Will give brainliest answer

Answer:

95.44% probability that the sample proportion will differ from the population proportion by less than 0.03.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

In this question:

[tex]p = 0.05, n = 212, \mu = 0.05, s = \sqrt{\frac{0.05*0.95}{212}} = 0.015[/tex]

What is the probability that the sample proportion will differ from the population proportion by less than 0.03?

This is the pvalue of Z when X = 0.03 + 0.05 = 0.08 subtracted by the pvalue of Z when X = 0.05 - 0.03 = 0.02. So

X = 0.08

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.08 - 0.05}{0.015}[/tex]

[tex]Z = 2[/tex]

[tex]Z = 2[/tex] has a pvalue of 0.9772

X = 0.02

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.02 - 0.05}{0.015}[/tex]

[tex]Z = -2[/tex]

[tex]Z = -2[/tex] has a pvalue of 0.0228

0.9772 - 0.0228 = 0.9544

95.44% probability that the sample proportion will differ from the population proportion by less than 0.03.

Answer:

The minimum value of the bill that is greater than 95% of the bills is $37.87.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

[tex]\mu = 28, \sigma = 6[/tex]

What are the minimum value of the bill that is greater than 95% of the bills?

This is the 95th percentile, which is X when Z has a pvalue of 0.95. So X when Z = 1.645.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]1.645 = \frac{X - 28}{6}[/tex]

[tex]X - 28 = 6*1.645[/tex]

[tex]X = 37.87[/tex]

The minimum value of the bill that is greater than 95% of the bills is $37.87.

Answer:

The sampled populations have equal variances

Step-by-step explanation:

ANOVA which is fully known as Analysis of variances can be defined as the collection of statistical models as well as their associated estimation procedures which enables easily and effectively analyzis of the differences among various group means in a sample reason been that ANOVA is a total variance in which the observed variance in a specific variable is been separated into components which are attributable to various sources of variation which is why ANOVA help to provides a statistical test to check whether two or more population means are equal.

Therefore the required condition for using an ANOVA procedure on data from several populations for mean comparison is that THE SAMPLED POPULATION HAVE EQUAL VARIANCE.

The limit lim x → 3 (x^3 - 4x + 3) = 18, the largest possible values of δ that correspond to ε = 0.2 and ε = 0.1 are approximately δ = 0.5 and δ = 0.2, respectively.

To find the largest possible values of δ corresponding to ε = 0.2 and ε = 0.1 for the given limit, we need to use the definition of a limit and manipulate the expression until we isolate δ.

The definition of a limit states that for any ε > 0, there exists a δ > 0 such that if 0 < |x - 3| < δ, then |(x^3 - 4x + 3) - 18| < ε.

Let's work through the calculations for ε = 0.2:

|(x^3 - 4x + 3) - 18| < 0.2

Simplifying the expression within the absolute value:

|x^3 - 4x - 15| < 0.2

To find the largest possible value of δ, we want to determine the maximum distance between the function and the limit value of 18 within the given tolerance ε = 0.2.

Using a graphing calculator, we can plot the function f(x) = x^3 - 4x + 3 and observe the values of x for which |f(x) - 18| < 0.2. By analyzing the graph, we can find the largest possible interval around x = 3 that satisfies this condition.

By observing the graph, it appears that for ε = 0.2, the largest possible value of δ is approximately 0.5.

Now let's repeat the process for ε = 0.1:

|(x^3 - 4x + 3) - 18| < 0.1

|x^3 - 4x - 15| < 0.1

Using the same approach as before, we can graph the function f(x) = x^3 - 4x + 3 and identify the largest possible interval around x = 3 where |f(x) - 18| < 0.1.

Based on the graph, it seems that for ε = 0.1, the largest possible value of δ is approximately 0.2.

