produce how many moles of Fe₂O₃?
[tex]moles of Fe_{2} O_{3} =\frac{0.15 moles of Fe*2 moles of Fe_{2} O_{3} }{4 moles of Fe}[/tex]
moles of Fe₂O₃= 0.075
0.075 moles of iron oxide would be produced by complete reaction of 0.15 moles of iron.
Can animals and plants adapt to climate changes?
Answer:
Yes but will take a very very long time for them to adapt most will die but as gemeration passes they will get used to it
COULD SOMEONE PLEASE GIVE ME THE ANSWER FOR THIS NO BOTS PLEASEEE TODAY IS THE LAST DAY FOR MISSING WORK!!!!
Answer:
:D
Explanation:
8. D. All of the above
9. C. Mechanical weathering
10. D. All of the above
Answer:
8. D
9. A
10. D
All of the following describe the unique role of water except-
Water is polar and cannot dissolve nonpolar compounds such as oil
Water is considered a universal solvent because it can dissolve more substances than any other liquid.
Water is nonpolar and can dissolve nonpolar compounds such as oil
Water has the ability to form hydrogen bonds
Mendel crossed tall pea plants with short pea plants. the offspring were all tall plants.
1. Which allele is recessive?
2. Which allele is dominant?

please hurry

Answer:
1. Allele for shortness (t)
2. Allele for tallness (T)
Explanation:
Gregor Mendel performed numerous experiments using pea plants (Pisium sativum). He tested the height traits of pea plants by crossing tall pea plants (TT) and short pea plants (tt) to obtain offsprings that were all tall (Tt) in the first filial generation (F1).
This is possible because the allele for tallness is DOMINANT while the allele for shortness is RECESSIVE. This means that tallness allele (T) will mask the phenotypic expression of shortness allele (t) when in an heterozygous state (Tt) as in the F1 generation.
Which of the following is a property of carbon atoms?
They are chemically inert.
They have six valence electrons.
They readily give up two electrons
They are found in all living things.
They are found in all living things. Hence, option D is correct.
What is an atom?An atom is any particle of matter which contains at least one proton.
Carbon is stored in plants and trees. Plants take carbon dioxide from the atmosphere to make the building blocks of food during photosynthesis. Carbon is stored in the hydrosphere and dissolved in ocean water and lakes. Carbon is used by several organisms to produce shells.
Hence, option D is correct.
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You can prepare a buffer solution by combining equal moles of which pair of substances?
A. weak acid and its conjugate base
B. strong acid and a strong base
C. strong base and its conjugate acid
D. salt and a weak acid
Answer:
A. weak acid and its conjugate base
Explanation:
A buffer solution can be made with a weak acid and conjugate base or a weak base and conjugate acid.
This may help you:
https://chem.libretexts.org/Bookshelves/Physical_and_Theoretical_Chemistry_Textbook_Maps/Supplemental_Modules_(Physical_and_Theoretical_Chemistry)/Acids_and_Bases/Buffers/Introduction_to_Buffers
Answer question in picture
(D)
Explanation:
On the left side two molecules, each made of 2 grays and 3 blues, which suggests that only (D) offers the right combination: 2 Al atoms and 3 O atoms that make up Al2O3.
Please show your work if possible!
Answer:
54.93 g/mol
Explanation:
a) the element with symbol Mn is known as Manganese and I figured it out by looking at the periodic table.
b) I took a look at the periodic table again, and seen how much the atomic mass is and from there I observed:
Mn= 54.938 g/mol
rounded is 54.94 g/mol
At 289 K, a sample of gas has a volume of 42.0 cm3. What volume does the gas occupy at 342 K? (12.5 Points)
Answer: [tex]49.7\ cm^3[/tex]
Explanation:
Given
At temperature [tex]T_1=289\ K[/tex]
Volume is [tex]V_1=42\ cm^3[/tex]
and the temperature changes to [tex]T_2=342\ K[/tex]
At this temperature volume is [tex]V_2[/tex]
Consider Pressure remains the constant
[tex]\therefore \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\\Rightarrow V_2=V_1\times \dfrac{T_2}{T_1}\\\\\text{Insert values}\\\\\Rightarrow V_2=42\times \dfrac{342}{289}\\\\\Rightarrow V_2=49.7\ cm^3[/tex]
The volume at this temperature is [tex]49.7\ cm^3[/tex]
Planets X and Y orbit each other in space. Which changes would have the greatest effect on increasing the gravitational attraction between the two planets?
