In each of the molecules drawn below one chemical bond is colored red. Decide whether this bond is likely to be polar or not. If the bond is likely to be polar, write down the chemical symbol for the atom which will have more negative charge. The highlighted bond is polar and the more negative atom is The highlighted bond is nonpolar. The highlighted bond is polar and the more negative atom is The highlighted bond is nonpolar. The highlighted bond is polar and the more negative atom is The highlighted bond is nonpolar.
The question is incomplete, the complete question is shown in the image attached to this answer
Answer:
See Explanation
Explanation:
I want us to bear something in mind. A compound is polar when there is a considerable difference in electronegativity between two bonding atoms in the molecule.
The implication of this is, the shared electron pair of the bond will be closer to the atom of greater electronegativity than the atom of lesser electronegativity thereby creating a dipole in the molecule.
Let us consider each of the compounds;
For Cl-F, the highlighted bond is polar and F is the more electronegative atom
For H-Br, the highlighted bond is polar and Br is the more electronegative atom
For N≡N, the highlighted bond is nonpolar since it is a homonuclear diatomic molecule.
A solution has a [OH−] of 1 x 10^−11 M. What is the [H3O+] of the solution?
Explanation:
Ionic product of water, Kw
[tex]Kw = [OH {}^{ - } ][H _{3} O {}^{ + } ] \\ 1.0 \times {10}^{ - 14} = (1 \times {10}^{ - 11} )[H _{3} O {}^{ + } ] \\ [H _{3} O {}^{ + } ] = \frac{(1.0 \times {10}^{ - 14}) }{(1 \times 10 {}^{ - 11}) } \\ ][H _{3} O {}^{ + } ] = 0.001 \: M[/tex]
Select the element(s) that will have ONE unpaired electron in the p orbital.
Ca
N
B
Ar
Br
Answer: The element B will have ONE unpaired electron in the p orbital.
Explanation:
The electronic configuration of each given element is as follows.
Atomic number of calcium (Ca) is 20.
Ca: [tex]1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2}[/tex]
Atomic number of nitrogen (N) is 7.
N: [tex]1s^{2} 2s^{2} 2p^{3}[/tex]
Atomic number of boron (B) is 5.
B: [tex]1s^{2} 2s^{2} 2p^{1}[/tex]
Atomic number of argon (Ar) is 18.
Ar: [tex]1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6}[/tex]
Atomic number of bromine (Br) is 35.
Br: [tex][Ar] 4s^{2} 3d^{10} 4p^{5}[/tex]
Therefore, boron is the only element that have one unpaired electron in the p-orbital.
Thus, we can conclude that element B will have ONE unpaired electron in the p orbital.
In the graphic,
X represents which element?
40
20
Answer:Ca
Explanation:
How many molecules are in 4.67 mols of H2O
Answer:
2.81 × 10²⁴ moleculesExplanation:
The number of molecules can be found by using the formula
N = n × L
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
We have
N = 4.67 × 6.02 × 10²³
We have the final answer as
2.81 × 10²⁴ moleculesHope this helps you
Given the following information: SO2(g) + 12 O2(g) = SO3(g) Kp = 2.5E-2 What is the Kp value for the following reaction: 2 SO2(g) + O2(g) = 2 SO3(g)
Answer:
K = 6.25x10⁻⁴
Explanation:
Based on the reaction:
SO₂ + 1/2 O₂ ⇄ SO₃ Kp = 2.5x10⁻²
We can find the Kp of a similar reaction using Hess's law where the sum of 2 reactions a and b produce a K that is:
K = Ka*Kb
The sum of twice the reaction of the problem:
SO₂ + 1/2 O₂ ⇄ SO₃
+ SO₂ + 1/2 O₂ ⇄ SO₃
2SO₂ + O₂ ⇄ 2SO₃
Where K must be:
K = Kp*Kp = Kp²
K = (2.5x10⁻²)²
K = 6.25x10⁻⁴