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Answer:

The probability of spending between 4 and 7 days in recovery

P(4≤x≤7) = 0.5445

Step-by-step explanation:

Step(i):-

Given mean of the Population μ = 5.3 days

Given standard deviation of the population 'σ' = 2 days

Let 'X' be the random variable in normal distribution

Let    x₁ = 4

[tex]Z_{1} = \frac{x_{1}-mean }{S.D} = \frac{4-5.3}{2} = -0.65[/tex]

Let    x₂ = 7

[tex]Z_{2} = \frac{x_{2}-mean }{S.D} = \frac{7-5.3}{2} = 0.85[/tex]

Step(ii):-

The probability of spending between 4 and 7 days in recovery

P(4≤x≤7) = P(-0.65≤Z≤0.85)

             =  P(Z≤0.85) - P(Z≤-0.65)

            = 0.5 + A( 0.85) - ( 0.5 - A(-0.65)

            = 0.5 + A( 0.85) -  0.5 +A(0.65)   ( ∵A(-0.65) = A(0.65)

           =   A(0.85) + A(0.65)

          = 0.3023 + 0.2422

         = 0.5445

Final answer:-

The probability of spending between 4 and 7 days in recovery

P(4≤x≤7) = 0.5445

Answer:

see below

Step-by-step explanation:

Slope intercept form is y = mx+b where m is the slope and b is the y intercept

4x - 3y = 12

Solve for y

Subtract 4x from each side

4x-4x - 3y =-4x+ 12

-3y = -4x+12

Divide by -3

-3y/-3 = -4x/-3 + 12/-3

y = 4/3x -4

The slope is 4/3 and the y intercept is -4

The slope is Positive

Answer:

-2x + y = -1.

Step-by-step explanation:

The slope of the line = rise / run

= (11-9) / (6-5) = 2.

The point-slope form of the line is

y - y1 = 2(x - x1) where (x1, y1) is a point on the line so we have:

y - 11 = 2(x - 6)     ( using the point  (6, 11)

y = 2x - 12 + 11

y = 2x - 1

Convert to standard form:

-2x + y = -1.

Answer:

Terms:

1) = 7/3

2) = -7/9

3) = 7/27

4) = -7/81

Step-by-step explanation:

Your question did not state the equation of f(x), however; assuming f(x) = 7/(1+x)  ,....... at  a = 2

see solution attached then use it to work your f(x)

Answer:

The probability of the plants being tall is equal to P(TT) + P(Tt)= 1/4+1/2=3/4

Step-by-step explanation:

Hello!

The characteristic "height" of a plant is determined by the alleles "tall" T (dominant) and "short" a (recessive). If both parents are Tt, you have to calculate the probability of the offspring being tall (TT or Tt)

To construct the Punnet square you have to make a table, where the parental alleles will be in the margins, for example: the father's alleles in the columns and the mother's alleles in the rows.

Each parent will produce a haploid gamete that will carry one of the alleles, so the probability for the offspring receiving one of the alleles is 1/2

Father (Tt): gametes will carry either the dominant allele T or the recessive allele t with equal probability 1/2

Mother (Tt): gametes will also carry either the dominant allele T or the recessive allele t with equal probability 1/2

Then you have to cross each allele to determine all possible outcomes for the offsprings. For each cell, the probability of obtaining both alleles will be the product of the probability of each allele (See attachment)

First combination, the offspring will receive one dominant allele from his father and one dominant allele from his mother: TT, the probability of obtaining an offspring with this genotype will be P(T) * P(T) = 1/2*1/2=1/4

Second combination, the offspring will receive the recessive allele from the father and the dominant allele from the mother, then its genotype till be tT with probability: P(t)*P(T)= 1/2*1/2=1/4

Third combination, the offspring will receive one dominant allele from his father and one recessive allele from his mother, the resulting genotype will be Tt with probability: P(T)*P(t)= 1/2*1/2=1/4

Combination, the offspring will receive both recessive alleles from his parents, the resulting genotype will be tt with probability: P(t)*P(t)= 1/2*1/2=1/4

So there are three possible genotypes for the next generation:

TT with probability P(TT)= 1/4

Tt with probability: P(Tt)+P(tT)=1/4+1/4=1/2⇒ This genotype is observed twice so you have to add them.

tt with probability P(tt)= 1/4

Assuming this genotype shows complete dominance, you'll observe the characteristic "Tall" in individuals that carry the dominant allele "T", i.e. individuals with genotype "TT" and "Tt"

So the probability of the plants being tall is equal to P(TT) + P(Tt)= 1/4+1/2=3/4

I hope this helps!

Answer:

D

Step-by-step explanation:

The numbers that are less than 0 are negative. Negative numbers have the "-" sign in front of them so the answer is D.

Answer:

d

Step-by-step explanation:

The other ones will always be positive four

Answer:

(4.75, 2.5), (-0.35, -7.7), (0.4, -6.2)

Step-by-step explanation:

Given the line

[tex]y = 2x- 7[/tex]

Given the missing coordinates:

(4.75, )

(, –7.7)

(0.4, )

We know that every coordinate is of the form [tex](x,y)[/tex].