Group of answer choices
Halving the mass of planet X and doubling the distance between the planets
Halving the mass of planet X and halving the distance between the planets
Doubling the mass of planet X and halving the distance between the planets
Doubling the mass of planet X and doubling the distance between the planets
Answer:
halving, the mass of planet X and halving the distance between the planets
The gravitational force of attraction is the fundamental force of the universe. Doubling the mass of planet X and halving the distance between the planets increases the gravitational attraction. The correct option is C.
What is gravitational attraction?The force of attraction between any two bodies is directly proportional to the product of their masses and is inversely proportional to the square of the distance between them. The formula of gravitational force is given as:
F = G m₁m₂ / r²
From the equation it is clear that the gravitational force increases with the increase in the mass and decreases with the increase in the distance between the objects. This law is true for each particle of matter, each particle of matter attracts every other particles.
Here doubling the mass of planet X and halving the distance between the planets increases the gravitational attractive force.
Thus the correct option is C.
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Answer is C
Zeke is attempting to react a piece of magnesium metal with sulfuric acid. The sulfuric acid is a 5M solution. What could Zeke do
to slow down the rate at which the magnesium will react with the acid?
A)
increase the temperature
B)
add a 10M sulfuric acid solution
9)
add water to the acid to decrease its molarity
D)
add more of the 5M sulfuric acid to the reaction
Answer:
c)
Explanation:
add water to the acid to decrease its molarity
Need help on this question asap please please I’m going to really appreciate it
Answer:
0.11 moles
Explanation:
The equation of the reaction is;
2SO2 + O2 ------>2SO3
Number of moles of O2 in 3.42 g = 3.42g/32 g/mol = 0.11 moles
Hence, 0.11 moles of O2 is consumed when 3.42 g of O2 reacts with SO2 to form SO3.
What is the mole fraction of ethanol (C2H5OH) in a solution of 47.5 g of ethanol in 850 g of water?
Answer:
0.021
Explanation:
that's the answer because I just did an exam that included this question and then the miss explained to me why this was the answer, but don't worry am 100% sure the answer is 0.021 .
The mole fraction of ethanol in a solution of 47.5 g of ethanol in 850 g of water is 0.021.
How we calculate the mole fraction?Mole fraction of any substance present in solution will be calculted by dividing the moles of sample to the total moles of solution.
Moles will be calculated as:
n = W/M , where
W = given mass
M = molar mass
Moles of ethanol will be calculated as:
n = 47.5g / 46.07g/mol = 1.03 moles
Moles of water will be calculated as:
850g / 18g/mol = 47.18 moles
Total moles of solution = 1.03 + 47.18 = 48.21 moles
Mole fraction of ethanol in water will be calculated as:
mole fraction = 1.03 / 48.21 = 0.021
Hence, mole fraction is 0.021.
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Which of the following correctly describes a weak acid?
O It completely ionizes.
0 It produces hydroxide ions.
O It partially ionizes.
O It produces hydronium ions that are less effective than those from strong acids.
Answer:
It partially ionizes
Explanation:
Higher tier) Weak acids only partially ionise in water. Only a small fraction of their molecules break into hydrogen ions when added to water.
2C2H2 + 5O2 → 4CO2 + 2H2O
Which of the following statements would be correct if one mole of C2H2 was used in this reaction? (5 points)
a
One mole of oxygen was used in this reaction.
b
Five moles of oxygen were used in this reaction.
c
Four moles of carbon dioxide were produced from this reaction.
d
Two moles of carbon dioxide were produced from this reaction.
Answer:
d. Two moles of carbon dioxide were produced from this reaction
Explanation:
The given chemical reaction can be written as follows;
2C₂H₂ + 5O₂ → 4CO₂ + 2H₂O
From the above chemical reaction, we have;
Two moles of C₂H₂ reacts with five moles of O₂ to produce four moles of CO₂ and two moles of H₂O
We have;
One mole of C₂H₂ will react with two and half moles of O₂ to produce two moles of CO₂ and one mole of H₂O
Therefore, in the above reaction, when one mole of C₂H₂ is used, two moles of CO₂ will be produced.
To calculate the percentage of people who have a particular allele population studies are conducted to collect data.true or false
What does all matter have in common?
A.
It is made up of atoms.
B.
It is made up of molecules.
C.
It is all solid.
D.
It is too small to see.
Write a balanced equation out of these chemicals
Answer:
2Na + 2H20--> 2NaOH+H2
............. this is the ans
A 35 L tank of oxygen is at 315 K with an internal pressure of 190 atmospheres. How
many moles of gas does the tank contain?
Answer:
600.7 moles
Explanation:
Applying,
PV = nRT................... Equation 1
Where P = Pressure of oxygen, V = Volume of oxygen, n = number of moles, R = molar gas constant, T = Temperature.
make n the subject of the equation
n = PV/RT............... Equation 2
From the question,
Given: P = 190 atm, V = 35 L, T = 135 K
Constant: R = 0.082 atm.dm³/K.mol
Substitute these values into equation 2
n = (190×35)/(135×0.082)
n = 600.7 moles of xygen
If you want to eat foods that contain less additives, what could you do?
A.
Stay away from packaged foods.
B.
Stay away from fresh fruits and vegetables.
Answer: the answer is a
Explanation:
always eat fresh fruits and veggiies.
Explain to the people of Westfield what is in their water.
The presence of rust in the water of Westfield is the reason for the change in colour.
Reason for reddish colour of waterThe water of Westfield has reddish-brown substance. This reddish brown substance in the water is the rust which formed due to the chemical reaction between the iron pipes and the fertilizer substance present in the water.
Due to this reaction, the colour of Westfield's water is different from normal type of water so we can conclude that the presence of rust in the water of Westfield is the reason for the change in colour.
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I can't seem to figure out how to set up charts so there's just a screenshot of the question in the file attached :) Thank's for any help!!
Answer:
See Explanation
Explanation:
Volume of base used = (31.79 - 1.6) + (32.12 - 0.98) + (42.87 -13.21)/3 = 30.34 cm3
Volume of acid used = (24.86 - 0.42) + (24.11 - 0.11) + (27.67 -3.42)/3 = 24.23 cm3
For trial 1= number of moles of HBr = 24.44/1000 * 0.3 = 0.0073 moles
For trial 2= number of moles of HBr = 24/1000 * 0.3 = 0.0072 moles
For trial 3= number of moles of HBr = 0.0089 moles
HBr(aq) + KOH(aq) -----> KBr(aq) + H2O(l)
One mole of base is required to neutralize one mole of acid.
From CAVA/CBVB =nA/nB
CAVAnB = CBVBnA
CB = CAVAnB/VBnA
CB = 0.3 * 24.23 * 1/30.34 * 1
CB = 0.24 moldm-3
number of moles of KOH = concentration * volume
number of moles = mass/molar mass
molar mass of KOH = 56 g/mol
mass/56 = 0.24 * 30.34/1000
mass = 0.24 * 30.34/1000 * 56
mass =0.408 g of KOH
When the temperature of the water was 10°C the waterweed did not produce bubbles.
Suzi increased the temperature of the water in the water-bath to 20°C. The waterweed started to produce bubbles.