So, we can easily solve the for other variable if one variable is given from the given line using the graph or the given equation.

For the first coordinate:

(4.75, )

From graph it can be found that y = 2.5

Verifying using the equation.

Putting the value of x = 4.75 in the equation we get:

y = 2[tex]\times[/tex] 4.75 - 7

y = 9.5 - 7 = 2.5

So, the coordinate is  (4.75, 2.5)

For the second coordinate:

(, -7.7 )

From graph it can be found that x = -0.35

Verifying using the equation:

Putting the value of y = -7.7 in the equation we get:

-7.7 = 2x - 7

2x = -7.7 + 7 = -0.7

x = -0.35

So, the coordinate is  (-0.35, -7.7).

For the third coordinate:

(0.4, )

From graph it can be found that y = -6.2

Verifying using the equation.

Putting the value of x = 0.4 in the equation we get:

y = 2[tex]\times[/tex] 0.4 - 7

y = 0.8 - 7 = -6.2

So, the coordinate is  (0.4, -6.2)

Also, please refer to the attached graph.

So, the answer is:

(4.75, 2.5), (-0.35, -7.7), (0.4, -6.2)

Answer: its 2.5, -0.35, -6.2

Step-by-step explanation: in easier words

Answer:

  5 feet

Step-by-step explanation:

"Twice as tall" means "2 times as tall".

  2 × (2 1/2 ft) = (2 × 2 ft) +(2 × (1/2 ft)) = 4 ft + 1 ft = 5 ft

The child's mother is 5 feet tall.

Answer:

The mother is 5ft tall

Step-by-step explanation:

2 1/2 + 2 1/2 = 5ft

2ft+2ft = 4ft

1/2+1/2= 1ft

4ft+1ft = 5ft

Answer:

Each table is $6 and each chair is $2.50

Step-by-step explanation:

Answer:

a) Null and alternative hypothesis:

[tex]H_0: \pi=0.1\\\\H_a:\pi>0.1[/tex]

b) A Type I error is made when a true null hypothesis is rejected. In this case, it would mean a conclusion that the proportion is significantly bigger than 10%, when in fact it is not.

c) The consequences would be that they would be more optimistic than they should about the result of the investment, expecting a proportion of students that is bigger than the true population proportion.

d) A Type II error is made when a false null hypothesis is failed to be rejected. This would mean that, although the proportion is significantly bigger than 10%, there is no enough evidence and it is concluded erroneously that the proportion is not significantly bigger than 10%

e) The consequences would be that the investment may not be made, even when the results would have been more positive than expected from the conclusion of the hypothesis test.

Step-by-step explanation:

a) The hypothesis should be carried to test if the proportion of students that would eat there at least once a week is significantly higher than 10%.

Then, the alternative or spectulative hypothesis will state this claim: that the population proportion is significantly bigger than 10%.

On the contrary, the null hypothesis will state that this proportion is not significantly higher than 10%.

This can be written as:

[tex]H_0: \pi=0.1\\\\H_a:\pi>0.1[/tex]

Answer:

The standard error for the difference in proportions of males and females who use public transportation every working day is 0.015.

The conditions are met.

Step-by-step explanation:

The sample 1 (males), of size n1=2570 has a proportion of p1=0.389.

[tex]p_1=X_1/n_1=1000/2570=0.389[/tex]

The sample 2 (females), of size n2=2055 has a proportion of p2=0.745.

[tex]p_2=X_2/n_2=1532/2055=0.745[/tex]

The difference between proportions is (p1-p2)=-0.356.

[tex]p_d=p_1-p_2=0.389-0.745=-0.356[/tex]

The pooled proportion, needed to calculate the standard error, is:

[tex]p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{1000+1532}{2570+2055}=\dfrac{2532}{4625}=0.547[/tex]

The estimated standard error of the difference between means is computed using the formula:

[tex]s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.547*0.453}{2570}+\dfrac{0.547*0.453}{2055}}\\\\\\s_{p1-p2}=\sqrt{0.000096+0.000121}=\sqrt{0.000217}=0.015[/tex]

Conditions for a normal distribution approximation:

The expected number of "failures" or "successes", whichever is smaller, has to be larger than 10.

For the males sample, we have p=0.389 and (1-p)=0.611. The sample size is n=2570, so we take the smallest proportion and chek the condition:

[tex]n\cdot p=2570\cdot 0.389=999>10[/tex]

For the females sample, we have p=0.745 and (1-p)=0.255. The sample size is n=2055, so we take the smallest proportion and chek the condition:

[tex]n\cdot (1-p)=2055\cdot 0.255=524>10[/tex]

The conditions are met.

Answer:

(a)$29.95

(b)A

Step-by-step explanation:

The​ cost, in​ dollars, of producing x cellphone cases is given by:

[tex]C(x)=-0.05 x^2+55 x.[/tex]

We are required to evaluate: [tex]\dfrac{C(251)-C(250)}{251-250}[/tex]

[tex]C(251)=-0.05(251)^2+55(251)=10654.95\\C(250)=-0.05(250)^2+55(250)=10625\\\text{Therefore:}\\\\\dfrac{10654.95-10625}{251-250}=29.95[/tex]

[tex]\dfrac{C(251)-C(250)}{251-250}=\$29.95[/tex]

The value calculated above represents the additional cost to produce one more item after making 250 items.

Split up the interval [0, 3] into 6 subintervals,

[0, 1/2], [1/2, 1], [1, 3/2], [3/2, 2], [2, 5/2], [5/2, 3]

The right endpoints are given by the arithmetic sequence,

[tex]r_i=0+\dfrac i2=\dfrac i2[/tex]

with [tex]1\le i\le6[/tex].

We approximate the integral of [tex]f(x)[/tex] on the interval [0, 3] by the Riemann sum,

[tex]\displaystyle\int_0^3f(x)\,\mathrm dx=\sum_{i=1}^6f(r_i)\Delta x_i[/tex]

[tex]\displaystyle=\frac{3-0}6\sum_{i=1}^6\left(3{r_i}^2-8r_i\right)[/tex]

[tex]\displaystyle=\frac12\sum_{i=1}^6\left(\frac{3i^2}4-4i\right)[/tex]

[tex]\displaystyle=\frac38\sum_{i=1}^6i^2-2\sum_{i=1}^6i[/tex]

Recall the formulas,

[tex]\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2[/tex]

[tex]\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6[/tex]

Then the value of the integral is approximately

[tex]\displaystyle=\frac38\cdot\frac{6\cdot7\cdot13}6-2\cdot\frac{6\cdot7}2=\boxed{-\frac{63}8}=-7.875[/tex]

Compare to the exact value of the integral, -9.

The Riemann sum of [tex]f(x) = 3\cdot x^{2}-8\cdot x[/tex] with [tex]n = 6[/tex] is [tex]-\frac{63}{8}[/tex].

The formula for the right Riemann sum is described below:

[tex]S = \frac{b-a}{n} \cdot \Sigma\limit_{i= 1}^{n} \,f(x+i\cdot \frac{b-a}{n} )[/tex] (1)

Where:

If we know that [tex]f(x) = 3\cdot x^{2}-8\cdot x[/tex], [tex]a = 0[/tex], [tex]b = 3[/tex] and [tex]n = 6[/tex], then the Riemann sum is:

[tex]S = \frac{3-0}{6}\cdot [f(0.5) + f(1) + f(1.5) + f(2) + f(2.5) +f(3)][/tex]

[tex]S = \frac{1}{2}\cdot \left(-\frac{13}{4}-5-\frac{21}{4}-4-\frac{5}{4}+3\right)[/tex]

[tex]S = -\frac{63}{8}[/tex]

The Riemann sum of [tex]f(x) = 3\cdot x^{2}-8\cdot x[/tex] with [tex]n = 6[/tex] is [tex]-\frac{63}{8}[/tex].

We kindly invite to check this question on Riemann sum: https://brainly.com/question/23960718

This question was not properly written, hence it is incomplete. The complete question is written below:

Complete Question:

Abigail and Liza work as carpenters for different companies. Abigail earns $20 per hour at her company and Liza earns $25 per hour at her company. Last week, Abigail and Liza worked for a total of 30 hours and together earned a total of $690. How many hours did Liza work last week?

Answer:

Lisa worked for 18 hours last week

Step-by-step explanation:

Let the number of hours Abigail worked last week = A

Let the number of hours Liza worked last week = B

Abigail earns = $20 per hour at her company

Liza earns = $25 per hour at her company

A + B = 30 ........... Equation 1

B = 30 - A

20 × A + 25 × B = 690

20A + 25B = 690 ............... Equation 2

Substitute 30 - A for B in Equation 2

Hence, we have:

20A + 25(30 - A) = 690

20A + 750 - 25A = 690

Collect like terms

20A - 25A = 690 - 750

-5A = -60

A = -60/-5

A = 12

Since A represents the number of hours Abigail worked, Abigail worked for 12 hours last week.