She waited two minutes before starting to count the bubbles.
Explain why she waited for two minutes before she started to count the bubbles.
Science
Explanation:
she could waited for the saturated vapour pressure to equal the prevailing atmospheric pressure
ergo boiling to take place seeing as she had gotten the first indication that boiling had started
If two half lives have passed since a scientist collected a 1.00- gram sample of a U-235, how much U-235 is left now?
answers for most finals chem test questions (10th)
Answer:
one quarter of the original amount, so 0.25 g
Explanation:
Answer:
C
Explanation:
Prokaryotic and eukaryotic cells have many different characteristics. One difference
between prokaryotic and eukaryotic cells is that all eukaryotic cells —
Answer:
Have a nucleus
Explanation:
Pls check..
a deep underground cavern contains 2.24 x 10^6 L of methane (CH4) gas at a pressure of 15.0 atm and a temperature of 42 C. How many moles of methane does this natural gas deposit contain?
Answer:
This natural gas deposit contains 1,300,813.008 moles.
Explanation:
An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.
An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:
P * V = n * R * T
In this case:
P= 15 atmV=2.24*10⁶ Ln= ?R= 0.082 [tex]\frac{atm*L}{mol*K}[/tex]T= 42 C= 315 K (being 0 C= 273 K)Replacing:
15 atm* 2.24*10⁶ L= n*0.082 [tex]\frac{atm*L}{mol*K}[/tex]* 315 K
Solving:
[tex]n=\frac{15 atm* 2.24*10^{6}L }{0.082\frac{atm*L}{mol*K}*315 K}[/tex]
n=1,300,813.008 moles
This natural gas deposit contains 1,300,813.008 moles.
Na+ and P-3 whats the formula and whats the name of it
Answer:
sodium phosphide!!!!!!!!!!!!!!!
2. Find the Volume of 3.00 mol of gas whose temperature is 60.0 C and whose pressure is 5.00 L.
3. Find the tempature of 1.50 mol of gas whose pressure is 4.00 atm and whose volume is 7.50L
4. Find the number of moles of a certain ideal gas whose volume, tempature and pressure are 3.00 L, 25.0, and 2.00 atm, respectively
Please show work I will give you a 5 star review and much points
Answer:
2. 16.4 L
3. 243.6K
4. 0.25mol
Explanation:
Using the ideal gas formula for the series of questions in this case, we have;
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (K)
QUESTION 2:
V = ?
P = 5 atm
n = 3 mol
T = 60°C = 60 + 273 = 333K
PV = nRT
5 × V = 3 × 0.0821 × 333
5V = 82.02
V = 82.02/5
V = 16.4 L
QUESTION 3:
P = 4 atm
V = 7.5L
n = 1.5mol
T = ?
PV = nRT
4 × 7.5 = 1.5 × 0.0821 × T
30 = 0.123T
T = 30/0.123
T = 243.6K
QUESTION 4:
P = 2.00 atm
V = 3L
n = ?
T = 25°C = 25 + 273 = 298K
PV = nRT
2 × 3 = n × 0.0821 × 298
6 = 24.47n
n = 6/24.47
n = 0.25mol
What set of coefficients will balance the chemical equation: _NaBr (aq) + _H3PO4 (aq) → _Na3PO4(aq) + _HBr (aq)
A. 3,1,1,3
B. 1,2,3,1
C. 3,1,3,1
D. 1,1,3,3
The Balanced chemical equation for above reaction will be :
[tex] \small{ \mathrm{3NaBr + H_3PO_4 \rightarrow Na_3PO_4 + 3HBr}}[/tex]
The Coefficients will be :
[tex]NaBr - 3[/tex][tex]H_3PO_4 - 1[/tex][tex]Na_3PO_4 - 1[/tex][tex]HBr - 3 [/tex]So, Correct option is :
A. 3, 1, 1, 3
_____________________________
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