Substitute 12 for A in Equation 1

A + B = 30

12 + B = 30

B = 30 - 12

B = 18

Since B represents the number of hours Liza worked, therefore, Liza worked for 18 hours last week.

Answer: 111=11

Step-by-step explanation: PEMDAS

(55.5 times 2)=5+13-7

(111)=5+13-7

(111)=18-7

111=11

Answer:

x=5  x=-3

Step-by-step explanation:

x^2 − 2x − 15 =0

Factor

What two numbers multiply to -15 and add to -2

-5*3 = -15

-5+3 =-2

(x-5) (x+3)=0

Using the zero product property

x-5 =0   x+3 =0

x=5  x=-3

Answer:

x^2 - 2x - 15 = 0

(x - 5) (x + 3) = 0

x - 5 = 0

x = 5

x + 3 = 0

x = -3

Answer:

Sides:

Angles:

Step-by-step explanation:

Apply the law of sines to find the sine of [tex]\angle A[/tex]:

[tex]\displaystyle \frac{\sin{A}}{\sin{C}} = \frac{a}{c}[/tex].

[tex]\displaystyle\sin A = \frac{a}{c} \cdot \sin{C} = \frac{103}{159} \times \left(\sin{104^{\circ}}\right) \approx 0.628556[/tex].

Therefore:

[tex]\angle A = \displaystyle\arcsin (\sin A) \approx \arcsin(0.628556) \approx 38.9^\circ[/tex].

The three internal angles of a triangle should add up to [tex]180^\circ[/tex]. In other words:

[tex]\angle A + \angle B + \angle C = 180^\circ[/tex].

The measures of both [tex]\angle A[/tex] and [tex]\angle C[/tex] are now available. Therefore:

[tex]\angle B = 180^\circ - \angle A - \angle C \approx 37.1^\circ[/tex].

Apply the law of sines (again) to find the length of side [tex]b[/tex]:

[tex]\displaystyle\frac{b}{c} = \frac{\sin \angle B}{\sin \angle C}[/tex].

[tex]\displaystyle b = c \cdot \left(\frac{\sin \angle B}{\sin \angle C}\right) \approx 159\times \frac{\sin \left(37.1^\circ\right)}{\sin\left(104^\circ\right)} \approx 98.8[/tex].

Answer:

Option 4

Step-by-step explanation:

The central angles are "Angles in the center"

So,

Central Angles are <AOB, <BOC and <AOC

Answer:

<AOB, <BOC and < AOC

Step-by-step explanation:

There are 3 angles at center O . The largest is <AOC ( = 180 degrees). Thn you have 2 more each equal to 90 degrees.

Answer:

488p - 244

Step-by-step explanation:

Step 1: Add

61(8p - 4)

Step 2: Distribute

488p - 244

Answer:

790π

Step-by-step explanation:

We are given;

Diameter of cylinder;d = 10 mm

So, radius;r = 10/2 = 5 mm

Height of cylinder;h = 70mm

Surface area of cylinder is given by the formula; S.A = 2πr² + 2πrh

Plugging in the relevant values, we have;S.A = 2π(5)² + 2π(5)(70)

S.A = 50π + 700π

S.A = 750π

Now, because one base of the cylinder is hidden as the cone is stacked on that face, we will deduct the area of that base face;

Thus, Surface area = 750π - π(5)² = 750π - 25π = 725π

For the cone,

Height;h = 12mm

Since this is stacked directly on the cylinder, it will have the same radius. Thus; radius;r = 5mm

Now,formula for surface area of cone is;

S.A = πr² + πrL

Where L is slant height.

We can use pythagoras theorem to get L.

So, L² = r² + h²

L = √r² + h²

L = √(5² + 12²)

L = √(25 + 144)

L = √169

L = 13

So, S.A of cone = π(5)² + (π×5×13)

S.A = 25π + 65π = 90π

Similar to what was done to the Cylinder, since the circular base of the cone is stacked on the cylinder, we will deduct the surface area of that base as it is hidden.

So, S.A is now = 90π - π(5)²

= 90π - 25π = 65π

Thus,total surface area of the pencil = 725π + 65π = 790π

Answer:[tex]790\pi sq. Mm[/tex]

Step-by-step explanation:got it right on the test

Let's solve the first equation and see if both -6−6minus, 6 and 666 are possible values of ccc.

Hint #22 / 4

\begin{aligned} c^2&=36\\\\ \sqrt{c^2}&=\sqrt{36}&\\\\ c &=\pm 6 \end{aligned}

c

2

c

2

​

c

​

=36

=

36

​

=±6

​

​

Yes, both -6−6minus, 6 and 666 are possible values of ccc for the first equation!

Hint #33 / 4

Let's do the same for the second equation.

\begin{aligned} c^3&=216\\\\ \sqrt[\scriptstyle 3]{c^3}&=\sqrt[\scriptstyle 3]{216}&\\\\ c &=6 \end{aligned}

c

3

3

c

3

​

c

​

=216

=

3

216

​

=6

​

​

No, both -6−6minus, 6 and 666 are not possible values of ccc for the second equation.

Hint #44 / 4

The following equation has both -6−6minus, 6 and 666 as possible values of ccc:

c^2 = 36c

2

=36

The equation that has both -6 and 6 as possible values is c² = 36.

Option A is the correct answer.

An equation contains one or more terms with variables connected by an equal sign.

Example:

2x + 4y = 9 is an equation.

2x = 8 is an equation.

We have,

If c is a possible value of 6, then c - 6 = 0.

Similarly, if c is a possible value of -6, then c + 6 = 0.

A)

c² = 36

We can factor this equation as c² - 36 = 0, which gives us (c - 6) (c + 6) = 0. Therefore, both c = 6 and c = -6 are solutions to this equation.

B)

c³ = 216

We can factor 216 as 6³, so c³ - 6³ = (c - 6) (c² + 6c + 36) = 0.

The quadratic factor c² + 6c + 36 does not have any real roots, so the only solution to this equation is c = 6.

Therefore, -6 is not a possible solution to this equation.

Thus,

The equation that has both -6 and 6 as possible values is c² = 36.

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Answer:

a. True

Step-by-step explanation:

The frequency distribution is a summary of the gathered data set, in which the interval of values is divided into classes.

A requirement for a frequency distribution is for the classes to be mutually exclusive and exhaustive. That is, each individual, object, or measurement in the data set must belong to one and only one class.

Then, we can conclude that each individual, object, or measurement must appear in at least one (in fact, only in one) category or class.

Answer:

The statements that are true are: A, B, F, G, and H.

Step-by-step explanation:

The statements are:

A. A 90% confidence interval would be narrower than the interval given.

TRUE.

The less confidence, the less conservative is the interval and the narrower it can be. So this statement is true.

B. You are 95% confident that the proportion of all seniors who drive to campus is in the interval from .69 to .85.

TRUE.

That is the definition of confidence interval.

C. 95% of all seniors drive to campus from 69% to 85% of the time, and the rest drive more frequently or less frequently.

FALSE.

The confidence interval only has meaning referred to the population proportion, not the individual values. So we can not claim this is true.

D. All seniors drive to campus an average of 77% of the time.

FALSE.

The average is expected to be, with 95% confidence, between 0.69 and 0.85. The sample proportion is 0.77*, and this outcome is used to calculate the confidence interval, but we don't know if the true average is 0.77.

*Sample proportion:

[tex]p=(LL+UL)/2=(0.69+0.85)/2=1.54/2=0.77[/tex]

E. You are 95% confident that the proportion of seniors in the sample who drive to campus is between .69 and .85.

FALSE.

The sample proportion is known and it is 0.77.

F. 77% of the seniors in your sample drive to campus.

TRUE.

This is the sample proportion.

G. If the sampling were repeated many times, you would expect 95% of the resulting samples to have a sample proportion that falls in the interval from .69 to .85.

TRUE.

This is a property of the confidence intervals.

H. If the sampling were repeated many times, you would expect 95% of the resulting confidence intervals to contain the proportion of all seniors who drive to campus.

TRUE.

This is a property of the confidence intervals.

Answer:

88

Step-by-step explanation:

Angle Formed by Two Chords  = 1/2( sum of Intercepted Arcs)

ABD = 1/2 ( 131+ 53)

ABD = 1/2 (184)

      =92

We know that ABC + ABD form a straight line

ABC = 180 -ABD

ABC = 180 -92

ABC = 88